How many valence electrons are there is the molecule CH 06P2

Answer:

20atm

Explanation:

according to boyles law P1V1= P2V2

Answer

The two types of chemical bonds that atoms can form to achieve stability are called ionic bonds and covalent bonds. In ionic bonds, atoms donate or receive electrons to achieve stability. In covalent bonds, atoms share electrons to achieve stability.

The concentrations : 0.15 M

pH=11.21

The ionization of ammonia in water :

NH₃+H₂O⇒NH₄OH

NH₃+H₂O⇒NH₄⁺ + OH⁻

The concentrations of all species present in the solution = 0.15 M

Kb=1.8 x 10⁻⁵

M=0.15

[tex]\tt [OH^-]=\sqrt{Kb.M}\\\\(OH^-]=\sqrt{1.8\times 10^{-5}\times 0.15}\\\\(OH^-]=\sqrt{2.7\times 10^{-6}}=1.64\times 10^{-3}[/tex]

[tex]\tt pOH=-log[OH^-]\\\\pOH=3-log~1.64=2.79\\\\pH=14-2.79=11.21[/tex]

Explanation:

A stethoscope is used to listen to sounds that the heart , lungs , blood flow , intestines make.

Answer:

The magnesium ion is much smaller than the magnesium atom because magnesium atom contains more electrons as compared to magnesium ion. Explanation: ... Whereas when an atom tends to lose an electron then it acquires a positive charge and size of the atom tends to increase.

Answer:

Because it looses it two electrons to form a stable octet Ionic form..........

Answer:

B

Explanation:

a mole is "a chemist's dozen" lol

Graphite is sometimes used to reduce the friction between two surfaces that are rubbing together. Therefore, this happen because of weak covalent bond.

Graphite is among the most prevalent carbon allotropes. It is also the stable allotrope for carbon, and as such, it is employed in electrochemistry to define the heat of synthesis of carbon compounds. With a hardness of 2.09-2.23 g/cm3, graphite is an excellent conductor of electricity and heat.

Graphite is a large covalent structure in which each carbon atom is covalently linked to three other carbon atoms. Graphite is sometimes used to reduce the friction between two surfaces that are rubbing together. This happen because of weak covalent bond.

Therefore, graphite is sometimes used to reduce the friction between two surfaces that are rubbing together. This happen because of weak covalent bond.

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Answer:

Increases

Explanation:

The gravitational potential energy of an object increases as you bring it higher with respect to the ground.

Gravitational potential energy depends on the mass, height and gravity between two bodies;

   Gravitational potential energy  = mgh

m is the mass

g is the height

h is the height

Answer:

true

Explanation:

Answer:

The answer is "1 and 4 polygons were similar".

Explanation:

In the given question, in both figures 1 and 4, it's measure angle were 10, 60, 110. In figure number 4, its angle is 10, 60, and on the third side, its value is equal to 110, which is (180 - 70).

Answer:

A. 2 Fe, 3 S and 12 O

B. 43 moles of H

C. 1.0×10² moles of C

Explanation:

A. Formula for iron (III) sulfate is Fe₂(SO₄)₃

This salt has 2 atoms of iron and 3 sulfates, so in total we have:

2 Fe, 3 S and 12 O

Pay attention to the subscripts

B. Formula for quinine is: C₂₀H₂₄N₂O₂

If we continue with the example before we can say that 1 mol of Iron (III) sulfate contains 2 moles of Fe, 3 moles of S and 12 moles of O

Then, 1 mol of quinine contains 24 moles of H

So 1.8 moles of quinine, may contain (1.8 . 24) /1 = 43 moles of H

C.  1 mol of quinine contains 20 moles of C

5.4 moles of quinine may contain (5.4 . 20) /1 = 1.0×10²

(As the answer must be in 2 significant figures and the real answer is 108, I had to use scientific notation)

The work energy of this process : 2337.298 J

The laws of thermodynamics 1 state that: energy can be changed but cannot be destroyed or created  

ΔU=Q-W

Q=m.c.Δt

[tex]\tt Q=8.85\times 2.650\times 63.2=1482.198~J[/tex]

the work (W) :

[tex]\tt W=Q-\Delta U\\\\W=1482.198-(-855.1)=2337.298~J[/tex]

umm explanation pls so i answee

Answer:

P1 = 21.23 atm

Explanation:

Initial Volume V1 = 11.95 L

Final Volume V2 = 5.24L

Final Pressure P2 = 9.31 atm

Initial Pressure P1 = x

The relationship between these values is given as;

P1 / V1 = P2 / V2

P1 / 11.95 = 9.31 / 5.24

P1 = 21.23 atm

Answer:

0.138 moles of oxygen are needed to combine with 0.276 moles of carbon.

Explanation:

Given data:

Moles of oxygen needed = ?

Moles of carbon present = 0.276 mol

Solution:

Chemical equation:

2C  + O₂      →        2CO

Now we will compare the moles of carbon with oxygen.

              C            :          O₂  

              2            :            1

             0.276     :        1/2×0.276  = 0.138 mol

Thus, 0.138 moles of oxygen are needed to combine with 0.276 moles of carbon.

Answer:

411.6 g

Explanation:

The equation for the decomposition of potassium chlorate to produce oxygen is given as;

2KClO3 --> 2KCl + 3O2

From the stochiometry of the reaction 2 mole of KClO3 produces 3 mol of O2

At STP,

1 mol = 22.4L

3 mol = x

x = 67.2L

2 mole of KClO3 produces 67.2L of O2

How many moles would produce 113L?

2 = 67.2

x = 113

x = 3.36 moles

Moles can be converted to mass using;

Mass = moles * Molar mass

Mass = 3,36 * 122.5 g/mol

Mass = 411.6 g

Answer:

Physical Change. Physical changes are changes in which no bonds are broken or formed. This means that the same types of compounds or elements that were there at the beginning of the change are there at the end of the change.

Answer:

3.57 × 10⁵ mol O₂

7.13 × 10⁵ mol H₂O

Explanation:

Step 1: Write the balanced equation

2 H₂ + O₂ ⇒ 2 H₂O

Step 2: Calculate the moles corresponding to 1.44 × 10⁶ g of hydrogen

The molar mass of hydrogen is 2.02 g/mol.

1.44 × 10⁶ g × (1 mol/2.02 g) = 7.13 × 10⁵ mol

Step 3: Calculate the moles of oxygen needed to react with 7.13 × 10⁵ moles of hydrogen

The molar ratio of H₂ to O₂ is 2:1. The reacting moles of oxygen are 1/2 × 7.13 × 10⁵ mol = 3.57 × 10⁵ mol.

Step 4: Calculate the moles of water produced from 7.13 × 10⁵ moles of hydrogen

The molar ratio of H₂ to H₂O is 2:2. The moles of water formed are 2/2 × 7.13 × 10⁵ mol = 7.13 × 10⁵ mol.

Answer:

48.0g is the specific gravity of liquid sample with a mass of 35.0g and a volume of 14.00 mL

Hydrogen can only form single covalent bonds when forming molecular compounds. Therefore, option B is correct.

A covalent bond is a type of chemical bond formed between two or more atoms in which electrons are shared between them. Covalent bonds usually occur between nonmetal atoms and are formed by the sharing of valence electrons.

Hydrogen can only form a single covalent bond because it has only one valence electron and needs one more electron to complete its valence shell, making it stable.

Nitrogen can form triple covalent bonds, carbon can form multiple covalent bonds, and oxygen can form double covalent bonds in molecular compounds.

Thus, option B is correct.

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Answer:

79.63

Explanation:

Answer:

Mantle convection

Explanation:

The source of the force that moves tectonic plates along plate boundaries is as a result of the mantle convection.

Taking into account the reaction stoichiometry and the definition of molarity, 175 mL of 2 M H₂SO₄ will react with 28.0 g of NaOH.

In first place, the balanced reaction is:

H₂SO₄ + 2 NaOH  → Na₂SO₄ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

[tex]Molarity= \frac{number of moles}{volume}[/tex]

Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].

The following rule of three can be applied: If by reaction stoichiometry 80 grams of NaOH react with 1 mole of H₂SO₄, 28 grams of NaOH react with how many moles of H₂SO₄?

[tex]moles of H_{2}S O_{4} =\frac{28 grams of NaOHx1 mole ofH_{2}S O_{4} }{80 grams of NaOH}[/tex]

moles of H₂SO₄= 0.35 moles

In this case, you know:

Replacing in the definition of molarity:

[tex]2 \frac{moles}{liter}= \frac{0.35 moles}{volume}[/tex]

Solving:

2 [tex]\frac{moles}{liter}[/tex] × volume= 0.35 moles

volume= 0.35 moles ÷ 2 [tex]\frac{moles}{liter}[/tex]

volume= 0.175 liters= 175 mL (being 1 L= 1000 mL)

Finally, 175 mL of 2 M H₂SO₄ will react with 28.0 g of NaOH.

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Answer:

The advantages of using an indicator to inform pH measurements:

It gives a mathematically result of the pH, in addition, it gives the precise pH of solvent, and it also gives an idea of the straight of the solution also.

Now, the advantage of using a pH meter:

It is a rapid method to characterize between acids, bases. However, this method does not show how strong acid or base actually are, plus it tends to gives a range of acidity or basicity not quite accurate as a result.

Answer:

Average atomic mass of chlorine is 35.48 amu.

Explanation:

Given data:

Percent abundance of Cl-35 = 76%

Percent abundance of Cl-37 = 24%

Average atomic mass = ?

Solution:

Average atomic mass  = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass  = (76×35)+(24×37) /100

Average atomic mass =  2660 + 888 / 100

Average atomic mass  = 3548/ 100

Average atomic mass = 35.48 amu

Average atomic mass of chlorine is 35.48 amu.

Answer:

Fair test.

PLS GIVE BRAINLIEST

Answer:

B: They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers.

Explanation:

I took the Unit test on EDG and I got it correct

Pls mark me brainliest

Answer:

Biggest Radii     V²⁺ > V³⁺ > V⁴⁺ > V⁵⁺     Smallest Radii

General Formulas and Concepts:

Explanation:

The Periodic Trend for Atomic Radii is down and to the left. Therefore, the element with the largest radius would be in the bottom left corner of the Periodic Table.

Anions will always have a bigger radii than the parent radii. When we add e⁻ to the element, we are increasing the e⁻/e⁻ repulsions. This will cause e⁻ to repel themselves more and thus create more space, increasing the radii size.

Cations will always have smaller radii than the parent radii. When we remove e⁻ from the element, we are decreasing e⁻/e⁻ repulsions. Since there are less e⁻, there is no need for more space and thus decreases the radii size.

Since Cations are smaller than the parent radii, the more e⁻ we remove, the smaller it will become.

Therefore, the least removed e⁻ Vanadium would be the largest and the most removed e⁻ Vanadium would be the smallest.