Jonah and Jesse are taking a trip. Jonah left at 7 a.m. and travel at an average of 40 miles per hour. Jesse left at 10 a.m. and travel at average of 50 mph. At what time are they at the same place at the same time? Write a system of equations to represent this situation. Then use the substitution method with that system to determine at what time they will be in the same location. How many miles away from will they be at that time?

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Answers

Answer 1

Answer:

y=40(t -7); y=50(t-10)t=22; 10 p.m.y=600 miles from home

Step-by-step explanation:

a) Let t represent the clock time (hours after midnight). The distance from home will be ...

  distance = speed × time

  jonah = 40(t -7)

  jesse = 50(t -10)

  jonah = jesse . . . . . . . same distance from home at the same time

(Note: you could let y = distance traveled and use y in both equations. That would give 2 equations in 2 unknowns, instead of 3 equations in 3 unknowns.)

__

b) substituting the first two equations into the second, we get ...

  40(t -7) = 50(t -10)

  4t -28 = 5t -50 . . . . . . . divide by 10, eliminate parentheses

  22 = t

Jonah and Jesse will be at the same place at 10 p.m.

__

c) We can find the distance by substituting into either equation.

  jonah = 40(22 -7) = 40(15) = 600

They will be 600 miles from home at that time.


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a parking garage charges $4 for the first hour and $1.50 for each additional hour. sydney has 13$ in her purse

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Answer:

7 hours

Step-by-step explanation:

Answer:

she could park there for 7 hours

Step-by-step explanation:

13-4=9 9/1.50=6

Consider the expression 20-(4^2/2). How many terms does the expression have?

Answers

Answer:

huh

Step-by-step explanation:

what is the equation of the line that passes through the point (4,0) and has a slope of 5/4?

Answers

Answer:

y=5/4x-5

Step-by-step explanation:

y-y1=m(x-x1)

y-0=5/4(x-4)

y=5/4(x-4)

y=5/4x-20/4

y=5/4x-5

Need help please ……………………………..

Answers

Answer:

[tex]-2^{-2} = \frac{1}{-2^{2} } = \frac{1}{4} = 0.25[/tex]

[tex]-2^{-1} = \frac{1}{-2 } = -0.5[/tex]

[tex]-2^{0} = 1[/tex]

[tex]-2^{1} = -2[/tex]

[tex]-2^{2} = 4[/tex]

Step-by-step explanation:

PLLLZZZ NO ONE WILL HELP ME!!!
Given this equation in slope-intercept form…
y = 2x + 5
Identify or solve for the following:
Slope
y-intercept
x-intercept
Independent variable
Dependent variable
Domain
Range
We would like to represent a line passing through the point (5,0) with a slope of 2. Please write the equation for this line in slope-intercept form and in point-slope form.

What is the rate of change of the function above?

Answers

Answer:

y = m x + b    standard form of straight line

y = 2 x + 5

The slope is m and = 2

the y intercept is 5  because when x = o y = 5

if y = 0 then x = -2/5 and would be the x intercept

x is the independent variable and y is the dependent variable

I am not familiar with your definitions for domain and range but

both x and y can vary from -∝ to = ∝

please help me with the question please ☹️

Answers

Answer:

the last one

Step-by-step explanation:

because those are oppiste poles

Image attached giving 25 points please help

Answers

Answer:

Rational

Step-by-step explanation:

It isnt whole because its a decimal,

It isnt an Integer because its a decimal

It isnt natural because its a decimal

Meaning it can only be rational

A train leaves a point A at 5 pm and reach another point B at 11 pm. Another train leaves point B at 7 pm and reach point A at 10 pm. At what point will the two trains meet?

Answers

Answer: I think the two trains meet at 9pm

Explanation: A=train a B=train b

If A is traveling for 6 hours and B is traveling for 3 hours, then you minus 3 hours from A, so you are left with 3 hours. Convert that into time, and you are left with 9pm!

Hope this helps! :)

Step-by-step explanation:

let's think this through.

train a goes from A to B in 6 hours. that means with a speed of 1/6 / hour.

train b goes from B to A in 3 hours, so it is twice as fast as train a = 2/6 / hour.

when train b leaves B (at 7pm), train a was already traveling for 2 hours (1/3 of the whole trip) leaving it with 4 hours to go (2/3 if the distance).

that means that at that point now both trains are moving against each other with a relative speed of 3 times the

speed of a (the original speed of a plus the double speed of b).

this is the same as one train standing, and the other going the whole distance with 3 times the speed of a.

the whole distance is 2/3 of AB.

the speed is 3/6 / hour = 1/2 / hour.

so, a single train with that speed would cover the total distance AB in 2 hours. or half of the distance in 1 hour.

the question now, how long for 2/3 of AB.

the distances relate by a factor :

1/2 × f = 2/3

f = 2/3 / 1/2 = 2/3 × 2/1 = 4/3

now we need to multiply also the time in the distance/time speed ratio by this factor.

therefore, 2/3 of the total distance is done in 1×4/3 = 4/3 of an hour.

that means both trains meet after 4/3 of an hour after 7pm.

that is 7pm plus 1 hour and 20 minutes giving us 8:20pm.

Tìm nghiệm tổng quát của các phương trình
y"+2y'-3y=0

Answers

Answer:

y € R i guess

Step-by-step explanation:

I hope it correct

Mark which expressions represent the distance between 46 and-15

Answers

|-15-46|
...........

The
is the distance across a circle, going through the center.
circumference
diameter
radius
area

Answers

The distance across a circle, going through the center is called Diameter.

Interest = $45.58, time = 1 year, rate = 2.25%. Find the principal. Round to the nearest hundredth place

Answers

Answer:

$2,025.78

Step-by-step explanation:

I = Prt ⇒ P = [tex]\frac{I}{rt}[/tex]

2.25% = 0.0225

P = 45.58 ÷ ( 0.0225 × 1 ) ≈ $2,025.78

x/2 - 3 = 5 Solve the equation algebraically show work to support the answer

Answers

Answer:

x = 16

Step-by-step explanation:

Answer:

x = 16

Step-by-step explanation:

x/2 - 3 = 5

x/2 = 5+3

x/2 = 8

x = 8×2

x = 16

3
Johnny has been hired to draw a mural on the window of the pet store. The scale drawing he is using is shown below.
4.5 cm
6 cm
If 1 centimeter represents 10 inches on the mural, what is the actual height and width of the hamster that he will be drawing on the
mural?
OA.
66 in by 49.5 in
ОВ.
90 in by 120 in
Od
6 in by 4.5 in
OD. 60 in by 45 in

Answers

Answer:

OD 60 in by 45 in

Step-by-step explanation:

Find the side of a rhombus if its diagonals are 14 and 48
(Use Pythagorean theorem)

Answers

Answer:

25

Step-by-step explanation:

Let,

Rhombus = ABCD

Diagonal = AC and BD

Mark its centre as O

Now,

AC = 2AO

AO = AC/2

AO = 48/2

AO = 24 cm

Also,

BD = 2BO

BO = BD/2

BO = 14/2

BO = 7 cm²

Now,

In ∆AOB

AB² = AO² + BO²

Here, AB is the side

AB² = (24)² + (7)²

AB² = 576 + 49

AB² = 625

AB = √(625)

AB = 25

Write -37.75 as a mixed number.​

Answers

Answer:

[tex]-37\frac{3}{4}[/tex]

Step-by-step explanation:

0.75 is equivalent to three quarters, or (3/4).

3/4 would be the fraction. -37 would be the whole number.

[tex]-37.75 = \boxed{-37\frac{3}{4}}[/tex]

Hope this helps.

Answer:

- 37 3/4

Step-by-step explanation:

PLS HELP PLEASSSSS IM SERIOUSLY CRYING RN

Answers

i really don’t know 555

[tex]x = 23[/tex]

Step-by-step explanation:

First, we need to write the equations in their standard form, i.e., all the variables and their coefficients are to be placed on the left hand side and the plain numbers on the right hand side. The first equation is already in its standard form:

[tex]2x + 5y = 35\;\;\;\;\;(1)[/tex]

but we need to rewrite the 2nd one. So the standard form of the 2nd equation can be written as

[tex]x + 15y = -10\;\;\;\;\;(2)[/tex]

Now that the equations are in their standard forms, the next step that we need to do is to eliminate one of the variables, namely the y. To do that, we need to multiply either one of the equations so that when we add them together, the y-variable gets eliminated. Note if we multiply Eqn(1) by -3, we'll get -15y on one equation and a +15y on the other equation so that when they are added together, they cancel out. So if we do that, we get

[tex]-6x - 15y = -105\;\;\;\;\;(3)[/tex]

Adding Eqn(3) to Eqn(2), we get

[tex]-5x = -115[/tex]

or

[tex]x = \dfrac{-115}{-5} = 23[/tex]

F r e e points for people that is low on points :)

Answers

Answer:

im not low on points but thank you <3.

Step-by-step explanation:

Answer:

:) :) :) :) :) :) :) :) :) :)

Dog slept 3 hours . If the dog snored 1/3 of an hour . How many times did he snore

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Answer:

it depends how much the god snores within a certain time period

What is the standard deviation of 82,93,89 and 88?

Answers

Answer:

4.546, rounded

Step-by-step explanation:

pls mark brainliest!

Help Will give Branliest

Answers

They Y intercept is 1

(-7,-4) (-11,-2) slope

Answers

Answer:

1/3

Step-by-step explanation:

-2-4 = -6

-7-11 = -18

2 + 2 = 3
prove me wrong

Answers

Answer:

2+2=4................

Answer:

you are wrong because 2+2=4

some help, I need some answers

Answers

Answer:

Well your Hypotenuse is 10 and your other angle is 8 so it is most likely 6 because you see a change in 2 each time and it is about 2 units smaller because all right triangles follow a pattern

Step-by-step explanation:

if it was too go even higher it would go to 12,14,16 etcetera

The verticles of a triangle are the points R(3,c),Q(9,2) and R(3c,11) where c is constant. Given that angle PQR is 90​

Answers

Answer:

Step-by-step explanation:

Find c if ∠PQR = 90°?

I will ASSUME you mean point P is at (3. c)

slope of PQ is (2 - c) / (9 - 3) = (2 - c) / 6

slope of QR is (11 - 2) / (3c - 9) = 9 / (3c - 9)

perpendicular lines have negative reciprocal slopes.

(2 - c) / 6 = -1(3c - 9)/9

9(2 - c) = -6(3c - 9)

18 - 9c = -18c + 54

       9c = 36

         c = 4

6. The California Tiger Salamander is an endangered species, which decreases at the rate of 4.6% per year in a habitat that currently has 60 of them. Write an exponential function and find how many California Tiger Salamanders will be left after 4 years.

7. Factor and solve the following equation 2x2 + x - 21 = 0.

8. Alvin throws the football to a receiver who jumps up to catch the ball. The height of the ball over time can be represented by the quadratic equation -4.9t2 + 7.5t + 1.8 = 2.1 . This equation is based on the acceleration of gravity -4.9 m/s2, the velocity of his pass is 7.5 m/s and releases the football at a height of 1.8 meters, and the height where the receiver catches the ball of 2.1 meters. Put the equation in standard form and then solve by using the quadratic equation.

9. Examine the graph of f(x) and the table that contains values of g(x). Which function has a greater rate of change over the interval [0,2]? Explain your answer.

Answers

[tex]\rule{2000pt}{1000000pt}[/tex]

A quadratic function and an exponential function are graphed below. How do the decay rates of the functions compare over the interval -2<= x <= 0?


The exponential function decays at one-half the rate of the quadratic function.
The exponential function decays at the same rate as the quadratic function.
The exponential function decays at two-thirds the rate of the quadratic function.
The exponential function decays at three-fourths the rate of the quadratic function.

Answers

Answer:

×e[-2,0}

Why;-2<x<0

Write the compound inequality in interval rotation

so the answer is;×e[-2,0}

brainliest me thanks for later

Answer:

D) The exponential function decays at three-fourths the rate of the quadratic function.

Step-by-step explanation:

Which of the following is the graph of y = |x - 3|

Answers

Answer:

y = | x - 3 | is graphed on the attachment below

Step-by-step explanation:

If you ever need an equation graphed, here's a useful site called Desmos that can do that really well and for free.

You buy 3.18 pounds of ​apples, 1.35 pounds of oranges​, and 2.25 pounds of pears. What is your total​ bill?

Answers

Answer:

6.78

Step-by-step explanation:

Answer:

6.78 pounds

Step-by-step explanation:

Add: 3.18+1.35+2.25=6.78

(If you wanted the cost for the whole thing then you need to include the price for each of the pounds)

Answer them all please ​

Answers

Answer:

see the attachment

i hope it helps u ✌️✌️✌️☠️

a) The highest common factor and the least common multiple are 12 and 48, respectively.

b) The highest common factor and the least common multiple are 12 and 72, respectively.

c) The highest common factor and the least common multiple are 8 and 160, respectively.

d) The highest common factor and the least common multiple are 12 and 48, respectively.

e) The highest common factor and the least common multiple are 14 and 840, respectively.

Procedure - Determination of the Highest Common Factor and the Least Common Multiple of two integers

In this question we must determine the highest common factor and the least common multiple of two integers.

The highest common factor consists in the maximum product of common prime numbers, of the two numbers that divides it, and the least common multiple consists in the product of prime numbers, common and not, of the two numbers, that creates a product that it is greater or equal to the greater integer.

Now, we proceed to determine the numbers for each case:

a) 12 and 48

First, we factorize each integer:

[tex]12 = 2^{2}\times 3[/tex], [tex]48 = 2^{4}\times 3[/tex]

Then the highest common factor and the least common multiple are, respectively:

[tex]LCM = 2^{4}\times 3 = 48[/tex], [tex]HCF = 2^{2}\times 3 = 12[/tex]

The highest common factor and the least common multiple are 12 and 48, respectively. [tex]\blacksquare[/tex]

b) 24 and 36

First, we factorize each integer:

[tex]24 = 2^{3}\times 3[/tex], [tex]36 = 2^{2}\times 3^{2}[/tex]

Then, the highest common factor and the least common multiple are, respectively:

[tex]LCM = 2^{3}\times 3^{2} = 72[/tex], [tex]HCF = 2^{2}\times 3 = 12[/tex]

The highest common factor and the least common multiple are 12 and 72, respectively. [tex]\blacksquare[/tex]

c) 32 and 40

First, we factorize each integer:

[tex]32 = 2^{5}[/tex], [tex]40 = 2^{3}\times 5[/tex]

Then, the highest common factor and the least common multiple are, respectively:

[tex]LCM = 2^{5}\times 5 = 160[/tex], [tex]HCF = 2^{3} = 8[/tex]

The highest common factor and the least common multiple are 8 and 160, respectively. [tex]\blacksquare[/tex]

d) 24, 48 and 60

First, we factorize each integer:

[tex]24 = 2^{3}\times 3[/tex], [tex]48 = 2^{4}\times 3[/tex], [tex]60 = 2^{2}\times 3 \times 5[/tex]

Then, the highest common factor and the least common multiple are, respectively:

[tex]LCM = 2^{4}\times 3 \times 5 = 48[/tex], [tex]HCF = 2^{2}\times 3 = 12[/tex]

The highest common factor and the least common multiple are 12 and 48, respectively. [tex]\blacksquare[/tex]

e) 42, 56 and 70

First, we factorize each integer:

[tex]42 = 2\times 3 \times 7[/tex], [tex]56 = 2^{3}\times 7[/tex], [tex]70 = 2\times 5\times 7[/tex]

Then, the highest common factor and the least common multiple are, respectively:

[tex]LCM = 2^{3} \times 3 \times 5 \times 7 = 840[/tex], [tex]HCF = 2\times 7 = 14[/tex]

The highest common factor and the least common multiple are 14 and 840, respectively. [tex]\blacksquare[/tex]

To learn more on prime numbers, we kindly invite to check this verified question: https://brainly.com/question/4184435

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