Answer:
this is it
Explanation:
the control and experiemental groups i didnt know
Based on the measured force between objects that are 10 meters apart, how can you find the force between objects that are any distance apart ?
Answer:
F' = 100 F/r²
Explanation:
The gravitational force of attraction between two objects is given by the Newton's Gravitational Formula. The Newton's Gravitational Formula is as follows:
F = Gm₁m₂/r²
where,
F = Force between objects
G = Universal Gravitational Constant
m₁ = mass of first object
m₂ = mass of second object
r = distance between objects = 10 m
Therefore,
F = Gm₁m₂/10²
Gm₁m₂ = 100F --------------------- equation (1)
Now, we consider these objects at any distance r apart. So, the force becomes:
F' = Gm₁m₂/r²
using equation (1), we get:
F' = 100 F/r²
So, if the force (F) between objects 10 m apart is known, we can find it at any distance from the above formula.
The force between objects that are any distance apart is expressed as [tex]P'=\frac{100P}{r^2}[/tex]
According to the gravitational law, the force acting on an object is directly proportional to the product of their masses and inversely proportional to the square of their distance apart. Mathematically,
[tex]P=\frac{GMm}{r^2}[/tex]
M and m are the masses
r is the distance between the masses
If the force between objects that are 10 meters apart, hence;
[tex]P=\frac{GMm}{10^2}\\P=\frac{GMm}{100}\\GMm = 100P[/tex]
To find the force between objects that are any distance apart, we will use the same formula above to have;
[tex]P'=\frac{GMm}{r^2}\\[/tex]
Substitute the result above into the expression to have:
[tex]P'=\frac{100P}{r^2}[/tex]
Hence the force between objects that are any distance apart is expressed as [tex]P'=\frac{100P}{r^2}[/tex]
Learn more on gravitational law here: https://brainly.com/question/11760568
Does electric and magnetic objects both have north and south poles
Explanation:
hope this answer was helpful
A steam catapult applies a very large force to supplement the engine thrust of a jet fighter as it takes off from an
aircraft carrier. The jet has a mass of 4000 kg and must reach its take off speed of 70 m/s at the end of the 220
m flight deck. What is the combined force of the catapult and engines? (Use the work-energy theorem)
Answer:
The combined force of the catapult and engines is 44545.455 newtons.
Explanation:
Let suppose that platform of the aircraft carrier is horizontal, such that changes in gravitational potential energy can be neglected. In addition, effects of non-conservative forces are neglected. By using Principle of Energy Conservation and Work-Energy Theorem we find that steam catapult-jet aircraft is represented by:
[tex]K_{1}+W_{1\rightarrow 2} = K_{2}[/tex] (1)
Where:
[tex]K_{1}[/tex], [tex]K_{2}[/tex] - Initial and final translational kinetic energies of the jet fighter, measured in joules.
[tex]W_{1\rightarrow 2}[/tex] - Work done on the jet fighter due to the combined force of the catapult and engines, measured in joules.
By applying definitions of translational kinetic energy and work, we expand and simplify the equation above as follows:
[tex]F\cdot \Delta s = \frac{1}{2}\cdot m\cdot (v_{2}^{2}-v_{1}^{2})[/tex]
[tex]F = \frac{m\cdot (v_{2}^{2}-v_{1}^{2})}{2\cdot \Delta s}[/tex] (2)
Where:
[tex]F[/tex] - Combined force of the catapult and engines, measured in newtons.
[tex]m[/tex] - Mass of the jet fighter, measured in kilograms.
[tex]\Delta s[/tex] - Length of the catapult, measured in meters.
[tex]v_{1}[/tex], [tex]v_{2}[/tex] - Initial and final speeds of the jet aircraft, measured in meters per second.
If we know that [tex]m = 4000\,kg[/tex], [tex]v_{1} = 0\,\frac{m}{s}[/tex], [tex]v_{2} = 70\,\frac{m}{s}[/tex] and [tex]\Delta s = 220\,m[/tex], then the combined force of the catapult and engines is:
[tex]F = \frac{(4000\,kg)\cdot \left[\left(70\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]}{2\cdot (220\,m)}[/tex]
[tex]F = 44545.455\,N[/tex]
The combined force of the catapult and engines is 44545.455 newtons.
The combined force of the catapult and engines is 44,545.5 N.
The given parameters;
mass of the jet, = 4000 kgspeed of the jet, v = 70 m/slength of the deck, d = 220 mThe combined force of the catapult and engines is determined by applying work energy theorem as shown below;
[tex]W = \Delta E\\\\Fd = \frac{1}{2}m(v^2 -u^2) \\\\220F = \frac{1}{2}(4000)(70^2 - 0^2) \ \\\\220 F = 9,800,000\\\\F = \frac{9,800,000}{220} \\\\F = 44,545.5 \ N[/tex]
Thus, the combined force of the catapult and engines is 44,545.5 N.
Learn more here:https://brainly.com/question/10063455
A type of cuckoo clock keeps time by having a mass bouncing on a spring, usually something cute like a cherub in a chair. What force constant is needed to produce a period of 0.320 s for a 0.0190-kg mass?
Answer:
k = 7.32 N/m
Explanation:
We know that the time period of a spring mass system is given as follows:
T = 2π√(m/k)
T² = 4π²m/k
k = 4π²m/T²
where,
k = force constant = ?
m = mass = 0.019 kg
T = Time Period = 0.32 s
Therefore,
k = 4π²(0.019 kg)/(0.32 s)²
k = 7.32 N/m
carter found the rock shown in the picture below near a river
Answer:
there's no picture
Explanation:
and what would the question be anyways?
Answer:
what is the question
Explanation:
A water molecule is made up of one oxygen and two hydrogen atoms. Why is water considered a pure substance?
Answer:
A mixture is when two or more substances combine physically together.
However, in water, two hydrogen atoms combine with one oxygen atom chemically, forming a new substance that has properties different from hydrogen alone or oxygen alone.
Explanation:
A current of 15 Amps flows through a circuit with a resistance of 0.10 Ohms. What is the voltage?
A. 0.006 Volts
OB. 1.5 Volts
O C. 15 Volts
D. 150 Volts
Voltage = (current) x (resistance) (Ohm's law)
Voltage = (15 A) x (0.10 ohm)
Voltage = 1.5 volts (B)
Which sequence shows electromagnetic waves arranged in a decreasing order of their wavelengths?
Answer: Gamma rays, x-rays, ultraviolet rays, visible light, and infrared rays.
Answer:
C) radio → infrared → ultraviolet → gamma
Explanation:
It Increases left to right therefore it decreases right to left
Full moon is located______
a. farthest from the Sun
b. at a 90 degree angle with the Sun and Earth
c. closest to the Sun
Answer:
Im going to take an educated guess and say its B.
Explanation:
A Full moon is located farthest from the Sun. Thus, the correct option for this question is A.
What is a Full moon?A full moon may be defined as one of the types of lunar phases when the Moon significantly appears fully illuminated from Earth's perspective. This event typically occurred when Earth is located between the Sun and the Moon.
When the earth is located between the sum and the moon, it is the time when the moon is located farthest from the sun. And it directs to an event of a full moon. The average time duration of the full moon and the repetition of the same phase normally requires 29.53 days.
Therefore, the Full moon is located farthest from the Sun. Thus, the correct option for this question is A.
To learn more about the Full moon, refer to the link:
https://brainly.com/question/15032553
#SPJ2
things that affects the demand for electricity
A solid keeps its shape due to which of the following factors?
Space between particles
Attractive forces between particles
The type of element in the solid
The container it is placed in
Answer:
c
Explanation:
because whatever elements are used like gas uses water evaporation so yeah
Answer:
(A) Space between particles!
Explanation:
Solids can hold their shape because their molecules are tightly packed together!
✞ Bye Have A Nice Day! ✞
Light travels fastest through which of the following?
A.
air
B.
glass
C.
vacuum
D.
water
HELP PLEASE I need to finish this asap
Answer:
I'm not 100% sure, but I think the answer would be the first one because there's a force pushing the object in every direction, so they would cancel eachother out and make the object stay in the same place.
Explanation:
pls vote brainliest
What holds the metal ions together in a lattice?
A. covalent bonds
B. metallic bonds
C. hydrogen bonds
D. ionic bonds
Answer:
B. Metallic bonds.
What is the momentum of a 8850 kg medium truck that is traveling with a velocity of 55 m/s west on the highway
Answer:
486,750 kg*m/s
Explanation:
Momentum is mass*velocity
M = m*v
M = 8850kg*55m/s
M = 486,750 kg*m/s
The momentum of an 8850 kg medium truck that is traveling with a velocity of 55 m/s west on the highway is 486750 kg m / s.
What is momentum?Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force acting on the particle equals the time rate of change of momentum.
According to Newton's second law, if a particle is subjected to a constant force for a specific amount of time, the result of the force and time (referred to as the impulse) is equal to the change in momentum.
Given:
The mass of the truck is, m = 8850 kg,
The velocity of the truck is, v = 55 m/s,
Calculate the momentum of the truck as shown below,
Momentum = m × v
Momentum = 8850 × 55
Momentum = 486750 kg m / s
Thus, the Momentum of the truck is 486750 kg m / s.
To know more about momentum:
https://brainly.com/question/904448
#SPJ2
A batter hits a foul ball. The 0.140-kg baseball that was approaching him at 40.0 m/s leaves the bat at 30.0 m/s in a direction perpendicular to the line between the batter and the pitcher. What is the magnitude of the impulse delivered to the baseball?
A) 9.80 Ns
B) 3.50 Ns
C) 7.00 Ns
D) 5.60 Ns
E) 1.40 Ns
Answer:
The magnitude of the impulse delivered to the baseball is 7.0 Ns
Explanation:
Given;
mass of the foul ball, m = 0.14 kg
initial velocity, u = 40 m/s
final velocity, v = 30 m/s in perpendicular direction
Impulse is given as change in momentum;
initial momentum in horizontal direction, Pi = mu
Pi = 0.14 x 40 = 5.6 Ns
final momentum in perpendicular direction, Pf = mv
Pf = 0.14 x 30
Pf = 4.2 Ns
The resultant impulse is given by;
J² = 5.6² + 4.2²
J² = 49
J = √49
J = 7.0 Ns
Therefore, the magnitude of the impulse delivered to the baseball is 7.0 Ns
Which describes an image that a concave mirror can make?
A. The image is always virtual.
B. The image can be either virtual or real.
C. The image is never upside down.
D. The image can only be the same size as the object.
Answer:
A
Explanation:
The image formed by the concave mirror is always virtual. An enlarged image is caused when the concave mirror is positioned too near to the object.
What is a concave mirror?When a hollow spherical is divided into pieces and the exterior surface of each cut portion is painted, it forms a mirror, with the inner surface reflecting the light.
A concave mirror is a name for this sort of mirror. An enlarged and fake image is caused when the concave mirror is positioned too near to the object.
When the distance between the item and the mirror is increased, however, the size of the image decreases, and a true picture is generated.
The picture created by the concave mirror may be manipulated. The image formed by the concave mirror is always virtual.
Hence, option A is correct.
To learn more about the concave mirror, refer to the link;
https://brainly.com/question/25937699
#SPJ2
A 16-V battery powers a series circuit that contains two lightbulbs The
voltage across the first lightbulb is 12-V
Complete question:
A 16-V battery powers a series circuit that contains two lightbulbs. The voltage across the first lightbulb is 12-V.
a. What fractional part of the circuit's total energy is transformed in the first lightbulb? Simply your answer.
b. What fractional part of the circuit's total energy is transformed in the second lightbulb? Simply your answer.
Answer:
(a) Fraction of energy of the first bulb in the total energy of circuit is 3/4
(b) Fraction of energy of the second bulb in the total energy of circuit is 1/4
Explanation:
Given;
total voltage across the series circuit, [tex]V_T[/tex] = 16 V
voltage across the first light bulb, V₁ = 12 V
The voltage across the second light bulb is given by;
V₂ = [tex]V_T[/tex] - V₁
V₂ = 16 V - 12 V
V₂ = 4 V
The total power across the circuit is given by;
P = I[tex]V_T[/tex]
P = 16I
Where;
I is the constant current in the circuit
(a)
power in the first light bulb is given by;
P₁ = 12I
Fraction of this power in the total energy of circuit is given by;
[tex]\frac{P_1}{P} = \frac{12I}{16I} = \frac{3}{4}[/tex]
(b)
power in the second light bulb is given by;
P₂ = 4I
Fraction of this power in the total energy of circuit is given by;
[tex]\frac{P_2}{P} = \frac{4I}{16I} = \frac{1}{4}[/tex]
What is the density of the paint if the mass of a tin containing 5000 cm3 paint is 7 kg. If the mass of the empty tin, including the lid is 0.5 kg.
We are given:
Mass of the Paint bucket (with paint) = 7000 grams
Mass of the paint bucket (without paint) = 500 grams
Volume of Paint in the Bucket = 5000 cm³
Mass of Paint in the Bucket:
To get the mass of the paint in the bucket, we will subtract the mass of the bucket from the mass of the paint bucket (with paint)
Mass of Paint = Mass of Paint bucket (with paint) - Mass of the paint Bucket (without paint)
Mass of Paint = 7000 - 500
Mass of Paint = 6500 grams
Density of the Paint:
We know that density = Mass / Volume
Density of Paint = Mass of Paint / Volume occupied by Paint
Density of Paint = 6500/5000
Density of Paint = 1.3 grams / cm³
If you push a heavy box at rest, you must exert some force before it begins to move. Once its moving, you don’t have to as much force. Which of Newton’s three laws explains this?
Answer:
momentum does
Explanation:
Calculate the velocity of an object moved around a circle with a radius of 1.65 m and an
acceleration of 3.5 m/s2.
Answer:
2.4m
Explanation:
Given parameters:
Radius of circle = 1.65m
Acceleration = 3.5m/s²
Unknown:
Velocity of the object = ?
Solution:
To solve this problem, we have to apply the formula of centripetal acceleration;
Centripetal acceleration = [tex]\frac{v^{2} }{r}[/tex]
v is the velocity
r is the radius
v² = centripetal acceleration x radius
Insert parameters and solve;
v² = 3.5 x 1.65
v = √5.775 = 2.4m
The velocity of the object as it moves around a circle with the given radius and acceleration is 2.4m/s.
Given the data in the question;
Radius; [tex]r = 1.65m[/tex]Centripetal acceleration; [tex]a_c = 3.5m/s^2[/tex]Velocity; [tex]v = \ ?[/tex]
From the centripetal force equation, we use the expression for centripetal acceleration:
[tex]a_c = \frac{v^2}{r}[/tex]
Where [tex]a_c[/tex] is the centripetal acceleration, v is the velocity and r is radius.
We substitute our given values into the equation
[tex]3.5m/s^2 = \frac{v^2}{1.65m} \\\\v^2 = 3.5m/s^2\ *\ 1.65m\\\\v^2 = 5.775m^2/s^2\\\\v = \sqrt{5.775m^2/s^2} \\\\v = 2.4m/s[/tex]
Therefore, the velocity of the object as it moves around a circle with the given radius and acceleration is 2.4m/s.
Learn more: https://brainly.com/question/17689540
If the brakes are applied and the speed of the car is reduced to 13 m/s in 14 s, determine the constant deceleration of the car.Express your answer to three significant figures and include the appropriate units. Assume ais negative if it acts in the opposite sense to the positive velocity.
Answer:
Explanation:
v = u + at
v is final velocity , u is initial velocity , a is acceleration and t is time .
here v = 0 , u = 13 m /s , t = 14 s
putting the values
0 = 13 + 14 a
a = 13 / 14 m /s²
= - .9286
= - 0.929 m /s²
a bowling ball hits two standing bowling pins at the same time. which of the following is true. assume that all collisions are elastic
Answer:
b?
Explanation:
Explain the "war of the currents"
Answer:
the war of currents is
Explanation:
The war of currents was a series of events surrounding the introduction of competing electric power transmission systems in the late 1880s and early 1890s.
Answer:
a series of events surrounding the introduction of competing electric power transmission systems in the late 1880s and early 1890s
Explanation:
The Amazon rainforest has millions of trees down in South America. Pantanal, the largest wetland, or swamp, on Earth sits directly below the Amazon on a map. Explain this phenomenon using processes from the water cycle.
The subject is science just to let you know.
Answer:The Pantanal is, when the season changes of the river flow, the pantanal shrinks after a few river channels The amazon rainforest has a lot of trees.The vapor rises and condenses it into clouds.Water leaves the forest and comes back, the amazon leaves itself.If the amazon water was not to go by itself everything would be different.
Answer:
Nine, Brazil, Venezuela
Explanation:
A 1,200 kg roller coaster car starts rolling up a slope at a speed of 15 m/s. What is the highest point it could reach?
Answer:
11.48 m
Explanation:
The following data were obtained from the question:
Mass (m) of the roller coaster = 1200 Kg
Initial velocity (u) = 15 m/s.
Final velocity (v) = 0 m/s (at highest point)
Acceleration due to gravity (g) = 9.8 m/s²
Highest point (h) =?
The highest point reached by the roller coaster can be obtained as illustrated below:
h = u²/2g
h = 15² / 2 × 9.8
h = 225/19.6
h = 11.48 m
Therefore, the highest point reached by the roller-coaster is 11.48 m
At which temperature are the particles in a pencil moving faster: 20°C or 50°C?
Answer:
movement generates energy=heat so 50c should be it
pls answer this
quick as possible
Answer:
The answer is the 4th one
Explanation:
Good luck man
What is the magnitude of the tangential acceleration of a bug on the rim of a 13.0-in.-diameter disk if the disk accelerates uniformly from rest to an angular speed of 79.0 rev/min in 3.80 s
Answer:
The correct solution will be "12.48 in/s²".
Explanation:
The given values are:
Angular speed
= 79.0 rev/min
Time
= 3.80 seconds
Now,
⇒ [tex]Angular \ acc.=\frac{(\frac{79\times 2\times \pi}{60})}{3.8}[/tex]
[tex]=\frac{8.2}{3.8}[/tex]
[tex]=2.1 \ rad/s^2[/tex]
Tangential acceleration will be:
= [tex]Angular acc.\times radius[/tex]
= [tex]2.1\times 6.5\times 0.0254[/tex]
= [tex]0.3467 \ m/s^2[/tex]
= [tex]12.48 \ in/s^2[/tex]
QUESTION 13
Marci would describe almost a perfect person whenever her friends would ask her who she thought was
her ideal life partner. This "perfect" person would be ain)
O a prototype
b.reinforcer
oc. anagram
d. heuristic