Answer: Hello attached below is the complete question and using data from ALEKS data tab
answer:
PbCl₂ : Yes , PH = 3
CaC0₃ : Yes, PH = 3
AgCn : Yes , PH = 3 .
Explanation:
For PbCl₂
PbCl₂ solubility will change ( decrease ) with increase in PH, and the PH at which PbCl₂ will be most soluble is at PH = 3
For CaC0₃
Addition of -ions which increases the PH level will cause a decrease in the solubility of CaC0₃ hence the PH at which it will be most soluble in an aqueous solution is PH = 3
For AgCn
Increase in the PH level there would be a decrease in the solubility of AgCn hence the PH at which AgCn is most soluble ( highest solubility ) = 3
The ability of a solute to be able to dissolve is called solubility. Yes, at pH 3, the solubility of lead chloride, calcium carbonate, and silver cyanide.
What is solubility?The ability of the solute to get dissolved in a solvent to form a saturated solution is called solubility.
For lead chloride, the solubility will decrease as the pH will increase and is most soluble at a pH of 3.
For calcium carbonate, the addition of ions increases the pH will result in a decreased solubility, and will be most soluble at pH 3.
For silver cyanide increased pH decreases the solubility and is most soluble at a pH of three.
Therefore, solubility decrease with an increase in pH due to the concentration factor.
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When 12.00 moles of potassium chlorate decomposes, how many dm3 of oxygen are produced at 325K and 188 kPa?
2KClO3 →2KCl + 3O2
show work pls
Answer:
258.71 dm³
Explanation:
We'll begin by calculating the number of mole of O₂ produced by the decomposition of 12 moles of KClO₃. This can be obtained as follow:
The balanced equation for the reaction is given below:
2KClO₃ —> 2KCl + 3O₂
From the balanced equation above,
2 moles of KClO₃ decomposed to produce 3 moles of O₂.
Therefore, 12 moles of KClO₃ will decompose to produce = (12 × 3)/2 = 18 moles of O₂.
Finally, we shall determine the volume of the O₂. This can be obtained as follow:
Temperature (T) = 325 K
Pressure (P) = 188 KPa
Number of mole (n) = 18 moles
Gas constant (R) = 8.314 KPa.dm³/Kmol
Volume (V) =?
PV = nRT
188 × V = 18 × 8.314 × 325
188 × V = 48636.9
Divide both side by 188
V = 48636.9 / 188
V = 258.71 dm³
Thus, 258.71 dm³ of oxygen were obtained from the reaction.
How many grams of oxygen are required to burn 3.01 x 10^23 propane molecules?
A common asteroid is in the first photograph. Haley's Comet is in the second photograph. What can be inferred about comets and asteroids? Answer A Both have orbits around the Earth that are ellipses B Both are miniature planets because they orbit the Sun C Both could be planetary fragments from the beginnings of solar system formation D Both are made of rock, ice, and solar dust from the beginning of the solar system
Answer:
D Both are made of rock ,ice and solar dust from the beginning of the solar system
Answer:
The answer is D
Explanation:
Inquiry Extension Consider a reaction that occurs between solid potassium and chlorine gas. If you start with an initial mass of 15.20 g K, and an initial mass of 2.830 g Cl2, calculate which reactant is limiting. Explain how to determine how much more of the limiting reactant would be needed to completely consume the excess reactant. Verify your explanation with an example
The 3.13 g of K would be needed to completely react with the remaining [tex]Cl_2[/tex].
To determine which reactant is limiting, we need to calculate the amount of product that can be formed from each reactant and compare them. The reactant that produces less product is the limiting reactant, since the reaction cannot proceed further once it is consumed.
The balanced chemical equation for the reaction between solid potassium and chlorine gas is:
2 K(s) + [tex]Cl_2[/tex](g) -> 2 KCl(s)
From the equation, we can see that 2 moles of K react with 1 mole of [tex]Cl_2[/tex] to form 2 moles of KCl.
First, we need to convert the masses of K and [tex]Cl_2[/tex] into moles:
moles of K = 15.20 g / 39.10 g/mol = 0.388 mol
moles of [tex]Cl_2[/tex] = 2.830 g / 70.90 g/mol = 0.040 mol
Now, we can use the mole ratio from the balanced equation to calculate the theoretical yield of KCl from each reactant:
Theoretical yield of KCl from K: 0.388 mol K x (2 mol KCl / 2 mol K) = 0.388 mol KCl
Theoretical yield of KCl from [tex]Cl_2[/tex]: 0.040 mol [tex]Cl_2[/tex] x (2 mol KCl / 1 mol [tex]Cl_2[/tex]) = 0.080 mol KCl
We can see that the theoretical yield of KCl from K is 0.388 mol, while the theoretical yield of KCl from [tex]Cl_2[/tex] is 0.080 mol. Therefore, the limiting reactant is [tex]Cl_2[/tex], since it produces less product.
To determine how much more of the limiting reactant would be needed to completely consume the excess reactant, we can use the stoichiometry of the balanced equation.
We know that 1 mole of [tex]Cl_2[/tex] reacts with 2 moles of K to produce 2 moles of KCl. Therefore, the amount of additional K needed to react with the remaining [tex]Cl_2[/tex] can be calculated as follows:
moles of K needed = 0.040 mol [tex]Cl_2[/tex] x (2 mol K / 1 mol [tex]Cl_2[/tex])
= 0.080 mol K
This means that 0.080 moles of K would be needed to completely consume the remaining [tex]Cl_2[/tex]. We can convert this to a mass by multiplying by the molar mass of K:
mass of K needed = 0.080 mol K x 39.10 g/mol
= 3.13 g K
Therefore, The 3.13 g of K would be needed to completely react with the remaining.
Example verification:
Suppose we had an additional 0.50 g of [tex]Cl_2[/tex] in the reaction. Would all of the K be consumed, or would there still be excess K?
Moles of additional [tex]Cl_2[/tex] = mass of [tex]Cl_2[/tex] / molar mass of [tex]Cl_2[/tex]
Moles of additional [tex]Cl_2[/tex] = 0.50 g / 70.90 g/mol
Moles of additional [tex]Cl_2[/tex] = 0.0070 mol
The theoretical yield of KCl that can be formed from the additional [tex]Cl_2[/tex] is:
0.0070 mol [tex]Cl_2[/tex] x (2 mol KCl / 1 mol [tex]Cl_2[/tex]) x (74.55 g KCl / 1 mol KCl) = 1.04 g KCl
Therefore, the total amount of KCl that can be formed from all of the [tex]Cl_2[/tex] is:
5.95 g + 1.04 g = 6.99 g
The amount of K that would be needed to completely consume all of the [tex]Cl_2[/tex].
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0.41g of neon is held in a 200. mL container at 11 °C. Calculate the pressure in atm.
Answer:
2.39 atm
Explanation:
We'll begin by calculating the number of mole in 0.41 g of neon (Ne). This can be obtained as follow:
Mass of Ne = 0.41 g
Molar mass of Ne = 20 g/mol
Mole of Ne =.?
Mole = mass / molar mass
Mole of Ne = 0.41 / 20
Mole of Ne = 0.0205 mole
Next we shall convert 200 mL to L.
1000 mL = 1 L
Therefore,
200 mL = 200 mL × 1 L / 1000 mL
200 mL = 0.2 L
Next, we shall convert 11 °C to Kelvin temperature.
T(K) = T(°C) + 273
T(°C) = 11 °C
T(K) = 11 + 273
T (K) = 284 K
Finally, we shall determine the pressure. This can be obtained as follow:
Mole of Ne (n) = 0.0205 mole
Volume (V) = 0.2 L
Temperature (T) = 284 K
Gas constant (R) = 0.0821 atm.L/Kmol
Pressure (P) =?
PV = nRT
P × 0.2 = 0.0205 × 0.0821 × 284
P × 0.2 = 0.4779862
Divide both side by 0.2
P = 0.4779862 / 0.2
P = 2.49 atm
Therefore, the pressure of the gas is 2.39 atm
Calculate the volume of solvent present in a 55.5%
by volume of 10.5 mL alcohol solution.
Answer:
I dont know
Explanation:
good luck
write half-reactions that show how H2O2 can act as either an oxidizing agent or a reducing agent, and describe where each of these situations occurred in your testing.
Answer:
H2O2 reduces itself to H2O and also oxidizes to O2 simultaneously thereby acting both as an oxidizing and reducing agent .
Explanation:
When
H2O2 acts as an oxidizing agent
H2O2 + 2e- 2H+---> 2H2O
Reducing agent
H2O2 --> O2 + 2e + 2H+
H2O2 reduces itself to H2O and also oxidizes to O2 simultaneously thereby acting both as an oxidizing and reducing agent .
What does the cell theory state? Answer F All organisms are composed of a nucleus G All prokaryotes are composed of multiple cells H All prokaryotes are single celled organisms J All organisms are composed of cells
Answer:
(J) All organisms are composed of cells
How can heat energy transform from mechanical energy?
A)Burning
B)Friction
C)Light
D)Flames
Answer:
A
Explanation:
brainliest pls
A balloon is inflated to a volume of 8.0 L on a day when the atmospheric pressure is 1.013 bar . The next day, a storm front arrives, and the atmospheric pressure drops to 0.968 bar . Assuming the temperature remains constant, what is the new volume of the balloon, in liters
Answer:
[tex]V_2=8.4L[/tex]
Explanation:
Hello there!
In this case, according to the definition of the Boyle's law, which describes de pressure-volume behavior as an inversely proportional relationship, it is possible for us to write:
[tex]P_1V_1=P_2V_2[/tex]
Thus, since we are given the initial pressure and temperature, and the final pressure, we are able to calculate the final volume as shown below:
[tex]baV_2=\frac{P_1V_1}{P_2}\\\\V_2=\frac{8.0L*1.013bar}{ 0.968bar}\\\\V_2=8.4L[/tex]
Regards!
Explain the term orbital.
Answer: a mathematical expression describing the probability of finding an electron at various locations; usually represented by the region of space around the nucleus where there is a high probability of finding an electron
Explanation:
Cell membranes are selectively permeable. This means that A. only water can move freely across the cell membrane. B. any substance can move across the cell membrane, but chemical energy will always be required. C. some substances can move freely across the cell membrane, while others must be transported. D. no substances can move freely across the cell membrane.
Answer:
C. some substances can move freely across the cell membrane, while others must be transported.
Explanation:
0.850 moles of N2 originally at 85°C is cooled such that it now occupies 17.55L at 1.25 atm. What is the final temperature of the gas?
The final temperature of the gas is 269.9 K, or -3.25 °C, which was calculated with the help of ideal gas equation.
What is the ideal gas equation?The ideal gas equation gives the relation between pressure, volume and temperature.
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
To find the initial volume of the gas. We can use the fact that the number of moles of gas does not change during the cooling process:
n = 0.850 moles
We can also use the ideal gas law to find the initial volume of the gas:
PV = nRT
V = nRT/P
where R = 0.08206 L atm/K mol is the gas constant.
Convert the initial temperature from Celsius to Kelvin:
T1 = 85 °C + 273.15 = 358.15 K
Substitute the given values into the equation:
V₁ = (0.850 mol)(0.08206 L atm/K mol)(358.15 K)/(1 atm) = 24.03 L
Now we can use the combined gas law to find the final temperature:
(P₁V₁/T₁) = (P₂V₂/T₂)
Substitute the given values into the equation:
(1.25 atm)(24.03 L)/(358.15 K) = (P₂) (17.55 L)/(T2)
Solve for T₂:
T₂ = (P₂)(17.55 L)(358.15 K)/(1.25 atm)(24.03 L)
T₂ = 269.9 K
Therefore, the final temperature of the gas is 269.9 K, or -3.25 °C.
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What are the missing coefficients for C3H8 + o2 = Co2 +H2O
Answer: C3H8 + 5O2 = 3Co2 +4H2O
Explanation: Equations must be balanced
You must have the same amount of C
H and O on both sides of the equation
when rolling a number cube 500 times, how many times you expect to get a 3?
Answer:
[tex]\frac{250}{3}[/tex]
Explanation:
you can expect to get a 3 (theoretically) 1 time every 6 times you roll. A 1/6 chance.
Here's the equation:
[tex]\frac{1}{6} =\frac{x}{500}[/tex]
cross multiply (i think that's what it is called)
500=6x
divide by 6 on both sides:
x=[tex]\frac{250}{3}[/tex] or approx 83 times.
Hope this helps! Lmk if u have more questions <3
PLEASE HELP I HAVE 19 MINUTES LEFT I WILL MARK BRAINLIEST
How much more acidic is a pH of 4 as compared to a pH of 6.5?
Answer:
316.227766
Explanation:
Can someone please solve this question?? Is an element in group 3 likely to bond with an element from group 2?? Explain using the number of balance electrons from each element and the tot number of balance electrons needed to fill an about shell
Answer:
An atom with one or two valence electrons more than a closed shell The number of valence electrons of an element can be determined Groups 3-12 (transition metals), 2* (The 4s shell is complete and cannot hold any more electrons) in explaining the molecular structure of many organic compounds.
Explanation:
A balloon is filled with 3.50 L of water at 24.0°C. What is the volume of the water at 307 K?
Answer:
what is the volume of the water at 307 k?
How many sulphur atoms are there in 0.125 moles of sulphur
Explanation:
There are 6.022x1023 molecules in 1 mole of SO3 (Avogadro's number) so in 0.25 moles, there are (0.25)(6.022x1023) molecules in the 0.25 moles of SO3. or 1.506x1023 molecules per 0.25 moles of SO3.
There is one atom of sulfur in each molecule of SO3. So there are 1.506x1023 atoms of sulfur in 0.25 moles of SO3.
According to the concept of Avogadro's number there are 0.7525 ×10²³ atoms of sulfur in 0.125 moles of sulfur.
What is Avogadro's number?Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.
It has a SI unit of reciprocal mole whose numeric value is expressed in reciprocal mole which is a dimensionless number and is called as Avogadro's constant.It relates the volume of a substance with it's average volume occupied by one of it's particles .
According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.
Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number
In the given example, number of atoms of sulfur are calculated as, Avogadro's number×number of moles, that is,6.022×10²³ ×0.125=0.75275×10²³ atoms
Therefore, there are 0.75275×10²³ atoms in 0.125 moles of sulfur.
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Which organic compound listed below does not have a carbonyl group ?
A. Aldehyde
B. Ketone
C. Ethers
D. Protein
E. Ester
F. Amides
Give the ratio that balances out the following equation: ___Cr + ___Pb(NO3)4 ---> ___ Cr(NO3)3 + ____ Pb
the doge has the answer
Pb(NO3)4
There are four stages to the classical demographic transition model Pre-transitional Europe was characterized by high and
fluctuating mortality and a high birth rate. The transition model began to progress into and through stage 2 in the late 18th and early
19th century. All BUT ONE contributed to the decline in mortality.
S- -1]))
A)
Enacting measures to provide clean water supplies.
B)
Public health advances including quarantine of settlements undergoing
epidemics
The development of vaccines to prevent disease and antibiotics to treat
infection.
D)
Widespread acceptance of germ theory resulting in more hygienic
practices, including hand washing and sterilizing medical equipment and
infants' bottles.
Question 6 (4 points)
(08.02 MC)
What is the percentage by mass of solution formed by dissolving 27.0 grams of HCl in 102.0 grams of water? (4 points)
а
26.596
D
20.946
с
18.296
d
16.796
Answer:
20.9%
Explanation:
I took the test i hope this helps:)
The percentage by mass of solution formed by dissolving 27.0 grams of HCl in 102.0 grams of water is 20.93%. This is calculated using the definition (formula) of percentage by mass of a solution.
What is meant by percentage by mass?The mass percent of a solution is defined as the ratio of the mass of solute that is present in a solution, relative to the mass of the solution, as a whole.
The formula for percentage by mass is given as
percentage by mass = (mass of the solute/ total mass of the compound solution) × 100
Calculating percentage by mass for the given solution:The mass of the solute ( the chemical which is going to be dissolved) HCl
= 27.0 grams
The mass of the solvent (the substance in which a solute dissolve) water
= 102.0 grams
So, the total mass of the solution = 27.0 + 102.0 = 129.0 grams
Then, the percentage by mass = [tex]\frac{27.0}{129.0}[/tex] × 100 = 20.93%
Which is approximate equal to 20.946 at option B.
Therefore, the percentage by mass of solution formed by dissolving 27.0 grams of HCl in 102.0 grams of water is 20.93%.
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Help plz:)))I’ll mark u Brainliest
Answer:
[tex]\Delta _{fus}H=205J/g=13.03kJ/mol[/tex]
Explanation:
Hello there!
In this case, since the heat of fusion is a property that allows us to calculate the heat involved during the change from solid to liquid (fusion) and is calculated as shown below:
[tex]Q=m*\Delta _{fus}H[/tex]
In such a way, given the heat involved during this process and the mass of copper, we calculate the heat of fusion as shown below:
[tex]\Delta _{fus}H=\frac{Q}{m}=\frac{41000J}{200.g}\\\\\Delta _{fus}H=205J/g[/tex]
Or in kJ/mol:
[tex]\Delta _{fus}H=205\frac{J}{gCu}*\frac{63.546 gCu}{1molCu}\\\\ \Delta _{fus}H=13026.93J/mol=13.03kJ/mol[/tex]
Regards!
A certain mass of water was heated with 41,840 Joules, raising its temperature from 22.0°C to 28.5 °C. Find the
mass of the water.
Answer:
1.5 × 10³ g
Explanation:
Step 1: Given and required data
Transferred heat (Q): 41,840 JInitial temperature: 22.0 °CFinal temperature: 28.5 °CSpecific heat capacity of water (c): 4.184 J/g.°CStep 2: Calculate the temperature change
ΔT = 28.5°C - 22.0 °C = 6.5 °C
Step 3: Calculate the mass (m) of water
We will use the following expression.
Q = c × m × ΔT
m = Q / c × ΔT
m = 41,840 J / (4.184 J/g.°C) × 6.5 °C = 1.5 × 10³ g
An experimental measurement was taken of 10.4mL and the actual measurement was 9.7mL. What is the percent error?
Answer:
13%
Explanation:
how many molecules in 400g of acetic acid
Answer:chemical formula of acetic acid is or
so, molecular mass of acetic acid = 2 × atomic mass of C + 4 × atomic mass of H + 2 × atomic mass of O
= 2 × 12 + 4 × 1 + 2 × 16
= 24 + 4 + 32
= 60g/mol
given mass of acetic acid = 22g
so, no of moles of acetic acid = given mass/molecular mass
= 22/60 ≈ 0.367
so, number of moles of acetic acid is 0.367mol
number of molecules in 0.367 mol of acetic acid = 6.022 × 10²³ × 0.367
= 2.21 × 10²³
Explanation:
In calorimetry, energy is measured through heat transfer from one substance to
another. Which of the following is NOT a method of heat transfer?
Answer:
Refraction
Explanation:
A student pours 10.0 g of salt into a container of water and observes the amount of time it takes for the salt to dissolve. She then repeats the process using the same amounts of salt and water but this time she slowly stirs the mixture while it is dissolving. The student performs the experiment one more time but this time she stirs the mixture rapidly.
Answer:
It will go faster each time because she is stirring therefore the water can get to the salt faster than it just sitting at the top
Explanation:
given mass of nitrogen is 0.12 dm^3 at 60°C and 1.01*10^5 Nm^2. Find its pressure at the same temperature if its volume is changed to 0.24 dm^3
50500Nm^2 or 5.05Nm^2
Explanation:
so bring out the parameters
p1= 0.12dm3, T1= 60c , because temperature is in kelvin add 273= 333k, v1= 0.12dm3 , T2= to the same value because the temperature didn't change = 333k, v2= 0.24dm3,P2= ?
general gas equation p1v1 over T1 = P2V2 over T2, when you input everything or make p2 the subject of the formula first you'll get the answer, pressure can have an s.i unit of mmhg but I'm using the same si unit as the question given and always check your units in the question to convert. please if this question has options please check, I don't want you to fail so verify from others if I made a mistake