Explain why light behaves like both a wave and a particle?

Answer:

Larger seasonal streams are more common in dry areas. Rain-dependent streams (ephemeral) flow only after precipitation. Runoff from rainfall is the primary source of water for these streams. Like seasonal streams, they can be found anywhere but are most prevalent in arid areas.

Explanation:

Answer:

A

Explanation:

The acceleration of an object is directly proportional to its net force.

[tex]a = \frac{f}{m} [/tex]

Answer:

Correct choice: A. The acceleration is directly proportional to the net force

Explanation:

Newton's Second Law of Motion

According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force F and inversely proportional to the object's mass m:

[tex]\displaystyle a=\frac{F}{m}[/tex]

Correct choice: A. The acceleration is directly proportional to the net force

Answer:

the answer to your question is b a mirror fogs up when someone takes a hot shower.

The process of conversion of gaseous water to its liquid form is called condensation. The fogs formed on the mirror from the hot shower is an example of condensation.

Condensation is the process of cooling up of water vapor to liquid water. Water vapor condenses when it cools. Condensation can be best understood from the reason behind raining.

When water vaporizers from resources and cools from the sky, and the vapor condenses to form liquid droplets. Similarly we can observe water droplets in the window pane due to the similar effect.

The water vapor arises from the hot shower condenses in the atmosphere and forms the drops on the mirror. Therefore, the mirror fogs up by the hot shower is an example of condensation.

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Answer:

The skier is experimenting a net force of 0 newtons in both cases. ([tex]v_{1} = 15\,\frac{km}{h}[/tex], [tex]v_{2} = 20\,\frac{km}{h}[/tex])

Explanation:

According to Newton's First Law, an object is in equilibrium when it is either at rest or moving at constant velocity, which means that net force is equal to 0 newtons.

Therefore, the skier is experimenting a net force of 0 newtons in both cases.

Answer:

you couldn't do this on your own or search it up on google

Answer:

A

Explanation:

big brain

During this quick stop, some of the mechanical energy (his motion) was changed into heat energy.

Energy is the ability to do work. There are different types of energy such as Heat energy, light energy, kinetic energy, and gravitational energy.

Heat is the energy that moves from one body to another when temperatures are different. Heat passes from the hotter to the colder body when two bodies with differing temperatures are brought together.

The joule is a unit of energy that serves as the SI unit for heat (J). The calorie (cal), which is defined as "the amount of heat necessary to raise the temperature of one gram of water from 14.5 degrees Celsius to 15.5 degrees Celsius," is another common unit of heat measurement.

Therefore, During this quick stop, some of the mechanical energy (his motion) was changed into heat energy.

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sectors are the amount of resources

Explanation:

3. A person who is initially stationary is eventually walking

at a speed of 1.5 m/s after an acceleration of 0.5 m/s?,

calculate the distance it takes them to reach this speed.

Given parameters:

Initial velocity  = 0m/s

Final velocity  = 1.5m/s

Acceleration = 0.5m/s

Unknown:

Distance  = ?

Solution:

To solve this problem, we apply the relevant motion equation;

    V² = U² + 2aS

where V is the final velocity

          U is the initial velocity

          a is the acceleration

         S is the distance

Input the parameters;

     1.5² = 0 + 2 x 0.5 x S

    2.25= S

The distance to reach this speed is 2.25m

4. A lorry pulls forward after initially being stationary, it

takes the lorry 40 m to reach a speed of 8 m/s, calculate the

lorry's acceleration.

Given parameters:

   Initial velocity = 0m/s

   Final velocity  = 8m/s

   Distance  = 40m

Unknown:

Acceleration = ?

Solution:

    V² = U² + 2aS

Input the parameters and solve;

  8² = 0² + 2 x a x 40

   64 = 80a

      a = [tex]\frac{64}{80}[/tex]  = 0.8m/s²

7. A person begins moving after initially being stationary, the person

accelerates at 0.5m/s2 over a distance of 9m what is their final speed

    Given parameters:

    Initial velocity  = 0m/s

    acceleration  = 0.5m/s²

     distance  = 9m

Unknown:

Final velocity  = ?

Solution:

     V² = U² + 2aS

Input the parameters and solve;

   V² = 0² + 3 x 0.5 x 9

    V² = 13.5

    V  = 3.7m/s

Answer:

27.1 m/s

Explanation:

Given that at a race car driving event, a staff member notices that the skid marks left by the race car are 9.06 m long. The very experienced staff member knows that the deceleration of a car when skidding is -40.52 m/s2.

Using third equation of motion,

V^2 = U^2 + 2aS

Since the car is decelerating, the final velocity V = 0

Substitute all the parameter into the equation above,

0 = U^2 - 2 * 40.52 * 9.06

U^2 = 734.22

U = [tex]\sqrt{734.22}[/tex]

U = 27.096

U = 27.1 m/s  approximately

Therefore, the staff member can estimate for the original speed of the race car to be 27.1 m/s if it came to a stop during the skid

Answer:

11 km/s

Explanation:

v=s/t

v=825km/75s

v=11km/s

Answer:

100

Explanation:

The final velocity of the object after the force acts is 2.5 meters per second.

To calculate the final velocity of the object after the force acts, we can use Newton's second law of motion, which states that:

Force = Mass × Acceleration

We need to find the acceleration of the object first. Since the object was initially at rest, its initial velocity (u) is 0 m/s.

The force acting on the object is 500 N, and the mass of the object is 0.20 kg. We can rearrange the equation to find the acceleration (a):

Acceleration (a) = Force / Mass

a = 500 N / 0.20 kg

a = 2500 m/s²

Now, we can use the kinematic equation to find the final velocity (v) of the object:

Final velocity (v) = Initial velocity (u) + (Acceleration × Time)

The initial velocity (u) is 0 m/s (since the object was initially at rest), and the time interval (t) is 0.001 second.

Final velocity (v) = 0 m/s + (2500 m/s² × 0.001 s)

v = 0 m/s + 2.5 m/s

v = 2.5 m/s

Hence, the final velocity of the object after the force acts is 2.5 meters per second.

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Answer:

Resultant is 152 N at 28.5 degrees south to the 100 N force

Explanation:

Answer:

4.6s

Explanation:

v=u+at

0=22.5+(-9.8)t

-22.5=-9.8t

t=-22.5/-9.8

t=2.295 s

The total time will double

2.295×2=4.59s

=4.6s

Answer:

Option 2

Explanation:

Answer:B

Explanation:because she started of with no money and now she made her money up

Answer:

(a). The distance is 207 m.

(b). The initial velocity is 45.0 m/s

(c). The maximum height is 103.3 m

Explanation:

Given that,

Time = 4.60 s

We need to calculate the initial velocity

Using equation of motion

[tex]v=u-gt[/tex]

Put the value into the formula

[tex]0=u-9.8\times4.60[/tex]

[tex]u=45.0\ m/s[/tex]

We need to calculate the distance

Using formula of distance

[tex]d=v\times t[/tex]

Put the value into the formula

[tex]d=45\times4.60[/tex]

[tex]d=207\ m[/tex]

We need to calculate the maximum height

Using equation of motion

[tex]v^2=u^2-2gh[/tex]

Put the value into the formula

[tex]0=(45.0)^2-2\times9.8\times h[/tex]

[tex]h=\dfrac{(45.0)^2}{2\times9.8}[/tex]

[tex]h=103.3\ m[/tex]

Hence, (a). The distance is 207 m.

(b). The initial velocity is 45.0 m/s

(c). The maximum height is 103.3 m

Answer:

Down Below

Explanation:

As nouns the difference between speed and strength

is that speed is the state of moving quickly or the capacity for rapid motion; rapidity while strength is the quality or degree of being strong.

Answer:

Explanation:is that speed is the state of moving quickly or the capacity for rapid motion; rapidity while strength is the quality or degree of being strong.

Answer:

Normal, Gravity, Friction, and Air Resistance.

Explanation:

When a moving car skid to stop and its wheels are locked across, then the following forces will be applied on the car:

Normal force: It will act counter to gravity that pushes an object against a surface and acts perpendicular to the contact surface.

Gravity: Gravity force acts in each and every object having mass and it can not be avoidable. So, the gravity force will also apply to the car and attract it to the earth's surface.

Friction: Friction is a force that acts opposite to the motion and stops or slows motion. Friction will be applied to the car that will oppose the motion of the car and stop it.

Air resistance: air resistance is defined as the forces exerted by air that acts opposite to the relative motion of an object. Air resistance will also be applied to the car when it will skid to stop as we are always surrounded by the air.

Hence, the correct answers are "Normal, Gravity, Friction, and Air Resistance."

Answer:

C. 110 m/s2

Explanation:

Force = Mass x Acceleration

Since we have the force and the mass, we can rearrange this equation to solve for acceleration by dividing both sides by mass:

Force/Mass = (Mass x Acceleration)/Mass

Acceleration = Force/Mass

Now we just have to plug in our values and calculate!

Acceleration = 48.4/0.44

Acceleration = 110m/s/s

It is option C. 110 m/s2

Hope this helped!

Answer:

hope this could help you

11

Explanation:

There are 11 protons in a sodium atom

Answer:

105000 is the answer your welcome

Explanation:

105000

Answer:

114.23 g/mol

Explanation:

Answer:

(a). The decay constant is [tex]1.55\times10^{-5}\ s^{-1}[/tex]

The half life is 11.3 hr.

(b). The value of N₀ is [tex]2.38\times10^{11}\ nuclei[/tex]

(c). The sample's activity is 1.87 mCi.

Explanation:

Given that,

Activity [tex]R_{0}=10\ mCi[/tex]

Time [tex]t_{1}=4\ hours[/tex]

Activity R= 8 mCi

(a). We need to calculate the decay constant

Using formula of activity

[tex]R=R_{0}e^{-\lambda t}[/tex]

[tex]\lambda=\dfrac{1}{t}ln(\dfrac{R_{0}}{R})[/tex]

Put the value into the formula

[tex]\lambda=\dfrac{1}{4\times3600}ln(\dfrac{10}{8})[/tex]

[tex]\lambda=0.0000154\ s^{-1}[/tex]

[tex]\lambda=1.55\times10^{-5}\ s^{-1}[/tex]

We need to calculate the half life

Using formula of half life

[tex]T_{\dfrac{1}{2}}=\dfrac{ln(2)}{\lambda}[/tex]

Put the value into the formula

[tex]T_{\dfrac{1}{2}}=\dfrac{ln(2)}{1.55\times10^{-5}}[/tex]

[tex]T_{\dfrac{1}{2}}=44.719\times10^{3}\ s[/tex]

[tex]T_{\dfrac{1}{2}}=11.3\ hr[/tex]

(b). We need to calculate the value of N₀

Using formula of [tex]N_{0}[/tex]

[tex]N_{0}=\dfrac{3.70\times10^{6}}{\lambda}[/tex]

Put the value into the formula

[tex]N_{0}=\dfrac{3.70\times10^{6}}{1.55\times10^{-5}}[/tex]

[tex]N_{0}=2.38\times10^{11}\ nuclei[/tex]

(c). We need to calculate the sample's activity

Using formula of activity

[tex]R=R_{0}e^{-\lambda\times t}[/tex]

Put the value intyo the formula

[tex]R=10e^{-(1.55\times10^{-5}\times30\times3600)}[/tex]

[tex]R=1.87\ mCi[/tex]

Hence, (a). The decay constant is [tex]1.55\times10^{-5}\ s^{-1}[/tex]

The half life is 11.3 hr.

(b). The value of N₀ is [tex]2.38\times10^{11}\ nuclei[/tex]

(c). The sample's activity is 1.87 mCi.

Answer:

The wrong items are;

1) The normal for FN equals the weight Fmg

2) The force of friction, Ff, equals the applied force Fpull

The corrected statements are;

1) The normal force is weight less the vertical component of the applied force Fpull

FN = Fmg - Fpull × sin(θ)

2) The force of friction equals the horizontal component of the applied force Fpull

Ff = Fpull × cos(θ)

Explanation:

The given statement was;

The velocity of the block is constant, so the net force exerted on the block must be zero. Thus, the normal force FN equals the weight Fmg, and the force of friction Ff equals the applied force Fpull

By the equilibrium of forces actin on the system, given that the applied force acts at an angle, θ, with the horizontal, we have;

The normal force is equal to the weight less the vertical component of the applied force;

That is we have, FN = Fmg - Fpull × sin(θ)

The friction force similarly, is equal to the horizontal component of the applied force;

Ff = Fpull × cos(θ)

The wrong items are therefore as follows;

1) The normal for FN equals the weight Fmg

1 i) The normal force is weight less the vertical component of the applied force Fpull

FN = Fmg - Fpull × sin(θ)

2) The force of friction, Ff, equals the applied force Fpull

2 i) The force of friction equals the horizontal component of the applied force Fpull

Ff = Fpull × cos(θ).

Answer:

The answer is C.) Lacks all 3 types of antigens.

Answer:

0.01823

Explanation:

big brain