factorise

3a^2+8a+4


someone help​

Answer:

5 is the base

4 is the exponent

Answer:

D. $2,000

Step-by-step explanation:

Found this answer somewhere and it made sense so I hope its correct :D

Answer:

it is 3500 You take 4000 divide by 200 which is 20 months then take 150 times 20 equals 3000 then add 500

Step-by-step explanation:

Answer:

Paul has not yet posted 6 fliers.

Step-by-step explanation:

How many did he post last week?  (1/5)(70) = 14

This week?  (5/7)(70) = 50

Already posted:  14 + 50 = 64

Not yet posted:  70 - 64 = 6

Answer:

Step-by-step explanation:

Set a system of equations as below:

Multiply the first equation by 150 and subtract from the second equation.

This will eliminate y, solve for x:

(BC + AD) / 2 = 17

(2x + 1 + 3x + 8) / 2 = 17

5x + 9 = 34

5x = 25

x = 5

Answer

y=1/4x

Step-by-step explanation:

2-1/8-4=1/4

Choose either of these points ( I will use 4,1 becuase it's easier)

1=1/4(4)=b

1=1+b

0=b

y=1/4x (you don't put the zero)

Answer:

What? I don't understand your question.

Step-by-step explanation:

just no just n oh yeah btw shoot some

Answer: C) y = -1

Step-by-step explanation:

A horizontal line is represented by y = a constant.  As such, the line must be    y = -1, because the given point is (-3, -1), which has a y-coordinate of -1.

Answer:

D y=-1

Step-by-step explanation:

In horizontal lines, the equation is y=b. B is the location of the y-axis where the line crosses through it. Hope this helps :)

Answer:

41 inches

Step-by-step explanation:

To solve for the diagonal length of his television, we can use the formula:

a² + b² = c²

Square the length and width of the TV then add them together. Then find the square root of the sum.

40² = 1600

9² = 81

1600 + 81 = 1681

√1681 = 41

A.

Jay's original brand is $5 more than the price of a box of the super-saving brand.

Since Jay's original brand costs $15 per box and the price of Luke's super-saving brand is y = 10x where x = number of boxes. For one box, x = 1.

So, y = 10x

y = 10 × 1

y = $10

So, Jay's brand costs $15 per box and Luke brand cost $10 per box.

So, the difference in price is per box is $15 - 10$ = $5

So, Jay's original brand is $5 more than the price of a box of the super-saving brand.

B.

Jay saves $40 per month with the change in cereal brand if he buys 8 cereal boxes each month

Since the difference in price for each box bought is $5. Jay saves $5 for every super-saving cereal brand he buys.

So, if he buys 8 cereal boxes per month, he saves $5 per box × 8 boxes per month = $40 per month.

So, Jay saves $40 per month with the change in cereal brand if he buys 8 cereal boxes each month

Learn more here:

https://brainly.com/question/23741990

m = (Y2 - Y1)/(X2 - X1)

m = (7 - (-6))/(-11 - 17)

m = (7 + 6)/(-28)

m = 13/(-28) = -(13/28)

Answer:

A. She can buy 8 pizzas; B. At least 6 pizzas.

Step-by-step explanation:

Since Grace has $105, we can set our inequality to be less than or equal to that amount of money.  We also know she needs to spend $25 on the cake no matter what.  Assuming x is the amount of pizzas she can buy and each pizza costs $9.25, our inequality looks like this:

9.25x + 25 ≤ 105

To solve this inequality, we first subtract 25 from both sides, which gives us:

9.25x ≤ 80

Then we divide by 9.25 on both sides, giving us:

x ≤ 8.6486

Since Grace is only able to buy whole pizzas, the most she can buy is 8 pizzas.

If each pizza serves 4 people and there are 22 people attending, we need to be able to feed 22 or more people.  We can use this inequality, where x is still the number of pizzas.

4x ≥ 22

Dividing both sides by 4, we get:

x ≥ 5.5

Again, assuming we can only buy whole pizzas, we would need at least 6 pizzas to feed the entire party.

By definition of inverse function,

[tex]F\left(F^{-1}(x)\right) = x[/tex]

so that

[tex]5F^{-1}(x) - 6 = x[/tex]

[tex]5F^{-1}(x) = x + 6[/tex]

[tex]F^{-1}(x) = \dfrac{x + 6}5[/tex]

Similarly,

[tex]G\left(G^{-1}(x)\right) = G^{-1}(x) - 4 = x \implies G^{-1}(x) = x+4[/tex]

Then the inverse of the composition [tex]F\circ G[/tex] is such that

[tex]\left(F \circ G\right) \left((F \circ G)^{-1}(x)\right) = x[/tex]

By definition of composition,

[tex](F\circ G)(x) = F(G(x))[/tex]

Applying [tex](F\circ G)^{-1}[/tex] to this recovers x, and this involves first inverting F, then G:

[tex](F\circ G)^{-1}(x) = G^{-1}\left(F^{-1}(x)\right)[/tex]

So, we find

[tex](F\circ G)^{-1}(x) = G^{-1}\left(F^{-1}(x)\right) = G^{-1}\left(\dfrac{x+6}5\right) = \dfrac{x+6}5 + 4 = \boxed{\dfrac{x+26}5}[/tex]

Answer:

26,530,000

Step-by-step explanation:

this is quite easy, first you can write this question differently

Just view this problem as 7 x 379 which is 2653, now count how many zeros 70,000 has, which is 4 and add it to the answer 2653, which will give you 26,530,000

The multiplication or products of 70,000 and 379 is 26,530,000

Given:

70,000 × 379

= 26,530,000

Where from the left,

In words, 26,530,000 is written as twenty six million, five hundred and thirty thousand.

Learn more about multiplication;

https://brainly.com/question/10873737

Answer:

Step-by-step explanation:

Direct variation:

Inverse variation:

Given:

and

From the first equation we can see:

It means if p varies directly as q, then q directly varies as p.

Square the second equation:

Since p varies directly as q and q varies inversely with t⁴, we can state p varies inversely with t⁴.

Answer:

Step-by-step explanation:

System of equations according to given:

Substitute n into first equation and solve for s:

Equations are

EQUATION(2)× 30

[tex]\\ \sf\longmapsto 30x-30y=120--(3)[/tex]

Subtracting (1) and (3)

[tex]\\ \sf\longmapsto 80y=560[/tex]

[tex]\\ \sf\longmapsto y=7[/tex]

The corresponding answers for each student plan are:

plan A: 15 years

plan B: 5 years

plan C: 10 years

plan D: 9 years

Thus, first, the graph corresponding to each of the plans must be analyzed. The Y-axis corresponds to money and the x-axis corresponds to the time in years.

Thus, in-plane A, it can be observed that to reach the desired value, the graph will be projected in exponential, so it will be close to 15 years. In plan B, this projection will be reached around 5 years. In plans C and D, this projection will be 10 years and 9 years respectively.

Answer:it's 13

please let me know if this is wrong

Answer:

Answer:

i am uncertain by the question

Step-by-step explanation:

10-3=7

10/3=3.333...

Answer:

the answer is "what are you doing step

bro"

Answer: See below.

Step-by-step explanation:

See attachment. It depends on what is considered the "third" term. If n=2 then the result is 16. If 3, the result is 36.

Answer:

there is no y axis because the term is kept in second of y and if that is negative then only y axis will there otherwise there will no y axis

The ordered pair represents the reflection of the point (−2,3) over the y-axis is (2, 3)

A reflection of a point in the axes involved reflecting the image over the axes to create a mirror image.

Given that, a point is (-2,3) is being reflected over y-axis,

Rule of reflection over y-axis is, A(x, y) ↔ A'(-x, y)

Therefore, applying the rule to (-2,3):

(-2,3) ↔ (2, 3)

Hence, the reflected point is (2, 3)

For more references on reflection over axes, click;

https://brainly.com/question/29253977

#SPJ2

Answer:

B) 7 - 5x

Step-by-step explanation:

7 - 5x is the difference between the number 7 and the product of 5 and 'x'

Answer:

b)

Step-by-step explanation:

i hope this help you

Answer:

10:32

Step-by-step explanation:

32-22=10 male teachers

Answer:

g(x) = 2|x|: vertical stretch by a factor of 2.

h(x) = ⅓|x|: vertical compression by a factor of ⅓.

w(x) = 4|x|: vertical stretch by a factor of 4.

Step-by-step explanation:

Given the graph of an absolute value parent function, f(x) = |x|:

Multiplying the parent function by a number, where a > 1 causes a vertical stretch by a factor of a.  

Hence, when a > 1, the graph is narrower than the parent function.

In the case of the function, g(x) = 2|x|, the graph represents a vertical stretch by a factor of 2.  When a vertical stretch occurs, the y-coordinates will be twice of what the y-coordinates of the parent function.  For instance, compare the y-coordinates of f(x) = |x| and g(x) = 2|x|  when x = 1.  

In the parent graph, f(x) = |x|: when x = 1, y = 1.

In g(x) = 2|x|, when x = 1, y = 2.

Multiplying the parent function by a number, where 0 < a < 1 causes a vertical compression by a factor of a.  

Hence, when 0 < a < 1 , the graph is wider than the parent function.    

In the case of the function, h(x) = ⅓|x|, the graph represents a vertical compression by a factor of ⅓.  When a vertical compression occurs, the y-coordinates will be ⅓ of what the y-coordinates of the parent function.

If you compare the y-coordinates of the parent function, f(x) = |x|, and h(x) = ⅓|x|,  when x = 1:

In the parent graph, f(x) = |x|: when x = 1, y = 1.

In h(x) = ⅓|x|:  when x = 1, y = ⅓.

Using the same techniques presented in the previous sections of this post, we could focus on comparing the difference between the y-coordinates of the parent graph, f(x) = |x|, and w(x) when x = 1.

In the parent graph, f(x) = |x|: when x = 1, y = 1.

In w(x) = a|x|,  when x = 1, y = 4.  

This shows that the graph is vertically stretched by a factor of 4, where the graph appears narrower than the parent function.

Therefore, the function that represents the given graph is w(x) = 4|x|.

Answer:

6 time

Step-by-step explanation:

97÷14=6•928

=6 or round it up to 7

Answer:

6

Step-by-step explanation:

97÷14=6.928

6 or round it up to 7

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\boxed{\textsf{2y = 24}}\\\\\large\text{DIVIDE 2 to BOTH SIDES}\\\\\large\boxed{\mathsf{\dfrac{2y}{2}=\dfrac{24}{2}}}\\\\\large\text{CANCEL out: }\rm{\dfrac{2}{2}}\large\text{ because it gives you 1}\\\large\text{KEEP: }\rm{\dfrac{24}{2}}\large\text{ because it gives you the answer of the y-value.}\\\\\large\boxed{\mathsf{12= \dfrac{24}{2}}}\\\\\large\text{SIMPLIFY IT!}\\\\\large\boxed{\mathsf{y = 12}}\\\\\huge\text{Therefore, your answer is: \boxed{\mathsf{a = 12}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]