Help me find the radius please

Answer:

the circumfrence is the diameter times pi so if the diameter was 3 you would time that by 3.14 to get the circumfrence hope that helps

Step-by-step explanation:

The circumference of the scaled copy is half the circumference of the original circle.

The area of the scaled circle is half the area of the original circle.

A scale factor is defined as the ratio between the scale of a given original object and a new object,

We have,

Let the radius of the circle = r

The circumference of the circle = 2πr

The area of a circle = πr²

Now,

Scale factor = Original circle / Scaled circle

Now,

Scale factor = 2

2 = Circumference of the Original circle / Circumference of the Scaled circle

Circumference of the Scaled circle = (1/2) Circumference of the Original circle

Again,

Scale factor = 2

2 = Area of the Original circle / Area of the Scaled circle

Area of the scaled circle = (1/2) Area of the original circle

Thus,

The circumference of the scaled copy is half the circumference of the original circle.

The area of the scaled circle is half the area of the original circle.

Learn more about scale factors here:

https://brainly.com/question/20759556

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Answer:

i dont onderstand Thais

Standard form:

x - y = 7

Factored form:

y = x - 7

Answer:

y = x - 3 - 4

y = x - 7

(x - 7 = y)

(x = y + 7)

Step-by-step explanation:

Hope you got it.

Answer:

x = 2 + 2i, x = 2 - 2i

Step-by-step explanation:

[tex] {x}^{2} - 4x + 8 = 0 \\ \\ {x}^{2} - 4x + 4 + 4= 0 \\ \\ {x}^{2} - 4x + {(2)}^{2} = - 4 \\ \\ {(x - 2)}^{2} = - 4 \\ \\ x - 2 = \pm \sqrt{ - 4} \\ \\ x - 2 = 2i \\ \\ x = 2 \pm 2i \\ \\ x = 2 + 2i, \: \: \: x = 2 - 2i[/tex]

Answer:

x = -1, 0, 1, 2, 3, 4

y = 3, 2, 1, 0, -1, -2

Answer:

x = -1, 0, 1, 2, 3, 4

y = 3, 2, 1, 0, -1, -2

Answer:

[tex] - \frac{x + 2a}{3a + x} [/tex]

Step-by-step explanation:

[tex] \frac{ {x + ax - 2 {a}}^{2} }{3a {}^{2} - 2ax - {x}^{2} } [/tex]

i) write ax as a difference

[tex] \frac{ {x}^{2} + 2ax - ax - 2 {a}^{2} }{3 {a}^{2} - 2ax - x {}^{2} } [/tex]

ii) write -2ax as a difference

[tex] \frac{ {x}^{2} + 2ax - ax - 2a {}^{2} }{3a {}^{2} + ax - 3ax - x {}^{2} } [/tex]

iii) factor out x from the expression

[tex] \frac{x(x + 2a) - ax - 2 {a}^{2} }{3 {a}^{2} + ax - 3ax - {x}^{2} } [/tex]

iv) factor out -a from the expression

[tex] \frac{x(x + 2a) - a(x + 2a)}{3 {a}^{2} + ax - 3ax - {x}^{2} } [/tex]

v) factor out a from the expression

[tex] \frac{x(x + 2a) - a(x + 2a)}{a(3a + x) - 3ax - {x}^{2} } [/tex]

vi) factor out -x from the expression

[tex] \frac{x(x + 2a) - a(x + 2a)}{a(3a + x) - x(3a + x)} [/tex]

vii) factor out x+2a from the expression

[tex] \frac{(x + 2a)(x - a)}{a(3a + x) - x(3a + x)} [/tex]

viii) factor out 3a+x from the expression

[tex] \frac{(x + 2a)(x - a)}{(3a + x)(a - x)} [/tex]

ix) factor out the negative sign from the expression and rearrange the term

[tex] \frac{(x + 2a)( - ( - a - x))}{(3a + x)(a - x)} [/tex]

x) reduce the fraction a-x

[tex] \frac{(x + 2a)( - 1)}{(3a + x)} [/tex]

[tex] - \frac{x + 2a}{3a + x} [/tex]

Answer:

Step-by-step explanation:

First of all, we will sort the data.

185 227 234 245 278 278 279 281 281 291 299

Mean:

Mean is defined as the sum of values divided by the number of values.

n = 11

[tex]Mean = \frac{sum}{n}\\= \frac{185+227 +234+ 245+ 278+ 278+ 279+ 281+ 281+ 291+ 299}{11}\\=\frac{2878}{11}\\=261.63\ pounds[/tex]

Median:

As the number of values is odd,

The median will be:

[tex]Median = (\frac{n+1}{2})th\ value\\= \frac{11+1}{2}\\=\frac{12}{2}\\=6th\ value[/tex]

The 6th value is 278

Median = 278

Mode:

Mode is the most frequent value in a data set.

In the given dataset,

278 and 281 are modes as both are repeated twice

Mid-range:

Mid-range is the average of maximum and minimum value

So,

Min = 185

Max = 299

So,

[tex]Mid-range = \frac{Max+Min}{2}\\= \frac{185+299}{2}\\= \frac{484}{2}\\= 242[/tex]

Hence,

im guessing 800 50X4 = 200 and 200X4 = 800

i never learned this but i hope its correct.

the answer will be 2.5 hope that helps you

Answer:

2.5 or in other terms 2 1/2

Step-by-step explanation:

Answer:

Explicación más abajo

Step-by-step explanation:

Integración Indefinida

La integral

[tex]I=\int \dfrac{x .arcsen\left(x\right)}{\sqrt{1-x^2}}[/tex]

Se resuelve con el cambio de variables:

t=arcsen(x)

Una vez hechos los cambios, la integral se resuelve en función de t:

[tex]I=sen(t)-t.cos(t)+C[/tex]

Hay que devolver los cambios para mostrarla en función de x.

El cambio de variables también se puede escribir:

x=sen(t)

Recordando que

[tex]cos(t)=\sqrt{1-sen^2(t)}[/tex]

Entonces:

[tex]cos(t)=\sqrt{1-x^2}[/tex]

Devolviendo los cambios:

[tex]I=sen(t)-t.cos(t)+C=x-arcsen(x)\sqrt{1-x^2}+C[/tex]

Es la respuesta correcta

Answer:

Y = 3x - 6

Step-by-step explanation:

- 3y = -9x + 18

divide by -3

y = 3x - 6

Answer:

[tex]\frac{2}{3}[/tex]

Step-by-step explanation:

To find the slope, you need to find the [tex]\frac{rise}{run}[/tex] between two points.

[tex]\frac{rise}{run}[/tex] = [tex]\frac{7-1}{3-(-3)}[/tex]

     = [tex]\frac{7-1}{3+3}[/tex]

     = [tex]\frac{6}{9}[/tex]

     = [tex]\frac{2}{3}[/tex]

Answer:

To calculate slope with any two given points the formula is y2 - y1 / x2 - x1. So to solve the problem just plug in the values: 7 - 1 / 3 - (-3),  6 / 6, the slope is 1

Answer:

If point C lies between two points A and B such that AC=BC, then point C is the bisector of A and B, that means it is at right the centre.

Answer:

-7d-14

Step-by-step explanation:

First, let's distribute -7 to (d+2)

-7xd

-7x2

We will get -7d-14

Answer:

I just saw a girl post the nastiest nu!des EVER

Answer:

If the segments AU and UT are equal then AT equals 66, if the segments are not equal then AT equals 6x+24. Depends on what you are learning. Use what you need!

Step-by-step explanation:

4x+5 = 2x+19

2x=14

x=7

4(7)+5+2(7)+19 = 42+24 = 66

Answer: 22

Step-by-step explanation: 65 divided by 3 is 22

Answer:

21or22

Step-by-step explanation:

65/3

Answer:

Because even and odd are 2 different ways to determine whether or not you get the right answer for the chosen function.

Step-by-step explanation:

Hope this helps!!!

Answer:

For even functions, we take f(-x) to be the starting function. The y-axis reflection of this function is f(-(-x)), which is equal tof(x). So the relationship f(-x) = f(x) means that the function is the same as its y-axis reflection.

For odd functions, there are two reflections that must occur. First, we start with f(-x). The y-axis reflection of this function is f(-(-x)) = f(x). When we apply an x-axis reflection to this result, we get -f(-(-x)) = -f(x). So the fact that f(-x) = -f(x) means that odd functions are the same as sequential reflections across both the x-axis and the y-axis. (The same sequence of reflections also represents a rotation 180 degrees about the origin).

Step-by-step explanation:

Step-by-step explanation:

4 different vehicles,

2 different paints,

2 different seats.

Total number of combinations = 4 * 2 * 2 = 16.

Answer:talk some English dude

Step-by-step explanation:

Answer:

Hope this may helps you

Step-by-step explanation:

6×3(11)

6×33

198

Answer:

198

Step-by-step explanation:

6 ×3(2+9)

= 6×3×11

= 6×33

= 198

Answer:

28 i assume.

Answer:

The answer is 28% :))

Answer:

b:q

Step-by-step explanation:

im pretty sure its that. ive learned this before.

if you flipped them so that c and r were facing the same direction, then b and q would be too.

Answer:

[tex]\mathbf{P =\bigg (P_o +\dfrac{ I}{k} \bigg)e^{kt}- \dfrac{I}{k}}[/tex]

Step-by-step explanation:

Given that:

A country population at any given time (t) is:

[tex]\dfrac{dP}{dt}= kP+I[/tex]

where;

P = population at any time t

k = positive constant

I = constant rate of immigration into the country.

Using the method of separation of the variable;

[tex]\dfrac{dP}{kP+1}= dt[/tex]

Taking integration on both sides:

[tex]\int \dfrac{dP}{kP+I}= \int \ dt[/tex]

[tex]\dfrac{1}{k} log (kP + I) = t+c_1 \ \ \ here: c_1 = constant \ of \ integration[/tex]

[tex]log (kP + I) =k t+kc_1[/tex]

By applying the exponential on both sides;

[tex]e^{log (kP + I) }=e^{k t+kc_1 }[/tex]

[tex]KP+I = e^{kt} *e^{kc_1}[/tex]

Assume [tex]e^{kc_1 }= C[/tex]

Then:

[tex]kP + I = Ce^{kt}[/tex]

[tex]kP = Ce^{kt}-I[/tex]

[tex]P =\dfrac{ Ce^{kt}-I}{k} \ \ \---- Let \ that \ be \ equation \ (1)[/tex]

When time t = 0, The Total population of the country is also [tex]P_o[/tex]

[tex]P_o = \dfrac{Ce^{0(t)} -I}{k}[/tex]

[tex]P_o = \dfrac{Ce^{0} -I}{k}[/tex]

[tex]P_o = \dfrac{C-I}{k}[/tex]

C - I = kP₀

C =  kP₀ + I

Substituting the value of C back into equation(1), we have:

[tex]P =\dfrac{ (kP_o+1)e^{kt}-I}{k}[/tex]

[tex]P =\dfrac{ (kP_o+1)e^{kt}}{k} - \dfrac{I}{k}[/tex]

[tex]\mathbf{P =\bigg (P_o +\dfrac{ I}{k} \bigg)e^{kt}- \dfrac{I}{k}}[/tex]