Answer:
Gemma can type 3150 words in 3/4hr
Step-by-step explanation:
350 word------>five minutes
x words------->3/4hr
convert 3/4hr-minutes
3/4×60=45minutes
x word =350×45/5
x word=3,150 words
Which statement is true?
Please help
if p is a prime number and a is a positive inte- ger, how many distinct positive divisors does pa have?
If p is a prime number and a is a positive integer, then pa has (a+1) distinct positive divisors.
A prime number is a positive integer greater than 1, which is divisible only by 1 and itself. Divisors are the numbers that evenly divide a given number.
For a prime number p raised to the power of a (p^a), the number of distinct positive divisors can be found using the following formula:
Number of divisors = (a + 1)
This is because each power of p from 0 to a can divide p^a without any remainder, giving us a total of a + 1 distinct divisors. These divisors are:
1, p, p^2, p^3, ..., p^(a-1), p^a
For example, if p = 2 (a prime number) and a = 3 (a positive integer), then the number of distinct positive divisors for 2^3 (which is 8) would be:
Number of divisors = (3 + 1) = 4
The divisors for 2^3 (8) are 1, 2, 4, and 8.
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an appropriations bill passes the u.s. house of representatives with 47 more members voting in favor than against. if all 435 members of the house voted either for or against the bill, how many voted in favor and how many voted against? in favor members against mem
194 member voted against the bill whereas 241 members voted in favour of the bill.
What is bill refers to?A bill usually refers to a piece of paper money, such as a dollar bill or a euro bill.
To solve this problem, we can use algebra. Let's call the number of members who voted against the bill "x". Then, the number of members who voted in favor of the bill would be "x + 47" (since there were 47 more members voting in favor than against).
We know that the total number of members who voted (either for or against) was 435. So, we can write an equation:
x + (x + 47) = 435
Simplifying this equation, we get:
2x + 47 = 435
Subtracting 47 from both sides:
2x = 388
Dividing both sides by 2:
x = 194
So, 194 members voted against the bill, and the number of members who voted in favor would be:
x + 47 = 194 + 47 = 241
Therefore, 241 members voted in favor of the bill.
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In a triangle PQR,the sides PQ, QR and PR measure 15 in, 20 in and 25 in respectively.
Triangle PQR's perimeter is **60 inches**.
What is the triangle's perimeter?The lengths of a triangle's sides added together form its perimeter.
Pythagorean triplet: what is it?The Pythagorean theorem asserts that in a right-angled triangle, the square of the hypotenuse's length (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides 1. A Pythagorean triplet is a group of three positive integers that satisfies this condition.
Triangle PQR has sides PQ = 15 inches, QR = 20 inches, and PR = 25 inches.
A triangle's perimeter is equal to the sum of its sides. Triangle PQR's perimeter is 15 + 20 + 25= **60 inches**. as a result.
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Which property was used to simplify the expression? 3c+ 9 + 4c = 3c + 4c + 9
The property used to simplify the expression is the Commutative Property of Addition, which states that changing the order of addends does not change the sum.
What is Commutative Property?The Commutative Property is a property of operations that states that the order in which two numbers are added or multiplied does not affect the result. In other words, the property says that changing the order of the terms being added or multiplied will not change the final answer.
According to given information:The property that was used to simplify the expression is the Commutative Property of Addition. This property states that the order in which we add two numbers does not affect the result. In other words, if we have two numbers a and b, then a + b is equal to b + a.
In the given expression, we have two terms, 3c and 4c, that are being added together. By applying the Commutative Property of Addition, we can rearrange the terms to get 4c + 3c. This gives us the simplified expression 7c + 9.
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Given the following code fragment, which of the following expressions is always true?
int x;
scanf("%d", &x);
A) if( x = 1)
B) if( x < 3)
C) if( x == 1)
D) if((x/3) > 1)
If the expressions given, only C) if( x == 1) is always true.
In the given code fragment, the value of x is read from the user using the scanf() function. The value of x can be any integer value, depending on what the user enters. After the value of x is read, the program checks the value of x using a conditional statement (if statement) and executes the code inside the if statement only if the condition is true.
Expression A) if( x = 1) assigns the value 1 to x and then checks if x is true. This means that the condition is always true, because the assignment operation (=) returns the assigned value (in this case, 1), which is a non-zero value and therefore considered true in C programming.
Expression B) if( x < 3) checks if x is less than 3. This expression is not always true, as x can be any value greater than or equal to 3, in which case the condition would be false.
Expression C) if( x == 1) checks if x is equal to 1. This expression is always true if the user enters the value 1 for x.
Expression D) if((x/3) > 1) checks if the integer division of x by 3 is greater than 1. This expression is not always true, as x can be any value less than or equal to 3, in which case the result of the integer division by 3 would be 1 or less, in which case the condition would be false.
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the only expression that is always true in this code fragment is option C) if( x == 1).
The expression that is always true in this code fragment is option C) if( x == 1).
Option A) if( x = 1) is not always true because it is an assignment statement instead of a comparison statement. It assigns the value 1 to x instead of checking if x is equal to 1.
Option B) if( x < 3) is also not always true because x could be any number less than 3.
Option D) if((x/3) > 1) is not always true because x could be any number less than or equal to 3, in which case the expression would evaluate to false.
Therefore, the only expression that is always true in this code fragment is option C) if( x == 1).
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If r=0.5 m, A = ???
(Use the r key.)
The calculated value of the angular velocity of the object is 2 rad/s.
Calculating the angular velocityThe angular velocity, denoted by the Greek letter omega (ω), represents the rate of change of the angle with respect to time.
For an object moving in a circular path, the angular velocity is related to the linear speed and the radius of the circle by the equation:
ω = v/r
where v is the linear speed and r is the radius.
In this case, the radius is 0.5m and the speed is 1ms−1. Thus, the angular velocity is:
ω = v/r = 1/0.5 = 2 radians per second (rad/s)
Therefore, the angular velocity of the object is 2 rad/s.
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Complete question
An object moves in a circular path of radius 0.5m with a speed of 1ms−1. What is its angular velocity (A)?
If r = 0.5 m, A = ???
. imagine you had a research question in which you wanted to compare a sample mean to the mean of a population. under these circumstances you would either do a z-test or a one-sample t-test. what key piece of information would be missing if you needed to do a one-sample t-test?
Sample size and sample standard deviation are the key information needed for a single-sample t-test.
In the event that you need to compare the test cruel with the populace cruel, and you perform a single-sample t-test rather than a z-test, the vital piece of data that will be lost is the populace standard deviation.
Within the z-test, the populace standard deviation is known and the standard mistake of the cruel is calculated utilizing the populace standard deviation.
In a single-sample t-test, the populace standard deviation is obscure, and the standard mistake of the cruel is evaluated from the test standard deviation.
Therefore, sample size and sample standard deviation are the key information needed for a single-sample t-test.
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State the amplitude, period, phase shift, and vertical shift of the function kt=cos2pit/3
Answer:
The given function is k(t) = cos(2πt/3).
The general form of a cosine function is A*cos(Bx - C) + D, where:
A is the amplitudeB is the frequency (which is related to the period)C is the phase shiftD is the vertical shiftComparing this form to the given function, we can see that:
The amplitude of k(t) is A = 1, since the maximum value of the cosine function is 1 and the minimum value is -1.The frequency of k(t) is B = 2π/3, since the argument of the cosine function is 2πt/3. The frequency is related to the period T by the formula T = 2π/B. Therefore, the period of k(t) is T = 3.The phase shift of k(t) is C = 0, since there is no horizontal shift in the argument of the cosine function.The vertical shift of k(t) is D = 0, since the average value of the cosine function over one period is zero.Therefore, the amplitude of k(t) is 1, the period of k(t) is 3, the phase shift of k(t) is 0, and the vertical shift of k(t) is 0.
The function:
V(x) = x(10-2x)(16-2x), 0
a) Find the extreme values of V.
b) Interpret any valuse found in part (a) in terms of volumeof the box.
The minimum value of V occurs at x ≈ 0.93, which means that the volume of the box is smallest when the height is about 0.93 units.
To find the extreme values of V, we need to take the derivative of V and set it equal to zero. So, let's begin:
[tex]V(x) = x(10-2x)(16-2x)[/tex]
Taking the derivative with respect to x:
[tex]V'(x) = 10x - 4x^2 - 32x + 12x^2 + 320 - 48x[/tex]
Setting V'(x) = 0 and solving for x:
[tex]10x - 4x^2 - 32x + 12x^2 + 320 - 48x = 0\\8x^2 - 30x + 320 = 0[/tex]
Solving for x using the quadratic formula:
[tex]x = (30 ± \sqrt{(30^2 - 4(8)(320))) / (2(8))\\x = (30 ± \sqrt{(1680)) / 16\\x = 0.93 or x =5.07[/tex]
So, the extreme values of V occur at x ≈ 0.93 and x ≈ 5.07. To determine whether these are maximum or minimum values, we need to examine the second derivative of V. If the second derivative is positive, then the function has a minimum at that point. If the second derivative is negative, then the function has a maximum at that point. If the second derivative is zero, then we need to use a different method to determine whether it's a maximum or minimum.
Taking the second derivative of V:
V''(x) = 10 - 8x - 24x + 24x + 96
V''(x) = -8x + 106
Plugging in x = 0.93 and x = 5.07:
V''(0.93) ≈ 98.36 > 0, so V has a minimum at x ≈ 0.93.
V''(5.07) ≈ -56.56 < 0, so V has a maximum at x ≈ 5.07.
Now, to interpret these values in terms of the volume of the box, we need to remember that V(x) represents the volume of a box with length 2x, width 2x, and height x. So, the maximum value of V occurs at x ≈ 5.07, which means that the volume of the box is greatest when the height is about 5.07 units. The minimum value of V occurs at x ≈ 0.93, which means that the volume of the box is smallest when the height is about 0.93 units.
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a) The extreme values of V are:
Minimum value: V(0) = 0
Relative maximum value: V(3) = 216
Absolute maximum value: V(4) = 128
b) The absolute maximum value of V at x = 4 represents the case where the box has a square base of side length 4 units, height 2 units, and width 8 units, which has a volume of 128 cubic units.
a) To find the extreme values of V, we first need to find the critical points of the function. This means we need to find where the derivative of the function equals zero or is undefined.
Taking the derivative of V(x), we get:
[tex]V'(x) = 48x - 36x^2 - 4x^3[/tex]
Setting this equal to zero and solving for x, we get:
[tex]48x - 36x^2 - 4x^3 = 0[/tex]
4x(4-x)(3-x) = 0
So the critical points are x = 0, x = 4, and x = 3.
We now need to test these critical points to see which ones correspond to maximum or minimum values of V.
We can use the second derivative test to do this. Taking the derivative of V'(x), we get:
[tex]V''(x) = 48 - 72x - 12x^2[/tex]
Plugging in the critical points, we get:
V''(0) = 48 > 0 (so x = 0 corresponds to a minimum value of V)
V''(4) = -48 < 0 (so x = 4 corresponds to a maximum value of V)
V''(3) = 0 (so we need to do further testing to see what this critical point corresponds to)
To test the critical point x = 3, we can simply plug it into V(x) and compare it to the values at x = 0 and x = 4:
V(0) = 0
V(3) = 216
V(4) = 128
So x = 3 corresponds to a relative maximum value of V.
b) In terms of the volume of the box, the function V(x) represents the volume of a rectangular box with a square base of side length x and height (10-2x) and width (16-2x).
The minimum value of V at x = 0 represents the case where the box has no dimensions (i.e. it's a point), so the volume is zero.
The relative maximum value of V at x = 3 represents the case where the box is a cube with side length 3 units, which has a volume of 216 cubic units.
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Find the volume of a pyramid with a square base, where the area of the base is 19. 6 ft 2 19. 6 ft 2 and the height of the pyramid is 11. 6 ft 11. 6 ft. Round your answer to the nearest tenth of a cubic foot
If the area of the base is 19. 6 ft^2 and the height of the pyramid is 11. 6 ft, the volume of the pyramid is approximately 79.1 cubic feet.
The formula for the volume of a pyramid is given by:
V = (1/3) × base area × height
In this case, we are given that the pyramid has a square base, so the base area is simply the area of a square with side length s:
base area = s^2 = 19.6 ft^2
We are also given the height of the pyramid:
height = 11.6 ft
Substituting these values into the formula for the volume of a pyramid, we get:
V = (1/3) × base area × height
= (1/3) × 19.6 ft^2 × 11.6 ft
≈ 79.1 ft^3 (rounded to the nearest tenth)
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these four geometry questions i’m not quite sure how to do and have been struggling in them for a while and it’s due tomorrow!!!!
The total areas of each composite shape are:
1) 121 in²
2) 150m²
3) 14.03 ft²
4) 538.36 cm²
How to find the area of the composite figure?1) Formula for area of a rectangle is:
Area = Length * width
Thus:
Area of composite shape = (9 * 8) + (7 * 7)
= 121 in²
2) Formula for area of rectangle is:
Area = Length * width
Area = 12 * 5 = 60 m²
Area of triangle = ¹/₂ * base * height
Area = ¹/₂ * 12 * 15
Area = 90 m²
Area of composite shape = 60 + 90 = 150m²
3) Area of triangle = ¹/₂ * 3 * 7 = 10.5 ft²
Area of semi circle = ¹/₂ * πr²
= ¹/₂ * π * 1.5²
= 3.53 ft²
Total composite area = 10.5 ft² + 3.53 ft²
Total composite area = 14.03 ft²
4) Total composite area = (¹/₂ * π * 7.5²) + (30 * 15)
= 538.36 cm²
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A pancake company uses the
function f(x) = 1.5x² to calculate
the number of calories in a
pancake with a diameter of x cm.
What is the average rate of change
for the function over the interval
10
A.) 150 calories per cm of diameter
B.) 33 calories per cm of diameter
C.) 65calories per cm of diameter
D.) 215 calories per cm of diameter
Answer:
To find the average rate of change of the function f(x) = 1.5x² over the interval [10, 11], we need to calculate the change in f(x) over the interval, and divide by the change in x.
The change in f(x) over the interval [10, 11] is:
f(11) - f(10) = (1.511^2) - (1.510^2) = 165 - 150 = 15
The change in x over the interval [10, 11] is:
11 - 10 = 1
Therefore, the average rate of change of the function over the interval [10, 11] is:
(15/1) = 15
This means that for every 1 cm increase in diameter (i.e., for every 1 unit increase in x), the number of calories in the pancake increases by an average of 15 calories per cm of diameter.
Therefore, the answer is (A) 150 calories per cm of diameter.
You select a marble without looking and then put it back. If you do this 24 times, what is the
best prediction possible for the number of times you will pick a marble that is not orange?
times
Step-by-step explanation:
24 times, as there are no orange marbles in the set.
so, every pull will produce a marble that is not orange with 100% certainty.
in general, we have 12 marbles.
let's change the problem description into picking a marbles that is not blue.
we have 6 blue marbles.
the chance to pick a blue marble is therefore 6/12 = 1/2.
and the probability to not pick a blue marbles is 1 - 1/2 = 1/2.
so, in 24 pulls, we expect 24× 1/2 = 12 times to get a marble that is not blue.
or change it to "not green" marbles.
5 green marbles.
the probability to pick a green marble is 5/12.
the probabilty to not pick a green marble = 1 - 5/12 = 7/12.
in 24 pulls we expect 24 × 7/12 = 14 times to get a marble that is not green.
it change it to "not purple" marbles.
1 purple marble.
the probability to pick a purple marble is 1/12.
the probabilty to not pick a purple marble = 1 - 1/12 = 11/12.
in 24 pulls we expect 24 × 11/12 = 22 times to get a marble that is not purple.
Solve the following problem. Be sure to show all the steps (V. E. S. T. ) and work in order to receive full credit.
The sum of three numbers is 26. The second number is twice the first and the third number is 6 more than the second. Find the numbers.
Please help due tomorrow
The three numbers are 4, 8, and 14.
Let's use variables to represent the three numbers
Let x be the first number.
Then the second number is twice the first, so it is 2x.
The third number is 6 more than the second, so it is 2x + 6.
We know that the sum of the three numbers is 26, so we can write an equation:
x + 2x + (2x + 6) = 26
Now we can solve for x
5x + 6 = 26
5x = 20
x = 4
So the first number is 4.
To find the second number, we can use the equation we wrote earlier:
2x = 2(4) = 8
So the second number is 8.
To find the third number, we can use the other equation we wrote earlier
2x + 6 = 2(4) + 6 = 14
So the third number is 14.
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Lin notices that the number of cups of red paint is always 2/5 of the total number of cups. She writes the equation r = 2/5 to describe the relationship.
In the given equation r = 2/5 t "r" is the dependent variable.
Dependent variables:In mathematics, a variable is a symbol that represents a quantity that can take on different values. In many cases, variables can be divided into two types: dependent variables and independent variables.
An independent variable is a variable that can be changed freely, and its value is not dependent on any other variable in the equation.
A dependent variable is a variable whose value depends on the value of one or more other variables in the equation
Here we have
Lin notices that the number of cups of red paint is always 2/5 of the total number of cups.
She writes the equation r = 2/5 t to describe the relationship.
In the equation, r = 2/5 t, "t" represents the total number of cups, while "r" represents the number of cups of red paint.
Here "t" is the independent variable because it represents the total number of cups, which can be changed arbitrarily.
The value of "r" depends on the value of "t" because the number of cups of red paint is always 2/5 of the total number of cups.
Therefore,
In the given equation r = 2/5 t "r" is the dependent variable.
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Complete Question:
Lin notices that the number of cups of red paint is always 2/5 of the total number of cups. She writes the equation r = 2/5 t to describe the relationship. Which is the independent variable? Which is the dependent variable? Explain how you know.
in a study of the treatment of congestive heart failure (chf), a new surgical procedure was compared to the standard surgical procedure. the study enrolled 550 people with chf and randomly assigned half to receive the new procedure and half to receive the standard procedure. among those that received the new procedure, 98 died within 5 years. among those that received the standard procedure, 190 died within 5 years. what is the result for the appropriate measure to describe the strength of the association between surgical procedure and death?
The result for the appropriate measure, relative risk, is approximately 0.515.
This indicates that the risk of death within 5 years is about 51.5% lower in the new procedure group compared to the standard procedure group.
This suggests a strong association between the surgical procedure and the reduction in the risk of death.
To determine the strength of the association between the surgical procedures and death, we can calculate the relative risk.
Identify the numbers given in the question.
- Total participants: 550
- New procedure group: 275 (half of 550)
- Deaths in new procedure group: 98
- Standard procedure group: 275 (half of 550)
- Deaths in standard procedure group: 190
Calculate the death rate (proportion of deaths) in each group.
- Death rate in new procedure group = (Number of deaths in new procedure group) / (Total in new procedure group) = 98/275 ≈ 0.356
- Death rate in standard procedure group = (Number of deaths in standard procedure group) / (Total in standard procedure group) = 190/275 ≈ 0.691
Calculate the relative risk.
- Relative risk = (Death rate in new procedure group) / (Death rate in standard procedure group) = 0.356/0.691 ≈ 0.515.
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You need to lower your debt to credit limit ratio by $1000. Your current limit is $1400. $1000 is what percent of your credit limit
$1000 is 71.43 percent of the credit limit.
To lower the debt to credit limit ratio by $1000, you have a few options. The first option is to increase your credit limit by requesting a higher limit from your credit card issuer. Alternatively, you can pay off some of your outstanding balance to reduce your debt. Either way, it's important to make sure you're not maxing out your credit limit, as this can negatively impact your credit score.
It's also a good idea to review your spending habits and create a budget to ensure you're not overspending and accumulating debt. By making responsible financial decisions and managing your credit wisely, you can improve your credit score and achieve your financial goals.
To calculate the percentage of $1000 in terms of the credit limit of $1400, we need to divide $1000 by $1400 and multiply the result by 100. This gives us,
($1000 / $1400) x 100 = 71.43%
Therefore, $1000 is approximately 71.43% of the credit limit of $1400.
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HELP PLS EXPLAIN THISSSSS
Plugging in the values given into the expression, and simplifying, we would have our answer as: B. [tex]\frac{9}{25}[/tex]
How to Evaluate an Expression?To evaluate an expression, follow these steps:Identify the variables and constants in the expression.Substitute the given values for each variable in the expression.Simplify the expression until there are no more operations left.Given that, a = 5 and k = -2, substitute the values into the expression given and simplify:
[tex](\frac{3^2(5^{-2})}{3(5^{-1})} )^{-2}[/tex]
Simplify:
[tex](\frac{9 * \frac{1}{25} }{3* \frac{1}{5} } )^{-2}[/tex]
[tex](\frac{\frac{9}{25} }{\frac{3}{5} } )^{-2}\\\\(\frac{9}{25} * \frac{5}{3} } )^{-2}\\\\(\frac{3}{5} )^{-2}\\\\ = \frac{9}{25}[/tex]
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What is the length of XW and what is the length of WV?
The value of length XW and WV are 20 and 25 respectively.
What are similar triangles?Similar triangles are triangles that have the same shape, but their sizes may vary. The ratio of corresponding sides of similar triangles are equal.
Therefore XW/VW = XY/XZ
= XW/45 = 24/54
54(XW) = 45× 24
54(XW) = 1080
divide both sides by 54
XW = 1080/54
XW = 20
Therefore WV can be found by subtracting XW for VX
= 45-20 = 25
therefore the value of XW and WV are 20 and 25 respectively.
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Lucia has three separate pieces of ribbon. Each piece is 5 yards long. She needs to cut pieces that are 27 inches long to decorate folklorico dance dresses. What is the greatest number of 27-inch pieces that she can cut from three pieces of ribbon?
A 20
B 18
C 7
D 6
The greatest number of 27-inch pieces that she can cut from three pieces of ribbon is found to be 19. So, option B is the correct answer choice.
Each yard is equal to 36 inches, so 5 yards are equal to 180 inches. Therefore, each piece of ribbon is 180 inches long.
To find out how many 27-inch pieces Lucia can cut from each piece of ribbon, we divide 180 by 27.
180/27 = 6.67
Since Lucia can only cut whole pieces, she can cut 6 pieces of ribbon from each piece of ribbon.
Therefore, she can cut a total of 6 x 3 = 18 pieces of ribbon from the three separate pieces of ribbon.
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An angle measures 37.6° more than the measure of its complementary angle. What is the measure of each angle?
The pair of required complementary angles are 26.2° and 63.8° respectively.
What are complementary angles?Two angles are said to be supplementary angles because they combine to generate a linear angle when their sum is 180 degrees.
When two angles add up to 90 degrees, however, they are said to be complimentary angles and together they make a right angle.
If the total of two angles is 90o (ninety degrees), then the angles are complementary.
A 30-angle and a 60-angle, for instance, are two complementary angles.
So, to find the 2 angles which are complementary:
x + x + 37.6 = 90
Now, solve it as follows:
x + x + 37.6 = 90
2x = 90 - 37.6
2x = 52.4
x = 52.4/2
x = 26.2
Now, x = 26.2 and the second angle x + 37.6 is = 26.2 + 37.6 = 63.8°.
Therefore, the pair of required complementary angles are 26.2° and 63.8° respectively.
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three machines, a, b, c produce a large number of identical products. 60% of the products come from machine a, 30% from b and 10% from c. historical records indicate that 10% of the parts produced by machine a are defective, compared with 30% for machine b and 40% for machine c. what is the probability that a randomly chosen part is defective?
The probability that a randomly chosen part is defective is 0.16, or 16%.
The probability that a randomly chosen part is defective, we need to use the law of total probability.
Let [tex]$D$[/tex] be the event that a part is defective and let [tex]$M_i$[/tex] be the event that the part came from machine [tex]$i$[/tex], for [tex]$i = A, B, C$[/tex].
Then we have:
[tex]$P(D) = P(D|M_A)P(M_A) + P(D|M_B)P(M_B) + P(D|M_C)P(M_C)$[/tex]
60% of the products come from machine A, 30% from machine B, and 10% from machine C.
Therefore:
[tex]$P(M_A) = 0.6$[/tex]
[tex]$P(M_B) = 0.3$[/tex]
[tex]$P(M_C) = 0.1$[/tex]
The probability of a part being defective is 10% if it comes from machine A, 30% if it comes from machine B, and 40% if it comes from machine C.
Therefore:
[tex]$P(D|M_A) = 0.1$[/tex]
[tex]$P(D|M_B) = 0.3$[/tex]
[tex]$P(D|M_C) = 0.4$[/tex]
Substituting these values into the law of total probability, we get:
[tex]$P(D) = 0.1 \cdot 0.6 + 0.3 \cdot 0.3 + 0.4 \cdot 0.1 = 0.16$[/tex]
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the weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 3245 grams and a standard deviation of 625 grams. if a newborn baby boy born at the local hospital is randomly selected, find the probability that the weight will be greater than 2620 grams. round your answer to four decimal places.
The probability that the weight of a randomly selected newborn baby boy born at the local hospital will be greater than 2620 grams is 0.9099 (rounded to four decimal places).
The probability can be calculated using the standard normal distribution as follows:
P(Z > (2620 - 3245) / 625) = P(Z > -1.335)
Using a standard normal distribution table, we find that the probability of Z being greater than -1.335 is 0.9099.
We use the standard normal distribution because we know the mean and standard deviation of the population of newborn baby boys' weights. We convert the raw score of 2620 grams to a z-score, which tells us how many standard deviations the raw score is away from the mean.
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The data for the height and weight of different people was collected the line of best fit for this date it was determined to be Y equals 0. 9 1X -65. 5 where X is the height in centimeters and why is the weight in kilograms is in the equation predict the height of a person who weighs 63 kg
According to the equation, a person who weighs 63 kg is predicted to be approximately 141 centimeters tall.
The equation given is Y = 0.91X - 65.5, where X represents the height in centimeters and Y represents the weight in kilograms. To predict the height of a person who weighs 63 kg, we need to solve for X, the height in centimeters.
To do this, we can plug in the given weight of 63 kg for Y in the equation and then solve for X. So, we have:
63 = 0.91X - 65.5
Adding 65.5 to both sides, we get:
63 + 65.5 = 0.91X
Simplifying, we have:
128.5 = 0.91X
Finally, to solve for X, we divide both sides by 0.91, giving:
X = 141.21
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call a positive integer kinda-prime if it has a prime number of positive integer divisors. if there are $168$ prime numbers less than $1000$, how many kinda-prime positive integers are there less than $1000$?
There are 173 kinda-prime positive integer less than 1000.
To find the number of kinda-prime positive integer less than 1000, we'll follow these steps:
1. Understand the definition of a kinda-prime number: A positive integer is kinda-prime if it has a prime number of positive integer divisors.
2. Determine the number of prime numbers less than 1000: There are 168 prime numbers less than 1000, as given.
3. Determine the possible prime number of divisors: Since 168 is not too large, we only need to consider 2 and 3 as possible prime numbers of divisors for a kinda-prime number.
4. Analyze the cases:
Case 1: Kinda-prime numbers with 2 divisors (prime numbers)
All prime numbers have exactly 2 divisors (1 and itself). Thus, all 168 prime numbers less than 1000 are kinda-prime.
Case 2: Kinda-prime numbers with 3 divisors
Let N be a kinda-prime number with 3 divisors. Then, N = p^2 for some prime number p. To find the suitable prime numbers p, we need[tex]p^2 < 1000[/tex]. The prime numbers that meet this condition are 2, 3, 5, 7, and 11 (since 13^2 = 169 > 1000). Therefore, there are 5 additional kinda-prime numbers ([tex]2^2, 3^2, 5^2, 7^2, and 11^2[/tex]).
5. Add the total number of kinda-prime numbers from both cases: 168 + 5 = 173.
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[tex]$(\pi(1000)-1)+11=\boxed{177}$[/tex] "kind a-prime" positive integers less than $1000$.
Let [tex]$n$[/tex] be a positive integer with[tex]$k$[/tex] positive integer divisors.
If [tex]$k$[/tex] is prime, then.
[tex]$n$[/tex] is a "kind a-prime" integer.
[tex]$k$[/tex] must be of the form.
[tex]$k=p$[/tex] or [tex]$k=p^2$[/tex] for some prime [tex]$p$[/tex].
If [tex]$k=p$[/tex], then [tex]$n$[/tex] must be of the form.
[tex]$p^{p-1}$[/tex] for some prime [tex]$p$[/tex]. Since [tex]$p < 1000$[/tex], there are.
[tex]$\pi(1000)$[/tex]possible values of [tex]$p$[/tex].
[tex]$p=2$[/tex] gives [tex]$2^1$[/tex], which is not prime, so we have to subtract.
[tex]$1$[/tex] from [tex]$\pi(1000)$[/tex] to get the number of possible.
[tex]$p$[/tex].
[tex]$\pi(1000)-1$[/tex] values of [tex]$p$[/tex] that give a "kind a-prime" integer of this form.
If [tex]$k=p^2$[/tex], then [tex]$n$[/tex] must be of the form.
[tex]$p^{p^2-1}$[/tex] for some prime[tex]$p$[/tex].
There are.
[tex]$\pi(31)=11$[/tex] primes less than [tex]$31$[/tex], and each of them gives a different "kind a-prime" integer of this form.
Since [tex]$31^5 > 1000$[/tex], no primes larger than [tex]$31$[/tex]can be used to form a "kind a-prime" integer of this form.
[tex]$11$[/tex] possible values of [tex]$p$[/tex] that give a "kind a-prime" integer of this form.
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If you spin the spinner 36 times, what is the best prediction possible for the number of times
it will land on green or blue?
The best prediction possible for the number of times the spinner will land on green or blue is given as follows:
30 spins.
How to calculate a probability?A probability is calculated as the division of the desired number of outcomes by the total number of outcomes in the context of a problem/experiment.
Out of six regions, three are green and two are blue, hence the probability of one spin resulting in green or blue is given as follows:
p = (3 + 2)/6
p = 5/6.
Thus the expected number out of 36 trials of spins resulting in green or blue is given as follows:
E(X) = 5/6 x 36
E(X) = 30 spins.
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As a nurse working in a hospital one of the jobs is to give appropriate doses of medicine
before surgery so the patient doesn't wake up during surgery. 4cc of this particular medicine is
meant for a 180lb man, what would be the correct dosage for a 145 lb. woman?
Answer:
the correct dosage of the medicine for a 145 lb. woman would be approximately 3.22 cc
Step-by-step explanation:
To calculate the correct dosage of the medicine for a 145 lb. woman, we can use the following formula:
dosage = (weight of patient / weight of reference patient) x reference dosage
where the weight of the reference patient is 180 lb. and the reference dosage is 4 cc.
Plugging in the given values, we get:
dosage = (145 / 180) x 4
= 3.22 cc (rounded to two decimal places)
Therefore, the correct dosage of the medicine for a 145 lb. woman would be approximately 3.22 cc. However, it's important to note that dosages of medications should only be determined by a qualified medical professional based on a number of factors, including the patient's weight, medical history, and current condition.
For the first half of a baseball season, a player had 90 hits out of 270 times at bat. The player's batting average was
90
270
≈ 0. 333. During the second half of the season, the player had 64 hits out of 276 times at bat. The player's batting average was
64
276
≈ 0. 232. (Round your answers to three decimal places. )
(a) What is the average (mean) of 0. 333 and 0. 232?
The issue inquires to discover the normal (cruel) of two values:
0.333 and 0.232. To do this, able to essentially include the two values together and partition them by 2. Including the two values gives us:
0.333 + 0.232 = 0.565
Separating by 2 gives us:
0.565 / 2 = 0.2825
So the normal of 0.333 and 0.232 is 0.2825.
In any case, the issue inquires to circular our answer to three decimal places, which suggests we have to be circular 0.2825 to the closest thousandth. The third decimal put maybe a 2, which implies we circular down. Hence, the ultimate reply is roughly 0.283, adjusted to three decimal places.
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6 greater than a number is 24.
Answer:
Step-by-step explanation:
6 greater than a number is 24.
This means adding 6 to a number, x, will equal 24.
6 + x = 24
subtract 6 from both sides of the equation, and you are left with x=18
18 is your answer!!