Populations are effected by the birth and death rate, as well as the number of people who move in and out each year. The birth rate is the percentage increase of the population due to births and the death rate is the percentage decrease of the population due to deaths. Write a program that displays the size of a population for any number of years. The program should ask for the following data:
• The starting size of a population
• The annual birth rate
• The annual death rate
• The number of years to display
Write a function that calculates the size of the population for a year. The formula is
N = P + BP − DP
where N is the new population size, P is the previous population size, B is the birth rate, and D is the death rate.
Input Validation: Do not accept numbers less than 2 for the starting size. Do not accept negative numbers for birth rate or death rate. Do not accept numbers less than 1 for the number of years.
#include
using namespace std;
double calcOfPopulation(double, double, double);
double inputValidate(double, int);
int main()
{
double P, // population size
B, // birth rate %
D, // death rate %
num_years;
cout << "Starting size of population: ";
P = inputValidate(P, 2);
cout << "Annual birth rate: %";
B = inputValidate(B, 0);
cout << "Annual death rate: %";
D = inputValidate(D, 0);
cout << "Number of years to display: ";
num_years = inputValidate(num_years, 1);
cout << "Population size for "
<< num_years << " years "
<< " = "
<< (calcOfPopulation(P, B, D) * num_years)
<< endl;
return 0;
} // END int main()
double inputValidate(double number, int limit)
{
while(!(cin >> number) || number < limit)
{
cout << "Error. Number must not be "
<< " 0 or greater:";
cin.clear();
cin.ignore(numeric_limits::max(), '\n');
}
return number;
}
double calcOfPopulation(double P, double B, double D)
{
B *= .01; // 3.33% = .0333
D *= .01; // 4.44% = .0444
return P + (B * P) - (D * P);

Answers

Answer 1

Answer:

See attachment for program source file

Explanation:

The source code in the question is not incorrect; just that, it was poorly formatted.

So, what I did it that:

I edited the source code to be in the right formats.numeric_limits needs the <limits> header file to work properly. The <limits> header file was not included in the original source file; so, I added #include<limits> at the beginning of the source fileI corrected the wrongly declared function prototypes.

See attachment for the modified program source file


Related Questions

How to use the RANK Function in Microsoft Excel

Answers

Answer:

=RANK (number, ref, [order])

See Explanation

Explanation:

Literally, the rank function is used to rank values (i.e. cells) in a particular order (either ascending or descending).

Take the following instances:

A column used for total sales can use rank function to rank its cells from top sales to least.

A cell used for time can also use the rank function to rank its cells from the fastest time to slowest.

The syntax of the rank function is:

=RANK (number, ref, [order])

Which means:

[tex]number \to[/tex] The rank number

[tex]ref \to[/tex] The range of cells to rank

[tex]order \to[/tex] The order of ranking i.e. ascending or descending. This is optional.

njvekbhjbehjrbgvkheb

Answers

Answer:

shvajskzhzjsbssjjsusisj

Write functions to compute a subset, find member, union, and intersection of sets. Follow the steps below:

1. Read two integers from the user.
2. Suppose one of the integers is 2311062158. The binary equivalent of this integer stored in a register will be 1000 1001 1100 0000 0000 0010 1000 1110. This data should be regarded as bit strings representing subsets of the set {1, 2, … 32}. If the bit string has a 1 in position i, then element i is included in the subset. Therefore, the string: 1000 1001 1100 0000 0000 0010 1000 1110 corresponds to the set: {2, 3, 4, 8, 10, 23, 24, 25, 28, 32}.
3. Print out members of the set from smaller to larger. You can do a loop from 1 to 32. Load a masking bit pattern that corresponded to the position number of the loop counter (0x00000001 for 1). Isolate the bit in the operand by using the AND operation. If the result of the AND is not 0 then the loop counter is in the set and should be displayed. Increment the counter and shift the masking bit pattern to the left.
4. Read a number from the user. Determine if that element is a member of the given sets.
5. Determine the union of two sets.
6. Determine the intersection of two sets.
7. Implement a loop back to the main function. See the prompts below: "Enter the first number:" "Enter the second number:" "Members of Set 1:" "Members of Set 2:" "Enter an element to find:" "It is a member/ not a member of set 1" "It is a member/ not a member of set 2" "Union of the sets:" "Intersection of the sets:" "Do you want to compute set functions again?"
8. Test the program using the following data:

Enter the first number: 99999
Enter the second number: 111445
Members of set 1: 1 2 3 4 5 8 10 11 16 17
Members of set 2: 1 3 5 7 9 10 13 14 16 17
Enter an element to find: 7
It is not a member of set 1
It is a member of set 2
Union of the sets: 1 2 3 4 5 7 8 9 10 11 13 14 16 17
Intersection of the sets: 1 3 5 10 16 17

Answers

Explanation:

Suppose one of the integers is 2311062158. The binary equivalent of this integer stored in a register will be 1000 1001 1100 0000 0000 0010 1000 1110. This data should be regarded as bit strings representing subsets of the set {1, 2, … 32}. If the bit string has a 1 in position i, then element i is included in the subset. Therefore, the string: 1000 1001 1100 0000 0000 0010 1000 1110 corresponds to the set: {2, 3, 4, 8, 10, 23, 24, 25, 28, 32}.


Landing pages in a foreign language should never be rated fully meets?

Answers

Answer:

if the landing page provides all kind information of information as to that site people usually like it or will most likely enjoy it

BRAINLIEST?????

Explanation:

Which of the following describes a characteristic of organic light-emitting diodes (OLEDs) used in clothing?

uniform

flexible

transparent

sizeable

Answers

Flexible

Hopes this helps!

Answer:

Yes the answer is flexible.

Explanation:

I took the test and got it right.

Write a program second.cpp that takes in a sequence of integers, and prints the second largest number and the second smallest number. Note that in the case of repeated numbers, we really mean the second largest and smallest out of the distinct numbers (as seen in the examples below). You may only use the headers: and . Please have the output formatted exactly like the following examples: (the red is user input)

Answers

Answer:

The program in C++ is as follows:

#include <iostream>

#include <vector>

using namespace std;

int main(){

   int n;

   cout<<"Elements: ";

   cin>>n;

   vector <int>num;

   int input;

   for (int i = 1; i <= n; i++){        cin>>input;        num.push_back(input);    }

   int large, seclarge;

   large = num.at(0);      seclarge = num.at(1);

  if(num.at(0)<num.at(1)){     large = num.at(1);  seclarge = num.at(0);   }

  for (int i = 2; i< n ; i ++) {

     if (num.at(i) > large) {

        seclarge = large;;

        large = num.at(i);

     }

     else if (num.at(i) > seclarge && num.at(i) != large) {

        seclarge = num.at(i);

     }

  }

  cout<<"Second Largest: "<<seclarge<<endl;

  int small, secsmall;

  small = num.at(1);       secsmall = num.at(0);

  if(num.at(0)<num.at(1)){ small = num.at(0);  secsmall = num.at(1);   }

  for(int i=0; i<n; i++) {

     if(small>num.at(i)) {  

        secsmall = small;

        small = num.at(i);

     }

     else if(num.at(i) < secsmall){

        secsmall = num.at(i);

     }

  }

  cout<<"Second Smallest: "<<secsmall;

  return 0;

}

Explanation:

See attachment for explanation

Given positive integer n, write a for loop that outputs the even numbers from n down to 0. If n is odd, start with the next lower even number.

Answers

Answer:

if(n % 2 == 0){

   for(int i = n; i >= 0; i-=2){

        System.out.println(i);

    }

}

else{

     for(int i = n - 1; i >= 0; i-=2){

        System.out.println(i);

     }

}

Sample output

Output when n = 12

12

10

8

6

4

2

0

Output when n = 21

20

18

16

14

12

10

8

6

4

2

0

Explanation:

The above code is written in Java.

The if block checks if n is even by finding the modulus/remainder of n with 2.  If the remainder is 0, then n is even. If n is even, then the for loop starts at i = n. At each cycle of the loop, the value of i is reduced by 2 and the value is outputted to the console.

If n is odd, then the else block is executed. In this case, the for loop starts at i = n - 1 which is the next lower even number. At each cycle of the loop, the value of i is reduced by 2 and the value is outputted to the console.

Sample outputs for given values of n have been provided above.

Popular periodicals might include newspapers

True or false?

Answers

Answer:

False

Explanation:

Because there is no way that would be correct!

Answer:

True

Explanation:

It makes sense

~Plz tap the crown ~

~Thank you~

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