Answer:
Step-by-step explanation:
these functions are both straight lines with a slope of 1
f(x) = x passes through the origin (0,0)
h(x) = x-4 is parallel to f(x) = x and passes through the y axis at (0, -4) and is below the line f(x) = x
A composite figure is formed by placing a half-sphere atop a cylinder. The half-sphere and the cylinder both have a radius of 3 centimeters. The height of the cylinder is 10 centimeters.
What is the exact volume of the composite figure?
Enter your answer in the box.
_cm³
The volume of the composite figure can be divided into two separate figures: a cylinder and a half-sphere, with the total volume being 108 cubic centimeters.
What is the exact volume of the composite figure?The composite figure can be divided into two separate figures: a cylinder and a half-sphere.
The formula for the volume of a cylinder is:
Volume of the cylinder = π[tex]r^2[/tex]h, where r is the radius of the cylinder and h is the height of the cylinder.
In this case, the radius of the cylinder is 3 centimeters and the height of the cylinder is 10 centimeters, so the volume of the cylinder is:
Volume of the cylinder = π[tex](3cm)^2(10cm)[/tex] = 90π [tex]cm^3[/tex]
The formula for the volume of a half-sphere is:
Volume of half-sphere = (2/3)π[tex]r^3[/tex], where r is the radius of the half-sphere.
In this case, the radius of the half-sphere is also 3 centimeters, so the volume of the half-sphere is:
Volume of half-sphere = (2/3)π[tex](3cm)^3[/tex] = 18π [tex]cm^3[/tex]
To find the total volume of the composite figure, we add the volume of the cylinder and the volume of the half-sphere:
Total volume = Volume of cylinder + Volume of half-sphere
Total volume = 90π [tex]cm^3[/tex] + 18π [tex]cm^3[/tex]
Total volume = 108π [tex]cm^3[/tex]
Therefore, the exact volume of the composite figure is 108π cubic centimeters.
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A
P. Alex works as one of three unpaid interns at an office for
college credit. She does the work that the company would
otherwise pay an employee $12 per hour to do. If the
office is open for 8 hours in a day, and if Alex works for
the full day on each of the 20 workdays in a month, how
much money does the company save per month by having
Alex work instead of a paid employee?
After calculations, we find that the company saves a total of $12 x 160 = $1,920 per month by having Alex work instead of a paid employee.
In this scenario, the company has three unpaid interns, including P. Alex, who are working in exchange for college credit. This means that the company does not have to pay these interns any salary or wages.
If the company were to hire a paid employee instead of having an intern like Alex work, they would have to pay that employee $12 per hour for the work that needs to be done. This is the amount that the company would have to spend in wages for each hour worked by the employee.
Now, we know that Alex works for the full 8 hours per day, and for 20 workdays in a month. This means that she works a total of 8 x 20 = 160 hours in a month.
Therefore, the total amount of money the company would have to pay a paid employee for the same amount of work that Alex does would be $12 per hour x 160 hours = $1,920.
Since Alex is working for the company without any payment, the company saves the entire amount of $1,920 per month that they would have had to pay a paid employee to do the same work.
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You are going to use an incline plane to lift a heavy object to the top of a shelving unit with a height of 8 ft. The base of the incline plane is 9 ft from the shelving unit. What is the length of the incline plane?
Check the picture below.
[tex]\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ c^2=a^2+o^2\implies c=\sqrt{a^2 + o^2} \end{array} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{9}\\ o=\stackrel{opposite}{8} \end{cases} \\\\\\ c=\sqrt{ 9^2 + 8^2}\implies c=\sqrt{ 81 + 64 } \implies c=\sqrt{ 145 }\implies c\approx 12.04~ft[/tex]
Given: ABCD is a parallelogram, E is the midpoint of overline AB and F is the midpoint of overline DC. Prove: overline DE ≌ overline FB.
Therefore , the solution of the given problem of parallelograms comes out to be s intended, overline DE and overline FB are congruent.
How do parallelograms function?In Euclidean mathematics, a simple quadrilateral of two sets of equal distances is referred to as a parallelogram. In a specific kind of quadrilateral known as a parallelogram, both set of opposite sides are straight and equal. There are four types of parallelograms, 3 of which are each mutually exclusive. Rhombuses, parallelograms, squares, but also rectangles are the four distinct shapes.
Here,
We can use the midpoint theorem and the fact that the opposing sides of a parallelogram are parallel and congruent to demonstrate that overline DE is congruent with overline FB.
The midpoint theory tells us that DE EA because we first know that E is the midpoint of overline AB.
The midpoint theory tells us that BF FC because we also know that F is the midpoint of overline DC.
As a result, overline DE and overline BC are parallel, and overline BF and overline AD are parallel.
DE EA and BF FC resulted in:
=> FC = EA Plus DE (Preserving equality by adding identical lengths)
If we replace FC with EA and DE with BF, we get:
=> BF + FC = DE + DE
If we simplify, we get:
=> 2DE = 2BF
When you divide both parts by 2, you get:
=> DE = BF
We have thus demonstrated that, as intended, overline DE and overline FB are congruent.
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In △PQR, the length of PQ⎯⎯⎯⎯⎯ is 16 units. A series of midsegments are drawn such that ST⎯⎯⎯⎯⎯ is the midsegment of △PQR, UV⎯⎯⎯⎯⎯⎯ is the midsegment of △STR, and WX⎯⎯⎯⎯⎯⎯ is the midsegment of △UVR
The length of PQ is 16 units. ST is the midsegment of PQR, UV is the midsegment of STR, and WX is the midsegment of UVR. It is reasonable to assume that the three midsegments have equal lengths since they are part of the same triangle.
In a triangle, the midsegment is a line segment that connects the midpoints of two sides of the triangle and is parallel to the third side. In the given triangle PQR, the length of PQ is 16 units. ST is the midsegment of PQR, UV is the midsegment of STR, and WX is the midsegment of UVR. Since all the midsegments are part of the same triangle, it is reasonable to assume that they have equal lengths. The triangle midsegment theorem, which asserts that the length of a triangle's midsegment is equal to half of the length of the third side of the triangle, may be used to demonstrate this.. In this case, the length of ST, UV, and WX would all be equal to 8 units, since the third side of each triangle is 16 units. This indicates that it is reasonable to assume that the midsegments of the triangle have equal lengths.
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what is 10 divided by 1/5
The costs of repairing iPads in UAE are normally distributed with a mean of 173 Dhs. If
3%
of the costs exceed 243 Dhs, find the standard deviation of the costs. Round your answer to the nearest diham (Whole number).
The standard deviation of the costs is 37 Dhs
The given mean is 173 and 3% of costs exceed 243. We have to calculate the standard deviation of the cost. Therefore, let's first start by calculating the z-score as follows;z-score formula = `(x - μ) / σ`z-score = `243 - 173 / σ`z-score = `70 / σ`We need to find the standard deviation of the costs. Since the z-score formula includes standard deviation, we can first calculate the z-score and then use it to calculate the standard deviation.Using the z-table, we can find the z-score for 3% = -1.88-1.88 = (243 - 173) / σσ = (243 - 173) / -1.88σ = -70 / -1.88σ = 37.23≈ 37The standard deviation of the costs is 37 Dhs. Hence, the correct option is as follows.Option D is the correct option.
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In the Kite ABCD AP= 6 mm, PB= 63‾√3
mm, PD = 7 mm, find the area to the nearest tenth
The area of the given kite to the nearest tenth would be = 135.10mm².
How to calculate the area of a kite?A kite is defined as the type of quadrilateral that has two pairs of sides that are equal in length and which are adjacent to each other.
To calculate the area of the kite given such as ABCD, the formula = ½ × AC × BD.
Given the sides such as:
AP = 6 mm
PB = 6√3 mm
PD = 7mm
But AC = 6mm × 2 = 12mm
BD = 6√3+7 = 13√3mm
Therefore the area = 1/2 × 12× 13√3
= 6×13√3
= 135.10mm²
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Myesha has a bag that contains orange chews, lemon chews, and lime chews. She performs an experiment. Myesha randomly removes a chew from the bag, records the result, and returns the chew to the bag. Myesha performs the experiment 17 times. The results are shown below:
A orange chew was selected 12 times.
A lemon chew was selected 2 times.
A lime chew was selected 3 times.
Based on these results, express the probability that the next chew Myesha removes from the bag will be a flavor other than lime as a percent to the nearest whole number.
The probability that the next chew Myesha removes from the bag will be a flavor other than lime is 82%.
What is probability?
Probability is the measure of the likelihood or chance of an event occurring. It is a numerical value between 0 and 1, where 0 indicates that the event is impossible and 1 indicates that the event is certain to occur. Probabilities between 0 and 1 represent the degree of uncertainty about whether the event will occur or not.
Out of the 17 times Myesha performed the experiment, a lime chew was selected 3 times. Therefore, the probability that the next chew Myesha removes from the bag will be a lime chew is 3/17.
To find the probability that the next chew Myesha removes from the bag will be a flavor other than lime, we need to subtract the probability of getting a lime chew from 1.
P(flavor other than lime) = 1 - P(lime)
P(flavor other than lime) = 1 - 3/17
P(flavor other than lime) = 14/17
To express this probability as a percent to the nearest whole number, we multiply by 100 and round to the nearest integer:
P(flavor other than lime) = 14/17 x 100
P(flavor other than lime) = 82.35
P(flavor other than lime) ≈ 82%
Therefore, the probability that the next chew Myesha removes from the bag will be a flavor other than lime is approximately 82%.
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6 poini(s) The geomerric mean ral places as necimal ped tho The value of this stock at cent as nee ded (Round to the nearest c. Compare the rese correct answ choos chour choice. A. The value c. Compare the result of (b) to the value of the $1,000 of the social media stock, Choose the correct answer below and fill in the answer box to complete your choice. (Round to the nearest cent as needed. A. The value of the $1,000 invested in the conglomerate corporation's stock in 2014 was greater than that of the value of the $1,000 invested in the social media stock. The conglomerate corporation's stock would earn \$ more than the social media's stock. B. The value of the $1,000 invested in the conglomerate corporation's stock in 2014 was less than that of the value of the $1,000 invested in the social media stock. The social media stock would earn $ more than the conglomerate corporation's stock.
The social media stock would earn $ more than the conglomerate corporation's stock.
When answering questions on Brainly, it is important to always be factually accurate, professional, and friendly, be concise and not provide extraneous amounts of detail, repeat the question in your answer, provide a step-by-step explanation in your answer, and use the following terms in your answer: geometric, Compare, invested.The value of a conglomerate corporation's stock was $1,145 in 2014.
If $1,000 were invested in this stock, what would its value be in 2017 if the stock had increased 3.5% annually?The solution to the given problem is as follows:Calculate the value of the stock when $1,000 was invested in 2014.Using the geometric mean formula,$\text{Geometric mean} = \sqrt[n]{a_1a_2a_3\cdots a_n}$Here, $n = 3$ since the value is given for the years 2014, 2015, and 2016. $a_1 =$ the value of the stock in 2014, $a_2 =$ the value of the stock in 2015, and $a_3 =$ the value of the stock in 2016.
We have to find $a_1$.Solve for $a_1:$\[a_1 = \frac{\text{Geometric mean}}{\sqrt[n-1]{a_2a_3\cdots a_n}} = \frac{\sqrt[3]{1145}}{\sqrt[2]{1.035^2}} \approx 1042.97\]Therefore, the value of the stock when $1,000$ was invested in 2014 was approximately $1,042.97$.
Calculate the value of the stock in 2017.Using the same formula as before, we have:\[\text{Geometric mean} = \sqrt[3]{1042.97 \cdot 1.035 \cdot 1.035} \approx 1,124.54\]Therefore, the value of the stock in 2017 would be approximately $1,124.54$ dollars.Compare the results obtained from the above two parts to the value of $1,000$ of the social media stock.
The value of $1,000$ of the social media stock after three years with a 7% annual increase is given by:\[\text{Social media stock} = 1000 \cdot (1 + 0.07)^3 \approx 1225.04\]Therefore, we can compare the results obtained from the two previous parts to see which one is greater. It is clear that the social media stock value of $1,000$ is greater than that of the conglomerate corporation's stock. Therefore, the correct answer is:The value of the $1,000 invested in the conglomerate corporation's stock in 2014 was less than that of the value of the $1,000 invested in the social media stock. The social media stock would earn $ more than the conglomerate corporation's stock.
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A small country consists of five states (A, B, C, D, and E). The total population of the country is 24.4 million. According to the country's constitution, the seats in the legislature are apportioned to the states according to their populations. The table below shows each state's standard quota. Find the apportionment under Hamilton's method.
Therefore, the apportionment under Hamilton's method is:
State Apportionment
A 18
B 22
C 13
D 30
E 17
What is Hamilton's method?
To use Hamilton's method, we need to calculate each state's priority by dividing its population by the geometric mean of its current seat and the next higher integer seat.
Then, we assign seats based on priority until we reach the total number of seats (in this case, 100).
State Population Standard Quota
A 5.6 18
B 6.8 22
C 3.6 12
D 3.2 10
E 5.2 17
To calculate priorities, we first find the geometric mean of the current seat and the next higher integer seat for each state:
State A: sqrt(18*19) ≈ 18.49
State B: sqrt(22*23) ≈ 22.94
State C: sqrt(12*13) ≈ 12.68
State D: sqrt(10*11) ≈ 10.49
State E: sqrt(17*18) ≈ 17.89
Then, we divide each state's population by its corresponding priority:
State A: 5.6/18.49 ≈ 0.303
State B: 6.8/22.94 ≈ 0.296
State C: 3.6/12.68 ≈ 0.284
State D: 3.2/10.49 ≈ 0.305
State E: 5.2/17.89 ≈ 0.291
We then assign seats based on priority, starting with the highest priority and rounding down to the nearest integer:
State D: 30 seats
State A: 18 seats
State E: 17 seats
State B: 22 seats
State C: 13 seats
This adds up to 100 seats, as required.
Therefore, the apportionment under Hamilton's method is:
State Apportionment
A 18
B 22
C 13
D 30
E 17
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Question 6, 1.6.75 Solve the absolute value equation or indicate that th |7x-4|+5=5
x = -1/7.
To solve the absolute value equation or indicate that th |7x-4|+5=5, you should follow the steps given below:Step 1: Write the absolute value equation as two separate equations, one with a positive argument and one with a negative argument. |7x - 4| + 5 = 5, can be written as:7x - 4 + 5 = 5 or 7x - 4 - 5 = -5Step 2: Simplify both equations.7x = 4 or 7x = -1Step 3: Solve for x by dividing both sides by the coefficient of x.7x = 4 → x = 4/7 or7x = -1 → x = -1/7Therefore, the solution of the absolute value equation |7x-4|+5=5 is x = 4/7 and x = -1/7.
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A checking account has a balance of $350. A customer makes two withdrawals, one $50 more than the other. Then he makes a deposit of $75
The first withdrawal from the account is $200 and another is $150
A mathematical expression made up of variables, coefficients, constants, and operations like addition, subtraction, multiplication, and division is called an algebraic expression. In general, something is considered equal if two of them are the same. Similar to this, analogous expressions in mathematics are those that hold true even when they appear to be different. Yet, both forms provide the same outcome when the values are entered into the formula.
A checking account has a balance of $350
A customer makes two withdrawals
first is $50 more than the other,
let another withdrawal is $x
then first withdrawal is $(50+x)
then,
x+(50+x)=350
2x=300
x=$150
hence first withdrawal is $200
and another is $150
Then he makes a deposit of $75,
So the remaining balance in the account is $75.
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A kite is flying 85 ft off the ground, and its string is pulled taut. The angle of elevation of the kite is 58 . Find the length of the string. Round your answer to the nearest tenth.
The length of the string which is pulled taut as described in the task content is; 100.2 ft.
What is the length of the string?As evident in the task content; the kite is flying 85 ft off the ground, and the angle of elevation is; 58°.
It therefore, follows from trigonometric ratios that the ratio which holds true is;
sin (58°) = 85 / l
where l = Length of the string.
Therefore;
Multiply both sides by l;
l sin (58) = 85
Divide both sides by sin (58);
l = 85 / sin (58)
I = 100.2 ft (nearest tenth)
Ultimately, the length of the string as described in the task content is; 100.2 ft.
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I need help with this question if anyone knows it?
Answer:
the answer is 13700m²
Step-by-step explanation:
cut this shape in two parts namely
A and B
from my view it could be cut into 1. two triangles or 2. a triangle and a rectangle
I will pick 2 because it seems much more simpler
let the triangle be A
let the rectangle be B
firstly you have to cut it then separate the shape with name given when dis is done you'll have
for ∆A=length=170-70=100m
but in B the small place is 110m,but the bigger one is 160
so to find height of triangle we say
160m-110m=50m for h of A
so for B we have
length=160m, width of breath=70m
Area of the total shape=area of A + area of B
=1/2(b×h) + (L×B)
=1/2×100×50 + (160×70)
=50m×50m+11200m²
=2500+11200
=13700m²
Find the midpoint of the line segment AB if A = (7, 2) and B = (5, -4). ( with photo pls)
Answer:
(6, -1)
Step-by-step explanation:
The midpoint formula, (y2+y1)/2 and (x2+x1)/2 will help us find our answer. So (2-4)/2= -1 and (7+5)/2=6, so (6,-1) is the midpoint of segment AB.
Mail surveys have the concern of _____ but have the advantage of _____. Group of answer choices low return rate; eliminating interviewer bias interviewer bias; high return rate sampling bias; interviewer bias increasing socially desirable responses; high return rate
The correct option is a low return rate; eliminating interviewer bias. Mail surveys have the concern of low return rate but have the advantage of eliminating interviewer bias.
A mail survey is a form of a self-administered survey in which the questionnaire is sent to the respondent through the post. Mail surveys are convenient because they allow participants to respond on their schedule and in the privacy of their own homes.
Mail surveys have the concern of a low return rate but have the advantage of eliminating interviewer bias. The concern of mail surveys is a low return rate. One of the greatest advantages of mail surveys is that they do not require any interaction between the researcher and the respondent. Mail surveys' response rate is typically lower than phone or face-to-face surveys. However, it eliminates interviewer bias.
Interviewer bias occurs when the interviewer's characteristics or behavior have an impact on the participant's responses. Interviewer bias can occur in face-to-face interviews or phone surveys. Respondents may attempt to please the interviewer or present themselves in a more favorable light than they otherwise would in order to avoid social disapproval.
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Please help me answer my homework in the image
Answer:
C) Both pairs of opposite sides are parallel because mPN = mLM = (1/2) and mPL = mMN = - 2.
Step-by-step explanation:
The corners of a rectangle are all right angles. The two sets of sides are parallel. In this example:
PL ║ MN and
LM ║ NP
To prove that the corners are all right angles, we could compre the slopes of the two lines that form each corner. They will be perpendicular if they are 90°.
In this example:
PL ⊥ LM and
MN ⊥ NP
So one approach Sherry may have taken is to compare the slopes of all four lines. To prove the object is a rectangle she could show that:
1. The sets of parallel lines have equal slopes, and
2. The sets of perpendicular lines have slopes that are the negative inverse of each other. (e.g., if a line has slope 5, a perpendicular line will have slope -(1/5))
To prove these points, Sherry probably used a spreadsheet to calculate each line's slopes. See the attached spreadsheet for how she may have set up the calculations. The slopes are the Rise/Run for each line. Rise is the change in y and x is the change in x between the two points.
Note the green cells. These are the slopes. Sherry found that:
a) PL ║ MN and LM ║ NP, since PL and MN both have slopes of -2; and LM and NP both have slopes of -0.5
b) PL ⊥ LM and MN ⊥ NP, since PL and LM and MN and NP both have slopes that are the negative inverse of each other (-2 and -(1/-2) or 0.5)
These are the two conditions Sherry originally established as proof of a rectangle.Without having checked whether any of the other answer options are viable options, Sherry will likely have seen, and done, enough to have chosen option C as proof that quadrilateral PLMN is a rectangle.
Find the difference quotient of \( f \); that is, find \( \frac{f(x+h)-f(x)}{h}, h \neq 0 \), for the following function. Be sure to simplify. \[ f(x)=\frac{9}{x^{2}} \] The difference quotient for \(
The difference quotient of the given function is\[\frac{f(x+h) - f(x)}{h} = \frac{-2x - h}{x^2(x+h)^2}\]The given function is\[f(x) = \frac{9}{x^2}\]
Now we have to find the difference quotient of this function, which is given as\[\frac{f(x+h) - f(x)}{h}\]
We are given that \(h ≠ 0\).
So, first let's find \(f(x+h)\).\[f(x+h) = \frac{9}{(x+h)^2}\]
Now we can put both the values of \(f(x+h)\) and \(f(x)\) in the difference quotient.
\[\frac{f(x+h) - f(x)}{h} = \frac{\frac{9}{(x+h)^2} - \frac{9}{x^2}}{h}\]
Let's put the LCM of \((x+h)^2\) and \(x^2\) which is \(x^2(x+h)^2\) in the numerator.
\[\frac{\frac{9x^2 - 9(x+h)^2}{x^2(x+h)^2}}{h}\]
Now, simplify the numerator.
\[\frac{9x^2 - 9(x^2 + 2xh + h^2)}{x^2(x+h)^2h}\]\[\frac{9x^2 - 9x^2 - 18xh - 9h^2}{x^2(x+h)^2h}\]
Now we can cancel out the common factor of 9 from both numerator and denominator.
\[\frac{-2xh - h^2}{x^2(x+h)^2h}\]
Now cancel out h from both numerator and denominator.
\[\frac{-2x - h}{x^2(x+h)^2}\]
So, the difference quotient of the given function is\[\frac{f(x+h) - f(x)}{h} = \frac{-2x - h}{x^2(x+h)^2}\]
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Un granjero tiene pienso para alimentar a sus 12 vacas durante 45 días, si compra 3 vacas más, ¿Cuánto le durará el pienso?
He can feed 15 cows till 36 days because earlier he feed 12 cows till 42 days. So we see we uses the concepts inversely proportional.
What is inversely proportional?In this type of proportional is if their are two quantities then if first one is increase then automatically second one is decrease.
Suppose if a, b are two variables , and if they are indirectly proportional then we can write it as a ∝ 1/b , that means xy = k(where k is constant).
Let number of day be x days.
and, total number of cows = 12 + 3 (After he buy 3 more cow)
then, Number of cows and the number of days are inversely proportion.
So, we can write [tex]\frac{12}{15} = \frac{x}{45}[/tex]
[tex]= x * 15 = 12 * 45[/tex]
[tex]\implies x = 36\ days[/tex]
So, He can feed 15 cows till 36 days.
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Question in English :
A farmer has feed to feed his 12 cows for 45 days. if he buys 3 more cows, How long does the feed last?
On a standardized test with a normal distribution the mean score was 67. 2. The standard deviation was 4. 6. What percent of the data fell between 62. 6 and 71. 8?
Question 2 options:
95%
68%
4. 6%
13. 2%
The total percent of the data falling between 62. 6 and 71. 8 is around 68%
Mean score = 67.2
Standard deviation = 4.6
Standardizing the values of interest by converting them into z-scores by -
z = (x - μ) / σ
where x is the score, μ is the mean, and σ is the standard deviation.
Calculating for the lower bound of 62.6:
z1
= (62.6 - 67.2) / 4.6
= - 4.6/4.6
= -1
Similarly,
Calculating for the upper bound of 71.8:
z2
= (71.8 - 67.2) / 4.6
= 4.6/4.6
= 1
Getting the area under curve between these two z-scores using a table of common normal probability. The normal distribution is symmetric, thus, the area between z1 and z2, can be then subtracted from the area to the left of z2. The Left of z1 is an area of 0.1587 and the left of z2 is an area of 0.8413. Therefore, the area between z1 and z2 is:
= 0.8413 - 0.1587
= 0.6826
Converting this area to a percentage -
0.6826 × 100%
= 68.26%
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Drag the number cards so that the values of x are as small as possible
By dragging the number cards to form the lowest sum possible and substituting that sum into the formula for x, we can make the value of x as small as possible.
The formula for x is x = (a + b + c + d)/4. In order to minimize the value of x, we should aim to make the sum of a, b, c, and d as small as possible. To do this, we can drag the number cards to form the lowest sum possible. For example, if the number cards are 5, 6, 7, and 8, we can drag them to form the sum of 26 (5 + 6 + 7 + 8 = 26). To calculate the value of x, we can substitute the sum of the numbers in the formula and divide it by 4. In this example, x = (26/4) = 6.5. By using this strategy, we can minimize the value of x and make it as small as possible.
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Complete question:
What is the smallest value for x when you drag the number cards?
What is the area of this trapezoid? Enter your answer in the box. Ft²
Trapezoid with parallel sides labeled 13 feet and 31 feet. The dashed perpendicular
segment between them is labeled 16 feet
The area of the given trapezoid would be 176 feet² with the length of the parallel sides of the trapezoid is 13 feet and 31 feet respectively and the height of the trapezoid given is 16 feet.
Given that,
The length of the parallel sides of the trapezoid is 13 feet and 31 feet
The height of the trapezoid given is 16 feet.
We know that area of trapezoid is (a+b)×h/2
Where, (a) and (b) are Length of the parallel sides of trapezoid and h is the height of trapezoid.
Thus, Area = (13+31) × 16/2
Area = 22×8
Area = 176 feet²
Hence the area of the given trapezoid would be 176 feet² with the length of the parallel sides of the trapezoid is 13 feet and 31 feet respectively and the height of the trapezoid given is 16 feet.
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Calculate the perimeter of the following.
The perimeter of the figure is 52 cm
How to determine the perimeter of the figureFrom the question, we have the following parameters that can be used in our computation:
The composite figure
The perimeter of the figure is the sum of the side lengths of the figure
So, we start by calculating the missing lengths as follows
Missing = 12 cm/4
Missing = 3 cm
Using the above as a guide, we have the following:
Perimeter = 12 + 9 + 3 + 3 + 3 + 3 + 3 + 3 + 7 + 9 - 3
Evaluate
Perimeter = 52
Hence, the perimeter is 52 cm
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solve with explanation
[tex] \frac{x - 4}{2(x - 3)} - \frac{x - 1}{2x} [/tex]
The simplified expression of (x - 4)/2(x - 3) - (x - 1)/2x is -3/(2x).
What is the simplification of the expression?
The given expression (x - 4)/2(x - 3) - (x - 1)/2x can be simplified to;
(x - 4)/(2x - 6) - (x - 1)/2x
To solve this expression, we need to first find a common denominator for the two fractions.
The least common multiple of the denominators 2x and 2x - 6 is;
2x( x - 3)
So we'll multiply the first fraction by (x - 3)/(x - 3) and the second fraction by (x - 3)/(x - 3) to get a common denominator:
((x - 4)/(2x - 6)) · ((x - 3)/(x - 3)) - ((x - 1)/(2x)) · ((x - 3)/(x - 3))
Now we can combine the numerators over the common denominator:
((x - 4)(x - 3) - (x - 1)(x - 3))/(2x(x - 3))
Expanding the parentheses and combining like terms, we get:
(x² - 7x + 12 - x² + 4x - 3)/(2x(x - 3))
Simplifying the numerator, we get:
(-3x + 9)/(2x(x - 3))
Now we can factor out a -3/2 and simplify:
(-3/2) · (x - 3)/(x(x - 3))
The (x - 3) terms cancel out, leaving us with:
(-3/2) · 1/x
= -3/(2x)
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Solve the quadratics attached using the quadratic formula or completing the square
[tex]n^2+9n+18[/tex]
Answer:
n = -3 or n = -6
Step-by-step explanation:
Solve for n over the real numbers:
n^2 + 9 n + 18 = 0
Subtract 18 from both sides:
n^2 + 9 n = -18
Add 81/4 to both sides:
n^2 + 9 n + 81/4 = 9/4
Write the left-hand side as a square:
(n + 9/2)^2 = 9/4
Take the square root of both sides:
n + 9/2 = 3/2 or n + 9/2 = -3/2
Subtract 9/2 from both sides:
n = -3 or n + 9/2 = -3/2
Subtract 9/2 from both sides:
Answer: n = -3 or n = -6
Mark horneó 195 galletas y las dividió en partes iguales en 13 paquetes. ¿Cuántas galletas puso Mark en cada paquete?
Answer:
Para saber cuántas galletas puso Mark en cada paquete, podemos dividir el número total de galletas por el número de paquetes:
195 galletas ÷ 13 paquetes = 15 galletas por paquete
Por lo tanto, Mark puso 15 galletas en cada paquete.
¡Espero que esto haya ayudado! Si no es así, lo siento. Si necesitas más ayuda, ¡pregúntame! :]
all the whole numbers that re greater than -4 but less than 3
Answer: -3, -2, -1, 0, 1 and 2
Answer:
0, 1, and 2
Step-by-step explanation:
A whole number is any number that does not contain a fraction, decimal, or negative value. For example, 1, 25, and 365 are whole numbers. Whereas the values of -3, 100.01, 365 ¼, and 2006.3 are not.
A retailer receives some products from three suppliers - S1, S2 and S3. The probability of successfully delivering the products in time by the suppliers are 0.85 for $1, 0.82 for $2 and 0.91 for S3. No supplier's delivery is impacted by any other supplier's delivery. The manufacturer orders 500 units of a raw material from $1, 120 units from $2 and 156 units from $3. What is the expected loss for the retailer given that failure to receive the materials in time will cost the manufacturer $20 per unit for the product supplied by S1, $30 for the product supplied by S2 and $10 for the product supplied by S3.
The expected loss for the retailer is $2288.4.
The retailer receives some products from three suppliers: S1, S2, and S3. The probability of successfully delivering the products in time by the suppliers are 0.85 for $1, 0.82 for $2, and 0.91 for S3. The manufacturer orders 500 units of a raw material from $1, 120 units from $2, and 156 units from $3. In case of failure to receive the materials in time, the manufacturer will bear $20 per unit for the product supplied by S1, $30 for the product supplied by S2, and $10 for the product supplied by S3. We have to calculate the expected loss for the retailer.
Let's calculate the expected loss for each supplier separately.Expected loss for supplier S1:Number of units ordered from S1 = 500The probability that the product will not be delivered in time = 1 - 0.85 = 0.15The expected loss per unit = $20Total expected loss for the products supplied by S1 = Expected loss per unit × Number of units ordered from S1 × Probability that the product will not be delivered in time= 20 × 500 × 0.15= $1500Expected loss for supplier S2:Number of units ordered from S2 = 120The probability that the product will not be delivered in time = 1 - 0.82 = 0.18
The expected loss per unit = $30Total expected loss for the products supplied by S2 = Expected loss per unit × Number of units ordered from S2 × Probability that the product will not be delivered in time= 30 × 120 × 0.18= $648 Expected loss for supplier S3:Number of units ordered from S3 = 156The probability that the product will not be delivered in time = 1 - 0.91 = 0.09The expected loss per unit = $10Total expected loss for the products supplied by S3 = Expected loss per unit × Number of units ordered from S3 × Probability that the product will not be delivered in time= 10 × 156 × 0.09= $140.4The total expected loss for the retailer = Expected loss for supplier S1 + Expected loss for supplier S2 + Expected loss for supplier S3= $1500 + $648 + $140.4= $2288.4
Hence, the expected loss for the retailer is $2288.4.
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Use the dot plots below----What is the mean height at Camp 1 (round to the nearest tenth) ?
The mean height of camp 1 is 2.5.
Define the term dοt plοts?A dοt plοt is a type οf graphical display that shοws the distributiοn οf a set οf data values. In a dοt plοt, each data pοint is represented by a dοt that is placed abοve its cοrrespοnding value οn a number line οr axis. The dοts are stacked οn tοp οf each οther tο shοw the frequency οr density οf the data at each value οr range οf values.
Dοt plοts are useful fοr visualizing small tο mοderate-sized data sets and fοr identifying patterns, οutliers, and gaps in the data. They are alsο easy tο cοnstruct and interpret, making them a pοpular tοοl fοr explοratοry data analysis.
Mean height of club fit = (2 + 2 + 3 + 5 + 3 + 3 + 1 + 1)/8
= 2.5
Thus, The mean height of camp 1 is 2.5.
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