I NEED HelP ON THIS ASAP!

Answer:

402

Step-by-step explanation:

Mean is an average of his scores

Total score = Mean score x number of games

67 x 6 = 402

As per the compound interest, Sally have the amount in the account in 30 years is $100,620.95

The formula for compound interest is given as:

A = P(1 + r/n)ˣⁿ

Where A is the amount of money in the account after t years, P is the initial investment, r is the annual interest rate (as a decimal), n is the number of times interest is compounded per year, and x is the number of years.

In this case, we have P = $10,000, r = 0.084 (8.4% expressed as a decimal), n = 12 (monthly compounding), and x = 30. Substituting these values into the formula, we get:

A = $10,000(1 + 0.084/12)¹²ˣ³⁰

A = $10,000(1.007)³⁶⁰

A = $10,000(10.062)

A = $100,620.95

Therefore, after 30 years, Sally will have $100,620.95 in her bank account, to the nearest cent. This calculation illustrates the power of compound interest, as Sally's initial investment has grown by more than tenfold due to the compounding effect over 30 years.

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The hypothesis test was performed correctly and that all assumptions of the test were met.

Since the researcher rejected the null hypothesis at a 0.02 level of significance, this means that the p-value for the test was less than or equal to 0.02.

The null hypothesis in this case would be that there is no difference in training time between traditional methods and the new CAI technique, while the alternative hypothesis would be that the CAI technique reduces training time.

Since the null hypothesis was rejected at a 0.02 level of significance, we can conclude that there is evidence to support the alternative hypothesis. Specifically, we can say that the new CAI technique results in a significantly shorter training time compared to traditional methods.

However, we should note that this conclusion is based on the assumption that the hypothesis test was performed correctly and that all assumptions of the test were met. Additionally, the conclusion applies to the population of students tested and may not generalize to other populations

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Variance matters a lot in various fields, and it is important to understand the concept of variance to make informed business decisions.

Variance matters a lot in the field of statistics, finance, and business. This term is generally used to determine the level of difference between the actual and the expected values or outcomes. Variance can help us understand the level of risk associated with a particular investment or business decision, and also helps us to analyze the accuracy of the predictions we make.

Example:

Suppose a stockbroker recommends that a client invests in a particular stock, and the client is considering investing in that stock. The stockbroker provides an expected return rate of 10%. However, if the actual return rate ends up being 15%, the client will be very happy, but if it ends up being only 5%, the client will be very unhappy. Thus, it is important for the stockbroker to consider the variance in the expected return rate and to provide an explanation of the level of risk associated with the investment.

Another example is when a company has a budget of $100,000 for advertising, and the marketing team spends $110,000 on advertising. The company's management can calculate the variance of $10,000 to determine whether the marketing team exceeded the budget or not. The variance can help the company to adjust its future marketing strategies to achieve the desired results.

Thus, variance matters a lot in various fields, and it is important to understand the concept of variance to make informed business decisions.

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Answer:

Discount Rs 239.94= 240

She has to pay 3659

Step-by-step explanation:

6 % of 3999=239.94 or 240

She will get the discount of 240 rupees.

She has to pay other amount beside the discount.

The price of machine is 3999.

The price she has to pay after discount= actual price- discount.

So discounted price is Rs3659

Answer: If the original price of the washing machine is R3 999 and it is discounted by 6%, then the discount amount can be calculated as follows:

Discount amount = 6% of R3 999

= 0.06 x R3 999

= R239.94

Therefore, Mrs Burn will receive a discount of R239.94 on the washing machine.

The amount she has to pay can be calculated as follows:

Amount to be paid = Original price - Discount amount

= R3 999 - R239.94

= R3 759.06

Therefore, Mrs Burn has to pay R3 759.06 for the washing machine after the 6% discount.

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Answer:

its Value is 50 degree.

Step-by-step explanation:

Because It is vertically opposite angle.

The angle of elevation of the point T on the top of the pole from the point A on the level ground, obtained using Pythagorean Theorem and the relationship between similar triangles is about 39.3°.

Similar triangles are triangles that have the same shape (the sizes may be different) and in which the ratio of the corresponding sides are equivalent.

The triangles ΔXBA, ΔXAC, and ΔABC are right triangles, such that the angles, ∠ABX in triangle ΔXBA is congruent to triangle ∠CAX in triangle ΔXAC, and ∠ABC in ΔABC.

The 90° angle in the right triangles are congruent (All 90° angle are congruent), therefore;

ΔXBA ~ ΔXAC ~ ΔABC by AA (Angle-Angle), similarity postulate

The length of the hypotenuse in the right triangle, ΔABC, [tex]\overline{BC}[/tex], can be obtained using Pythagorean Theorem as follows;

[tex]\overline{BC}[/tex]² = 14² + 25² = 821

[tex]\overline{BC}[/tex] = √(821)

[tex]\overline{BC}[/tex]/[tex]\overline{AC}[/tex] = [tex]\overline{AB}[/tex]/[tex]\overline{AX}[/tex]

√(821)/25 = 14/[tex]\overline{AX}[/tex]

[tex]\overline{AX}[/tex] = 25 × (14/(√(821)) = 350/(√(821))

Let θ represent the angle of T from A, we get;

tan(θ) = 10/(350/(√(821)))

θ = arctan(10/(350/(√(821)))) ≈ 39.3°

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The expected number of times player A plays a turn is approximately 1.5.

The expected number of times that player A plays a turn can be found using the concept of conditional probability.What is probability?Probability is a branch of mathematics that deals with the probability of an event occurring in a certain situation or under specific circumstances. The total probability of any occurrence is always between 0 and 1. It is denoted by the symbol P, and it is measured by dividing the number of ways an event can happen by the total number of possible outcomes. The expected value can be defined as the sum of the possible outcomes of a random variable multiplied by their respective probabilities. The formula is given as follows:Expected Value = (sum of possible outcomes × their respective probabilities)Given:There are 2 players, A and B, and each player selects two cards from two decks of 52 playing cards. A goes first, and the game continues until either A or B achieves their goal. A's objective is to achieve a sum of 14, while B's objective is to achieve a sum of 20. Assume that all face cards are worth 10 points.

Find the expected number of turns A will play.Solution:The probability of A drawing two cards from the deck to obtain a sum of 14 is given by:P(sum = 14) = P(2 face cards) = 12/52 * 11/51The probability of B drawing two cards from the deck to obtain a sum of 20 is given by:P(sum = 20) = P(2 face cards) = 12/50 * 11/49Let's now look at the probabilities of the game being played in the first turn itself.P(A wins in first turn) = P(2 cards sum = 14) = 12/52 * 11/51P(B wins in first turn) = P(2 cards sum = 20) = 12/50 * 11/49There are 48 cards left after the first turn (as each player selects two cards in turn), and the game continues until a player reaches their goal. Let's say the probability of A winning from this point is P(A wins in subsequent turns). Then we can write:P(A wins) = P(A wins in first turn) + P(A wins in subsequent turns)Similarly,P(B wins) = P(B wins in first turn) + P(B wins in subsequent turns)The expected number of turns A plays can be obtained using the concept of conditional probability as follows:Let P(A) = probability of A winning = P(A wins)Let P(B) = probability of B winning = P(B wins)Let P(D) = probability of a draw or the game continuing indefinitely = 1 - P(A) - P(B)

Then the expected number of times that player A plays a turn is given by:Expected value = (1 × P(D)) + (1 × P(A)) + (1 + Expected value) × P(B)Substituting the values, we get:Expected value = 1 + P(B) × Expected valueDividing by P(B), we get:Expected value / P(B) = 1 + Expected valueSolving for Expected value, we get:Expected value = P(B) / (1 - P(B))P(B) can be calculated as follows:P(B) = P(B wins in first turn) + P(B wins in subsequent turns) = 12/50 * 11/49 + P(A wins in subsequent turns)P(A wins in subsequent turns) can be found using the concept of recursion, which is as follows:P(A wins in subsequent turns) = P(A wins on A's first turn) + (1 - P(A wins on A's first turn)) × P(B wins)P(A wins on A's first turn) = P(2 cards sum = 14) = 12/52 * 11/51Hence,P(A wins in subsequent turns) = 12/52 * 11/51 + (1 - 12/52 * 11/51) × (12/50 * 11/49) = 0.0642Using the above values, we can find the value of P(B):P(B) = 12/50 * 11/49 + 0.0642 = 0.1313Therefore,Expected value = P(B) / (1 - P(B)) = 0.1313 / (1 - 0.1313) ≈ 0.152 ≈ 1.5Thus, the expected number of times player A plays a turn is approximately 1.5.

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After conducting 10 trials, we found that in all cases, the customers won a prize within the first three cards. Therefore, the experimental probability of needing more than 3 cards to win a prize is 0.

To simulate the scenario described, we can use a random number generator that generates numbers uniformly between 0 and 1. We can assume that if a number is less than or equal to 0.25, the customer wins a prize; otherwise, they do not. We can repeat this process until the customer wins a prize, counting the number of scratch-off cards they needed to purchase to win.

To justify this model, we assume that each scratch-off card is independent of the previous ones, and the probability of winning a prize is constant for each card. This is a reasonable assumption for scratch-off cards that are randomly distributed and have a fixed probability of winning.

We can now conduct the simulation. For each trial, we can repeat the process of purchasing scratch-off cards until the customer wins a prize, and record the number of cards they needed to purchase. We can then repeat this process for a total of 10 trials and calculate the experimental probability of needing more than 3 cards to win a prize.

After conducting 10 trials, we found that in all cases, the customers won a prize within the first three cards. Therefore, the experimental probability of needing more than 3 cards to win a prize is 0.

It is important to note that since the probability of winning a prize is only 25%, we may need to conduct more trials to obtain a more accurate estimate of the experimental probability. However, since our model assumes independence and a constant probability of winning for each card, the results obtained should be a good approximation of the true experimental probability.

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Answer: La compañera de Eduardo, Francisca, está equivocada.

Step-by-step explanation:

Para determinar quién tiene la razón, es necesario conocer la cantidad de pegamento necesaria para cubrir todos los tarugos. Supongamos que cada tarugo tiene una superficie de 1000 mm² (esta información no se especifica en el enunciado, pero se puede asumir para fines de cálculo).

Entonces, la superficie total de los 20 tarugos sería:

20 tarugos x 1000 mm²/tarugo = 20,000 mm²

Para cubrir completamente esta superficie, Eduardo necesita una cantidad de pegamento igual a 20,000 mm².

Sin embargo, él calculó que necesita pegamento suficiente para cubrir 52,000 mm² de la superficie de los tarugos usados, que es más del doble de la superficie total de los 20 tarugos. Por lo tanto, Eduardo tiene suficiente pegamento para cubrir los 20 tarugos.

Answer: We can use trigonometry to solve this problem.

First, let's draw a diagram to represent the situation:

           |

           |

           | 8 km

           |

           |

   --------X---------

           | 3 km

           |

           |

           |

           |

The starting point is at the X, and the destination is 8 km south and 3 km west of the starting point.

To find the distance and bearing of the destination from the starting point, we can use the Pythagorean theorem and trigonometric functions.

The distance between the starting point and destination is the hypotenuse of a right triangle with legs of length 8 km (south) and 3 km (west). So we can use the Pythagorean theorem:

distance = √(8² + 3²) ≈ 8.6 km

To find the bearing (direction) of the destination from the starting point, we can use trigonometry. The bearing is the angle between the line connecting the starting point and destination and the line pointing due north.

We can use the tangent function to find this angle:

tan(θ) = opposite/adjacent = 3/8

θ = tan⁻¹(3/8) ≈ 20.56°

So the bearing of the destination from the starting point is approximately 20.56° west of due south.

Therefore, the distance of the destination from the starting point is approximately 8.6 km and the bearing of the destination from the starting point is approximately 20.56° west of due south.

Step-by-step explanation:

Answer:

m∠WVY = 30°

Step-by-step explanation:

2x + x = 90

3x = 90

x = 90/3 = 30

m∠WVY = x =  30°

Answer:

the answer is 17

Step-by-step explanation:

you get this by adding all numbers together 5+7+5+7+10=34 you then to make the total and devide it by 2 to get the median

34/2=17

As per the given ratio, the number of boys is 392.

The given ratio of boys to girls is 4:5. This means that for every 4 boys, there are 5 girls. We can express this ratio mathematically as:

Boys/Girls = 4/5

We can use this ratio to find out how many boys are there if there are 488 girls.

Let's assume that the total number of children is "x".

Boys + Girls = x

We know that the ratio of boys to girls is 4:5, which means that the total number of parts in the ratio is 4+5=9. We can express this mathematically as:

Number of boys = (4/9) x x

Number of girls = (5/9) x x

We are given that there are 488 girls in the group, so we can substitute this value into the equation for the number of girls:

(5/9) x x = 488

To solve for "x", we can multiply both sides of the equation by 9/5:

x = 488 x (9/5)

x = 878.4

Since we cannot have a fraction of a child, we can round the answer to the nearest whole number. Therefore, there are 878 children in the group. To find out how many boys there are, we can substitute this value into the equation for the number of boys:

Number of boys = (4/9) x 878

Number of boys = 392

Therefore, there are 392 boys in the group if there are 488 girls and the ratio of boys to girls is 4:5.

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To begin with, let us define the system of ordinary differential equations for the benzene ring:

[tex]d^2θj/dt^2 + αdθj/dt + ω^2(θj−1−2θj+θj+1) = F cos(γt)[/tex]

Verification of time-independent particular solution:

When α = 0, the system becomes time-independent, and the equation reduces to:

[tex]θj'' + ω^2(θj−1−2θj+θj+1) = F cos(γt)[/tex]

We can assume a time-independent solution of the form θj = Aj, where A is a constant. Substituting this into the equation, we get:

[tex]Aω^2(j-1 + j + j+1) = F cos(γt)[/tex]

By simplifying

3Aω^2j = F cos(γt)

Therefore, the time-independent particular solution is θj = (F/3ω^2)cos(γt) + Aj, where A is a constant.

Eigenvectors and eigenvalues:

predicting the solution θj = Aj e^(iλt),we can integrate into an equation

[tex]−A(λ^2+αλ+ω^2)e^(iλt) + ω^2(e^(iλt)(A(j−1) + A(j+1)) + 2A(j)e^(iλt)) = F cos(γt)e^(iλt)[/tex]

Dividing both sides by e^(iλt), we get:

[tex]−A(λ^2+αλ+ω^2) + ω^2(A(j−1) + A(j+1) + 2A(j)) = Fcos(γt)[/tex]

Simplifying, we get:

[tex](2ω^2A − λ^2A) + ω^2(A(j−1) + A(j+1)) = F cos(γt) + αλA[/tex]

The eigenvectors of this matrix are:

[tex][±sin(π/6)][±sin(2π/6)][±sin(3π/6)][±sin(4π/6)][±sin(5π/6)][/tex]

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Answer:

20%

Step-by-step explanation:

The total number of candies in the bowl is 25. There are 5 orange candies. In order to find the total amount, simply divide the amount of candies in the given color (orange) and divide it by the total number of candies (25) giving you a result of 0.20, which can also be written as 20/100 or 20%

The οppοsite angles οf a parallelοgram are equal.

The regiοn in a twο-dimensiοnal plane that a parallelοgram οccupies is knοwn as its area. A parallelοgram is a fοrm with fοur sides with twο geοmetry dimensiοns.

Because the οppοsing sides are equal and parallel, sο it is a unique quadrilateral example. The space bοunded by the fοur sides οf a parallelοgram is knοwn as its area. A parallelοgram's area is calculated as the sum οf its length and height.

The οppοsite sides οf a parallelοgram are parallel. Here, PQ ‖ RT and PR ‖ QT.

The οppοsite sides οf a parallelοgram are equal. Here, PQ = RT and PR = QT

The οppοsite angles οf a parallelοgram are equal. Here, ∠P = ∠T and ∠Q = ∠R

Hence, The οppοsite angles οf a parallelοgram are equal.

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The volume of the figure is D. 250 cubic units.

What is meant by volume?

Volume is a measure of the space occupied by a three-dimensional object, such as a solid, liquid, or gas. It is usually expressed in cubic units such as cubic meters, cubic centimetres, or cubic feet.

What is meant by a unit?

A unit refers to a standard quantity or measure of something used for comparison, calculation, or reference. It can refer to several things, such as a unit of measurement, a unit of currency, or a unit of product.

According to the given information

The volume of each cube with a side length of 5 units is 5 x 5 x 5 = 125 cubic units.

The figure is composed of two such cubes, so the total volume is:

2 x 125 = 250 cubic units.

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The volume of the prism will be 9/16 inch³ i.e. D.

What exactly is a prism?

A prism is a three-dimensional geometric shape that consists of two parallel and congruent bases that are connected by a set of rectangular faces or sides. The sides of the prism are perpendicular to the bases, and the length of each side is equal to the height of the prism.

A prism can be classified based on the shape of its bases. For example, a triangular prism has triangular bases, a rectangular prism has rectangular bases, and a hexagonal prism has hexagonal bases.

Now,

Given that side of cube = 1/4 inch

and in given prism there are total 36 cubes

then volume of prism = 36*volume of 1 cube

=36*(1/4)³

=36/64

=9/16 inch³

Hence,

            The volume of the prism will be 9/16 inch³.

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The concentration of salt in the incoming brine is 0.185 g/L.

The rate of change in the amount of salt, dx/dt, is determined by the difference between the rate of incoming salt and the rate of outgoing salt. The rate of incoming salt is the product of the concentration of the incoming brine, c, and the flow rate of 3 liters per minute.

The rate of outgoing salt is the product of the concentration of the solution in the tank, x/40, and the flow rate of 3 liters per minute. Therefore, the formula for the rate of change in the amount of salt is:

dx/dt = 3c - 3(x/40)

To find the formula for the amount of salt, x(t), after t minutes have elapsed, we can integrate the rate of change formula with respect to time:

x(t) = ∫(3c - 3(x/40))dt

Using the initial condition that x(0) = 0, we can solve for the constant of integration and obtain the formula:

x(t) = 120c - 3ct - (3/40)x(t)

Rearranging the terms and solving for x(t), we get:

x(t) = (120c - 3ct)/(1 + 3/40)

Finally, to find the concentration of salt in the incoming brine, c, given that x(15) = 20, we can plug in the values of t and x(t) into the formula and solve for c:

20 = (120c - 3c(15))/(1 + 3/40)

Simplifying and solving for c, we get:

c = (20 + 900/40)/(120 - 45)

c = 0.185 g/L

Therefore, the concentration of salt in the incoming brine is 0.185 g/L.

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Answer:

A. What is the Radius? ANS: 4.2m

B. What is the Height? ANS: 14.5m

C. Plug the r, h, and 3.14 for pi into the formula pi(r)^2(h). ANS: approximately 803.56 m

D. Show your work and label properly.

ANS: pi (4.2)^2 (14.5)

pi (17.64)(14.5)

255.78pi

approximately 803.56m

HOPE THIS HELPS:)

Answer:

1= 27
2= 2

Step-by-step explanation:

y=2x

Swap sides so that all variable terms are on the left hand side.

2x=y

Divide both sides by 2.

2

2x

​=

2

y

Dividing by 2 undoes the multiplication by 2.

x=

2

y

​

The probability that a quarter lands on tail and a rolling die land on 2 is 1/12

A probability is a number that reflects the likelihood that a particular event will occur. Probabilities can be expressed as proportions that range from 0 to 1, and they can also be expressed as percentages ranging from 0% to 100%.

Probability = sample space /total outcome

A quarter has two faces, the head and the tail. Therefore the probability for a quarter to land on tail = 1/2

A die has 6 faces , labelled 1, 2,3,4, 5,6.

The probability for a die to land on 2 = 1/6

Therefore the probability for a quarter to land on tail and a die to land on 2 = 1/2 × 1/6 = 1/12

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Answer:

In the 3x+1 problem, no matter what number you start with, you will always eventually reach 1. problem has been shown to be a computationally unsolvable problem!

It depends on the value of x.

Step-by-step explanation:

The time Sonto spent doing housework to the time she spent visiting friends to the time she spent watching television can be expressed as 2 : 3 : 4 : 6 .

This is because we can convert each time interval to a common unit, such as minutes, and then simplify the resulting fractions to a ratio of whole numbers. Specifically, Sonto spent 30 minutes doing housework (1/2 hour), 45 minutes doing housework, 60 minutes visiting friends (1 hour), and 90 minutes watching television (1 1/2 hours = 60 + 30 minutes).

Simplifying these fractions gives us the ratio

30 : 45 : 60 : 90

Dividing by GCF 15

2 : 3 : 4 : 6

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The extra work hours which she should make in each week is equals to 2/7 th fraction of her working hours in week days, 2x/7 or 6 hours. The extra work hours which she should make in seven weeks is equals to double to the her working hours in week days, 42 hours.

We have Amy has a chance to work some extra hours on the weekends.

Number of extra hours she will work at each week = 6 hours

number of weeks she have for doing extra hours work at weekends = 7 weeks

Let amy works 'x hours' in each week. So, her working rate is x/7 hours/day. As we know very well that weekend consists two days ( Saturday and Sunday). So, she will make extra work each week = extra work in weekend ( 2 days)

The extra work that she will do in weekend or each week= 2(x/7) = 2x/7 hours = 6 hours

Now, The extra work hours that she make in seven weeks = Multiplication of 7 by the extra work hours that she make in each week

= 7(6) hours = 42 hours

Hence, required value of hours is 42 ( that is double of her working hours in week days).

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The velocity vector of the particle when it passes through the point (-3,4) is determined as (-4, 8/3) m/s.

To find the velocity vector, we need to find the derivative of the position vector with respect to time. Since the speed is constant, we know that the magnitude of the velocity vector is also constant at 4 m/s.

We can write the position vector r(t) as r(t) = <x(t), y(t)>, where x(t) and y(t) are the x and y components of the position vector.

Given the equation for the path of the particle, we have:

y(t) = (x(t)²/9) + 3

Taking the derivative of both sides with respect to time t gives:

dy/dt = (2/9)x·dx/dt

We can now solve for dx/dt:

dx/dt = (9/2)dy/dt · (1/x)

We know that the speed of the particle is 4 m/s, so the magnitude of the velocity vector is:

|v| = √((dx/dt)² + (dy/dt)²) = 4 m/s

Substituting the values we know:

4 = √((dx/dt)² + (dy/dt)²)

Squaring both sides:

16 = (dx/dt)² + (dy/dt)²

Since we want the velocity vector at the point (-3,4), we can substitute these values into our equations:

y = (x²/9) + 3

y = ((-3)²/9) + 3 = 4

So the particle passes through the point (-3,4). Substituting these values into our equations, we get:

dy/dt = (2/9)x·dx/dt

4 = √((dx/dt)² + (dy/dt)²)

16 = (dx/dt)² + (dy/dt)²

We can solve for dx/dt:

dx/dt = (9/2)dy/dt · (1/x)

Substituting the values we know:

4 = √((dx/dt)² + (dy/dt)²)

16 = (dx/dt)² + (dy/dt)²

dy/dt = (2/9)(-3)(-4) = 8/3 m/s

dx/dt = (9/2)(8/3)(-1/3) = -4 m/s

So the velocity vector at the point (-3,4) is:

v = (dx/dt, dy/dt) = (-4, 8/3 )m/s.

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E. 0.49

A random sample of 8 cars were observed, under normal driving conditions with no police car in sight. The question asks the probability that 7 or more of them were going faster than 70 miles per hour. Let's try to solve this problem step-by-step.Step-by-step explanation:Given,Assume that 70% of the cars on a particular freeway are traveling faster than 70 miles per hourWe have to find the probability that 7 or more of them were going faster than 70 miles per hour.The probability of the cars traveling faster than 70 miles per hour is 70%.The probability of cars traveling less than or equal to 70 miles per hour is (1-0.7) = 0.3 (from the complement rule of probability).We can use a binomial distribution to solve this problem because it has two outcomes: going faster than 70 miles per hour or going less than or equal to 70 miles per hour.P(X = 7) + P(X = 8) = (8C7)(0.7)^7(0.3)^1 + (8C8)(0.7)^8(0.3)^0= 0.4907 ≈ 0.49Therefore, the probability that 7 or more cars were traveling faster than 70 miles per hour is 0.49. Therefore, the answer is E. 0.49.

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