Hydrogen and iodine gas combine to form hydrogen iodide gas.

H2 (g) + I2 (g) ⇌ 2 HI (g)

At a certain temperature, the equilibrium concentration of hydrogen and iodine gas are 0.291 M and 0.172 M, respectively. At this temperature, the equilibrium constant, Kc, is 30.6. What is the concentration of hydrogen iodide gas under these conditions?

The vapor pressure of mercury at 25°C is 1.85 torr. To convert the vapor pressure of mercury from mmHg to atm, we can use the conversion factor 1 atm = 760 mmHg:

A liquid's molecules enter the gaseous phase when heated because they have enough kinetic energy to overcome the forces holding them in the liquid. By doing this, they produce a population of molecules in the vapour phase above the liquid, which leads to the creation of a pressure—the liquid's vapour pressure.

1.85  mmHg x (1 atm / 760 mmHg) = 0.00243 atm (rounded to 3 significant digits)

Therefore, the vapor pressure of mercury at 25°C is 0.00243 atm.

To convert the vapor pressure of mercury from mmHg to torr, we can simply use the definition that 1 torr = 1 mmHg:

1.85 mmHg = 1.85 torr (rounded to 3 significant digits)

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We have 0.34 L of the remedy. A type of concentration known as % mass/volume shows how much solute is present in 100 mL of solution.

Volume is the amount of space a thing occupies, whereas mass is the amount of stuff it contains. Example: Basketball and bowling balls have roughly the same volume, but the bowling ball has a lot more mass. Make sure you understand the distinction between mass and weight before utilising measurement words.

In this instance, there are 100 mL of solution and 25 g of CuSO4.

We can use the rule of three to determine the solution:

100 mL of solution holds 25 g of solute.

Our 85 g may fit in (85.100) /25, or 340 mL.

Volume is converted from mL to L.

1L / 1000mL = 0.34 L 340ml

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The percent by mass of Xe in sample A is calculated as 77.6%.

To calculate the mass percent of an element in compound, we divide the mass of element in 1 mole of compound by the molar mass of compound and multiply the result by 100.

The percent by mass of Xe in sample A can be calculated using the following formula:

percent by mass of Xe = (mass of Xe / total mass of sample) x 100%

Given mass of Xe is 77.6 g and total mass of sample is 100.0 g.

Putting these values into the formula, we get:

percent by mass of Xe = (77.6 g / 100.0 g) x 100% = 77.6%

Hence, the percent by mass of Xe in sample A is 77.6%.

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Answer:

(0.22 L) × (1 mL/10^-3 L) × (1.57 g/mL) / (61.04 g/mol) = ?

First, let's simplify the units:

(0.22 L) × (1000 mL/1 L) × (1.57 g/mL) / (61.04 g/mol) = ?

(0.22 L) × (1570 g/mol) / (61.04 g/mol) = ?

Now we can cancel out the units of g/mol:

(0.22 L) × (1570/61.04) = ?

(0.22 L) × 25.73 = ?

5.66 L·g

Therefore, the units of the student's answer are L·g.

The mass of the unknown element cobalt is obtained as 40 g. This can be seen from the calculation that we have in the solution.

If you have a compound that contains an unknown element, you can use the molar mass of the compound to find the relative atomic mass of the unknown element

We can see that the question has already given us the mass of the sample as we have and the percentage of the cobalt that we have in the sample.

50 = x/80 × 100

x = 50/100 × 80

= 40 g

Thus we would have a total of about 40 g of cobalt in the sample.

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Missing parts;

A sample of the compound weighs 80 grams.  If the mass percent of cobalt is 50%, How many grams of cobalt are in the sample?

The pressure exerted by the nitrogen gas in the container of volume 10.0L  at a temperature of 298K is 12.14 atm.

Pressure in chemistry is defined as the force per unit area exerted by a gas on the walls of its container. It is the result of the constant, random motion of gas molecules colliding with the walls of the container.

To find the pressure exerted by the N₂ gas, we can use the ideal gas law:

PV = n*R*T

R is the universal gas constant, whose value is constant and is given by 0.0821 L·atm/mol·K

To solve for P:

P = n*R*T/V

Substituting the given values, we get:

P = (0.50 mol) *  (298 K) / (10.0 L)* (0.0821 L·atm/mol·K)

P = 12.14 atm

Therefore, the pressure exerted by the N₂ gas in the 10.0L container at 298K is 12.14 atm.

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Answer:

1 mole of Cl2 reacts with 2 moles of NaBr to produce 1 mole of Br2.

So, to calculate the number of moles of Br2 produced, we first need to find the number of moles of Cl2 required to react with 5.2 moles of NaBr. Since the stoichiometric ratio of Cl2 to NaBr is 1:2, we need half as many moles of Cl2 as moles of NaBr:

Number of moles of Cl2 = 5.2 moles NaBr / 2 = 2.6 moles Cl2

Now we can use the stoichiometric ratio between Cl2 and Br2 to calculate the number of moles of Br2 produced:

1 mole Cl2 produces 1 mole Br2

Therefore, 2.6 moles Cl2 will produce 2.6 moles Br2.

Explanation:

One should consider factors such as the process constraints, the process dynamics, and process output requirements.

What are process constraints?

Process constraints are limitations on the process variables due to physical, chemical, or economic factors. A constraint is a limitation or bias on the variability or possibilities of change in the sort of such elements. A constraint is an effort by a group of elements to reduce the degrees of freedom of the elements of a system.

The selection of variables to measure for the control of a chemical process can be quantified using a process flow diagram and a process control hierarchy. The process flow diagram shows the process variables and their relationships, while the process control hierarchy shows the control loops and the measurement and control variables for each loop. The number and type of variables to measure depend on the complexity of the process, the desired control objectives, and the available instrumentation and control technologies.

Therefore, process constraints, the process dynamics, and process output requirements are the factors.

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The thyroid gland produces and secretes two hormones, thyroxine (T4) and triiodothyronine (T3), which are involved in regulating the body's metabolism.

The thyroid gland is regulated by the pituitary gland, which secretes thyroid-stimulating hormone (TSH). When TSH binds to receptors on the thyroid gland, it stimulates the production and secretion of T4 and T3. These hormones play an important role in the growth and development of the body's tissues and organs, including the brain, heart, and muscles.

If there is an overproduction of thyroid hormones, it can lead to hyperthyroidism, which can cause symptoms such as weight loss, nervousness, and rapid heartbeat. On the other hand, an underproduction of thyroid hormones can lead to hypothyroidism, which can cause symptoms such as fatigue, weight gain, and cold intolerance.

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Most frequently, a salicylates component is used to: Aid in the diagnosis of sudden or progressive aspirin toxicity. When you take a lot of aspirin at once, you might get acutely poisoned.

Blood test results are frequently impacted by prescription medicines, non-prescription pharmaceuticals (such as aspirin, cold medicine, and vitamins), and alcohol consumption. In order to properly interpret the findings of your blood tests, your doctor needs a thorough and candid picture of your medication use.

Aspirin Reaction Units are used to report test findings (ARU). 350-549 ARU is the therapeutic range for people on an antiplatelet regimen to effectively suppress platelets. Those who are not taking aspirin or whose treatment is ineffectively suppressing platelet function have values of 550–700 ARU.

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If you start with 4.55 x 10²⁵ molecules of C₅H₁₂, you would produce 1.82 x 10²⁶ g of H₂.

The balanced equation shows that for every one molecule of C₅H₁₂ that reacts, 2 molecules of H₂ are produced.

C₅H₁₂ --> C₅H₈ + 2H₂

To determine the mass of H₂ produced, we need to convert the number of molecules of C₅H₁₂ to molecules of H₂ using the stoichiometry of the balanced equation:

1 molecule of C₅H₁₂ produces 2 molecules of H₂

4.55 x 10²⁵ molecules of C₅H₁₂ x (2 molecules of H₂ / 1 molecule of C₅H₁₂) = 9.10 x 10²⁵ molecules of H₂

Now, to find the mass of H₂ produced, we need to use the molar mass of H₂, which is approximately 2 g/mol:

9.10 x 10²⁵ molecules of H₂ x (2 g/mol) = 1.82 x 10²⁶ g of H₂

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Answer:

9.10 x 10²⁵ molecules of H₂ x (2 g/mol) = 1.82 x 10²⁶ g of H₂

Explanation:

350 mg of sodium would be ingested if you consumed 85 g of the food. This is less than the 2,300 mg (or one teaspoon of table salt) daily limit that is advised.

The body needs sodium, a mineral, to maintain the proper balance of body fluids. It is an explosively reactive alkali group metallic element that is soft, light, and silvery-white. It reacts with water. Table salt and a number of processed foods both contain sodium. Table salt is created when sodium and chlorine are combined. Nonetheless, the body can get harmed by excess sodium.

The amount of sodium in various foods, and even within the same food category, varies greatly.

But, you can ascertain the salt content per serving, which is often represented in milligrams, by looking at the nutrition facts label or ingredient list of the meal (mg). So, using a proportion, you can determine how much salt is in 85 g of the food:

(x mg sodium) / (serving size in g) = (sodium per serving in mg) / (85 g)

The amount of sodium in 85 g of the food, expressed in milligrams, can be found by solving for x. You may divide this by 1000 to get grams.

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Answer:

The density equation is given by:

p = 70.5 * exp(82700000 * p)

where p is the pressure in pounds per square inch (lbf/in²) and ρ is the density in pounds per cubic foot (lbm/ft³).

To determine the units of the constants 70.5 and 82700000 in short, we can use dimensional analysis.

The unit of the exponential term is dimensionless, so we only need to consider the units of the constant term.

The unit of the density (ρ) is lbm/ft³, and the unit of the pressure (p) is lbf/in².

So, we can write the equation as:

ρ = (70.5 lbm/ft³) * exp(82700000 * p)

To get the units of the constant 70.5, we can divide both sides by the exponential term and simplify:

ρ / exp(82700000 * p) = 70.5 lbm/ft³

Therefore, the units of 70.5 are lbm/ft³.

To get the units of the constant 82700000, we can rearrange the equation and take the natural logarithm of both sides:

ln(ρ/70.5 lbm/ft³) = 82700000 * p

The units of the left-hand side are dimensionless, and the units of the right-hand side are 1/in². So, the units of the constant 82700000 are 1/in².

Answer:

It's (d) 4.65 ≃ 4.7

Explanation:

By understanding that a mole  is the unit of amount of substance that equals Avogadro's number ([tex]N_a[/tex] = 6.022*10^23)

we make a ratio of moles as below:

2KClO3 --> 2KCl + 3O2
2        :        2     :    3
3.1      :        ?      :    ?

part value = 3.1 / 2 = 1.55

number of moles of O2 yielded from this reaction = 1.55 * 3 = 4.65 moles

A complex molecule known as an organic is composed primarily of carbon atoms joined to other elements and/or other carbon atoms.

Although the distinction between "organic" and "inorganic" is disputed, many authors in the field of chemistry believe that any chemical compound that contains carbon-hydrogen or carbon-carbon bonds is considered to be an organic compound. Methane is an example of an organic compound, but opinions on whether carbon halides without hydrogen (such as carbon tetrachloride,  are organic or inorganic vary from author to author.

Millions of organic substances have been identified as a result of carbon's capacity to catenate (form strands with other carbon atoms).

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The formula for iron(II) bromide is FeBr2, while the formula for barium chloride is BaCl2. The products of the reaction are barium bromide (BaBr2) and iron(II) chloride (FeCl2).

What is Balanced Equation ?

A balanced chemical equation is a symbolic representation of a chemical reaction that shows the relative numbers of reactant and product molecules or ions involved. In a balanced equation, the number of atoms of each element must be the same on both the reactant and product sides, in order to obey the law of conservation of mass.

The balanced chemical equation for the reaction between iron(II) bromide and barium chloride is:

FeBr2 + BaCl2 → BaBr2 + FeCl2

In this reaction, the iron(II) ion (Fe2+) in iron(II) bromide (FeBr2) is replaced by the barium ion (Ba2+) from barium chloride (BaCl2), forming barium bromide (BaBr2) and iron(II) chloride (FeCl2). The balanced equation shows that two bromide ions (Br-) and two chloride ions (Cl-) are involved in the reaction, which ensures that the equation is balanced in terms of both mass and charge.

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Volume is the measure of the space a substance takes up, hence the correct option is A.

Nominal, ordinal, interval, and ratio measurements are the four main types of measurement.

An object or event's attributes are quantified through measurement so that they can be compared to those of other things or events. In other words, measurement is the process of comparing a physical quantity to a fundamental reference quantity of the same kind to determine how big or small it is.

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The limiting reactant would be  H₂O.

The mass of the excess reactant would be 13.05 grams

Number of moles of P₂O5 = mass / molar mass

Number of moles of P₂O5 = 55 g / 141.88 g/mol

Number of moles of P₂O5 = 0.388 moles

Number of moles of H₂O = mass / molar mass

Number of moles of H₂O = 16 g / 18.02 g/mol

Number of moles of H₂O = 0.888 moles

Using the balanced chemical equation, we see that 1 mole of P₂O5 reacts with 3 moles of H₂O to produce 2 moles of H3PO4. Therefore, to react with all the P₂O5, we would need:

0.388 moles of P₂O5 × (3 moles of H₂O / 1 mole of P₂O5) = 1.164 moles of H₂O

Since we only have 0.888 moles of H₂O, it is the limiting reactant.

To determine the amount of excess P₂O5, we need to find how many moles of H₂O would be needed to react with all the P₂O5:

0.888 moles of H₂O × (1 mole of P₂O5 / 3 moles of H₂O) = 0.296 moles of P₂O5

The amount of excess P₂O5 is the initial moles of P₂O5 minus the moles of P₂O5 required to react with all the H₂O:

0.388 moles of P₂O5 - 0.296 moles of P₂O5 = 0.092 moles of excess P₂O5

Mass = 0.092 x 141.88 = 13.05 grams

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Lipids dissolve in alcohol, a solvent. It removes the skin's lipids, particularly from the stratum corneum.

Because the lipids that normally prevent water loss are removed during alcohol soaking, the rate of water loss increases.

Therefore, water may evaporate more slowly than other liquids despite having a lower molecular weight. The molecules of ethyl (rubbing) alcohol, which are more loosely bound than those of water, evaporate almost five times faster than water. Lower-energy, lower-temperature molecules are left behind when energetic molecules leave a liquid.

The rate of water loss from the skin of a hand was measured. Following the measurement, the hand was soaked in alcohol for 15 minutes. After all the alcohol had been removed from the hand, the rate of water loss was again measured. Compared with the rate of water loss before soaking, what difference, if any, would you expect in the rate of water loss after soaking the hand in alcohol?

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The reaction of 2,2-dichloro-3-methylbutane with water results in the formation of 3-methyl-2-butanol, which can react with OH- in a nucleophilic substitution reaction to form 3-methyl-2-butyl alcohol and water.

The reaction can be represented by the following equation:

2,2-dichloro-3-methylbutane + H2O → 3-methyl-2-butanol + H+ + Cl-

The reaction of 2,2-dichloro-3-methylbutane with water can result in the formation of an alcohol and a hydrogen ion. The product of this reaction is 3-methyl-2-butanol.

The reaction can be represented by the following equation:

2,2-dichloro-3-methylbutane + H2O → 3-methyl-2-butanol + H+ + Cl-

In this reaction, one of the chlorine atoms from 2,2-dichloro-3-methylbutane is replaced by a hydroxyl group (-OH) from water, resulting in the formation of an alcohol group (-OH) in the product, 3-methyl-2-butanol. The other chlorine atom remains as an ion, Cl-.

The product, 3-methyl-2-butanol, can react with OH- in a nucleophilic substitution reaction. In this reaction, the hydroxide ion (OH-) acts as a nucleophile and attacks the carbon atom that is attached to the leaving group (the -OH group) in the 3-methyl-2-butanol molecule. The leaving group then departs with its pair of electrons, forming a new bond with the nucleophile (OH-). The result is the formation of a new alcohol molecule.

The reaction can be represented by the following equation:

3-methyl-2-butanol + OH- → 3-methyl-2-butyl alcohol + H2O

In this reaction, the -OH group of 3-methyl-2-butanol is replaced by the hydroxide ion (OH-) to form 3-methyl-2-butyl alcohol, and a water molecule is formed as a byproduct.

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Answer:

Explanation:Before dividing the initial solution:

Initial volume = 1.0 L

Initial concentration = 0.40 M

After dividing into two equal parts:

Each part has a volume of 0.5 L

The first part has a concentration of 0.40 M

The second part has a concentration of 0.20 M (diluted by 50% with 1.5 L of water)

When the two parts are mixed:

Total volume = 1.0 L + 0.5 L + 0.5 L + 1.5 L = 3.5 L

Total moles of sulfuric acid = (1.0 L x 0.40 M / 1000) + (0.5 L x 0.40 M / 1000) + (0.5 L x 0.20 M / 1000) + (1.5 L x 0 / 1000) = 0.5 mol

Final concentration before adding more sulfuric acid = 0.5 mol / 3.5 L = 0.14 M

When 2.0 L of 0.1 M sulfuric acid are added:

Total volume = 3.5 L + 2.0 L = 5.5 L

Total moles of sulfuric acid = 0.5 mol + (2.0 L x 0.1 M / 1000) = 0.7 mol

Final concentration = 0.7 mol / 5.5 L = 0.13 M

Therefore, the final molar concentration of the solution is 0.13 M.

Answer:

To show that the data are in accord with the law of multiple proportions, we need to determine the ratios of the masses of to in each compound and see if they are in small whole number ratios.

For the first compound:

Mass of : 23.3 g

Mass of : 3.00 g

Ratio of masses: 23.3 g / 3.00 g = 7.77

For the second compound:

Mass of : 7.00 g

Mass of : 4.50 g

Ratio of masses: 7.00 g / 4.50 g = 1.56

These ratios are not in small whole number ratios, which indicates that the formula for the first compound cannot be determined by simple inspection. However, the fact that the ratios are different is in accord with the law of multiple proportions, which states that when two elements form more than one compound, the masses of one element that combine with a fixed mass of the other element are in small whole number ratios.

Let's assume that the formula for the second compound is . This means that the ratio of to in the compound is 2:1. From the data provided, we know that there are 4.50 g of in the compound, which means there must be twice as much in the compound. Therefore, there are 9.00 g of in the compound.

To determine the formula of the first compound, we can subtract the mass of from the total mass of the compound:

Mass of : 23.3 g

Mass of : 3.00 g

Total mass: 26.3 g

Mass of : 26.3 g - 3.00 g = 23.3 g

So the ratio of to in the first compound is:

Mass of : 23.3 g

Mass of : 3.00 g

Ratio of masses: 23.3 g / 3.00 g = 7.77

We can divide this ratio by the ratio of to in the second compound to get the ratio of the two compounds:

Ratio of first compound: 7.77

Ratio of second compound: 2.00

The ratio of the two compounds is not a small whole number ratio, which suggests that the formula for the first compound is more complex than a simple binary compound. Therefore, we cannot determine the formula of the first compound from the data provided.

Answer:

the formula of the first compound is A2.08B0.78, which we can simplify to A2B.

Explanation:

To determine if these data are in accord with the law of multiple proportions, we need to compare the ratios of the masses of one element to the fixed mass of the other element in each compound:

For the first compound:

mass ratio of A:B = 23.3 g / 3.00 g = 7.77

For the second compound:

mass ratio of A:B = 7.00 g / 4.50 g = 1.56

If the ratios of the masses of one element to the fixed mass of the other element are simple whole number ratios, then the data are in accordance with the law of multiple proportions. We can see that the ratios calculated above are not simple whole numbers, so the law of multiple proportions does not appear to be satisfied.

To determine the formula of the first compound, we can assume that the formula is AxBy, where x and y are the subscripts that we need to determine. We can set up a system of equations based on the mass ratios:

23.3 g of A combines with 3.00 g of B:

(23.3 g A) / (x mol A) = (3.00 g B) / (y mol B)

7.77 mol A / mol B = (23.3 g A) / (3.00 g B)

7.77 (y/x) = 23.3 / 3.00

y/x = 3/7.77

7.77 g of A combines with 1.00 g of B:

(7.77 g A) / (x mol A) = (1.00 g B) / (y mol B)

1.56 mol A / mol B = (7.77 g A) / (1.00 g B)

1.56 (y/x) = 7.77 / 1.00

y/x = 5/2

Now we have two equations for y/x that we can solve simultaneously:

y/x = 3/7.77

y/x = 5/2

Setting these two expressions equal to each other, we get:

3/7.77 = 5/2x

x = 2.08

Now that we know x, we can use one of the equations for y/x to solve for y:

y/x = 3/7.77

y/2.08 = 3/7.77

y = 0.78

Therefore, the formula of the first compound is A2.08B0.78, which we can simplify to A2B.

A contraption that swiftly prepares food is run by infrared rays. Microwaves employ infrared rays to heat meals by warming any water that may be present.

Numerous food production processes, including drying, boiling, heating, peeling, polyphenol recovery, freeze-drying, antioxidant recovery, microbiological inhibition, sterilizing grains, baking bread, roasting food, making juices, and cooking food, all use infrared technology.

Infrared radiation has the ability to ease or release muscle tension and encourage local blood circulation in the body. Infrared radiation has been used in conventional and modern medicine to treat conditions including autoimmune diseases and issues with wound healing in addition to relieving muscle pain and tension.

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In chemical, deposition is the process of building an object by putting fresh layers on top of one another.

Deposition includes the direct transformation of a vapor into a solid without first going through the liquid phase. A layer of substance is added to the surface of a substrate during deposition; the substrate might be solid or liquid.

This method is employed in many different contexts, including the creation of protective coatings, optical coatings, and thin films for electrical devices. A number of methods, such as atomic layer deposition, physical vapor deposition, and chemical vapor deposition (CVD), can be used to deposit material (ALD).

A phase change from the liquid phase to the vapor phase is called vaporization (or vaporization) of an element or molecule. Both evaporation and boiling result in sublimation. Boiling is a bulk phenomenon, whereas evaporation is a surface phenomenon.

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Answer:

The balanced equation for the reaction between sodium hydroxide and sulfuric acid is:

H2SO4 + 2NaOH → Na2SO4 + 2H2O

From this equation, we can see that one mole of sulfuric acid reacts with two moles of sodium hydroxide.

The amount of sodium hydroxide used in the titration is:

n(NaOH) = C(NaOH) x V(NaOH) = 0.246 M x 29.61 mL = 0.007298 moles of NaOH

Since two moles of NaOH react with one mole of H2SO4, the amount of H2SO4 present in the sample is:

n(H2SO4) = 0.007298 moles of NaOH / 2 = 0.003649 moles of H2SO4

The volume of the sulfuric acid solution used in the titration is 10.00 mL. Therefore, the molarity of the sulfuric acid solution is:

M(H2SO4) = n(H2SO4) / V(H2SO4) = 0.003649 moles / 10.00 mL = 0.3649 M

So, the molarity of sulfuric acid is 0.3649 M.

a. The maximum and minimum temperature of a thermocouple is   [tex]-200^{o} C to 350^{o} C[/tex].

Therefore the difference between the actual and indicated temperature is indicated as [tex](125*5 = 625^{o} C/s)[/tex]

c.The time lag between the actual temperature and the indicate temperature is equal to the time constant of the thermocouple.

A sensor that detects temperature is a thermocouple. It is made up of two distinct metals that are attached at one end. A voltage is produced that is linked to temperature when the junction of the two metals is heated or cooled.

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Answer: 2.025

Explanation: Set up the ratio 100ml/78.5g = xml/1.59kg

Once you have your units in order, solve for x and then convert to liters and there you have your answer!

Answer:

To calculate the molar mass of the gas, we can use the ideal gas law, which relates the pressure, volume, temperature, and number of moles of a gas:

PV = nRT

where P is the pressure in atmospheres, V is the volume in liters, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/mol·K), and T is the temperature in kelvin.

First, we need to convert the temperature to kelvin:

T = 99.0 °C + 273.15 = 372.15 K

Next, we can calculate the number of moles of gas using the ideal gas law:

n = PV/RT

where P is the pressure in atmospheres (we convert 748 torr to atmospheres by dividing by 760 torr/atm), V is the volume in liters (we convert 250 mL to 0.25 L), R is the ideal gas constant, and T is the temperature in kelvin:

n = (748/760) × 0.25 L / (0.0821 L·atm/mol·K × 372.15 K) = 0.0105 mol

Finally, we can calculate the molar mass of the gas by dividing the mass of the condensed vapor (1.097 g) by the number of moles:

molar mass = mass/number of moles = 1.097 g / 0.0105 mol = 104.38 g/mol

Therefore, the molar mass of the gas is approximately 104.38 g/mol.

Explanation:

Answer:

the new concentration of the sodium chloride solution after 300 mL of solvent evaporates is 1.12 M.

Explanation:

To calculate the new concentration of the sodium chloride solution after 300 mL of solvent evaporates, we need to first determine how many moles of solute are present in the original solution:

moles of solute = concentration x volume

moles of solute = 0.70 M x 0.800 L

moles of solute = 0.56 moles

Next, we can calculate the new volume of the solution after 300 mL evaporates:

new volume = original volume - amount evaporated

new volume = 0.800 L - 0.300 L

new volume = 0.500 L

Finally, we can calculate the new concentration of the solution using the moles of solute and the new volume:

new concentration = moles of solute / new volume

new concentration = 0.56 moles / 0.500 L

new concentration = 1.12 M

Therefore, the new concentration of the sodium chloride solution after 300 mL of solvent evaporates is 1.12 M.