Answer:
add 12.18 to both sides and the divide by 2.14 on both sides until its x equal whatever you get
trinomios de 6x 2 + 13 x + 5
Answer:
77
Step-by-step explanation:
6x2 = 12
13x5 = 65
65+12 = 77
The answer is 77.
According to the National Institute of Health, about 37% of high school seniors have vaped in the past year. Suppose that a survey contacts an SRS of 400 high school seniors and calculates the sample proportion, , in this sample who have vaped in the past year. What is the mean of the sampling distribution of ?
Using the Central Limit Theorem, it is found that the mean of the sampling distribution of sample proportions is 0.37.
The Central Limit Theorem establishes that, for a proportion p in a sample of size n, the sampling distribution of sample proportions has:
Mean [tex]\mu = p[/tex].Standard error [tex]s = \sqrt{\frac{p(1 - p)}{n}}[/tex]For this problem, about 37% of high school seniors have vaped in the past year, hence [tex]p = 0.37[/tex].
Then, the mean of the sampling distribution of sample proportions is 0.37.For more on the Central Limit Theorem, you can check https://brainly.com/question/4086221
(8y²)(-3x²y²)(2/3xy⁴)
HELP PLEASEEEEEEEE
Step-by-step explanation:
1 Remove parentheses.
8{y}^{2}\times -3{x}^{2}{y}^{2}\times \frac{2}{3}x{y}^{4}
8y
2
×−3x
2
y
2
×
3
2
xy
4
2 Use this rule: \frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}
b
a
×
d
c
=
bd
ac
.
\frac{8{y}^{2}\times -3{x}^{2}{y}^{2}\times 2x{y}^{4}}{3}
3
8y
2
×−3x
2
y
2
×2xy
4
3 Take out the constants.
\frac{(8\times -3\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}
3
(8×−3×2)y
2
y
2
y
4
x
2
x
4 Simplify 8\times -38×−3 to -24−24.
\frac{(-24\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}
3
(−24×2)y
2
y
2
y
4
x
2
x
5 Simplify -24\times 2−24×2 to -48−48.
\frac{-48{y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}
3
−48y
2
y
2
y
4
x
2
x
6 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x
a
x
b
=x
a+b
.
\frac{-48{y}^{2+2+4}{x}^{2+1}}{3}
3
−48y
2+2+4
x
2+1
7 Simplify 2+22+2 to 44.
\frac{-48{y}^{4+4}{x}^{2+1}}{3}
3
−48y
4+4
x
2+1
8 Simplify 4+44+4 to 88.
\frac{-48{y}^{8}{x}^{2+1}}{3}
3
−48y
8
x
2+1
9 Simplify 2+12+1 to 33.
\frac{-48{y}^{8}{x}^{3}}{3}
3
−48y
8
x
3
10 Move the negative sign to the left.
-\frac{48{y}^{8}{x}^{3}}{3}
−
3
48y
8
x
3
11 Simplify \frac{48{y}^{8}{x}^{3}}{3}
3
48y
8
x
3
to 16{y}^{8}{x}^{3}16y
8
x
3
.
-16{y}^{8}{x}^{3}
−16y
8
x
3
Done
14.
Considered a sample of 52 football games where 32 of them were won by the home team use a 0.01 significance level to test the claim that the probability that the home team wins is greater than one half
Answer: Yes the win level is greater than 1/2
Step-by-step explanation: 32/52 is greater than 1/2
You roll one die 8 times. What is the probability of rolling exactly six fours
Please convert the fraction into a decimal
Answer:
4/8 = 1/2 = 0.5 is your answer
150 in product of primes in index form
Answer:
Step-by-step explanation:
The prime factor representation of 150 is 2 x 3 x 5^2
how are ∠1 and ∠2 related
A. They are supplementary
B. They are complementary
C. They are Vertical
D. They are adjacent
Answer:
D. They are adjacentStep-by-step explanation:
Angles 1 and 2 have common side, so they are adjacent. They are not making a right or straight angle.
Correct choice is D
these two questions are hard for me. please help
Answer:
first one is second
Step-by-step explanation:
second one is A
A car dealer starts the month with 120 cars. The dealer sells 3 cars each day. The number of cars remaining on any day can by modeled by the function f(x) = 120 - 3x. What should the domain of the function be if you want to know the number of cars remaining on any day during the month? What are the maximum and minimum values during the month?
The domain of the function to know the number of cars remaining on any day during the month is [0, 40]. The maximum and minimum values are 120 and 0 respectively.
The domain is the all inputted value for which the function is defined. All the x values are domain of a function.
Now, finding the domain of the function,
We know that, the number of cars cannot be negative, so
[tex]f(x)\geq0\\120-3x\geq0\\3x\leq120\\x\leq40[/tex]
The number of cars should be greater than 0, so x > 0.
So, the domain will be [0, 40].
The maximum value is given by putting x = 0,
[tex]f(0)=120-3(0)\\=120[/tex]
The minimum value is given by putting x = 40,
[tex]f(40)=120-3\times40\\=120-120\\=0[/tex]
Therefore, the domain of the function f(x)=120-3x to know the number of cars remaining on any day during the month is [0, 40]. The maximum and minimum values are 120 and 0 respectively.
To learn more about the Domain of Functions visit here:
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PLSSS HELP!!
Which equation could have been used to create this graph?
y = x + 4
y = 2x
y = 4x
y = x + 2
solve for x PLS HELP QUICK I HAVE A FINAL TMRW AND I REALLY NEED TO KNOW HOW TO DO IT
Answer:
x = -9/2
Step-by-step explanation:
64 = 2^6
if you have the same base, you can set the exponents equal and solve for x.
-2x-3 = 6
-2x = 9
x = -9/2
good luck on your final! you got this!
Step-by-step explanation:
[tex] {2}^{ - 2x - 3} = 64[/tex]
first, get 64 to a base of 2
[tex] {2}^{ - 2x - 3} = {2}^{6} [/tex]
now we can drop the bases
[tex] - 2x - 3 = 6[/tex]
And now we can solve it like any other equation
[tex] - 2x = 6 + 3[/tex]
[tex] - 2x = 9[/tex]
[tex]x = - \frac{9}{2} [/tex]
answer this please
as percentages
Anyone know this? please help and Thank you very much!!!
[tex](9+7i)(6+3i)\\\\=54+27i + 42i + 21i^2\\\\=54+69i -21~~~;[i^2 =-1]\\\\=33+69i[/tex]
Are these figures below similar?
NO LINKS!! NEED ANSWER ASAP
What is the Distance formula of (-6, -12) and (4,8)
Distance formula is in picture
Answer:
The distance formula is 22.360679775
if you round it to the nearest tenth, then the answer is 22.4
Step-by-step explanation:
(-6, -12) and (4,8)
(x2 - x1)² + (y2 - y1)²
Place the x and y values
(4 - - 6)² + (8 - - 12)²
= 10² + 20²
= 100 + 400 = 500
√500 = 22.360679775
Round it to the nearest tenth and you will get 22.4
Hope this helps!
please mark me as the brainliest
The formula in finding the distance between two points is given below:
[tex] \sf{d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}}[/tex]where:
[tex] \sf{(x_1, y_1) = (-6, -12)}[/tex][tex] \sf{(x_2, y_2) = (4, 8)}[/tex]Substitute the given values into the distance formula and solve for d:
[tex] \sf{d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}}[/tex][tex] \sf{d = \sqrt{[4 - ( - 6)]^2 + [8 - ( - 12)]^2}}[/tex][tex] \sf{d = \sqrt{(10)^2 + (20)^2}}[/tex][tex] \sf{d = \sqrt{100 + 400}}[/tex][tex] \sf{d = \sqrt{500}}[/tex][tex] \bold{d = 22.4 \: units}[/tex]Therefore, the distance between the two points is 22.4 units (nearest tenth).
Cheers!
HAS ANYONE EVER DONE MARKET DAY AT SCHOOL IT IS SO STRESSFUL HELPPPPP
Kind of, Market day as in make stuff and then sell it or Market day as in Sell food, I remember this in elementary school 2 Different Kind of Market day :)
please help ! 20 pts please
The given ratios expresses the number of time a value is larger or smaller
than another value.
The correct responses are;
3. (B) 12 and 244. (D) 6, 9, 215. [tex]\underline{(E) \ \displaystyle \frac{11}{2}}[/tex]6. [tex]\underline{(E) \ \displaystyle \frac{5}{14}}[/tex]7. (B) [tex]\overline{EF}[/tex] = 6, [tex]\overline{AC}[/tex] = 9·√58. (C) The values are equal9. (A) The value in column A is greaterReasons:
3. Given that the perimeter of the rectangle = 72
The ratio of the lengths of the sides = 1:2
Let a and b represent the sides, we have;
2·a + 2·b = 72
[tex]\displaystyle \frac{a}{b} = \mathbf{\frac{1}{2}}[/tex]
Which gives;
2·a = b
2·a + 2·(2·a) = 72
6·a = 72
a = 72 ÷ 6 = 12
b = 2·a = 2 × 12 = 24
The lengths of the sides are; (B) 12 and 24
4. Extended ratio = 2:3:7
The perimeter = 36
The lengths of the sides are;
[tex]\displaystyle \frac{2}{2 + 3 + 7} \times 36 = \mathbf{6}[/tex]
[tex]\displaystyle \frac{3}{2 + 3 + 7} \times 36 = \mathbf{9}[/tex]
[tex]\displaystyle \frac{7}{2 + 3 + 7} \times 36 = \mathbf{21}[/tex]
The lengths are; (D) 6, 9, 21
5. The given equation is presented as follows;
[tex]\displaystyle \frac{5}{x + 7} = \mathbf{\frac{3}{x + 2}}[/tex]
5 × (x + 2) = 3 × (x + 7)
5·x + 10 = 3·x + 21
5·x - 3·x = 21 - 10
2·x = 11
[tex]\displaystyle x = \mathbf{ \frac{11}{2}}[/tex]
The correct option is; [tex]\displaystyle \underline{(E) \ \frac{11}{2}}[/tex]
6. The width to length ratio is [tex]\displaystyle \mathbf{\frac{2.5}{7.0}}[/tex]
The simplified ratio is therefore;
[tex]\displaystyle \frac{2.5}{7.0} = \frac{2 \times 2.5}{2 \times 7.0} = \mathbf{\frac{5}{14}}[/tex]
The correct option is (E) [tex]\displaystyle \underline{(E) \ \frac{5}{14}}[/tex]
7. The given ratio of the lengths is 3:1
Therefore;
[tex]\overline{BC}[/tex]:[tex]\overline{EF}[/tex] = 3:1
Which gives;
[tex]\displaystyle \mathbf{\frac{\overline{BC}}{\overline{EF}}} = \frac{3}{1}[/tex]
[tex]\overline{BC}[/tex] = 18
Therefore;
[tex]\displaystyle \frac{18}{\overline{EF}} = \frac{3}{1}[/tex]
18 × 1 = 3 × [tex]\overline{EF}[/tex]
[tex]\displaystyle \overline{EF} = \frac{18 \times 1}{3} = 6[/tex]
[tex]\overline{EF}[/tex] = 6
By Pythagorean theorem, we have;
[tex]\overline{DF}[/tex]² = [tex]\mathbf{\overline{DE}}[/tex]² + [tex]\mathbf{\overline{EF}}[/tex]²
Which gives;
[tex]\overline{DF}[/tex]² = 3² + 6² = 45
[tex]\overline{DF}[/tex] = √(45) = 3·√5
Using the given ratio, we have;
[tex]\overline{AC}[/tex] = 3 × [tex]\mathbf{\overline{DF}}[/tex]
Which gives;
[tex]\overline{AC}[/tex] = 3 × 3·√5 = 9·√5
[tex]\overline{AC}[/tex] = 9·√5
The correct option is; (B) [tex]\overline{EF}[/tex] = 6, [tex]\overline{AC}[/tex] = 9·√5
8. EF = 1, AB = 2
CD = 2, CE = 4
Therefore;
[tex]\displaystyle \mathbf{\frac{EF}{AB}} =\frac{1}{2}[/tex]
[tex]\displaystyle \mathbf{\frac{CD}{CE}} =\frac{2}{4} = \frac{1}{2}[/tex]
Which gives;
[tex]\displaystyle \frac{EF}{AB} =\displaystyle \mathbf{\frac{CD}{CE}}[/tex]
(C) The values are equal
9. AC = 6, BE = 8
DF = 3, BD = 6
Column A
[tex]\displaystyle \frac{AC}{BE} =\displaystyle \mathbf{\frac{6}{8}} = \frac{3}{4}[/tex]
Column B
[tex]\displaystyle \frac{DF}{BD} =\displaystyle \mathbf{\frac{3}{6}} = \frac{1}{2}[/tex]
[tex]\displaystyle \frac{3}{4} > \mathbf{\frac{1}{2}}[/tex]
Therefore;
Column A is greater than column B
(A) The value in column A is greater
Learn more about ratios here:
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graph -1,-1 on this graph
Answer:
UP THE DOWN THAT WHAT I GOT
Step-by-step explanation:
There are 750 calories in ten ounces of a certain ice cream. How many calories are
there in three pounds?
1 pound = 16 ounces
Before you try that problem, answer the question below.
How many ounces will you need to find the number of
calories for?
try
You must answer all questions above in order to submit.
attempt 1 out of 2
Help me solve this PLEASE?
Work Shown:
1 pound = 16 ounces
3 pounds = 48 ounces (multiply both sides by 3)
Based on that, we can then say,
(750 calories)/(10 ounces) = (x calories)/(48 ounces)
750/10 = x/48
75 = x/48
x/48 = 75
x = 48*75
x = 3600
Mark's test scores for this semester were: 83, 80, 91, 74, 66, 95, 87, 72, 95, & 98. What is the mode of his test scores?
nnnnnnnnnnnnnnnkkkkkkkkkkkkkkkkkkkkkkkkkkkkk
nicole sold half of her comic books then bought 12 more . She now has 25 books. How many did she begin with.
Graph the function f(x)=3/2x-4. Use the line tool and select two points to graph.
Answer:
Slope = 3/2
y-intercept = -4
x | y
0 -4
2 -1
Step-by-step explanation:
Xavier's pet turtle laid eggs! So far, only 2 eggs have hatched for every 5 that are unhatched. If Xavier's turtle laid 35 eggs in all, how many eggs have hatched?
Answer: 21
Step-by-step explanation:
A wooden rod of 5 m 75 cm was cut into 5 equal pieces. What is the length of each piece.
We have: 5m 75cm = 5.75 m
So the length of each piece is : [tex]l = \frac{5.75}{5} =1.15<m>[/tex]
ok done. Thank to me :>
find g12 in the sequence -1,-3,-9,-27,....
a. -59,049
b. -177,147
c. 118,098
d. -19,683
Answer:
b. [tex]a_{12}=-177147[/tex]
Step-by-step explanation:
This is a geometric sequence:
[tex]a_n=a_1x^{n-1}[/tex]
where n is the index in the sequence and x is the common scale factor.
In the given sequence here, the common factor is 3:
[tex]-3\div-1=3\\-9\div-3=3\\-27\div-9=3[/tex]
That's the factor, and we know the first term is -1, so you can write the equation for this sequence:
[tex]a_n=(-1)(3)^{n-1}[/tex]
Finally, plug in 12 for n and solve:
[tex]a_{12}=(-1)(3)^{12-1}\\a_{12}=(-1)(3)^{11}\\a_{12}=(-1)177147\\a_{12}=-177147[/tex]
The supermarket has 40 aisles. 5% are empty, without any shoppers. How many empty aisles are there in the supermarket?
didn't know how to workout iam only 3rd standard
A sports store donates basketballs and soccer balls to the boys and girls club. The ratio of basket balls to soccer balls is 7:6. The store donates 24 soccer balls. How many basketballs do they donate
The number of basket balls donated is; 28 basket balls
We are told that;
Ratio of basket balls to soccer balls = 7:6
Now, the number of soccer balls donated was 24.
This, means fraction of the total number of balls x for soccer balls was; [6/(7 + 6)]x
Thus;
[6/(7 + 6)]x = 24
6x/13 = 24
6x = 24 × 13
6x = 312
x = 312/6
x = 52 balls
Now, since total balls are 52 and soccer balls are 24, then;
Number of basketballs = 52 - 24
Number of basketballs = 28 basketballs
Read more about fraction and proportions at; https://brainly.com/question/1581333
write f(2)=3 in coordinate
form (x,y)
Answer:
Coordinate form is [tex](x,y)=(2,3)[/tex]
Step-by-step explanation:
Usually the form is
[tex]f(x)=y[/tex]
Here
We have [tex]f(2)=3[/tex]
Hence [tex](x,y)=(2,3)[/tex]
Recommendations Skill plans A Math FL Standards Algebra 1 > J.10 Solve one-step and two-step equations: word problems UFG You have prize On a sunny fall day, Raymond and his family go to an orchard to pick apples for their famous apple pies. First, they pick enough Golden Delicious apples to fill a bag. Then, they pick enough Honeycrisp apples to fill another bag. The bag of Honeycrisp apples weighs 20 pounds. In all, Raymond's family picks 44 pounds of apples. Which equation can you use to find the weight w of the Golden Delicious apples? W + 20 = 44 20w = 44 W - 20 = 44 = 44 20 Solve this equation for w to find the weight of the Golden Delicious apples. pounds Submit
(a) The equation for estimating the weight W of the Golden Delicious apples is W + 20 = 44.
(b) The weight of the Golden Delicious apples is 24 pounds.
Let the weight of the Golden Delicious apples = WWeight of the Honeycrisp apples = 20 lbTotal weight of the apples = 44 lb
The equation for estimating the weight W of the Golden Delicious apples is calculated as follows;
Weight of Golden delicous apples + Weight of Honeycrisp = Total weight of the apples
W + 20 = 44
The weight of the Golden Delicious apples is calculated as follows;
W + 20 = 44
collect similar terms together;
W = 44 - 20
W = 24 lb
Learn more about word problem in Algebra here: https://brainly.com/question/17067890
(test question) If you're good at geometry please help me
Step-by-step explanation:
this is a rectangle. so, all things are symmetric.
EI = IG = FI = IH
IGF = IFG = IEH = IHE
therefore, since EI = FI
2x + 8 = 6x - 20
28 = 4x
x = 7
now,
EG = EI + IG = 2×EI = 2×(2×7 + 8) = 2×22 = 44
IFE is a complementary angle to IFG (together they have 90°).
and because IFG = IGF = 30°
IFE = 90 - 30 = 60°