help plz will give brainliest and dont answer if u dont know

Answer:

I believe D

Explanation:

I'm not for sure but I think it is D

Answer:

vector quantity............

Explanation:

Mark me braimlist

Answer:

scalar

Explanation:

Answer:

27.1m/s

Explanation:

Given parameters:

Height of the building  = 30m

Initial velocity  = 12m/s

Unknown:

Final velocity  = ?

Solution:

We apply one of the kinematics equation to solve this problem:

         v²  = u²  + 2gh

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

h is the height

          v²   = 12²  + (2 x 9.8 x 30)

          v  = 27.1m/s

Answer:

a: solid

b:  liquid

c: liquid

d: gas

e: gas

f:  liquid

Explanation:

According to the forces of attraction, the states of matter in each case serially are as follows: solid, liquid,liquid,gas,gas and liquid respectively.

Matter in chemistry, is defined as any kind of substance that has mass and occupies space that means it has volume .Matter is composed up of atoms which may or not be of same type.

Atoms are further made up of sub atomic particles which are the protons ,neutrons and the electrons .The matter can exist in various states such as solids, liquids and gases depending on the conditions of temperature and pressure.

The states of matter are inter convertible into each other by changing the parameters of temperature and pressure.Matter can neither be created nor destroyed rather is conserved at end of chemical change.

Learn more about matter,here:

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Explanation:

Hooke's Law: Fe = kx

x = Fe / k = (22.0N) / (4.00N/cm) = 5.50cm.

10.00cm + 5.50cm = 15.50cm

The new length of the spring is 15.50cm.

Answer:

there are not all safe for humans

Atlantic Ocean (salt water)

Answer:

That is Gravitational potential energy.

Answer: Sam provides the biggest power

Explanation: Power is defined, in Physics, as the rate of work done. Work is energy transferred to an object due to the force causing the displacement of the object.

So, to determine Power:

For Sam:

P = [tex]\frac{work}{time}[/tex]

[tex]P=\frac{F.d}{t}[/tex]

[tex]P=\frac{300.5}{30}[/tex]

P = 50 Watts

The unit for Power is [P] = J/s = Watt

For Gary:

P = [tex]\frac{work}{time}[/tex]

[tex]P=\frac{1000}{25}[/tex]

P = 40 Watts

Comparing power of Sam and Gary, we can conclude that Sam provides the biggest power of 50 Watts.

Answer:

The angle of projection is 12.26⁰.

Explanation:

Given;

initial position of the dart, h₀ = 1.50 m

height above the ground reached by the dart, h₁ = 1.73 m

maximum height reached by the dart, Hm = h₁ - h₀ = 1.73 m - 1.50 m= 0.23 m

velocity of the dart, u = 10 m/s

The maximum height reached by the projectile is calculated as;

[tex]H_m = \frac{u^2sin^2 \theta}{2g}[/tex]

where;

θ is angle of projection

g is acceleration due to gravity = 9.8 m/s²

[tex]H_m = \frac{u^2sin^2 \theta}{2g}\\\\sin^2 \theta = \frac{H_m \ \times \ 2g}{u^2} \\\\sin^2 \theta = \frac{0.23 \ \times \ 2(9.8)}{10^2} \\\\sin ^2\theta =0.04508\\\\sin \theta = \sqrt{0.04508} \\\\sin \theta = 0.2123\\\\\theta = sin^{-1}(0.2123)\\\\\theta = 12.26^0[/tex]

Therefore, the angle of projection is 12.26⁰.

Answer:

sexual reproduction

Explanation:

Answer:

C.

That is your answer  

Answer: 24.97 kg

Explanation:

The gravitational force between two objects of masses M1, and M2 respectively, and separated by a distance R, is:

F = G*(M1*M2)/R^2

Where G is the gravitational constant:

G = 6.67*10^-11 m^3/(kg*s^2)

In this case, we know that

R = 0.002m

F = 0.0104 N

and that M1 = M2 = M

And we want to find the value of M, then we can replace those values in the equation to get

0.0104 N = (6.67*10^-11 m^3/(kg*s^2))*(M*M)/(0.002m)^2

(0.0104 N)*(0.002m)^2/(6.67*10^-11 m^3/(kg*s^2)) = M^2

623.69 kg^2 = M^2

√(623.69 kg^2) = M = 24.97 kg

This means that the mass of each object is 24.97 kg

Answer:

three 3

Explanation:

Answer is D

Ndmdjdndbdjdkskd

The impulse acting on an object and the impact time, the equation F= I / Δt can be used to calculate the force applied to an object, therefore the correct answer is D.

The product of the average applied force and the time for which it is exerted is known as an impulse.

the mathematical relation for impulse is

Impulse  = F * Δt

where F represents the force applied and Δt represents the time for which the force is applied

Thus, the correct equation that can be used to calculate the force applied to an object is F = I /Δt and the correct option is D.

Learn more about impulse, here

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Answer:

1800J

Explanation:

Step one:

given data

mass of bullet m= 3g= 0.03kg

initial velocity u = 400m/s

final velocity v= 200 m/s

Step two:

1.The bullet's lost kinetic energy went inside the tree.

2. The energy transferred is computed as

= initial KE- KE final

Initial KE= 1/2mu^2

Initial KE= 1/2*0.03*400^2

Initial KE= 1/2*0.03*160000

Initial KE= 1/2*4800

Initial KE= 2400J

KE final= 1/2mv^2

KE final= 1/2*0.03*200^2

KE final= 1/2*0.03*40000

KE final= 1/2*1200

KE final= 600J

KE transferred = 2400-600

KE transferred= 1800J

Answer:its b

Explanation:

Answer:

c

Explanation:

energy doesnt affect to mass of a object

Answer:

Shorter string produces more frequency in two different strings because the equation for frequency is velocity/wavelength , this means that a shorter string creates a shorter wavelength which essentially increases the total frequency produced

Answer:

Im not sure, are there options for it?

Explanation:

Answer:

False

Explanation:

because Only Volt and Newton are units come from metric units, however, the Tesla is not come from Metric units.

Answer:

True

Explanation:

Study guide answer key

Answer:

A

Explanation:

C = (F-32)*5/9 = 73*5/9 = 40.55555

since the answers are spread apart, technically you can just estimate by doing -32

and then /2

since 5/9 is close to 1/2

Answer:

3

Explanation:

Answer:

darn this too much lololpop

Given that,

Initial force, F = 12 N

First initial charge, q₁ = 3C

First new charge, q₁' = 6C

Initial distance, r = 15 cm

New distance, r' = 45 cm

To find,

The new force of attraction.

Solution,

The force between two charges is given by :

[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]

[tex]12=k\dfrac{3\times q_2}{15^2}\ ....(1)[/tex]

Let F' is the new force.

[tex]F'=k\dfrac{q_1'q_2'}{r'^2}[/tex]

[tex]F'=\dfrac{k\times 6\times q_2}{(45)^2}\ ...(2)[/tex]

As q₂ is same in this case.

Dividing equation (1) and (2) :

[tex]\dfrac{F}{F'}=\dfrac{k\dfrac{3q_2}{15^2}}{\dfrac{k\times 6\times q_2}{45^2}}\\\\\dfrac{12}{F'}=4.5\\\\F'=\dfrac{12}{4.5}\\\\F'=2.67\ N[/tex]

So, the new force of attraction is 2.67 N.