Mr. Stansbury went grocery shopping on Tuesday and bought 4 pounds of oranges for $10.88. What is the unit price per ounce?

Answer:

96 oz

Step-by-step explanation:

1 lb= 16 oz

so, 16×6=96

Answer:

C,

Step-by-step explanation:

A and D is incorrect because they are negative correlation

and B is incorrect because a correction of 0.95 means all values are close to each other, but B values are scattered much more that C values

so answer C

Answer:

60 degrees

Step-by-step explanation:

Similar shapes have the same angles but different side lengths.

Answer:

The answer is 60°

Step-by-step explanation:

Because pentagon JKLMN is basically the same as pentagon VWXYZ and if you see in the smaller pentagon the angle for L is 90° and same goes for the bigger pentagon

Answer: 130cm

Let's think the width of the rectangle as, "x"

45*x= 900

x= 900/45

x= 20

45+45+20+20

= 130cm

Answer:

[tex] \frac{2}{5} > \frac{1}{6} [/tex]

Answer: B. >

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Step-by-step explanation:

1 10.38

2 16.77

3 11.499

4 11.486

5 0.0947

6 30.52875

7 525

8 32.57862069

9 16.5625

Answer:

x = 2.6, y = 2.2

Step-by-step explanation:

if 4y = 2 + 3x - 1 and

y = 2x - 3,

4y = 2 + 3x -1 and 4y = 8x - 12 so

8x - 12 = 2 + 3x - 1

so 5x - 12 = 1,

5x = 13,

x = 2.6

If x = 2.6,

y = 5.6 - 3

so y = 2.2

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Answer:

84

Step-by-step explanation:

TPS + SPR = RPT and TPS = RPT - SPR

The measure of RPT and SPR are given so we just need to place them and do the calculation

TPS = 137 - 53

TPS = 84

Step-by-step explanation:

we use the law of sine :

sin(A)/a = sin(B)/b = sin(C)/c

with the related angles being opposite of the lines.

so, we have

sin(A)/1 = sin(A) = sin(90)/ sqrt(10) = 1/ sqrt(10) =

= 0.316227766...

cos²(A) + sin²(A) = 1

cos(A) = sqrt(1 - sin²(A)) = sqrt(1 - 0.1)) = sqrt(0.9) =

= 0.948683298...

tan(A) = sin(A)/cos(A) = 0.333333333...

cot(A) = 1/tan(A) = 3

sec(A) = 1/cos(A) = 1.054092553...

csc(A) = 1/sin(A) = 3.16227766...

Answer:

4(1.25) = if it’s only one month then it’s 5 miles

Step-by-step explanation:

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Step-by-step explanation:

-0.5 cause decimals and fraction are not included

Answer:

 (c)  p = vm

Step-by-step explanation:

Momentum, represented by 'p', is the product of mass and velocity. It is a vector quantity, just as velocity is a vector quantity.

  p = vm

Answer:

Perimeter = 12 1/2 in

Area = 9.375 in

Step-by-step explanation:

Perimeter:

(3 3/4) + (3 3/4) + (2 1/2) + (2 1/2) = 12 1/2

Area:

(3 3/4) * (2 1/2) = 9.375

Answer:

P = 12 1/2 in

A = 9 3/8 in²

Step-by-step explanation:

L = 3 3/4 in

W = 2 1/2 in

Area:

A = L × W

A = (3 3/4 in)(2 1/2 in)

A = 15/4 in × 5/2 in

A = 75/8 in²

A = 9 3/8 in²

Perimeter:

P = 2(L + W)

P = 2(3 3/4 in + 2 1/2 in)

P = 2(15/4 in + 5/2 in)

P = 2(15/4 in + 10/4 in)

P = 2(25/4 in)

P = 25/2 in

P = 12 1/2 in

Answer:

0.459

the 9 rounds the 5 up to a 6 so its 0.46

Answer:

The answer is 0.46

Step-by-step explanation:

The 9 is over 5, so you round up which bumps the 5 up to a 6. It could also be written as 0.460 but the extra 0 is unnecessary.

Answer:30 drinks

Step-by-step explanation:

Answer:step 2

Step-by-step explanation:

Answer:

C. (10 - 2) ÷ 4

Step-by-step explanation:

To determine which expression represent a number that is one fourth as great as 10-2 the following logical reasoning has to be made:

Given that a number is raised that is a quarter as large as (10-2), the result of this mathematical operation must be divided by 4.

Thus, since 10 minus 2 is equal to 8 and 8 divided by 4 gives 2, the division is necessary as a mathematical operation.

So, since the only option that raises a division is option C, that's the correct option.

a) The value of [tex]k'(0)[/tex] is [tex]\frac{3\sqrt{3}}{2}[/tex].

b) The value of [tex]m'(5)[/tex] is approximately -0.034.

c) The value of [tex]x[/tex] is approximately 0.622.

a) [tex]f(x)[/tex] is a piecewise function formed by two linear functions, whose form is defined by the following definition:

[tex]f(x) = \frac{y_{2}-y_{1}}{x_{2}-x_{1}} \cdot x + b[/tex] (1)

Where:

Now we proceed to determine the linear functions:

Line 1: [tex]x \in [-1, 2)[/tex]

[tex](x_{1}, y_{1}) = (0, 3)[/tex], [tex](x_{2}, y_{2}) = (1, 5)[/tex], [tex]b = 3[/tex]

[tex]f(x) = \frac{5-3}{1-0}\cdot x + 3[/tex]

[tex]f(x) = 2\cdot x + 3[/tex]

Line 2: [tex]x \in [2, 8][/tex]

[tex](x_{1}, y_{1}) = (2, 7)[/tex], [tex](x_{2}, y_{2}) = (8, 3)[/tex]

First, we determine the slope of function:

[tex]m = \frac{3-7}{8-2}[/tex]

[tex]m = -\frac{2}{3}[/tex]

Now we proceed to determine the intercept of the linear function:

[tex]7 = -\frac{2}{3}\cdot 2 + b[/tex]

[tex]b = \frac{25}{3}[/tex]

[tex]f(x) = -\frac{2}{3}\cdot x +\frac{25}{3}[/tex]

The first derivative of a linear function is its slope, and the first derivative of a product of functions is defined by:

[tex]k'(x) = f'(x)\cdot g(x) + f(x)\cdot g'(x)[/tex]

If we know that [tex]f(x) = 2\cdot x + 3[/tex], [tex]f'(x) = 2[/tex], [tex]g(x) = \sqrt{x^{2}-x+3}[/tex], [tex]g'(x) = \frac{2\cdot x - 1}{2\cdot \sqrt{x^{2}-x+3}}[/tex] and [tex]x = 0[/tex], then:

[tex]k'(x) = 2\cdot \sqrt{x^{2}-x+3}+\frac{(2\cdot x +3)\cdot (2\cdot x - 1)}{2\cdot \sqrt{x^{2}-x+3}}[/tex]

[tex]k'(0) = 2\sqrt{3}-\frac{3}{2\sqrt{3}}[/tex]

[tex]k'(0) = \frac{12-3}{2\sqrt{3}}[/tex]

[tex]k'(0) = \frac{9}{2\sqrt{3}}[/tex]

[tex]k'(0) = \frac{3\sqrt{3}}{2}[/tex]

The value of [tex]k'(0)[/tex] is [tex]\frac{3\sqrt{3}}{2}[/tex].

b) The derivative is found by means of the formulas for the derivative of the product of a function and a constant and the derivative of a division between two functions:

[tex]m'(x) = \frac{f'(x)\cdot g(x)-f(x)\cdot g'(x)}{2\cdot [g(x)]^{2}}[/tex] (2)

If we know that [tex]f(x) = -\frac{2}{3}\cdot x +\frac{25}{3}[/tex], [tex]f'(x) = -\frac{2}{3}[/tex], [tex]g(x) = \sqrt{x^{2}-x+3}[/tex], [tex]g'(x) = \frac{2\cdot x - 1}{2\cdot \sqrt{x^{2}-x+3}}[/tex] and [tex]x = 5[/tex], then:

[tex]f(5) = 5[/tex]

[tex]f'(5) = -\frac{2}{3}[/tex]

[tex]g(5) = \sqrt{23}[/tex]

[tex]g'(5) = \frac{9\sqrt{23}}{46}[/tex]

[tex]m'(5) = \frac{\left(-\frac{2}{3} \right)\cdot \sqrt{23}-\left(-\frac{2}{3} \right)\left(\frac{9\sqrt{23}}{46} \right)}{3\cdot 25}[/tex]

[tex]m'(5) \approx -0.034[/tex]

The value of [tex]m'(5)[/tex] is approximately -0.034.

c) In this case we must find a value of [tex]x[/tex], so that [tex]h'(x) = 2[/tex]. Hence, we have the following formula below:

[tex]5\cdot e^{x}-9\cdot \cos x = 2[/tex]

A quick approach is using a graphing tool a locate a point so that [tex]5\cdot e^{x}-9\cdot \cos x = 2[/tex]. According to this, the value of [tex]x[/tex] is approximately 0.622.

To learn more on derivatives, we kindly invite to check this verified question: https://brainly.com/question/21202620

According to the two-way table, the correct option is:

From the table, it is taken that:

Hence, the highlighted 0.1 = 10% means that:

You can learn more about two-way tables at https://brainly.com/question/24670062

Answer:

Number 21 is < number 23 is > number 22 is < and number 24 is >

Step-by-step explanation:

Answer:

the word phrase use to represent 6x+ 6 is sum 6x and 6

Step-by-step explanation:

first you sum 6x and 6

The student made $100 in week 8.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

Amount earned from the first week to 6 weeks.

110, 100, 90, 110, 100, 90

We see that,

Every 3 weeks the amount gets repeated.

So,

7th week = 110

8th week = 100

Thus,

The amount earned in week 8 is $100.

Learn more about expressions here:

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Answer:

y = 3

x = 2

Step-by-step explanation:

-5x + 4y = 2

9x - 4y = 6

Sum both eq.

-5x + 9x = 4x

+4y - 4y = 0

2 + 6 = 8

then:

4x + 0 = 8

4x = 8

x = 8/4

x = 2

from the first eq.

-5x + 4y = 2

-5*2 + 4y = 2

-10 + 4y = 2

4y = 2 + 10

4y = 12

y = 12/4

y = 3

Check:

from the second eq.

9x - 4y = 6

9*2 - 4*3 = 6

18 - 12 = 6

Here is ur answer of your question

Answer:

Should be 3 units away from the picture

Step-by-step explanation:

I hope this helps! ;)

The coordinates of the image of EFG under the dilation with scale factor 3/2 and center of dilation (0, 0) are E(-3,3), F'(-3,-3) and G'(3,-3).

Dilation of a figure, means the transformation of the figure. The factor by which the given figure dilated, called the scale factor of dilation.

The image of EFG under the dilation with scale factor and center of dilation has to be drawn.

The coordinates or the triangle are E(-2,2), F(-2,-2) and G(2,-2). The new points after the dilation are,

[tex]E'(-2\times\dfrac{3}{2},2\times\dfrac{3}{2})=E'(-3,3)\\F'(-2\times\dfrac{3}{2},-2\times\dfrac{3}{2})=F'(-3,-3)\\G'(2\times\dfrac{3}{2},-2\times\dfrac{3}{2})=G'(3,-3)[/tex]

The dilated image of triangle EFG is attached below.

Thus, the coordinates of the image of EFG under the dilation with scale factor 3/2 and center of dilation (0, 0) are E(-3,3), F'(-3,-3) and G'(3,-3).

Learn more about the dilation of the figure here;

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Answer:

See explanation

Step-by-step explanation:

Dilation of 4

G (0, 1) G' (0, 4)

F (1, 1) F' (4, 4)

Gx'/Gx = 0 / 0 = 0

Gy' / Gy = 4 / 1 = 4

Fx' / Fx = 4 / 1 = 4

Fy' / Fy = 4 / 1 = 4

[tex]3|x-7| = 15\\\\\implies |x-7| =\dfrac{15}3\\\\\implies |x -7| = 5\\\\\implies x -7 = 5 ~~ \text{or}~ x - 7 = -5\\\\\implies x = 12 ~~\text{or}~~ x = 2[/tex]