Consider a rigid 3-mass system ( with origin at the leftmost mass 1 kg) which can rotate about an axis perpendicular to the system. The mass are separated by rods of length 5m, so that the entire length is 10m. Find the x-coordinate of the center of the mass for the three-mass system with respect to the origin. Treat mass as particles. Answer in unit of m.
now consider a rotation axis perpendicular to the system and passing through the point Xo at distance 3.8 m from the leftmost mass 1kg. find the moment of inertia of the 3-mass system about the new axis. Answer in unit of kg.m^2

Answers

Answer 1

Answer:

1)    x_{cm} = 5 m ,  2)  I = 168.32 kg m²

Explanation:

1) An important concept of center of mass is

          [tex]x_{cm} = \frac{1}{M} \sum x_{i} m_{i}[/tex]

where M is the total mass of the system

Let's apply this equation to our case, suppose that all masses are equal and are worth 1 kg

         [tex]x_{cm}[/tex] = ⅓ (1 0 + 1 5 + 1 10)

         x_{cm} = 5 m

2) In this para indicates that there is an axis of rotation at the point xo = 3.8 m and they ask to calculate the moment inertia.

Let's use the parallel axes theorem

          I =    I_{cm} + M D

where    I_{cm}  is the moment of inertia with respect to the center of mass, D the distance between the two axes of rotation and M the total mass of the system

Let's look for the moment of inertia of the center of mass

         [tex]I_{cm}[/tex] = 1  0 + 1  5² + 1  10²

         I_{cm} = 125 kg m²

the total moment of inertia is

        I = 125 + 3 3.8²

        I = 168.32 kg m²

Answer 2

The moment of inertia of the 3-mass system about the new axis is 54.32 kgm/s².

We have three masses each of mass = 1kg such that they are in line with mass m at origin, m at 5m and m at 10m

(a) The center of mass:

[tex]X=\frac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3} \\ \\ X =\frac{ 1*0+1*5+1*10}{1+1+1}\\ \\ X = 5m[/tex]

Hence the center of mass of the system is at x = 5m.

(b) The moment of inertia about the axis passing through x = 3.8m

from the parallel axis theorem:

[tex]I = I_{cm} + Md^2[/tex]

where, [tex]I_{cm}[/tex] is the moment of inertial along an axis passing through the center of mass of the system, M is the total mass of the system and d is the distance of the given axis from center of mass.

M = 3kg

d = 5 - 3.8 = 1.2m

[tex]I_{cm}=1*5^2+1*0+1*5^2\\\\ I_{cm}=50 kgm/s^2[/tex]

Md² = 3×(1.2)²

Md² = 4.32 kgm/s²

I = 50 + 4.32

I = 54.32 kgm/s² is the moment of inertial about the given axis.  

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Related Questions

What is unique regarding the abdominal muscle when is compared to other muscle in the body?

(A) it is a very large muscle
(B) it does not develop easily
(C) it can move the body either from the ribcage or the pelvis.
(D) it can get injured easily if you perform a lot os repetitions.
(E) none of the above

Answers

Answer:a is the answer

Two spheres of equal mass, A and B, are projected off the edge of a 1.0 m bench.    Sphere A has a horizontal velocity of 10 m/s and sphere B has a horizontal velocity of 5 m/s.

__ 5.    If both spheres leave the edge of the table at the same instant, sphere A will land
a.    at some time after sphere B.
b.    at the same time as sphere B.
c.    at some time before sphere B.
d.    There is not enough information to decide.

__ 6.    If both spheres leave the edge of the table at the same instant, sphere A hits the floor at the spot marked X.  Sphere B will hit the floor
a.    at some point between the edge of the table and X.
b.    at some point past X.
c.    at the same distance from the table as X.
d.    there is not enough information to decide.

Answers

Answer:

c. because A will land first becuase its heavier

and D.

Explanation:

A 0.60-kg mass at the end of a spring vibrates 3.0 times per second with and amplitude of 0.13m. Determine
(a) The velocity when it passes the equilibrium point,
(b) The velocity when it is 0.10 m from equilibrium
(c) The total energy of the system, and
(d) The equation describing the motion of the mass, assuming the x was a maximum at t = 0.

Answers

Answer:

a) The velocity when it passes the equilibrium point is [tex]\pm 2.451[/tex] meters per second.

b) The velocity when it is 0.10 meters from equilibrium is [tex]\pm 1.567[/tex] meters per second.

c) The total energy of the system is 1.802 joules.

d) The equation describing the motion of the mass, assuming that initial position is a maximum is [tex]x(t) = 0.13\cdot \sin (18.850\cdot t +0.5\pi)[/tex].

Explanation:

a) If all non-conservative forces can be neglected and spring has no mass, then the mass-spring system exhibits a simple harmonic motion (SHM). The kinematic formula for the position of the system ([tex]x(t)[/tex]), measured in meters, is:

[tex]x(t) = A\cdot \sin(\omega \cdot t +\phi)[/tex] (1)

Where:

[tex]A[/tex] - Amplitude, measured in meters.

[tex]\omega[/tex] - Angular frequency, measured in radians per second.

[tex]t[/tex] - Time, measured in seconds.

[tex]\phi[/tex] - Phase, measured in radians.

The kinematic equation for the velocity formula of the system ([tex]v(t)[/tex]), measured in meters per second, is derived from (1) by deriving it in time:

[tex]v(t) = \omega\cdot A\cdot \cos (\omega\cdot t+\phi)[/tex] (2)

The velocity when it passes the equilibrium point occurs when the cosine function is equal to 1 or -1. Then, that velocity is determined by following formula:

[tex]v = \pm \omega\cdot A[/tex] (3)

The angular frequency is calculated by this expression:

[tex]\omega = 2\pi\cdot f[/tex] (4)

Where [tex]f[/tex] is the frequency, measured in hertz.

If we know that [tex]f = 3\,hz[/tex] and [tex]A = 0.13\,m[/tex], then the velocity when it passes the equilibrium point, which is the maximum and minimum velocities of the mass:

[tex]\omega = 2\pi\cdot (3\,hz)[/tex]

[tex]\omega \approx 18.850\,\frac{rad}{s}[/tex]

[tex]v = \pm \left(18.850\,\frac{rad}{s} \right)\cdot (0.13\,m)[/tex]

[tex]v = \pm 2.451\,\frac{m}{s}[/tex]

The velocity when it passes the equilibrium point is [tex]\pm 2.451[/tex] meters per second.

b) First, we need to determine the spring constant of the system ([tex]k[/tex]), measured in newtons per meter, in terms of the angular frequency ([tex]\omega[/tex]), measured in radians per second, and mass ([tex]m[/tex]), measured in kilograms. That is:

[tex]k = \omega^{2}\cdot m[/tex] (5)

If we know that [tex]\omega \approx 18.850\,\frac{rad}{s}[/tex] and [tex]m = 0.60\,kg[/tex], then the spring constant is:

[tex]k = \left(18.850\,\frac{rad}{s} \right)^{2}\cdot (0.60\,kg)[/tex]

[tex]k = 213.194\,\frac{N}{m}[/tex]

Lastly, we determine the velocity when the mass is 0.10 meters from equilibrium by the Principle of Energy Conservation:

[tex]U_{k} + K = K_{max}[/tex] (6)

[tex]\frac{1}{2}\cdot k\cdot x^{2} + \frac{1}{2}\cdot m\cdot v^{2} = \frac{1}{2}\cdot m\cdot v_{max}^{2}[/tex] (7)

Where:

[tex]U_{k}[/tex] - Current elastic potential energy, measured in joules.

[tex]K[/tex] - Current translational kinetic energy, measured in joules.

[tex]K_{max}[/tex] - Maximum translational kinetic energy, measured in joules.

[tex]v[/tex] - Current velocity of the system, measured in meters per second.

[tex]m[/tex] - Mass, measured in kilograms.

[tex]v_{max}[/tex] - Maximum velocity of the system, measured in meters per second.

If we know that [tex]k = 213.194\,\frac{N}{m}[/tex], [tex]x = 0.10\,m[/tex], [tex]m = 0.60\,kg[/tex] and [tex]v_{max} = \pm 2.451\,\frac{m}{s}[/tex], then the velocity of the mass-spring system is:

[tex]\frac{k}{m} \cdot x^{2} + v^{2} = v_{max}^{2}[/tex]

[tex]v^{2} = v_{max}^{2}-\frac{k}{m}\cdot x^{2}[/tex]

[tex]v = \sqrt{v_{max}^{2}-\frac{k\cdot x^{2}}{m} }[/tex] (8)

[tex]v = \sqrt{\left(\pm 2.451\,\frac{m}{s} \right)^{2}-\frac{\left(213.194\,\frac{N}{m} \right)\cdot (0.10\,m)^{2}}{0.60\,kg} }[/tex]

[tex]v \approx \pm 1.567\,\frac{m}{s}[/tex]

The velocity when it is 0.10 meters from equilibrium is [tex]\pm 1.567[/tex] meters per second.

c) The total energy of the system ([tex]E[/tex]), measured in joules, can be determined by the following expression derived from the Principle of Energy Conservation:

[tex]E = \frac{1}{2}\cdot m\cdot v_{max}^{2}[/tex] (9)

If we know that [tex]m = 0.60\,kg[/tex] and [tex]v_{max} = \pm 2.451\,\frac{m}{s}[/tex], then the total energy of the system is:

[tex]E = \frac{1}{2}\cdot (0.60\,kg)\cdot \left(\pm 2.451\,\frac{m}{s}\right)^{2}[/tex]

[tex]E = 1.802\,J[/tex]

The total energy of the system is 1.802 joules.

d) Given that initial position of the mass-spring system is a maximum, then we conclude that the equation of motion has the following parameters: ([tex]A = 0.13\,m[/tex], [tex]\omega \approx 18.850\,\frac{rad}{s}[/tex] and [tex]\phi = 0.5\pi\,rad[/tex])

From (1) we obtain the resulting formula:

[tex]x(t) = 0.13\cdot \sin (18.850\cdot t +0.5\pi)[/tex] (10)

The equation describing the motion of the mass, assuming that initial position is a maximum is [tex]x(t) = 0.13\cdot \sin (18.850\cdot t +0.5\pi)[/tex].

Choose all correct sentences Group of answer choices The power is maximum when the value of the impedance is greater than the value of the resistance. Resonance occurs when omega squared space equals 1 divided by space L C At resonance, the power is maximum and the impedance is minimum. At resonance, R squared space equals space (X subscript L minus X subscript c )squared The impedance Z is always larger than the resistance R.

Answers

Answer:

True  b and c

Explanation:

In an RLC circuit the impedance is

         [tex]Z = \sqrt{[R^{2} + ( (wL)^{2} + (\frac{1}{wC})^{2} ] }[/tex]

examine the different phrases..

a) False. The maximum impedance is the value of the resistance  

b) True. Resonance occurs when  

              (wL)² + (1 / wC)² = 0

               w² = 1 / LC

c) True. In resonance the impedance is the resistive part and the power is maximum  

d) False. In resonance the inductive and capacitive part cancel each other out  

e) False. The impedance is always greater outside of resonance, but at the resonance point they are equal

An object whose specific gravity is 0.850 is placed in water. What fraction of the object is below the surface of the water?

Answers

Answer:

The fraction of the object that is below the surface of the water is ¹⁷/₂₀

Explanation:

Given;

specific gravity of the object, γ = 0.850

Specific gravity is given as;

[tex]specific \ gravity = \frac{density \ of the \ object}{density \ of \ water}\\\\0.85= \frac{density \ of the \ object}{1000 \ kg/m^3} \\\\density \ of the \ object = 850 \ kg/m^3[/tex]

Fraction of the object's weight below the surface of water is calculated as;

[tex]= \frac{850}{1000} \ \times\ 100\%\\\\= 85 \% \\\\= \frac{17}{20}[/tex]

Therefore, the fraction of the object that is below the surface of the water is ¹⁷/₂₀

Based on its location on the periodic table, which metal is likely to be less reactive than both strontium and sodium?

magnesium (Mg)
barium (Ba)
cesium (Cs)
rubidium (Rb)

Answers

Answer:

Magnesium is the correct answer

Explanation:

It is magnesium because as we move down the periodic table group, atomic sizes increase which is as a result of lesser forces of attraction between nucleus and valence of an atom which makes the atom to be prone to leave as electrons so easily, elements become more reactive.

But as we move along the period , atomic sizes decrease because there is a more force of attraction between nucleus of an atom and it valence electrons making it less reactive just as the case in magnesium. Other elements are more reactive than it across the group.

Answer:

Magnesium

Explanation: Correct on edge!

Hope this Helps! :)

1. Derive the equation of the trajectory of a projectile.
(3mks)
2. A ball is thrown with an initial speed uof 30 m/s at an angle & above thehorizontal, where
sin 0 = 4/5 and cos 0 = 3/5.
(5mks)
(a) decompose the vector u into itsx and y components.
(b) When t= 2 s, find the position of the ball andthe magnitude and direction of its
velocityu.
(c) Determine
the value
of the highest point of the ball's trajectory.
(d) calculate how much time has elapsed forthe ball to reach the highest point.
(e) Calculate the values of the total time of theball's flight T and the horizontal range R.
ASAN
3. In the model of the hydrogen atom proposed by Niels Bohr an electron circulatesa
stationary proton in a circle of radius 7' = 5.28 x 10-11 m with a speedı= 2.18 x 106m's
(a) Find the magnitude of the electron sradial acceleration in this model.
(1mk)
(b) Determine the period of the motion,
(Imk)​

Answers

We should be lovers instead

If forces acting on an object are unbalanced, the object could experience a change in ________.

mass, speed, or direction
negative acceleration or mass
direction, mass, or both
speed, direction, or both

Answers

Speed is the answer

D) Speed, direction, or both

Mass doesn’t just CHANGE like that.

how is red shift evidence of the big bang
it implies our universe is expanding
it implies our universe is collapsing
it implies our universe is standing still

Answers

Answer:

it implies our universe is expanding

When 26400j of energy is supplied to a 2.0kg bloom of aluminum it temperature rise from 20oc to 35oc.The block is well so there is no energy lost to sorround determine the specific heat capacity of aluminum

Answers

Answer:

880J/kelvin

Explanation:

Q =MC ×change in t

c =C/m

C=Q/change in t

c= Q/ m× change in t

c = 26400 / 2.0 × 15

c = 880 J/kelvin

What power does a toaster with 15 A of current and 20 Ωof resistance consume?

Answers

Answer:

4500W

Explanation:

[tex]P = {I}^{2} R[/tex]

where P = Power consumed , I = Current & R = Resistance.

In the question it's given that

I = 15A ; R = 20Ω

So ,

[tex]P = {15}^{2}\times 20 = 225 \times 20 = 4500W[/tex]

4500w is the answer to this question

What is the volume of a brick that is 30 cm long, 8 cm wide, and 10 cm tall?

Answers

Anwer: volume = 30×8×10 = 2400 centimeters to the power of 3

Number 1a and b and number 2(everything)

Answers

Answer:

Explanation:

The density of a substance is the ratio of its mass to its volume. Its unit of measurement is kg[tex]m^{-3}[/tex].

i.e density, ρ = [tex]\frac{mass}{volume}[/tex]

1a. To determine the density of the acetic acid, Rachael needs to know the mass and volume of the acid.

i. Measure the mass of the given beaker using the mass balance.

ii. Transfer the acetic acid into the beaker, and measure the new mass using the mass balance.

iii. Subtract the mass of the beaker from the new mass to determine the mass of the acetic acid.

iv. Measure the volume of the acid on the scale of the beaker.

v. Divide the value of the mass by its volume to determine its density of the acetic acid.

b. Given that the density is 1.05 g/[tex]cm^{3}[/tex], and volume is 200 [tex]cm^{3}[/tex].

Then,

density = [tex]\frac{mass}{volume}[/tex]

1.05 = [tex]\frac{mass}{200}[/tex]

mass = 1.05 x 200

         = 210 g

mass = 210 g

2. Length of titanium = 0.40 m

   Area of titanium = 0.05 [tex]m^{2}[/tex]

mass = 90.0 kg

density = [tex]\frac{mass}{volume}[/tex]

But,

volume = area x length

            = 0.05 x 0.4

           = 0.02 [tex]m^{3}[/tex]

density of titanium = [tex]\frac{90}{0.02}[/tex]

                = 4500 kg[tex]m^{-3}[/tex]

If a neutral atom has 25 protons in its nucleus. What is the number of surrounding electrons? Explain your answer.

Answers

Answer:

25 electrons.

Explanation:

In a neutral atom, the number of protons is equal to the number of electrons, therefore there are 25 protons and 25 electrons.

Final Answer: 25 electrons

Explanation/Reasoning:

Hey there!

The number of protons in the nucleus of a neutral atom would have 25 protons. This is because it is equal to the atomic number.

The number of protons is equal to the number of electrons. So for our answer, the number of atoms in a neutral atom will be 25 electrons because the neutral atom had 25 protons.

~I hope I helped you :)~

2. Using Graph 2, calculate the net force experienced by the particle between 4 and 6 seconds. The
particle has a mass of 0.25 kg.

A +5.0 N
B. +0.5 N
C. -0.5 N
D. -2.0 N

Answers

Using Newtons Second Law:

F = m×a

F = (0.25 kg)(-2 m/s²)

F = -0.5 N

The correct option is C

Look at this model of an atom. Using a periodic table, which element does it represent?

Answers

Answer:

Nitrogen

Explanation:

What is the change in potential energy in moving a 10kg box from the floor to a table 1 m high?

Answers

Explanation:

potential energy formula is 1/2 mv2(this 2 is square).

m means mass and v means velocity.

now, you can calculate

The change in potential energy in moving a 10kg box from the floor to a table 1 m high is 98 Joules.

To find the potential energy, the given values are,

Mass of the box = 10Kg

Height h = 1 m

What is Potential energy?

The potential energy can be defined as the energy that is stored and that can be determined through various parts in a particular system.

Also, the energy will gets stored when the object is not moving.

For example: Spring. Even when the spring is not stretched or contracted it stores energy.

The formula for Potential energy PE= mgh joules.

m is the Mass,

g is the acceleration due to gravity = 9.8 m/s²,

h is the height.

Substituting all the given values,

Potential Energy= 10 (9.8)(1)

PE= 98 J

Thus the potential energy of the box= 98 J.

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what type of plate boundary decreases the amount of the Earth's crust?

Answers

Answer:

Convergent.

Explanation:

Just as oceanic crust is formed at mid-ocean ridges, it is destroyed in subduction zones. Subduction is the important geologic process in which a tectonic plate made of dense lithospheric material melts or falls below a plate made of less-dense lithosphere at a convergent plate boundary.

Calculate the change in entropy of 0.020 kg of ice when it melts at 0.0°C. The heat of fusion of ice is 3.36 x 10'J/kg.

Answers

Answer:

S = 2461.53 [kJ]

Explanation:

The change in entropy in a process such as melting can be calculated by means of the following expression.

[tex]S=\frac{H*m}{T}[/tex]

where:

S = entropy [kJ]

H = fusion heat = 3.36*10¹ [J/kg]

m = mass = 0.02 [kg]

T = temperature in kelvin = 273 [K]

[tex]S = \frac{0.02*3.36*10^{1} }{(273+0)}\\S = 2461.53 [kJ][/tex]

True/False: The core, mantle, and crust explanation for the Earth's layers is outdated and now we use the 5 layer explanation. *

Answers

Answer:

False

Explanation:

We still use the old way. It's easier to understand the old way, and its NOT outdated.


The weight of the bricks is 5000N. Calculate the mass of the bricks.
(1 kg weighs 10N)

Answers

Answer:

500kg

Explanation:

....................

Answer:

500Kg

Explanation:

1 kg = 10N

? =5000N

5000N÷10N * 1Kg = 500Kg

An object is moving diagonally (down and to the left). You want it to stop moving. In what direction (or
directions) should you exert a force to get the object to stop?
a. Force direction(s):
b. Explain your answer:

Answers

A. Up and to the right
B. Put it in the opposite direction so it won’t go left

In specific heat capacity experiment, the ammeter in circuit is connected in

Answers

Answer:

In series

Explanation:

In such experiment, the ammeter is connected in series with the heater, in order to measure the circulating current.

By the way, ammeters are always connected in series in circuits to measure the running current in it.

In the Sun, fusion reactions create helium nuclei. To form each helium
nucleus, four hydrogen nuclei fuse. The four hydrogen nuclei have a greater
total mass than the newly formed helium nucleus. Which statement explains
this difference in mass?
O A. Some of the mass burned and was transformed into gases.
O B. Mass was destroyed and disappeared.
O c. Some of the mass of the four hydrogen nuclei was converted into
energy
D. Some of the mass was transformed into protons.

Answers

Answer:

C. Some of the mass of the four hydrogen nuclei was converted into

energy

Explanation:

a p e x , just took the quiz

Some of the mass of the four hydrogen nuclei was converted into energy.

When four hydrogen nuclei fuse to form one helium nuclei, mass defect, some mass is converted into energy, that is the reason of energy of the sun.

What is fusion?

"When two nuclei form a big nuclei, the phenomenon is known as fusion."

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A convex mirror has a focal length of -12 cm. A lightbulb with
a diameter of 6.0 cm is placed 60.0 cm in front of the mirror.
Locate the image of the lightbulb. What is its diameter?​

Answers

Answer:

PLEASE MARK AS BRAINLIEST!!

Explanation:

ANSWER IS IN THE IMG BELOW

I NEED BY JAN 4!!!!!!
Research what is known about Earth’s magnetic field. Begin by looking for images and credible sites on the Internet or refer to some books in a library. Answer the following questions:

What is the approximate size of Earth’s magnetic field?
Where are Earth’s magnetic poles?
Where is the magnet that causes Earth’s magnetic field located? What is this magnet made of?
Does Earth’s magnetic field move?

Answers

The earth has a magnetic field. It is much like a bar magnet. Imagine a gigantic bar magnet inside the Earth. But there is no giant magnet inside it.

To have a pretty good idea what earth's magnetic field is shaped like we imagine a bar magnet inside the earth.

The magnetic field is made by the motion of molten iron in earth's outer core.  The swirling motion of molten iron changes all the time. Therefore, the magnetic fields will also get change. Then, the magnet poles also move.

The North pole and the south pole are two geographic poles of earth.  These poles are the places on the earth's surface that earth's imaginary spin axis passes through.

There are two magnetic poles of the earth: North magnetic pole and South magnetic pole.

Earth's magnetic field is tilted a little bit. If we imagine that earth's magnetic field is made by a giant bar magnet. Then, the bar magnet would make an with earth's spin axis.

The geographic poles and the magnetic poles are not in the same place.

If we are standing at one magnetic poles then the magnetic field lines would be straight up and down.

Earth's magnetic field is a complex and dynamic phenomenon that is generated by the motion of molten iron in its outer core. The magnetic field extends far beyond the planet and is responsible for protecting Earth from harmful solar radiation and cosmic rays.

What is the approximate size of Earth's magnetic field?

Earth's magnetic field is roughly dipolar in shape, meaning it has two main magnetic poles - north and south - and the field lines emerge from the north and re-enter at the south pole. The magnetic field has a strength of about 25-65 microteslas (μT) at the Earth's surface, and it extends for several tens of thousands of kilometers into space.

2. Where are Earth's magnetic poles?

Earth's magnetic poles are not fixed and are constantly moving due to the complex and dynamic nature of the planet's magnetic field. Currently, the north magnetic pole is located in the Arctic Ocean, close to Canada's Ellesmere Island, and the south magnetic pole is located in the Antarctic Ocean, near the coast of Antarctica.

3. Where is the magnet that causes Earth's magnetic field located? What is this magnet made of?

The magnet that causes Earth's magnetic field is not a physical magnet but rather a result of the motion of molten iron in the Earth's outer core. The outer core is a layer of liquid iron and nickel that surrounds the solid inner core. The motion of this molten iron generates electrical currents, which in turn create a magnetic field.

4. Does Earth's magnetic field move?

Yes, Earth's magnetic field is not static and is constantly changing due to the complex nature of the planet's interior. The magnetic poles are constantly moving and the strength of the magnetic field can vary over time. The magnetic field can also be influenced by external factors such as solar storms and changes in the solar wind. Scientists continue to study Earth's magnetic field to better understand its behavior and how it affects the planet.

Therefore, The magnetic field of the Earth is a complex and dynamic phenomenon caused by the movement of molten iron in its outer core. The magnetic field extends far beyond the planet and is in charge of shielding the planet from harmful solar radiation and cosmic rays.

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In the Fresnel circular aperture setup, the distances from the aperture to the light source and the reception screen are 1.5 m and 0.6 m, respectively. The wavelength is 630 nm. Suppose that the radius of the aperture can be increased from 0.5 mm, determine: (a) The first two radii when the center intensity at the reception screen is maximum. (b) The first two radii when the center intensity is minimum.

Answers

Explanation:

The width of the central maximum is given by

W = 2 λ L / a

where W is the width of the central maximum

λ is the wavelength of the light used.

L is the distance between the aperture and screen

a is the width of the slit or aperture

So we can see that if any one quantity is varied by keeping others constant in the above formula , there would be a change in width of central maximum.

Can cause a stationary object to start moving or moving object to change its speed or direction or both

Answers

Answer:

Force

Explanation:

Only a force can cause a stationary object to move or a moving object to change its speed or direction.

types of magnetic resonance image​

Answers

Answer: ur mom

Explanation:

Using a light microscope, a student identified the following characteristics of four organisms found in a sample of pond water. Based on the observations of the student,
which organisms most likely belong to the taxonomic group for bacteria?
Pond-Water Organisms
Organism 1 Single-celled, nucleus, large vacuole
Organism 2 Single-celled, no nucleus, cell wall
Organism 3 Single-celled, no nucleus
Organism 4 Single-celled, nucleus
Organism 1 and 4
Organism 1 and 2
Organism 3 and 4
Organism 2 and 3

Answers

Answer:

Organisms 2 and 3

Explanation:

Other Questions
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