is that point to the left of the first two particles, to their right, or be- tween them? (b) should the third particle be positively or negatively charged? (c) is the equilibrium stable or unstable?

Answers

Answer 1

A third charged particle (does not matter whether it is a positive or negative charged particle) can be placed in between -3q and -q at x along .

Is  equilibrium stable or unstable?

Stable equilibrium exists when the object is in its lowest energy condition; metastable equilibrium exists when additional energy (ΔG) must be introduced before the object can reach true stability; unstable equilibrium exists when no additional energy is needed before reaching metastability or stability.

An equilibrium is asymptotically stable when f'(x)<0\ ; that is, the slope of f is negative. It is unstable when f'(x)>0\ . The left two equilibria in the figure are hyperbolic (f'(x) \neq 0), the others are non-hyperbolic because the slope (eigenvalue) is zero.

A system is said to be in stable equilibrium if, when displaced from equilibrium, it experiences a net force or torque in a direction opposite to the direction of the displacement. For example, a marble at the bottom of a bowl will experience a restoring force when displaced from its equilibrium position.

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Related Questions

a skier starts from rest on the higher peak. at what speed would she arrive at the lower peak if she just coasted without using poles? assume there is no friction.

Answers

The kinetic friction observed by skier when he starts from rest on the higher peak is 0.0.0313.

Here is the information we need:

h1 denotes the starting height (850 m)

The final height is given by h2 (750 m)

is the inclination angle (30°)

k is the kinetic friction coefficient.

The total distance traveled is given by d.

The distance traveled downward is denoted by d1.

The distance traveled uphill is denoted by d2.

Where:

d=d1 + d2 =h1/sin + h2/sin =850/sin30+750/sin30

=3200 m

Because the skier begins and ends at rest, the change in kinetic energy is zero.

When traversing a distance d, the energy dissipated by kinetic friction (negative sign) is equal to the change in gravitational potential energy.

[h2-h1]k =h1-h2d

=850-750/3200

=0.0313

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Complete question : Two snow-covered peaks are at elevations of 850 and 750 m above the valley between them. Both elevations have an incline of 30 degrees. A ski-run extends from the top of the higher peak to the top of the lower one. A skier starts from rest on the higher peak and stops on top of the lower peak. What is the kinetic friction coefficient?

a person walks first at a constant speed of 5.10 m/s along a straight line from point circled a to point circled b and then back along the line from circled b to circled a at a constant speed of 3.30 m/s. (a) what is her average speed over the entire trip?

Answers

The average speed of that person with two constant speed for a certain distance is 4 m/s.

How to calculate average speed over the entire trip?

Assume the distance from point a and b is c, As per data given velocity from a to b = 5.10 m/sec. So,

time a to b = c : 5.10.

Since the constant speed is 3.3. then

time b to a = c : 3.30

The we can determine the average speed as follow:

Total distance = c + c = 2c

Total time = time a to b + time b to a

Total time = c : 5.10 + c : 3.30

Total time = 0.196c + 0.303c

Total time = 0.499c

Average speed = total distance : total time

Average speed =  2c : 0.499c

Average speed = 4.00801603206

Let round the result, so the average speed = 4 m/s

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when two cars collide in real life they come to a stop. does this prove that conservation of momentum is not true in real life? explain

Answers

Some of the velocity from a collision between two vehicles crumples their bodies. A purposeful loss of kinetic energy occurs.

According to the rule of conservation of momentum, when two bodies contact in a closed or isolated system, their combined momentum before and after the collision must be identical if no outside force is acting on them. In other words, the system momentum is unchanged.

Momentum is defined as p = mv (in kg/s).

Where V is a body's speed, m = the body's mass, In order to maintain momentum

mv = unchanging

This is,

m1v1 = m2v2

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if dust deosnt have an intitial charge , then how can a charged object(such as a piece of paper) attract bits of dust, since coulombs law states tgat two different charges are needed for an attractive force?

Answers

Dust particles can acquire a charge through a process called triboelectrification, which occurs when two materials rub against each other, transferring electrons from one material to the other.

What is triboelectrification?

Triboelectrification is the phenomenon in which a charge is generated through the contact and separation of two materials. It is also known as "friction electrification" or "contact electrification".

When dust particles rub against a piece of paper, transferring electrons from the dust particles to the paper and giving the dust particles a negative charge. Once the dust particles have acquired a charge, they can be attracted to a charged object, such as a piece of paper, through Coulomb's law, which states that objects with opposite charges will experience an attractive force.

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what is the process of splitting a uranium atom called?
a. Nuclear Fusion
b. Nuclear Fission
c. Nuclear Confusion
d. Nuclear Dillusion

Answers

Nuclear fission produces energy when atoms split apart. All nuclear power plants utilise nuclear fission, and uranium atoms are frequently employed in nuclear power reactors.

When a neutron meets with a uranium atom during nuclear fission, it splits the atom, releasing a large amount of energy in the form of heat and radiation. Nuclear fission, another name for the splitting of atoms, generates radiation and radioactivity. In 1939, Dr. Lise Meitner made the discovery of how radioactivity may be created. She discovered that radiation could be released when a neutron, a tiny particle, was fired into another atom. Fission is the process by which a heavy, unstable nucleus splits into two lighter nuclei, whereas fusion is the joining of two light nuclei to release large amounts of energy.

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A 60 kilogram person jumps off a platform, landing while moving at 2. 0 meters per second. Determine the force exerted on the persons feet when he lands if he stops in 0. 25 seconds

Answers

The force exerted on the person's feet when he lands if he stops in 0. 25 seconds is found to be 480 N.  

What is Force?

Force may be characterized as a type of circumstance that significantly deals with the pushing or pulling of an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects.

According to the context of this question,

The mass of a person, m = 60 Kg.

The velocity of a person, v = 2.0 meters/sec.

The time is taken, t = 025 seconds.

The formula for calculating force is as follows:

F = mv/t.

          = 60 × 2 ÷ 0.25 = 480 N.

Therefore, the force exerted on the person's feet when he lands if he stops in 0. 25 seconds is found to be 480 N.

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a baseball player feels a frictional force of 400N as she slides into home. what impulse would be created?

Answers

The impulse that would be created by the  baseball player is  600 Ns.

What is the impulse created by the baseball player?

The impulse created by the baseball player is the product of force and time of the force impact.

J = Ft

where;

F is the applied forcet is the time of force action

The frictional force created by the baseball player = 400 N.

The time of force action = 1.5 seconds

The impulse that would be created by the  baseball player is calculated as follows;

J = 400 N x 1.5 seconds

J = 600 Ns

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The complete question is below:

A baseball player feels a frictional force of 400N as she slides into home. what impulse would be created if the force acted for 1.5 seconds?

1. A quarterback passes a football at a velocity of 15.2 m/s at an angle of 40° to the horizontal
toward an intended receiver 27.4 m downfield. The pass is released 1.3 m above the ground. Assume
that the receiver is stationary. Does he catch the ball to complete the pass if he were to catch the ball
at the same height it is released?

Answers

The intended receiver did not receive the ball since the ball travelled a shorter distance.

What is the time of motion of the ball?

The time of motion of the ball is calculated by applying the following formula as shown below.

h = vt + ¹/₂gt²

where;

v is the velocity of the ballg is the acceleration due to gravityt is the time of motion

1.3 = ( 15.2 x sin40 )t  +   ¹/₂ ( 9.8 )(t²)

1.3 = 9.8t  +  4.9t²

4.9t² + 9.8t - 1.3 = 0

solve the quadratic equation suing formula method;

t = 0.13 second

The horizontal distance of the ball is calculated as;

d = Vₓt

d = ( 15.2 x cos 40) x 0.13

d = 1.51 m

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asportscar, electro-fiasco i, can accelerate uniformly to 100 km/h in 3.5 s. its maximum braking rate can not exceed 0.7g. what is the minimum time required to go 1.0 km, assuming it begins and ends at rest?

Answers

The minimum time required to travel 1.0 km is 8.75 seconds.

What is travel?

Travel is the movement of people from one place to another, usually over a certain distance and for a certain period of time. It can be done for many reasons, including pleasure, business, or to visit family or friends.

This can be calculated by taking the total distance traveled (1.0 km) and dividing it by the average speed (100 km/h). The average speed is 100 km/h because the car accelerates uniformly from 0 km/h to 100 km/h in 3.5 seconds.
Therefore, the total time required is 10 seconds (1 km / 100 km/h). However, this does not take into account the deceleration time of the car, which must also be taken into account.
The maximum braking rate of the car is 0.7 g, which is equivalent to 7 m/s2. Since the car must come to a complete stop at the end of the 1.0 km journey, the time required for deceleration must be calculated. This can be done using the equation:
Time for deceleration = (Final Velocity - Initial Velocity) / Acceleration
Since the initial velocity is 0 m/s and the final velocity is 0 m/s, the equation simplifies to:
Time for deceleration = 0 / 7 m/s2 = 0 seconds
Therefore, the total time required to travel 1.0 km is 10 seconds (for acceleration) + 0 seconds (for deceleration) = 10 seconds. Subtracting this from the total time required gives us the minimum time required to travel 1.0 km, which is 8.75 seconds.

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a ferry boat shaped just like a brick is 7.7 m wide and 6.2 m long. when a truck pulls onto it, the boat sinks 5.57 cm in the water. what is the weight of the truck? the acceleration of gravity is 9.81 m/s 2 . answer in units of n.

Answers

The weight of the truck is approximately 254,979 N or 254.9 kN

To find the weight of the truck, we can use the principle of buoyancy, which states that the buoyant force exerted on an object submerged in a fluid is equal to the weight of the fluid that is displaced by the object.

First, we need to find the volume of the water displaced by the boat when the truck pulls onto it. We can use the dimensions of the boat and the amount it sinks in the water to calculate this. The boat is shaped like a brick, so we can assume it has the same dimensions on the top and bottom.

The boat's width is 7.7 m and its length is 6.2 m. The boat sinks 5.57 cm or 0.0557 m in the water.

The volume of the water displaced is the product of the boat's width, length, and the amount it sinks in the water.

Volume of water displaced = 7.7 m x 6.2 m x 0.0557 m = 25.9 m^3

Next, we can use the density of water, which is about 1000 kg/m^3 to find the weight of the water displaced.

Weight of water displaced = 1000 kg/m^3 x 25.9 m^3 = 25900 kg

Finally, we can use the weight of the water displaced to find the weight of the truck using the equation of buoyancy force which is equal to the weight of the fluid displaced.

Weight of truck = weight of water displaced x g

Weight of truck = 25900 kg x 9.81 m/s^2 = 254979 N

Therefore, the weight of the truck is approximately 254,979 N or approximately 254.9 kN.

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why (if you are careful) are you able to float a needle on the surface of water?water has adhesive properties.

Answers

Floating a needle on the surface of water is possible because of the phenomenon known as surface tension.

Surface tension occurs when molecules of a liquid stick together, creating a thin film of liquid on the surface. This film is able to support objects that are light enough to float.

The adhesive properties of water are due to its molecules bonding together, creating a strong force that allows it to hold objects on its surface. When a needle is placed carefully on water, it is light enough to be supported by the surface tension and the needle will float.

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the terminals of a 15 v battery. after a long time, the capacitor is disconnected from the battery but is not discharged. what are the charge on each electrode, the electric field strength inside the capacitor, and the potential difference between the electrodes a. right after the battery is disconnected? b. after insulating handles are used to pull the electrodes away from each other until they are 1.0 cm apart? c. after the original electrodes (not the modified electrodes of part b) are expanded until they are 20 cm in diameter?

Answers

After the original electrodes 0.8nC are expanded until they are 20 cm in diameter.

What is meant by diameter?

A line that is straight and cuts through the middle of a body or figure. Particularly: the length of a diameter; a line segment passing through the centre of a circle with its ends on the circumference.It is twice as long as a circle's radius, or Diameter = 2 Radius.The diameter of a circle cuts through the centre whereas the radius extends from the centre to the edges of the circle. The diameter of a circle effectively divides the shape in two.The diameter or length of a circle is its circumference. A straight line connecting a point on one end of the circle to a point on the other end, passing through the centre, is the diameter.

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A rock is thrown horizontally from a height of 6.00 m. what
is the time required for the rock to reach the ground

Answers

The time required for the rock to reach the ground is 1.11 second.

What is acceleration?

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

Initial height of the rock: h = 6.00 m.

Acceleration due to gravity: g = 9.8 m/s²

Let,  the time required for the rock to reach the ground is = t.

Then:

h = 1/2 × gt²

t = √(2h/g)

= √ {(2 × 6.00)/9.8} second.

= 1.11 second.

Hence, the time required for the rock to reach the ground is 1.11 second.

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Position (m)
0
12
10
5. Using the graph, describe what is happening between 4 and 6 seconds.
Position vs Time
6
Time (s)
8
10
12

Answers

In the position time graph, between 4 and 6 seconds, the object is at rest because the change in position with time is zero.

What is position - time graph?

A position - time graph is a type of graph in which the position of an object is plotted against time of motion of the object.

In a position time graph, the slope of the graph is the velocity of the object since velocity is defined as the change in displacement with change in time.

From the given position - time graph, between 4 to 6 seconds, the change in position of the object is constant, hence the velocity of the object will be zero, so we can conclude that the object is at rest between 4 to 6 seconds.

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his state no longer recongizes alienation of affection as an issue that can be litigated. which motion should

Answers

"A motion to dismiss should be filed if alienation of affection is not recognized as an issue that can be litigated in that state.

In physics, motion is defined as a change in a body's position or orientation over time. Translation is the term for motion along a line or a curve. Rotation is another motion that modifies a body's orientation.

The four types of motion are: linear, rotary reciprocating and oscillating.

Hence , If the state does not recognize alienation of affection as a matter that can be argued, a move to dismiss should be made.

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The question is incomplete, the complete question is:

"His state no longer recognizes alienation of affection as an issue that can be litigated. Which Motion should be filed ?

a 2.0-mm-diameter glass bead is positively charged. the potential difference between a point 2.0 mm from the bead and a point 4.0 mm from the bead is 500 v. what is the charge on the bead?

Answers

The glass bead has a 0.001 m radius. The distance between the first and second points from the bead's center is 0.003 and 0.005 meters, respectively.

How big is a circle's radius?

The radius of a circular is the distance a circle's center from any point along its perimeter. Usually, "R" or "r" is used to indicate it.

In geometry, what is a radius?

A radius is indeed a line segment that has one endpoint in the circle's center and the other terminus on the circumference of the circle. Circle's diameter equals the radius The diameter of a circle is a line segment that has its ends on the circle and passes through its center. Radius x 2 equals the diameter.

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a point charge of 8.74 x 10-6 c is at the origin while a second point charge of -5.91 x 10-6 c is at the coordinates (0.53, 0.41) meters. in degrees relative to the positive x direction, what is the direction of the force exerted on the charge at the origin?

Answers

The direction of the force on the charge at the origin is towards the charge at (0.53, 0.41) m, since the charges have opposite signs and attract each other.

The direction of the force exerted on a point charge at the origin by a second point charge can be found using Coulomb's law, which states that the force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them. The formula for the force is:

F = k * q1 * q2 / r^2

where k is the Coulomb constant (8.99 x 10^9 N * m^2 / C^2), q1 and

q2 are the charges, and

r is the distance between the charges.

To find the direction, we must first find the components of the force along the x and y axes.

Then, we can use arctan to find the angle relative to the positive x direction.

The distance between the charges can be found using the Pythagorean theorem:

[tex]r = \sqrt{((0.53 m)^2 + (0.41 m)^2)[/tex] = 0.65 m

The x and y components of the force can then be found using the formula:

Fx = F * cos(θ) = k * q1 * q2 * x / r^3

Fy = F * sin(θ) = k * q1 * q2 * y / r^3

where θ is the angle between the force and the positive x direction, and x and y are the x and y components of the displacement vector between the charges, respectively.

Finally, the direction of the force can be found using arctan:

θ = arctan(Fy / Fx)

The direction of the force on the charge at the origin is towards the charge at (0.53, 0.41) m,

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04.06 Recording Your Cardiovascular Workout— Flexibility/Cardiovascular Log
Type Name:
Type Date:
Flexibility
Date



Stretching exercise
Muscle worked
reps/time
reps/time
reps/time
Chest/Biceps Stretch
Pectoralis, Biceps






Shoulder/Triceps Stretch
Deltoids, Triceps






Upper Back & Torso Stretch
Trapezius






Lower Back Stretch
Latisimus Dorsi






Lying Quad Stretch
Quadriceps






Modified Hurdler’s Stretch
Hamstrings






Calf Stretch
Gastrocnemius






Lying abdominal stretch
Abdominals








**Remember to use the FIT principles to help you improve your flexibility.


















Target Heart Rate Zone (from lesson 04.02 Monitoring the Heart)
Lower Limit =
Upper Limit =
**Make sure you get your heart rate into this range during your workouts.
Cardiovascular
Date






Activity Selected






Starting heart rate






Heart-rate after 5 minutes









Heart rate after 10 minutes






Ending heart rate






5-minute recovery heart rate






Length of activity (minutes)









**Remember to use the FIT principles to help you improve your cardiovascular fitness.
Comments:

Answers

The FIT principles are a set of guidelines for designing effective exercise programs. They include:

Frequency: How often you perform the exercise. To improve flexibility, aim to stretch at least 2-3 times per week.

Intensity: How hard you work during the exercise. When stretching, intensity should be moderate and not painful.

Time: How long you perform the exercise. Hold each stretch for 15-30 seconds and repeat each stretch 2-4 times.

Type: The specific exercises you perform. Include a variety of stretches for different muscle groups, such as the hamstrings, quadriceps, and lower back.

How to explain the principle?

By following these principles, you can create a stretching routine that is effective for improving your flexibility. It's important to keep in mind that flexibility is also depend on several factors such as age, injury history, and genetics.

So, it's always good to consult with a physical therapist or physician before starting any new exercise program.

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note that in this arrangement, the net charge is zero (so we expect no monopolar field far away). the two visible dipoles also cancel, so we expect no dipolar field far away. what might we call the first surviving term in the distant field?

Answers

The first surviving term in the distant field in this situation might be referred to as a quadrupolar field.

The Distant Field Situation

The determination that the first surviving term in the distant field is a quadrupolar field is based on the fact that the net charge and the visible dipoles in the arrangement cancel out, leaving no monopolar or dipolar fields.

A quadrupole is a distribution of charges in which there are two positive and two negative charges of equal magnitude and opposite sign, arranged symmetrically about a central point.

A quadrupole generates a quadrupolar field, which falls off as the inverse cube of the distance from the source, as opposed to the inverse square of the distance for a dipole.

So when a net charge and dipoles are cancelled, the next term that could survive is the quadrupolar term.

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a quartz crystal vibrates with a frequency of 77,621 hz. what is the period of the crystal's motion?

Answers

Formula for period:

[tex]T=\dfrac{1}{f}[/tex]

period(measured in seconds) = 1 / frequency(measured in hertz)

__________________________________________________________

Given:

[tex]f=77,621Hz[/tex]

[tex]T=?[/tex]

__________________________________________________________

Finding period:

[tex]T=\dfrac{1}{f}[/tex]

[tex]T=\dfrac{1}{77,621}[/tex]

__________________________________________________________

Answer:

[tex]\fbox{T = 0.0000129}[/tex]

A black suv was driving east on Ridge, as the suv drove through an intersection on a green light it was immediately hit by a silver 4 door sedan. The black suv was hit on the driver's side, the suv spun halfway around and pushed on the sidewalk. Explain why the suv gets pushed and jumps the crib

Answers

Answer:

The black suv gets pushed and jumps the curb because of the momentum the silver sedan had during impact.

Explanation:

Because the silver sedan ran the light and hit the black suv at full speed, the momentum from the sedan will have enough force to push the black suv into the curb.

2 attempts left enter your answer in the provided box. a metal ball-bearing with a circumference of 41.3 mm weighs 8.77 g. what is the density of the metal in g/cm3 (v of a sphere

Answers

A metal ball bearing that has a 41.3 mm circumference weights 8.77 g. the metal has a density of 7.816 g/cm3. The mass of a material per unit of volume is its density.

We must first estimate the volume of the metal ball bearing before dividing the mass by the volume to obtain the density of the metal.

First  calculate the radius,

C = 2πr = 41.3mm = 4.13cm

here, we can find the radius,

r = c/2π = 4.13/2π = 0.65cm

to find the volume,

V = 4/3πr³

V = 4/3 π X 0.65³

V =  1.14cm³

now, to calculate density,

m = 8.77g

d = m/v

d = 8.77/1.14

d = 7.6 g/cm³

Finally, by dividing the mass by the volume, we get at the metal's density, which comes to around 7.6 g/cm3.

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1. A student is sitting on the edge of a swimming pool. The student repeatedly dips his foot in and out of the pool, making waves that move across the water. The student dips his foot slowly at first and then does it faster, each time to the same depth. Which of the following properties of the waves increases as the student dips his foot faster?
A. frequency
B. period
C. velocity
D. wavelength

Answers

Frequency of the waves increases as the student dips his foot faster.

What is frequency?

Frequency is a measure of how often something occurs over a given period of time. It can be used to measure the rate of events, such as the number of times a sound or light wave occurs in a given second. Frequency is measured in hertz (Hz), which is the number of occurrences per second. Frequency can also refer to the number of times a certain event occurs in a given sample size, such as the number of times a person visits a website in a month. It is a common measure used in statistics and is often used to compare data sets.

Therefore, Frequency of the waves increases as the student dips his foot faster.

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An aircraft decelerate at 0.5 m/.after 8 minute it velocity ha dropped to 160 m/ .find it initial velocity.

Answers

Acceleration (a) is the change in velocity (Δv) versus the change in time (Δt), given by the formula a = Δv/Δt. This allows you to measure how quickly the velocity changes in meters per second (m/s^2). Acceleration is also a vector quantity, so it contains both magnitude and direction. Negative acceleration is termed as deceleration

Deceleration can be calculated by dividing the final velocity minus the initial velocity by the time it takes for this velocity to drop.

The known and unknown quantities from the question are as follows:

u = initial velocity = ? m/s

v = final velocity = 160 m/s

a = acceleration = -0.5 m/s²

t = time interval = 8 min × 60 s/1 min = 480 s

Calculate the initial velocity using the following kinematic equation.

v = u + at

Solve for u.

u = v - at

u = 160 m/s - (-0.5 m/s² × 480 s) = 400 m/s

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The spring-held follower AB has a mass of 0. 45 kg and moves back and forth as its end rolls on the contoured surface of the cam, where r = 0. 15 m and z=(0. 02cos2θ)m. The cam is rotating at a constant rate of 30 rad/s. The spring is uncompressed when θ = 90∘

Answers

The body and through a specific angle experience angular accelerations of 0.87266 rad/sec2 and 12566.8 rad, respectively.

Calculate angular acceleration ?

A rotating rigid body's angular velocity rises from 500 to 1500 rev/min under the given conditions.

Time= 120s

Finding - Angle and angular acceleration

The basic idea is that we must change rev/min to rad/sec.

ωf= ωi + αt

ωf- ωi = αt

Formula for angular acceleration: = [f- i]/t

Angle deviation formula: =it + t2/2

Calculations-

Rev/Min to rad/Sec conversion

I equals 500 rev/min

500 x 2 rad/rev x 1 minute and 60 seconds equals 52.3598 rad/sec.

f = 1500 rev/min

=1500 x 2 rad/rev x 1 minute and 60 seconds = 157.079 rad/sec

52.3598 rad/sec for I

ωf=157.079rad/sec

Now, to calculate angular acceleration, use the formula: [f- i]/t.

52.3598 rad/sec − 157.079 rad/sec = 120

1.872666 rad/sec

To calculate the angle deviated, enter -=i t + t2/2.

=52.3598 x 120 + [0.87266 x 120 x120]/2

ΔФ= 12566.8rad

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a body at temperature of 100f is placed in a room of temperature 50. the room temperature does not change appreciably. if after 10 minutes the temperature of the body has dereased to 90 f, when will the body be at a temperature of 60*f?

Answers

The body will be at a temperature of 60°F after around 72 minutes.

The problem can be solved using Newton's law of cooling, which states that the rate of change of temperature of an object is proportional to the difference in temperature between the object and its surroundings. Mathematically, this can be represented as:

T(t) = T_s + (T₀ - T_s) e^(-kt)

where T(t) is the temperature of the object after time t, T₀ is the initial temperature of the object, T_s is the temperature of the surroundings, t is time and k is a constant of proportionality called the cooling coefficient.

Use the initial condition T = 90°F at t = 10 min, T_s = 50°F, T₀ = 100°F to solve for the value of k.

T(t) = T_s + (T₀ - T_s) e^(-kt)

90°F = 50°F + (100°F - 50°F) e^(-k)(10)

40°F = 50°F e^(-k)(10)

e^-10k = 0.8

k = 0.0223

thus we can calculate the time it takes for the body to reach a temperature of 60°F:

T(t) = T_s + (T₀ - T_s) e^(-kt)

60°F = 50°F + (100°F - 50°F) e^(-0.0223)(t)

10°F = 50°F e^(-0.0223)(t)

e^(-0.0223)(t) = 0.2

t = 72.1721

t ≅ 72 minutes

Therefore, it would take around 72 minutes for the body to reach a temperature of 60*F.

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what is the magnitude and direction of the electric force on an electron ina uniform electric field of strenght 2360n/c that points due east

Answers

The magnitude of the electric force on the electron is 2360 N and it points due east.

What is electric force?

Electric force is an attractive or repulsive force between two particles that have an electric charge. This force is generated when two charged particles interact due to their charges. The strength of the electric force depends on how much charge each particle has, as well as their distance from each other. Electric forces are responsible for phenomena such as static electricity and lightning, and they can also be used to power electric motors and other devices.

This is because an electric field exerts a force on a charged particle in the direction that is opposite to the direction of the field. Since the electric field points due east, then the force on the electron will point due west.

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1) define the term zenith. what constellation is at zenith right at sunset on january 20, 2023, and how did you use stellarium to figure it out?

Answers

The point of the celestial sphere that is directly opposite the nadir and vertically above the observer is known as Zenith.

Perseus, auriga, taurus, gemini are zenith at sunset tonight. Stellarium is a open software that shows real time 3d sky images. From which you can know the position of stars, planets, constellations and other sky objects. If you are using stellarium mobile app, just point it towards the sky and it will show the celestial objects with names. The rising constellations rotate based on our Earth and where it is as it travels through space. It can be predicted through stellarium.  The time period zenith every so often approach the best factor, way, or stage reached with the aid of using a celestial frame on its every day obvious direction round a given factor of observation.

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The point in the sky or the celestial sphere that is immediately above the observer is called the zenith.

The point on the celestial sphere that is immediately above a viewer on Earth is called the zenith. The nadir is the point directly beneath you that is 180 degrees opposite the zenith. To see your sky, drag the "Markings" pane to the side. You can now figure out the limits of the constellations.

On the meridian, roughly in the middle of the "sky," is where the zenith is located the area of the sky directly overhead, altitude = 90 degrees. In more specific terms, it is situated where declination and observer latitude are equal. The celestial equator and the ecliptic are additional reference points on the planisphere.

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at a specific moment, a falling object with mass 4 kg is moving 7 m/s and is 3 meters above the ground. how many joules of mechanical energy does the object have?

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A falling item with a mass of 4 kg is 3 metres above the earth and is travelling at a speed of 7 m/s at that precise time. The item has a mechanical energy of 216.4 Joules.

A falling object's kinetic energy (KE) and potential energy may be used to compute its mechanical energy (PE).

KE = 1/2 mv ²

= 1/2 X 4 X 14 = 98

where m is the item's mass and v is its velocity,

The equation PE = m * g * h gives the potential energy of an item.

PE =  4 X 9.8X 3 =  117.6

E = KE + PE gives the object's total mechanical energy.

E = 98 + 117.6

= 215.6 J

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Two people push on a shopping cart from opposite sides. In which situation

will the motion of the shopping cart stay the same?

A. The two people push with different amounts of force.

B. One of the people stops applying a force.

C. One of the people applies twice as much force.

D. The two people push with a balanced

face

Answers

Two people push on a shopping cart from opposite sides. Situation will the motion of the shopping cart stay the same, the correct option is (D) The two people push with a balanced face.

In this situation, the net force on the shopping cart will be zero, since the two forces are equal in magnitude and opposite in direction. If the forces are balanced, the shopping cart will not accelerate and will stay in the same state of motion (at rest or moving at a constant velocity). In scenario A and C, the forces are not balanced and therefore will cause acceleration. In scenario B, the net force will be non-zero and the acceleration will cause the shopping cart to change its velocity and direction.

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