How long would it take to travel 50 km traveling at a speed of 10 km/hr

Answer:

1030.3504 units

Explanation:

Disk radius = 7 inches

Density at distance x = p(x) = [tex]\sqrt{10x}[/tex]

Calculate the mass of the two-dimensional object

M = 2[tex]\pi[/tex][tex]\sqrt{10} * (\frac{2}{5} ) *(7)^{\frac{5}{2} }[/tex] = 1030.3504 units

Answer:

A.No. Assuming no other factors (such as air resistance) the first object will have a velocity of 32 feet/second when the other is dropped. Since they will both have the same acceleration, the first distance between them will increase by 32 feet per second.

Explanation:

Answer:

noun. a person who is connected with another or others by blood or marriage. something having, or standing in, some relation or connection to something else. something dependent upon external conditions for its specific nature, size, etc. (opposed to absolute).

Answer:

The value of q is [tex]\dfrac{Q}{8}[/tex]

Explanation:

Given that,

Each charge = -Q

Distance between charges = L

Reduced force = [tex]\dfrac{F}{2}[/tex]

Suppose, Two particles each with a charge -Q are fixed a distance L apart as shown above. Each particle experiences a net electric force F. A particle with a charge +q is now fixed midway between the original two particles.

We know that,

The force on each end is

[tex]F=\dfrac{kQ^2}{L^2}[/tex]...(I)

If the charge q is placed at mid point then

The  force on each end charge is

[tex]\dfrac{F}{2}=F+F'[/tex]....(II)

We need to calculate the value of q

Using equation (II)

[tex]\dfrac{F}{2}=F+F'[/tex]

Put the value of F into the formula

[tex]\dfrac{\dfrac{kQ^2}{L^2}}{2}=k\dfrac{Q^2}{L^2}+k\dfrac{q\times(-Q)}{(\dfrac{L}{2})^2}[/tex]

[tex]\dfrac{kq(-Q)}{(\dfrac{L}{2})^2}=-\dfrac{kQ^2}{2L^2}[/tex]

[tex]\dfrac{q}{\dfrac{1}{4}}=\dfrac{Q}{2}[/tex]

[tex]q=\dfrac{Q}{8}[/tex]

Hence, The value of q is [tex]\dfrac{Q}{8}[/tex]

Answer: IM 95%sure that the answer is B jus took the test got the answer right

Explanation:

Answer:

sorry I forgot I wish I could help

Answer:

1,839.375 Joules

Explanation:

Work is said to be done is the force applied to an object cause the object to move through a distance.

Workdone = Force * Distance

Workdone = mass * acceleration due to gravity * distance

Given

Mass = 75.0kg

acceleration due to gravity = 9.81m/s²

distance = 2.50m

Substitute the given parameters into the formula:

Workdone = 75.0*9.81*2.50

Workdone = 1,839.375Joules

Hence the workdone is 1,839.375 Joules

Answer:

The spring constant is 3.44x10⁶ kg/s².

Explanation:

We cand find the spring constant by conservation of energy:

[tex] E_{i} = E_{f} [/tex]

[tex] mgh = \frac{1}{2}kx^{2} [/tex]   (1)

Where:

m is the mass =  41700 kg

g is the gravity = 9.81 m/s²

h is the height = 2.65 m

x is the distance of spring compression = 79.4 cm

k is the spring constant =?

Solving equation (1) for k:

[tex]k = \frac{2mgh}{x^{2}} = \frac{2*41700 kg*9.81 m/s^{2}*2.65 m}{(0.794 m)^{2}} = 3.44 \cdot 10^{6} kg/s^{2}[/tex]              

Therefore, the spring constant is 3.44x10⁶ kg/s².

I hope it helps you!

Answer:

40

Explanation:

Answer:

[tex]200.38^0[/tex]

Explanation:

Given the forces:

F1 = 8.92 i + 17.37 j

F2 = 8.31 i - 10.97 j

If a third vector is added to them such that they add up to to the null vector as F1 + F2 + F3 = 0

then to get F3:

F3 = -F2-F1

F3 = -(8.31 i - 10.97 j)-(8.92 i + 17.37 j )

F3 = -8.31 i + 10.97 j-8.92 i - 17.37 j

F3 = -8.31i-8.92i+10.97j-17.37j

F3 = -17.23i-6.4j

from the vector:

x = -17.23 and y = -6.4

angle of the third vector with respect to the +x-axis is expressed as:

[tex]\theta = tan^{-1}\frac{y}{x}\\ \theta = tan^{-1}\frac{-6.4}{-17.23}\\\theta = tan^{-1}0.3715\\\theta = 20.38^0[/tex]

Hence the angle the vector makes with the x axis will be [tex]\theta = 180+20.38 = 200.38^0[/tex]

Answer:

Explanation:

The work done by an object can be found by using the formula

From the question

force = 290 N

distance = 5 m

We have

workdone = 290 × 5

We have the final answer as

Hope this helps you

Answer:

D

Explanation:

Answer:

c.4s

Explanation:

Answer:

v₁f = -6.2 cm/s

Explanation:

        [tex]m_{1} *v_{1o} = m_{1}* v_{1f} + m_{2}* v_{2f}[/tex]

       [tex]\frac{1}{2}*m_{1}*v_{1o}^{2} = \frac{1}{2}*m_{1}*v_{1f} ^{2} + \frac{1}2}*m_{2}*v_{2f}^{2}[/tex]

       [tex]v_{1f} = \frac{-m_{1} }{3*m_{1}} *v_{1o} =\frac{-v_{1o}}{3} = -\frac{18.6 cm/s}{3} = -6.2 cm/s[/tex]

Answer:

t = 5.77 s

Explanation:

This exercise will use Newton's second law for rotational motion

            τ = I α

             α = τ / I

             α = 66/175

             α = 0.3771   rad/s²

now we can use the rotational kinematics relations, remember that all angles must be in radians

            θ = 1 rev = 2π radians

            θ = w₀ t + ½ α t²

as the wheel starts from rest w₀ = 0

             t = √ (2θ/α)

let's calculate

             t = √ (2 2π / 0.3771)

             t = 5.77 s

Answer:

The value is [tex]n=  9.375 *10^{15} \  electrons [/tex]

Explanation:

From the question we are told that

  The average current is  [tex]I  =  25.0 \mu A = 25.0 *10^{-6} \  A[/tex]

Generally the quantity of charge (electron )  is mathematically represented as

       [tex]Q =  ne[/tex]

Here e is the charge on a single electron with value [tex]e = 1.60  *10^{-19} \  C[/tex]

   Generally current is mathematically represented as

     [tex]I  = \frac{Q}{t}[/tex]

=>   [tex]I  = \frac{ne}{t}[/tex]

Here t is time which is given as 1 minutes =  60  seconds

  and  n is the number of electrons

So

      [tex]25.0 *10^{-6}  = \frac{ n* 1.60  *10^{-19}}{60}[/tex]

=>    [tex] 60  * 25.0 *10^{-6} =  n* 1.60  *10^{-19}  [/tex]

=>    [tex]n=  \frac{60  * 25.0 *10^{-6} }{ 1.60  *10^{-19} }[/tex]

=>    [tex]n=  9.375 *10^{15} \  electrons [/tex]

The number of electrons that strike the screen every minute is; n = 9.375 × 10¹⁵ electrons

We are given;

Average Current; I = 25 μA = 25 × 10⁻⁶ A

Formula for the current is;

I = Q/t = ne/t

where;

n is number of electrons

e is electron charge = 1.6 * 10⁻¹⁹ C

t is time = 1 minute = 60 seconds

Thus making n the subject gives;

n = It/e

n = (25 × 10⁻⁶ * 60)/(1.6 * 10⁻¹⁹)

n = 9.375 × 10¹⁵ electrons

Read more about number of electrons at; https://brainly.com/question/11406294

Answer:acbd

Explanation:

Answer:

The force is [tex]F_b =  216 \  N [/tex]

Explanation:

From the question we are told that

   The  mass of the bungee jumper is  m  = 80 kg

    The spring constant is  [tex]k = 20 \ N/ m[/tex]

    The extension of the rubber bungee cords is  x = 50 m

Generally the weight of the jumper is

      [tex]W =  m *  g[/tex]

=>   [tex]W =  80 *  9.8 [/tex]

=>   tex]W =  784  \  N  [/tex]

Generally  the returning force of the rubber bungee cords is mathematically represented as

      [tex]F  =  k  *  x[/tex]

=>     [tex]F  =  20   * 50 [/tex]

=>     [tex]F  =  1000 \  N [/tex]

The force to be applied by the bear is

    [tex]F_b =  F -  W[/tex]

=>    [tex]F_b =  100 -  784[/tex]

=>  [tex]F_b =  216 \  N [/tex]

Answer:

What do you mean ma´am/sir?

Explanation:

Answer:

3.2

Explanation:

I hope that this helps! Have a good day!!

Answer:

Biology

Physics

Chemistry

Explanation:

Biology (life like cells, human reproduction, etc.)

Physics (Studies forces, like gravity.)

Chemistry (studies the atoms, the elements, etc.)

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is  B

Explanation:

   The number  of alphabet is  n= 4  (a , b , c , d )

Generally the total  number of  string of length 10 over the 4 alphabets is  

     [tex]N  =  4^{10}[/tex]

Gnerally the number of string of length 10 that does not include b is  

     [tex]T =  3^{10}[/tex]    

Generally the number of strings of length 10 over the 4  alphabets that have at least one alphabet b  somewhere in the string is  

        [tex]G  =  N - T[/tex]

=>    [tex]G  =  4^{10} -  3^{10}[/tex]

Answer:

m₁ = 70 lb

Explanation:

Here we will use the law of conservation of momentum:

m₁u₁ + m₂u₂ + m₃u₃ = m₁v₁ + m₂v₂ + m₃v₃

where,

m₁ = mass of first suitcase = ?

m₂ = mass of second suitcase = 30 lb

m₃ = mass of baggage carrier = 50 lb

u₁ = initial speed of first suitcase = 7.2 ft/s

u₂ = initial speed of second suitcase = 7.2 ft/s

u₃ = initial speed of baggage carrier = 0 ft/s

v₁ = Final speed of first suitcase = 4.8 ft/s

v₂ = Final speed of second suitcase = 4.8 ft/s

v₃ = Final speed of baggage carrier = 4.8 ft/s

because after collision all three will have same speed

Therefore,

(m₁)(7.2 ft/s) + (30 lb)(7.2 ft/s) + (50 lb)(0 ft/s) = (m₁)(4.8 ft/s) + (30 lb)(4.8 ft/s) + (50 lb)(4.8 ft/s)

(m₁)(7.2 ft/s) + (216 lb ft/s) + (0 lb ft/s) = (m₁)(4.8 ft/s) + (144 lb ft/s) + (240 lb ft/s)

(m₁)(7.2 ft/s) - (m₁)(4.8 ft/s) = 168 lb ft/s

m₁ = (168 lb ft/s)/(2.4 ft/s)

m₁ = 70 lb

Answer:

b

Explanation:

Answer:

hi

Explanation:

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Answer:

The region where an electron is most likely to be is called an orbital. Each orbital can have at most two electrons. Some orbitals, called S orbitals, are shaped like spheres, with the nucleus in the center.

Explanation:Hope this helps :)

By definition, a region around the nucleus of an atom where electrons are likely to be found​ is called an orbital.

First of all, an atom is the smallest constituent unit of ordinary matter that has the properties of a chemical element.

All atoms are made up of subatomic particles: protons and neutrons, which are part of their nucleus, and electrons, which revolve around them. Protons are positively charged, neutrons are neutrally charged, and electrons are negatively charged.

In other words, every atom consists of a nucleus in which neutrons and protons meet and energy levels where electrons are located.

This is, the atomic nucleus is the central part of the atom that is made up of protons and neutrons, while the orbitals or peripheral region is an area where electrons are found.

In summary, a region around the nucleus of an atom where electrons are likely to be found​ is called an orbital.

Learn more:

Answer and Explanation:

TL: DR The Sun is much more massive than Neptune — more than enough to make up for the somewhat smaller distance between the two planets at the closest approach.

[The surprise in this answer (to me, a non-astronomer), is that the gap between the orbits of Neptune and Uranus is large — half the distance from Uranus to the Sun.]

The ratio of gravitational attraction of the Sun on Uranus versus Neptune on Uranus is directly proportional to the ratio of the Sun’s mass to Neptune’s and inversely proportional to the ratio of the square of the distances (let’s use the closest approach of the two planets to one another to calculate a maximum attraction).

Numbers:

Sun’s mass: 2 x 10^30 kg

Neptune’s mass: 1 x 10^26 kg

Distance of Sun to Uranus: 3 x 10^9 km

Closest approach of Uranus and Neptune: 1.5 x 10^9 km

Without doing any arithmetic, we see that even at their closest approach, Uranus and Neptune are separated by about one-half of the Uranus to Sun distance. Squaring that ratio, we see that if the Sun and Neptune had the same mass, the attraction between the Sun and Uranus would only be about 1/4 of that between the Sun and Neptune; however, the Sun has 20000 times the mass of Neptune, so the attraction between Uranus and the Sun is about 5000 times stronger than the maximum attraction between Uranus and Neptune.

The explanation of the possibility of why sun exerts a greater force on Uranus than Neptune exerts on Uranus is; because the force was calculated to be greater.

The formula for calculating the Force of Gravity between two masses is:

F = G*m₁*m₂/r²

Where;

F = force of gravity

G = gravitational constant = 6.674 × 10⁻¹¹ N•m²/kg²

m₁ = mass of the larger object

m₂ = mass of the smaller object

r = the distance between the centers of the two masses

Now, from online values, we have the following;

mass of Neptune; m₁ =  102.413 × 10²⁴ kg

mass of Uranus; m₂ = 86.813 × 10²⁴ kg

average distance between the centers of Neptune and Uranus; r = 1.62745 × 10¹² m

Thus, force exerted by Neptune on Uranus is;

F = (6.674 × 10⁻¹¹ × 102.413 × 10²⁴ × 86.813 × 10²⁴)/(1.62745 × 10¹²)²

F = 2.240 × 10¹⁷ N

We are told that the force the Sun exerts on Uranus is 1.41 the force the Sun exerts on Uranus is 1.41 × 10²¹ N.

That is greater than the force Neptune exerts on Uranus.

Read more about Force of Gravity at; https://brainly.com/question/7281908

The answer is A I Hope this answer helps you (i got the question right)

Answer:

A. As speed increases, kinetic energy increases exponentially.

Explanation:

The amount of kinetic energy an object has depends on the speed. Kinetic energy is also known as "motion energy." This being said, if speed is increasing, decreasing, or staying constant, the kinetic energy of the object will too.

Answer:

25.  Approximately 8.1 meters

26. North 1.31 km, and East 2.81 km

Explanation:

25.

Notice that the displacements: 6 meters east and 5.4 south create the legs of a right angle triangle. The hypotenuse of that triangle will be the distance (d) needed to cover in order to get the ball in the hole in one putt. That is:

[tex]d=\sqrt{6^2+5.4^2} =\sqrt{65.16} \approx 8.072\,\,\,m[/tex]

which can be rounded to 8.1 m.

26.

Notice that the 3.1 km at an angle of 25 degrees north of east, is the hypotenuse of a right angle triangle that has for legs the east and north components of that distance.

We can find the leg corresponding to the east displacement using the cosine function (that relates adjacent side with hypotenuse):

[tex]east\,\, comp=3.1 * cos(25^o)\approx 2.809\,\,km[/tex]

and we can calculate the north component using the sine function that relates the opposite side to the angle with the hypotenuse.

[tex]north\,\,component = 3.1 * sin(25^o) \approx 1.31 \,\,km[/tex]

Answer:

y(i) = h

v(y.i) = 0

Explanation:

See attachment for elaboration