On a standardized test with a normal distribution the mean score was 67. 2. The standard deviation was 4. 6. What percent of the data fell between 62. 6 and 71. 8?

Question 2 options:



95%



68%



4. 6%



13. 2%

If they use a scale factor Sin : 2ft. , approximately 14.43 square feet will the tapestry cover.

The tapestry will cover approximately 57.4 square feet.

To calculate this, first multiply the width and the length of the painting (in inches) to find the area of the painting in inches squared.

28.7 inches x 36.25 inches = 1040.375 inches squared

Then, convert the inches squared to feet squared by dividing by 144.

1040.375/144 inches squared = 7.21354 feet squared

Finally, multiply the area of the painting in feet squared by the scale factor (2 feet) to find the area of the tapestry in feet squared.

7.21354 feet squared x 2 feet = 14.42708 feet squared

Finally, round the answer to the nearest hundredth to get the answer:

14.43 feet squared, or 57.4 square feet

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The derivative of x23x is $\frac{2}{3}x^{-1/3}3^x+ x^{2/3} \ln(3)3^x$.

The functions are as follows: (a) 23x(b) 10(5−6n+n2)(c) 3x2+2(d) t2t​(e) x23xDifferentiation is the process of finding the derivative of a function or equation. The derivative of a function, in calculus, is the rate at which it changes with respect to its independent variable.

In other words, it represents the slope of the tangent line at a particular point on the graph of the function. The following are the derivatives of the functions mentioned above: (a) 23x Solution:We know that, f(x) = 23xNow, differentiating both sides of the equation with respect to x we get, $\frac{d}{dx}(f(x))= \frac{d}{dx}(23x)$Here, $\frac{d}{dx}$ is the differential operator.

It implies that we need to find the derivative of the function with respect to x.Then, $\frac{d}{dx}(23x)= 23 \frac{d}{dx}(x)$Now, $\frac{d}{dx}(x)= 1$So, $\frac{d}{dx}(f(x))= 23$Therefore, the derivative of 23x is 23. (b) 10(5−6n+n2) Solution:We know that, f(x) = 10(5−6n+n2)Now, differentiating both sides of the equation with respect to x we get, $\frac{d}{dx}(f(x))= \frac{d}{dx}[10(5−6n+n^2)]$Here, $\frac{d}{dx}$ is the differential operator.

It implies that we need to find the derivative of the function with respect to x.Then, $\frac{d}{dx}(10(5−6n+n^2))= 10 \frac{d}{dx}(5−6n+n^2)$Now, $\frac{d}{dx}(5−6n+n^2)= \frac{d}{dx}(5)- \frac{d}{dx}(6n)+ \frac{d}{dx}(n^2)$Now, $\frac{d}{dx}(5)= 0$ because 5 is a constant, and its derivative is always 0. Hence, we can ignore it.Then, $\frac{d}{dx}(6n)= 6 \frac{d}{dx}(n)$Now, $\frac{d}{dx}(n)= 1$So, $\frac{d}{dx}(6n)= 6$Then, $\frac{d}{dx}(n^2)= 2n$Therefore, $\frac{d}{dx}(f(x))= 10 (0 - 6 + 2n) = 20n - 60$Therefore, the derivative of 10(5−6n+n2) is 20n - 60. (c) 3x2+2 Solution:We know that, f(x) = 3x2+2Now, differentiating both sides of the equation with respect to x we get, $\frac{d}{dx}(f(x))= \frac{d}{dx}(3x^2+2)$Here, $\frac{d}{dx}$ is the differential operator.

It implies that we need to find the derivative of the function with respect to x.Then, $\frac{d}{dx}(3x^2+2)= 3 \frac{d}{dx}(x^2)+ \frac{d}{dx}(2)$Now, $\frac{d}{dx}(x^2)= 2x$So, $\frac{d}{dx}(f(x))= 3(2x)+ 0 = 6x$Therefore, the derivative of 3x2+2 is 6x. (d) t2t​ Solution:We know that, f(x) = t2t​Now, differentiating both sides of the equation with respect to x we get, $\frac{d}{dx}(f(x))= \frac{d}{dx}(\frac{t^2}{t})$Here, $\frac{d}{dx}$ is the differential operator.

It implies that we need to find the derivative of the function with respect to x.Then, $\frac{d}{dx}(\frac{t^2}{t})= \frac{d}{dx}(t^{2-1})$Now, $\frac{d}{dx}(t^{2-1})= 1 t^{2-1-1} \frac{d}{dx}(t)$So, $\frac{d}{dx}(t)= 0$ because t is a constant. Hence, we can ignore it.Then, $\frac{d}{dx}(f(x))= 1 t \frac{d}{dx}(t)= t$Therefore, the derivative of t2t​ is t. (e) x23x Solution:We know that, f(x) = x23xNow, differentiating both sides of the equation with respect to x we get, $\frac{d}{dx}(f(x))= \frac{d}{dx}(x^{2/3}3^x)$Here, $\frac{d}{dx}$ is the differential operator.

It implies that we need to find the derivative of the function with respect to x.Then, $\frac{d}{dx}(x^{2/3}3^x)= \frac{d}{dx}(x^{2/3})3^x+ x^{2/3} \frac{d}{dx}(3^x)$Now, $\frac{d}{dx}(x^{2/3})= \frac{2}{3}x^{-1/3}$Then, $\frac{d}{dx}(3^x)= \ln(3)3^x$So, $\frac{d}{dx}(f(x))= \frac{2}{3}x^{-1/3}3^x+ x^{2/3} \ln(3)3^x$Therefore, the derivative of x23x is $\frac{2}{3}x^{-1/3}3^x+ x^{2/3} \ln(3)3^x$.

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The area of the triangle ABC is 87.176 cm square.

A triangle is a polygon with three vertices and three sides. The internal angle of the triangle, which is 180 degrees, is built. It means that a triangle's internal angles sum to 180 degrees. It has the fewest sides of any polygon. Instead, a triangle is a three-sided, two-dimensional geometry with internal angles that are 180°.

A triangle with a right angle of 90 degrees is equivalent to one of a triangle's angles.

Triangles abc and acd. ACD is 108 cm square in size. Calculate ABC's area.

Given: ACD is 108 cm square in size.

Area of ACD = 108, thus calculate the area of ABC.

[tex]\frac{1}{2}*CD*AC=108\\\\\frac{1}{2}*16*AC=108\\\\8*AC=108\\\\AC=\frac{108}{8}\\\\Area\ (ABC)=\frac{1}{2}*AC*BC*sin38,\\ = \frac{1}{2}*\frac{27}{2}*21*sin38\\=87.176 cm^2[/tex]

[tex]\frac{1}{2}*CD*AC=108\\\\\frac{1}{2}*16*AC=108\\\\8*AC=108\\\\AC=\frac{108}{8}\\\\Area\ (ABC)=\frac{1}{2}*AC*BC*sin38,\\ = \frac{1}{2}*\frac{27}{2}*21*sin38\\=87.176 cm^2[/tex]

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The dimensions of the pool should be 8 feet deep, 13 feet wide, and 43 feet long.

Let's assume that the depth of the pool is "x".

Given that the width is 5 feet more than the depth, then the width is x + 5.

Also, the length is 35 feet more than the depth, then the length is x + 35.

The volume of the pool is 2000 cubic feet, then:

length x width x depth = 2000

(x + 35) (x + 5) (x) = 2000

x^3 + 40x^2 + 175x - 2000 = 0

We can use trial and error or synthetic division to find that one of the roots of this cubic equation is x = 8.

Therefore, the depth of the pool is 8 feet.

The width is x + 5 = 8 + 5 = 13 feet.

The length is x + 35 = 8 + 35 = 43 feet.

So, the dimensions of the pool should be 8 feet deep, 13 feet wide, and 43 feet long.

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The foreshadowing of Mr. and Mrs. White and Herbert ignoring the warnings about the danger of the supernatural helps to build suspense and create a sense of foreboding, thus helping to establish the theme of the story.

If that is the case, then yes, the White family ignoring the warnings about the danger of the supernatural helps develop the theme of the story. The story explores the consequences of tempting fate and meddling with the unknown, as the family's wishes on the cursed monkey's paw lead to tragic and horrifying outcomes.

The foreshadowing of danger through warnings and ominous hints, such as the Sergeant-Major's tales and the paw's sinister appearance, underscores the gravity of the situation and the potential consequences of the family's actions. However, the White family disregards these warnings and ultimately pays the price for their curiosity and greed.

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The total amount of fees for each bank is First state bank = $8, National bank = $12.50, and third city bank = $9.

The fundamentals of mathematics are arithmetic operations. Operations like addition, subtraction, multiplication, and division make up the majority of it. Sometimes referred to as mathematical operations, these. In daily life, we employ mathematical operations to calculate overall business revenue and costs, create monthly or yearly budgets, measure distances, and more. We use them nearly constantly throughout the day. For instance, we use them to calculate the overall amount of homework problems, time, money, the number of chocolates we ate, the total number of grades we received across all courses, etc.

Given that, one month you write 5 checks and use bank's ATM machine 3 times, you use a non bank ATM twice and your debit card 8 times

The total amount for first state bank is:

C = 5(1) + 3(1) = $8

The total amount for National bank is:

C = 12.50

The total amount for third city bank is:

C = 3(1) + 8(0.75) = 9

Hence, the total amount of fees for each bank is First state bank = $8, National bank = $12.50, and third city bank = $9.

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there are 10,626 possible ways to select a president, a secretary, and a treasurer from a board of directors with 23 members.

To solve this problem, we can use the formula for permutations, which is:

P(n, r) = n! / (n - r)!

where n is the total number of items, and r is the number of items selected.

In this case, we need to select 3 people from a group of 23, without replacement and order matters. Therefore, the number of ways to do this is:

P(23, 3) = 23! / (23 - 3)!

= 23! / 20!

= 23 x 22 x 21

= 10,626 possible ways

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Answer:

Step-by-step explanation:

i don't know

Answer: 447/3

Feet to yards is every three feet is one yard

Step-by-step explanation:

447 divided by 3 equals 149 yards

The two expressions used to solve the product are 3 * (3/6)  and (3/1) * (1/2). The product of the given expression is 3/2.

A fraction is a number that expresses a portion of a total or the relationship between two quantities. Normally, it is written with a horizontal line separating the numerator from the denominator. The denominator represents the entirety or the second number, whereas the numerator represents a portion of the total or the first amount. The simplest way to multiply a fraction is to add the numerators and denominators together.

The product of 3 and (3/6), is:

3 * (3/6) = (3 * 3) / 6 = 9/6 = 3/2

Therefore, the product of 3 and (3/6) is 3/2.

Another expression that is equivalent to the product of 3 and (3/6) is:

3 * (3/6) = (3/1) * (1/2) = 3/2

This expression is equivalent to the previous one, as both represent the same value of 3/2.

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The longer side of the Quadrilateral/Parallelogram is approximately 16.28 cm.

what are quadrilaterals?

Quadrilaterals are geometric figures with four sides and four angles. They are two-dimensional shapes that can be classified based on their properties such as angles, side lengths, and symmetry.

Now,

Let's denote the shorter side of the parallelogram by x and the longer side by y. Since opposite sides of a parallelogram are congruent, the perimeter of the parallelogram is:

2x + 2y = 80

Simplifying this equation, we get:

x + y = 40

Now, let's consider the diagonal that is perpendicular to one of the sides. This diagonal divides the parallelogram into two right triangles. Let's denote the length of the altitude (or height) of each right triangle by h, as shown in the diagram below:

         /|\

       /  |  \

     /    |    \

   /______|______

           20 cm

Using the Pythagorean theorem, we have:

h² + (x/2)² = 20²

Simplifying this equation, we get:

h² + x²/4 = 400

4h² + x² = 1600

Since h is also the height of the parallelogram, we know that h is perpendicular to the longer side y. Thus, we have:

h² + y² = (2h)²

h² + y² = 4h²

Substituting the value of h² from the first equation into the second equation, we get:

x²/4 + y² = 4(400 - x²/4)

x² + 4y² = 1600

Substituting x = 40 - y from the perimeter equation, we get:

(40 - y)² + 4y² = 1600

5y² - 80y + 400 = 0

y² - 16y + 80 = 0

Using the quadratic formula, we get:

y = (16 ± √(16² - 4*80))/2

y = 8 ± √(14)

Since y must be greater than x, we take the larger value of y:

y = 8 + √(14)

Therefore, the longer side of the parallelogram is approximately 16.28 cm.

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As a result, the exponential function travelling between the points (5, 32567) and (4, 16189) has the following formula: function  [tex]f(x) = 14000 * (1.007044628)^x[/tex]

Mathematicians examine numbers with their modifications, equations and associated structures, forms and their locations, and feasible positions for these things. The term "function" indicates the connection between a collection of inputs, each of which has a corresponding output. A function is a connection of inputs and outputs where each supply leads to a specific, identifiable outcome. Each function is assigned a domain, a codomain, or a scope. The letter f is widely used to denote functions (x). The symbol for entry is an x. The four primary types of accessible capabilities are on functions, yet another skills, so multiple capabilities, in capabilities, and on operations.

f(x) = a * bx, where a and b are unknown constants. We have two places through which the function passes, which implies we have two equations:

[tex]f(5) = a * b^5 = 32567 f(4) = a * b^4 = 16189[/tex]

When we divide these two equations, we get:

[tex]b^5 / b^4 = 32567 / 16189 b = (32567 / 16189)^(1/1) = 1.007044628[/tex]

We may solve for a by substituting this value of b in any of the equations:

[tex]a = 16189 / b^4 = 16189 / (1.007044628)^4 = 14000[/tex]

As a result, the exponential function travelling between the points (5, 32567) and (4, 16189) has the following formula:

[tex]f(x) = 14000 * (1.007044628)^x[/tex]

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The sample is large enough, random, and representative of the population being studied to avoid biased results.

The following list of potential sampling flaws that can result in biassed results is based on the information provided:

Limited sample size: Of the 30,000 batteries produced that day, the manager only examined 100 of them. It's possible that this sample size is insufficient to adequately represent the full population of batteries. A bigger sample size can yield more reliable results.

Non-random sampling: It's unclear how the manager decided to test 100 batteries. The outcomes might be skewed if the selection wasn't random or if there was any bias throughout the selection procedure.

Selection from a non-representative subset of the population: It is unclear if the 100 batteries that were subjected to inspection were drawn at random from the full population of batteries manufactured that day or merely from a particular section of the production line. The results might not be representative of the whole population of batteries manufactured that day if the batteries were only collected from a portion of the production line.

Confirmation bias: The manager's inspection procedure may have been prejudiced inadvertently, looking for more of what they anticipated to see. For instance, the management might have been more inclined to identify more batteries as being in good condition if they had expected the batteries to be of high quality, which could have skewed the results.

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a) The probability that a randomly selected box contains at least one defective bulb is approximately 0.099. b) The probability that a randomly selected box contains at most one defective bulb is approximately 0.9998.

a) To find the probability that a randomly selected box contains at least one defective bulb, we can use the complement rule: the probability of the complement of the event (no defective bulbs) is easier to calculate. The probability that a bulb is not defective is 199/200, so the probability that all 20 bulbs in a box are not defective is (199/200)²⁰. Therefore, the probability that at least one bulb is defective is:

1 - (199/200)²⁰ ≈ 0.099

So the probability that a randomly selected box contains at least one defective bulb is approximately 0.099.

b) To find the probability that a randomly selected box contains at most one defective bulb, we can calculate the probability of each possible outcome (0, 1, or 2 defective bulbs) and add them up.

The probability of no defective bulbs is (199/200)²⁰ ≈ 0.9048.

The probability of exactly one defective bulb is:

20C1 * (1/200) * (199/200)¹⁹ ≈ 0.0950

where 20C1 is the number of ways to choose one defective bulb out of 20.

The probability of two defective bulbs is:

20C2 * (1/200)² * (199/200)¹⁸ ≈ 0.0002

where 20C2 is the number of ways to choose two defective bulbs out of 20.

Therefore, the probability of at most one defective bulb is:

0.9048 + 0.0950 ≈ 0.9998

So the probability that a randomly selected box contains at most one defective bulb is approximately 0.9998.

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The constant of variation is [tex]\frac{1}{8}[/tex].

The discrepancy among an ideal and real scenario is referred to as the Law of Variation. The most frequent manifestations of variation or variability are changes in the data, anticipated results, or minor changes in the quality of the output.

The types of variation are given below-

According to the question;

A quantity m varies jointly with p and r which shows that p and r in joint variation with m.

m ---> pr

m = kpr

where, k is the constant of variation.

m = 1, p = 2, r = 4.

Substitute the values in the relation,

1 = k(2)(4)

1  = 8k

k = 1/8

Therefore, the constant of variation is [tex]\frac{1}{8}[/tex].

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The constant of variation is 1/8, which is option A.

What is variation?

The way in which a quantity changes or varies with respect to another quantity. There are two types of variation: direct variation and inverse variation. Direct variation occurs when two quantities change in the same direction. In other words, if one quantity increases, the other quantity also increases.

y = kx, where y and x are the two quantities, and k is a constant of proportionality.

Inverse variation occurs when two quantities change in opposite directions. In other words, if one quantity increases, the other quantity decreases.

y = k/x, where y and x are the two quantities, and k is a constant of proportionality.

If m varies jointly with p and r, we can write the relationship as:

m = k * p * r

where k is the constant of variation.

We are given that when p is 2 and r is 4, m is 1. Substituting these values into the equation, we get:

1 = k * 2 * 4

Simplifying this equation, we get:

k = 1 / (2 * 4)

k = 1/8

Therefore, the constant of variation is 1/8, which is option A.

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Answer:

Larger number: 39

Smaller number: 19

Step-by-step explanation:

Write two equations and solve the system of equations.

One number can be x. The other number can be y.

"sum" means adding.

x + y = 58

"difference" means subtracting.

x - y = 20

Take both equations, stack them and add them together from the top down.

x + y = 58

x - y = 20

_________

2x = 78

Divide by 2

x = 39

Use either original equation to find the other number.

x + y = 58

39 + y = 58

subtract 39

y = 19

The bigger number is 39 and the smaller number is 19.

A minimum sample size of 1399 is required assuming a prior knowledge of the sample proportion of 11%, and a minimum sample size of 960 is required if no prior knowledge of the sample proportion is assumed.

To obtain an estimate of the percentage of U.S. adults with pinworm with an error of no more than 1.5 percentage points at a 95% confidence level, a minimum sample size of 1399 is required, assuming prior knowledge of the sample proportion of 11%.

However, if no prior knowledge of the sample proportion is assumed, a minimum sample size of 960 is required.

To calculate the minimum sample size, the formula n = (Z² * p * (1-p)) / E² is used, where n is the sample size, Z is the Z-value for the desired confidence level (1.96 for 95% confidence), p is the prior sample proportion, and E is the desired margin of error.

Therefore, assuming a prior knowledge of the sample proportion of 11%, a sample size of 1399 was needed. If no prior knowledge was assumed, a minimum sample size of 960 was required.

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we will multiply x by both terms in the parentheses, giving us x²+2x. Then, we will subtract 1 from this expression, leaving us with x²+2x-1. Therefore, the expanded expression is x²+2x-1.

x(x+2) - 1To rewrite the expression x²+x-2 as a product of two factors, we will use algebraic factoring. First, we will factor out the greatest common factor from the expression, which is x. We do this by dividing each term in the expression by x, leaving us with x+2 and -1. The expression can now be written as x(x+2) - 1. This expression is the product of two factors x and (x+2) - 1.

x²+2x-1 To expand the expression x(x+2) - 1, we will use the distributive property. First, we will multiply x by both terms in the parentheses, giving us x²+2x. Then, we will subtract 1 from this expression, leaving us with x²+2x-1. Therefore, the expanded expression is x²+2x-1.

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The speed of the plane in still air is 87 mph and the speed of the wind is 29 mph.

The cost of one package of tulip bulbs is $10.8 and the cost of one bag of daffodil bulbs is $8.5.

A van can carry 14 students and a bus can carry 62 students.

There are 13 students in each van and 59 students in each bus.

Let the speed of the plane be p and the speed of the wind be w. Then we have the following system of equations:

p + w = d/t1 = 580/5 = 116

p - w = d/t2 = 580/10 = 58

Adding the two equations, we get:

2p = 174

p = 87 mph

Substituting this value into either equation, we get:

w = 29 mph

Therefore, the speed of the plane in still air is 87 mph and the speed of the wind is 29 mph.

Let the cost of one package of tulip bulbs be x and the cost of one bag of daffodil bulbs be y. Then we have the following system of equations:

6x + 12y = 198

7x + 6y = 127

Multiplying the second equation by 2 and subtracting it from the first equation, we get:

5x = 54

x = 10.8

Substituting this value into either equation, we get:

y = 8.5

Therefore, the cost of one package of tulip bulbs is $10.8 and the cost of one bag of daffodil bulbs is $8.5.

Let the number of students a van can carry be x and the number of students a bus can carry be y. Then we have the following system of equations:

16x + 8y = 752

5x + 5y = 380

Simplifying the second equation, we get:

x + y = 76

Multiplying this equation by 8 and subtracting it from the first equation, we get:

8x = 112

x = 14

Substituting this value into either equation, we get:

y = 62

Therefore, a van can carry 14 students and a bus can carry 62 students.

Let the number of students a van can carry be x and the number of students a bus can carry be y. Then we have the following system of equations:

16x + 5y = 417

10x + 8y = 480

Multiplying the first equation by 2 and subtracting it from the second equation, we get:

6x = 42

x = 7

Substituting this value into either equation, we get:

y = 51

Therefore, a van can carry 7 students and a bus can carry 51 students.

Let the number of students in each van be x and the number of students in each bus be y. Then we have the following system of equations:

14x + 16y = 1086

10x + 13y = 870

Multiplying the first equation by 13 and subtracting it from the second equation multiplied by 16, we get:

2x = 26

x = 13

Substituting this value into either equation, we get:

y = 59

Therefore, there are 13 students in each van and 59 students in each bus.

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7) A plane traveled 580 miles to Ankara and back. The trip there was with the wind. It took 5 hours. The trip back was into the wind. The trip back took 10 hours. Find the speed of the plane in still air and the speed of the wind.

8) Amanda and Ndiba are selling flower bulbs for a school fundraiser. Customers can buy packages of tulip bulbs and bags of daffodil bulbs. Amanda sold 6 packages of tulip bulbs and 12 bags of daffodil bulbs for a total of $198. Ndiba sold 7 packages of tulip bulbs and 6 bags of daffodil bulbs for a total of $127. Find the cost each of one package of tulips bulbs and one bag of daffodil bulbs.

9) The local amusement park is a popular field trip destination. This year the senior class at High School A and the senior class at High School B both planned trips there. The senior class at High School A rented and filled 16 vans and 8 buses with 752 students. High School B rented and filled 5 vans and 5 buses with 380 students. Each van and each bus carried the same number of students. How many students can a van carry? How many students can a bus carry?

10) The senior classes at High School A and High School B planned separate trips to New York City. The senior class at High School A rented and filled 16 vans and 5 buses with 417 students. High School B rented and filled 10 vans and 8 buses with 480 students. Every van had the same number of students in it as did the buses. How many students can a van carry? How many students can a bus carry?

11) The senior classes at High School A and High School B planned separate trips to the water park. The senior class at High School A rented and filled 14 vans and 16 buses with 1086 students. High School B rented and filled 10 vans and 13 buses with 870 students. Every van had the same number of students in it as did the buses. Find the number of students in each van and in each bus.

The factoring method is a technique used to solve quadratic equations of the form ax^2 + bx + c = 0, where a, b, and c are constants and x is the variable. To use the factoring method, we need to find two numbers that multiply to give c and add to give b. We then use these two numbers to factor the quadratic expression into two binomials, set each binomial equal to zero, and solve for x.

The format of a problem that can be solved using the factoring method should be in the form of ax^2 + bx + c = 0, where a, b, and c are constants and x is the variable. The quadratic expression should be factorable into two binomials.

The factoring method can be applied to any quadratic problem that is in the correct format and is factorable. However, not all quadratic equations can be factored. In cases where the quadratic expression cannot be factored, we need to use other methods such as the quadratic formula or completing the square.

The main limitation of the factoring method is that it only works for quadratic equations that can be factored into two binomials. If the quadratic equation cannot be factored or if it has complex roots, then the factoring method cannot be used to solve the problem.

We make each factor equal to zero because if the product of two factors is zero, then at least one of the factors must be zero. Therefore, we set each factor equal to zero and solve for x to find the roots of the quadratic equation.

Therefore , the solution of the given problem of unitary method comes out to be the distance between Barry and Dillon is roughly 6.2 feet.

Using the unilateral approach, the task can be completed by increasing the information obtained from such a nanosection by two. In essence, that whenever a wanted item emerges, the colour area of both the production runs were either skipped or the defined entity is set. For forty pens, a variable charge of Inr ($1.01) could have been required.

Here,

We can use a diagram to show the three passengers' locations on the bus in order to solve this issue:

Let x serve as a proxy for the separation between Barry and Dillon.

Using the knowledge provided, we can create two equations:

Barry is five steps away from Julian.

=> x² +d² = 5.

They are eight feet apart, Dillon and Julian.

Duplicate the formula

d = distance between Barry and Dillon (d = x² + 8² ).

The two formulae can be made equal to one another in order to find d:

=> x² + 5² = x² + 8²

=> 25 = 64 - x²

=> x² = 39

=> x ≈ 6.2

This means that, rounded to the closest tenth, the distance between Barry and Dillon is roughly 6.2 feet.

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Answer:

6.2 ft

Step-by-step explanation:

To find:-

Answer:-

On drawing a figure representing the given situation , we get a right angled triangle . To find out the distance between Barry and Dillon we can use Pythagoras theorem, according to which;

[tex]\rm\implies h^2=a^2+b^2\\[/tex]

Here h is the longest side and a and b are two other sides. And in this question, hypotenuse is 8ft . One of the other side is 5ft .

On substituting the respective values , we have ;

[tex]\rm\implies 8^2 = 5^2+a^2 \\[/tex]

[tex]\rm\implies 64 = 25 + a^2\\[/tex]

[tex]\rm\implies 64 - 25 = a^2 \\[/tex]

[tex]\rm\implies 39 = a^2 \\[/tex]

[tex]\rm\implies a =\sqrt{39}\\[/tex]

[tex]\rm\implies \red{ a = 6.2 } \\[/tex]

Hence the distance between Barry and Dillon is 6.2 ft. (nearest tenth) .

60

8.43

alternative hypothesis

(a) The hypotheses for this question are:

1) H0: μ = 60  
Ha: μ > 60

2) H0: μ = 60  
Ha: μ < 60

3) H0: μ = 60
Ha: μ ≠ 60

(b) The test statistic is calculated as:
t = (103-60)/(35/√32) = 8.43

(c) Based on a significance level of α = 0.01, the correct conclusion for the hypothesis test is that the mean chirp rate for crickets on a high-protein diet is greater than 60 chirps per second, as the test statistic (8.43) is greater than the critical value (2.58). Therefore, we can reject the null hypothesis and accept the alternative hypothesis.

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The box plots show the average wind speeds, in miles per hour, for various cities in two different countries.

Box plots are graphical representations of data that summarize important features such as the center, spread, and shape of a distribution. In this case, the box plots show the average wind speeds, in miles per hour, for different cities in two different countries.

The box in the plot represents the middle 50% of the data, with the line inside the box showing the median. The whiskers extend to the minimum and maximum values of the data, excluding any outliers, which are shown as individual points outside the whiskers.

Comparing the box plots for the two countries, we can see that the average wind speeds for the cities in Country A are generally lower than those in Country B. The box in Country A is shorter and closer to the bottom of the plot, indicating less variability in the data. Meanwhile, the box in Country B is taller and more spread out, suggesting a wider range of wind speeds across the cities.

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Based on the box plot, which type of Raina's squash has a higher median length?

π/4 [2 + 1/5x] is the equation that expresses the cross-sectional area of the bar as a function of the position, x, along the length. The area of a circle is given by A=πr2.

Let us now consider a uniformly tapering circular bar having length,

L = 10 inches

and having diameter,

d₁ = 2 inches

at one end and

d₂ = 4 inches

at the other end, therefore we know that d₂ > d₁

let us consider a very short section xx of length kx and diameter dx, situated at a distance x from end A

now diameter, dx = d₁ + (d₂ - d₁)x

= d₁ + kx

where k = d₂ - d₁/ L

= 4-2/10 = 2/10 = 1/5

cross section area of the given circular bar 1

π/4 d₁²

π/4(d₁+Kx)

π/4 [2 + 1/5x]

here the cross section over 1x function of the given position of x, along the length.

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Answer:

5 gallons of 70% antifreeze, 1 gallon of 45% antifreeze

Step-by-step explanation:

Many different combinations can be made to equal 65% pure antifreeze.

Essentially, this problem is asking us to find a combination that fits a mean of 65%. So, multiply 5 by 70 to get 350, and 1 x 45 to get 45. Add 350 + 45 together to get 395, and divide by the total amount of gallons used - 6.

395/6 = 65, which is the target value.

a) Interval(s) of the domain in which the water balloon's height increasing is from x = 0 to x = 2.

b)  Interval(s) of the domain in which the water balloon's height staying the same is from x = 2 to x = 4.

c) Interval(s) of the domain in which the water balloon's height decreasing the fastest is from x = 8 to x = 10.

d) The predicted height of the water balloon at 14 seconds is 82 feet.

a) The water balloon's height is increasing from x = 0 to x = 2 seconds, as the height goes from 26 feet to 34 feet.

b) The water balloon's height is staying the same from x = 2 seconds to x = 4 seconds, as the height remains at 34 feet.

c) The water balloon's height is decreasing the fastest from x = 8 seconds to x = 10 seconds, as the height drops from 30 feet to 0 feet over a span of only 2 seconds. During this interval, the balloon is likely hitting the ground.

d) To predict the height of the water balloon at 14 seconds, we need to find the corresponding value of f(x) on the linear model. Since the given ordered pairs only go up to x = 12 seconds, we need to use the equation of the line to extrapolate beyond that point.

We can first find the slope of the line using any two of the ordered pairs. Let's use (0, 26) and (2, 34):

slope = (34 - 26) / (2 - 0) = 4

Using the point-slope form of the equation, we can write the equation of the line as:

f(x) - 26 = 4(x - 0)

f(x) = 4x + 26

To predict the height at 14 seconds, we can simply substitute x = 14 into the equation:

f(14) = 4(14) + 26

f(14) = 82

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Complete question is:

The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in seconds:

A linear model with ordered pairs at 0, 26 and 2, 34 and 4, 34 and 8, 30 and 10, 0 and 12, 0. The x axis is labeled Time in seconds, and the y axis is labeled Height in feet.

a) During what interval(s) of the domain is the water balloon's height increasing? (2 points)

b) During what interval(s) of the domain is the water balloon's height staying the same? (2 points)

c) During what interval(s) of the domain is the water balloon's height decreasing the fastest? Use complete sentences to support your answer. (3 points)

d) Use the constraints of the real-world situation to predict the height of the water balloon at 14 seconds. Use complete sentences to support your answer. (3 points)

Therefore , the solution of the given problem of probability comes out to be P = 0.8236 ,  P= 0.0155 and P = 0.0203

The calculation of the probability that a statement is true or that a particular event will happen is the main objective of the patterns in the form known as hyperparameters. Chance can be represented by any number from range  0 and 1, where 1 typically signifies certainty and 0 typically signifies potential. A probability diagram illustrates the likelihood that a particular occurrence will take place.

Here,

Based on the survey findings, let p represent the likelihood that an executive thinks workers are most productive on Tuesdays: p = 0.48

Suppose there were n leaders who were surveyed: n = 190

Using Appendix A and the binomial distribution method, we can calculate:

=> P(X < 85) = P(X ≤ 84) = 0.0155

b. To determine the likelihood that more than 95 of the executives think that workers are most effective on Tuesdays, use Appendix A and the complement rule.

=> P(X > 95) = 1 - P(X ≤ 95) = 1 - 0.9797 = 0.0203

c. We need to compute P(X > 79) to determine the likelihood that more than 79 executives think workers are most productive on Tuesdays. This can be done using the complement rule and Appendix

A:

=> P(X > 79) = 1 - P(X ≤ 79) = 1 - 0.1764 = 0.8236

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