How many moles of chlorine could be produced by decomposing 157g NaCl? 2NaCl --> 2Na+Cl2

Answers

Answer 1
Here is the answer for your question which the mole of chlorine is 1.34
How Many Moles Of Chlorine Could Be Produced By Decomposing 157g NaCl? 2NaCl --> 2Na+Cl2
Answer 2

By decomposing 157g of NaCl, approximately 1.35 moles of chlorine can be produced.

To determine the number of moles of chlorine that could be produced by decomposing 157g of NaCl, we need to use the molar mass of NaCl and apply stoichiometry.

The molar mass of NaCl is the sum of the atomic masses of sodium (Na) and chlorine (Cl), which is approximately 22.99 g/mol + 35.45 g/mol = 58.44 g/mol.

Now, we can calculate the number of moles of NaCl:

Moles of NaCl = Mass of NaCl / Molar mass of NaCl

Moles of NaCl = 157 g / 58.44 g/mol

Moles of NaCl ≈ 2.69 mol

According to the balanced equation 2NaCl → 2Na + Cl₂, we can see that for every 2 moles of NaCl, we produce 1 mole of Cl₂.

Therefore, using the stoichiometric ratio, we can calculate the number of moles of chlorine produced:

Moles of Cl₂ = (Moles of NaCl / 2) × 1

Moles of Cl₂ = 2.69 mol / 2

Moles of Cl₂ ≈ 1.35 mol

Thus, by decomposing 157g of NaCl, approximately 1.35 moles of chlorine can be produced.

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Why was the war in Peru difficult?

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Answer:

in contrast, peru and Bolivia entered the war hindered by numerous domestic fractures and by an economic and insititutional backwardness that nearly prevented the two countries from fighting the war at all

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Explanation:

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Write the symbol for every chemical element that has atomic number less than 13 and atomic mass greater than 17.2 u.

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Answer:

c.boron-11

Explanation:

The atomic mass of boron is 10.81 u.

And 10.81 u is a lot closer to 11u than it is to 10u, so there must be more of boron-11.

To convince you fully, we can also do a simple calculation to find the exact proportion of boron-11 using the following formula:

(10u)(x)+(11u)(1−x)100%=10.81u

Where u is the unit for atomic mass and x is the proportion of boron-10 out of the total boron abundance which is 100%.

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11u−ux=10.81u

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The N2O decomposition, 2 N2O (g) → 2 N2 (g) + O2 (g), is a zero order reaction that has a reaction rate constant of 2.00 × 10−3 M/s. Initially, 2.00 moles of N2O gas are infused into a 1.00 L vessel at 300. K.Calculate the pressure inside the vessel at 100. seconds after the start of the reaction. Temperature is held constant.

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Answer:

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Answer:

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Answer:

Needle and Scale Leaves. This kind of leaves are mostly found in 'evergreen' trees. ...

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Explanation:

Answer:

Broad

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Answers

Answer:

Because of the two different parts of the molecule, a soap molecule is soluble in water and at the same time can dissolve fats. The fats are attracted to the non-polar tail part of the soap while the polar head makes the whole complex.

Explanation:

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At a certain temperature, the equilibrium pressures of NO2 and N2O4 are 1.4 bar and 0.46 bar, respectively. If the volume of the container is doubled at constant temperature, what would be the partial pressures of the gases when equilibrium is re-established?

Answers

The partial pressure of NO₂ at equilibrium is 0.70 bar and the partial pressure of N₂O₄, at equilibrium is 0.23 bar.

Let x be the mole fraction of NO₂ and x' be the mole fraction of N₂O₄.

The total pressure according to Dalton's law of partial pressure is the sum of the partial pressures of each gas.

Let P be the total pressure of the gases, P' be the partial pressure of NO₂ = 1.4 bar and P" be the partial pressure of N₂O₄ = 0.46 bar.

So, P = P' + P"

= 1.4 bar + 0.46 bar

= 1.86 bar

Since P' = xP

x = P'/P

= 1.4 bar/1.86 bar

= 0.753

Also, P" = xP

x' = P"/P

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= 0.247

Now, since the volume of the container is doubled at constant temperature, we use Boyle's law to determine the new pressure. P₁.

Boyle's law states that the pressure of a given mass of gas is inversely proportional to its volume provided the temperature remains constant. It is written mathematicaly as PV = constant

So, PV = P₁V₁

P₁ = (V/V₁)P

Since V/V₁ = 1/2

P₁ = (V/V₁)P

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So, the new partial pressure of NO₂, P₂ = xP₁

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The new partial pressure of N₂O₄, P₃ = x'P₁

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= 0.23 bar

So, the partial pressure of NO₂ at equilibrium is 0.70 bar and the partial pressure of N₂O₄, at equilibrium is 0.23 bar.

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Answer:

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Explanation:

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Answers

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Answer:

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а
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b
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с
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d
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e
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Answers

Answer:

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Answers

Explanation:

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Answers

Answer:

sensory experience of a chemical reaction called combustion. In a way, fire is like the leaves changing color in fall, the smell of fruit as it ripens, or a firefly's blinking light. All of these are sensory clues that a chemical reaction is taking place

Explanation:

Sensory encounter with the combustion chemical process. Fire can be compared to the fall foliage's shifting hues, the aroma of ripe fruit, or the blinking light of fireflies. These are all sensory indicators that a chemical reaction is occurring.

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not during a phase change: temperature rises


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Gases fill their container, showing that gas particles are strongly attracted through electrostatic forces.
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Gases fill their container, showing that gas particles are not tied together and can move far apart.
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Answers

Answer:

1) during a phase change: particles overcome forces of attraction and temperature stays the same not during a phase change: temperature rises 2)Particle motion decreases, and electrostatic forces pull particles closer together.

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Explanation:

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Answer:

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Answer:

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Answers

Answer:

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calculate the number of molecules in 4.48dm3 of hydrogen at STP​

Answers

Answer: 1 more of hydrogen =22.4dm3

X moles of hydrogen =4.48dm3

22.4dm3x = 4.48dm3

4.48dm3\22.4dm3

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Answers

Answer:

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Answers

Answer:

because those are the only thermometers that are truly accurate for kelvins

Explanation:

The Kelvin temperature in thermometers is used by scientists because it provides a temperature where zero indicates the complete absence of thermal energy.

What is the Kelvin scale?

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