How would a harsh winter most likely affect the rabbit population size?

Answer:

D.

Explanation:

The smaller flashlight has less inertia than the larger flashlight, so it takes

less force to change the motion of the smaller flashlight.

Inertia is defined as the property of an object to resist changes in its velocity

when in motion. A larger or bigger body has more mass and inertia as it

requires more force to change the direction of the object.

The smaller flashlight has less inertia than the larger flashlight and hence

requires less force to change its motion due to its smaller size.

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Answer:

1. Falso

2. Falso

3. Verdadero

4. Falso

5. verdadero

Explanation:

1. Las células de los animales, las plantas y los hongos son eucariotas

2. Los hongos se reproducen sobre todo por medio de esporas

3. cerevisiae se reproduce tanto asexual y sexualmente levaduras se reproducen asexualmente mediante un proceso conocido como gemación.

4. La tinción de Azul de lactofenol se emplea para observar hongos.

5. Los hongos pueden ser unicelulares o pluricelulares. Las levaduras son hongos unicelulares

Answer:

habitat

Explanation:

The ecological levels do not describe interacting biotic and abiotic factors in an area's habitat. The correct option is D.

A habitat is a place where physical or biotic factors are presented. This is a place where all the factors are present to live a species with all suitable conditions.

Habitat of different species is different. They live in their suitable habitat to grow and reproduce accordingly. If a species is moved from its habitat, then it may have difficulties in surviving.

So habitat is not a place where all biotic and species abiotic factors are present, it is a place where all living factors are present that are necessary for the living of a person. So, it is not the ecological level of  interacting biotic and abiotic factors in an area

Thus, the correct option is D. Habitat.

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#SPJ2

Abraham believed that God could raise Isaac from the dead or more specifically that he could raise the Dead

Yes The two peptides will separate from each other in an electric field when the pH is 7.0

The two peptides wil drift/separate from each other when the pH is 7.0 because of the reaction of trypsin enzyme and also the difference in charge between HbA and Hbs

Considering charge of each peptide

Since The isoelectric point of normal Hba is 6.9 and Hbs possess two fewer negative charges per hemoglobin molecules

The Hbs is more hydrophobicity than HbA due to the substitution of glutamic acids of HbS by valine residue.

Considering Electrophoresis

At a lower pH level Hbs shows a slower moving band than Hba

while a higher pH level the HbS peptide is less negatively charged while the carboxyl group of HbA is more negatively charged and Hba moves faster as well as an acidic pH.

Hence we can conclude that the two peptides will separate from each other in an electric field when the pH is 7.0

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Answer:

Woolley dubbed the statues “Rams Caught in a Thicket” as an allusion to the biblical story of Abraham. They more likely represent goats, which could often be seen standing on their hind legs, to reach leaves in the trees, as seen here.

An evidence that shows that evolution does not exist is: Weak genetic similarities in closely related organisms and strong genetic similarities in distantly related.

Therefore, an evidence that shows that evolution does not exist is: Weak genetic similarities in closely related organisms and strong genetic similarities in distantly related.

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Answer:Its B

Explanation:

Answer:

Arctic, Antarctic, and Alpine

Arctic, Antarctic, and alpine

Answer:

pH is a measure of the concentration of H3O+ ions in a solution. Adding an acid increases the concentration of H3O+ ions in the solution. ... If an acid is added to a basic solution, the solution becomes less basic and moves toward the middle of the pH scale. This is called neutralizing the base.

Answer:

Explanation:

Maybe next time^^

___________

Answer:

A

Explanation:

not 100% sure but it seems to be the only sensible answer

Ansew heheheheheheh

Explanation:

If mitosis DID NOT happen... the organism would stay as a single cell. The life we know it now... wouldn't exist as we have multi-cellular stuff.

Answer:

Make food for the cell

Explanation:

Since the purpose of the chloroplast is to create energy for the cell, should it be damaged it would lose its ability to do so.

Hopefully this is a better answer

Answer:

I believe it is b

Explanation:

Chloroplast help to produce food and uses the suns sun rays or energy given off of it to produce one it’s green color and it well the food

Answer:

Mainly because if a disorder is dominant, then it will be manifested by all who have the gene. If the disorder is severe, then it will reduce the chances of the individual surviving to grow up and reproduce (unless the disorder only manifests symptoms in later life). If they do reproduce, then 50% of their offspring will inherit the gene, and be at a similar disadvantage in reproduction. Thus, there is likely to be selection against the gene. By contrast, a recessive disorder is only manifested if both parents pass on the abnormal gene, and an individual with one gene for the disorder is usually at no disadvantage. Thus, there is much less selection against abnormal recessive disorders.

Answer:

Yes

Explanation:

it is depend on the fruit of apple

Answer:  It's starts burning body fat.

Explanation:

Answer:

Lightning is not considered a form of precipitation but rather a discharge of electricity.

thats nice :)

also hi hru

Although I cannot see the model for Simone's experiment, I can offer the insight that the most likely role of plants in the model is that they consume the carbon atoms and produce oxygen.

Therefore, we can confirm that the most likely role of plants in the model created by Simone, is that they will consume carbon atoms in the form of carbon dioxide in order to sustain photosynthesis, which releases oxygen.

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Answer:

Sorry about that

Explanation:

Answer:

5730 years

Explanation:

In a chemical reaction, including radioactive decay, the half-life of a species is the time taken for the substance to decrease to exactly one-half its initial value.

For a first-order reaction, the half-life of the reactant is

                                                  [tex]t_{\frac{1}{2}} \ = \ \displaystyle\frac{\ln 2}{\lambda} \ \ \ \ \ \ (1)[/tex],

where λ is the reaction's rate constant modeled by the differential equation describing the kinetics of a first-order reaction

                                               [tex]N \ = \ N_{0}e^{-\lambda t} \ \ \ \ \ (2)[/tex],

where N is the remaining amount of substance after time t and [tex]N_{0}[/tex] is the initial amount of substance before the chemical reaction proceeds.

Since the value of λ is constant, rearrange equation (1) with λ as the subject,

                                                       [tex]\lambda \ = \ \displaystyle\frac{\ln 2}{t_{\frac{1}{2}}}[/tex].

Given that only 12.5% of carbon-14 remained after 17190 years assuming that initially there was 100% of carbon -14, substitute in the values into equation (2) and solve for λ (make λ the subject of the equation),

                               [tex]\-\hspace{0.56cm}12.5 \ = \ 100e^{-\lambda \times 17190} \\ \\ \-\hspace{0.5cm} \displaystyle\frac{12.5}{100} \ = \ e^{-17190\lambda} \\ \\ \displaystyle\frac{\ln\displaystyle(\frac{1}{8})}{-17190} \ = \ \lambda \\ \\ \-\hspace{1.05cm} \lambda \ = \ \displaystyle\frac{3\ln2}{17910} \ \ \ \ \ \ \ \ \ \ (\ln \displaystyle\frac{1}{x} \ = \ -\ln x\ ; \ \ln x^{n} \ = \ n\ln x )[/tex]

Equate both λ,

                                            [tex]\displaystyle\frac{\ln 2}{t_{\frac{1}{2}}} \ = \ \displaystyle\frac{3\ln2}{17190} \\ \\ \-\hspace{0.26cm} t_{\frac{1}{2}} \ = \ \ln 2 \ \times \ \displaystyle\frac{17190}{3\ln2} \\ \\ \-\hspace{0.26cm} t_{\frac{1}{2}} \ = \ \displaystyle\frac{17190}{3} \\ \\ \-\hspace{0.26cm} t_{\frac{1}{2}} \ = \ 5730[/tex]

*Note that the above calculations demonstrated that carbon-14 went through 3 half-lives to yield a remaining 12.5% of its original amount, since

                                 [tex]100\% \ \overset{t_{\frac{1}{2}}}\longrightarrow \ 50\% \ \overset{t_{\frac{1}{2}}}\longrightarrow \ 25\% \overset{t_{\frac{1}{2}}}\longrightarrow \ 12.5\%[/tex].

Therefore, if n is the time taken for carbon-14 to half its initial amount trice to remain 12.5% of its initial amount. Then, the half-life of carbon-14 is [tex]\displaystyle\frac{n}{3}[/tex].