In projectile mtion, what is the y-component of the initial velocity? if V= Vi = 100 m/s and the angle with horizontal axis Θ = 30 degrees

Answers

Answer 1

Answer:

hence the y - component of the velocity is 50m/s

In Projectile Mtion, What Is The Y-component Of The Initial Velocity? If V= Vi = 100 M/s And The Angle

Related Questions

Solid solutions containing two or more metal are commonly called alloys. True or false

Answers

Answer:

True

Explanation:

An alloy is a combination of metals or metals combined with one or more other elements. For example, combining the metallic elements gold and copper produces red gold, gold and silver becomes white gold, and silver combined with copper produces sterling silver.

Answer:

this is true

Explanation:

yes yes true

MUSIC

Progressions can start on any number of chords but usually end on the I.
true or false

Answers

Answer:

true

Explanation:

Answer:

false

Explanation:

A force of 900N acts on
a stationary body
for 40sec and the body acquires the velocity of360 m/s calculate mass a body.

Answers

Answer:

Explanation:

It is still using F = m*a -- just in a disguised form.

Givens

F = 900 N

vf = 360 m/s

vi = 0

t = 40 second

Formulas

a = (vf - vi)//t

F = m * a

Solution

a = (360 - 0)/ 40

a = 9

F = m * a

900 = m * 9

m = 900/9

m - 100 kg.          Doesn't seem high enough.

Answer:

a= V- u/t

a= 360 - 0 /40 = 9 m/sec2

F = MA

900 = M * 9

M = 900/9

M= 100 kg

when we say Mohit has Blue Eyes which part of the ice is begin referred to US blue​

Answers

Answer:

The iris

Explanation:

In the iris mohit have blue eyes Iris. The colored part of the eye which helps regulate the amount of light entering the eye. When there is bright light, the iris closes the pupil to let in less light. Ok so please mark me as brainleast

1. A race starts out at rest and accelerates to 30m/s over a period of 10s. What is the acceleration of the car?
O 3.0 m/s
O 3.0 m.s2
O 2.0 m/s2
O 5.0 m/s2

Answers

Answer:3.0m/s

Explanation:

A car weighing 19600N is moving with a speed of 30 m/sec on a level road. If it is brought to rest in a distance of 100 m. Find the average distance friction force acting on it

Answers

Answer:

F = -8820 N

Explanation:

Given that,

The weight of a car, W = 19600 N

Initial speed of the car, u = 30 m/s

It is brought to rest, final velocity, v = 0

Distance, d = 100 m

We need to find the average friction force acting on it.

Firstly we find the acceleration of the car using third equation of motion. Let it is a.

[tex]v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(0)^2-(30)^2}{2\times 100}\\\\=-4.5\ m/s^2[/tex]

Average frictional force,

F = ma

m is mass, [tex]m=\dfrac{W}{g}=\dfrac{19600\ N}{10\ m/s^2}=1960\ kg[/tex]

F = 1960 kg × -4.5 m/s²

= -8820 N

So, the average friction force acting on it is 8820 N.

A ball of radius R and mass m is magically put inside a thin shell of the same mass and radius 2R. The system is at rest on a horizontal frictionless surface initially. When the ball is, again magically, released inside the shell, it sloshes around in the shell and eventually stops at the bottom of the shell. How far does the shell move from its initial contact point with the surface

Answers

Answer:

[tex]x =\frac{-R}{2}[/tex]

Explanation:

From the question we are told that mass

Thin layer radius [tex]= 2R[/tex]

Generally the expression for ths solution is given as

Xcm =(m*0 =m(-2R))/2m =-mR/(2m)=-R/2

the center of mass will not move at initial state  

Considering the center of mass of both bodies

[tex]xcm=\frac{m*x+m*x)}{2m} =x[/tex]

[tex]x =\frac{-R}{2}[/tex]

Therefore the enclosing layer moves [tex]x =\frac{-R}{2}[/tex]                          

The shell move from its initial contact point with the surface is,

[tex]x =\dfrac{-R}{2}[/tex]

Given-

Radius of the ball is [tex]R[/tex].

the mass of the ball is [tex]m[/tex].

The mass of the thin shell is [tex]m[/tex].

The radius of the thin shell is [tex]2 R[/tex].

For the two bodies with mass [tex]m[/tex], the center of mass can be given as,

[tex]x_{cm}=\dfrac{m_{1} x_{1}+m_{2} x_{2} }{m_{1} +m_{2}}[/tex]

In the given question, the mass of both the bodies are equal and the given distance of center of mass for both bodies are also equal. Therefore,

[tex]x_{cm}=\dfrac{m x_+mx }{m +m}[/tex]

[tex]x_{cm}=\dfrac{2mx }{2m}[/tex]

[tex]x_{cm} =x[/tex]

Distance for center of mass can also be given as,

[tex]x_{cm} =m\times o[/tex]

[tex]x_{cm} =m\times \dfrac{-R}{2m}[/tex]

[tex]x_{cm} =\dfrac{-R}{2}[/tex]

Comparing both the values of the distance of center of mass we get,

[tex]x =\dfrac{-R}{2}[/tex]

Hence, The shell move from its initial contact point with the surface is,

[tex]x =\dfrac{-R}{2}[/tex]

For more about the center of mass follow the link below,

https://brainly.com/question/8662931

What the distance between 2 particles is doubled and the force between them is quartered, what is that called

Answers

Answer:

Coulomb's law.

Explanation:

If the distance between two particles is doubled and the force between them is quartered, this is known as Coulomb's law. Coulomb presented a law in which he states that when there is increase occur in distance between two objects, the force between them is decreases so if the distance between two particles or objects is doubled so the force between them is also quartered.

When an object moves, where does the energy come from?

Answers

Ans: Kinetic and potential energies are found in all objects. If an object is moving, it is said to have kinetic energy (KE). Potential energy (PE) is energy that is "stored" because of the position and/or arrangement of the object. The classic example of potential energy is to pick up a brick.

Answer:

Kinetic energy.

Explanation:

This is the energy of motion, observable as the movement of an object or subatomic particle. Every moving object and particle have kinetic energy.

HELP ASAP!! WILL TRY TO GIVE BRAINLIESTT!!

Please define the prefixes hyper-, hypo-, & iso- AND describe a solution that is hypertonic, hypotonic, & isotonic as well as compare how a living cell reacts when placed in a solution of each of the 3 types.

Answers

If a cell is placed in a hypertonic solution, water will leave the cell, and the cell will shrink. In an isotonic environment, there is no net water movement, so there is no change in the size of the cell. When a cell is placed in a hypotonic environment, water will enter the cell, and the cell will swell.

What is the net force of the diagram?

Answers

The answer is
For the diagram
90 N

A student rings a brass bell with a frequency of 200 Hz. The sound wave
travels through brass, air, and glass. What is the wavelength of the wave in
brass?
Medium
Wave speed
(m/s)
Brass
4,700
Air
346
Glass
5,640
A. 2.3 m
B. 0.43 m
C. 0.043 m
D. 23.5 m

Answers

Answer:

Option D. 23.5 m

Explanation:

From the question given above, the following data were obtained:

Frequency = 200 Hz

Speed of sound in brass = 4700 m/s

Wavelength of sound in brass =?

We can obtain the wavelength of the sound in the brass by using the following formula as illustrated below:

Wave speed = wavelength × frequency

4700 = wavelength × 200

Divide both side by 200

Wavelength = 4700 / 200

Wavelength = 23.5 m

Thus, the wavelength of the sound in the brass is 23.5 m

‼️can someone help me‼️


• What are the other two ways that you can rewrite the
formula F=ma?
• If I push a wheelbarrow, with a force of 240 N, with an
acceleration of 4 m/s2, how much mass does the
wheelbarrow have? (Solve using formula F=ma)

Answers

Answer:

Part A:

The other two ways we can rewrite F = m·a are;

1) F = dp/dt

2) F = m × d(v)/dt

Part B:

The mass of the wheelbarrow is 60 kg

Explanation:

Part A:

The other two ways of rewriting the equation are;

1) Force as the rate of change of momentum, F = dp/dt = d(m·v)/dt and

2) From the above equation, where, m is constant, we have;

F = d(m·v)/dt  = m × d(v)/dt

∴ F = m × d(v)/dt

Part B:

The force with which we push the wheelbarrow = 240 N

The acceleration, a, given to the wheelbarrow (by the applied force) = 4 m/s²

From F = m × a

Where;

m = The mass of the wheelbarrow

m = F/a = 240 N/(4 m/s²) = 60 kg

The mass of the wheelbarrow = m = 60 kg.

How much energy is required to raise the temperature of 5.0 g of silver from 298 K to
334 K?

Answers

Answer:

43.2J

Explanation:

Q = m × c × ∆T

Where:

Q = amount of energy

m = mass (grams)

c = specific heat capacity

∆T = change in temperature

Mass = 5.0g

Specific heat capacity of Silver (Ag) = 0.240 J/g°C

We need to convert the temperature from Kelvin (K) to °C

Initial temperature = 298 - 273 = 25°C

Final temperature = 334 - 273 = 61°C

Q = 5 × 0.240 × (61°C - 25°C)

Q = 1.2 × 36

Q = 43.2J

Indica en cada caso si estas fuerzas producen un efecto deformador o dinámico: a) Empujar un carro de la compra c) Atraer mediante un imán un clavo que estaba en reposo b) Modelar una figura de arcilla d) Lanzar una pelota de tenis

Answers

Answer:

Dynamic   a, b and d

Deformer  c and d

Explanation:

When a force is applied to an object, the acceleration may or may not change, which is analyzed from Newton's second law, this effect is a dynamic effect on the system; The environment can change the shape of the object, in this case the force creates a deformation in it.

With these clarifications let's analyze the different situations.

a) Dynamic. When pushing a car initially an acceleration is created in it, shortly after this decreases to zero and continues with constant speed.

b) Dynamic. When the nail moves it does not change the shape of the body that contains it, nor the shape itself, therefore the system can be analyzed with Newton's second law and the force is of the Dynamic type

c) Deformer. In this case the body (clay) has no net movement, but it does change its shape, so the effect of the force translates into a deformation of the system

d) Deformar and Dynamic. The launch of tennis balls has an initial deformation stage during the acceleration process, in this part the force is of the DEFORMING type, but during the trajectory the deformation disappears and the ball has (gravity) a DYNAMIC action

a ball bounce on the ground. at what position (A,B,C)does the ball have the greatest potential energy? kinetic energy? explain your answer.​

Answers

Answer:

What is the meaning of the kinetic I think the answer is both the ball has both Kinetic and potential energy so I think is the answer is true

What movement allows us to move our side to side?

Answers

Answer:

Ball-and-socket joints

Explanation:

at constant pressure by what fraction of its volume will aquantity of gas change if the temperature changes from -173degree C to 27degree C

Answers

Answer:

The volume of the gas becomes three times the initial volume.

Explanation:

Given that the pressure is constant, and temperature changes from -173degree C to 27degree C.

So, the initial temperature, [tex]T_1[/tex] = -173 degree C = -173+273 = 100 K.

The final temperature, [tex]T_2[/tex]= 27 degree C = 27+273=300 K.

As the pressure is constant, so [tex]P_1=P_2[/tex].

Let V_1 and V_2 be the initial and final volume respectively.

Assuming that the given gas is ideal gas.

So, applying the ideal gas equation

PV=nRT

where n is the number of moles of the gas and R is the universal gas constant.

For the initial state, [tex]P_1V_1=n_1RT_1\cdots(i)[/tex]

and for the final state, [tex]P_2V_2=n_2RT_2 \cdots(ii)[/tex]

Dividing the equation (i) by (ii), we have

[tex]\frac {P_1V_1}{P_2V_2}=\frac {n_1RT_1}{n_2RT_2} \\\\\frac {P_1V_1}{P_2V_2}=\frac {n_1T_1}{n_2T_2}[/tex]

As the mass of the gas is not changing, so [tex]n_1=n_2[/tex], then

[tex]\frac {P_1V_1}{P_2V_2}=\frac {T_1}{T_2}[/tex]

As the pressure is not changing, so [tex]P_1=P_2[/tex], then

[tex]\frac {V_1}{V_2}=\frac {100}{300}[/tex]

[tex]V_2=3V_1[/tex]

So, the volume of the gas becomes three times the initial volume.

The law of __________________________ says that people think of similar objects as belonging together.

Answers

Answer:

Explanation:is the law means that the police are the law

I think the answer would be the principle of similarity.. It states that when things appear to be similar to each other that people tend to group the objects together. Also they tend to think of them as the same function. Not totally sure, but I hope this helped.

Calculate the aceleration of a vehicle of 100 kg when applicates 400 N

Answers

Answer:

For this we applicate 2nd law of Newton:

F = ma

Replacing:

400 N = 100 kg * a

a = 400 N / 100 kg

a = 4 m/s²

The aceleration is 4 meters per second squared.

Answer:

....................

Explanation:

---------------------

what is gravity???☺️

Answers

Answer:

Gravity

Explanation:

its an invisible force that pulls objects

toward each other.

hope it helps

A force that pulls objects downwards

a beaker weighs 0.4N when empty and1.4N when filled with water what does ot weigh when filled with brine of density 1.2 g/cm3

Answers

Answer:2.47

Explanation:

So, the beaker weighs 1.40N when filled with water, brine of density weighs about 1.7N, you add the density + water. Have a good day!

How do the summer monsoons of India affect the hydrosphere, geosphere, and biosphere?

Answers

Answer:

Explanation:

The monsoon rains are the main source of water for 55 percent of the country’s arable land. This means the rains are crucial — not only for India’s farmers, but for its economy as a whole. Now, that’s a good thing when the monsoon arrives on time and brings the right amount of rain. But when it’s late or weak, it leads to drought.

Which one hits the ground first, a
bullet dropped from a height, or a
bullet fired simultaneously from
the same height?

Answers

Answer:

A bullet fired simultaneously from the same height

Explanation:

It will reach the ground first because a greater force is being acted upon it. The first option is only acted on by gravity

An explosion occurs at the end of a pier. The sound reaches the other end of the pier by traveling through three media: air, fresh water, and a slender metal handrail. The speeds of sound in air, water, and the handrail are 355, 1480, and 5490 m/s, respectively. The sound travels a distance of 117 m in each medium. (a) After the first sound arrives, how much later does the second sound arrive

Answers

Answer:

0.05773 sec

Explanation:

We know that

time = distance/speed = d/V

for air

t1 = 117/355 = 0.3295 sec

for fresh water

t_2 = 117/1480 = 0.07905 sec

for metal

t_3 = 117/5490 = 0.02131 sec

So as we can see sound will reach through metal hand rail 1st, then through fresh water and then through air

1st = metal hand rail

2nd = fresh water

3rd = air

time difference between 1st and 2nd sound = t_2 - t_3 = 0.07905 - 0.02131 = 0.05773 sec

A sign is attached to the side of a building as seen below. The sign is attached to a steel rod. A wire connects to the end of the rod for support. The mass of the sign is 50 kg. Determine the supporting force exerted by the cable

Answers

Answer:

500N

Explanation:

50kgx10N/kg

= 500N

Why is a teacher's feedback valuable?

Answers

Answer:

Because they could help you move on better with your strategy and ultimately get you better scores on tests  

Answer:

Through feedback, teachers can provide the students with suggestions for development, learning strategies and corrections for errors. The importance of constructive feedback allows for many positive opportunities. This component also enhances a student's self-efficacy and provides an avenue for motivation.

Mr. D's dog Gromit jumped out of a second story window (through the screen) and fell to the ground below. The window is 15 feet high, the acceleration of gravity is 9 m/s', and there are 3.28 feet in each meter. What was the final velocity of this crazed dog? (True story, don't worry he's fine and now he knows about gravity)

Answers

Answer:

Vf = 9.46 m/s

Explanation:

In order to find the final velocity of the dog we can use third equation of motion:

2gh = Vf² - Vi²

where,

g = acceleration due to gravity = 9.8 m/s²

h = height of window = (15 ft)(1 m/3.28 ft) = 4.57 m

Vf = Final Velocity of Dog = ?

Vi = Initial Velocity of Dog = 0 m/s

Therefore,

(2)(9.8 m/s²)(4.57 m) = Vf² - (0 m/s)²

Vf = √(89.572 m²/s²)

Vf = 9.46 m/s

If y is inversely proportional to x and y = 4 and x=10, find y when x = 20

Answers

Answer:

Y=8

Explanation:

Y=4

X=10

if x is 20 it means it is doubled frm the previous therefore it means even y has to be doubled

first. now

x=10. x=20

y=4. y=8

A single celled organism is found in a sample of water. It contains a nucleus as well as other membrane bound organelles and possesses collagen for movement. This organism most likely belongs to which kingdom?

Answers

Answer:

Explanation:

The cell is the smallest living organism that contains all the features of life, and most all life on the planet begins as a single-cell organism. Two types of single-celled organisms currently exist: prokaryotes and eukaryotes, those without a separately defined nucleus and those with a nucleus protected by a celluA single-celled organism is found living in a deep sea vent at the bottom of the ocean in extremely hot water. If it is examined further, which of the following is most likely to be found within it? It will have DNA that is not contained in a nucleus since it is likely a member of the domain Archaea.lar membrane.

The answer is Protista.

Hope this helps. :)
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