Can someone please explain to me how to tell if a number it's prime or not

Answer:

56p + 48q + 88

Step-by-step explanation:

When you see parentheses in math, it usually means that you are distributing (multiplying).

So here you would multiply everything inside the parentheses by 8.

7q x 8 = 56q

6p x 8 = 48p

8 x 11 = 88

56q + 48p + 88

There are no like terms here so the answer cannot be simplified any further.

Answer:

X²(4+x)

Step-by-step explanation:

You pick out the common term

Greetings.

The answer is x²(4+x)

Explanation:

[tex]4x^2+x^3\\[/tex]

By using a common factor, we factor x-term out. We factor the x-term with least degree and that is 2-degree. So we factor x² out.

When factored out, It's similar to dividing. When x² is divided by itself, the result is 1. When x³ is divided by x², the result is x (From the property of exponent.)

Similar to dividing, but we pull x² out.

[tex]4x^2+x^3\\x^2(4+x)[/tex]

Therefore, the answer/factored form is x²(4+x)

Answer:

17*200/17+83

Step-by-step explanation:

Points A and B are 200 mi apart. A cyclist started from point A and a motorcyclist started from point B, moving towards each other. The speed of the cyclist was 17 mph, the speed of motorcyclist was 83 mph. At what distance from point A will they meet?

The distance under the question is 17*200/17+83= 17*2 = 34 miles.

17+83 = 100 mph in the denominator is the relative speed of the participants,  the rate of decreasing the distance between them.

200/17+83=200/100= 2 hours is the time before they meet.

therefore  17*200/17+83 is the time before they meet

Answer:

He scored better on the second test by a margin of 3%.

Step-by-step explanation:

Find the percentage of each one by dividing Ahmed's score / Total possible score

24/30 = 0.8 > move the decimal place over twice for % > 80%

20/24 = 0.83333 > move the decimal place over twice for % > 83%

He scored 3% better on the second test.

Answer:

Step-by-step explanation:

Slope of DE = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

                    =  [tex]\frac{c-c}{a+b-b}[/tex]

                    = 0

Slope of BC = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

                    = [tex]\frac{0-0}{2a-0}[/tex]

                    = 0

Therefore, DE║BC because slopes of BC and DE are equal.

Answer:

Demarcus is right the phone will cost $345

Step-by-step explanation:

15% of 300 = 45

300+45=345

Answer:

D: 14.5

Step-by-step explanation:

4.1 = d - 10.4    add 10.4 to each side

14.5 = d

Answer:

14.5

Step-by-step explanation:

10.4 - 4.1 = 14.5

Answer:

[tex]x = \frac{16\sqrt{3}}{3}[/tex]

[tex]y = \frac{32\sqrt 3}{3}[/tex]

Step-by-step explanation:

Calculating (x):

Here, we make use of the tan formula

[tex]tan\theta = \frac{Opp}{Adj}[/tex]

Where

[tex]\theta = 60[/tex]

[tex]Opp = 16[/tex]

[tex]Adj = x[/tex]

This gives:

[tex]tan\ 60= \frac{16}{x}[/tex]

Make x the subject

[tex]x = \frac{16}{tan\ 60}[/tex]

tan(60) in surd form is [tex]\sqrt{3}[/tex]

So:

[tex]x = \frac{16}{\sqrt{3}}[/tex]

Rationalize

[tex]x = \frac{16}{\sqrt{3}} * \frac{\sqrt{3}}{\sqrt{3}}[/tex]

[tex]x = \frac{16\sqrt{3}}{3}[/tex]

Calculating (y):

Here, we make use of the tan formula

[tex]sin\theta = \frac{Opp}{Hyp}[/tex]

Where

[tex]\theta = 60[/tex]

[tex]Opp = 16[/tex]

[tex]Hyp= y[/tex]

This gives:

[tex]sin\ 60= \frac{16}{y}[/tex]

Make y the subject

[tex]y= \frac{16}{sin\ 60}[/tex]

tan(60) in surd form is [tex]\frac{\sqrt{3}}{2}[/tex]

[tex]y= \frac{16}{\frac{\sqrt{3}}{2}}[/tex]

[tex]y = 16/\frac{\sqrt 3}{2}[/tex]

[tex]y = 16*\frac{2}{\sqrt 3}[/tex]

[tex]y = \frac{32}{\sqrt 3}[/tex]

Rationalize

[tex]y = \frac{32}{\sqrt 3}*\frac{\sqrt 3}{\sqrt 3}[/tex]

[tex]y = \frac{32\sqrt 3}{3}[/tex]

Answer:

its to small

Step-by-step explanation:

Answer:Find the slope of the original line and use the point-slope formula  

y

−

y

1

=

m

(

x

−

x

1

)

to find the line parallel to  

y

=

3

x

+

6

.

y

=

3

x

−

5

Step-by-step explanation:

Answer:

The Answer should be....

3q + 21

Answer:

The gas pump filling the gallons in 1 minute will be: 15

Step-by-step explanation:

As there are 60 seconds in 1 minute.

Thus,

Gas pump filling the gallons in 1 minute will be:

[tex]60\:\times 2^{-2}[/tex]

[tex]=60\times \frac{1}{2^2}[/tex]             ∵ [tex]a^{-b}=\frac{1}{a^b}[/tex]

[tex]\mathrm{Multiply\:fractions}:\quad \:a\times \frac{b}{c}=\frac{a\:\times \:b}{c}[/tex]

[tex]=\frac{1\times \:60}{2^2}[/tex]

[tex]=\frac{60}{2^2}[/tex]

[tex]=\frac{2^2\times \:3\times \:5}{2^2}[/tex]

[tex]=3\times \:5[/tex]

[tex]=15[/tex] gallons in one minute

Therefore, the gas pump filling the gallons in 1 minute will be: 15

Answer:

L = 3x cm

Step-by-step explanation:

For this problem, let's consider the relation that is stated:

Length is 3 times as much as the width.  The width is x cm.

Mathematically we can say the following:

L = 3W

W = x cm

So we can say the following about the length:

L = 3W

L = 3(x cm)

L = 3x cm

Cheers.

HL postulate is the answer

Answer:

Step-by-step explanation:

The total number of workers is our unknown. If 40% of this unknown number are women and the number of women is 1380, then the equation looks like this:

(remember that the word "of" generally means to multiply)

(also remember that we have to use the decimal form of a percent in an equation)

.40(x) = 1380 then divide to get the number of total workers:

x = 3450

Answer:

29

Step-by-step explanation:

the rest of the numbers are closer to each other but if you plot these you see that 29 doesnt belong

Answer:

Number of video game = 20

Step-by-step explanation:

Given:

Total number of project = 56

Ratio = 5:9

Find:

Number of video game

Computation:

Number of video game = 56[5/(5+9)]

Number of video game = 56[5/(14)]

Number of video game = 280 / 14

Number of video game = 20

I assume you're referring to the product,

[tex]\log_{5t}(5t+1)\cdot\log_{5t+1}(5t+2)\cdot\cdots\cdot\log_{5t+n}(5t+n+1)[/tex]

Recall the change-of-base identity:

[tex]\log_ab=\dfrac{\log_cb}{\log_ca}[/tex]

where c > 0 and c ≠ 1. This means the product is equivalent to

[tex]\dfrac{\log(5t+1)}{\log(5t)}\cdot\dfrac{\log(5t+2)}{\log(5t+1)}\cdot\cdots\cdot\dfrac{\log(5t+n+1)}{\log(5t+n)}[/tex]

and it telescopes in the sense that the numerator and denominator of any two consecutive terms cancel with one another. The above then simplifies to

[tex]\dfrac{\log(5t+n+1)}{\log(5t)}=\boxed{\log_{5t}(5t+n+1)}[/tex]

Answer:

Sequence; 12, 24, 36, 48, 60, 72, 84, 89, 108...

12th value: 144

The sum of all numbers go through the 12th : 936

Step-by-step explanation:

Answer:

It’s rule is to find the first 5 terms of the variable “n”

Step-by-step explanation:

Answer:

brainlest?

Step-by-step explanation:

......

Answer: I looked it up and got a couple of answers of spatial reasoning. Don’t know if that helps but yeah thats what I got lol

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

the equation for Josh is 500 + 40x while the equation for Vanessa is only 60x

if josh's account balance is greater than it would be josh > vanessa or vanessa < josh

Answer:

x=-13

Step-by-step explanation:

Hope this helped :)

Answer:

x = -13

Step-by-step explanation:

-2x + 10 + 3x = 2x + 6 + 17

x + 10 = 2x + 6 + 17

x + 10 = 2x + 23

10 = 2x + 23 - x

10 = x + 23

10 - 23 = x

-13 = x

x = -13

It is E

Duhhhhhhhhhhhhh

Answer:

1.25,but your teacher is prolly looking for a fraction so 1 1/4

Step-by-step explanation:

DO NOT PUT 20 THAT PERSON S WRONG

Answer:

a. The number of units which will minimize average cost is approximately 5,130 units.

b. The firm should produce 12,500 items, x, for maximum profit.

c. The number of items, x, that will produce a maximum profit is 60 items.

Step-by-step explanation:

Note: This question is not complete as there are some signs are omitted there. The complete question is therefore provided before answering the question as follows:

1. If the total cost function for a product is C(x) = 200(0.02x + 6)^3 dollars, where x represents the number of hundreds of units produced, producing how many units will minimize average cost?

2. A firm can produce only 3900 units per month. The monthly total cost is given by C(x) = 500 + 200x dollars, where x is the number produced. If the total venue is given by R(x) = 450x-1/100x^2 dollars, how many items, x, should the firm produce for maximum profit?

3. If the profit function for a product is P(x) = 3600x + 60x2 - x3 - 72,000 dollars, selling how many items, x, will produce a maximum profit?

The explanation to the answer is now given as follows:

1. If the total cost function for a product is C(x) = 200(0.02x + 6)3 dollars, where x represents the number of hundreds of units produced, producing how many units will minimize average cost?

Given;

C(x) = 200(0.02x + 6)^3 ……………………………………….. (1)

We first simplify (0.02x + 6)^3 as follows:

(0.02x + 6)^3 = (0.02x + 6)(0.02x + 6)(0.02x + 6)

First, we have:

(0.02x + 6)(0.02x + 6) = 0.004x^2 + 0.12x + 0.12x + 36 = 0.004x^2 + 0.24x + 36

Second, we have:

(0.02x + 6)^3 = 0.004x^2 + 0.24x + 36(0.02x + 6)

(0.02x + 6)^3 = 0.00008x^3 + 0.048x^2 + 7.20x + 0.0024x^2 + 1.44x + 216

(0.02x + 6)^3 = 0.00008x^3 + 0.048x^2 + 0.0024x^2 + 7.20x + 1.44x + 216

(0.02x + 6)^3 = 0.00008x^3 + 0.0504x^2 + 8.64x + 216

Therefore, we have:

C(x) = 200(0.02x + 6)^3 = 200(0.00008x^3 + 0.0504x^2 + 8.64x + 216)

C(x) = 0.016x^3 + 10.08x^2 + 1,728x + 43,200

Therefore, the average cost (AC) can be calculated as follows:

AC(x) = C(x) / x = (0.016x^3 + 10.08x^2 + 1,728x + 43,200) / x

AC(x) = (0.016x^3 + 10.08x^2 + 1,728x + 43,200)x^(-1)

AC(x) = 0.016x^2 + 10.08x + 1,728 + 43,200x^(-1) …………………………. (2)

Taking the derivative of equation (2) with respect to x, equating to 0 and solve for x, we have:

0.032x + 10.08 - (43,300 / x^2) = 0

0.032x + 10.08 = 43,300 / x^2

X^2 * 0.32x = 43,300 – 10.08

0.32x^3 = 43,189.92

x^3 = 43,189.92 / 0.32

x^3 = 134,968.50

x = 134,968.50^(1/3)

x = 51.30

Since it is stated in the question that x represents the number of hundreds of units produced, we simply multiply by 100 as follows:

x = 51.30 * 100 = 5,130

Therefore, the number of units which will minimize average cost is approximately 5,130 units.

2. A firm can produce only 3900 units per month. The monthly total cost is given by C(x) = 500 + 200x dollars, where x is the number produced. If the total revenue is given by R(x) = 450x-1/100x^2 dollars, how many items, x, should the firm produce for maximum profit?

P(x) = R(x) - C(x) ……………. (3)

Where;

P(x) = Profit = ?

R(x) = 450x-1/100x^2

C(x) = 500 + 200x

Substituting the equations into equation (3), we have:

P(x) = 450x - 1/100x^2 - (500 + 200x)

P(x) = 450x - 0.01x^2 - 500 - 200x

P(x) = 450x - 200x - 0.01x^2 - 500

P(x) = 250x - 0.01x^2 – 500 …………………………………. (4)

Taking the derivative of equation (4) with respect to x, equating to 0 and solve for x, we have:

250 - 0.02x = 0

250 = 0.02x

x = 250 / 0.02

x = 12,500 items

Therefore, the firm should produce 12,500 items, x, for maximum profit.

3. If the profit function for a product is P(x) = 3600x + 60x2 – x^3 - 72,000 dollars, selling how many items, x, will produce a maximum profit?

Given;

P(x) = 3600x + 60x2 – x^3 - 72,000 …………………………. (5)

Taking the derivative of equation (5) with respect to x, equating to 0 and solve for x, we have:

3600 + 120x - 3x^2 = 0

Divide through by 3, we have:

1200 + 40x – x^2 = 0

1200 + 60x – 20x – x^2 = 0

60(20 + x) – x(20 + x) = 0

(60 – x)(20 + x) = 0

Therefore,

x = 60, or x = - 20

The negative value of x (i.e. x = - 20) will be will be ignored because it has no economic significance. Therefore, the number of items, x, that will produce a maximum profit is 60 items.