Here’s the zoomed graph!

didn't know how to workout iam only 3rd standard

Answer:

The distance formula is 22.360679775

if you round it to the nearest tenth, then the answer is 22.4

Step-by-step explanation:

(-6, -12) and (4,8)

(x2 - x1)² + (y2 - y1)²

Place the x and y values

(4 - - 6)² + (8 - - 12)²

= 10² + 20²

= 100 + 400 = 500

√500 = 22.360679775

Round it to the nearest tenth and you will get 22.4

Hope this helps!

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The formula in finding the distance between two points is given below:

where:

Substitute the given values into the distance formula and solve for d:

Therefore, the distance between the two points is 22.4 units (nearest tenth).

Cheers!

We have: 5m 75cm = 5.75 m

So the length of each piece is : [tex]l = \frac{5.75}{5} =1.15<m>[/tex]

ok done. Thank to me :>

The given ratios expresses the number of time a value is larger or smaller

than another value.

The correct responses are;

Reasons:

3. Given that the perimeter of the rectangle = 72

The ratio of the lengths of the sides = 1:2

Let a and b represent the sides, we have;

2·a + 2·b = 72

[tex]\displaystyle \frac{a}{b} = \mathbf{\frac{1}{2}}[/tex]

Which gives;

2·a = b

2·a + 2·(2·a) = 72

6·a = 72

a = 72 ÷ 6 = 12

b = 2·a = 2 × 12 = 24

The lengths of the sides are; (B) 12 and 24

4. Extended ratio = 2:3:7

The perimeter = 36

The lengths of the sides are;

[tex]\displaystyle \frac{2}{2 + 3 + 7} \times 36 = \mathbf{6}[/tex]

[tex]\displaystyle \frac{3}{2 + 3 + 7} \times 36 = \mathbf{9}[/tex]

[tex]\displaystyle \frac{7}{2 + 3 + 7} \times 36 = \mathbf{21}[/tex]

The lengths are; (D) 6, 9, 21

5. The given equation is presented as follows;

[tex]\displaystyle \frac{5}{x + 7} = \mathbf{\frac{3}{x + 2}}[/tex]

5 × (x + 2) = 3 × (x + 7)

5·x + 10 = 3·x + 21

5·x - 3·x  = 21 - 10

2·x = 11

[tex]\displaystyle x = \mathbf{ \frac{11}{2}}[/tex]

The correct option is; [tex]\displaystyle \underline{(E) \ \frac{11}{2}}[/tex]

6. The width to length ratio is [tex]\displaystyle \mathbf{\frac{2.5}{7.0}}[/tex]

The simplified ratio is therefore;

[tex]\displaystyle \frac{2.5}{7.0} = \frac{2 \times 2.5}{2 \times 7.0} = \mathbf{\frac{5}{14}}[/tex]

The correct option is (E) [tex]\displaystyle \underline{(E) \ \frac{5}{14}}[/tex]

7. The given ratio of the lengths is 3:1

Therefore;

[tex]\overline{BC}[/tex]:[tex]\overline{EF}[/tex] = 3:1

Which gives;

[tex]\displaystyle \mathbf{\frac{\overline{BC}}{\overline{EF}}} = \frac{3}{1}[/tex]

[tex]\overline{BC}[/tex] = 18

Therefore;

[tex]\displaystyle \frac{18}{\overline{EF}} = \frac{3}{1}[/tex]

18 × 1 = 3 × [tex]\overline{EF}[/tex]

[tex]\displaystyle \overline{EF} = \frac{18 \times 1}{3} = 6[/tex]

[tex]\overline{EF}[/tex] = 6

By Pythagorean theorem, we have;

[tex]\overline{DF}[/tex]² = [tex]\mathbf{\overline{DE}}[/tex]² + [tex]\mathbf{\overline{EF}}[/tex]²

Which gives;

[tex]\overline{DF}[/tex]² = 3² + 6² = 45

[tex]\overline{DF}[/tex] = √(45) = 3·√5

Using the given ratio, we have;

[tex]\overline{AC}[/tex] = 3 × [tex]\mathbf{\overline{DF}}[/tex]

Which gives;

[tex]\overline{AC}[/tex] = 3 × 3·√5 = 9·√5

[tex]\overline{AC}[/tex] = 9·√5

The correct option is; (B) [tex]\overline{EF}[/tex] = 6, [tex]\overline{AC}[/tex] = 9·√5

8. EF = 1, AB = 2

CD = 2, CE = 4

Therefore;

[tex]\displaystyle \mathbf{\frac{EF}{AB}} =\frac{1}{2}[/tex]

[tex]\displaystyle \mathbf{\frac{CD}{CE}} =\frac{2}{4} = \frac{1}{2}[/tex]

Which gives;

[tex]\displaystyle \frac{EF}{AB} =\displaystyle \mathbf{\frac{CD}{CE}}[/tex]

(C) The values are equal

9. AC = 6, BE = 8

DF = 3, BD = 6

Column A

[tex]\displaystyle \frac{AC}{BE} =\displaystyle \mathbf{\frac{6}{8}} = \frac{3}{4}[/tex]

Column B

[tex]\displaystyle \frac{DF}{BD} =\displaystyle \mathbf{\frac{3}{6}} = \frac{1}{2}[/tex]

[tex]\displaystyle \frac{3}{4} > \mathbf{\frac{1}{2}}[/tex]

Therefore;

Column A is greater than column B

(A) The value in column A is greater

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Using the Central Limit Theorem, it is found that the mean of the sampling distribution of sample proportions is 0.37.

The Central Limit Theorem establishes that, for a proportion p in a sample of size n, the sampling distribution of sample proportions has:

For this problem, about 37% of high school seniors have vaped in the past year, hence [tex]p = 0.37[/tex].

For more on the Central Limit Theorem, you can check https://brainly.com/question/4086221

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Kind of, Market day as in make stuff and then sell it or Market day as in Sell food, I remember this in elementary school 2 Different Kind of Market day :)

(a) The equation for estimating the weight W of the Golden Delicious apples is W + 20 = 44.

(b) The weight of the Golden Delicious apples is 24 pounds.

The equation for estimating the weight W of the Golden Delicious apples is calculated as follows;

Weight of Golden delicous apples + Weight of Honeycrisp = Total weight of the apples

W + 20 = 44

The weight of the Golden Delicious apples is calculated as follows;

W + 20 = 44

collect similar terms together;

W = 44 - 20

W = 24 lb

Learn more about word problem in Algebra here: https://brainly.com/question/17067890

Answer:

x=24

Step-by-step explanation:

2x+20=2x-4+x

Subtract 2x from both sides

2x+20-2x=2x-4+x-2x

Simplify

20=-4+x

Add 4 to both sides

24=x

Switch sides

x=24

Answer:

x = -9/2

Step-by-step explanation:

64 = 2^6

if you have the same base, you can set the exponents equal and solve for x.

-2x-3 = 6

-2x = 9

x = -9/2

good luck on your final! you got this!

Step-by-step explanation:

[tex] {2}^{ - 2x - 3} = 64[/tex]

first, get 64 to a base of 2

[tex] {2}^{ - 2x - 3} = {2}^{6} [/tex]

now we can drop the bases

[tex] - 2x - 3 = 6[/tex]

And now we can solve it like any other equation

[tex] - 2x = 6 + 3[/tex]

[tex] - 2x = 9[/tex]

[tex]x = - \frac{9}{2} [/tex]

[tex](9+7i)(6+3i)\\\\=54+27i + 42i + 21i^2\\\\=54+69i -21~~~;[i^2 =-1]\\\\=33+69i[/tex]

Work Shown:

1 pound = 16 ounces

3 pounds = 48 ounces (multiply both sides by 3)

Based on that, we can then say,

(750 calories)/(10 ounces) = (x calories)/(48 ounces)

750/10 = x/48

75 = x/48

x/48 = 75

x = 48*75

x = 3600

Step-by-step explanation:

this is a rectangle. so, all things are symmetric.

EI = IG = FI = IH

IGF = IFG = IEH = IHE

therefore, since EI = FI

2x + 8 = 6x - 20

28 = 4x

x = 7

now,

EG = EI + IG = 2×EI = 2×(2×7 + 8) = 2×22 = 44

IFE is a complementary angle to IFG (together they have 90°).

and because IFG = IGF = 30°

IFE = 90 - 30 = 60°

Answer:

Slope = 3/2

y-intercept = -4

x  |  y

0  -4

2   -1

Step-by-step explanation:

========================================================

Explanation:

i = sqrt(-1)

Lets list out the first few powers of i

By the time we reach the fourth power, we repeat the cycle over again (since i^0 is also equal to 1). The cycle is of length 4, which means we'll divide the exponent over 4 to find the remainder. Ignore the quotient. That remainder will determine if we go for i^0, i^1, i^2 or i^3.

For example, i^5 = i^1 because 5/4 leads to a remainder 1.

Another example: i^6 = i^2 since 6/4 = 1 remainder 2

Again, we only care about the remainder to find out which bin we land on.

-------------

Turning to the question your teacher gave you, we have,

739/4 = 184 remainder 3

So i^739 = i^3 = -i

--------------

Side notes:

Answer:

Step-by-step explanation:

Angles 1 and 2 have common side, so they are adjacent. They are not making a right or straight angle.

Correct choice is D

Step-by-step explanation:

1 Remove parentheses.

8{y}^{2}\times -3{x}^{2}{y}^{2}\times \frac{2}{3}x{y}^{4}

8y

2

×−3x

2

y

2

×

3

2

xy

4

2 Use this rule: \frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}

b

a

×

d

c

=

bd

ac

.

\frac{8{y}^{2}\times -3{x}^{2}{y}^{2}\times 2x{y}^{4}}{3}

3

8y

2

×−3x

2

y

2

×2xy

4

3 Take out the constants.

\frac{(8\times -3\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

(8×−3×2)y

2

y

2

y

4

x

2

x

4 Simplify 8\times -38×−3 to -24−24.

\frac{(-24\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

(−24×2)y

2

y

2

y

4

x

2

x

5 Simplify -24\times 2−24×2 to -48−48.

\frac{-48{y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

−48y

2

y

2

y

4

x

2

x

6 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x

a

x

b

=x

a+b

.

\frac{-48{y}^{2+2+4}{x}^{2+1}}{3}

3

−48y

2+2+4

x

2+1

7 Simplify 2+22+2 to 44.

\frac{-48{y}^{4+4}{x}^{2+1}}{3}

3

−48y

4+4

x

2+1

8 Simplify 4+44+4 to 88.

\frac{-48{y}^{8}{x}^{2+1}}{3}

3

−48y

8

x

2+1

9 Simplify 2+12+1 to 33.

\frac{-48{y}^{8}{x}^{3}}{3}

3

−48y

8

x

3

10 Move the negative sign to the left.

-\frac{48{y}^{8}{x}^{3}}{3}

−

3

48y

8

x

3

11 Simplify \frac{48{y}^{8}{x}^{3}}{3}

3

48y

8

x

3

to 16{y}^{8}{x}^{3}16y

8

x

3

.

-16{y}^{8}{x}^{3}

−16y

8

x

3

Done

The number of basket balls donated is; 28 basket balls

We are told that;

Ratio of basket balls to soccer balls = 7:6

Now, the number of soccer balls donated was 24.

This, means fraction of the total number of balls x for soccer balls was; [6/(7 + 6)]x

Thus;

[6/(7 + 6)]x = 24

6x/13 = 24

6x = 24 × 13

6x = 312

x = 312/6

x = 52 balls

Now, since total balls are 52 and soccer balls are 24, then;

Number of basketballs = 52 - 24

Number of basketballs = 28 basketballs

Read more about fraction and proportions at; https://brainly.com/question/1581333

Answer:

I am not sure the answer is , if its minus ,divade ,multiply or plus but down the answer is correct

Step-by-step explanation:

17x - 75

× = 75÷17

x= 4.4117647059

Answer: Yes the win level is greater than 1/2

Step-by-step explanation: 32/52 is greater than 1/2

The domain of the function to know the number of cars remaining on any day during the month is [0, 40]. The maximum and minimum values are 120 and 0 respectively.

The domain is the all inputted value for which the function is defined. All the x values are domain of a function.

Now, finding the domain of the function,

We know that, the number of cars cannot be negative, so

[tex]f(x)\geq0\\120-3x\geq0\\3x\leq120\\x\leq40[/tex]

The number of cars should be greater than 0, so x > 0.

So, the domain will be [0, 40].

The maximum value is given by putting x = 0,

[tex]f(0)=120-3(0)\\=120[/tex]

The minimum value is given by putting x = 40,

[tex]f(40)=120-3\times40\\=120-120\\=0[/tex]

Therefore, the domain of the function f(x)=120-3x to know the number of cars remaining on any day during the month is [0, 40]. The maximum and minimum values are 120 and 0 respectively.

To learn more about the Domain of Functions visit here:

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Answer:

4/8 = 1/2 = 0.5 is your answer

Answer:

first one is second

Step-by-step explanation:

second one is A

Answer:

y=-1/2x-8

Step-by-step explanation:

y-y1=m(x-x1)

y-(-5)=-1/2(x-(-6))

y+5=-1/2(x+6)

y=-1/2x-6/2-5

y=-1/2x-3-5

y=-1/2x-8

Answer:

b. [tex]a_{12}=-177147[/tex]

Step-by-step explanation:

This is a geometric sequence:

[tex]a_n=a_1x^{n-1}[/tex]

where n is the index in the sequence and x is the common scale factor.

In the given sequence here, the common factor is 3:

[tex]-3\div-1=3\\-9\div-3=3\\-27\div-9=3[/tex]

That's the factor, and we know the first term is -1, so you can write the equation for this sequence:

[tex]a_n=(-1)(3)^{n-1}[/tex]

Finally, plug in 12 for n and solve:

[tex]a_{12}=(-1)(3)^{12-1}\\a_{12}=(-1)(3)^{11}\\a_{12}=(-1)177147\\a_{12}=-177147[/tex]

Answer:

77

Step-by-step explanation:

6x2 = 12

13x5 = 65

65+12 = 77

The answer is 77.

Answer:

Step-by-step explanation:

The prime factor representation of 150 is 2 x 3 x 5^2