in a reaction of an acid that has an equal amount of a base, the ph changes to a value that is closer to

Answer:

15.6 moles

Explanation:

For every 2 moles of H3PO4 that is reacted, 6 moles of H2O are produced.

So if 5.2 moles of H3PO4 are reacted with calcium hydroxide, calculate the moles of H2O produced by this:

5.2 moles H3PO4 * (6 moles H2O / 2 mole H3PO4) = 15.6 moles H2O

Therefore 15.6 moles of H2O would be produced if 5.2 moles of H3PO4 are reacted with calcium hydroxide.

Coal, oil, and natural gas are examples of fuels that store chemical energy. The chemical energy in these fuels is transformed into heat energy when they are burnt. Some fuels, known as fossil fuels.

are composed of the remnants of plants and animals that existed millions of years ago.Coal was generated by burying dead plants in mud and silt, which prevented them from decaying. More muck covered and squished the plants over time, and the sludge hardened into rock.Coal, oil, and natural gas are examples of fuels that store chemical energy. The chemical energy in these fuels is transformed into heat energy when they are burnt. Some fuels, known as fossil fuels. The dead plants were converted into coal. Plants and animals that fell to the sea floor and were covered by silt produced oil and Coal, oil, and natural gas are examples of fuels that store chemical energy. The chemical energy in these fuels is transformed into heat energy when they are burnt.

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Mole present in 85 grams of calcium is 2.12 moles

It is given that

given mass of calcium = 85 grams

molar mass of calcium = 40 grams

We have to find the moles

The mole is the amount of substance of a system which contains as many elementary entities as there are atoms in 0.012 kilogram of carbon 12, its symbol is “mol”

moles = given mass/molar mass

moles = 85 gram/40 gram

moles = 2.12

Hence, moles in 85 grams of calcium is 2.12 moles

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The fact that the amount of substances is fundamental means that its unit, the mole should be a base unit.

We have to know that the SI unit is the internationally accepted unit that we can be able to use to obtain the quantities that are basic in physics. We know that there are some units that we call the base units.

The reason why we call them the base units is because all other computations are based on them. The mole should be a base unit because the mole deals with the amount of substance which is quite fundamental in science.

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Answer: An element has 2 isotopes: 6X at 7.59% and 7X at 92.41%. What is the average atomic mass?

Explanation:

In a bid to  calculate the average atomic mass, we  multiply the fraction of each isotope by the mass number , then add them together.

This is more like weighted average, as shown below:

average atomic mass=(mass number of first isotope*fraction)+(mass number of second isotope*fraction)

average atomic mass=(6X*7.59%)+(7X*92.41%)

average atomic mass= 6.92X

We can calculate the molarity by dividing the quantity of barium hydroxide in moles by the volume of the initial solution.

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Volume of one mole of gas at STP = 22.4 L

number of particles in one mole of any substance = 6.022 ×10²³

What is the mass of 9.30 mole of SiH₄ = 298.81

The mole, abbreviated as mol, is the International System of Units' unit of material amount (SI). The amount of substance is a metric for how many elementary entities of a specific substance there are in a given object or sample. An elementary entity can be any of the following, depending on the substance: an atom, a molecule, an ion, an ion pair, or a subatomic particle like an electron. For instance, although having different volumes and masses, ten moles of water (a chemical compound) and ten moles of mercury (a chemical element) contain precisely the same amount of substance and each ion in the mercury is present in exactly one molecule of water.

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The graph below shows the phase change for water. The statement that describes what is occurring at segment C is energy and temperature remain the same. The correct option is D.

A phase diagram is a visual representation of a substance's physical state under various pressures and temperatures.

Temperature is on the x-axis and pressure is on the y-axis in a typical phase diagram. Phase changes happen as we go across the lines or curves on the phase diagram.

Therefore, the correct option is D. Energy and temperature remain the same.

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The question is incomplete. Your most probably complete question is given below: the graph is attached.

The bromobenzene used in the experiment was equimolar to 3.7 grams of benzophenone. The correct answer is C. 

The stoichiometry of a chemical reaction tells us the relative amounts of reactants and products involved in the reaction. In this case, the reaction is between bromobenzene and benzophenone to form a new compound.

The balanced equation for this reaction is:

From the equation, we can see that one mole of bromobenzene reacts with one mole of benzophenone. Therefore, an equimolar amount of benzophenone is the same as the amount of bromobenzene used in the experiment. Since the molar mass of benzophenone is 182.23 g/mol, we can use this value to calculate the mass in grams by multiplying it with the number of moles.

To calculate the equimolar amount of benzophenone, we use the following formula:

Let's assume that the mass of bromobenzene used in the experiment is x. Hence:

Therefore, the equimolar amount of benzophenone is 3.7 grams.

This question should be provided with answer choices, which are:

The correct answer is C.

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If the natural abundance of chlorine-35 is 75.8% and that of chlorine-37 is 24.2%, then the average atomic mass of chlorine will be 35.44 amu.

Chlorine exists in two isomeric forms which are the chlorine-35 and chlorine-37. The atomic mass of the chlorine elements is basically the average atomic mass of its isotopes depending upon their abundance in nature.

The atomic mass of chlorine-35 is 34.97amu and a natural abundance equal to 75.8 %. The atomic mass of chlorine-37 is equal to 36.97 amu with an abundance of 24.2%.

To calculate the average atomic mass of chlorine,

The abundance of chlorine-35 = 75.8% = 0.758

The abundance of chlorine-37 = 24.2% = 0.242

⇒ Average atomic mass = 34.97 × 0.758 + 36.97 × 0.242

⇒ Average atomic mass = 26.50 + 8.94

⇒ Average atomic mass = 35.44 amu  

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A 64.8 g 64.8 g sample of the compound x2o5 x 2 o 5 contains 48.0 g 48.0 g of oxygen atoms. The molar mass of element x is 56 g/mol.

To determine the molar mass of element X, we can use the information provided about the mass of the compound and the mass of the oxygen atoms.

First, convert the mass of the compound to moles by dividing it by the molar mass of the compound:

(64.8 g) / (molar mass of X2O5) = moles of X2O5

Next, use the moles of X2O5 to determine the moles of oxygen atoms by multiplying by the number of oxygen atoms per molecule of X2O5:

moles of X2O5 x (5 moles of O / 1 mole of X2O5) = moles of O

Then, convert the mass of the oxygen atoms to moles by dividing it by the molar mass of oxygen:

(48.0 g) / (16.00 g/mol) = 3.00 moles of O

We know that the mass of the compound is equal to the mass of the element X and the mass of the oxygen atoms.

mass of X = mass of the compound - mass of the oxygen atoms

mass of X = 64.8 - 48.0 = 16.8 g

convert the mass of element X to moles by dividing it by the molar mass of X:

(16.8 g) / (molar mass of X) = moles of X

Now we can calculate the molar mass of element X by using the moles of X and the mass of X

molar mass of X = mass of X / moles of X

molar mass of X = 16.8 g / (3.00 moles of O x (1 mole of X2O5 / 2 moles of X)) = 56 g/mol.

The molar mass of element X is 56 g/mol.

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The mass of NO2 produced by the reaction is 24.61g when the initial mass of 16.07g NO, an excess of O2 is converted to product NO2.

Given the chemical reaction: 2NO(g) + O2(g) + 2NO2(g)

The equation is balanced.

The initial mass of NO is (m) = 16.07g

Here first we calculate the number of moles of NO is used = mass/Molar mass of NO

moles of NO used = 16.07/30 = 0.535

An excess of O2 is used so we can neglect that.

Now calculate the moles of NO2 produced.

moles of NO2 =  0.535 x 2 mol(NO2) / 2mol(NO) =  0.535

we can determine that NO is the limiting reactant.

To convert from moles to mass, use the product's molar masses.

Molar mass of NO2 = 46g/mole

Then the mass of NO2 produced = 0.535 x 46 x 1 = 24.61g

Hence the mass of NO2 produced by the reaction is 24.61g

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The number of mole of methane, CH₄ needed to produce 5.75 moles of water vapour is 2.875 moles

We'll begin by obtaining the moles of CH₄ that reacted from the balanced equation:

CH₄ + 2O₂ -> CO₂ + 2H₂O

From the balanced equation above,

2 moles of H₂O were obtained from 1 mole of CH₄

Using the above information, we can determine the number of moles of CH₄ needed for the reaction. Details below:

From the balanced equation above,

2 moles of H₂O were obtained from 1 mole of CH₄

Therefore,

5.75 moles of H₂O will be obtained from = (5.75 × 1) / 2 = 2.875 moles of CH₄

Thus, we can conclude that the number of moles of CH₄ needed is 2.875 moles

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Answer:

Explanation:

Dipole-dipole interactions are a type of chemical bonding that occurs between two polar molecules. In a dipole-dipole interaction, the positively charged end of one molecule is attracted to the negatively charged end of another molecule. This creates a strong force between the two molecules, which holds them together. Dipole-dipole interactions are weaker compared to covalent and ionic bonds, but they can still play an important role in determining the properties of a substance.

The value of the Kp is 0.0036.

Kp is used to represent the equilibrium constant expression in terms of partial pressure. Equilibrium constant Kp is measured when the partial pressure of products is divided by partial pressure of reactants and the partial pressure are raised with some power which is equal to the coefficient of the substance present in the balanced chemical equation.

                      A    +     B     ⇆     2C

t = 0              3.4         7.5            0

Equilibrium  3.4 - x     7.5 - x      2x

According to the question,

2x = 0.57

⇒ x = 0.57/2 = 0.285

Kc = (2x)²/{(3.4 - x) (7.5 - x)}

⇒Kc = (0.285)²/(3.115 × 7.215)

⇒Kc = 0.081225/22.47425

⇒Kc = 0.0036

The given question is incomplete so I have answered it on general basis.

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The concentration of the strontium hydroxide, Sr(OH)₂ solution is 0.083 M.

The pH of a solution is a measure of the molar concentration of hydrogen ions in the solution and as such is a measure of the acidity or basicity of the solution.

The letters pH stand for "power of hydrogen" and the numerical value is defined as the negative base 10 logarithms of the molar concentration of hydrogen ions.

Mathematically;

pH = - log [H⁺]

pOH = 14 - pH

where;

[H⁺] = concentration  of hydrogen ions

[OH⁻] = concentration of hydroxide ions

pOH = 14 - 13.22

pOH = 0.78

The concentration of hydroxide ions in the solution is:

[OH⁻] = 10⁻⁰°⁷⁸

[OH⁻] = 0.166 M

The concentration of the strontium hydroxide, Sr(OH)₂ solution = 0.166/2 M

The concentration of the strontium hydroxide, Sr(OH)₂ solution = 0.083 M

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The element whose mass number is 115 and contains 65 neutrons per atom, its atomic number will be-

Atomic Number (Z) = Mass Number (A) - Number of Neutrons (N)

Z = 115 - 65

Z = 50

So, the atomic number for the given element is 50.

Tin is the element with the symbol Sn which has an atomic number of 50. Tin is classified as a post-transition metal. Tin is a silver-coloured metal and remains solid at room temperature.

The atomic number is the number of protons in an atom. Due to this, it is sometimes named the proton number. The atomic number is indicated by the letter Z. The symbol Z is derived from the German word Zahl, which means several numerals.

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The de Broglie wavelength of a particle is given by the equation:

λ = h / p.

Where λ is the de Broglie wavelength, h is Planck's constant (6.62607015 x 10^-34 Js) and p is the momentum of the particle.. The de Broglie wavelength of an oxygen molecule at room temperature is on the order of 4.8 x 10^-10 m. This wavelength is much smaller than the average distance between oxygen molecules in a gas at 1 atm, which is about 2 x 10^-10 m. This means that the de Broglie wavelength of an oxygen molecule is much smaller than the distance between the oxygen molecules and it is not possible to see the interference or diffraction patterns of individual molecules in most cases.

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If 19.4 grams of ammonium chloride are used, option D (10.63 g) of water are theoretically produced.

The balanced equation for the reaction between ammonium chloride and water is:

NH4Cl + H2O ---> NH3 + HCl

From the balanced equation, we can see that for every 1 mole of NH4Cl, 1 mole of H2O is produced.

To find out how many grams of water are theoretically produced, we can use the conversion factor of 1 mole = molar mass.

The molar mass of NH4Cl is (114.01 + 41.01) = 18.05 g/mol

19.4 g of NH4Cl is equal to 19.4/18.05 = 1.07 mol

So, theoretically 1.07 mol of H2O is produced, which is equal to the molar mass of H2O (18.02 g/mol) x 1.07 mol = 19.37 grams of water.

So, the answer is 19.37g of water.

Therefore, The correct answer is 19.37g, but option D (10.63 g) is the nearest correct answer as the question given.

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Chaulmoogra oil has long-chain fatty acids, but the ethyl esters generated using the ball process include shorter-chain fatty acids. Because shorter chain fatty acids may more easily.

enter cell membranes, they are more quickly absorbed by the body. Furthermore, the ethyl esters are more water-soluble than the oil, allowing for improved absorption. The big, insoluble molecules of long-chain fatty acids in chaulmoogra oil are most likely responsible for the production of painful bubbles. The ethyl esters' short chain fatty acids are less prone to create such bubbles and hence less unpleasant.comparing the structures of chaulmoogra oil with the ethyl esters formed by the ball method, why do you think the ethyl esters might be more readily absorbed by the body (and not form the painful bubbles like the oil) The big, insoluble molecules of long-chain fatty acids in chaulmoogra oil are most likely responsible for the production of painful bubbles. The ethyl esters' short chain fatty acids are less prone to create such bubbles and hence less unpleasant.comparing the structures.

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Neither Compound A nor Compound B is aromatic.

The statement "compound A is a 3 carbon ring with a double bond between carbons 1 and 2. carbon 3 has a lone pair and a negative charge and is bonded to one hydrogen" and "compound b is a 5 carbon ring with two double bonds. the non-alkene carbon has a carbocation" is true.

Compound A is not considered to be aromatic because it does not meet the criteria for aromatic compounds. Aromatic compounds have a specific type of cyclic and fully conjugated system of electrons which allows them to have delocalized pi electrons and a cyclic ring of alternating single and double bonds. Compound A has a three-carbon ring with a double bond between carbons 1 and 2, but the third carbon has a lone pair and a negative charge, which breaks the conjugation of the ring.

It also lacks the cyclic ring of alternating single and double bonds, which is a requirement for aromaticity.

Compound B is not considered to be aromatic because it does not meet the criteria for aromatic compounds. Aromatic compounds have a cyclic ring of alternating single and double bonds. Compound B has a 5-carbon ring with two double bonds but it also has a carbocation which again breaks the conjugation of the ring and it is not a cyclic ring of alternating single and double bonds.

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The change in entropy Δs when 3.4 g of diethyl ether condenses at 34.6 °C is 4.1 J/K.

Enthаlpy (H) is defined аs the аmount of energy releаsed or аbsorbed during а chemicаl reаction. Entropy (S) defines the degree of rаndomness or disorder in а system.

The relаtionship between both pаrаmeters is given аs;

ΔS = ΔH ÷ T

ΔH = 26.7 KJ/mol for 1 mol of diethyl ether

number of moles = mаss ÷ molаr mаss

number of moles = 3.4 ÷ 72 = 0.04722

ΔH = 26700 × 0.04722 = 1260.77 J

T = 34.6 + 273 = 307.6 (upon converting to Kelvin temperаture)

ΔS = 1260.77 ÷ 307.6

ΔS = 4.1 J/K

Your question is incomplete, but most probably your full question can be seen in the Attachment.

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The amount of heat needed to boil 15.5 g of methanol (ch3oh). the molar heat of vaporization for methanol is 35.21 kj/mol. the molar mass of methanol is 32.04 g/mol.

To calculate the amount of heat needed to boil 15.5 g of methanol, we need to use the formula: Q = mL

Where Q is the heat energy, m is the mass of the substance, and L is the molar heat of vaporization.

First we need to find the moles of methanol:

moles = mass / molar mass

moles = 15.5 g / 32.04 g/mol = 0.4828 moles

Then we can calculate the heat energy required to boil the methanol:

Q = mL

Q = 0.4828 moles * 35.21 kJ/mol

Q = 17.04 kJ

So, 17.04 kJ of heat energy is required to boil 15.5 g of methanol.

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If we have 325 grams of glucose and 137 grams of oxygen, the limiting reagent is oxygen. The mass of carbon dioxide that will be produced is 137 grams.

This means that the reaction will be limited by the amount of oxygen available, and not by the amount of glucose. The mass of carbon dioxide that will be produced will be equal to the mass of oxygen used in the reaction. In this case, 137 grams of carbon dioxide will be produced.

The reaction can be written as: glucose + oxygen --> carbon dioxide + water. This equation shows that for every molecule of glucose, 6 molecules of oxygen are needed to produce 6 molecules of carbon dioxide and 6 molecules of water.

Therefore, the amount of carbon dioxide produced will depend on how much oxygen is available. In this case, 137 grams of oxygen is available, so 137 grams of carbon dioxide will be produced.

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The equation must have the following form to be balanced: 4CO2 + 2H2O = 2C2H2 + 5O2

S8: O2 = 1/8; S8 utilized = 240/8 = 30SO2 generated is equal to the number of sulphur molecules used, which is 240. Stoichiometry is the name given to the study of chemical processes in mathematics. Numerous calculations can be done, such as stoichiometry, which is most usually performed with moles but can also be done with masses and even percentages. Stoichiometric ratio A stoichiometric ratio is important when considering the interactions between specific elements or molecules. This exact ratio of reactant to product coefficients is necessary for a reaction to occur properly. Let's discuss some problems you can run across when you learn about stoichiometry. Chemical Equations in Balance Equations needing to be balanced is a fairly common stoichiometric issue type. This is an essential chemistry skill since a reaction can only occur if the ratio of reactants to products is correct.possess. Additionally, it provides an essential framework for organic chemistry. Balance the ensuing reply: _ CO2 + _ H2O C2H2 + _ O2 To be balanced, equations must have an equal number of each element on both sides of the reaction. Before balancing the oxygen, you can start by balancing the carbons and hydrogens. The equation must have the following form to be balanced: 4CO2 + 2H2O = 2C2H2 + 5O2

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If 0.5 L of air at 203 k in an expandable container at constant pressure. The volume of air at 273 K would be 0.67 L.

The universal (or perfect) gas constant is 8.314 joules per kelvin per mole, according to the ideal gas law, which stipulates that PV is equal to nRT. n is the number of moles of the gas.

The Ideal Gas Law states that when a gas is at a given temperature, pressure, and volume, it has an equal number of molecules (but not the same mass)

V₁=0.5 L

T₁=203 K

V₂= 273 K

V₂ = unidentified

Now, V₁/T₁=V₂/T₂

So,

0.5L/203 = V₂/273

V₂= 0.67 L

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Atomic mass is the sum of the total number of protons and neutrons in an atom, while atomic number is the number of protons in the nucleus of an atom.

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Answer:

The answer is B

Explanation:

That's what the person above said.

Answer:

At standard temperature and pressure (STP), which is defined as 0 °C (273.15 K) and 100 kPa (1 atmosphere), several elements exist as gases.

The elements that are gases at standard temperature and pressure include:

Helium (He)

Neon (Ne)

Argon (Ar)

Krypton (Kr)

Xenon (Xe)

Radon (Rn)

Hydrogen (H2)

Answer:

At standard temperature and pressure (STP), which is defined as 0 °C (273.15 K) and 100 kPa (1 atmosphere), several elements exist as gases.

The elements that are gases at standard temperature and pressure include:

Helium (He)

Neon (Ne)

Argon (Ar)

Krypton (Kr)

Xenon (Xe)

Radon (Rn)

Hydrogen (H2)

A reaction between a methane and oxygen molecule collision could not occur for a number of reasons: (1) The energy of the impact could not be sufficient to withstand the reaction's activation energy.

(2) The reactant molecules may not establish chemical connections with one another because the impact may not be directed properly. (3) The reactant molecules may not have enough time to form chemical interactions with one another after the impact. (4) It's possible that the reactant molecules lack particular characteristics, such as a specific quantity of unpaired electrons, which are required for chemical reactions to occur. (5) The reaction may be reversible and the products' ability to reactivate the reactants may need more energy.

the smallest component of a material that possesses both its chemical and physical characteristics. One or more atoms make up molecules.

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The total pressure of the gases inside the container is the sum of the partial pressures of all the gases present.

The partial pressure of a gas is the pressure that the gas would have if it were alone in the container at the same temperature. In this case, the container holds three gases: Gas A, Gas B, and Gas C. The partial pressures of Gas A, Gas B, and Gas C are given as 453.9 mmHg, 287.6 mmHg, and 382.4 mmHg, respectively. To find the total pressure of the gases inside the container, we add the partial pressures of all three gases: 453.9 mmHg + 287.6 mmHg + 382.4 mmHg = 1123.9 mmHg. Therefore, the total pressure of the gases inside the container is 1123.9 mmHg.

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