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The ratio i100hz/i1000hz is 1000, meaning that the least intense perceptible sound at 100 Hz is 1000 times more intense than the least intense perceptible sound at 1000 Hz.

Intense is an adjective describing something that is extreme or powerful, either in terms of strength, emotion, or concentration. It can refer to a feeling, such as intense emotion, or a physical sensation, such as intense pain.

The least intense perceptible sound at 100 Hz is about one millionth of a Pascal, while the least intense perceptible sound at 1000 Hz is about one billionth of a Pascal. Therefore, the ratio i100hz/i1000hz is 1000, meaning that the least intense perceptible sound at 100 Hz is 1000 times more intense than the least intense perceptible sound at 1000 Hz.

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After a brief period of falling, the upward air friction on the cargo would equal the downward gravity pull if a parachute opened.

Air resistance reaches its maximum magnitude at the falling object's terminal velocity. Due to the fact that the two forces are acting in opposing directions, there is no net force acting on the item, and its speed has stabilised.

In addition, gravity is pulling the thing downward as it falls. Gravity is an imbalanced force at the beginning of a descent. The result is an increase in speed or acceleration for the object. Aerodynamic drag or air resistance is encountered as it accelerates.

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In this case, the acceleration amplitude would be (0.23 ips x 1170 cpm)2 = 546.7 g.

Acceleration is the rate of change of velocity over time. It is a vector quantity, meaning that it has both magnitude and direction. The magnitude of acceleration is the rate at which the velocity changes, and the direction of acceleration is the same as the direction of the velocity.

Displacement amplitude:
The formula for displacement amplitude is displacement amplitude = velocity amplitude / (2πf).
In this case, the displacement amplitude would be 0.23 ips / (2π x 1170 cpm) = 0.00196 inches pk-pk. Converting to mils pk-pk, this would be 1.96 mils pk-pk.
Acceleration amplitude:

The formula for acceleration amplitude is acceleration amplitude = (velocity amplitude x f)2.
In this case, the acceleration amplitude would be (0.23 ips x 1170 cpm)2 = 546.7 g.

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The mass of the object is: 100 kg

It is the physical magnitude that expresses the effort necessary to move the mass of one kilogram with an acceleration of one meter per second squared, this is expressed in units of the international system in Newton.

To solve this exercise, the formula and procedure to be applied is:

F = m * a

Where:

Information about the problem:

Applying the force formula and isolating the mass, we get:

F = m * a

m= F/a

m= 5.0x 10^2 n /5.0 m/s²

m= 100 kg

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The magnitude of electric force is [tex]2.27 * 10^{6} N[/tex] (downwards)

We know that electric force between two charges is given by equation:

                                         F = [tex]\frac{k.q_{1} .q_{2} }{r^{2} }[/tex]

Where,

k = constant = [tex]9 * 10^{9} Nm^{2} /C^{2}[/tex]

q1 = first charge =35 C

q2 = second charge = -35 C

r = distance between them = 2.2 km = 2200m

Putting these values in above equation we get:

F = -[tex]2.27 * 10^{6} N[/tex] , where negative sign denotes the direction.

So, the magnitude of electric force is [tex]2.27 * 10^{6} N[/tex] (downwards)

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The cost of making toast 16 times per month at a rate of 9.0 cents/kWh is approximately $0.1 per month.

How does the energy consumption of a device change with the length of usage?

The strength consumption of a tool commonly will increase with the duration of utilization. This is due to the fact maximum devices devour electricity continuously at the same time as in use, no matter how long they're used for. Some gadgets, along with appliances with standby or sleep modes, may devour less strength while now not in use, but will eat extra strength the longer they're used. For example, a fridge will consume extra power over a month than it will over an afternoon, and a pc will devour more energy over a 12 months than it's going to over a month.

A few gadgets, consisting of incandescent light bulbs, will eat extra energy and put on out faster the greater they may be used.

We convert from Watt to kilowatt

650/1000 = 0.65KW

We convert from minutes to hour:

6/60= 0.1 hr

Convert cents to dollars

9/100 = $0.09

Energy cost in KWh= 0.65 × 0.1 × 0.09 ×16= $ 0.1 per month

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0.034 second is the main time period of the motion for a machine which is operating at a speed of 1780 cpm.

Time period of an object is the time required for it to complete its one cycle or oscillation. Angular frequency is angular displacement of any object of the waves per unit time. The formula for time is, T = 1/f

where T is time-period and f is frequency.

Operating speed of the machine = 1780 cpm (cycle per minute)

Cycle in one minute = 1780

Cycle in 1 second = 1780/60 = 29.67 cycles

Time required in one cylcle, T = 1/29.67 = 0.034 second

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Celestial navigation is the best method of naming or locating stars, if we have to give someone the location of a star.

With the help of "sights" or time angular measurements taken typically between a celestial body (e.g. the Sun, a planet, the moon or a star) and the visible horizon, Celestial navigation locate a star or any celestial body. However it can also take advantage of measurements between celestial bodies without taking the Earth horizon as reference, such as when the Moon is used in the practice, then it is called "lunars" or lunar distance method, which is used for determining precise time when time is unknown.

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Option E -  it remains the same , if a simple pendulum oscillates with small amplitude and its length is doubled .

The greatest displacement or distance that a point on a wave or vibrating body may travel in relation to its equilibrium position

A wave's amplitude is the difference between its starting position and its maximum displacement. Frequency is the amount of waves which pass past the certain place each second. Period is the length of time it takes for a wave cycle to finish.

    Given,length of a simple pendulum  is doubled .

To find, frequency of motion.

we have Time period T before doubling the length,

T = 2π[tex]\sqrt{\frac{L}{g} }[/tex]   L- length,g-acceleration due to gravity

T/2π = [tex]\sqrt{\frac{L}{g} }[/tex]  

g = L(2π/T[tex])^{2}[/tex]   → 1

when length is doubled,Time period [tex]T^{'}[/tex]

[tex]T^{'}[/tex] = 2π [tex]\sqrt{\frac{2L}{g} }[/tex]

( [tex]T^{'}[/tex] /2π[tex])^{2}[/tex] = [tex]\frac{2L}{g}[/tex]

g=2L( 2π/T[tex])^{2}[/tex] → 2

from equation 1 and 2

L( 2π/T[tex])^{2}[/tex] = 2L( 2π/T[tex])^{2}[/tex]

2π/T=[tex]\sqrt{2}[/tex](2π/T)

1/T  =[tex]\sqrt{2}[/tex](1/T)

we know,frequency γ = 1/T

γ  =[tex]\sqrt{2}[/tex]  γ '

γ ' =[tex]\frac{1}{\sqrt{2} }[/tex]  γ

Therefore option E is correct.

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The volume of object will be equal to the volume of water displaced so the object's volume is also 17.04 dm⁻³.

In water, the object appears lighter than in air.

That is,

936 - 769 = 167N.

Water provided the167N buoyant force.

The buoyant force on an object in water is equal to the weight of water displaced by the object. The buoyant force acting on the metal object in this case is 167N. The object must have displaced the same weight of water.

Given g = 9.8m/s²

Water displacement mass:

Mass = weight /g

         = 167/9.8

.         = 17.04 kg

Water displacement volume:

At room temperature, the density of water is 1.000 kg.dm⁻³. Each kilogram of water has a volume of 1 dm³ (one cubic decimeter), which is equal to 1 L. (one liter).

V = Mass / Density

= m/ρ

= 17.04/1.000 kg.dm⁻³

= 17.04dm⁻³

The object is completely submerged. As a result, the object's volume will remain constant. The object is completely submerged. As a result, the object's volume will be equal to the volume of water displaced. The object's volume is also 17.04 dm⁻³.

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The distance between the two parallel plates can be found using the equation E = V/d where E is the electric field, V is the potential difference and d is the distance between the plates. Thus, d = V/E = 125V / 4.25 x 103N/C = 29.41cm

The relationship between electric field, potential difference and distance in parallel plates is inversely proportional. As the potential difference increases, the electric field between the plates increases and the distance between the plates decreases. And as the distance between the plates increases, the electric field between the plates decreases and the potential difference applied to the plates decreases.

It can be mathematically represented by the formula E = V / d, where E is the electric field, V is the potential difference, and d is the distance between the plates.

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The distance between the two parallel plates can be found using the equation E = V/d  , 29.41cm far apart are the plates .

                             E = V/d

where E is the electric field,

V is the potential difference and

d is the distance between the plates.

                          Thus, d = V/E

                          = 125V / 4.25 x 103N/C

                                    = 29.41cm

The relationship between electric field, potential difference and distance in parallel plates is inversely proportional. As the potential difference increases, the electric field between the plates increases and the distance between the plates decreases. And as the distance between the plates increases, the electric field between the plates decreases and the potential difference applied to the plates decreases.

It can be mathematically represented by the formula E = V / d, where E is the electric field, V is the potential difference, and d is the distance between the plates.

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The building block of all elements and the smallest component into which an element can be divided d. atom

Quarks, the universe's tiniest particles, are significantly smaller and have far greater energy levels than the protons and neutrons in which they are found.

An atom is the smallest unit of an element that retains all of its characteristics.

However, atoms include several subatomic particles, the most significant of which are protons, neutrons, and electrons.

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The resultant force is approximately 11.75 N

If five equal forces of 10 N are applied at a point, and the angle between them is equal, then the forces can be considered as forming a regular pentagon.

The angle between any two adjacent forces in a regular pentagon:

180 - 360 degrees

            n

where,

n = the number of sides.

In this case, the angle is

180 - 360

           5

θ = 108 degrees.

To calculate the resultant force, we can use vector addition. Since the forces are equal and the angle between them is 108 degrees, we can use the law of cosines to find the magnitude of the resultant force. The law of cosines states that the square of the magnitude of the resultant force (R) is equal to the sum of the squares of the individual forces (F) plus twice the product of the individual forces and the cosine of the angle between them (θ).

R² = F² + F² + 2 * (F) *(F)* cos(108)

R² = 10² + 10² + 2(10)(10)cos(108)

R² = 100 + 100 + 200 * (cos(108))

R² = 100 + 100 + 200 * (-0.309016994)

R = ([tex]\sqrt({100 +100 - 62)}[/tex]

R = √138

R = 11.75 N

The magnitude of the resultant force is approximately 11.75 N, which is the force that would be required to replace all five forces.

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here is ur answer

MARK BRAIN PLease

The average velocity of the car is 40m/s

The average velocity of an object can be determined by dividing the change in position by the change in time.

For this situation, the vehicle begins from rest (initial velocity of 0 m/s) and arrives at a final velocity of 80 m/s.

We can use the equation:

Average velocity = (final velocity + initial velocity) / 2

Average velocity = (80 m/s + 0 m/s) / 2

Average velocity = 40 m/s

This is the average velocity of the vehicle during the entire time interval. Remember that this isn't equivalent to the instantaneous velocity at one point in time, which can be not quite the same as the average velocity.

It's important to take note of that on the off chance that the vehicle's speed increase isn't constant, the average velocity won't rise to the final velocity in addition to the initial velocity isolated by two.

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The velocity of the sailor relative to the aircraft carrier is - 7 m/s.

The velocity of the sailor relative to the aircraft carrier is calculated by applying the principle of relative velocity as shown below.

Vs/c = Vs - Vc

where;

The velocity of the sailor relative to the aircraft carrier is calculated as;

Vs/c = 36 m/s  -  43 m/s

Vs/c = -7 m/s

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When this problem is solved, we will arrive at the value 72741 to 4 meters per second.

An object's total, directionless motion is measured in terms of distance. Distance may also be referred to as the amount of ground covered by an element, depending on the starting or finishing point.

By calculating its distance, we can determine an object's actual size. One can measure the space that an object takes up above us. Its true size can be determined after we know how far away it is. As you get further away, something gets smaller.

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The minimum thickness of a soap bubble film (air-soap-air) with refractive index 1.38 that results in a constructive interference in the reflected light if this film is illuminated by a beam of light of wavelength 610 nm is 150

nm.

The refractive index of an optical medium is described as a dimensionless number that gives the indication of the light bending ability of that medium.

Condition for constructive interference is given as ,

2μt = (2n + 1) λ/2

t =  (2n + 1) x 900 / 4x 1.5

where n = 0(for minimum thickness)

Therefore t= 150nm

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There is not enough information to determine which object will reach the bottom of the ramp first. So option 1 is correct.

Without knowing the mass, radius, and coefficient of friction of the objects and the angle of the ramp, we can't determine which object will have the greater acceleration and thus reach the bottom of the ramp first.

To determine which object will reach the bottom of the ramp first, we need to know the acceleration of each object. The acceleration of an object is determined by the net force acting on it.

Which in turn is determined by the gravitational force acting on the object and the frictional force acting on it.

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The density of silicon is [tex]2.33 * 10^{-9} kg.m^{3}[/tex]

Given density of silicon  is 2.33 gram centimeter cube.

We know that:

                            100 cm = 1 m

                            1cm = 1/100m = [tex]10^{-2} m[/tex]

                            [tex]1 cm^{3} = 10^{-6} m^{3}[/tex]

Also,

        1000 gram = 1 kg

        1 gram = 1/1000 kg = [tex]10^{-3} kg[/tex]

Now, to convert gram centimeter cube into kilogram meter cube we should multiply by these values.

So, By putting these values we get:

Density = 2.33 * [tex]10^{-3} kg * 10^{-6} m^{3} = 2.33 * 10^{-9}kg. m^{3}[/tex]

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The amount of the potential energy that was converted into thermal energy  is determined as 440,000 J.

The amount of the potential energy that was converted into thermal energy  is calculated by applying the principle of conservation of energy as follows;

P.E - K.E = Eth

where;

( 2,000 kg x 9.8 m/s² x 150 m ) - ¹/₂ (2,000 kg )( 50 m/s )² = Eth

2,940,000 J - 2,500,000 J = Eth

440,000 J = Eth

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At the height 2650 km, the value of acceleration due to gravity is 50% of its value at the surface.

The new value of gravity at a height h is given as g' = g R²/(R+h)²

As visible from the formula, increasing h results in decreasing gravity.

So, just put g′ = g/2 i.e. 50% less than g where g is gravity at surface. So, we get,

g/2 = g R²/(R+h)²

1/2 = R²/(R+h)²

2/1 = (R+h)²/R²

√2 = (R+h)/R = 1 + h/R

h/R = √2 - 1 = 0.414

h = 0.414 R

As we know radius of the earth = 6400 km, putting it in the above equation,

h = 0.414 R = 0.414(6400) = 2649.6 km

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If the work required to speed a car up from 10km/h to 20km/h is 5.0 x 10^3 J, the work required to increase the cars speed from 20km/h to 30km/h is: 8.33 × 10³J.

Using this formula to determine the   work required to increase the cars speed from 20km/h to 30km/h

[tex]Wii = Wi (V^2_2- V^2_1) /v^2_2 - v^2_1[/tex]

Let plug in the formula

Work required = (5 × 10³) (30² -20²) / (20² -10²)

Work required = (5 × 10³)  ( 900 - 400) /(400  - 100)

Work required = (5 × 10³) ( 500) / 300

Work required = 8.33 × 10³J

Therefore the Work required is 8.33 × 10³J.

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The force required to hold the ping pong ball completely under the water is 36,189.98 dyne.

Diameter of ball = 4.18 cm

The radius of the ball = 2.09 cm

The volume of the ball can be calculated as   V=    [tex]\frac{4}{3}[/tex]π r³                      

Therefore, the volume of the ball = 38.26 cm³

The net force required to completely submerge a ball under water = (Buoyant force) - (the weight of the ball)

If ρ₁ is used for the density of water. Then, the value of ρ₁ is 1 g cm⁻³.

Buoyant force = ρ₁gV

                      = 1 × 980 × 38.26

                      = 37494.80 dyne

Here, ρ₂ = density of ball = 0.0348 1 g cm⁻³.

                 Weight of ball = ρ₂gV

                                           = 0.0348 × 980 × 38.26

                                          = 1304.82 dyne

Therefore, the net force required to completely submerge a ball under water    = 37494.80 - 1304.82 = 36,189.98 dyne or 0.362 N

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The upper fixed point, also known as steam point, is the temperature at which pure water boils at normal atmospheric pressure.

In case of the Celsius scale, the upper fixed point is 100°C.

This is the boiling point of pure water at 1atm which is the normal atmospheric pressure.

The pressure that the atmosphere exerts on the earth's surface is called atmospheric pressure.

The temperature at which liquid water starts changing into vapour is called boiling point.

Celcius is an unit of measuring temperature.

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The driver gear is the gear that provides the input motion to the gear train, while the driven gear is the gear that receives motion from the other gears in the train and provides the output motion.

This refers to the main or primary gear that majorly drives the other gears found in the gear train.The driver gear is typically connected to a power source, such as an electric motor or a combustion engine, while the driven gear is connected to the load that the gear train is intended to drive. The driver gear is also the one that has the greater torque and the one that rotates faster.

Driven gears refer to the gear that receives motion from the other gears in the train and provides the output motion.

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Correct Question:

what is the gauge pressure profile of the water against a section of the container?

Gauge pressure is the pressure in relation to atmospheric pressure. For pressures greater than atmospheric pressure, gauge pressure is positive. For pressures lower than atmospheric pressure, gauge pressure is negative.

Pg stands for gauge pressure, which has the following relationships with absolute pressure: pg is equal to p - pa, where Pa is the local atmospheric pressure. Example: The tyre pressure, as determined by a vehicle tyre gauge, is 32.0 psi. The local atmosphere has a pressure of 14.2 psi.

There is pressure between two items that are in touch. The pressure profile is the distribution of pressure throughout the whole contact area.

Since the majority of gauges measure pressure in relation to atmospheric pressure, which acts as the zero point, this form of reading is simply referred to as "gauge pressure." But anything that is not a total vacuum is seen as being under pressure of some kind.

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The possible ways that heat can be transferred in this system are:

The most typical method of heat transfer is conduction, which involves the direct exchange of heat between two things.

Heat waves are created during the radiation heat transfer process and may be absorbed, reflected, or transmitted through a cooler substance. Earth is warmed by the sun using electromagnetic radiation. Heat waves come from warm bodies.

When Joiya sets the bottle of water down on a table or chair, then by conduction, heat ( or the loss of it ) would move around the table. Radiation would allow for the cold temperature to move into the air around the cold bottle.

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Options for this question include:

The required acceleration has a magnitude of 19.7 m/s2  directed upwards, correct to three significant figures.

The the purpose of analysis, the motion of rocket is divided into two phases.

Phase 1: the free fall motion of the rocket from the height 2.98*102m to a height 96.5m.

Phase 2: the motion of the rocket due to the acceleration of the rocket also from the height 96.5 m to the point of touchdown y = 0m.

The initial velocity of the rocket is 0m/s when it started to experience a fall from rest under free fall. g = 9.8m/s² t1 is the time taken for phase 1 and t2 is the time taken for phase2.

The final velocity under free fall becomes the initial velocity for the accelerated motion of the rocket in phase 2 and the final velocity or speed in phase 2 is equal to zero.

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Part a: Velocity with no friction: v = 6.41 m/s.

Part b:  velocity of the moving object when it reached at the bottom is found as  5.29 m/s.

Potential energy P.E

P.E =  mgh

P.E = 38 x 9.8 x 2.1   J

This all transforms to kinetic energy just at bottom = 0.5 mv² if there is no energy loss.

So,

0.5 x 38 x v² = 38 x 9.8 x 2.1,

v = 6.41 m/s

Part b: If friction results in a loss of energy of 250 J

0.5 x 38 x v² = 38 x 9.8 x 2.1 - 250

v² = 532.04/ (0.5 x 38)

v = 5.29 m/s

Thus, the velocity of the moving object when it reached at the bottom is found as  5.29 m/s.

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The correct question is-

2. A 38kg child is at the top of a slide that is 2. 1m tall.

(a) If there is no friction, how fast will they be moving when they reach the bottom of the slide?

(b) If they lose 250. 0J of energy to sound, heat, and friction, how fast will they be moving when they reach the bottom?