How to find the missing numbers

Answer:

The relative risk of being a college graduate for Boone County residents as compared to Cooper County residents is 3.11.

Step-by-step explanation:

Denote the events as follows:

C = Cooper County resident

B = Boone County resident

G = graduate

NG = non-graduate

The information provided is summarized as follows:

               G       NG     Total

     C       18       82       100

     B       28      22        50

Total       46      104      150

Compute the relative risk of being a college graduate for Boone County residents as compared to Cooper County residents as follows:

[tex]\text{Relative Risk}=\frac{\text{Graduates in Boone County}}{\text{Graduates in Cooper County}}[/tex]

                      [tex]=\frac{28/50}{18/100}\\\\=\frac{28}{50}\times \frac{100}{18}\\\\=3.11111\\\\\approx 3.11[/tex]

Thus, the relative risk of being a college graduate for Boone County residents as compared to Cooper County residents is 3.11.

The relative risk of remaining a college graduate for Boon County residents in comparison to Cooper County residents would be 0.500

Relative risk is used in the statistical analysis of the data of ecological, cohort, medical, and intervention studies, to estimate the strength of the association between exposures (treatments or risk factors) and outcomes. Mathematically, it is the incidence rate of the outcome in the exposed group.

The relative risk is calculated by dividing the probability of an event for group 1 divided by the probability of an event occurring for group 2.

The probability of the Boone country resided is a college graduate,

By the formula of classical probability [tex]P(A)=\frac{m}{n}[/tex] then,

[tex]\frac{18}{100}=0.18[/tex]

The probability of cooper country resided is a college graduate is,[tex]\frac{18}{50}=0.36[/tex]

The relative risk is being a college graduate Boone country resided as compared to cooper country resident is,

[tex]\frac{0.18}{0.36} =0.500[/tex]

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Answer:

andrew gets 15 dollars a hour

and andr

Answer:

elsa's interval width will be greater than that of frank

Step-by-step explanation:

first of all we are told that both Elsa and Frank have the same sample proportion so their midpoint is also going to be the same.

now as the confidence level goes higher, so also would the margin of error increase. then the width of the confidence interval would rise so it can be more confident.

from this question elsa has a larger confidence level therefore her intervals width will be greater than franks own.

Answer:

g=4 h=6

Step-by-step explanation:

3g +h = 18 (Equation 1)

2g+3h=26 (Equation 2)

From equation 1

3g+ h =18

h= 18-3g (equation 3)

substitute equation 3 into equation 2

2g+3h= 26

2g+ 3(18-3g)= 26

2g+3×18+3(-3g)=26

2g+54-9g=26

9g-2g= 54-26

7g=28

7g÷7 = 28÷7

g= 4

substitute g into equation 1

3g+h=18

3(4)+ h= 18

12+h= 18

h=18-12

h= 6

Answer:

g = 4; h = g

Step-by-step explanation:

When solving an equation with two variables, the goal is to isolate at least one of the variables so that you can plug it in to the equation to get the other. There are multiple ways to solve this so I'll just be giving one.

3g + h = 18

2g + 3h = 26

In these two equations, I notice that if I multiply the first equation by 3, the two equations will have the same values of h, so I'd be able to isolate g:

9g + 3h = 54

2g + 3h = 26

Now, subtract the second equation from the first to isolate g:

9g + 3h = 54

-2g + 3h = 26

= 7g = 28

= g = 4

Now that we have solved for g, we can plug it into either of the equations and solve for h:

2(4) + 3h = 26

= 8 + 3h = 26

= 3h = 18

= h = 6

And in conclusion, g = 4 and h = 6.

Answer:

[tex]\left(x-1+3y\right)\left(x-1-3y\right)[/tex]

Step-by-step explanation:

[tex]x^2-2x+1-9y^2\\\\factor(skip for time)\\\\\left(x-1\right)^2-9y^2\\\\[/tex]

A little algebra process later...

you got the answer

Hoped this helped ya

<3

Answer:

(x-1-3y) x (x-1+3y)

Step-by-step explanation:

x^2-2x+1-9y^2

Using a^2 - 2ab + b^2 = (a-b)^2 (factor the expression) = (x-1)^2 - 9y^2

(x-1)^2 - 9y^2 = (x-1-3y) x (x-1+3y)  should be the answer :)

Answer:

In the given expression, 10x + 8, the numerical coefficient is 10 and the literal coefficient is x. The number 8 is not considered as a coefficient since the value is a constant.

Answer: 10 + 8

Step-by-step explanation: If you want to find a coefficient you need to only remove the variable from the expression. For example what is the coefficient of 4x its 4. Please mark as the brainliest!

Answer:

Week 1 - 20

Week 2 - 27

Week 3- 34

Week 4 - 41

Week 5 - 48

Etc, etc,...

Step-by-step explanation:

The values increase by 7 each week.

Answer as a mixed number = 46 & 1/4

Answer as a decimal = 46.25

===============================================

Work Shown:

9 & 1/4 = 9 + 1/4 = 9 + 0.25 = 9.25

1/5 = 0.2

A bag of cashews weighs 9.25 pounds and one serving is 0.2 pounds.

Let x be the number of servings

1 serving = 0.2 pounds

x servings = 0.2x pounds after multiplying both sides by x

0.2x pounds represents the total bag's weight so,

0.2x = 9.25

x = 9.25/0.2

x = 46.25 answer in decimal form

x = 46 + 0.25

x = 46 + 1/4

x = 46 & 1/4  answer in mixed number form

This means we have 46 full servings plus an additional 1/4 of a serving.

Answer:

Step-by-step explanation:

5.234

Answer:

We reject H₀, we find that the  current level of mercury uptake in the Everglades has decrease

Step-by-step explanation:

We need to test the current wading bird average 14,6 vs the 1995 average. As sample mean is 14,6 and population mean is 15 we are going to check test is of one tail (left tail test)

Test Hypothesis:

Null hypothesis             H₀          μ   =  μ₀

Alternative hypothesis Hₐ          μ   <  μ₀

Sample size 25             then n < 30 we will use t-student table

Population mean : μ₀ = 15 ppm

sample mean :  μ  = 14,6 ppm

sample standard deviation:   s = 1 ppm

Sample size n :  25

degrees of freedom   df = n - 1         df = 24

We will develop the test for CI 90%  then  α = 10%      α = 0,1   α/2 = 0,05

For that values in t student table we find:

t(c) = 1,711    by symmetry t(c) = - 1,711

To compute ts

t(s) =  ( μ - μ₀ ) / s/√n

t(s) = 14,6 - 15 / 1 /√25

t(s) = - 0,4*5 / 1

t(s) = - 2

Comparing t(c)and t(s)

|t(s)| > |t(c) |      and t(s) < t(c)         -2 < -1,711

Therefore t(s) in in the rejection region, we reject H₀  

Answer: 31

Step-by-step explanation: long division

Answer:

answer is 5

Step-by-step explanation:

f(5)= -5×5^2+26×5

= -125+130

= 5

Answer:

If there was 2 gallons in the tub at the moment, it must mean that it has been 2/3 of a minute or 40 seconds.

The two rates would be 3:60 and 2:40 and so on 1:20

Step-by-step explanation:

Good luck! Hope this helps! <3

Answer:

y=mx+b

y=mx+b-b

y-b=mx

y-b/m = mx/m

y-b/m = x

Answer:

x = (y - b)/M.

Step-by-step explanation:

y = Mx + b

Mx = y - b

x = (y - b)/M.

Answer:cool

Step-by-step explanation:

Answer:

23

Step-by-step explanation:

let the number be 'a'

-2(a - 19)= -8

open the brackets

-2a + 38 = -8

collect like terms

38 + 8 = 2a

46 = 2a

a = 23

Answer:

2 plus 3

Step-by-step explanation:

Answer:

4mm

Step-by-step explanation:

The ratio of the two congruent shapes are 2.5:1

15 : 6 = 2.5 : 1

15/6 = 2.5

5 : 2 = 2.5 : 1

5/2 = 2.5

Therefore, 10 : x = 2.5 : 1

10/x = 2.5

x = 4

Answer: 15, 2, 6, and 5

Step-by-step explanation: they are equal to the measurements listed

Answer:

can i friend you

Step-by-step explanation:

Answer:

The average cost per​ tape is 10.

Step-by-step explanation:

The cost of manufacturing a particular videotape is :

C(x) = 9000+9x

Where

x is the number of tapes produced.

We need to find the value of average per tape i.e. [tex]\lim_{x \to 9000} \bar C(x)[/tex]

[tex]\bar C(x)=\dfrac{9000+9x}{x}\\\\=\dfrac{9000}{x}+9\\\\ \lim_{n \to 9000} \bar C(x)=\dfrac{9000}{9000}+9\\\\=1+9\\\\=10[/tex]

So, the average cost per​ tape is 10.

Answer:

true

Step-by-step explanation:

if the ball lands on the team who served the ball's side of the court they are allowed to replay it. :)

Answer:

The big container holds 30 gallons and the small container holds 20 gallons

Step-by-step explanation:

Let

The big container = x

Small container = y

The big container can hold 10 gallons less than twice the small

x = 2y - 10

Total gasoline in both containers = 50 gallons

x + y = 50

Substitute x = 2y - 10 into the equation

2y - 10 + y = 50

3y = 50 + 10

3y = 60

Divide both sides by 3

y = 60 / 3

= 20

y = 20 gallons

Recall,

x + y = 50

x + 20 = 50

x = 50 - 20

= 30

x = 30 gallons

The big container holds 30 gallons and the small container holds 20 gallons

Answer:

The big container has 30 gallons and the small container has 20 gallons.

Step-by-step explanation:

[tex]\tt Step-by-step~explanation:[/tex]

Slope = rise/run

[tex]\tt Steps:[/tex]

Rise: The line travels 5 units vertically (up) from the first point to the second.

Run: The line goes 6 units horizontally (left) from the first point to the second.

Slope = rise/run; Slope = 5/6

[tex]\Large\boxed{\tt The~slope~of~the~line~is:~\frac{5}{6}~units }[/tex]

Answer:

Slope = rise/run

Step-by-step explanation:

Answer:

a = -6

Cov (2X+Y, 3X-4Z) = 30

Step-by-step explanation:

Key points:

Cov(2X, -3Y+2) = a⋅Cov (X,Y)

Cov (2X, -3Y) + Cov (2X, 2) = a⋅Cov (X,Y)

(2)⋅(-3)⋅Cov (X, Y) + 0 = a⋅Cov (X,Y)

-6⋅Cov (X, Y) + 0 = a⋅Cov (X,Y)

⇒ a = -6.

(c)

Suppose that X, Y, and Z are independent, with a common variance of 5, i.e. V (X) = V (Y) = V (Z) = 5

Cov (2X+Y, 3X-4Z) = Cov (2X, 3X) + Cov (2X, -4Z) + Cov (Y, 3X) + Cov (Y, -4Z)

                               = 6⋅Cov (X, X) - 8⋅Cov (X, Z) + 3⋅Cov (Y, X) - 4⋅Cov (Y, Z)

                               = (6 × 5) - 0 + 0 - 0

                               = 30

Thus, the value of Cov (2X+Y, 3X-4Z) is 30.

The value of a = -6. And, Cov (2X+Y, 3X-4Z) = 30.

Since

Cov (aX, bY) = a·b·Cov (X, Y)

Cov (X, X) = V (X)

Cov (X, a) = 0

In the case when X and Y are independent so Cov (X, Y) = 0.

Now

Cov(2X, -3Y+2) = a⋅Cov (X,Y)

Cov (2X, -3Y) + Cov (2X, 2) = a⋅Cov (X,Y)

(2)⋅(-3)⋅Cov (X, Y) + 0 = a⋅Cov (X,Y)

-6⋅Cov (X, Y) + 0 = a⋅Cov (X,Y)

a = -6.

(c)

here

Suppose that X, Y, and Z are independent, with a common variance of 5, i.e.

V (X) = V (Y) = V (Z) = 5

So,

Cov (2X+Y, 3X-4Z) = Cov (2X, 3X) + Cov (2X, -4Z) + Cov (Y, 3X) + Cov (Y, -4Z)

= 6⋅Cov (X, X) - 8⋅Cov (X, Z) + 3⋅Cov (Y, X) - 4⋅Cov (Y, Z)

= (6 × 5) - 0 + 0 - 0

= 30

Thus, the value of Cov (2X+Y, 3X-4Z) is 30.

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Answer:

(1) B

(2) A

(3) C

(4) B

Step-by-step explanation:

(1)

The observational units in this study are the men with prostate cancer.

(2)

As the study involves a treatment and a control group, it is an experimental study.

(3)

The primary purpose of random assignment in this type of study is to create treatment groups that are alike in all aspects except for the treatment administered.

(4)

The explanatory variable or the independent variable, is the variable that is altered to observe the changes in the dependent variable.

The explanatory variable in this case is whether or not man undergoes surgery.

(5)

The response variable or the dependent variable is the variable that is being observed for any changes for the given treatments.

The response variable in this case is whether or not man dies of prostate cancer related reasons.

Answer:

The point estimated is 0.260

Step-by-step explanation:

The computation is shown below:

Sample in which the people have diabetes = 52

Random sample = 200

Significance level = 5%

Based on this, the, estimation point is

= Sample in which the people have diabetes ÷ Random sample

= 52 ÷ 200

= 0.260

hence, the point estimated is 0.260

We simply applied the above formula

And, the same is to be considered

The Null Hypothesis is accepted because the value of z is 0.973 and this can be determined by performing the test of the Hypothesis.

Given :

Hypothesis are as follows:

Null hypothesis,  [tex]\rm H_0: p\leq 0.231[/tex]

Alternate hypothesis,  [tex]\rm H_a : p>0.231[/tex]

Now, performing the test of the hypothesis. The critical value z is given by:

[tex]z = \dfrac{\hat{p}-p_0}{\sqrt{\dfrac{p_0(1-p_0)}{n}}}[/tex]    ----- (1)

Now, the value of [tex]\hat {p}[/tex] is given by:

[tex]\hat{p}=\dfrac{52}{200} = 0.26[/tex]

Now, put the values of known terms in equation (1).

[tex]z = \dfrac{0.26-0.231}{\sqrt{\dfrac{0.231\times 0.769}{200}}}[/tex]

[tex]z = \dfrac{0.029}{0.0298}[/tex]

z = 0.973

Therefore, the null hypothesis is accepted.

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