QUESTION 17 PLEASE HELP ME ASAPP

[tex]\begin{cases} x=-7\implies &x+7=0\\ x=0\implies &x=0\\ x=1\implies &x-1=0\\ x=6\implies &x-6=0 \end{cases}\qquad \implies (x+7)(x)(x-1)(x-6)=\stackrel{y}{0} \\\\\\ (x+7)(x)\stackrel{using~\mathbb{FOIL}}{(x^2-7x+6)}=0\implies (x^2+7x)(x^2-7x+6)=0[/tex]

[tex]\begin{array}{llll} x^2-7x+6\\ \qquad \times ~x^2\\\cline{1-1} x^4-7x^3+6x^2 \end{array}\qquad +\qquad \begin{array}{llll} x^2-7x+6\\ \qquad \times ~7x\\\cline{1-1} 7x^3-49x^2+42x \end{array} \\\\\\ (x^4-7x^3+6x^2)+(7x^3-49x^2+42x)=0 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill x^4-43x^2+42x=y~\hfill[/tex]

[tex] \rm \frac{19}{12} - \frac{3}{4} = \frac{9}{12} - \frac{9}{12} = \frac{9 - 9}{12} = \frac{0}{12} = \bf0 \: \: (done.)[/tex]

Answer:

[tex]\frac{19}{12} - \frac{3}{4}=\frac{5}{6}[/tex]

Step-by-step explanation:

[tex] \frac{19}{12} - \frac{3}{4} [/tex]

[tex] = \frac{19 \times 4}{12 \times 4} - \frac{3 \times 12}{4 \times 12}[/tex]

[tex] = \frac{76}{48} - \frac{36}{48} [/tex]

[tex] = \frac{76 - 36}{48}[/tex]

[tex]= \frac{40}{48} [/tex]

[tex] = \frac{40 \div 8}{48 \div 8} [/tex]

[tex] = \frac{5}{6}[/tex]

Answer:

-7

Step-by-step explanation:

a=9 a2=2 a3=-5 a4=-12

d = a4-a3 ,a3-a2, a2-a.

so:

d = -12-(-5) =-12+5 =-7

also;

d = -5-2 = -7

and

d= 2-9 =-7

so the common difference is -7

Answer:

-7

Step-by-step explanation:

We know that

Common difference = a2 - a1

=> 9 - 2

=> -7

Answer:

its 3 OR C

Step-by-step explanation:

Answer:

x + (4x-20) = 180

by linear pair

therefore x= 70

Applying the definition of linear pair, the value of x is: D. 40.

Therefore:

x + (4x - 20°) = 180°

5x - 20 = 180

5x = 180 + 20

5x = 200

x = 40

Therefore, applying the definition of linear pair, the value of x is: D. 40.

Learn more about linear pair on:

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Answer:

6% a year

Step-by-step explanation:

r=(1/t)(A/p-1)

r= 1/9((418/400)-1) = 0.005

0.005*100 (for percentage) = 0.5%

rate monthly is 0.5%

0.5*12= 6

yearly is 6%

Answer:

Slope = 4

Step-by-step explanation:

Change in Y = 4

Change in X = 1

Slope = Δy/Δx = 4/1 = 4

Answer:

56study hard watch your book for 20 minute and look....this is a hint

Answer:

5:1

Step-by-step explanation:

divide eatch side

Answer:

It's 1:5

Step-by-step explanation:

Answer:

y = -6

Step-by-step explanation:

-2(y - 3) = y + 24

-2y + 6 = y +24

-18 = 3y

-6 = y

[tex]\huge \rm༆ Answer ༄[/tex]

Measure of each side of a triangle can't be greater than the sum of the other two sides and can't be smaller than the difference between the two other sides. therefore the most appropriate choice is ~

I hope it helps ~

We have:

1) 3 + 5 = 8 ⇒ wrong

2) 4 + 7 > 9 ⇒ right

3) 2 + 11 < 15 ⇒ wrong

ANSWER: 4 cm, 7 cm, 9 cm

Ok done. Thank to me :>

Answer:

D <----last option  Domain is set of real numbers or (-∞,+∞)

The maximum number of bags is an illustration of the greatest common factor

The maximum number of bags John can make is 8

The given parameters are:

[tex]Chocolate=48[/tex]

[tex]Peanut=56[/tex]

Start by expressing 48 and 56 as a product of their factors.

[tex]Chocolate = 1 \times 2 \times 2 \times 2 \times 2 \times 3[/tex]

[tex]Peanut = 1 \times 2 \times 2 \times 2 \times 7[/tex]

The product of the common factors between the above products is:

[tex]Factors = 1 \times 2 \times 2 \times 2[/tex]

Multiply

[tex]Factors = 8[/tex]

The above represents the greatest common factor of 48 and 56.

Hence, the maximum number of bags John can make is 8

Read more about greatest common factor at:

https://brainly.com/question/219464

Step-by-step explanation:

To determine the maximum number of bags John can make, we need to find the greatest common divisor (GCD) of the two quantities: 48 chocolate chip cookies and 56 peanut butter cookies.

The GCD is the largest number that divides both quantities without leaving a remainder. It represents the maximum number of bags that can be made, with each bag containing an equal number of cookies of each type.

Let's find the GCD of 48 and 56:

Step 1: List the divisors of each number:

Divisors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

Divisors of 56: 1, 2, 4, 7, 8, 14, 28, 56

Step 2: Identify the common divisors in both lists:

Common divisors of 48 and 56: 1, 2, 4, 8

Step 3: Determine the greatest common divisor (GCD):

The greatest common divisor of 48 and 56 is 8.

So, John can make a maximum of 8 bags, with each bag containing an equal number of chocolate chip and peanut butter cookies.

PLEASE MARK AS BRAINLIEST IF SATISFIED WITH THIS ANSWER PLEASE

Answer: m>-50

x<=3 3/4

at point -2.1 3rd arrow

at 1.33 4th arrow

at 4 2nd arrow

Step-by-step explanation:

Answer:

B,C,D,F, those are yhe right answer

Answer:

0,0

Step-by-step explanation:

because it is in the centre of the graph

Answer:

I think it's B

Step-by-step explanation:

Answer:

1188 grams of water

Step-by-step explanation:

x is the grams of water

so total is 12+x grams

sugar/total is 12/12+x

and 1% ratio is 12/12+x=1/100

so x would be 1188 grams of water.

Answer:

1188

Step-by-step explanation:

Start with the part and whole proportion

[tex]\frac{12}{?} =\frac{1}{100}[/tex]

multiply the one by 12 and 100 by 12

[tex]\frac{12}{1200} =\frac{1}{100}[/tex]

now subtract 12 from 1200

then you get 1188.

I hope this helps :))

Step-by-step explanation:

(x-8)²+(y--8)²=(2)²

x²-16x+64+y²+16y+64=4

x²+y²-16x+16y+124=0

Answer:

25%

Step-by-step explanation:

[tex] \frac{1200}{960} \times 100 \%= 1.25\% \\ [/tex]

so it increases 25%

Answer:

B

Step-by-step explanation:

rise over run gives you 4/1 which equals 4. and the only 2 intercepts given lead negatively so the line has to be negative which gives you -4 then where x=0 is the x intercept which is positive 4

Answer:

B) y=-4x+4

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(4-0)/(0-1)

m=4/-1

m=-4

y-y1=m(x-x1)

y-0=-4(x-1)

y=-4(x-1)

y=-4x+4

Answer:

[tex]\boxed{\tt \frac{40}{9}} \ \sf or \ \boxed{\tt 4 \frac{4}{9}}[/tex]

Step-by-step explanation:

[tex]\textsf{We are asked to solve for the sum of 2 fractions.}[/tex]

[tex]\large\underline{\textsf{What are Fractions?}}[/tex]

[tex]\textsf{Fractions are representations of rational numbers that can be represented as part}[/tex]

[tex]\textsf{of a whole number.}[/tex]

[tex]\underline{\textsf{What are the parts of a fraction?}}[/tex]

[tex]\textsf{Fractions have 2 parts, they're called the Numerator and the Denominator.}[/tex]

[tex]\frac{\sf Numerator}{\sf Denominator}[/tex]

[tex]\textsf{The Numerator represents the amount of equal parts a certain rational number}[/tex]

[tex]\textsf{has compared to the Denominator. The Denominator represents the total amount}[/tex]

[tex]\textsf{of parts that make a fraction equal to 1. If the Numerator is the same as the}[/tex]

[tex]\textsf{Denominator, then the fraction is just 1. If the Numerator is greater than 1, then}[/tex]

[tex]\textsf{this kind of fraction is considered an Improper Fraction, and improper fractions}[/tex]

[tex]\textsf{are fractions that are improper due to the Numerator being greater than the}[/tex]

[tex]\textsf{Denominator, which means these fractions shouldn't be represented as fractions,}[/tex]

[tex]\textsf{but there's nothing wrong with representing it as a fraction.}[/tex]

[tex]\textsf{Since we know what majority of fractions are, we may begin adding these fractions}[/tex]

[tex]\textsf{which are improper.}[/tex]

[tex]\large\underline{\textsf{How are we able to Add Fractions?}}[/tex]

[tex]\textsf{Adding Fractions is simply adding the Numerators together since the Denominator}[/tex]

[tex]\textsf{can't be changed, if so then the equation won't be equal.}[/tex]

[tex]\textsf{*Remember that when adding fractions we must have common denominators.}[/tex]

[tex]\textsf{This means that we should find the LCM (Least Common Multiple) of the}[/tex]

[tex]\textsf{Denominators.}[/tex]

[tex]\underline{\textsf{For our problem;}}[/tex]

[tex]\textsf{Since we already have Common Denominators, we are able to simply add the}[/tex]

[tex]\textsf{Numerators.}[/tex]

[tex]\large\underline{\textsf{Solving;}}[/tex]

[tex]\textsf{Add the Numerators together.}[/tex]

[tex]\tt \frac{\boxed{\tt 23}}{9} + \frac{\boxed{\tt 17}}{9} =\boxed{\tt \frac{40}9}[/tex]

[tex]\tt \frac{40}{9} \ \textsf{can be our final answer. However, since our sum is an Improper Fraction, it's}[/tex]

[tex]\textsf{greater than 1. Since 40 can divide into 9 about 4 times, our whole number will}[/tex]

[tex]\textsf{be 4, and the remainder will be our fraction.}[/tex]

[tex]\underline{\textsf{Explained in numerical;}}[/tex]

[tex]\tt \frac{40}{9} = \frac{9}{9} + \frac{9}{9} + \frac{9}{9} + \frac{9}{9} + \frac{4}{9} = \boxed{\tt 4 \frac{4}{9}}[/tex]

[tex]*\tt \frac{36}{9} = \frac{4}{1}[/tex]

[tex]\textsf{These are called Whole Number Fractions.}[/tex]

[tex]\large\underline{\textsf{Hence;}}[/tex]

[tex]\tt \frac{23}{9} + \frac{17}{9} = \boxed{\tt \frac{40}{9}} \ \sf or \ \boxed{\tt 4 \frac{4}{9}}[/tex]

[tex]\large\underline{\textsf{Learn more about Fractions;}}[/tex]

https://brainly.com/question/26180542

[tex]\textsf{This answer will give you a great review of how to turn word-form problems into}[/tex]

[tex]\textsf{fractions, and how to simpify those fractions.}[/tex]

Answer:

f(2) = 2.5×2-10.5

=5-10.5

=-5.5

g(2) = 64(0.5×2)

= 64×1

=64

f(3)=2.5×3-10.5

=7.5-10.5

=-3

g(3)=64(0.5×3)

=64×1.5

=96

f(4)=2.5×4-10.5

=10-10.5

=-500

g(4)=64(0.5×4)

=64×2

=128

f(5)=2.5×5-10.5

=12.5-10.5

=2

g(5)=64(0.5×5)

=64×2.5

=150

I think it is the processs It will help you

Answer: 1600m^2

Its a square so all sides are equal. So...

400m * 400m

= 1600m^2

Answer:

The given perimeter is \[44cm\]. Hence, the area of the given square is \[121c{m^2}\].

Step-by-step explanation:

Answer:

[tex] \frac{2}{5} > \frac{1}{6} [/tex]

Answer: B. >

#CarryOnLearning

Step-by-step explanation:

standard deviation of $3

Find a 98% confidence interval about the mean (one decimal place).

Is a value of X=48 unusually high or is it normal? Choose correct explanation

Answer: The blue dot's value on the number line is 1.

Step-by-step explanation: Each two-skip interval from -7 to -3 is a skip of 4. Therefore, -3 skipped two times is -3 + 4, which equals 1, therefore the blue dot's value on the number line is 1.

Answer:

[tex]b=-a^2-c[/tex]

Step-by-step explanation: