Answer:
The graphic organizers help to keep track of the details. They are a visual representation of knowledge that rescue the important aspects of a concept using labels within a scheme. They also present information in a concise manner, highlighting the organization and the relationship of the concepts. Graphic organizers help students organize their thinking process and their writing.
Explanation:
Velocity is an extensive property of a system. TRUE OR FALSE
[tex] \: \: \: [/tex]
[tex] \pink{false}[/tex]
because velocity is neither an intensive nor extensive propertyhope it helpsAnswer:
False
Explanation:
I hope this helped have a great day!!!
Two students run a race. Student A is 50 kg and runs at 5 m/s. Student B is 30 kg and runs at 2 m/s. Which
student has more Kinetic energy?
Answer:
Explanation:
KEA = ½(50)5² = 625 J
KEB = ½(30)2² = 60 J
Student A has more kinetic energy.
More than ten times more kinetic energy due to both larger mass and higher velocity.
plz help ASAP I'll mark as brainliest
Hi there!
1.
Hooke's law states that:
F = -kx
k = Spring constant (N/m)
x = DISPLACEMENT from equilibrium (m)
Essentially, the force of a spring is PROPORTIONAL to its spring constant and its displacement from its equilibrium point.
2.
The force of the spring (T) is not proportional to the spring's length (l), but rather its DISPLACEMENT from its equilibrium length. (Δl)
3.
The equilibrium length is where the force of the spring (T) = 0N. Looking at the graph, the line intersects this value at l = 30cm.
4.
We can begin by looking at the given graph.
When the spring force = 4N, the total length of the spring is 35 cm.
Now, the EQUILIBRIUM length is 30 cm, so the total elongation is:
35 - 30 = 5 cm.
5.1.
If the spring elongates by 10 cm, the total length of the spring is:
30 + 10 = 40 cm
According to the graph, a length of 40 cm corresponds to a force of 8N.
5.2.
We can solve for the weight of the ball using the following:
W (weight) = m (mass) · acceleration due to gravity (10N/kg)
Using a summation of forces:
∑F = T - W
The elongation that we are solving for occurs at the equilibrium point (net force = 0 N), so:
0 = T - W
T = W = 8 N
5.3.
0 = T - Mg
T = Mg
Use the prior value of T and gravity to solve:
8 = 10M
m = 0.8 kg
How can whales descend quickly and face no problems
Answer:
Whales face an increasing number of threats including: For hundreds of years people hunted whales for their oil to fuel lamps and candles, to lubricate machinery and to make margarine, lipsticks and other products. They also used baleen whales to make tennis racquets and corsets!
Explanation:
Energy can be changed from one form to another. Which terms can be used to describe these changes? Check all
that apply.
energy conversion
energy conservation
energy correlation
energy transformation
energy transference
Answer:
energy transformation
Answer: Energy Transformation & Energy Conversion.
A dockworker applies a constant horizontal force of 80.0 N to a block of ice on a smooth horizontal floor. The frictional force is negligible. The block starts from rest and moves 11.0 m in 5.00 s. (a) what is the mass of the block office? (b) If the worker stops pushing at the end of 5.00 s, how far does the block move in the next 5.00 s?
Answer:
(a) 91 kg (2 s.f.) (b) 22 m
Explanation:
Since it is stated that a constant horizontal force is applied to the block of ice, we know that the block of ice travels with a constant acceleration and but not with a constant velocity.
(a)
[tex]s \ = \ ut \ + \ \displaystyle\frac{1}{2} at^{2} \\ \\ a \ = \ \displaystyle\frac{2(s \ - \ ut)}{t^{2}} \\ \\ a \ = \ \displaystyle\frac{2(11 \ - \ 0)}{5^{2}} \\ \\ a \ = \ \displaystyle\frac{22}{25} \\ \\ a \ = \ 0.88 \ \mathrm{m \ s^{-2}}[/tex]
Subsequently,
[tex]F \ = \ ma \\ \\ m \ = \ \displaystyle\frac{F}{a} \\ \\ m \ = \ \displaystyle\frac{80 \ \mathrm{kg \ m \ s^{-2}}}{0.88 \ \mathrm{m \ s^{-2}}} \\ \\ m \ = \ 91 \mathrm{kg} \ \ \ \ \ \ (2 \ \mathrm{s.f.})[/tex]
*Note that the equations used above assume constant acceleration is being applied to the system. However, in the case of non-uniform motion, these equations will no longer be valid and in turn, calculus will be used to analyze such motions.
(b) To find the final velocity of the ice block at the end of the first 5 seconds,
[tex]v \ = \ u \ + \ at \\ \\ v \ = \ 0 \ + \ (0.88 \mathrm{m \ s^{-2}})(5 \ \mathrm{s}) \\ \\ v \ = \ 4.4 \ \mathrm{m \ s^{-1}}[/tex]
According to Newton's First Law which states objects will remain at rest
or in uniform motion (moving at constant velocity) unless acted upon by
an external force. Hence, the block of ice by the end of the first 5
seconds, experiences no acceleration (a = 0) but travels with a constant
velocity of 4.4 [tex]m \ s^{-1}[/tex].
[tex]s \ = \ ut \ + \ \displaystyle\frac{1}{2}at^{2} \\ \\ s \ = \ (4.4 \ \mathrm{m \ s^{-2}})(5 \ \mathrm{s}) \ + \ \displaystyle\frac{1}{2}(0)(5^{2}) \\ \\ s \ = \ 22 \ \mathrm{m}[/tex]
Therefore, the ice block traveled 22 m in the next 5 seconds after the
worker stops pushing it.
Do you think the rider in the above figure is really in danger? What If people below were removed?
The rider will be in danger when the people below are removed, because they initially helped to maintain equilibrium.
A system subjected to different forces is said to be in equilibrium when all the forces applied to the system are equal.
For a system subject to two opposite forces, the following exists;
If the upward force and the downward forces are equal, the system will remain in equilibrium positionIf the upward or downward force is greater than the other, the system will move in the direction of the greater force.Thus, we can conclude that the rider will be in danger when the people below are removed, because they initially helped to maintain equilibrium. Once these people are removed, the rider tends to move at a greater speed and possibly fall from the initial position.
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A sailcraft is stalled on a windless day. A fan is attached to the craft and blows air into the sail which bounces backward upon impact. The boat can what?
Answer:
Impulse = change in momentum w bounce
There are 2 impulses acting. Recoil of the fan going the negative direction and the impulse of the air bouncing off the sail. The greater impulse will bounce so the direction will be to the right moving the craft.
PLEASE ANSWER QUICK GIVING BRAINLIEST TO THE ONE WHO ANSWERS
Describe what happens when iron and oxygen combine. Can the change be reversed?
Answer:
iron combines with oxygen to produce rust, which is the compound named iron oxide.
Explanation:
Need quite a bit of help
When the cart was at Table
Normal reaction (N)=mgNow acceleration due to gravity acting on the gravity.
When the air comes out of straw it tries to take the cart upwards.But the force is equal to that of acceleration due to gravity but in opposite direction.Hence.
[tex]\\ \sf\Rrightarrow F_{net}=0N[/tex]
So the cart doesn't move9. If the force acting on a mass of 4kg accelerates it at a rate of 2m/s2, what will be the acceleration of the body when the force is doubled?
Explanation:
Force= mass× acceleration
Force= 4×2
= 8N
Doubling the force, 8×2= 16N
16= 4 × a
a= 16/4
= 4m/s²
Blonde hair is produced by inheriting double recessive alleles (bb) from one’s parents. What is the probability of their offspring having blonde hair?
plz help
Answer:
25%
Explanation:
A cylinder with a radius of 1.8 cm is floating in water as shown below. The mass of the cylinder is 1.80 kg. Calculate the depth of the bottom end of the cylinder
Answer:
Explanation:
I will ASSUME that the cylinder floats with the axis through the center of its flat ends is perpendicular to the water surface.
The cylinder will displace it's mass in water.
water density has a value of 1000 kg/m³
if the depth of the bottom is "h" in meters
1.80 kg = π(0.018² m²)(h m)(1000) kg/m³
h = 1.768388256...
or about 1.77 m
2. Where do hyperbolic comets originate?
A.the Oort cloud
B.the asteroid belt
B.the Kuiper belt
C.interstellar space
Answer:
Hyperbolic comets originate from the Kuiper Belt.
Giving all of my points! (please help with a few questions if you can)
Physical Science A Semester Exam Hydrogen is in Group 1 of the periodic table. Which kind of bond would form between two hydrogens?
O A covalent bond would form because the electron would be shared so both hydrogens have a full, stable shell.
O An ionic bond would form because both atoms are nonmetals.
O An ionic bond would form because one hydrogen would transfer its valence electron to the other hydrogen to make a full
O A metallic bond would form because both atoms are metals.
[tex]\huge \bf༆ Answer ༄[/tex]
The Correct choice is ~ A
A covalent bond would form because the electron would be shared so both hydrogens have a full, stable shell.
A covalent bond would form between two hydrogens because the electron would be shared so both hydrogens have a full, stable shell.
What is covalent bond?Equal shares of electrons from the two involved atoms result in the formation of a covalent bond. This sort of bonding's electron pair is known as the shared pair or bonding pair. Molecular bonds are another name for covalent bonds. The atoms will reach stability in their outer shell, analogous to the atoms of noble gases, thanks to the sharing of bonding pairs.
The simplest material with a covalent bond is the hydrogen molecule. Two hydrogen atoms, each with one electron in a 1s orbital, combine to produce it. The two electrons in the covalent bond are shared by both hydrogen atoms, and each one takes on an electron configuration like that of helium.
Learn more about covalent bonds here:
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1. A 1.30 kg ball strikes a wall with a velocity of -10.5 m/s. The ball bounces off with a velocity of 6.50 m/s. If the ball is in contact with the wall for 0.0210 seconds, what is the force exerted
on the ball by the wall?
O 1050 N
22.1 N
0 402 N
0 651 N
CAN SOMEONE PLS PLS ACTUALLY HELP ME
Let F be the magnitude of the force. The impulse of this force while the ball is in contact with the wall is
Ft = F (0.0210 s)
and this impulse is equal to the change in the ball's momentum,
m ∆v = (1.30 kg) (6.50 m/s - (-10.5 m/s)) = (1.30 kg) (17.0 m/s)
Solve for F :
F (0.0210 s) = (1.30 kg) (17.0 m/s)
F = (1.30 kg) (17.0 m/s) / (0.0210 s)
F ≈ 1050 N
6. The first vertebrates appeared during
a. Precambrian time
b. the Paleozoic Era
C. the Mesozoic Era
d. The Cenozoic Era
Answer:
b. the Paleozoic Era
Explanation:
The first vertebrates to appear are primitive fish in the Cambrian Period, but bony fishes with actual bony vertebratae didn't appear for another 100 million years. The Cambrian Period is the first of three periods in the Paleozoic Era. The Cambrian explosion was an event when practically all major animal phyla started appearing in the fossil record.
A ball is kicked horizontally from a 60 meter tall cliff at 10 m/s. How far from
the base of the cliff does it land?
Hi there!
We can begin by deriving the equation for how long the ball takes to reach the bottom of the cliff.
[tex]\large\boxed{\Delta d = v_it+ \frac{1}{2}at^2}}[/tex]
There is NO initial vertical velocity, so:
[tex]\large\boxed{\Delta d= \frac{1}{2}at^2}}[/tex]
Rearrange to solve for time:
[tex]2\Delta d = at^2\\\\t = \sqrt{\frac{2\Delta d}{g}}[/tex]
Plug in the given height and acceleration due to gravity (g ≈ 9.8 m/s²)
[tex]t = \sqrt{\frac{2(60)}{(9.8)}} = 3.5 s[/tex]
Now, use the following for finding the HORIZONTAL distance using its horizontal velocity:
[tex]\large\boxed{d_x = vt}\\\\d_x = 10(3.5) = \karge\boxed{35 m}[/tex]
8/10
A person stands on a square pedestal whose side lengths are
1.20 m. The person and pedestal together weigh 1.84 x 103 N.
What is the pressure the person and and pedestal exert on the
floor in Pa?
Answer:
Explanation:
P = 1.84 x 10³ N / 1.20² m² = 1,277.77777... N/m²
P = 1.28 x 10³ Pa
2. What is the oxidation number of oxygen in most compounds?
A. 6
B.-2
C. 8
D.O
Answer:i am pro
kExplanation:
if it takes a track runner 2.16 seconds to reach a speed of 5.31 m/s from the start of a race, what is the runners acceleration?
Answer:
Explanation:
Answer:
Explanation:
8.
When minerals seep into and replace the organic cells of a dead organism, creating a
mineral replica of the organism is called ...
Petrification
b. Tar Seeps
C. Amber
d. Mummification
Answer:
a. petrification
Explanation:
tar seeps = natural trade that, because of its close proximity to the ground surface, seeps from the cracks in the Earth or between rocks forming pits or pools (tar pits)
amber = fossilized resin produced by extinct coniferous trees, typically yellow in color
mummification = a process in which the skin and flesh of a corpse can be preserved by embalming and drying
6. A man with a mass of 75 kg standing on a skateboard is holding a medicine ball that has
a mass of 20 kg. If the man throws the ball to the left with a speed of 10 m/s,
a) What happens to the man on the skateboard?
b) What is the man's speed after throwing the ball?
Answer:
Explanation:
Conservation of momentum
a) the man and skateboard move to the right.
b) His speed depends on the reference frame of the ball speed.
If the speed of the ball is 10 m/s relative to ground and the man's final speed is v, then.
(75 + 20)(0) = 20(10) + 75(v)
v = -200/75 = -2.6666...
|v| = 2.7 m/s relative to the ground
This is the likely answer they are seeking.
If the ball is thrown with a speed of 10 m/s relative to the man
(70 + 20)(0) = 20(v + 10) + 75v
20v + 200 = - 75v
200 = - 95v
v = -2.105... m/s velocity or a speed of
|v| = 2.1 m/s relative to ground
and the ball has a velocity of 10 - 2.1 = 7.9 m/s relative to ground.
As a truck rounds a curve, a box in the bed of the truck slides to the side farthest from the center of the curve. This movement of the box is a result of
Answer:
inertia
Explanation:
the mass of the box will want to continue on its straight line motion.
As centripetal force on the wheel treads causes the truck to turn, frictional force between the box and truck bed is insufficient to keep the box turning at the same rate that the truck turns, so relative velocity occurs between box and bed until the centripetal force is increased by contact with the truck side wall farthest from the center of curvature.
5. Which statement about the acceleration of an object is corr
a. The acceleration of an object is directly proportional to t
external force acting on the object and inversely propo
mass of the object.
b. The acceleration of an object is directly proportional to
external force acting on the object and directly propor
mass of the object.
c. The acceleration of an object is inversely proportional
external force acting on the object and inversely prop
mass of the object.
d. The acceleration of an object is inversely proportiona
external force acting on the object and directly propo
mass of the object.
Answer:
a
Explanation:
you will find out that an object that has more weight requires more energy to move than the one with less weight
How do you find the capacitance in this?
Answer:
Explanation:
parallel capacitances add directly
Series capacitances add by reciprocal of sum of reciprocals.
Ceq = [ C ] + [1 / (1/C + 1/C)] + [1 / (1/C + 1/C + 1/C)]
Ceq = [ C ] + [C / 2] + [C / 3]
Ceq = [ 6C/6 ] + [3C / 6] + [2C / 6]
Ceq = 11C/6
The potential at point P is the work required to bring a one-coulomb test charge from far
away to the point P?
True or false ?
A model shows a machine that works using electric fields. What would this machine need for the electrical field to function properly
True or False. Father of a multitude" obeyed God's command to kill His son because the Ten Commandments had not yet been given.
Answer:
Explanation:
He agreed to the command, because it was God who proposed it. The story is supposed to make a comment on faith. Abraham had faith that somehow God would make everything right. The Ten commandments came later, but really had nothing to do with Abraham's decision.
True.
What is the average momentum of Cart 1 during the entire time shown before
kg-m
the collision, in units .?
$
Note that the collision appears to take place somewhere between 0.5 s and 0.6
s (perhaps at 0.6 s exactly, but we cannot be sure), so we can safely say that
data up to and including 0.5 s is "before the collision."
The average momentum of Cart 1 during the entire time shown before the collision is 0.24 kgm/s.
The given parameters:
Mass of the cart 1 = 500 g = 0.5 kgThe average velocity of the cart 1 before collision is calculated as follows;
[tex]v = \frac{\Delta x}{\Delta t} \\\\v = \frac{0.55 - 0.31}{0.5 - 0} \\\\v = 0.48 \ m/s\\\\[/tex]
The average momentum of Cart 1 during the entire time shown before the collision is calculated as follows;
[tex]P = mv\\\\P = 0.5 \times 0.48\\\\P = 0.24 \ kgm/s[/tex]
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