Find the zeros of ƒ(x) = x3 + 6x2 + 8x.
A) x = 0, –2, –4
B) x = 0, 2, 4
C) x = 2, 4
D) x = –2, –4

Answers

Answer 1

Answer:

Option A: [tex]x=0[/tex], [tex]x=-2[/tex], and [tex]x=-4[/tex]

Step-by-step explanation:

[tex]f(x)=x^3+6x^2+8x[/tex]

[tex]0=x^3+6x^2+8x[/tex]

[tex]0=x(x^2+6x+8)[/tex]

[tex]0=x(x+2)(x+4)[/tex]

[tex]x=0[/tex], [tex]x=-2[/tex], and [tex]x=-4[/tex]

Answer 2

[tex]x^3+6x^2+8x = 0\\\\\implies x^3+2x^2 +4x^2+8x =0\\\\\implies x^2(x+2) +4x (x+2) =0\\\\\implies (x+2)(x^2 +4x) = 0\\\\\implies x (x+2) (x+4)=0\\\\\text{Hence,} \\\\x = 0 ,-2,-4[/tex]


Related Questions

Oscar has baskets that each contain 25 apples. Each day 2 apples are
eaten from each basket. Oscar has (25 – 2d) apples left afterd days in
one basket. If Oscar has 7 baskets of apples, how many apples are left
after d days?

Answers

Answer:

  175 -14d

Step-by-step explanation:

There will be 7 times as many as in one basket.

 7(25 -2d) = 175 -14d . . . . total apples left

The probability of event A is 0.53 and the probability of event B is 0.17. The probability of A and B occurring is 0.901. Which statement accurately describes these two events?

Answers

Answer: Choice C

Explanation:

We're given that

P(A) = 0.53P(B) = 0.17P(A and B) = 0.901

Note that P(A)*P(B) = 0.53*0.17 = 0.0901 which is somewhat similar to 0.901 but not entirely the same. We have an extra zero between the decimal point and the nine. So this indicates that [tex]P(A)*P(B) \ne P(\text{A and B})[/tex]. Therefore, events A and B are not independent. We consider them dependent.

can anyone plz help me with this math problem

Answers

the answer to the question is f=1

What the vertex of y=4(x-3)^2+3

Answers

Answer:

(3,3)

Step-by-step explanation:

we rewrite in vertex form and use this form to find the vertex (h,k)



What does point G represent in the context of this situation?

Answers

Answer:

The famous point G that everyone enjoys... of course it represents a point of a graph! What else could it be? G stands for graph.


Anybody know the answer !!

Answers

Answer:

17.08

Step-by-step explanation:

When it reaches its maximum, suppose that y = 0

Therefore you will need to factorise and solve

-16x^2 + 267 x + 107 = 0

Here you can use the quadratic equation[tex]\frac{-b+-\sqrt{b^{2}-4ac } }{2a}[/tex]

Where you will get x = -0.39 seconds or 17.08 seconds (rounded to 2 decimal places according to the question

Because -0.39 is negative, this answer can be deleted

Leacing x = 17.08 seconds

The answer is 17.08!!!

Solve for x.
(−19)2=x

Answers

Answer:

Step-by-step explanation:

Answer:

x=-38

Step-by-step explanation:

-19*2=-38

Hope this helps! Pls give brainliest! Also sub to kgir633 on yt.

Simplify the expression: 4s+10–2+4s

Answers

Answer:

8s+8

Step-by-step explanation:

Put it into groups: (4s+4s)+(10-2)=8s+8

Brainliest is appreciated

Answer:

(4s+4s)+(10-2)= 8s/8 =1   so s=1

Step-by-step explanation:

The equation 5y = 6 represents purchasing tubs of yogurt for $6. Which of these equations are equivalent to the equation 5y=6?
a 5y + 4 = 10
b 5y - 1 = 3
c 15y = 18
d 5y = 12

Answers

Answer:

blah blah

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

please help me with this question.

Answers

Answer:

Exact Form: 309/25

Mixed Form: 12 and 9/25

Step-by-step explanation:

You need $145 in cash if you withdraw money from your savings account using the ATM how much will you need to withdraw in order to have at least one $145 based upon how ATM’s dispense money?

Answers

Answer:

290

Step-by-step explanation:

145 withdrawal free + 145 in cash = 290.

Can i get some help ?:

Answers

Answer:

7 + 3² - 2.5 / 4 - 1.2 > ( 3/4 + 1/8 ) ÷ 1/8 - 2²

Step-by-step explanation:

7 + 3² - 2.5 / 4 - 1.2 = 4.82142857

( 3/4 + 1/8 ) ÷ 1/8 - 2² = 3

Which means :

7 + 3² - 2.5 / 4 - 1.2 > ( 3/4 + 1/8 ) ÷ 1/8 - 2²

Can someone please give me the (Answers) to this? ... please ...

Answers

a.) The SAS Triangle Congruence Postulate states that if if a pair of corresponding sides, a pair of corresponding angles, and another pair of corresponding sides in two triangles are congruent, then the two triangles are congruent. Therefore, we can see that in both triangles, we are only shown a corresponding, congruent right angle. We need two pairs of sides with the corresponding right angles to prove that the triangles are congruent via SAS. We would need to know the length of side VX, and it’s corresponding side length, XV. We would also need to know the side lengths of WV and it’s corresponding side length, XK. We would then need some sort of symbol to represent a congruent relationship if the side lengths are congruent. Then, we would have two pairs of corresponding, congruent sides, and a pair of corresponding, congruent angles. Then, we would have a Side-Angle-Side.

b.) We are given two triangles with a pair of corresponding, congruent sides. We need to have a pair of corresponding, congruent angles, another pair of corresponding, congruent sides to follow SAS. Therefore, we would need to know the angle measures of angles UVW and KVM. We know that they are vertical angles, so they are indeed congruent. Now, we would need to know the side lengths of sides WV and VM. If those sides are congruent, then we have a pair of corresponding, congruent sides, a pair of corresponding, congruent angles, and another pair of corresponding, congruent sides, making SAS.

c.) The Angle Side Angle Postulate states that if there is a pair of corresponding, congruent angles, a pair of corresponding, congruent sides, and another pair of corresponding, congruent angles in two triangles, then the two triangles are congruent. We have a pair of corresponding, congruent angles, a pair of corresponding, congruent sides, but we need another pair of congruent, corresponding angles. Therefore, we would need to know the angle measures of angles MLK and STU. Then we would have a a pair of corresponding, congruent angles, a pair of corresponding, congruent sides, and another pair of corresponding, congruent angles.

Please give Brainliest! This took a lot of time!

Answer:

To be congruent at b. no. UV= VK,V=V,UW=KM.

To be congruent at C no. M=S,LM=ST,LK=TU.

Answer this correct and I will give you extra points.

Answers

Answer:

he didnt subtract each equations on both sides

5y-6=4y+1

-4       -4

y  -6=1

  +6=+6

y=7

Step-by-step explanation:

hope that wrk

plsss help mee i donot now the answer

Activity 1: Identifying Hypothesis and Conclusion Directions: Identify the hypothesis and the conclusion for each of the following statements.

1. If you live in Manila, then you live in the Philippines.

2. If a triangle is a right triangle, then one of its interior angle is a 90-degree angle.

3. A square is not a triangle.

4. An even number is divisible by 2.

5. The measure of an acute angle is less than 90.​

Answers

Answer:

1. If you live in Manila(hypothesis) then you live in the Philippines ( conclusion)

2. If a triangle is a right triangle (hypothesis), then one of its interior angle is a 90-degree angle ( conclusion)

3. A square is not a triangle (conclusion)

4. An even number is divisible by 2. (conclusion)

5. The measure of an acute angle is less than 90. (conclusion)

Marcus has twice as many pens as Bryan. Together they have 36 pens. How many pens does each boy have?

Answers

Answer:

Marcus has 24 pens while Bryan has 12 pens.

Step-by-step explanation:

Let u rep 1 unit.

Marcus = 2u

Bryan = u

2u+u=36

   3u=36

     u=36÷3

       =12

No. of pens Marcus has

= 2u

= 2×12

= 24

No. of pens Bryan has

= u

= 12

10 x + 2 y . Find P when: x = 3 and y = 6



help pleaseee

Answers

Answer:

42

Step-by-step explanation:

(10x3) + (2x6)

= 30 + 12

= 42

10x + 2 y = (10.3) +(2.6) = 30+12=42

Our answer is 42

the triangles are similar. what is the value of x? enter your answer in the box.

Answers

Answer:

l*b*h is the answer of this question

I need help with this problem
Solve the following system of equations using elimination by multiplication.

Answers

If the given equations are indeed

[tex]\begin{cases}x-\frac4{5y} = 9\frac45 \\ -14x - 4y = -46\end{cases}[/tex]

we can solve by substitution. Solve the second equation for x :

[tex]-14x - 4y = -46[/tex]

[tex]\implies 7x + 2y = 23[/tex]

[tex]\implies7x = 23 - 2y[/tex]

[tex]\implies x = (23 - 2y)/7[/tex]

Substitute this into the first equation and solve for y :

[tex]\dfrac{23-2y}7 - \dfrac4{5y} = 9\dfrac45[/tex]

On the right side, write the mixed number as an improper fraction:

[tex]9 + \dfrac45 = \dfrac{45}5 + \dfrac45 = \dfrac{45+4}5 = \dfrac{49}5[/tex]

[tex]\implies \dfrac{23-2y}7 - \dfrac4{5y} = \dfrac{49}5[/tex]

Multiply both sides of this equation by 35y (the LCM of the denominator of all three fractions)

[tex]35y \times \dfrac{23-2y}7 - 35y \times \dfrac4{5y} = 35y \times \dfrac{49}5[/tex]

[tex]5y\times(23-2y) - 7\times4 = 7y \times 49[/tex]

[tex]115y - 10y^2 - 28 = 343y[/tex]

[tex]10y^2 + 228y + 28 = 0[/tex]

[tex]5y^2 + 114y + 14 = 0[/tex]

To solve the quadratic, I'll complete the square :

[tex]5\left(y^2 + \dfrac{114}5y\right) + 14 = 0[/tex]

[tex]5\left(\left(y + \dfrac{57}5\right)^2 - \left(\dfrac{57}5\right)^2 \right) + 14 = 0[/tex]

[tex]5\left(y + \dfrac{57}5\right)^2 - \dfrac{57^2}5 + 14 = 0[/tex]

[tex]5\left(y + \dfrac{57}5\right)^2 = -\dfrac{3179}5[/tex]

This system has no real solutions since the square of any real number must be positive.

If we allow complex numbers, we can continue solving to end up with two complex solutions for y,

[tex]\left(y + \dfrac{57}5\right)^2 = -\dfrac{3179}{25}[/tex]

[tex]y + \dfrac{57}5 = \pm i \sqrt{\dfrac{3179}{25}}[/tex]

[tex]y = -\dfrac{57}5 \pm i\dfrac{17\sqrt{11}}5[/tex]

and we can go on to solve for x.

Hence my comment; I suspect you meant to write the system

[tex]\begin{cases}x-\frac45 y = 9\frac45 \\ -14x - 4y = -46\end{cases}[/tex]

because its solution is far simpler. Multiplying through the first equation by 5 gives

[tex]5\times x - 5 \times \dfrac45 y = 5 \times 9\dfrac45[/tex]

[tex]\implies 5x - 4y = 49[/tex]

(since we know 9 + 4/5 = 49/5)

Meanwhile, multiplying through the second equation by -1 gives

[tex]-1 \times (-14x) + (-1) \times (-4y) = -1 \times (-46)[/tex]

[tex]\implies 14x + 4y = 46[/tex]

So if we combine the two equations, we can eliminate y and solve for x :

[tex](5x - 4y) + (14x + 4y) = 49 + 46[/tex]

[tex]\implies 19x = 95[/tex]

[tex]\implies \boxed{x = 5}[/tex]

and solving for y gives

[tex]14x + 4y = 46[/tex]

[tex]\implies 70 + 4y = 46[/tex]

[tex]\implies 4y = -24[/tex]

[tex]\implies \boxed{y = -6}[/tex]

Maija is bicycling north on a straight path. She bicycles for
17.
4
kilometers when she realizes she is
thirsty. Maija remembers passing a water fountain
2 kilometers earlier By rounding to the nearest
whole number, estimate the distance from the beginning of Maija's ride to the water fountain

Answers

Answer:

The awnser is 19 Kilometers

Plzzz help me it’s due tonight!!!!!

Answers

Answer:

UV=5, VW=5[tex]\sqrt{3}[/tex], and m∠U=60

Step-by-step explanation:

sin 30=UV/10=>0.5=UV/10=>UV=5

VW=√(10²-5²)=√75=5√3

m∠U=180-90-30=60

Write an inequality that has the points (-2, -6) and (4, -3) on the line and (6, -4) and (2, -4) as solutions.


(use <= or >= for ≤ or ≥

symbols and write your inequality in y=mx+b form with no spaces)


inequality=

Answers

Answer in fraction form is:    y ≤ (1/2)x - 5  or  [tex]y \le \frac{1}{2}x-5[/tex]

Answer in decimal form is:  y ≤ 0.5x - 5

You only need to pick one answer format.

========================================================

Explanation:

The drawing is below.

Let's label the four given points as A,B,C,D

A = (-2,-6)B = (4,-3)C = (6,-4)D = (2,-4)

For now, let's focus on the boundary points A(-2, -6) and B(4, -3). A straight line in the form y = mx+b passes through these points. Compute the slope.

m = (y2-y1)/(x2-x1)

m = (-3 - (-6))/(4 - (-2))

m = (-3 + 6)/(4 + 2)

m = 3/6

m = 1/2

m = 0.5

Now let's use one of those (x,y) points along with that m value to find the y intercept b. I'll use the coordinates from point A.

y = mx+b

-6 = 0.5*(-2)+b

-6 = -1 + b

-6+1 = b

-5 = b

b = -5

The equation of the boundary line is y = 0.5x-5 which is the same as saying y = (1/2)x - 5 or [tex]y = \frac{1}{2}x-5[/tex]. We can refer to this as line AB.

-------------------------------

If you were to plot all four points (A,B,C,D) on the same xy grid, then you'd find that point D is on line AB. We're told that point D is a solution to the inequality, which must mean we are going to involve "or equal to" as part of the inequality sign. This will allow points on the boundary to be part of the solution set.

Notice how point C is below line AB. Since point C is also a solution, this means we go for "less than" to shade below the boundary. Overall, the sign we go for is "less than or equal to" or in short ≤

Therefore, the inequality is y ≤ 0.5x - 5

which is the same as writing y ≤ (1/2)x - 5  or [tex]y \le \frac{1}{2}x-5[/tex]

evaluate 3d/2a, when d=4 and a = -1​

Answers

Answer:

ok

Step-by-step explanation:

Can somebody help me :

Answers

Answer:

A

Step-by-step explanation:

Negative numbers are smaller than positive numbers.

Answer:

Your correct 6.55 is a positive number while -6.5 is negitive and positive numbers are always larger then negitive ones

Hope This Helps!!!


A music store purchases a grand
piano, wholesale, for $5,000.
They markup the retail price 65%.
What is the retail price?

Answers

Answer: 8250

Step-by-step explanation:

Answer:

8548

Step-by-step explanation:

3x - 7 = 3x + 9; x =

Please can someone help me and show me the answers step by steps

Answers

Answer:

i think probably x∉∅

Step-by-step explanation:

3x-7 = 3x+9

-7 = 9

so x∉∅

Answer:

0 = 16 or No Solution

Step-by-step explanation:

1) Add  7   to both sides of the equation

3x - 7 + 7 = 3x + 9 + 7

2) Simplify

A. Add the numbers

3x = 3x + 9 + 7

B. Add the numbers

3x = 3x + 16

3) Subtract 3x  from both sides of the equation

3x - 3x = 3x + 16 - 3x

4) Simplify

A. Combine like terms

0 = 3x + 16 - 3x

B. Combine like terms

0 = 16

What is the length of the mid segment AB??

Answers

Answer:

14.5

Step-by-step explanation:

AB is halfway between MN and PO. this means it would be the distance halfway between 9 units (length of MN) and 20 units (length of PO). to find this, find the average of 20 and 9. 20+9= 29. 29/2= 14.5

The ground temperature at an airport is 14 "C. The temperature decreases by 6.2 "C for every increase of 1 kllometer above the ground. What is the temperature outside a plane flying at an altitude of 5 kilometers?​

Answers

Answer:

-17 C

Step-by-step explanation:

14 - 5(6.2) = 14 - 31  = -17 C

Solve the equations.
[tex]3(x+4)^{2} =10x+32\\(x+4)^{2} =3x+40\\\frac{x^{2} -1}{2} -11x=11[/tex]

Answers

Answer:

  a) x = {-2 2/3, -2}

  b) x = {-8, 3}

  c) x = {-1, 23}

Step-by-step explanation:

If all you want are solutions, a graphing calculator can give them to you easily. The attachment shows the solutions as x-intercepts when the equation is rearranged to the form f(x) = 0.

__

In general, it can be convenient to write the equation in standard form with integer coefficients. Common factors among the coefficients should be removed.

a)

  3(x+4)^2 = 10x +32 . . . . . given

  3(x^2 +8x +16) -10x -32 = 0

  3x^2 +14x +16 = 0

To factor this, we're looking for factors of 3·16 that total 14.

  48 = 1·48 = 2·24 = 3·16 = 4·12 = 6·8

The last pair of factors has a total of 14, so we can rewrite the equation as ...

  (3x +6)(3x +8)/3 = 0

  (x +2)(3x +8) = 0

The solutions are the values of x that make the factors zero:

  x = -2, x = -8/3

__

b)

  (x +4)^2 = 3x +40 . . . . . . . . given

  x^2 +8x +16 -3x -40 = 0 . . . . subtract the right side

  x^2 +5x -24 = 0 . . . . . . . . simplify

  (x +8)(x -3) = 0 . . . . . . factor

The solutions are the values of x that make the factors zero:

  x = -8, x = 3

__

c)

  (x^2 -1)/2 -11x = 11 . . . . . given

  x^2 -1 -22x -22 = 0 . . . . . . multiply by 2, subtract the right side

  x^2 -22x -23 = 0 . . . . . . simplify

  (x -23)(x +1) = 0 . . . . . . factor

  x = 23, x = -1

_____

Additional comment

Factoring often gets to the solution with the least fuss when the solutions are rational. There are several ways factoring can be done when the leading coefficient is not 1. One of them is illustrated in (a) above. We will show two other methods that give the same result.

factoring by pairs

We have identified the factors of 3·16 = 48 that have a total of 14. We can use those factors to rewrite the 14x term in the equation.

  3x^2 +6x +8x +16 = 0

Now, we can group the terms in pairs, and factor each pair. It does not matter which of the factors (6 or 8) you write first. You will end with the same result.

  (3x^2 +6x) +(8x +16) = 0

  3x(x +2) +8(x +2) = 0

  (3x +8)(x +2) = 0   ⇒   x = -8/3, x = -2

__

factoring using the X method

This method is usually shown using a large graphic X. In the top quadrant is written the product of the leading coefficient and the constant: 3·16 = 48.

In the bottom quadrant is written the coefficient of the x-term: 14.

If one or the other, or both, of these top/bottom values is negative, be sure to keep the sign.

The side quadrants are then filled with values that have a product equal to the top number, and a sum equal to the bottom number. (Pay attention to the signs.) Further, in each of those quadrants, the number written is divided by the leading coefficient, and the fraction reduced to lowest terms.

Here, we would have 6/3 = 2 on one side, and 8/3 on the other side. Now the factors are written as (bx+a), where the reduced fraction on either side is a/b. In our example, the factors are (x+2) and (3x+8)

__

alternate X method

This starts off in the same way the X method does, as described above. However, the factors on either side of the X are not divided by the leading coefficient (a). If those side values are 'p' and 'q', the quadratic is written in factored form as ...

  (ax +p)(ax +q)/a = 0

You will notice we used this form above: (3x +6)(3x +8)/3 = 0.

Now, the divisor 'a' can be used to reduce either or both of the numerator factors. Here, the entire factor of 3 can be removed from (3x+6) to make the factorization be ...

  (x +2)(3x +8) = 0

__

Sometimes, one factor of the divisor will be removed from one term, and the other factor of it will be removed from the other term. An example of this might be ...

  [tex]\dfrac{(6x+3)(6x+2)}{6}=\dfrac{6x+3}{3}\cdot\dfrac{6x+2}{2}=(2x+1)(3x+1)[/tex]

23.15 – [ 115 + ( 12 - 25)]

Answers

Answer:

-78.85

Step-by-step explanation:

Using Order of Operations (PEDMAS):

23.15 – [ 115 + ( 12 - 25)]

= 23.15 – [ 115 + (-13)]

= 23.15 – [ 115 - 13]

= 23.15 -  102

= -78.85

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