Kevin and his children went into a restaurant and he bought $31.50 worth of hotdogs and drinks. Each hotdog costs $4.50 and each drink costs $2.25. He bought 3 times as many hotdogs as drinks. Graphically solve a system of equations in order to determine the number of hotdogs, x,x, and the number of drinks, y,y, that Kevin bought.

Answer:

45

Step-by-step explanation:

Answer:

2.5

Step-by-step explanation:

Answer:

5/2

Step-by-step explanation:

To divide fractions, you flip the second fractions and change it to multiplication.

(3/2) / (3/5) =

(3/2) x (5/3)

To multiply them, you just multiply their numerators together to get the new numerator and multiply the denominators together to get the new denominator.

(3/2) x (5/3) =

(3 x 5) / (2 x 3) =

15/6

This can be reduced to:

5/2

Answer:

56 if rounding but 56.50 if not

Step-by-step explanation:

rate

Answer:

I believe the y is parallel :)))))))))

Answer:

35 degrees

Step-by-step explanation:

70 divided by 2 is 35.

And both sides are equal to each other bc the lines are parallel.

Answer:

y = 1.75

x = 1.25

Step-by-step explanation:

Since the triangles have equal angles, you can use ratios to solve for x and y.

For y:

[tex]\frac{8}{10} =\frac{7}{a} \\8a=70\\a=8.75[/tex]

Subtract 7 from a to find y.

y = 8.75 - 7

y = 1.75

For x:

[tex]\frac{8}{10} =\frac{5}{b} \\8b=50\\b=6.25[/tex]

Subtract 5 from b to find x.

x = 6.25 - 5

x = 1.25

Answer:

Step-by-step explanation:

abc=80, abm= 100

acb= 40, acn= 140

angle a = 60

x=80, y=40

Answer:

x = 80° y = 40°

Step-by-step explanation:

ABC = 80°  ACB = 40°

ABC+ACB+A = 180° (sum of angles in a triangle = 180°)

80+40+A = 180°

A = 60°  (sum of angles in a triangle = 180°)

X = 80° (ALTERNATE ANGLES, angles x is alternate to angle ABC = 80° )

y = 40°  (alternate angles, angle y is alternate to angle ACB = 40°)

to cross-check : sum of angles on a straight line = 180°  

x+ y + A = 180sum of angles on a straight line = 180°

80+40+60 = 180°

ABM = 100°  = (sum of angles on a straight line = 180°)

80° + 100°  = 180°

ACN = 140° (sum of angles on a straight line = 180°)

40° + 140° = 180°

Answer:

Step-by-step explanation:

We can divide exponents by subtract 4 from 6. So, now we have 5^2 or 25.

The other way to solve to check our answer is to do the math.

5^6 = 15625

5^4 = 625

15625/625 = 25

So, we know we have the correct answer.

Answer:

The standard form of the given equation is f(x) =  0x²-4x+15=0

Step-by-step explanation:

The standard form  is ax²+bx+c=0

Given f(x) = -4(x-2)+ 7

   we can write the standard form

                     =  0x² -4(x-2)+7 =0

                   ⇒   0x² -4x +8 +7 =0

                   ⇒   0x² -4x + 15 =0

now comparing the standard form ax²+bx+c=0

                      a = 0 , b= -4 and c =15

Proportional equations are of the form y = kx, for some fixed constant k. The k value is the constant of proportionality.

The +100 at the end is why we don't have a proportional equation.

Visually all proportional equations go through the origin, meaning the lines have y intercept of 0. For y = 230x+100, the y intercept is 100.

Answer: B

Step-by-step explanation:

1/9(3)^x

(3)^(5) = 243

243(1/9) = 27

Hope this helps :)

Answer:

See below for Part A.

Part B)

[tex]\displaystyle h=\Big(\frac{125}{\pi}+27\Big)^\frac{2}{3}-9\approx7.4614[/tex]

Step-by-step explanation:

Part A)

The parabola given by the equation:

[tex]y^2=4ax[/tex]

From 0 to h is revolved about the x-axis.

We can take the principal square root of both sides to acquire our function:

[tex]y=f(x)=\sqrt{4ax}[/tex]

Please refer to the attachment below for the sketch.

The area of a surface of revolution is given by:

[tex]\displaystyle S=2\pi\int_{a}^{b}r(x)\sqrt{1+\big[f^\prime(x)]^2} \,dx[/tex]

Where r(x) is the distance between f and the axis of revolution.

From the sketch, we can see that the distance between f and the AoR is simply our equation y. Hence:

[tex]r(x)=y(x)=\sqrt{4ax}[/tex]

Now, we will need to find f’(x). We know that:

[tex]f(x)=\sqrt{4ax}[/tex]

Then by the chain rule, f’(x) is:

[tex]\displaystyle f^\prime(x)=\frac{1}{2\sqrt{4ax}}\cdot4a=\frac{2a}{\sqrt{4ax}}[/tex]

For our limits of integration, we are going from 0 to h.

Hence, our integral becomes:

[tex]\displaystyle S=2\pi\int_{0}^{h}(\sqrt{4ax})\sqrt{1+\Big(\frac{2a}{\sqrt{4ax}}\Big)^2}\, dx[/tex]

Simplify:

[tex]\displaystyle S=2\pi\int_{0}^{h}\sqrt{4ax}\Big(\sqrt{1+\frac{4a^2}{4ax}}\Big)\,dx[/tex]

Combine roots;

[tex]\displaystyle S=2\pi\int_{0}^{h}\sqrt{4ax\Big(1+\frac{4a^2}{4ax}\Big)}\,dx[/tex]

Simplify:

[tex]\displaystyle S=2\pi\int_{0}^{h}\sqrt{4ax+4a^2}\, dx[/tex]

Integrate. We can consider using u-substitution. We will let:

[tex]u=4ax+4a^2\text{ then } du=4a\, dx[/tex]

We also need to change our limits of integration. So:

[tex]u=4a(0)+4a^2=4a^2\text{ and } \\ u=4a(h)+4a^2=4ah+4a^2[/tex]

Hence, our new integral is:

[tex]\displaystyle S=2\pi\int_{4a^2}^{4ah+4a^2}\sqrt{u}\, \Big(\frac{1}{4a}\Big)du[/tex]

Simplify and integrate:

[tex]\displaystyle S=\frac{\pi}{2a}\Big[\,\frac{2}{3}u^{\frac{3}{2}}\Big|^{4ah+4a^2}_{4a^2}\Big][/tex]

Simplify:

[tex]\displaystyle S=\frac{\pi}{3a}\Big[\, u^\frac{3}{2}\Big|^{4ah+4a^2}_{4a^2}\Big][/tex]

FTC:

[tex]\displaystyle S=\frac{\pi}{3a}\Big[(4ah+4a^2)^\frac{3}{2}-(4a^2)^\frac{3}{2}\Big][/tex]

Simplify each term. For the first term, we have:

[tex]\displaystyle (4ah+4a^2)^\frac{3}{2}[/tex]

We can factor out the 4a:

[tex]\displaystyle =(4a)^\frac{3}{2}(h+a)^\frac{3}{2}[/tex]

Simplify:

[tex]\displaystyle =8a^\frac{3}{2}(h+a)^\frac{3}{2}[/tex]

For the second term, we have:

[tex]\displaystyle (4a^2)^\frac{3}{2}[/tex]

Simplify:

[tex]\displaystyle =(2a)^3[/tex]

Hence:

[tex]\displaystyle =8a^3[/tex]

Thus, our equation becomes:

[tex]\displaystyle S=\frac{\pi}{3a}\Big[8a^\frac{3}{2}(h+a)^\frac{3}{2}-8a^3\Big][/tex]

We can factor out an 8a^(3/2). Hence:

[tex]\displaystyle S=\frac{\pi}{3a}(8a^\frac{3}{2})\Big[(h+a)^\frac{3}{2}-a^\frac{3}{2}\Big][/tex]

Simplify:

[tex]\displaystyle S=\frac{8\pi}{3}\sqrt{a}\Big[(h+a)^\frac{3}{2}-a^\frac{3}{2}\Big][/tex]

Hence, we have verified the surface area generated by the function.

Part B)

We have:

[tex]y^2=36x[/tex]

We can rewrite this as:

[tex]y^2=4(9)x[/tex]

Hence, a=9.

The surface area is 1000. So, S=1000.

Therefore, with our equation:

[tex]\displaystyle S=\frac{8\pi}{3}\sqrt{a}\Big[(h+a)^\frac{3}{2}-a^\frac{3}{2}\Big][/tex]

We can write:

[tex]\displaystyle 1000=\frac{8\pi}{3}\sqrt{9}\Big[(h+9)^\frac{3}{2}-9^\frac{3}{2}\Big][/tex]

Solve for h. Simplify:

[tex]\displaystyle 1000=8\pi\Big[(h+9)^\frac{3}{2}-27\Big][/tex]

Divide both sides by 8π:

[tex]\displaystyle \frac{125}{\pi}=(h+9)^\frac{3}{2}-27[/tex]

Isolate term:

[tex]\displaystyle \frac{125}{\pi}+27=(h+9)^\frac{3}{2}[/tex]

Raise both sides to 2/3:

[tex]\displaystyle \Big(\frac{125}{\pi}+27\Big)^\frac{2}{3}=h+9[/tex]

Hence, the value of h is:

[tex]\displaystyle h=\Big(\frac{125}{\pi}+27\Big)^\frac{2}{3}-9\approx7.4614[/tex]

You seem to have left out that 0 ≤ x ≤ h.

From y² = 4ax, we get that the top half of the parabola (the part that lies in the first quadrant above the x-axis) is given by y = √(4ax) = 2√(ax). Then the area of the surface obtained by revolving this curve between x = 0 and x = h about the x-axis is

[tex]2\pi\displaystyle\int_0^h y(x) \sqrt{1+\left(\frac{\mathrm dy(x)}{\mathrm dx}\right)^2}\,\mathrm dx[/tex]

We have

y(x) = 2√(ax)   →   y'(x) = 2 • a/(2√(ax)) = √(a/x)

so the integral is

[tex]4\sqrt a\pi\displaystyle\int_0^h \sqrt x \sqrt{1+\frac ax}\,\mathrm dx[/tex]

[tex]=\displaystyle4\sqrt a\pi\int_0^h (x+a)^{\frac12}\,\mathrm dx[/tex]

[tex]=4\sqrt a\pi\left[\dfrac23(x+a)^{\frac32}\right]_0^h[/tex]

[tex]=\dfrac{8\pi\sqrt a}3\left((h+a)^{\frac32}-a^{\frac32}\right)[/tex]

Now, if y² = 36x, then a = 9. So if the area is 1000, solve for h :

[tex]1000=8\pi\left((h+9)^{\frac32}-27\right)[/tex]

[tex]\dfrac{125}\pi=(h+9)^{\frac32}-27[/tex]

[tex]\dfrac{125+27\pi}\pi=(h+9)^{\frac32}[/tex]

[tex]\left(\dfrac{125+27\pi}\pi\right)^{\frac23}=h+9[/tex]

[tex]\boxed{h=\left(\dfrac{125+27\pi}\pi\right)^{\frac23}-9}[/tex]

Answer:

The answer is translation :)

Answer:

10

Step-by-step explanation:

the mid-segment, 5, is parallel to the base of the triangle and the side that the mid-segment is parallel to is always double the length of the mid-segment, so the base of the base is 10. this triangle is an equilateral triangle so the side, x, is also 10.

Answer:

We have the expression:

(n + 2)^2 - (n - 2)^2

Let´s break the parentheses:

(n + 2)^2 = n^2 + 4*n + 4

(n - 2)^2 = n^2 - 4n + 4

Then:

(n + 2)^2  - (n - 2)^2 = (n^2 + 4*n + 4) - (n^2 - 4n + 4) =

                                 = (n^2 - n^2) + (4 - 4) + (4n - (-4n)) = 4n - (-4n) = 8*n

Then for any natural value of n, 8*n will be a multiple of 8.

Answer:

99 over 130 multiplied by 100 over 1

Answer:

The correct answer is B ; Karla must determine the area of a floor in her house.

Answer:

both are linear

a) 6x - y = 7

b) 2x - y = -5

Step-by-step explanation:

Answer:

CD = 5

Step-by-step explanation:

Given that ∆ACB is congruent to ∆DCE, it follows that their corresponding angles and corresponding side lengths are congruent to each other. Thus:

AC is congruent to CD,

BC is congruent to EC, and

AB is congruent to DE.

Since AC = 5, therefore CD = 5.

Answer:

f(3)=g(3)

Step-by-step explanation:

the only one i see is that

f(3)=g(3)

because the two functions intersect there

that means the two values are the same

Answer:  Approximately 1.9 atm

============================================

Work Shown:

[tex]P_1*V_1 = P_2*V_2 \ \text{ ... Boyle's Law}\\\\4.5*1.5 = P_2*3.5\\\\6.75 = P_2*3.5\\\\P_2*3.5 = 6.75\\\\P_2 = \frac{6.75}{3.5}\\\\P_2 \approx 1.92857142857142\\\\P_2 \approx 1.9\\\\[/tex]

If the volume is 3.5 liters, then the pressure is approximately 1.9 atm.

Note the increase in volume leads to the reduction of pressure, and vice versa. The two variables have an inverse relationship.

-----------

As a check,

[tex]P_1*V_1 = P_2*V_2\\\\4.5*1.5 \approx 1.9*3.5\\\\6.75 \approx 6.65\\\\[/tex]

We don't get the exact thing on both sides, but the two sides are close enough. We have rounding error due to P2 being not exact.

A more accurate check could be

[tex]P_1*V_1 = P_2*V_2\\\\4.5*1.5 \approx 1.92857*3.5\\\\6.75 \approx 6.749995\\\\[/tex]

which has the two sides much closer to one another. This helps us verify the answer.

Answer:

65.9

Step-by-step explanation:

Ok...

what exactly do you need help with?

Answer:

help with what lol

Step-by-step explanation:

Answer:

1) 0.99348

2) 0.55668

Step-by-step explanation:

Assume that men’s weights are normally distributed with a mean given by  = 172lb and a standard deviation given by  =29lb. Using the Central Limit Theorem to solve the following exercises

When given a random number of samples, we use the z score formula:

z-score is z = (x-μ)/σ/√n where

x is the raw score

μ is the population mean

σ is the population standard deviation.

(1) If 36 men are randomly selected, find the probability that they have a mean weight greater than 160lb.

For x > 160 lb

z = 160 - 172/29/√36

z = 160 - 172/29/6

z = -2.48276

Probability value from Z-Table:

P(x<160) = 0.0065185

P(x>160) = 1 - P(x<160) = 0.99348

(2) If 81 men randomly selected, find the probability that they have a mean weight between 170lb and 175lb.

For x = 170 lb

z = 170 - 172/29/√81

z = 170 - 172/29/9

z = -0.62069

Probability value from Z-Table:

P(x = 170) = 0.2674

For x = 175 lb

z = 175 - 172/29/√36

z = 175- 172/29/6

z = 0.93103

Probability value from Z-Table:

P(x = 175) = 0.82408

The probability that they have a mean weight between 170lb and 175lb is calculated as:

P(x = 175) - P(x = 170)

0.82408 - 0.2674

= 0.55668

Answer:

[tex]y = 320x +2080[/tex]

Step-by-step explanation:

Given

Population in 1995 = 2400

Population in 2000 = 4000

Required

Determine the linear equation

Let the years be represented with x.

In 1995, x = 1 i.e. the first year

In 2000, x = 6

Let y represents the population

When x = 1; y = 2400

When x = 6; y = 4000

First, we calculate the slope (m)

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

[tex]m = \frac{4000 - 2400}{6 - 1}[/tex]

[tex]m = \frac{1600}{5}[/tex]

[tex]m = 320[/tex]

Next, we calculate the line equation as follows:

[tex]y - y_1 = m(x - x_1)[/tex]

[tex]y - 2400 = 320(x - 1)[/tex]

[tex]y - 2400 = 320x - 320[/tex]

[tex]y = 320x - 320 + 2400[/tex]

[tex]y = 320x +2080[/tex]

Answer:

0.88

Step-by-step explanation:

-5.37 + 8.14 - 1.89

-5.37 + 6.25

= 0.88

Step-by-step explanation:

please i worked on paper worksheet

please see it

Answer:

[tex]35\%[/tex] represents the sample proportion of the population

Step-by-step explanation:

From the question we are told that

   The sample size is  n  = 947

   The proportion of the population that believes that the Yankees will miss the playoffs this year is    [tex]k = 35\% = 0.35[/tex]

From the question we are told the confidence level is  97%

   The lower limit of the confidence level is a = 28%

    The upper limit of the  b = 42%

Generally the sample proportion of this population is mathematically represented as

         [tex]\^ p = \frac{a+ b}{2}[/tex]

=>      [tex]\^ p = \frac{28 + 42 }{2}[/tex]

=>      [tex]\^ p = 35\%[/tex]

Hence  [tex]35\%[/tex] represents the sample proportion

Answer:

x=-5/2,0

Step-by-step explanation:

It is solved by first factorizing it

10x²+25x=5x(2x+5)=0

Finding the zeros

5x=0x=0/5=0

2x+5=0

x=-5/2

Therefore x is -5/2 or 0