pls help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer:

$28,875

Step-by-step explanation:

First, we would have to find 10% of $25,000

10% of $25,000 = $2,500

Now, we have to add the 2 values together

$25,000 + $2,500 = $27,500

Now, we can find the shipping fee, since it includes the engineering fee

5% of $27,500 = $1,375

Now, we can add the shipping fee to find the total

$27,500 + $1,375 = $28,875

Answer:

2cosAcosB = cos( A + B ) + cos( A - B )

Answer:

she will pay $19 for each day

Step-by-step explanation:

94-18=76

76÷4=19

The rental cost of each day Tara used the kayak is $19 if Tara stayed at the Merry Mountain campgrounds last weekend. She paid a rental fee to use a kayak for 4 days.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

It is given that:

Tara stayed at the Merry Mountain campgrounds last weekend. She paid a rental fee to use a kayak for 4 days.

Let x be the rental cost of each day Tara used the kayak.

4x + 18 = 94

4x = 94 - 18

4x = 76

x = 76/4

x = $19

Thus, the rental cost of each day Tara used the kayak is $19 if Tara stayed at the Merry Mountain campgrounds last weekend. She paid a rental fee to use a kayak for 4 days.

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Answer:

2/3 = 4/6 = 8/12

Step-by-step explanation:

Step-by-step explanation:

hope it will help you......

Answer:

Add 9.6 then divide by 3.2

Answer:

x+3/5=2

or,x+0.6=2

or,x=2-0.6

x=1.4

Answer:

Last choice

Step-by-step explanation:

First, convert (sinx)^2 to 1-(cosx)^2 via trigonometric identity derived from (sinx)^2 + (cosx)^2 = 1

[tex]\displaystyle \large{\sin^2x + \cos^2x=1 \longrightarrow \sin^2x=1-\cos^2x}[/tex]

Thus, the rewritten inequality is [tex]\displaystyle \large{1-\cos^2x>1+\cos x}[/tex]

Notice how the inequality has a quadratic pattern since we have (cosx)^2 and cosx in the inequality, simply arrange degrees in order.

[tex]\displaystyle \large{1-\cos^2x>1+\cos x}\\\displaystyle \large{0>1+\cos x-1+\cos^2x}\\\displaystyle \large{0>\cos x+\cos^2x}\\\displaystyle \large{\cos^2x+\cos x < 0}[/tex]

Then we factor cosx since the expression has cosx as a common factor.

[tex]\displaystyle \large{\cos x(\cos x+1)<0}[/tex]

Then we have to consider each inequalities which are cosx<0 and cosx+1<0 then merge both intervals once obtaining the solutions.

(1) [tex]\displaystyle \large{\cos x < 0}[/tex]

This inequality means that we have to find the x-value(s) that satisfy(ies) it.

Since cosx becomes negative after π/2 (Refer to unit circle, cosx becomes negative in second quadrant and this quadrant), that means it becomes negative until it reaches or < 3π/2.

Thus, [tex]\displaystyle \large{\frac{\pi}{2}<x<\frac{3\pi}{2}}[/tex] is the solution to cosx > 0.

The another way to solve inequality is to find the intersections by solving the equation then joint the interval together.

[tex]\displaystyle \large{\cos x<0 \longrightarrow \cos x=0}[/tex]

From the unit circle, cosx becomes 0 at x = π/2 and x = 3π/2 between interval [0,2π]

Therefore:

[tex]\displaystyle \large{\cos x = 0 \longrightarrow x = \frac{\pi}{2}, \frac{3\pi}{2}}\\\displaystyle \large{\boxed{\frac{\pi}{2}<x<\frac{3\pi}{2}}}[/tex]

(2) [tex]\displaystyle \large{\cos x+1<0 \longrightarrow \cos x <-1[/tex]

For this inequality, it appears that there have no solutions because cosine function is defined between [-1,1] in range hence there are no x-values in real plane that make cosx even less than -1.

Because only π satisfies cosx = -1 but not cosx < -1, we restrict π and every values.

Hence no solutions which cause a break of interval between π and π/2 < x < 3π/2

If you substitute x = π in, the inequality is false and therefore the answer is:

[tex]\displaystyle \large{\frac{\pi}{2}<x<\pi, \pi<x<\frac{3\pi}{2}}[/tex]

Answer:

D.

Step-by-step explanation:

The first two don't work, so it's between the last two.

This equation doesn't work for 180, so the answer is the last choice.

:)

[tex]\dfrac{2 \tfrac 12 }{\tfrac 52}\\\\\\\\= \dfrac{\left(\tfrac 5 2\right)}{\left(\tfrac 52 \right) }\\\\\\\\=1[/tex]

Answer:

10/40 were men, or simplified the amount is 1/4 of the total is men

Answer:

I believe it'd 69.5

Step-by-step explanation:

if u use the equation 2x+5=134, you get 64.5 for Josh and 69.5 for eric

Answer:

8 cm

Step-by-step explanation:

h = v/(pi r^2)

h = 904.78/ (3.1415 * 6^2)

Answer:

give the dimensions of the figure on the paper

Answer:

The sum of 3/5 and Square root of 13 is irrational. Since square root of 13 is irrational. And when you add it gives u irrational.

Answer:

√13

Step-by-step explanation:

1/33 is a fraction, meaning it is rational

1.6... has a repiton, meaning it is rational

-5.43 is a integer meaning it is rational

Answer:

d four

Step-by-step explanation:

How many solutions does the nonlinear system of equations graphed below have?  

Look at the number of points where the graphs intersect each other...the points where the graphs of the functions cross each other are the solutions to the system.  

Upon looking, you should see 4 points where the graphs intersect, so there are 4 solutions to the non-linear system of equations.

Answer:

HS = 5

Step-by-step explanation:

By the property of centroid, point S divides the median RP in the ratio of 2: 1: SR=2SP     HS = 1/2 SM

SP=4

SR + 2 = 2SP + 2 = 10 = SM

HS = 1/2*SM = 5

Answer:

6 4/9

Step-by-step explanation:

You divide 58 and 8 and your answer would be 6.444444 repeating.

Answer:

VI

Step-by-step explanation:

The letter "A" is a vowel and a capital letter, so this should be categorized in group VI, where the vowel circle and the capital letter circle overlap.

Answer:

F

Step-by-step explanation:

It is a capital letter and a vowel

Answer:

7377.4

Step-by-step explanation:

Answer:

see exp

Step-by-step explanation:

1.0, 1/3, 95%, 80%

Answer:

1/5

Step-by-step explanation:

First and foremost, I want to simplify these fractions, just to make everything a lot easier when I actually get to dividing. 5/50 can be divided by 5/5 to get 1/10, and 15/30 can be divided by 15/15 to get 1/2. So, now we're dividing 1/10 by 1/2.

To divide fractions, we can multiply the first fraction (in this case, 1/10) by the reciprocal of the second fraction (in this case, 1/2). The reciprocal of 1/2 is 2, so we can multiply 1/10 by 2 to find our answer. 1/10 × 2 = 2/10, or 1/5, so this is our final answer.

Hopefully that's helpful! If you have any further questions, let me know. :)

The quotient of given fractions is 1/5.

Given that, 5/50 divided by 15/30.

In Mathematics, fractions are represented as a numerical value, which defines a part of a whole. A fraction can be a portion or section of any quantity out of a whole, where the whole can be any number, a specific value, or a thing.

Now, 5/50 ÷ 15/30

Keep the first fraction 5/50 same change the division symbol and reciprocate the fraction 15/10

That is, 5/50 × 30/15

= 1/10 × 2/1

= 2/10

= 1/5

Therefore, the quotient of given fractions is 1/5.

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Answer:

its $5.76

Step-by-step explanation:

because $38.40 / 15 is $5.76

Answer:

check online for more information

The mean age will increase, and the median age will remain the same.

Option B is the correct answer.

It is the average value of the set given.

It is calculated as:

Mean = Sum of all the values of the set given / Number of values in the set

We have,

Ages:

14, 15, 15, 16, 16, 16, 16, 17, 17, 17, 17, 17, 18

The mean of the ages.

= (14 + 15 + 15 + 16 + 16 + 16 + 16 + 17 + 17 + 17 + 17 + 17 + 18) / 13

= 211/13

= 16.23

The median of the ages.

= 16

Now,

18 becomes 19.

14, 15, 15, 16, 16, 16, 16, 17, 17, 17, 17, 17, 19.

Mean = 212/13 = 16.3

Median = 16

Thus,

The mean age is increased.

The median is the same.

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all real numbers except the 90 and 270 because of cosx

-1-1 or 2-4 or 3-5 or 6-8 or 7-9 or 8-10

Answer:

[tex]A=\left(-1\dfrac{5}{5}\right)=(-2)\\\\B=\left(-\dfrac{4}{5}\right)\\\\C=\left(\dfrac{3}{5}\right)[/tex]

Step-by-step explanation:

Look at the picture.

[tex]\dfrac{2}{10}=\dfrac{1}{5}[/tex]

Answer:

  (a) 43.6490°N, 70.3928°W

  (b) Baker's Field

Step-by-step explanation:

The locations are all within a 7-mile square, so we will make the assumption of a flat Earth with parallel longitude lines. Then the "central" location will be the weighted average of the latitude and longitude coordinates.

Total population is 16000 +22000 +36500 = 74,500. For purposes of the arithmetic, we will subtract 43 from latitude and 70 from longitude, then multiply each fraction by 10. Similarly, we will divide each population by 1000.

The weighted average location is found from ...

  (16/74.5)(6.769, 3.717) +(22/74.5)(5.781, 3.222) +(36.5/74.5)(6.795, 4.447)

  = (1.4537, 0.7983) +(1.7071, 0.9515) +(3.3291, 2.1787) = (6.490, 3.928)

The center of gravity is about 43.6490°N, 70.3928°W.

__

The coordinate differences from the center of gravity are (in (°lat, °long)) ...

  Baker's Field: (0.0294, -0.0101)

  Lonesome Acres: (-0.1371, -.0072)

Clearly, Baker's field is closer to the site of part (a).

_____

Additional comment

Distance calculations could be refined further by considering that a degree of longitude at this latitude represents about 0.72 times the distance of a degree of latitude. In this problem, the location of Lonesome Acres has a latitude difference that is several times any of the other coordinate differences, so it is clearly much farther away from the desired location.

The calculations done here are a sort of first-level approximation. The least-significant digits in the coordinates represent a distance of less than 50 feet. If you really want accuracy to that level, then the (approximately) spherical shape of the Earth needs to be accounted for. As a second-level approximation, some reference point needs to be identified, and coordinates in miles (or feet) need to be expressed in relation to that reference. The best accuracy would be obtained using spherical trigonometry to identify the distances.

We expect any school that is constructed to be somewhat larger than 50 feet in any direction, so accuracy to the 4th decimal place in these locations is probably not required--except to satisfy some answer-checker.