Is this a positive trend or negative trend or no trend please help ​

Is This A Positive Trend Or Negative Trend Or No Trend Please Help

Answers

Answer 1

Answer:

negative trend because the values are decreasing


Related Questions

A standard train ticket in a certain city costs $1.50 per ride. People who use the train also have the option of purchasing a frequent rider pass for $17.25 per month. With the pass, a ticket costs only $0.75 per ride. How many train rides a month make the frequent rider pass a better deal than standard train tickets?

Answers

Just off the bat 17$is 12 rides and then 17.25 +0.75 is 18 so 13 rides

x = number of rides per month.

Without the pass, the cost per ride is 2.00 per ride.

With the pass, the cost per ride is 1.25 per ride plus 15.75 per month.

You want to know at what number of rides does the cost per ride using the pass become cheaper than the cost per ride without using the pass.

The formula for total cost is as follows:

without the pass:

C1 = 2*x

with the pass:

C2 = 15.75 + 1.25*x

You want to know when C2 becomes less than C1.

C2 < C1 is the inequality equation you are looking for.

Since C2 = 15.75 + 1.25*x, and C1 = 2*x, this equation becomes:

15.75 + 1.25*x < 2*x

Subtract 1.25*x from both sides of this equation to get:

15.75 < 2*x - 1.25*x which becomes:

15.75 < .75*x

Divide both sides of this equation by .75*x to get:

15.75/.75 < x

Simplify to get:

21 < x

21 < x is the same as x > 21.

Your answer is the C2 becomes cheaper than C1 when x > 21.

If you make x = 21, then:

C1 = 2*21 = 42
C2 = 15.75 + 1.25*21 = 15.75 + 26.25 = 42

They are equal.

If you make x = 22, then:

C1 = 2*22 = 44
C2 = 15.75 + 1.25*22 = 15.75 + 27.5 = 43.25

43.25 is cheaper than 44 so C2 is cheaper than C1, confirming that the equation is good.

Your high school freshman class consists of 760 students. In recent years, only 4 out of 7 students actually graduated in four years. Approximately how many of your classmates are expected to graduate in four years?
a.
190 students
b.
760 students
c.
434 students
d.
1330 students

Answers

The answer would be a. 190 students
190 hope this helps

Part A : At Mountain Park Middle school, there are 250 seventh-grade students who are not in advanced math. Let a represent the number of seventh-grade students who are not in advanced math?

Part B: How many students are NOT in advanced math?

Answers

Answer:

hard to explain

Step-by-step explanation:

Answer:I think 80 at bottom like

Step-by-step explanation:

Hw help ASAPPP
+10PTS

Answers

Y=1/4x +5 is the answer

Please help ASAP!!!!!!!!!

Answers

Answer:[tex]\boxed{24}[/tex]Solution Steps:

______________________________

1.) Plug our numbers into the formula:[tex]B[/tex] × [tex]H[/tex][tex]6[/tex] × [tex]4=24[/tex]

______________________________

Look at the following expression. Which operation should be done first?
23 – 5 × 4 + 32 (a small 2 next to the 3)
1.) 5 × 4
2.) 32 (small 2)
3.) 4 + 3
4.) 23 – 5

Answers

Answer

2.

Step-by-step explanation:

If f(x) = 3x - 1 and g(x) = x + 2, find (f- g)(x).
I can’t find it

Answers

Answer:

[tex](f-g)(x)=2x-3[/tex]

Step-by-step explanation:

We are given the two functions:

[tex]f(x)=3x-1\text{ and } g(x)=x+2[/tex]

And we want to find:

[tex](f-g)(x)[/tex]

This is equivalent to:

[tex]=f(x)-g(x)[/tex]

By substitution:

[tex]=(3x-1)-(x+2)[/tex]

Simplify. Distribute:

[tex]=(3x-1)+(-x-2)[/tex]

Rearrange:

[tex]=(3x-x)+(-1-2)[/tex]

Therefore:

[tex](f-g)(x)=2x-3[/tex]

Percent is always out of _________ ?

Answers

Answer:

Percent is always out of 100

Step-by-step explanation:

Answer:

100

Step-by-step explanation:

Can someone PLEASE answer 5 and 6 for me?this assignment is due in a few minutes

Answers

Answer:

Yes they are equivalent because if you divide 18 by 6 it is 3 and if you do the same for 21 and 7 it also equals 3 which means they get paid 3 per hour

As for 6 they are not bec if we do the same from to 6 220/25=8.8 and 90/10=9 meaning they don’t have the same feet to inches

Step-by-step explanation:

I hope this helps and I’m not to late.

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