Deshaun Watson launches a football at a speed of 24.7 ms and an angle of 33° above the horizontal How far down
the football field does the football land? What is the max height the football reaches during flight?
Show work

Answers

Answer 1

Answer:

9.23m

Explanation:

Max height = u²sin²theta/2g

u is the speed = 34.7m/s

theta is the angle of elevation = 33°

g is the acceleration due to gravity = 9.8m/s²

Substitute into the formula

Max height = 24.7²sin²33/2(9.8)

Max height = 610.09sin²33/2(9.8)

Max height = 610.09(0.29663)/19.6

Max height = 180.97/19.6

Max Height = 9.23m

Hence the max height the football reaches during flight is 9.23m


Related Questions

please help thank you ​

Answers

YOUR QUERY :

which of the following statements BEST describes the difference between an atom and an ion ?

Answer:

well the correct answer is

d. An atom contains equal numbers of protons and electrons whereas an ion contains unequal numbers of protons and electrons .

Explanation:

A charged atom is known as an ion, well it can be negative as well as positive charge.

if atom has more protons than electrons then it get positively charged and known as cation

if the atom has more electrons that the number of protons then the atom get negatively charged and known as anion

Two identical plastic cups contain the same amount of water at two different temperatures, as shown to the left. Both cups are placed in a room at 25° Celsius. At the time cups were placed in the room, in which cup do the water molecules have higher average kinetic energy? ( Cup 1 © Cup 2​

Answers

Answer:

the molecules will begin to move slowly and will turn to ice

Explanation:

hope this was good or not not sure if am right but yeah

The least count of stopwatch is 0.2s.The time of 20 oscillations of a pendulum was measured to be 25s.Find the percentage error in the measurement of time​

Answers

Answer:

0.8%

Explanation:

We are given;

Number of oscillations; n = 20

Time taken; t = 25 s

Formula for period of oscillation;

T = t/n = 25/20 = 1.25 s

We are told that the least count is 0.2 s. Thus, error is; ΔT = 0.2 s

percentage error in the measurement of time is given by;

(0.2/(20 × 1.25)) × 100% = 0.8%


Define friction. Prove that tangent of angle of friction is equal to coefficient
of friction.​

Answers

Answer:

Friction is the force that opposes movement between moving objects.

The angle at which one object starts to slip on the other is directly related to the coefficient. When the two objects are horizontal there is no frictional force. So, the coefficient of static friction is equal to the tangent of the angle at which the objects slide. A similar method can be used to measure μk.

Explanation:

Answer:

brainliest plsssssss

Explanation:

The resistance that one surface or object encounters when moving over another

Optimus Prime is flying straight up at 24 m/s when he accidentally drops his mega-ray blaster and it falls 94 m to the ground below. Calculate how long it takes for his mega-ray blaster to hit the ground.

Answers

Answer:

The time it will take the mega-ray blaster to hit the ground is 2.57 s.

Explanation:

Given;

initial velocity of Optimus Prime, u = 24 m/s

height of fall of the mega-ray blaster, h = 94 m

The time of fall of the mega-ray blaster is calculated using the following kinematic equation;

[tex]h = ut + \frac{1}{2}gt^2\\\\94 = 24t + \frac{1}{2}(9.8)t^2\\\\94 = 24t + 4.9t^2\\\\4.9t^2 +24t -94 = 0\\\\Use \ formula \ method \ to \ solve \ for \ "t"\\\\a = 4.9 , b = 24, c = -94\\\\t = \frac{-b \ +/- \ \sqrt{b^2 -4ac} }{2a} \\\\t = \frac{-24 \ +/- \ \sqrt{(24)^2 -4(-94 \times4.9)} }{2(4.9)} \\\\t = \frac{-24 \ +/- \ \sqrt{2418.4} }{9.8}\\\\t = \frac{-24 \ +/- \ 49.177 }{9.8}\\\\t = \frac{-24 \ +\ 49.177 }{9.8} \ \ or \ \ t = \frac{-24 \ -\ 49.177 }{9.8} \\\\[/tex]

[tex]t = 2.57 \ s \ \ or \ \ t = -7.47 \ s[/tex]

t = 2.57 s

Therefore, the time it will take the mega-ray blaster to hit the ground is 2.57 s.

A(n) 636 kg elevator starts from rest. It moves upward for 4.5 s with a constant acceleration until it reaches its cruising speed of 2.05 m/s. The acceleration of gravity is 9.8 m/s 2 . Find the average power delivered by the elevator motor during this period. Answer in units of kW.

Answers

Answer:

The average power delivered by the elevator motor during this period is 6.686 kW.

Explanation:

Given;

mass of the elevator, m = 636 kg

initial speed of the elevator, u = 0

time of motion, t = 4.5 s

final speed of the elevator, v = 2.05 m/s

The upward force of the elevator is calculated as;

F = m(a + g)

where;

m is mass of the elevator

a is the constant acceleration of the elevator

g is acceleration due to gravity = 9.8 m/s²

[tex]a = \frac{v-u}{t} \\\\a = \frac{2.05 -0}{4.5} \\\\a = 0.456 \ m/s^2[/tex]

F = (636)(0.456 + 9.8)

F = (636)(10.256)

F = 6522.816 N

The average power delivered by the elevator is calculated as;

[tex]P_{avg} = \frac{1}{2} (Fv)\\\\P_{avg} = \frac{1}{2} (6522.816 \ \times \ 2.05)\\\\P_{avg} = 6685.89 \ W\\\\P_{avg} = 6.68589 \ kW\\\\P_{avg} = 6.686 \ k W[/tex]

Therefore, the average power delivered by the elevator motor during this period is 6.686 kW.

Help! Help!

___ are a primary way to discourage drinking and driving.
A. High prices for alcohol
B. Scare tactics
C. Laws

Answers

Answer:

Laws

Explanation:

Laws are a primary way discourage drinking and driving

A primary way to discourage drinking and driving is Law.

What is drinking and driving?

The person who takes in alcohol and then drives on the road. This is strictly prohibited.

Laws against the  'drinking and driving' will make people get scared of getting charged or sentenced to jail for some years. Lot of accidents have caused when there were no laws against the action.

Thus, Laws are a primary way to discourage drinking and driving.

Learn more about drinking and driving.

https://brainly.com/question/11317786

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If at some point in time an object has zero velocity and zero acceleration, what does that mean about its motion at the next instant

Answers

Answer:

Explanation:

Usually, when an object possesses 0 velocity, then the object is expected to be at rest. But like the popular saying, there's always an exception to every rule. There exists cases in which an object isn't at rest, but possesses 0 speed or velocity. Since acceleration is the rate of change of velocity with time, the acceleration becomes negative, instead of positive.

Again, when the acceleration becomes zero, it means that the object isn't moving or it has no speed. And thus, the body is at rest. Every moving body as an acceleration, either positive, or negative. Zero acceleration means the object is at rest, and not moving at all.

Please leave a like if it helped you

At any point in time, when

when the acceleration becomes zero, it means that the object isn't moving or it has no speed. And thus, the body is at rest.

What is acceleration?

Acceleration is defined as the change of the velocity with the time. Acceleration is a vector quantity and is defined by both the magnitude and the direction

when the acceleration becomes zero, it means that the object isn't moving or it has no speed. And thus, the body is at rest. Every moving body as an acceleration, either positive, or negative. Zero acceleration means the object is at rest, and not moving at all.

Now If an object is moving with an acceleration that causes its speed to be reduced, there will be a moment in which it reaches v = 0, but this doesn't necessarily mean that the acceleration isn't acting anymore. If the object continues its movement with the same acceleration, it's velocity will become negative.

If you throw an object in the air with a certain velocity, it will move vertically, reducing its velocity in a 9,8  rate (which is the acceleration caused by gravity). At a certain point, the object will reach its maximum height, and will start to fall. In the exact moment that it reaches the maximum height, before it starts falling, its velocity is zero, but gravity is still acting on the object (this is the reason why it starts falling instead of just being stopped at that point). Therefore, at that point, the object has zero velocity but an acceleration of 9,8 .

To know more about acceleration follow

brainly.com/question/25749514

What happens to most of the light waves that strike a clear pane of glass? O A. absorption B. diffraction O C. reflection O D. transmission​

Answers

slight reflect but most goes through because glass is transparent

Most of the light waves that strike a clear pane of glass reflects. Details about reflection can be found below.

What is reflection?

Refection in physics is the property of a propagated wave being thrown back from a surface such as a mirror.

Mirror is an example of an object that could be hit by an incumbent wave, however, most of the light waves that hit the mirror surface gets reflected back.

Therefore, most of the light waves that strike a clear pane of glass reflects.

Learn more about refection at: https://brainly.com/question/15487308

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A Nov-Dec power bill shows that a home uses 1355 kwh over a 30-day period. Find the energy used (in kJ) for the 30-day period.

Answers

Answer:

The energy used for the 30-day period is 4878000 kilojoules.

Explanation:

According to the power bill, 1355 kilowatt-hours was used over a 30-day period. A kilowatt-hour is equal to 3600 kilojoules. Then, we calculate the energy used, measured in kilojoules, is determined by simple rule of three:

[tex]E = 1355\,kWh\times \frac{3600\,kJ}{1\,kWh}[/tex]

[tex]E = 4878000\,kJ[/tex]

The energy used for the 30-day period is 4878000 kilojoules.

( I will give a brainliest )
What must be changed, temperature or heat energy, during condensation?

Answers

Answer:

The answer is temperature lol

Explanation:

:)

two cars with initial speed 2v and v, lock their brakes and skid to a stop. what is the ratio of the distance travelled

Answers

Answer:

4:1

Explanation:

Given that the initial speed of the first car, u = 2v while the initial speed of the second car, u = v. To find the distance travelled, we are going to apply one of the equations of motion. The equation chosen is

v² = u² - 2as, where

s = the distance needed

a = acceleration due to gravity

u = initial velocity which is v & 2v

v = final velocity which is 0

For the first car with initial velocity, 2v, on substituting into the equation, we have

v² = u² - 2as(1)

0 = 4v - 2as(1)

4v = 2as(1)

2v = as(1), making s(1) subject of formula we have

s(1) = 2v/a

Taking the second car, we have u = v

v² = u² - 2as(2)

0 = v - 2as(2)

v = 2as(2), making s(2) subject of formula, we have

s(2) = v/2a

Not, ratio of s1 : s2 =

2v/a : v/2a

s1/s2 = 2v/a ÷ v/2a

s1/s2 = 2v/a * 2a/v

s1/s2 = 4av/av

s1/s2 = 4/1

Therefore, the ratio of the first car to the second car is 4:1

Please leave a like if it helped you

If the angle between two forces increases, the magnitude of their resultant-
A Decreases
C. Remain unchanged
D. Decrease than decreases​

Answers

A is the answer to your question

a ball of diameter 10 cm and mass 10 grams is dropped in a container of water. the cross sectional area of the container is 100 cm2.. what is the change in the height of the water column

Answers

Answer:

h = 9.83 cm

Explanation:

Let's analyze this interesting exercise a bit, let's start by comparing the density of the ball with that of water

       

let's reduce the magnitudes to the SI system

         r = 10 cm = 0.10 m

         m = 10 g = 0.010 kg

         A = 100 cm² = 0.01 m²

the definition of density is

          ρ = m / V

the volume of a sphere

         V = [tex]\frac{4}{3} \ \pi r^{3}[/tex]

          V = [tex]\frac{4}{3}[/tex] π 0.1³

          V = 4.189 10⁻³ m³

let's calculate the density of the ball

           ρ = [tex]\frac{0.010}{4.189 \ 10^{-3} }[/tex]

           ρ = 2.387 kg / m³

the tabulated density of water is

         ρ_water = 997 kg / m³

we can see that the density of the body is less than the density of water. Consequently the body floats in the water, therefore the water level that rises corresponds to the submerged part of the body. Let's write the equilibrium equation

            B - W = 0

            B = W

             

where B is the thrust that is given by Archimedes' principle

           ρ_liquid  g V_submerged = m g

           V_submerged = m / ρ_liquid

we calculate

            V _submerged = 0.10 9.8 / 997

             V_submerged = 9.83 10⁻⁴ m³

The volume increassed of the water container

           V = A h

            h = V / A

let's calculate

            h = 9.83 10⁻⁴ / 0.01

            h = 0.0983  m

this is equal to h = 9.83 cm

A man weighs himself twice in an elevator. When the elevator is at rest, he weighs 824 N; when the elevator starts moving upward, he weighs 932 N. Most nearly how fast is the elevator accelerating, assuming constant acceleration?

a. 0.64 m/s
b. 1.1 m/s^2
c. 1.3 m/s
d. 9.8 m/s^2

Answers

Answer: c. 1.3 m/s^2

Explanation:

When he is at rest, is weight can be calculated as:

W = g*m

where:

m = mass of the man

g = gravitational acceleration = 9.8m/s^2

We know that at rest his weight is W = 824N, then we have:

824N = m*9.8m/s^2

824N/(9.8m/s^2) = m = 84.1 kg

Now, when the elevators moves up with an acceleration a, the acceleration that the man inside fells down is g + a.

Then the new weight is calculated as:

W = m*(g + a)

and we know that in this case:

W = 932N

g = 9.8m/s^2

m = 84.1 kg

Then we can find the value of a if we solve:

932N = 84.1kg*(9.8m/s^2 + a)

932N/84.1kg = 11.1 m/s^2 = 9.8m/s^2 + a

11.1 m/s^2 - 9.8m/s^2 = a = 1.3 m/s^2

The correct option is C

Question 3 (1 point)
here were 2cars racing a quarter mile. The green car had a mass of 1200kg and crossed the finish line with a velocity of 53m/s. The red car had
a mass of 1100Kg and crossed the finish line with a velocity of 55m/s.,Which car had the great momentum?

Black car
Blue car
Green car
Red car

Answers

Answer:

The green car had the greatest momentum

Explanation:

Momentum

Momentum can be defined as "mass in motion" and is calculated as the product of the mass of the object by its velocity.

Being v the magnitude of the velocity and m the mass of the object, the momentum is calculated with:

p = mv

The green car had a mass of m1=1200 kg and crossed the finish line at v1=53 m/s. Hence, its momentum was:

p1 = 1200 Kg * 53 m/s = 63600 Kg.m/s

The red car had a mass of m2=1100 kg and crossed the finish line at v2=55 m/s. Hence, its momentum was:

p2 = 1100 Kg * 55 m/s = 60500 Kg.m/s

Since p1 > p2, then the green car had the greatest momentum

4) Which of the following is NOT true about lysozyme:
A) it destroys bacteria
B) it cleanses and protects the eye
C) it is an enzyme
D) it is found in tears
E) it stimulates the rods and cones

Answers

The following that are not true are E and D
E is not true the rest is true

Which type of telescope is best used to detect distant planets?​

Answers

I believe the answer would be, refractor type telescopes because these are best used for planetary observations.

A 420 g soccer ball is kicked into the air with an initial velocity of 30 m/s. How much kinetic energy does the soccer ball have?

Answers

Answer:189000J

Explanation:KE=1/2mv^2

1/2(420g)(30m/s)^2

=189000J

how are hydrosphere, atmosphere, Biosphere, and Biosphere connected to one another

Answers

Explanation:

Such spheres are intimately connected. Many animals (biosphere), for example, migrate through to the sky, while groundwater (hydrosphere) also flows through the ground (lithosphere). The domains are actually so closely related that a shift in one globe always results in a shift in one or both of some other spheres.

Determine the absolute pressure on the bottom of a swimming pool 30.0 mm by 8.4 mm whose uniform depth is 1.9 mm .

Answers

Answer:

=101343.62N/m^2

Explanation:

absolute pressure on the bottom of a swimming pool= atmospheric pressure +( 2 ×ρ ×g)

( 2 ×ρ ×g)= guage pressure

atmospheric pressure= 101325pa

h= height= 1.9 mm = 1.9×10^-3m

ρ = density of water

= 1000kg/m^3

g= acceleration due to gravity= 9.8m/s^2

Then substitute, we have

absolute pressure on the bottom of a swimming pool= 101325+ [0.0019 ×1000 × 9.8)]

=101343.62N/m^2

Hence, the absolute pressure on the bottom of a swimming pool is =101343.62N/m^2

Select the correct answer.
What type of motion means to bounce or spring back?

Spin
Rotate
Rebound
Speed

Answers

Answer:

Rebound

Explanation:

Answer:

Rebound is your answer

Explanation:

To rebound is to bounce or

spring back after coming into

contact with another object.

Examples:

Rebound

• A basketball rebounds off the

backboard.

• A hockey puck rebounds off

the wall.

How far will a 10N force pull a car if the work done is 20J?

Answers

Since Work done= Force x distance/displacement. Therefore substituting the values in and making Distance the subject of formula we get d=W/F =20/10 = 2 meters

let's say you hypothetically ran over someone with your car, and they are now under your car in between the front wheels and the back wheels, right, and they're stuck as in can't breathe type stuck, right, do you keep driving so they can breathe or do you let them chill under your car?
just curious...​

Answers

question: is this actually hypothetical?

Explanation:

also just leave the car there go get some McDonald's or sum and come back and if they're still breathing then go ahead and move the car .

Answer:

the same thing the last guy said

A 6.5 kg rock thrown down from a 120m high cliff with initial velocity 18 m/s down. Calculate
the following ATTENTION:using the energy/work formulae only: 3.The kinetic energy of the Rock half way down ? 4.the speed of the Rock half way down?
5.The speed of the Rock as it hits the ground?​

Answers

Answer:

See the answers below.

Explanation:

In order to solve this problem we must use the principle of energy conservation. Which tells us that the energy of a body will always be the same regardless of where it is located. For this case we have two points, point A and point B. Point A is located at the top at 120 [m] and point B is in the middle of the cliff at 60 [m].

[tex]E_{A}=E_{B}[/tex]

The important thing about this problem is to identify the types of energy at each point. Let's take the reference level of potential energy at a height of zero meters. That is, at this point the potential energy is zero.

So at point A we have potential energy and since a velocity of 18 [m/s] is printed, we additionally have kinetic energy.

[tex]E_{A}=E_{pot}+E_{kin}\\E_{A}=m*g*h+\frac{1}{2}*m*v^{2}[/tex]

At Point B the rock is still moving downward, therefore we have kinetic energy and since it is 60 [m] with respect to the reference level we have potential energy.

[tex]E_{B}=m*g*h+\frac{1}{2}*m*v^{2}[/tex]

Therefore we will have the following equation:

[tex](6.5*9.81*120)+(0.5*6.5*18^{2} )=(6.5*9.81*60)+(0.5*6.5*v_{B}^{2} )\\3.25*v_{B}^{2} =4878.9\\v_{B}=\sqrt{1501.2}\\v_{B}=38.75[m/s][/tex]

The kinetic energy can be easily calculated by means of the kinetic energy equation.

[tex]KE_{B}=\frac{1}{2} *m*v_{B}^{2}\\KE_{B}=0.5*6.5*(38.75)^{2}\\KE_{B}=4878.9[J][/tex]

In order to calculate the velocity at the bottom of the cliff where the reference level of potential energy (potential energy equal to zero) is located, we must pose the same equation, with the exception that at the new point there is only kinetic energy.

[tex]E_{A}=E_{C}\\6.5*9.81*120+(0.5*9.81*18^{2} )=0.5*6.5*v_{C}^{2} \\v_{c}^{2} =\sqrt{2843.39}\\v_{c}=53.32[m/s][/tex]

A volleyball experiences 494 Ns of impulse over a time period of 7 seconds. What was the magnitude of the force that acted on the volleyball during this time period?

Answers

Answer:

70.6N

Explanation:

Given parameters:

Impulse  = 494Ns

Time  = 7s

Unknown:

Force applied = ?

Solution:

To solve this problem, we use the formula of impulse;

      Impulse = Force x time

Now insert the parameters and solve;

       494  = Force x 7

            Force  = [tex]\frac{494}{7}[/tex]  

          Force  = 70.6N

What are forces like in a collision?

Answers

Answer:

equal in magnitude and opposite in direction.

Explanation:

I don't have 1 I just knew -_('-')_-

the force of an electric field is proportional to to electric charge? True or False

Answers

Answer:True

Explanation:

Answer:

I am going to say true not too sure

A different bullet has a mass of 0.09 kg. Starting from rest, after its gun's trigger is pulled, a constant force acts on the bullet for the next 0.025 seconds until the bullet leaves the barrel of the gun with a speed of 1,346 m/s.

What force acts on this bullet?

Answers

The force acts on this bullet : 4.8456 N

Further explanation

Given

m=0.09 kg

Δt=0.025 s

vo=0(from rest)

vt=1.346 m/s

Required

Force

Solution

Impulse is a change in momentum

I=ΔP

F.Δt=m(vt-vo)

Input the value

F x 0.025 = 0.09(1.346-0)

F=4.8456 N

EX 6-1 A ball is twirled on a 0.870 - m-long string with a constant speed of 3.36 m / s . Calculate the acceleration of the ball. Be sure to specify the direction of the acceleration.

Answers

Answer:

[tex]a=12.97\ m/s^2[/tex]

Explanation:

Given that,

The length of a string, l = 0.87 m

Speed of the ball, v = 3.36 m/s

We need to find the acceleration of the ball. The acceleration acting on the ball is centripetal acceleration. It is given by :

[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{(3.36)^2}{0.87}\\\\=12.97\ m/s^2[/tex]

So, the acceleration of the ball is [tex]12.97\ m/s^2[/tex].

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