It would take the runner approximately 10,268.29 seconds (or about 2 hours, 51 minutes, and 8 seconds) to complete a marathon race of 42.2 km, maintaining an average speed of 4.1 m/s.
We can use the formula:
time = distance ÷ speed
to calculate the time it would take the runner to complete a marathon race of 42.2 km, given an average speed of 4.1 m/s.
First, we need to convert the distance to meters, as the speed is given in meters per second:
42.2 km = 42,200 m
Now, we can substitute the values into the formula:
time = distance ÷ speed
time = 42,200 m ÷ 4.1 m/s
time ≈ 10,268.29 s
Thus the time that the runner would take is 10,268.29 seconds to complete a marathon race.
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Two spheres have identical charges and are 0. 012 m apart. The force between them is +0. 32 N. What is the magnitude of the charge on each sphere?
Two spheres have identical charges and are 0. 012 m apart. The force between them is +0. 32 N. the magnitude of the charge on each sphere is approximately 2.14 × 10^-6 C.
The force (F) between two charged spheres with charges q1 and q2, separated by a distance r, is given by Coulomb's law:
F = (1/4πε₀) * (q1*q2/r^2)
where ε₀ is the electric constant.
In this problem, we are given the following information:
The charges on the two spheres are identical, i.e., q1 = q2 = q
The distance between the spheres is r = 0.012 m
The force between the spheres is F = +0.32 N
Using Coulomb's law, we can write:
q^2 = (F * r^2)/(1/4πε₀)
We know the value of F, r, and ε₀, so we can substitute these values to calculate q:
q^2 = (0.32 N * (0.012 m)^2)/(1/4πε₀)
q^2 = 4.57 × 10^-9 C^2
Taking the square root of both sides, we get:
q = ±2.14 × 10^-6 C
Since the charges are identical, we take the positive value of q, which gives:
q = 2.14 × 10^-6 C
Thus the value is, 2.14 × 10^-6 C.
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Categorize each scenario according to whether or not work is done on the object. Work is not done Work is done on the locked door that remains closed while you try to pull it open on the door as you push against it and open it pull a tablecloth out from under them and they remain in place on the dishes when you on boxes as you lift them and place them on the shelf on a shopping cart as you push it around the store on the piano when you drop it from the thind floor to the ground floor on the bowling ball that you are holding while waiting for your turn to bowl
Work is done on the boxes as we push it around the store and on the piano when we drop it from the third floor and work is not done on the locked door, on the dishes and on the bowling ball.
The work done is given by the dot product of the displacement and the force,
W = F.d
W = FdcosA, A is the angle at which the force is applied.
In the first scenario, the work is not done on the locked door that remains closed while we try to pull it open on the door as we push against it and open it, because there is no displacement.
Work in not done to pull a tablecloth out from under them and they remain in place on the dishes, because no displacement of the dishes.
Work is done on boxes as we lift them and place them on the shelf on a shopping cart as we push it around the store because displacement happened.
Work is done on the piano when we drop it from the third floor to the ground floor because A = 0 degrees.
Work is not done on the bowling ball that we are holding while waiting for our turn to bowl because A = 90 degrees.
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thirty 6kg boxes lifted on to ashelf 1.5m height what is the total work
We must first determine the amount of force needed to lift the boxes against gravity. The weight of the boxes is calculated as follows: 30 boxes x 6 kg/box = 180 kg
Work = Force x Distance Work = 1765.8 N x 1.5 m Work = 2648.7 Joules Force = Weight x Gravitational Acceleration Force = 180 kg x 9.81 m/s2 Force = 1765.8 N
The total work required to raise thirty 6 kilogram boxes onto a 1.5 m high shelf is therefore 2648.7 Joules.
How can the gravitational pull of a planet be strengthened?Hence, the gravitational pull between two objects grows as their respective masses do as well. The force of gravity between two objects is equal to their respective masses multiplied by two. To put it another way, the gravitational potential energy directly relates to how high an item is above the earth. Consequently, an item needs be elevated higher in order to enhance its gravitational potential energy. The gravitational potential energy increases with height.
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How do this ? I don’t know. I need help
Answer:
inductance and genorator
Explanation:
Inductance is the tendency of an electrical conductor to oppose a change in the electric current flowing through it. The flow of electric current creates a magnetic field around the conductor. The field strength depends on the magnitude of the current, and follows any changes in current.
in which electrical wave changed into mechanical wave
Currently, electricity is the form of energy we use most in our daily lives. This means we are always using energy resources that can be transformed to electrical energy. You are an electrical engineer exploring different resources for producing electricity while also making sure to pick resources that are least harmful to the environment. Create a PowerPoint to include the below information:
1. What are the disadvantages of using fossil fuels for producing electricity?
2. Why do we depend so heavily on fossil fuels to produce electricity even when they cause air pollution?
3. Which energy resources seem to be the least harmful for the environment (this includes harmful to air, water, or living things)? Explain how you reached this conclusion.
4. Renewable energy resources affect the environment as well. Pick one renewable energy resource and describe how and why it affects the environment.
Answer:
1. The disadvantages of using fossil fuels for producing electricity include their contribution to air pollution and climate change, their finite supply, and the environmental damage caused by their extraction and transportation.
2. We depend heavily on fossil fuels to produce electricity because they are relatively cheap and abundant, and because our infrastructure is largely built around their use. Additionally, many people may not be aware of the negative environmental impacts of fossil fuel use or may not have access to alternative energy sources.
3. Renewable energy resources, such as solar, wind, and hydropower, are generally considered to be the least harmful to the environment because they produce little to no greenhouse gas emissions or other pollutants. Additionally, they do not require mining or drilling for fuel, and they do not produce toxic waste. However, the environmental impact of renewable energy sources can vary depending on factors such as the location of the power generation facilities and the materials used in the production of renewable energy technologies.
4. One renewable energy resource that affects the environment is hydropower. While hydropower is a clean and renewable energy source, it can have significant environmental impacts, particularly on aquatic ecosystems. The construction of dams and other hydropower facilities can alter river flows and disrupt fish migration patterns, and the flooding of large areas for reservoirs can displace communities and cause other ecological disruptions. Additionally, the decommissioning of hydropower facilities can also have environmental impacts, such as the release of sediment and other materials that have accumulated behind the dams. To mitigate these impacts, it is important to carefully consider the location and design of hydropower facilities and to prioritize ecological considerations in the planning and implementation of hydropower projects.
Hope this helps you! If not, I'm sorry! If you need more help, ask me! :]
80% of the heat supplied to a 30g block of ice at 0°c completely melt it to water 0°C. Calculate the total heat energy supplied=336jg^-1k
Given: mass of ice = 30g, specific heat of ice = 336 Jg^-1K^-1, specific heat of water = 4186 Jg^-1K^-1
Let x be the heat energy supplied to melt the ice. Heat energy required to raise the temperature of 30g of ice from 0°C to 0°C (its melting point) is given by: Q1 = mass x specific heat of ice x change in temperature, Q1 = 30g x 336 Jg^-1K^-1 x (0 - 0) = 0 J. Since 80% of the heat supplied completely melts the ice, the remaining 20% of the heat energy supplied is used to raise the temperature of the melted ice (now water) from 0°C to 0°C: Q2 = 0.2 x total heat energy supplied, Q2 = 0.2 x x. The total heat energy supplied is given by: total heat energy supplied = Q1 + Q2, x = (total heat energy supplied - Q1)/0.2, x = (336 Jg^-1K^-1 x 30g - 0)/0.2
x = 201600 J. Therefore, the total heat energy supplied to melt the ice completely to water at 0°C is 201600 J.
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What is the crossover point in miles between the hybrid vehicle and the alternative vehicle from a competing auto manufacturer? Hybrid Vehicle Vehicle Purchase Cost $18 comma 000 Vehicle Operating Cost per Mile $0. 14 Useful Life of Vehicle 14 years Miles per Year 16 comma 500 Miles per Gallon 33 Average Fuel Price per Gallon $3. 68 Alternative Vehicle Vehicle Purchase Cost $20 comma 000 Vehicle Operating Cost per Mile $0. 10 Useful Life of Vehicle 14 years Miles per Year 16 comma 500 Miles per Gallon 36 Average Fuel Price per Gallon $3. 68 The crossover point, M, is nothing miles (round your response to the nearest whole number)
The crossover point is 56,000 miles, rounded to the closest whole number. The total cost of owning the hybrid vehicle and the alternative vehicle is the same at this point.
The formula for the total cost is :
Total Cost = Vehicle Purchase Cost + (Operating Cost per Mile x Miles per Year x Useful Life of Vehicle)/Miles per Gallon x Average Fuel Price per Gallon
For the hybrid vehicle:
Total Cost = $18,000 + ($0.14 x 16,500 x 14)/33 x $3.68 = $47,672.03
For the alternative vehicle:
Total Cost = $20,000 + ($0.10 x 16,500 x 14)/36 x $3.68 = $47,672.22
Solving these two equations for M gives :
$18,000 + ($0.14 x 16,500 x 14)/33 x $3.68 = $20,000 + ($0.10 x 16,500 x 14)/36 x $3.68
M = 55998
If the vehicle's expected mileage exceeds 56,000 miles, the alternative vehicle becomes more cost-effective; if it falls below 56,000 miles, the hybrid vehicle becomes more cost-effective.
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The car maintained distance x
Answer:
7th grade in a year and I am not going for the same as a student from a school year or so cute cat that I don't have a lot to get for it is the greatest thing I can think they are you at the end a bit too far from your home or the other one that is the only thing that is a bit more expensive and
Describe the differences between magnetic potential energy and electric potential energy
Magnetic potential energy and electric potential energy are both forms of potential energy associated with the interactions between magnetic or electric fields and charges or magnetic moments.
However, there are some important differences between these two forms of potential energy. Magnetic potential energy is associated with the interactions between magnetic fields and magnetic moments. It is a function of the relative orientation of the magnetic moment and the magnetic field. The magnetic potential energy of a system is proportional to the product of the magnetic moment and the magnetic field strength, and it is greatest when the magnetic moment is aligned with the magnetic field. Electric potential energy, on the other hand, is associated with the interactions between electric fields and charges. It is a function of the relative position of the charges and the strength of the electric field. The electric potential energy of a system is proportional to the product of the charges and the electric field strength, and it is greatest when the charges are separated by the greatest distance. In general, magnetic potential energy tends to be weaker than electric potential energy because magnetic fields are generally weaker than electric fields. However, in certain systems such as magnetic storage devices, magnetic potential energy can be harnessed and used to store and transmit information.
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A ball of mass m, moving at a velocity v, collides with a stationary ball of mass 2m. The two balls stick together. What is the fraction of the initial kinetic energy is lost on impact?
Answer:
67%
Explanation:
In the absence of external forces, the total momentum of the system before the collision is equal to the total momentum after the collision. Since the second ball is initially at rest, the total momentum before the collision is simply m*v.
After the collision, the two balls stick together and move with a common velocity, which can be calculated using conservation of momentum:
m*v + 0 = (m+2m) * v_final
Solving for v_final, we get:
v_final = v/3
The initial kinetic energy of the system is:
K_i = 0.5mv^2
The final kinetic energy of the system is:
K_f = 0.5*(3m)v_final^2 = 0.5(3m)(v^2/9) = 0.5m*v^2/3
The fraction of the initial kinetic energy lost on impact is:
( K_i - K_f ) / K_i = ( 1 - 1/3 ) = 2/3 = 0.67
Therefore, 67% of the initial kinetic energy is lost on impact.
A student performing simple pendulum 1.2 sec, 1.23 sec, 4. 18. sec, 1. 25 sec, suspectuly time period. Tume Value Absolute error of Mean absolute ervar Percentage a cerror an experiment note the time period for
Answer:
Based on the data provided, it seems that the student is measuring the time period of a simple pendulum. The measured time periods are:
1.2 sec
1.23 sec
4.18 sec
1.25 sec
To find the mean time period, we add up all the measured values and divide by the total number of measurements:
Mean time period = (1.2 + 1.23 + 4.18 + 1.25) / 4 = 2.215 sec
To find the absolute error of each measurement, we subtract the mean time period from each measurement and take the absolute value:
Absolute error of 1st measurement = abs(1.2 - 2.215) = 1.015 sec
Absolute error of 2nd measurement = abs(1.23 - 2.215) = 0.985 sec
Absolute error of 3rd measurement = abs(4.18 - 2.215) = 1.965 sec
Absolute error of 4th measurement = abs(1.25 - 2.215) = 0.965 sec
To find the mean absolute error, we add up all the absolute errors and divide by the total number of measurements:
Mean absolute error = (1.015 + 0.985 + 1.965 + 0.965) / 4 = 1.23 sec
To find the percentage error of each measurement, we divide the absolute error of each measurement by the mean time period and multiply by 100:
Percentage error of 1st measurement = (1.015 / 2.215) * 100 = 45.9%
Percentage error of 2nd measurement = (0.985 / 2.215) * 100 = 44.4%
Percentage error of 3rd measurement = (1.965 / 2.215) * 100 = 88.8%
Percentage error of 4th measurement = (0.965 / 2.215) * 100 = 43.6%
Note that the third measurement has a significantly larger percentage error compared to the other measurements, which suggests that it may be an outlier or there may have been some systematic error in that particular measurement. It is important to carefully analyze such outliers and repeated experiments to ensure accurate results.
For the flight of airplanes in the earth's atmosphere, the variation of acceleration of gravity with altitude is generally ignored. One of the highest-flying aircraft has been the lockheed u-2 (see fig. 2 5. 52) which was designed to cruise at 70,000ft. How much does the acceleration of gravity at this altitude differ from the value at sea level?
The Lockheed U-2 or other high-flying aircraft's performance is likely to be unaffected by this disparity.
At an altitude of 70,000ft, the acceleration of gravity is slightly lower than the value at sea level due to the decrease in distance from the center of the Earth. However, this difference is typically small and is often ignored for the flight of airplanes in the Earth's atmosphere. The difference in acceleration of gravity between sea level and 70,000ft is approximately 0.006 m/s^2 or 0.06% of the value at sea level.
Therefore, the effect of this difference on the flight of the Lockheed U-2 or other high-flying aircraft is likely to be negligible and can be safely ignored for practical purposes.
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A stone falls from rest from the top of high tower. Ignore air resistance and take g=9.8m/s squared, Calculate
a)the speed of the stone after 2 seconds
b)how far the stone has fallen after 2 seconds
A stone falls from rest from the top of high tower. Ignore air resistance and take g=9.8m/s squared, s = 30.625 m
What exactly is electrical resistance?Electrical resistance, which opposes the flow of current, is resistance to electricity. In this sense, it acts as a gauge for the difficulty of current flow. Ohms are a unit of measurement for resistance.
What are different forms of resistance?R stands for resistance, which is measured in ohms. A resistor is indeed a machine made to create resistance. You can use resistors to divide voltage, restrict current, or produce heat. The two most common varieties of resistors are fixed and variable.
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Two identical conducting spheres having charges of opposite sign attract each other with a force of 0.108N when separated by 50.0cm. The spheres are suddenly connected by a thin conducting wire which is then removed and thereafter the spheres repels each other with a force of 0.0360 N. What were the initial charges on the spheres?
Answer:
3 μC, -1 μC or -3 μC, 1 μC
Explanation:
As you can see in the image, let initial charges on two identical spheres be Q and q respectively (we are not considering the sign of q to be negative, value of q will be negative after solving)
initially,
[tex]-0.108 = \frac{KQq}{r^2}[/tex] …. (1)
where r = 0.5 meter (given in question),
after connecting a thin wire, both spheres tend to achieve the same potential conserving the total charge as initial, so after connecting a thin wire potential of both spheres become equal.
let q1 be the final charge on sphere 1 and q2 be the final charge on sphere 2,
[tex]\dfrac{Kq_1}{r} = \dfrac{Kq_2}{r}\\\\q_1 = q_2\\[/tex]... (2)
also, charge is conserved so total charge remains the same,
[tex]Q + q = q1 + q2[/tex] … (3)
if you solve equation 2 and 3, you will get the the final charges,
[tex]q_1 = q_2 = \dfrac{Q + q}{2}[/tex]
now after connecting the spheres the force equation becomes,
[tex]0.0360 = \dfrac{K\left(\dfrac{Q + q}{2}\right)^2}{r^2}[/tex] … (4)
divide the equation 2 by 4, after some simplification we get the below quadratic equation
[tex]3Q^2 + 10Qq + 3q^2 = 0[/tex]
divide the whole equation by [tex]q^2[/tex],
[tex]3\left(\dfrac{Q}{q}\right)^2 + 10\dfrac{Q}{q} + 3 = 0[/tex]
now this is a quadratic equation, after solving we get
[tex]Q = -3q[/tex]
(other solution also works, considering magnitude of charge on Q is more)
now substitute [tex]Q = -3q[/tex] in equation 2 and solve for q
q = 1 μC
Q = -3 μC
(you may consider Q = 3 μC and q = -1 μC)
Hopefully this answer will help you figure out the solution
A system of two objects has ΔKtot = 6 J and ΔUint = -3 J
The ΔKtot represents the change in the total kinetic energy of the system, and the ΔUint represents the change in the total internal energy of the system.
Since the system consists of two objects, we can assume that the change in kinetic energy is due to the transfer of energy between the two objects, while the change in internal energy is due to a change in the potential energy of the system. The positive value of ΔKtot indicates that the total kinetic energy of the system has increased by 6 J. This means that one of the objects has gained kinetic energy while the other has lost the same amount of kinetic energy. This could happen if the two objects collided and transferred energy between each other. The negative value of ΔUint indicates that the total internal energy of the system has decreased by 3 J. This means that the potential energy of the system has decreased by the same amount, which could happen if the objects moved closer together and the force of attraction between them decreased. Overall, the change in kinetic energy and internal energy in the system shows that there has been a transfer of energy between the objects and a decrease in the potential energy of the system. This suggests that the objects may have undergone a collision or moved closer together due to the force of attraction between them.
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At a rock concert, the sound intensity 1. 0 m in front of the bank of loudspeakers is 0. 10 W/m2. A fan is 30 m from the loud speakers. Her eardrums have a diameter of 8. 4 mm. How much sound energy is transferred to each eardrum in 1. 0 second
At a rock concert, the sound intensity 1. 0 m in front of the bank of loudspeakers is 0. 10 W/m2. A fan is 30 m from the loud speakers. Her eardrums have a diameter of 8. 4 mm.The sound energy transferred to each eardrum in 1.0 second is 4.36 x 10^-11 J.
The sound intensity at a distance of 30 m from the loudspeakers can be calculated using the inverse square law:
I = I₀ / (4πr²)
where I₀ is the sound intensity at a distance of 1.0 m from the loudspeakers, r is the distance from the loudspeakers, and π is the mathematical constant pi (approximately 3.14).
Substituting the given values, we get:
I = 0.10 W/m² / (4π(30 m)²) = 7.87 x 10^-7 W/m²
The sound energy transferred to each eardrum in 1.0 second can be calculated using the formula:
E = A × t × I
where A is the area of the eardrum, t is the time, and I is the sound intensity.
The area of the eardrum can be calculated using the formula for the area of a circle:
A = πr²
where r is the radius of the eardrum, which is half the diameter.
Substituting the given values, we get:
A = π(8.4 mm / 2)^2 = 5.54 x 10^-5 m²
Substituting the given values and solving for E, we get:
E = 5.54 x 10^-5 m² × 1.0 s × 7.87 x 10^-7 W/m² = 4.36 x 10^-11 J
Therefore, the sound energy transferred to each eardrum in 1.0 second is 4.36 x 10^-11 J.
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Drivers should compensate for a lack of depth perception by..
Answer:
decreasing speed
Explanation:
so that way you have a faster reaction time
Can someone help me please.
The amount of loss in the mechanical energy of tha ball during the bounce is 7.35J (Option B)
How do i determine the amount of energy lost?We'll begin by obtaining the energy at the height of 5 m. Details below:Mass of object (m) = 0.5 KgInitial height (h₁) = 5 mAcceleration due to gravity (g) = 9.8 m/s² Energy at 5m (E₁) = ?E₁ = mgh₁
E₁ = 0.5 × 9.8 × 5
E₁ = 24.5 J
Next, we shall determine the energy during the bounce. Details below:
Mass of object (m) = 0.5 KgBounce height (h₂) = 3.5 mAcceleration due to gravity (g) = 9.8 m/s² Energy during bounce (E₂) = ?E₂ = mgh₂
E₂ = 0.5 × 9.8 × 3.5
E₂ = 17.15 J
Finally, we shall determine the loss in the amount energy during the bounce. This is shown below:
Energy at 5m (E₁) = 24.5 JEnergy during bounce (E₂) = 17.15 JLost energy (E) =?E = E₁ - E₂
E = 24.5 - 17.15
E = 7.35J
Thus, the lost energy is 7.35J (Option B)
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Find a center of mass of a thin plate of density delta equals 5 bounded by the lines y equals x and x equals 0 and the parabola y equals 20 minus x squared in the first quadrant
The center of mass of the thin plate is located at the point (16/3, 8/3) in the first quadrant.
To find the center of mass of a thin plate with a density of delta equals 5 bounded by the lines y equals x and x equals 0 and the parabola y equals 20 minus x squared in the first quadrant, we can use the following formula:
x = (1/M) ∫∫ x δ(x,y) dA
y = (1/M) ∫∫ y δ(x,y) dA
Now we can use this value of M to find the center of mass:
x = (1/M) ∫∫ x δ(x,y) dA
= (1/125) ∫₀²₀ ∫₀^x x 5 dy dx
= (1/125) ∫₀²₀ 5x²/2 dx
= 16/3
y = (1/M) ∫∫ y δ(x,y) dA
= (1/125) ∫₀²₀ ∫₀^x y 5 dy dx
= (1/125) ∫₀²₀ 5x(20-x²)/2 dx
= 8/3
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Hw2b. 8. Position from polar velocity a particle starts at time at the position the velocity of the particle is written in the polar basis associated with its current position, and is: what is the position of at ?
The particle's location vector at time t is given by: r(t) = t³ + t² + 1
As per the question, we have the velocity of the particle in polar coordinates, but we need to find the position of the particle at time t. To do this, we need to integrate the velocity vector to obtain the position vector.
Let's consider the given velocity vector:
v(t) = (3t² + 2t)i + (2t² + 3t)j
To integrate this velocity vector, we need to find the corresponding position vector. Since the velocity vector is given in polar coordinates, we can express it in terms of polar variables:
v(t) = r'(t) + r(t)θ'(t)
where r'(t) and θ'(t) are the radial and angular components of the velocity vector, respectively.
By comparing the given velocity vector with the above equation, we can write:
r'(t) = 3t² + 2t
θ'(t) = (2t²+ 3t)/r(t)
Integrating r'(t) with respect to t, we get:
r(t) = t³ + t² + C
where C is the constant of integration.
To determine the value of C, we need to use the initial condition given in the problem. The particle starts at the position r = 1 and θ = π/4 at time t = 0. This implies:
r(0) = 1
θ(0) = π/4
Substituting these values in the equation for r(t), we get:
1 = 0 + 0 + C
C = 1
Therefore, the position vector of the particle at time t is given by:
r(t) = t³ + t² + 1
To find the value of θ at time t, we integrate θ'(t) with respect to t:
θ(t) = ∫(2t² + 3t)/r(t) dt
= ∫(2t² + 3t)/(t³ + t² + 1) dt
This integral is not trivial to solve analytically. Therefore, the position of the particle at time t can be expressed as:
r(t) = (t³ + t² + 1)i + f(t)j
where f(t) is the solution of the above integral for θ(t).
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A 60 kg rollerblader holds a 4 m long rope that is loosely tied around a metal pole. You push the rollerblader, exerting a 40 N force on her, which causes her to move increasingly fast in a counterclockwise circle around the pole. The surface of the skate is smooth, and the wheels of her rollerblades are well oiled. Determine the tangential and rotational acceleration of the rollerblader
The tangential acceleration of the rollerblader is [tex]0 m/s^2[/tex], and her centripetal acceleration is [tex]0.42 m/s^2.[/tex]
What is centripetal force?The force you exert on the rollerblader is causing her to move in a circular path around the metal pole. This means that there must be a centripetal force acting on her, which is provided by the tension in the rope.
[tex]a = v^2 / r[/tex]
where a is the centripetal acceleration, v is the speed of the rollerblader, and r is the radius of the circle.
To find the speed of the rollerblader, we can use the fact that the tension in the rope is equal to the force you exert on her, which is 40 N. Therefore:
Tension = Centripetal force = [tex]m * a = m * v^2 / r[/tex]
[tex]40 N = (60 kg) * v^2 / 4 m[/tex]
[tex]v^2 = (40 N * 4 m) / 60 kg = 2.67 m/s[/tex]
[tex]v = \sqrt(2.67 m/s) = 1.63 m/s[/tex]
Now we can calculate the centripetal acceleration:
[tex]a = v^2 / r = (1.63 m/s)^2 / 4 m = 0.42 m/s^2[/tex]
Since the rollerblader is moving at a constant speed, her tangential acceleration is zero.
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Match each vocabulary word with the correct definition
Medium
Transverse Waves
1. the overlapping of 2 waves having equal amplitude and wavelength
a disturbance that travels through a medium transporting energy from one location to another location 2.
Surface Waves
3. a substance or material in which something exists or occurs
Crest
4. waves that require a medium in which to travel, involves a transfer of kinetic energy from one place to another in the material
Trough
5. waves in which the movement in the medium is perpendicular to the direction the wave is traveling
Interference
6. waves in which the movement in the medium is parallel to the direction the wave is traveling
Wave
7. a wave that travels on the surface of the water in both transverse and longitudinal motions
Amplitude
8. Height of a wave
Longitudinal Waves
9. Highest part of the wave
Mechanical Waves
10. Lowest part of the wave
Answer:
Medium - 3. a substance or material in which something exists or occurs
Transverse Waves - 5. waves in which the movement in the medium is perpendicular to the direction the wave is traveling
Surface Waves - 7. a wave that travels on the surface of the water in both transverse and longitudinal motions
Crest - 9. Highest part of the wave
Trough - 10. Lowest part of the wave
Interference - 1. the overlapping of 2 waves having equal amplitude and wavelength
Wave - 2. a disturbance that travels through a medium transporting energy from one location to another location
Amplitude - 8. Height of a wave
Longitudinal Waves - 6. waves in which the movement in the medium is parallel to the direction the wave is traveling
Mechanical Waves - 4. waves that require a medium in which to travel, involves a transfer of kinetic energy from one place to another in the material
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Directions: SHOW ALL WORK.
What net force is required to accelerate a car at a rate of 2 m/s² if the car has a mass
of 3.000 kg?
F=
m=
Hint: Gravity has an acceleration of 9.8m/s2
a=
Mass times the body's acceleration is how force is calculated. m * a = 3000 * 2 = 6000 Newton is the formula for force, which is defined as mass times acceleration.
What does force in science mean?The definition of "force" is obvious. At this level, the phrases "push" and "pull" are entirely suitable to describe forces. A force is not something that exists inside or within an object. A force acts on the first thing from another.
What differences do forces have?These types of forces are present when two objects interact physically and physically come into contact with one another. The various types of contact forces include frictional, tensile forces, normal, air pressure, applied, and spring forces.
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Gravity has an acceleration of 9.8m/s2. However, this does not apply to the question since the acceleration of the car is 2 m/s². The net force required to accelerate the car is 6.000 kg m/s².
What is acceleration?Acceleration is the rate of change of velocity. It is a vector quantity that is defined as the change in velocity divided by the change in time. Acceleration can be seen as the rate at which an object changes its speed or the rate at which its direction changes. Acceleration can occur in any direction, and can be either positive (speeding up) or negative (slowing down). In physics, acceleration can be caused by forces, such as gravity, friction, and air resistance, or by changes in the motion of an object, such as starting, stopping, turning, or changing speed.
F = ma
F = (3.000 kg)(2 m/s²)
F = 6.000 kg m/s²
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Two magnets with opposite poles facing each other are held close to each other but are not touching. When released, the magnets snap together. When this happens, what evidence is there that energy is being transformed?
20 Points! Please have explanation
When the magnets snap together, the kinetic energy of their motion is transformed into potential energy as they become magnetically attached.
This can be seen as an increase in the temperature of the magnets due to the friction produced as they come together. Additionally, sound waves are produced that are evidence of the energy being transformed from kinetic to potential.
When two magnets with opposite poles facing each other are held close to each other but not touching and released, the kinetic energy of their motion is transformed into potential energy as they become magnetically attached. This can be seen as an increase in the temperature of the magnets due to the friction produced as they come together, as well as sound waves that are evidence of the energy transformation.
What is Energy?
Energy is the ability to do work. It exists in many forms, such as kinetic, potential, thermal, electrical, chemical, and nuclear energy. It can be transferred from one form to another, and can be converted into other forms of energy.
What is Kinetic Energy?
Kinetic energy is the energy of motion. It is the energy of an object due to its movement, and can be calculated by taking the mass of the object and multiplying it by the square of its velocity.
What is Potential Energy?
Potential energy is the energy that an object has due to its position or configuration. It is the energy stored in an object as a result of its position relative to other objects, and can be converted into other forms of energy.
Energy is the ability to do work, and exists in many forms such as kinetic, potential, thermal, electrical, chemical, and nuclear energy. Kinetic energy is the energy of motion, while potential energy is the energy stored in an object due to its position relative to other objects. These two forms of energy can be converted into other forms, and can be used to do work.
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When the magnets snap together, the kinetic energy of their motion is transformed into potential energy as they become magnetically attached.
This can be seen as an increase in the temperature of the magnets due to the friction produced as they come together. Additionally, sound waves are produced that are evidence of the energy being transformed from kinetic to potential.
When two magnets with opposite poles facing each other are held close to each other but not touching and released, the kinetic energy of their motion is transformed into potential energy as they become magnetically attached. This can be seen as an increase in the temperature of the magnets due to the friction produced as they come together, as well as sound waves that are evidence of the energy transformation.
What is Energy?
Energy is the ability to do work. It exists in many forms, such as kinetic, potential, thermal, electrical, chemical, and nuclear energy. It can be transferred from one form to another, and can be converted into other forms of energy.
What is Kinetic Energy?
Kinetic energy is the energy of motion. It is the energy of an object due to its movement, and can be calculated by taking the mass of the object and multiplying it by the square of its velocity.
What is Potential Energy?
Potential energy is the energy that an object has due to its position or configuration. It is the energy stored in an object as a result of its position relative to other objects, and can be converted into other forms of energy.
Energy is the ability to do work, and exists in many forms such as kinetic, potential, thermal, electrical, chemical, and nuclear energy. Kinetic energy is the energy of motion, while potential energy is the energy stored in an object due to its position relative to other objects. These two forms of energy can be converted into other forms, and can be used to do work.
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A sealed, empty 1. 0 L plastic sports bottle is sitting on a porch
in the hot sunlight. The temperature of the air inside the bottle
is 39 °C (312 K). When the sun goes down, the air in the bottle
cools to 20. °C (293 K). Assuming that the bottle is completely
flexible, what is the volume of air at the cooler temperature?
The volume of air in the bottle at the cooler temperature is 1.064 L.
How to calculate volume of air at the cooler temperature?
To solve this problem, we can apply the Ideal Gas Law:
PV = nRT
where P is the gas's pressure, V is its volume, n is the number of moles in the gas, R is the ideal gas constant, and T is its absolute temperature.
Since the bottle is completely flexible, we can assume that the pressure inside the bottle remains constant throughout the process. Therefore, we can set the pressures of the gas at both temperatures equal to each other:
P1V1 = P2V2
where P1 and T1 are the pressure and temperature of the gas at the initial state (when it is hot) and P2 and T2 are the pressure and temperature of the gas at the final state (when it is cool).
We can rewrite this equation to find V2:
V2 = (P1/P2) * V1 * (T2/T1)
where V1 is the gas's initial volume.
Now, we can plug in the values:
V1 = 1.0 L
P1 = P2 (since the bottle is completely flexible)
T1 = 39 °C = 312 K
T2 = 20 °C = 293 K
The ideal gas constant R is 8.31 J/(mol*K), but we do not need to use it here since we are not given the number of moles of gas in the bottle.
Thus, we have:
V2 = (312/293) * 1.0 L = 1.064 L
Therefore, the volume of air in the bottle at the cooler temperature is 1.064 L.
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2. Convert the following to the specified units a). 56MΩ to Ω c). 60Kj to Joules d). 75µC to C
Answer:
c.) 60 000j
Explanation:
c.) 1kj=1000j
60kjx1000
=60 000joules
3. An 87 kg fullback moving east with a speed of 5.0 m/s is tackled by a 97 kg opponent running
west at 3.5 m/s, and collision is perfectly inelastic. Calculate the following:
Given:
Sketch the before and after collisions:
a.
The velocity of the players just after the tackle
b. The decrease in kinetic energy during the collision
The decrease in kinetic energy during the collision is 1187.62 J.
Steps
Before the collision, the fullback's momentum is:
p1 = m1v1 = (87 kg)(5.0 m/s) = 435 kg*m/s (to the east)
The opponent's momentum is:
p2 = m2v2 = (97 kg)(-3.5 m/s) = -339.5 kg*m/s (to the west)
The total momentum before the collision is:
p1 + p2 = (435 kgm/s) + (-339.5 kgm/s) = 95.5 kg*m/s (to the east)
After the collision, the two players move together as one mass. Let vf be their common final velocity. Then the total momentum after the collision is:
p = (m1 + m2)vf = (87 kg + 97 kg)vf = 184 kg*vf (to the east)
Since momentum is conserved, we can equate the total momentum before and after the collision:
p1 + p2 = p
95.5 kgm/s = 184 kgvf
vf = 0.52 m/s (to the east)
Therefore, the velocity of the players just after the tackle is 0.52 m/s to the east.
To find the decrease in kinetic energy during the collision, we first need to find the initial kinetic energy:
KEi = (1/2)m1v1^2 + (1/2)m2v2^2
KEi = (1/2)(87 kg)(5.0 m/s)^2 + (1/2)(97 kg)(-3.5 m/s)^2
KEi = 1211.75 J
Since the collision is perfectly inelastic, the final velocity is the same for both players, and their combined mass is 184 kg. Therefore, the final kinetic energy is:
KEf = (1/2)mvf^2
KEf = (1/2)(184 kg)(0.52 m/s)^2
KEf = 24.13 J
The decrease in kinetic energy during the collision is:
ΔKE = KEi - KEf
ΔKE = 1187.62 J
Therefore, the decrease in kinetic energy during the collision is 1187.62 J.
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An object experiences two forces acting on the same surface (i. E. They are additive): a force of 5. 0N acting at 60. ∘ to the horizontal and a force of 8. 0N acting 45∘ to the horizontal.
What is the magnitude of the resultant force on the object? Give your answer to the nearest newton, without units
The magnitude of the resultant force on the object is approximately 12 N.
For the 5.0 N force:
Horizontal component = 5.0 N * cos(60°) ≈ 2.5 N
Vertical component = 5.0 N * sin(60°) ≈ 4.3 N
For the 8.0 N force:
Horizontal component = 8.0 N * cos(45°) ≈ 5.7 N
Vertical component = 8.0 N * sin(45°) ≈ 5.7 N
Next, we can add the horizontal and vertical components separately:
Resultant horizontal component = 2.5 N + 5.7 N ≈ 8.2 N
Resultant vertical component = 4.3 N + 5.7 N ≈ 10 N
Finally, we can use the Pythagorean theorem to find the magnitude of the resultant force:
Resultant force = sqrt((8.2 N)^2 + (10 N)^2) ≈ 12 N
The resultant force is the net force that acts on an object. It is the vector sum of all the forces acting on the object. If an object is subjected to multiple forces, the resultant force determines the direction and magnitude of the object's motion. If the resultant force is zero, the object will remain at rest or continue moving at a constant velocity. If the resultant force is non-zero, the object will accelerate in the direction of the force.
The concept of the resultant force is particularly important in dynamics, the branch of mechanics that deals with the motion of objects under the influence of forces. The laws of motion developed by Sir Isaac Newton, which are the foundation of classical mechanics, are formulated in terms of resultant forces. The first law states that an object at rest will remain at rest or move at a constant velocity unless acted upon by a net external force, while the second law relates the acceleration of an object to the net force acting on it.
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A hot tub holds 480kg of water. On a cold day, the initial temperature of the water is 4 degrees C. Before getting in, the hot tub needs to reach a temperature of 50 C.
A). how much heat is needed to warm up the hot tub water?
B). The hot tub is heated by a propane heater. When burned, propane releases 4.65x10⁷ joules of heat energy per kilogram of propane. How much propane has to be burned to heat the hot tub water?
How do i set this up??
The amοunt οf heat required tο increase the temperature οf 480 kg water tο increase the temperature frοm 4°C tο 50°C is 9.3 × 10⁷ J.
The amοunt οf prοpane burned is 2kg.
What is heat energy?Temperature is a numerical indicatοr οf hοw hοt οr cοld sοmething is. Atοms and mοlecules make up sοlids, liquids, and gases. The temperature οf that substance wοuld be lοw while these atοms and mοlecules are mοving slοwly. The temperature rises as the atοms and mοlecules mοve mοre quickly. The cοmbined energy οf these atοms and mοlecules in mοtiοn is knοwn as heat.
Cοnductiοn, cοnvectiοn and radiatiοn are the three methοds οf heat transfer.
Using the fοrmula:
H = m×s×ΔT
where,
H is the tοtal heat
m is the mass
and ΔT is the change in temperature.
substituting the values and sοlving fοr H,
H = 9.3× 10⁷ J
The amοunt οf prοpane required = H/h
where
H is the tοtal heat and,
h is the heat released by 1kg οf Prοpane.
Mass οf prοpane required= 2kg
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A body is displaced through a certain distance x by a force of 30n. if the work done is 100j and the displacement is in the direction of force, what is the value of x
The work done on an object by a constant force is given by the formula:
W = Fd cos(theta)
where:
W = work done (in joules)
F = applied force (in newtons)
d = displacement (in meters)
theta = angle between the force and displacement vectors (in degrees)
In this case, the force is in the same direction as the displacement, so the angle between them is 0 degrees. Therefore, we can simplify the formula to:
W = Fd
We are given that the work done is 100 J and the force is 30 N. Substituting these values into the formula, we get:
100 J = 30 N * d
Solving for d, we get:
d = 100 J / (30 N) = 3.33 meters
Therefore, the displacement is 3.33 meters.