How many moles of Fe2O3 are formed when 4.2 moles of Fe reacts completely with oxygen?

Answer:

I think it is b chromosomes are made of DNA. I'm not for sure tho sorry

Molar mass of Cu2CO3 is 187.05 g/mol

Molar mass M is the product of the mass of a chemical compound and the molecular weight of the substance. MB = m/nB, where m is the total mass of a sample of a pure material and nB is the molecular weight of substance B, is the formula for it. Pure substance is covered under the definition. Any material has a molecular weight of 6.023 x 1023. (Avagadro number). It can be used to quantify the results of a chemical reaction. Mol is used to indicate the unit.

= 63.5*2+12.01+16*3

= 187.05

so the molar mass of Cu2Co3 is 187.05

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When the atom, or system, emits or absorbs energy, a transition between two energy levels is said to take place. A system's ground state is the lowest energy level, and excited states have higher energy levels.

Only specific discrete values of energy, known as energy levels, can be absorbed by a bound or spatially constrained quantum mechanical system or particle. Unlike classical particles, which can have any amount of energy as well as excited and ground states, Electrons may be found at specific intervals from an atom's nucleus known as energy levels, also referred to as electron shells. In essence, this means that nuclear power facilities operate at full capacity for more than 92% of the year. This is approximately roughly two times more than natural gas and coal units, and approximately three times as reliable as wind and solar facilities.

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the same net ionic process takes place when any strong acid reacts with any strong base. When a strong acid reacts with a strong base, the net ionic equation for the process is:

H+ (aq) + OH- (aq) → H2O (l)

This reaction is known as a neutralization reaction, and it is characterized by the neutralization of the strong acid and base by forming water and a salt. In this equation, the acid (H+) donates a proton to the base (OH-), forming water (H2O) and a salt. The acid and base are said to be neutralized, and the resulting solution is neutral (neither acidic nor basic). This type of reaction is common in many chemical reactions and is often used in the laboratory to neutralize solutions and to titrate acids and bases.

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Answer:

In 125 grams of feCO3  287.30 g of FeCO3 oxygen is produce

Explanation:

The Balance Chemical Equation is as follow,

                           FeCl₂ + Na₂CO₃    →    FeCO₃ + 2 NaCl

Calculate Mass of FeCl₂ as,

                           Molarity  =  Moles ÷ Volume

Solving for Moles,

                           Moles  =  Molarity × Volume

Putting Values,

                           Moles  =  2 mol.L⁻¹ × 1.24 L

                           Moles  =  2.48 mol

Also,

                            Moles  =  Mass ÷ M.Mass

Solving for Mass,

                           Mass  =  Moles × M.Mass

Putting Values,

                            Mass  =  2.48 mol × 126.75 g.mol⁻¹

                            Mass =  314.34 g of FeCl2

Calculate Mass of FeCO₃ formed as,

According to equation,

          126.75 g (1 mole) FeClZ produces  =  115.85 g (1 mole) FeCO₃

So,

               314.34 g of FeCl₂ will produce  =  X g of FeCO₃

Solving for X,

                    X =  (314.34 g × 115.85 g) ÷ 126.75 g

                     X =  287.30 g of FeCO₃

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In comparison to hydrogen chloride, ammonia diffuses 1.46 times more quickly.

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199.86 0r 200g/mol molar mass for the compound cabr2

The orbitals or shells that enclose an atom's nucleus are home to electrons. In the nucleus, protons and neutrons are present. In the atom's nucleus, they coalesce. An atom's nucleus is surrounded by electrons in distinct orbits. The molar mass is calculated by dividing the mass (g) of a certain chemical element or chemical compound by the amount of the substance (mol). The standard atomic masses (in g/mol) of the component atoms can be added to determine the molar mass of a compound.

Thus, the molar mass of CaBr2 can be calculated as shown below.

Molar mass=(1×40.078gmol+(2×79.904gmol)

=40.078gmol+159.808gmol

=199.886gmol

Hence, the molar mass of CaBr2 is 199.886gmol.

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The procedure for preparing 100ml of a 1.5m kbr solution ,

1. Weigh exactly 17.85 g of KBr in a clean and dry 100 mL beaker.

2. Dissolve this salt in a minimum amount of distilled water (approximately 10-20 mL).

3. Transfer this diluted solution in a clean and dry 100 mL volumetric flask.

4. Dilute this solution up to the mark using distilled water.

5. This is 1.5 M KBr solution. Ready for use.

KBr refers to potassium bromide . In reality, potassium bromide (KBr) is a chemical substance. One of the common anticonvulsant medications used to treat canine and feline epilepsy is potassium bromide, sometimes known as KBr. This can be taken on its own or in conjunction with phenobarbital to control seizure activity. The odourless potassium bromide salt is a white crystalline powder, colourless crystals, or a white granular solid with a strong bitter flavour .

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24g of mass of the ammonia evaporates as it absorbs 8. 2 kilo joules of energy.

q = m .ΔHf

[tex]8.2KJ=m(399)\frac{J}{g}\\\frac {8.2*10^{3} J}{339\frac{J}{g}}=m\\0.024*10^{3}g=m\\24g=m[/tex]

With the formula NH3, ammonia is a nitrogen and hydrogen inorganic chemical. Ammonia, the simplest pnictogen hydride and a stable binary hydride, is a colourless gas with a strong, pungent odour.When molecules on a liquid's surface escape into the vapour phase, evaporation takes place. When clusters of liquid molecules erupt into vapour bubbles, boiling happens within the liquid's bulk rather than at its surface. Below, at, and above their boiling points, all liquids will evaporate.It contributes considerably to the nutritional demands of terrestrial creatures by serving as a precursor to 45% of the world's food and fertilisers. Biologically, it is a frequent nitrogenous waste, especially among aquatic animals.

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Boric acid suppositories dissolve entirely in the  in just a few minutes. While utilising a  suppository, some people choose to

Boric acid suppositories dissolve entirely in the  in just a few minutes. While utilising a  suppository, some people choose to wear a . You can limit the growth of yeast by putting gelatin capsules containing boric acid into your . You might observe improvements in symptoms a few days after beginning medication. In most cases, the infection will go away in 1 to 2 weeks. Inconvenience in the  are among the negative effects of boric acid use. after entering the capsule, there is a slight burning sensation. sluggish  discharge.

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The partial pressure of oxygen would be 0.63198 atm or 480.3047 mmHg.

According to Dalton's law of partial pressure, the pressure of a gas consisting of a mixture of gases is the sum of the partial pressure of individual gases in the mixture. This law is mathematically expressed as:

[tex]P_{total[/tex] = [tex]P_1 + P_2 + .....[/tex]

In this case, [tex]P_{total[/tex] = 2 atm, PCO2 = 30.185 mmHg, and PN2 = 1009.525 mmHg

1 mmHg = 0.00131579 atm

30.185 mmHg = 0.03972 atm

1009.525 mmHG = 1.3283 atm

Thus, PO2 = Ptotal - PCO2 - PN2

                   = 2 -  0.03972 - 1.3283

                   = 0.63198 atm

0.63198 atm = 480.3047 mmHg

In other words, the partial pressure of oxygen in the gas mixture would be 0.63198 atm or 480.3047 mmHg.

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The mass of the water that is formed by the oxygen is 216 g.

We know that we would have to look at the reaction equation and this would give us an idea on how to be able to use the stoichiometry of the reaction equation so as to solve the problem that we have at hand here.

Then we have;

Equation of the reaction; [tex]2H_{2} +O_{2} --- > 2H_{2}O[/tex]

Number of moles of the oxygen = 192 grams /32 g/mol

= 6 moles

If 1 mole of oxygen forms 2 moles of water

6 moles of oxygen would form = 6 * 2/1

= 12 moles of water

Mass of the water = 12 moles * 18 g/mol

= 216 g

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Answer:

the first statement is correct...

it only supports the main idea of the law of conservation of mass...

hope I can help you...

The study of basic properties and behavior of matter is known as chemistry. It is a branch of natural science that studies everything from the atoms, molecules, and ions that make up a compound to the elements that make up matter:their composition,structure,characteristics, behavior, and what happpens when they interact.

Cooking is essentially a chemistry experiment. It's likely that you'll become a better cook if you comprehend the chemical processes involved in raising baked items, neutralizing acidity, or thickening sauces.  Information on petroleum, product recalls, pollution, the environment, and technological advancements.

Your understanding of the world around you is aided by chemistry. Environmental contamination is without a doubt a major issue on a global scale. But how does it impact Earthly life? Basic chemical knowledge is necessary to comprehend how environmental contamination affects both living things and the atmosphere.

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The naturally occurring the element x exists in three isotopic forms. The average atomic weight of x 28.544 amu.

Given that :

x- 28, Abundance % = 67.14 % = 0.6714

The atomic mass = 27.343 amu

x-29, Abundance % = 10.50 % = 0.1050

The atomic mass = 28.889 amu

x- 32, Abundance %  = 22.36 % = 0.2236

The atomic mass = 31.993 amu

The average atomic weight = ( 27.343 × 0.6714 ) + ( 28.889 × 0.1050) +

                                                          ( 31.993 × 0.2236)

                                                 = 18.358 + 3.0333 + 7.153

                                                 = 28.544 amu

Thus, the average atomic weight of naturally occurring element x exists in three isotopic forms 28.544 amu.

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The initial voltage of the electrochemical cell would be less than the voltage under standard conditions.

An electrochemical cell is a device that converts chemical energy into electrical energy, or vice versa, through a redox reaction. The voltage of an electrochemical cell can be determined by measuring the potential difference between the two half-cells that make up the cell. The voltage of an electrochemical cell is determined by the half-cell potentials and the concentration of the ions in the solutions. The half-cell potential of a metal is the potential of a metal electrode in a solution of its ions at standard conditions, which is defined as a concentration of 1 M and a temperature of 25°C. In the case of zinc, the half-cell potential is -0.76 V, and for copper, the half-cell potential is +0.34 V. In the given cell, one half-cell is made of a strip of pure zinc in 500 milliliters of 0.10 M ZnCl2 solution, and the other half-cell is made of a strip of pure copper in 500 milliliters of 0.010 M Cu(NO3)2 solution. The concentration of the ions in the solutions is not at the standard concentration of 1 M, which means that the voltage of the cell will be different from the standard voltage. A deviation from the standard concentration results in a deviation from the standard potential, with a lower concentration leading to a lower potential. Therefore, the initial voltage of the electrochemical cell would be less than the voltage under standard conditions because the concentrations of the ions in the solutions are not at the standard concentration of 1 M.

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All the statements given above are correct.

Atoms within resonance structures are the same. The species' structure is not accurately reflected by a single resonance structure.

A representation of a molecule or an ion called a resonance structure depicts several electron combinations that are not conceivable in a single, static structure.

Resonance hybrid refers to the actual structure of the molecule or ion, which is an average of the potential resonance structures.

Resonance structures are not different in terms of atoms, but rather in the arrangement of electrons.

Resonance structures vary, and no single resonance structure can fully capture the structure of an entire species.

The species that make up resonance structures have isomers.

The species could have any of these structures at any time since resonance forms quickly interconvert.

It is not real to have individual resonance shapes.

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Chloral hydrate is used as a hypnotic agent. It is metabolized in liver to form trichloroethanol and trichloroacetic acid.. So it is false that chloral hydrate is metabolized as formaldehyde.

Chloral hydrate is readily absorbed after oral administration and metabolized by alcohol dehydrogenase enzyme in liver. It is metabolized as trichloroethanol and trichloroacetic acid.  Trichloroethanol is the metabolite which results in all the pharmacological activity. Which is further metabolized as Trichloroethanol glucoronide and dichloroacetic acid.

Formaldehyde is toxic substance and it is metabolized in liver which has no association with chloral hydrate.

So it is false that chloral hydrate is metabolized to formaldehyde.

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a group electrons is called electon pair.

Answer:

B. electron pairs.

Explanation:

The balanced equation for the reaction of lithium and bromine to produce lithium bromide is:

Li + Br2 → LiBr

The total mass of the reactants and products must be equal in order for the rule of conservation of mass to apply. As a result, we can determine the mass of the other reactant and product if we know the mass of one reactant and one product.

In this instance, we are aware that the initial concentrations of the reactants are 25.0 g of lithium and 25.0 g of bromine. Lithium has a molar mass of 6.939 g/mol, while bromine has a molar mass of 159.808 g/mol. So that we may convert each substance's mass to a unit of moles:

Li: 25.0 g / 6.939 g/mol = 3.6 moles

Br2: 25.0 g / 159.808 g/mol = 0.156 moles

We can then convert the moles back to grams using the molar mass of each substance:

Li: 3.6 moles x 6.939 g/mol = 24.96 g

LiBr: 3.6 moles x (6.939 g/mol + 159.808 g/mol) = 627.38 g

Br2: 0.156 moles x 159.808 g/mol = 24.96 g

So, when the reaction is complete, we have 24.96 g of lithium, 24.96 g of bromine, and 627.38 g of lithium bromide.

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Atomic mass of elements can change. The elements with same atomic number, but have different atomic mass or mass number is called an isotopes.

Atomic number of an element does not change. However variations in their atomic masses can happen. Atomic mass is the sum of protons and neutrons in the nucleus. Number of protons does not change, but number of neutrons can vary and such element occur in nature or can be laboratory made and are called isotopes.

There are 3 isotopes for hydrogen. Protium has an atomic number of 1 mass mass number 1 (meaning only one proton in the nucleus and no neutrons). Deuterium have an atomic number 1 and atomic mass 2 ( 1 proton and 2 neutrons). Tritium with atomic number 1 and atomic mass 3( 1 proton and 2 neutrons).

        ₁H¹                  ₁H²                  ₁H³

 Protium          Deuterium        Tritium

So atomic mass can vary in elements.

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A gas occupies a volume of 14. 5 L at 230 K. Option (C), 17.4 K will the temperature be it the gas expands to 21.8 L.

The relationship between the temperature, volume, and pressure of a gas is described by the ideal gas law, PV = nRT, where P is the pressure, V is the volume. We are given the initial volume and temperature of the gas and we are asked to find the final temperature when the gas expands to a different volume. The ideal gas law is an equation of state of a gas, which describes the relationship between the pressure, volume, and temperature of a gas. We are given V1, T1, and V2. The number of moles and pressure are not given so we can consider them constants.

The equation is :

V1/T1 = V2/T2

T2 = T1(V1/V2)

T2 = 230 K (14.5L / 21.8L) = 17.4 K

So the temperature will be 17.4 K if the gas expands to 21.8L.

Therefore, the correct answer is 17.4 K (Option C).

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Complementary angles are two angles whose sum is 90 degrees.

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Carbon dioxide and water combine to form glucose and oxygen (C6H12O6).

Reaction C6H12O6+6O26CO2+6H2O C 6 H 12 O 6 + 6 O 2 → 6 C .

The equation for aerobic respiration is O 2 + 6 H 2 O, which is an oxidation or combustion reaction.

Carbon atom balance

6CO 2 +H 2 O C   6 H 12 O 6 +O 2

Equilibrate the hydrogen atom.

6CO 2 +6H 2 OC  6 H 12 O 6 +O2

The oxygen atom must be balanced.

6CO 2 + 6H 2 O + C  6 H 12 O 6 + 6O 2

The chemical formula for equilibrium is thus:

6CO 2 + 6H 2 O + C 6 H 12 O 6 + 6O 2.

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​

The experimental evidence that led Rutherford to develop his atomic model is; from a gold foil, alpha particles were shown to disperse backward.

Alpha particles were seen to disperse in the opposite direction after being emitted from a gold foil in the now-famous experiment. In his explanation, which he published in May 1911, Rutherford proposed that the dispersion was brought about by a rigid and compact core at the center of the atom known as the nucleus.

The reasoning that went into developing the atomic model was that the only way that alpha particles could be deflected at enormous angles as if they were impacting on a dense opaque region, and this dense region was located at the center of each atom.

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The molality of the solvent does not change as a function of temperature. Molality is a concentration unit that is unaffected by temperature, it is utilised in this project in place of molarity.

Molality, which is determined by the number of moles of solute per kilogram of solvent, is a unit used to describe the concentration of a solute in a solution. It has units of moles per kilogram (mol/kg) and is generally represented by the letter "m".

Since molality is a concentration unit that is unaffected by temperature, it is utilised in this project in place of molarity. The amount of moles of solute per kilogram of solvent is referred to as molality. The molality of the solvent does not change as a function of temperature because the solvent's volume does not. The amount of moles of solute per litre of solution, on the other hand, is referred to as molarity. The molarity fluctuates with temperature in the same way as the solvent's volume does.

In general, the difference between molarity and molality is greater when the concentration of a solution is high. For a solution with the same concentration, molality is almost always greater than molarity.

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A chemist must dilute the 67.3 ml of the 341 mM of aqueous copper(ii) sulfate solution until the concentration falls to 256 mM is 89.6 mL.

The initial concentration, C1 = 341 mM

The final volume, V1 = 67.3 mL

The final concentration, C2 = 256 mM

The final volume, V2 = ?

By adding the distilled water to the solution until it will reaches a certain final volume :

The expression is given as :

C1 V1 = C2 V2

V2 = C1 V1 / C2

V2 = ( 341 × 67.3 ) / 256

V2 = 89.6 mL

Thus, the final volume in milliliters is 89.6 mL.

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