Can you please help me it’s due at 11:59 please

Answer:

30 J

Explanation:

height = 3 m

mass = 1kg

acceleration due to gravity = 10m/s²

Potential Energy = mass× gravity × height

= 1kg ×10m/s²× 3m

= 30 J

Answer:

160,934.4 cm or in other words *160,934*

Explanation:

1 mile = 5280 ft.

5280 ft. = 63360 in.

63360 in. = 160934.4

Answer:

1305 I think but not sure

Answer:

5N westward, acting on the student

Explanation:

Answer: 5N westward, acting on the student

Explanation:

Answer:

1) False, since constant speed means constant velocity, but with constant direction as well. Velocity is speed with direction. When you move in a circle, there are boundaries which means that a constant moving speed will cause the object to veer(move in different directions) to maintain movement, If it doesn't veer, the object will deflect(rebound) off the surface due to friction, and impact force or depending on its physical bond of malleability or density.

2a) Create position vectors by drawing a ray from the center(origin) of the circle to each of your desired points, it's magnitude will be the radius(how convenient). Both of these vectors go from the center of the circle to the position on the circle. In general, the distance from the origin to a point is called the radius vector.

2b)

It's gonna take a huge amount of time and effort, and we're gonna spend a huge amount of money, to build a vacuum chamber big enough to do this experiment.  

So when we're finally ready to try it, the cannonball and golf ball will make a  kind of cute experiment, but let's make it really interesting.  Let's ALSO try it with a feather, an apple, a watermelon, a tennis ball, a basketball, a coffeepot, a chair, an old computer, a set of dishes, a trombone, a bicycle, a math book, a TV set, a gallon of milk, a skateboard, a shotgun, a concrete block, a car, a waterbed, a schoolbus, a battleship, your dog, and my wife !

Drop every single one of them from a height of 10 meters.

Every single one of them accelerates at 9.8 m/s² as it falls, takes 1.429 seconds to reach the floor, and hits the floor at a speed of 14 m/s.  The feather, the schoolbus, and my wife stay together all the way down.

The only way this doesn't happen is if ...

-- you do this experiment in some other place that's not Earth, or

-- you throw one of the objects and you don't just drop it, or

-- the vacuum chamber has a leak and some air gets into it.

Because that's how gravity works.

Answer: It’s 98,000

Explanation: Just did it on apex

The force of gravity depends on the mass of objects and the distance between them. This is true statement.

Physics defines force as the push or pull that modifies the velocity of a massed object.

The ability to change a body's resting or moving condition is referred to as an external force. There is a magnitude and a direction to it.

You may determine the Force using a spring balance. The SI's measure of force is the Newton.

The force of gravity between two objects is directly proportional to the mass of the object and inversely proportional to the square of the distance between them.

Hence, the force of gravity depends on the mass of objects and the distance between them. This is true statement.

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Answer:

The shortest possible stopping distance of the car is 175.319 meters.

Explanation:

In this case we see that driver use the brakes to stop the car by means of kinetic friction force. Deceleration of the car is directly proportional to kinetic friction coefficient and can be determined by Second Newton's Law:

[tex]\Sigma F_{x} = -\mu_{k}\cdot N = m \cdot a[/tex] (Eq. 1)

[tex]\Sigma F_{y} = N-m\cdot g = 0[/tex] (Eq. 2)

After quick handling, we get that deceleration experimented by the car is equal to:

[tex]a = -\mu_{k}\cdot g[/tex] (Eq. 3)

Where:

[tex]a[/tex] - Deceleration of the car, measured in meters per square second.

[tex]\mu_{k}[/tex] - Kinetic coefficient of friction, dimensionless.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

If we know that [tex]\mu_{k} = 0.0735[/tex] and [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], then deceleration of the car is:

[tex]a = -(0.0735)\cdot (9.807\,\frac{m}{s^{2}} )[/tex]

[tex]a = -0.721\,\frac{m}{s^{2}}[/tex]

The stopping distance of the car ([tex]\Delta s[/tex]), measured in meters, is determined from the following kinematic expression:

[tex]\Delta s = \frac{v^{2}-v_{o}^{2}}{2\cdot a}[/tex] (Eq. 4)

Where:

[tex]v_{o}[/tex] - Initial speed of the car, measured in meters per second.

[tex]v[/tex] - Final speed of the car, measured in meters per second.

If we know that [tex]v_{o} = 15.9\,\frac{m}{s}[/tex], [tex]v = 0\,\frac{m}{s}[/tex] and [tex]a = -0.721\,\frac{m}{s^{2}}[/tex], stopping distance of the car is:

[tex]\Delta s = \frac{\left(0\,\frac{m}{s} \right)^{2}-\left(15.9\,\frac{m}{s} \right)^{2}}{2\cdot \left(-0.721\,\frac{m}{s^{2}} \right)}[/tex]

[tex]\Delta s = 175.319\,m[/tex]

The shortest possible stopping distance of the car is 175.319 meters.

Answer:

False

Explanation:

More than one management style with all people is the most effective leadership technique for any organization. So, the given statement is False.

Leadership styles are defined as those adopted by company leaders to increase efficiency, satisfaction, growth and advancement in all positions in the organization. It requires a different style in different situations and each leader needs to know when to show a special behavior.

These strategies define every leader's personal leadership style. Some effective leadership Techniques are as follows:

Thus, more than one management style with all people is the most effective leadership technique for any organization. So, the given statement is False.

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Answer:

Physical change

Explanation:

A physical change can be reversible where the original form of the matter can be restored, or irreversible where the original form cannot be restored. Therefore, sawdust is a physical change.

Answer:

Explanation:

a )

initial velocity u = 45 m/s

acceleration a = - 5 m/s²

final velocity v = 0

v = u - at

0 = 45 - 5 t

t = 9 s

b )

s = ut - 1/2 at²

= 45 x 9 - .5 x5x 9²

405 - 202.5

202.5 m

2 )

a )

s = ut + 1/2 a t²

u = 0

s = 1/2 at²

= .5 x 9.54 x 6.5²

= 201.5 m

b )

v = u + at

= 0 + 9.54 x 6.5

= 62.01 m / s

3

a )

acceleration = (v - u) / t

= (34 - 42) / 2.4

= - 3.33 m /s²

b )

v² = u² - 2 a s

34² = 42² - 2 x 3.33² s

s = 27.41 m

c )

Average velocity

Total displacement / time

= 27.41 / 2.4

= 11.42 m /s

4 )

a )

v = u + at

v = 0 + 3 x 4

= 12 m /s

b )

s = ut + 1/2 a t²

= o + .5 x 3 x 4²

= 24 m

Answer:

the corrdct answer is core

Answer: C. Trial 3

Explanation:

Trial 1 and 2 equal 1.5, Trial 3 equals 1 and Trial 4 equals 3. Trial 3 is the smallest current .

The trial for which the students would measure the smallest current is the circuit is trial 2 and trial 3.

To know the trial which generates the smallest current, we need to determine the current in each trial.

Since current I = V/R where V = voltage and R = resistance.

For trial 1, V = 1.5 V and R = 200 Ω

So, I = 1.5 V/200 Ω

= 0.0075 A

= 7.5 mA

For trial 2, V = 1.5 V and R = 100 Ω

So, I = 1.5 V/100 Ω

= 0.015 A

= 15 mA

For trial 3, V = 3 V and R = 200 Ω

So, I = 3 V/200 Ω

= 0.015 A

= 15 mA

For trial 4, V = 3 V and R = 100 Ω

So, I = 3 V/100 Ω

= 0.03 A

= 3 mA

Trial 2 and trial 3 both produce a the smallest current of 15 mA.

So, the trial for which the students would measure the smallest current is the circuit is trial 2 and trial 3.

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Explanation:

Consider a mass of 10 kg, so m = 10

Let's say we apply a net force of 20 newtons, so F = 20

The acceleration 'a' is...

F = ma

20 = 10a

20/10 = a

2 = a

a = 2

The acceleration is 2 m/s^2. Every second, the velocity increases by 10 m/s.

---------------

Now let's double the net force on the object

F = 20 goes to F = 40

m = 10 stays the same

F = ma

40 = 10a

10a = 40

a = 40/10

a = 4

The acceleration has also doubled since earlier it was a = 2, but now it's a = 4.

---------------

In summary, if you double the net force applied to the object, then the acceleration doubles as well.

Acceleration is directly proportional to the net force on an object, and inversely proportional to its mass.

So if an object's mass stays the same while the net force on it doubles, then its acceleration will also double.

We don't know anything about the "trials".  This sounds like it might be a follow-up to a lab experiment that was performed when we weren't there.

We also don't know anything about "question 1".

Answer:

bada bop boop pow

Explanation:

Answer:

True

Explanation:

The term 'plyometrics' is used interchangeably with the term 'jump training'. The technique can be used for training in sports that require explosive movements.

Answer:

electrons will flow from lower (lithium) to higher (zinc)

You can make a stronger battery by having a larger electron affinity difference.

Hope this helps \(-._.-)/

Answer:

a correct

Explanation:

a hypothesis is a supposition made of a basis of limited evidence

Answer:

We have a mass of 200g (0.2kg) moving at 20m/s

Kinetic Energy KE = ½ mv^2 where m is mass and v is velocity

Actually, v is a vector quantity, so KE = ½ mv•v

The dot product of 2 vectors a and b is abCosθ where θ is the angle between the vectors.

Obviously v•v = v^2 Cos0 = v^2

In this case, we have KE = ½ (0.2)(20^2) = 40kg-m^2/s^2 = 40J

So we have kinetic energy in the amount of 40 Joules.

Explanation:

The right answer is "2.7 J"

Answer explanation:

Remember to convert grams to kilograms first by dividing by 1000.

Kinetic energy

= 1/2 × mass × speed2

= 1/2 × 0.2 kg × (5.2 m/s)^2

= 2.7 J (to 2 sig. fig.)

Hope it helps ✨✨

Answer:

Tech B

Explanation:

The control of electric actuators may be through through a two-wire or a five-wire circuit through the driver circuit by bidirectionally controlling via the motor wire polarity. The door position is determined by counting the actuator commutator pulses by the control module in the actuator with 2-wire, while the actuator with 5-wire uses potentiometer feedback.

The A/C ECU is the Air Condition Engine Control Unit.

Answer:

By observing the time between transits, we know the orbital period. Kepler's Third law can be used to determine the orbital radius of the planet if the mass of the orbiting star is known (R3=T2−Mstar/Msun, the radius is in AU and the period is in earth years).

Explanation:

hope this helps!

Answer:

21.3V

Explanation:

Explanation

E = V + Ir

V = E- Ir

V = 24 - {(24/36) x 4}

V = 21.3V

Answer:

2991.47 [cm^2]

Explanation:

To solve this problem we must perform a dimensional analysis and use the corresponding conversion values:

[tex]3.22[ft^{2}]*\frac{12^{2}in^{2} }{1^{2}ft^{2}} *\frac{2.54^{2}cm^{2} }{1^{2}in^{2} } \\2991.47[cm^{2}][/tex]