Mike drops a rock from the top of a suspension bridge. If the rock falls for 4.88 seconds,
how high is the bridge?

Answer:it was lifted

Explanation:

by me lifting it because i can life it very high

Use the equation a = F/m, where an is the acceleration, F is the force being applied, and m is the mass of the object, to calculate acceleration using mass and force. Calculating the acceleration is as simple as dividing the force by the mass.

Newton's Second Law of Motion states that the acceleration of an object is directly proportional to the force applied on it, and inversely proportional to its mass. The mathematical representation of this law is:

F = ma

where F is the force applied on an object, m is the mass of the object, and a is its acceleration. This law implies that the greater the force applied on an object, the greater its acceleration will be, and that the acceleration of an object will decrease as its mass increases, given a constant force.

This law helps to explain the behavior of objects under the influence of external forces. It is used in many areas of science and engineering, including mechanics, physics, and aerospace. Understanding the relationship between force, mass, and acceleration is fundamental to the study of mechanics and the design of machines and structures.

Here in the Question,

To find acceleration using mass and force, you can use the following steps:

1. Determine the force acting on the object. This can be done using a force meter, a scale, or by calculating the force using the formula F = ma, where F is the force in newtons (N), m is the mass of the object in kilograms (kg), and a is the acceleration in meters per second squared (m/s²).

2. Measure the mass of the object in kilograms. This can be done using a  scale.

3. Use the formula a = F/m to calculate the acceleration of the object. Rearrange the formula to solve for a: a = F/m.

5. Plug in the values for force and mass and solve for acceleration. For example, if the force acting on an object is 20 N and the mass of the object is 5 kg, the acceleration can be calculated as follows:

a = F/m

a = 20 N / 5 kg

a = 4 m/s²

So, the acceleration of the object is 4 meters per second squared.

It's important to note that the units of force and mass should be in the correct SI units (newtons and kilograms, respectively) to ensure the correct unit for acceleration (meters per second squared).

Therefore, To find acceleration using mass and force, use the formula a = F/m, where a is the acceleration, F is the force applied, and m is the mass of the object. Simply divide the force by the mass to calculate the acceleration.

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Answer:

42 Joules

Explanation:

Potential energy

= weight × height

= (3.5)(12)

= 42 joules

Explanation:

hope it's useful for you knows

Answer:

mesa

Explanation:



A mesa is a flat-topped mountain or hill. It is a wide, flat, elevated landform with steep sides. ... Spanish explorers of the American southwest, where many mesas are found, used the word because the tops of mesas look like the tops of tables.

Answer:

In physics, a state of matter is one of the distinct forms in which matter can exist. Four states of matter are observable in everyday life: solid, liquid, gas, and plasma.

...

To From Gas

Solid Deposition

Liquid Condensation

Plasma Ionization

As the Moon orbits our planet, its varying position means that the Sun lights up different regions, creating the illusion that the Moon is changing shape over time. This is because it rotates once on its axis in exactly the same time it takes to orbit Earth – 27 days and seven hours

Answer:

[tex]{ \rm{F=ma}} \\ [/tex]

Explanation:

Answer:

Please thank, answer below

Explanation:

Acceleration = (Final velocity - starting velocity)/time

Or, Force = mass * accelartion, which can be rewritten to be Accelaration = Force/mass

Let D be the total distance (say in meters) traveled by the train and T the time (say in seconds) it takes to do so. (Assume the train moves in a straight line in only one direction.) Then the average velocity of the train as it covers this distance is

v (ave) = D/T

We're told the train can traverse a distance of D/4 in a matter of T/2 seconds if it moves at a speed of 5 m/s. This means

D/4 = (5 m/s) (T/2)

⇒   5 m/s = 1/2 D/T

⇒   v (ave) = D/T = 10 m/s

Happy Holidays!

Recall the equation for kinetic energy:

[tex]\large\boxed{KE = \frac{1}{2}mv^2}}[/tex]

KE = kinetic energy (J)

m = mass (kg)

v = velocity (m/s)

Begin by converting 120 g to kg:

1000g = 1 kg

120 g = .120 kg

Plug in the given values:

[tex]KE = \frac{1}{2}(.120)(40^2) = \boxed{96J}[/tex]

Answer:

96 Joules

Explanation:

[tex]E_k=1/2* mass*velocity^2\\E_k=1/2 * 0.12 kg * (40m/s)^2 = 96 J[/tex]

Answer:

C

Explanation:

All of the other options are affecting the gravitational force and opposing force that pushed upwards, the diagram represents an object that is not moving up or down.

Answer:

9758 how many significant figures

[tex] = \frac{1}{2} \times 0.008 \times 420J \\ = 1.68J[/tex]

[tex]1.68J = \frac{1}{2} \times 75 \: kg \times v2 \\ = > v2 = \frac{1.68 \times 2}{75} m {s}^{ - 1} \\ = 0.0448 \: m \: {s}^{ - 1} [/tex]

Answer:

0.0448 m/s

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

Explanation:

Permanent magnets do have potential energy, stored in their magnetic field. That energy can be compared to the potential energy of some compressed spring. See the picture below, representing the magnetic field lines of a magnetized sphere : These lines are compressed inside the magnet.

Hi there!

Recall Newton's Second Law:

[tex]\large\boxed{\Sigma F = ma}}[/tex]

∑F = Net force (N)

m = mass (kg)

a = acceleration (m/s²)

We are already given the mass and acceleration, so we can plug these values into the equation:

∑F = 1600 · 4.5 = 7200 N

Answer:

a=Head

b=Tip

c=South pole of the magnet

d=North pole of the magnet

Answer:

TRUE !!

Explanation:

An atom is the smallest particle of an element

Answer:Passengers instinctively use the car as a frame of reference, while a physicist uses Earth. ... In such a frame of reference, Newton's laws of motion take the form given in Dynamics: Newton's Laws of Motion The car is a non-inertial frame of reference because it is accelerated to the side.

Explanation: Example of inertial and Noninertial Frame of Reference

Answer:

Space Launch System (SLS)

Explanation:

Space Launch System (SLS) is the United States Space Shuttle-derived heavy expendable launch vehicle being designed by NASA.

-TheUnknownScientist 72

Answer:

a 6.5 m

Explanation:

[tex]f = kx = > x = \frac{f}{k} = \frac{78}{12} = 6.5 m[/tex]

Answer:

40cm³

Explanation:

I only have an answer to 1a

Volume = Length X breadth X height

where;

length = 10cm

breadth = 2cm and;

width = 2cm

*Find*

V = ?

V = L X B X H

V = 10 X 2 X 2

= 40cm³✓

Answer:

State Police

the police organized and maintained by a state as distinguished from those of a lower subdivision (such as a city or county) of the state government.

The new gravitational force of the two objects will be 432 N.

The given parameters:

The gravitational force between the two objects is calculated by applying Newton's law of universal gravitation;

[tex]F = \frac{Gm_1m_2}{r^2} \\\\G = \frac{Fr^2}{m_1m_2}\\\\G = \frac{Gm_1m_2}{r^2} \\\\G = \frac{18r^2}{m_1m_2}[/tex]

[tex]\frac{18r^2}{m_1 m_2 } = \frac{F_2(\frac{1}{2}r)^2 }{2m_1 \times 3m_2} \\\\\frac{18r^2}{m_1 m_2 } = \frac{F_2 \times r^2}{4 \times 2m_1 \times 3m_2} \\\\\frac{18r^2\times 4 \times 2m_1 \times 3m_2}{m_1 m_2\times r^2 } = F_2\\\\432 \ N = F_2[/tex]

Thus, the new gravitational force of the two objects will be 432 N.

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Answer:

Explanation:

Power is the rate at which work is done and can be found by using the formula

[tex]p = \frac{w}{t} \\ [/tex]

p is the power in Watts (W)

w is the workdone in joules

t is time in s

but workdone = force × distance

From the question

force = 780 N

distance = 2 m

workdone = 780 × 2 = 1560 N

Since we now have the value of workdone we can find the power

We have

[tex]p = \frac{1560}{45} = 34.6666666... \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

100

Explanation:

The amount of current flowing in the wire is 1.69 × 10⁻¹⁶ A

From the question,

We are to calculate, the amount of current flowing in the wire.

From the formula,

[tex]I =\frac{nQ}{t}[/tex]

Where I is the current

n is the number of charge

Q is the quantity of charge

t is the time

From the given information

n = 8

Q = e = 1.69 × 10⁻¹⁹ C

t = 8 msecs = 8 × 10⁻³ sec

Putting the parameters into the formula, we get

[tex]I = \frac{8 \times 1.69 \times 10^{-19} }{8\times 10^{-3} }[/tex]

[tex]I = 1.69 \times 10^{-16} \ A[/tex]

Hence, the amount of current flowing in the wire is 1.69 × 10⁻¹⁶ A

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Answer:

D

Explanation:

A is wrong as the direction of the car changes, implying velocity is changing and not constant.

B and C are wrong as both the change in speed and direction contribute to the change in velocity

Assuming both billiard balls have the same mass, conservation of momentum says

[tex]m\vec v_1 + m\vec v_2 = m{\vec v_1}\,' + m{\vec v_2}\,'[/tex]

where m = mass of both billiard balls, and v₁ and v₂ = their initial velocities, and v₁' and v₂' = their final velocities. The masses are the same so the exact value of m is irrelevant. The first ball has initial speed 5 m/s and the second is at rest, so

[tex]\left(5 \dfrac{\rm m}{\rm s}\right) \, \vec\imath = {\vec v_1}\,' + {\vec v_2}\,'[/tex]

After the collision, the first ball has speed 4.35 m/s and is moving at angle of 30° below the original path, so

[tex]{\vec v_1}\,' = \left(4.35\dfrac{\rm m}{\rm s}\right)\left(\cos(30^\circ) \, \vec\imath + \sin(30^\circ) \, \vec\jmath\right) \approx \left(3.77 \dfrac{\rm m}{\rm s}\right) \vec\imath + \left(-2.18 \dfrac{\rm m}{\rm s}\right) \vec\jmath[/tex]

Then the second ball has final velocity vector

[tex]{\vec v_2}\,' \approx \left(1.23 \dfrac{\rm m}{\rm s}\right) \vec\imath + \left(2.18 \dfrac{\rm m}{\rm s}\right) \vec\jmath[/tex]

so it moves with speed

[tex]\left\|{\vec v_2}\,'\right\| \approx \sqrt{\left(1.23\dfrac{\rm m}{\rm s}\right)^2 + \left(2.18\dfrac{\rm m}{\rm s}\right)^2} \approx \boxed{2.50 \dfrac{\rm m}{\rm s}}[/tex]

at an angle of

[tex]\theta \approx \tan^{-1}\left(\dfrac{2.18}{1.23}\right) \approx \boxed{60.5^\circ}[/tex]

or about 60.5° above the original line of motion.