find the value of x {0<x<(π/2)} satisfying (cos x / cosec x + 1) + (cos x / cosec x-1) = 2 ​

Answer:

f(x) = ( 1/3) ^ (x)

Step-by-step explanation:

The function is

f(x) = (1/3) ^ (x)

When x = 1  f(x) = 1/3

when x=2    f(x) = 1/9

When x = -1  f(x) = ( 1/3) ^ -1 = 3/1 =3

Answer:

f(x)=(1/3)^x

Step-by-step explanation:

Plug in the given values of x in the function above and match the answers with f(x) which is y.

Answer:

70 likes

Step-by-step explanation:

49 likes / 7 minutes = 7 likes / minute

10 minutes * 7 likes / minute = 70 likes / 10 minutes

Answer:

165 seconds

Step-by-step explanation:

If you were going steadily 60 miles per hour, you would go one mile in one minute. So, if you were going steadily 40 miles per hour, without your speed going up or down, you would get through one mile in 3 3/4 minutes (which is 165 seconds more than 1 minute).

Hope this helps. Pls give brainliest! Also, pls sub to kgirl633 on yt!

Answer:

75

Step-by-step explanation:

A triangle can only have 3 angles that add up to 180 degrees. Subtract 70 and 35 from 180 to get 75.

180=x+70+35

180-(70+35)=x

Answer:

yoours

Step-by-step explanation:

thanks again for your time and consideration and I am a kid I am a kid

Answer:

The second years payment is 17689.

Step-by-step explanation:

If the first year is $10,205 then you subtract 10205 from 27894 which is 17689.

Equation: $27894-$10,205= $17689

The correct form of the regression line is [tex]\log time = 0.699 + 0.500\cdot \log length[/tex] (Correct choice: D).

According to the information presented in the figure, we know the following function:

Hence, the correct form of the regression line is:

[tex]\log time = 0.699 + 0.500\cdot \log length[/tex] (Correct choice: D)

The correct form of the regression line is [tex]\log time = 0.699 + 0.500\cdot \log length[/tex] (Correct choice: D).

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Answer:

D: logTime=0.699 + 0.500

Step-by-step explanation:

0.699 is the x value which can be found in data under Coef and Constant. The y value can be found under coef and log(length)

Answer:

C

Step-by-step explanation:

Ti-83 graph proves it.

The value of x in the equation is 364/145

The equation is given as:

[tex]\frac 32x - 5= -\frac 47x + \frac 15[/tex]

Collect the like terms

[tex]\frac 32x + \frac 47x= 5 + \frac 15[/tex]

Take the LCM

[tex]\frac{21x + 8x}{14} = \frac{25 + 1}{5}[/tex]

Evaluate the sum

[tex]\frac{29x}{14} = \frac{26}{5}[/tex]

Cross multiply

[tex]145x = 364[/tex]

Divide both sides by 145

[tex]x = \frac{364}{145}[/tex]

Hence, the value of x in the equation is 364/145

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Step-by-step explanation:

Two t-shirts that are(31.80) plus a hat(6.20) cost £38.00.

which means that one t-shirt costs £15.90 :)

Answer:

ABCD are the first 4 letters ina alphabet sooooo brooo wheres the parallelogram??

Step-by-step explanation:

Answer:

The value of B is 7.

B = 7

Answer:

B = 7

Step-by-step explanation:

first 100 + 47 + 10 + 100 = 257

second 200 + 50 = 250

257 - 250 = 7

Answer:

y = -8

Step-by-step explanation:

-7y + 11 = 75 + y

Bring the "y" variable on one side, and rest on the other.

Rearranging, we get,

-7y - y = 75 - 11

-8y = 64

-y = 8

y = -8

Hope it helps :)

The resulting coordinate will be D'(2, 6), E'(4, -6), and F'(0, 10),

Let the coordinate of the triangle DF be given as D(1, 3), E(2, -3) and F(0, 5).

For the coordinates D(1, 3), E(2, -3), and F(0, 5), assuming the coordinate point is dilated by a factor of 2, the resulting coordinate will be D'(2, 6), E'(4, -6), and F'(0, 10),

Learn more on dilation here: https://brainly.com/question/10253650

Note that the question is answered on a general term.

Answer:

√5

Step-by-step explanation:

I got it right on Edmentum

Hook me up with a 5 star and a thanks :)

Answer:

4 chairs

Step-by-step explanation:

Start with 2/3 can of paint: (2/3)

He used 1/6 of the can to paint each chair: (divided by 1/6)

Now use the 'keep, change, flip' method to get the expression: (2/3x6/1)

Then simplify your answer: (12/3)

Lastly simplify again: (4)

Thus, he painted 4 chairs.

Answer:

The height of the water increases 2 inches per minute.

Step-by-step explanation:

Answer:

Lisa earned $247.50 for working 33 hours.

Step-by-step explanation:

WAY 1: proportional reasoning

7.50 x

------ = ----

1 h 33h

33 / 1 = 33

7.50 x 33 = 247.5

WAY 2: unit rate reasoning

7.50 per hour so x value of money for 33 h

7.50 x 33 = 247.5

Answer:

247.50 Dollars

Step-by-step explanation:

If Lisa earns 7.50$ per hour and she has worked for 33 hours, and then if the question asks how much money she earned it'd have to be 7.50*33. Which is 247.50, and its asking how much money so then you'd have to write the dollars next to the answer, so the answer is,

247.50 Dollars

[tex]\text{Since det(A) = 0, the inverse of the matrix does not exist.}[/tex]

Answer:

y=K*x equation

k=constant of variation

y= 4 when x = 10

Step-by-step explanation:

8=k*20

divide both sides by 20 to solve for k

2/5=k

y=2/5 *10

y= 4 when x = 10

Answer:

48 is 25% of 12

Step-by-step explanation:

Answer:

70

Step-by-step explanation:

the sum of all angles is 180°

so 180-110= 70

Answer:

10×5

Step-by-step explanation:

put a zero at the end of five and make it 50

Answer: 11:12:40

Step-by-step explanation: If im right pls give brainliest

Using the grid model, the product of 3 and 13 is 39

Product refers to the result of multiplying two or more numbers or quantities together. It is a fundamental operation in arithmetic and algebra. When multiplying two numbers, the product is obtained by adding together a number of copies of one of the numbers, equal to the value of the other number.

Given, two numbers 3 and 9, and a grid.

To determine the product of 3 and 13 just count all the grids covered in 3 rows up to 13 columns or adding 3 for 13 times will result in 39.

Count the grids covered in a red box attached in the image below.

3+3+3+3+3+3+3+3+3+3+3+3+3=39

So, the product of 3 and 13 is 39.

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Answer:

60

Step-by-step explanation:

To begin solving think of just the pants and the shirts. Each of the 3 pair of pants can be paired with one of the 5 shirts giving you. 5x3=15 combinations

Therefore to apply this type of situation to all 5 shirts 3 pairs of pants and 4 ties

(5)(3)(4)=60

Answer:

Thermodynamics is a branch of physics that deals with heat, work, and temperature, and their relation to energy, entropy, and the physical properties of matter and radiation.

Answer:

(a) The particle is moving to the right in the interval  [tex](0 \ , \ \displaystyle\frac{\pi}{2}) \ \cup \ (\displaystyle\frac{3\pi}{2} \ , \ 2\pi)[/tex] , to the left in the interval [tex](\displaystyle\frac{\pi}{2}\ , \ \displaystyle\frac{3\pi}{2})[/tex], and stops when t = 0, [tex]\displaystyle\frac{\pi}{2}[/tex], [tex]\displaystyle\frac{3\pi}{2}[/tex] and [tex]2\pi[/tex].

(b) The equation of the particle's displacement is [tex]\mathrm{s(t)} \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(t)} \ + \ 3[/tex]; Final position of the particle [tex]\mathrm{s(2\pi)} \ = \ 3[/tex].

(c)  The total distance traveled by the particle is 9.67 (2 d.p.)

Step-by-step explanation:

(a) The particle is moving towards the right direction when v(t) > 0 and to the left direction when v(t) < 0. It stops when v(t) = 0 (no velocity).

Situation 1: When the particle stops.

[tex]\-\hspace{1.7cm} v(t) \ = \ 0 \\ \\ 5 \ \mathrm{sin^{2}(t)} \ \mathrm{cos(t)} \ = \ 0 \\ \\ \-\hspace{0.3cm} \mathrm{sin^{2}(t) \ cos(t)} \ = \ 0 \\ \\ \mathrm{sin^{2}(t)} \ = \ 0 \ \ \ \mathrm{or} \ \ \ \mathrm{cos(t)} \ = \ 0 \\ \\ \-\hspace{0.85cm} t \ = \ 0, \ \displaystyle\frac{\pi}{2}, \ \displaystyle\frac{3\pi}{2} \ \ \mathrm{and} \ \ 2\pi[/tex].

Situation 2: When the particle moves to the right.

[tex]\-\hspace{1.67cm} v(t) \ > \ 0 \\ \\ 5 \ \mathrm{sin^2(t) \ cos(t)} \ > \ 0[/tex]

Since the term [tex]5 \ \mathrm{sin^{2}(t)}[/tex] is always positive for all value of t of the interval [tex]0 \ \leq \mathrm{t} \leq \ 2\pi[/tex], hence the determining factor is cos(t). Then, the question becomes of when is cos(t) positive? The term cos(t) is positive in the first and third quadrant or when [tex]\mathrm{t} \ \epsilon \ (0, \ \displaystyle\frac{\pi}{2}) \ \cup \ (\displaystyle\frac{3\pi}{2}, \ 2\pi)[/tex] .  

*Note that parentheses are used to demonstrate the interval of t in which cos(t) is strictly positive, implying that the endpoints of the interval are non-inclusive for the set of values for t.

Situation 3: When the particle moves to the left.

[tex]\-\hspace{1.67cm} v(t) \ < \ 0 \\ \\ 5 \ \mathrm{sin^2(t) \ cos(t)} \ < \ 0[/tex]

Similarly, the term [tex]5 \ \mathrm{sin^{2}(t)}[/tex] is always positive for all value of t of the interval [tex]0 \ \leq \mathrm{t} \leq \ 2\pi[/tex], hence the determining factor is cos(t). Then, the question becomes of when is cos(t) positive? The term cos(t) is negative in the second and third quadrant or  [tex]\mathrm{t} \ \epsilon \ (\displaystyle\frac{\pi}{2}, \ \displaystyle\frac{3\pi}{2})[/tex].

(b) The equation of the particle's displacement can be evaluated by integrating the equation of the particle's velocity.

[tex]s(t) \ = \ \displaystyle\int\ {5 \ \mathrm{sin^{2}(t) \ cos(t)}} \, dx \ \\ \\ \-\hspace{0.69cm} = \ 5 \ \displaystyle\int\ \mathrm{sin^{2}(t) \ cos(t)} \, dx[/tex]

To integrate the expression [tex]\mathrm{sin^{2}(t) \ cos(t)}[/tex], u-substitution is performed where

[tex]u \ = \ \mathrm{sin(t)} \ , \ \ du \ = \ \mathrm{cos(t)} \, dx[/tex].

[tex]s(t) \ = \ 5 \ \displaystyle\int\ \mathrm{sin^{2}(t) \ cos(t)} \, dx \\ \\ \-\hspace{0.7cm} = \ 5 \ \displaystyle\int\ \ \mathrm{sin^{2}(t)} \, du \\ \\ \-\hspace{0.7cm} = \ 5 \ \displaystyle\int\ \ u^{2} \, du \\ \\ \-\hspace{0.7cm} = \ \displaystyle\frac{5u^{3}}{3} \ + \ C \\ \\ \-\hspace{0.7cm} = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(t)} \ + \ C \\ \\ s(0) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(0)} \ + \ C \\ \\ \-\hspace{0.48cm} 3 \ = \ 0 \ + \ C \\ \\ \-\hspace{0.4cm} C \ = \ 3.[/tex]

Therefore, [tex]s(t) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(t)} \ + \ 3[/tex].

The final position of the particle is [tex]s(2\pi) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(2\pi)} \ + \ 3 \ = \ 3[/tex].

(c)

[tex]s(\displaystyle\frac{\pi}{2}) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(\frac{\pi}{2})} \ + \ 3 \\ \\ \-\hspace{0.85cm} \ = \ \displaystyle\frac{14}{3} \qquad (\mathrm{The \ distance \ traveled \ initially \ when \ moving \ to \ the \ right})[/tex]

[tex]|s(\displaystyle\frac{3\pi}{2}) - s(\displatstyle\frac{\pi}{2})| \ = \ |\displaystyle\frac{5}{3} \ (\mathrm{sin^{3}(\frac{3\pi}{2})} \ - \ \mathrm{sin^{3}(\displaystyle\frac{\pi}{2})})| \ \\ \\ \-\hspace{2.28cm} \ = \ \displaystyle\frac{5}{3} | (-1) \ - \ 1| \\ \\ \-\hspace{2.42cm} = \displaystyle\frac{10}{3} \\ \\ (\mathrm{The \ distance \ traveled \ when \ moving \ to \ the \ left})[/tex]

[tex]|s(2\pi) - s(\displaystyle\frac{3\pi}{2})| \ = \ |\displaystyle\frac{5}{3} \ (\mathrm{sin^{3}(2\pi})} \ - \ \mathrm{sin^{3}(\displaystyle\frac{3\pi}{2})})| \ \\ \\ \-\hspace{2.28cm} \ = \ \displaystyle\frac{5}{3} | 0 \ - \ 1| \\ \\ \-\hspace{2.42cm} = \displaystyle\frac{5}{3} \\ \\ (\mathrm{The \ distance \ traveled \ finally \ when \ moving \ to \ the \ right})[/tex].

The total distance traveled by the particle in the given time interval is[tex]\displaystyle\frac{14}{3} \ + \ \displaystyle\frac{5}{3} \ + \ \displaystyle\frac{10}{3} \ = \ \displaystyle\frac{29}{3}[/tex].