Answers
Answer:
hope it helps...
Step-by-step explanation:
Related Questions
The length of a rectangular garden is 8m greater than twice the width the area of the garden is 280m^2 what is the width of the garden
Answers
Step-by-step explanation:
Given :-
The length of the garden 8m greater than 2 times the width.
Area of the garden is 280 m²
Let us consider the length as x and width as y.
Sp, we can day length as :-
x = 8 + 2y ---(1)
Now, we know that:-
Area of Rectangle = Length × Breadth
280 = x * y
We can replace the value of x now,
280 = y × ( 8 + 2y)
280 = 8y + 2y²
2y² + 8y - 280 = 0
y² + 4y - 140 = 0
Factorise it.
(y -10)(y + 14)
Cancelling -ve value, we get the width as 10 metres.
Hope it helps :)
Answer:
Step-by-step explanation:
Width = w
Length = 2w + 8
Area of rectangular garden = 280 square meter
length * width = 280
(2w + 8 ) *w = 280
2w * w + 8*w = 280
2w² + 8w = 280
2w² + 8w - 280 = 0
Divide the whole equation by 2
w² + 4w - 140 = 0
w² + 14w - 10w - 14 *10 = 0
w(w + 14) - 10(w + 14) = 0
(w + 14)(w - 10)= 0
w - 10 = 0 {Ignore w + 14, as measurements will not be -ve}
w = 10 m
l = 2*10 +8
= 20 +8
l = 28 m
solve 7!!!!!!!!!!!!!!!!!!!!!!!
Answers
Answer:
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Step-by-step explanation:
Determine the equation of a circle with center at (8, 10) and radius is 6
Answers
Where (h,k) is the center and the r is the radius . So the equation is as follows
( x- 8 ) ^2 + ( y -10 ) ^ 2 = 6^2
Hope this helped
Find the limit when X approaches zero
2xsinx/1-cosx
Answers
Answer:
4
Step-by-step explanation:
[tex] Lim_{x \to 0}\frac{2 x\sin x}{1-\cos x} [/tex]
[tex] =Lim_{x \to 0}\frac{2 x\sin x}{1-\cos x}\times \frac{1+\cos x}{1+\cos x} [/tex]
[tex] =Lim_{x \to 0}\frac{2 x\sin x(1+\cos x) }{1^2 -\cos^2 x} [/tex]
[tex] =Lim_{x \to 0}\frac{2 x\sin x(1+\cos x) }{1 -\cos^2 x} [/tex]
[tex] =Lim_{x \to 0}\frac{2 x\sin x(1+\cos x) }{sin^2 x} [/tex]
[tex] =Lim_{x \to 0}\frac{2x(1+\cos x) }{sin x} [/tex]
[tex] =Lim_{x \to 0} 2(1+\cos x) \times \frac{1}{Lim_{x \to 0}\frac{sin x}{x}} [/tex]
[tex] =2(1+\cos 0) \times 1 [/tex]
[tex] = 2(1+1) [/tex]
[tex] = 2(2) [/tex]
[tex] \therefore Lim_{x \to 0}\frac{2 x\sin x}{1-\cos x}= 4 [/tex]
Drag each tile to the table to multiply
(6x – y)(2x – y + 2).
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fill the table
2x -y 2
6x 12^2 -6xy 12x
-y -2xy y^2 -2y
1. Kathy is building a bed for her dollhouse. She used her real bed as a guide for how to
create the dollhouse bed. Her bed is 36 inches wide and 60 inches long. If she wants
to scale this down by 1/10, what would be the dimensions of the dollhouse bed?
Explain how you got your answer.
*Use the term SCALE FACTOR in your explanation.
PLS ANSWER QUICKLY !!!