The amount of work done to stop the car is equal to 322,099.85 Joules.
Given the following data:
Mass = 925 kilogramsVelocity = 95 km/hConversion:
Velocity = 95 km/h = [tex]\frac{95 \times 1000}{60 \times 60} = 26.39 \;m/s^2[/tex]
To determine the amount of work done to stop the car, we would apply the work-energy theorem:
Note: The amount of work done must balance the kinetic energy possessed by the car due to its motion.
From the work-energy theorem, we have:
[tex]Work\done = \Delta K.E\\\\Work\done = \frac{1}{2} MV^2[/tex]
Substituting the given parameters into the formula, we have;
[tex]Work\;done = \frac{1}{2} \times 925 \times (26.39)^2\\\\Work\;done =462.5 \times 696.4321[/tex]
Work done = 322,099.85 Joules
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2. In a race, if a runner starts and stops at the same position, what is their
displacement? *
Answer:
It is the same
Explanation:
I Jsut know
What role does physical health play into nutrition?
What is its time interval between the release of the ball and the time it reaches its maximum height? Its initial vertical speed is 9 m/s and the acceleration of gravity is 9.8 m/s 2 . Neglect air resistance.
Answer:
The time to reach max height is h = 1/2 g t^2
The time to fall is the same as that for an equivalent rise
m g h = 1/2 m v^2 KE vs PE
Here: (Vf - VI) / g = t = -9 / -9.8 = .92 s
A body is accelerated constantly. What is the form of the graph? A. cubic. B. inverse. C. linear. D. quadratic.
Answer:
D is the correct answer for this question.
Explanation:
I had done this already
An object has an acceleration of 6.0 m/s/s. If the NetForce was tripled and the mass was halved, then the new acceleration would be _____ m/s/s
Hi there!
We know that:
∑F = ma
If you tripled the net force and halved the mass:
3F = 1/2ma
Rearrange for 'a':
3F × 2 = ma
6F = ma
Thus, the new acceleration would be 6 times the original, or 36 m/s².
A person drops two objects from the same height. One object weighs 15 N, and the other weighs 10 N. How does the mass of the objects relate to the force of gravity on them? A. The 10 N object has the same mass as the 15 N object. B. The 10 N object has more mass than the 15 N object. C. The 15 N object has twice the mass of the 10 N object. D. The 15 N object has more mass than the 10 N object. SUR
Answer:
Your answer would be D :)
Explanation:
An object with a higher mass will always fall faster due to gravity acting upon it. 15 N is more massive than the 10 N object, so statement D is correct.
The time (t) required to empty a tank varies inversely as the rate (r) of pumping. If a
pump can empty a tank in 3 hours at a rate of 400 gallons per minute, how long will it
take to empty a tank at 600 gallons per minute?
Answer:
T = C / R t = time, C =constant of proportionality, R = rate
180 min = C / 400 gal/min
C = 72000 gal to empty tank
T = 72000 gal / 600 gal/min = 120 min = 2 hrs
atom a has an atomic number of 40 atom b has an atomic number of 20 and a mass of 40 which of these is an accurate statement
Answer:14
Explanation:cuz
Can anyone help out with this question?
I'll mark as brainliest
Thankyou.
Answer:
p=I×B
Explanation:
If a current 'I' flows through a given element in your circuit, losing voltage 'V' in the process, then the power 'P' dissipated by that circuit element is the product of that current and voltage.
Power of an electric motor is 1 h.p. what does it mean ?
Answer: HP = Horse Power.
Explanation: it is the unit given to tell the motor's particular power and 1hp = 746 watts.
1 Loudness and pitch are two important properties of a musical sound.
a If a musician plays a softer note, which property has been changed,
loudness or pitch?
b If the musician makes the note lower, which property has been
changed, loudness or pitch?
If two stars are in a binary system with a combined mass of 5.5 solar masses and an orbital period of 12 years, what is the average distance between the two stars
The average distance between the two stars is 792 light years
Let the mass of the first star be [tex]m_1[/tex]
Let the mass of the second star be [tex]m_2[/tex]
The combined mass of the two stars, [tex]m_1+m_2=5.5[/tex] solar masses
The orbital period of the stars, P = 12 years
Average distance between the two stars, D = ?
The average distance between the two stars can be calculated using Kepler's equation
[tex]D=(m_1+m_2)P^2[/tex]
Substitute [tex]m_1+m_2=5.5[/tex] and P = 12 into the formula [tex]D=(m_1+m_2)P^2[/tex]
[tex]D=5.5(12^2)[/tex]
D = 5.5(144)
D = 792 light years
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I=24
Q=400C
t=102
Help please
[tex] \huge \bf༆ Answer ༄[/tex]
The given terms in the question are : -
I = Electric current = 2 AmperesQ = Charge = 400 CoulombsWe have been given the task to find out time (t)
The formula that can be used to find time is : -
[tex] \sf \: I = \dfrac{ Q}{t}{} [/tex]
Rearrange the formula,
[tex] \sf \: t = \dfrac { Q}{I }[/tex]
Solve for time (t)
[tex] \sf t = \dfrac{400}{2} [/tex][tex] \sf t = 200 \: \: sec[/tex][tex]꧁ \: \large \frak{Eternal \: Being } \: ꧂[/tex]
Arthur (mass 79 kg) and Violet (mass 50 kg) are trying to play on a seesaw. If Violet sits 4 m from the fulcrum, at what distance from the fulcrum should Arthur sit
Hi there!
There are two torques acting on the system:
τ (Arthur) = RW = R(790N)
τ (Violet) = RW = 4(500N) = 2000N
∑τ = 0 = τ(Violet) - τ(Arthur)
Thus:
τ(Violet) = τ(Arthur)
2000 = 790R
R ≈ 2.53m
A ball is dropped from a 20.0 m high tower.
a. How long will it take the ball to reach the ground?
b. What is the velocity of the ball just before it hits the ground?
Hi there!
We can begin by using the derived kinematic equation:
[tex]t = \sqrt{\frac{2h}{g}[/tex]
Plug in the given values and let g = 9.8 m/s²:
[tex]t = \sqrt{\frac{2(20)}{g}} = \boxed{2.02 s}[/tex]
Now, we can solve for its final velocity using the equation:
[tex]v_f = v_i + at[/tex]
It is dropped from rest, so vi = 0 m/s.
[tex]v_f = at[/tex]
[tex]v_f = 9.8(2.02) = \boxed{19.796 m/s}[/tex]
Answer:
a. The ball would reach the ground in approximately [tex]2.02\; \rm s[/tex].
b. The velocity of the ball right before landing would be approximately [tex]19.8\; \rm m\cdot s^{-1}[/tex].
(Assumptions: the ball was dropped with no initial velocity; air resistance on the ball is negligible; [tex]g = 9.81\; \rm m\cdot s^{-2}[/tex].)
Explanation:
Under these assumptions, the acceleration of this ball would be constantly [tex]a = g = 9.81\; \rm m\cdot s^{-2}[/tex] (same as the gravitational field strength) during the descent.
Displacement of the ball: [tex]x = 20.0\; \rm m[/tex].
Initial velocity of the ball: [tex]v_{0} = 0\; \rm m\cdot s^{-1}[/tex].
Let [tex]t[/tex] denote the duration of this descent.
The SUVAT equation [tex]x = (1/2)\, a\, t^{2} + v_{0}\, t[/tex] relates the known quantities [tex]a[/tex], [tex]x[/tex], and [tex]v_{0}[/tex] to the unknown [tex]t[/tex].
Substitute the known quantities into this equation and solve to find the value of [tex]t\![/tex]:
[tex]\displaystyle 20.0\; {\rm m} = \frac{1}{2}\times 9.81\; {\rm m\cdot s^{-2}} \times t^{2} + 0\; {\rm m \cdot s^{-1}} \times t[/tex].
[tex]\displaystyle 20.0\; {\rm m} = \frac{1}{2}\times 9.81\; {\rm m\cdot s^{-2}} \times t^{2}[/tex].
[tex]\displaystyle t^{2} = \frac{20.0\; \rm m}{(1/2) \times 9.81\; \rm m\cdot s^{-2}}[/tex].
Since [tex]t > 0[/tex]:
[tex]\begin{aligned}t &= \sqrt{\frac{20.0\; \rm m}{(1/2) \times 9.81\; \rm m\cdot s^{-2}}} \\ &\approx 2.01928\; \rm s\\ &\approx 2.02\; \rm s \\ & (\text{Rounded to 2 sig. fig.})\end{aligned}[/tex].
Since the acceleration of this ball is constant, the velocity of the ball right before landing would be:
[tex]\begin{aligned}v_{1} &= a\, t \\ &\approx 9.81\; \rm m\cdot s^{-2} \times 2.01928\; \rm s \\ &\approx 19.8\; \rm m \cdot s^{-1} \end{aligned}[/tex].
Calculate the relative molecular of calcium carbonate
* as following method*
Answer:
100.22
Explanation:
Have a great day!
The diagram shows what happened in the Rutherford and Marsden scattering experiment. Complete this sentence: The particle shown in red will come straight back from the foil because it is __________ by the charge in the gold nucleus.
From Rutherford and Marsden scattering experiment, we can conclude that the particle shown in red will come straight back from the foil because it is deflected by the charge in the gold nucleus.
Rutherford proposed Planetary model atom, which visualized an atom to consists of a positively charged heavy core called the nucleus around which negatively charged electrons circle in orbits much as planets move round the sun
Thus, from Rutherford and Marsden scattering experiment, we can conclude that the particle shown in red will come straight back from the foil because it is deflected by the charge in the gold nucleus.
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the answer is reflected or u can say repelled
what are the three different ways to tell the difference between a solar and lunar eclipse?
Answer:
Solar eclipses occur when the Moon passes between Earth and the Sun, leaving a moving region of shadow on Earth's surface. Lunar eclipses occur when Earth passes between the Sun and the Moon, casting a shadow on the Moon. This is an annular eclipse.
(credits to "britannica")
Explanation:
An object weights 1000N on the earth’s surface. [ g=10N/Kg]
Calculate its mass
Answer: An object weights 1000N on the earth's surface. ... Calculate its mass ... strength is 10 N/kg how many newtons does a 30kg object weigh.
Explanation:
You use a rope 2.00 m long to swing a 10 kg weight around your head. The tension in the rope is 20 N. In half a revolution how much work in J is done by the rope on the weight
Answer:
No work is done on the weight. :3
To solve this we must be knowing each and every concept related to work and its calculation. Therefore, 250J is the work done in joule by the rope on the weight.
What is work?Work in physics is the energy delivered to or out of an item by applying force across a displacement. It is frequently expressed in its most basic form as the combination of displacement and force.
When a force is applied, it is said to produce positive work if it has a proportion in the orientation of the movement of a site of application. Work done is positive when the direction of force acting on the object and displacement of the object both are in the same direction.
Mathematically,
Work= force ×displacement
force =20 N
displacement=2.00 m
displacement=2×3.14×2=12.5m
substituting all the given values in the above equation, we get
Work= 20 ×12.5
Work =250J
Therefore, 250J is the work done in joule by the rope on the weight.
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#SPJ5
Glucose typically enters the cell through which mechanisms
Answer:
facilitated diffusion
why does the energy of characteristic x rays tend to increase for heavier elements?
The energy of characteristic x rays tend to increase for heavier elements
because the charge of the nucleus increases.
X ray is a form of an electromagnetic spectrum and the energy is directly
proportional to the charge of the nucleus. This implies that an increase in
the nucleus charge will lead to a corresponding increase in x ray energy
and vice versa.
X rays energy is also usually more in heavier elements than when
compared to lighter elements
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is the amplitude just 2? Or do I combine all of them and do 6?
Answer:
combine them all
6 m
Explanation:
Which of the following are for vector directione?
A Outside 45 degrees
G 35 degrees north of east
D 35 degrees inside
The student investigates how the resistance of a thermistor varies with temperature. The student has a power supply, a thermistor, an ammeter, a voltmeter and some connecting leads. Describe an investigation the student could carry out to measure the resistance of a thermistor between –10 °C and 70 °C.
Your answer should include:
1. Any other apparatus the student will need
2. The measurements to be taken
3. How the data should be processed.
(This question is worth 6 marks on my assignment so I just really want to get down the best possible answer for it.)
The characteristics of the thermistors allow to design an experiment to analyze the dependence of resistance with temperature;
1) We set up the circuit
2) We look for the current of the circuit and we keep it fixed.
3) We look for the thermistor resistances for each temperature.
4) Plot Resistance versus Temperature.
A Thermitor is an element whose resistance changes with temperature, for example a platinum resistance.
An experiment that we can carry out to measure is to set up the attached circuit where we have:
A DC power supply. A resistor to control the maximum current in the circuit and avoid thermal problems in the thermistor. A thermistor. A thermometer placed next to the thermistor. A source of heat under the thermistor under a glass with ice and water, but without affecting the other elements of the circuit.
Let's start by looking for the current in the circuit.
In thermistors, the resistance for room temperature is given, so if we measure the voltage across the fixed resistor, we can shrink the voltage across the thermistor.
[tex]V_{source} = V_R + V_{therm} \\V_{therm} = V_{source} - V_R \\ i = \frac{V_{therm} }{R_{therm}}[/tex]
This current remains fixed, since the fixed resistance is greater than the resistance of the thermistor throughout the range.
Second step.
Now we can change the temperature that is measured in the thermometer, for each temperature the voltage in the fixed resistance is measured, the resistance in the thermistor is calculated.
[tex]R_{therm} = \frac{V_{source} - V_R}{i}[/tex]
Third step.
We end with a graph of resistance versus temperature of the curve obtained, it is possible to understand the behavior of the resistance of the thermistor with temperature.
In conclusion with the characteristics of thermistors we can design an experiment to analyze the dependence of resistance with temperature:
1) We set up the circuit
2) We look for the current of the circuit and we keep it fixed.
3) We look for the thermistor resistances for each temperature.
4) Plot Resistance versus Temperature.
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if the amplitude of a sound wave is tripled, the intensity will:
Answer:
Increase 9 times
Explanation:
To measure the current through and the voltage across a resistor in a circuit, you should place the ammeter in _____ with the resistor and the voltmeter in _____ with the resistor.
Answer:
ammeter: seriesvoltmeter: parallelExplanation:
The current is the same through components connected in series. If you want to measure the current in a component, the ammeter must be placed in series.
__
The voltage is the same at the terminals of components connected in parallel. If you want to measure the voltage across a component, the voltmeter must be connected across the component, that is, in parallel with it.
[tex]\huge \mathbb \pink{ANSWER:}[/tex]
To measure the current through and the voltage across a resistor in a circuit, you should place the ammeter in series with the resistor and the voltmeter in parallel with the resistor.
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1+1 =?
2+2=?
3+3=?
1+1 =?
2+2=?
3+3=?
Answer:
here is your answer
1+1=2
2+2=4
4+4=8
Which is true of the intensity of sound?
Answer:
c.
Explanation:
As the distance between two objects changes, how does the gravitational force between them change?
Answer:
Explanation:
The gravitational force = G * m1 * m2 / r^2
That means as the distance increases, r get's bigger and m1 and m2 don't change, the force decreases. Read that sentence carefully. In physics, it is very important to know what goes up and goes down means and especially why.