I would thank u a bunch of u could help me with this! ASAP

Answer:

40

Step-by-step explanation:

20 x 2 because you will need 2 bags per kg

Answer:

Step-by-step explanation:

We will use a proportion to solve this.

x/y = x/y

let x = the number of families in each case

let y = the number of plants in each case

Since we don't know the second y, we will leave that as y and solve for it.

50/150 = 65/y

Cross-multiply

50y = 9750

Divide

195  = y

Now, we can check this by substituting the value of y back into the equation and seeing if both sides equal.

50 (195) = 9750

9750 = 9750 ✅

Answer:

$100

Step-by-step explanation:

since 1 hockey mask costs $10 and you need 10 masks you can multiply 10x10 and you will get 100

Answer:

positive

Step-by-step explanation:

even negatives = positive

whatever positives = positive

positive*positive = positive

Answer:

required answer is 9 of your question

Answer:

[tex]T(ln2)[/tex][tex]= <\sqrt{145} , \frac{6\sqrt{2} }{\sqrt{145} } , \frac{6\sqrt{2} }{\sqrt{145} } >[/tex]

Step-by-step explanation:

Given : [tex]r(t)=<7-\sqrt{e^t}, 3e^t,3e^t > .........(i)[/tex]

We first have to differentiate of equation [tex](i)[/tex]

[tex]r'(t) = < \frac{\sqrt{e^t} }{2} , 3e^t,3e^t> ..........(ii)[/tex]

Now to get a unit tangent vector at the given value of [tex]t[/tex], we put [tex]t = ln2[/tex] in equation [tex](ii)[/tex]

[tex]r'(ln2) = < \frac{\sqrt{e^{ln2}} }{2} , 3e^{ln2},3e^{ln2}>[/tex]

            [tex]= <\frac{1}{\sqrt{2} } ,6,6>[/tex]        [∵[tex]e^{lna}=a[/tex]]

Now to get a unit tangent vector , we will divide our vector [tex]r'(ln2)[/tex] by its magnitude. So let's first find the magnitude.

[tex]|r'(ln2)|=\sqrt{(\frac{1}{\sqrt{2} } )^2 +6^2+6^2}[/tex]

             [tex]= \sqrt{\frac{1}{2}+36+36 }[/tex]

             [tex]= \sqrt{\frac{145}{2} }[/tex]

Now we can find the our unit tangents vector.

      [tex]T(ln2)=\frac{r'(ln2)}{|r'(ln2)|}[/tex]

                  [tex]= \frac{<\frac{1}{\sqrt{2}} ,6,6> }{\sqrt{\frac{145}{2}} }[/tex]

                  [tex]= <\frac{\frac{1}{\sqrt{2} } }{\sqrt{\frac{145}{2}} } ,\frac{6}{{\sqrt{\frac{145}{2}} }}, \frac{6}{{\sqrt{\frac{145}{2}} }} >[/tex]

                   [tex]= <\sqrt{145} , \frac{6\sqrt{2} }{\sqrt{145} } , \frac{6\sqrt{2} }{\sqrt{145} } >[/tex]

Hence, [tex]T(ln2)[/tex] [tex]= <\sqrt{145} , \frac{6\sqrt{2} }{\sqrt{145} } , \frac{6\sqrt{2} }{\sqrt{145} } >[/tex]

Answer:

y=-0.215x^2+35

Step by Step:

Let, [tex]h=0[/tex],  [tex]k=35[/tex], [tex]x=8[/tex], [tex]y=21[/tex]

We know that, the general equation of the parabola.

   [tex]y-k = a(x-h)^2[/tex]

[tex]\Rightarrow y=a(x-h)^2+k .........(i)[/tex]

Substitute the  value of [tex]h, k, x, y[/tex] in equation [tex](i)[/tex] and find the value of [tex]a.[/tex]

  [tex]21=a(8-0)^2+35[/tex]

[tex]\Rightarrow 21=a\times 8^2+35[/tex]

[tex]\Rightarrow 21=64a+35[/tex]

[tex]\Rightarrow 64a=21-35[/tex]

[tex]\Rightarrow 64a=-14[/tex]

[tex]\Rightarrow a=\frac{-14}{65}[/tex]

[tex]\Rightarrow a=-0.215[/tex]

Hence, the equation of the parabola is:

[tex]y=-0.215x^2+35[/tex]

Answer:

It is the 3rd graph

Step-by-step explanation:

It is the only one that shows a porpotional relationship.

Answer:

sry mate.....

............

Answer:20 minutes

Step-by-step explanation:

Answer:

yes

Step-by-step explanation:

Answer:

18

Step-by-step explanation:

you have to multiply 2/3 by 27 km

Answer:

y=1/2x-2

Step-by-step explanation:

perpendicular lines have a neg. reciprocal for the slope.

for example:

in this equation y=-2x+1

-2 is the slope and the negative reciprocal would be 1/2

hence, the slop of our new line is 1/2

y=1/2x+b

we can substitute the coordinates given for x and y:

2=1/2(8)+b

2=4+b

-2=b

hence the new equation is y=1/2x-2

Answer:

A

Step-by-step explanation:

the equivalent pair of expression are 2(x+5)and 2x+10

Step-by-step explanation:

Kindly make the question clearer for assistance

Answer:

7

Step-by-step explanation:

(-5,7) lies in the graph!

Answer:

[tex]Scale\ Factor = \frac{1}{2}[/tex]

ABC dilated

Step-by-step explanation:

Given

Triangles ABC and DEF

Required

Determine the scale of dilation

First, we pick a side on ABC

[tex]AB = 6[/tex]

Pick a corresponding side on DEF

[tex]DE = 3[/tex]

The scale factor is then calculated as:

[tex]Scale\ Factor = \frac{DE}{AB}[/tex]

[tex]Scale\ Factor = \frac{1}{2}[/tex]

i.e. ABC was dilated by 1/2

Answer:

40

Step-by-step explanation:

took the test

Answer:

O The range of the function is all real numbers greater

than or equal to 0.

Step-by-step explanation:

The function f(x) = -square root x is shown on the graph.

Which statement is correct?

ТУ

7

6

5

3

The domain of the function is all real numbers less

than or equal to - 1

O The range of the function is all real numbers greater

than or equal to 0.

The range of the function is all real numbers less

than or equal to 0.

The domain of the function is all real numbers less

than or equal to 0.

2

55

14

-

2

-

3

4 5 6 7 X

-2

3

4

-5

Answer:

C:domain: all real numbers

range: all real numbers greater than 1

Step-by-step explanation:

Edge 2021

Answer: The GCF is 2 and the LCF is 1

Step-by-step explanation:

Answer:

1 should be the answer bi

Step-by-step explanation:

uh- this is the correct way to answer the problem....

−4x+12=−6x

Step 1: Add 6x to both sides.

−4x+12+6x=−6x+6x

2x+12=0

Step 2: Subtract 12 from both sides.

2x+12−12=0−12

2x=−12

Step 3: Divide both sides by 2.

[tex]\frac{2x}{2}[/tex] = [tex]\frac{-12}{2}[/tex]

x=−6

Answer:

$72.00

Step-by-step explanation:

Answer:

$72

Step-by-step explanation:

I hope this helps!

Answer:

The surface area of the box in terms of l is [tex]2l^2 +116/l[/tex]

Step-by-step explanation:

The length of the box = [tex]l[/tex]

The height of the box = [tex]h[/tex]

The volume of the box can be obtained by multiplying the surface area of the base by the height of the box.

The surface area of the base of the box is a square, so it will be obtained by multiplying [tex]l \times l = l^2[/tex]

hence volume = [tex]l^2 \times h =29[/tex]

Notice that we are told to give our answer in terms of l, so we will make h the Subject of the formula in the above equation.

[tex]h =29/l^2[/tex]

In the next phase, we are to find the surface area of the box.

The box has a square base, hence it will be made up of

2 squares with 4 rectangles. This is assuming the top is closed.

This means the surface area will be

[tex]2(l^2) +4 (l\times h)[/tex]

recall [tex]h = 29/l^2[/tex]

Hence, surface area =

[tex]2(l^2) +4(l \times 29/l^2)\\2l^2 +116/l[/tex]

The surface area of the box in terms of l is [tex]2l^2 +116/l[/tex]

The surface area of the closed box in terms of l only, which has the square base is,

[tex]2l^2+\dfrac{116}{l}\;\rm ft^2\\[/tex]

Volume of cuboid or box is the amount of quantity, which is obtained by it in the 3 dimensional space.

The volume of cuboid or box can be given as,

[tex]V=l\times b\times h[/tex]

Here, (l) is the length, (b) is the width of the box and (h) is the height of the box.

A closed box has a square base with side length l feet and height h feet.  Therefore, the length and width will be the same.

The volume of the box is 29 cubic feet. Thus,

[tex]29=l\times (l)\times h\\h=\dfrac{29}{l^2}[/tex]

The surface area of the square base box is,

[tex]A=2l^2+4lh[/tex]

Put the value of height,

[tex]A=2l^2+4l\dfrac{29}{l^2}\\A=2l^2+\dfrac{116}{l}\\[/tex]

Hence, the surface area of the closed box in terms of l only, which has the square base is,

[tex]2l^2+\dfrac{116}{l}\;\rm ft^2\\[/tex]

Learn more about the volume of cylinder here;

https://brainly.com/question/12748872

Answer:

It’s 10 inches, 12 inches, 13 inches

Step-by-step explanation:

Answer:

Hello! Just here so the other person can get brainliest. I will do the same for the other questions.

Step-by-step explanation: