can one entangled particle be measured for momentum while the other entangled particle is measured for position?

Answers

Answer 1

According to the principles of quantum mechanics, the answer to the question, "Can one entangled particle be measured for momentum while the other entangled particle is measured for the position?" is no.

If you measure the position of one particle in an entangled pair, you are creating a definite outcome for that particle. By measuring the other particle's momentum, you are causing it to have a definite outcome. That, however, is incompatible with the fact that the two particles are entangled. Their correlation will be broken if this is done.

The position and momentum measurements are incompatible in quantum mechanics. If you want to measure the position of a particle, the uncertainty in the momentum of the particle must be large. Conversely, if you want to measure the momentum of a particle, the uncertainty in the position of the particle must be large.

Furthermore, measuring the position of a particle has a detrimental effect on the uncertainty in its momentum. Similarly, measuring the momentum of a particle has a detrimental effect on the uncertainty in its position. The measurement outcomes of two entangled particles are determined by correlations between them.

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Related Questions

Determining the distance to stars can be challenging. The parallax method is one way of finding the distance to many stars around us. Your research team measures the parallax of two stars that have a distance of 5 degrees from each other in the night sky: The first star has a parallax of 0.11 arcsec, and the second has a parallax of 0.13 arcsec. How far apart are the two stars from each other? Express your answer in light-years​

Answers

To determine the distance to the stars, we need to use the parallax formula:

distance = 1 / (parallax angle in arcseconds)

Let's use this formula to calculate the distances to the two stars:

distance to star 1 = 1 / 0.11 arcsec = 9.09 parsecs

distance to star 2 = 1 / 0.13 arcsec = 7.69 parsecs

Now, we need to determine the distance between the two stars. We can use trigonometry to do this. The angle between the two stars is 5 degrees, which is equivalent to 300 arcminutes or 18,000 arcseconds. Since we know the distance to each star, we can use the tangent function to calculate the distance between them:

tan(5 degrees/2) = (distance to star 1 - distance to star 2) / distance between stars

Simplifying this equation, we get:

distance between stars = (distance to star 1 - distance to star 2) / 2 / tan(5 degrees/2)

Plugging in the values we calculated earlier, we get:

distance between stars = (9.09 parsecs - 7.69 parsecs) / 2 / tan(5 degrees/2) = 5.57 parsecs

Finally, we convert this distance to light-years:

1 parsec = 3.26 light-years

So, the distance between the two stars is:

distance between stars = 5.57 parsecs * 3.26 light-years/parsec = 18.15 light-years

Therefore, the two stars are about 18.15 light-years apart from each other.

1. A fairground ride consists of a large vertical drum that spins so
fast that everyone inside it stays pinned against the wall when
the floor drops away. The diameter of the drum is 10 m. Assume
that the coefficient of static friction between the drum and the
rider's clothes is 0. 15. What is the angular velocity of the drum at this speed?

Answers

The angular velocity of the drum is approximately 0.558 radians per second.

To find the angular velocity of the drum, we can use the centripetal force equation:

F = ma = mrω^2

where F is the force of friction between the drum and the rider's clothes, m is the mass of the rider, r is the radius of the drum (which is half its diameter, or 5 m), and ω is the angular velocity of the drum.

We can rearrange this equation to solve for ω:

ω^2 = F / mr

The force of friction can be found using the coefficient of static friction and the normal force, which is the weight of the rider:

F = μN = μmg

where μ is the coefficient of static friction, m is the mass of the rider, and g is the acceleration due to gravity.

Putting it all together, we have:

ω^2 = (μmg) / mr

Plugging in the given values, we get:

ω^2 = (0.15)(mg) / (5m)

where g is approximately 9.81 m/s^2.

Simplifying:

ω^2 = 0.03g

ω = sqrt(0.03g)

ω = sqrt(0.03 x 9.81)

ω = 0.558 rad/s

Thus the value of angular velocity is 0.558 radians per second.

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a car is traveling up one side of a hill and down the other side. the top of the hill is a circular arc with a radius of 45.0 m. determine the maximum speed the car can have without losing contact with the road.

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When a car travels up one side of a hill and down the other, it can lose contact with the road if it goes too fast. The maximum speed the car can have without losing contact with the road is 21.8 m/s.

The weight of the car is equal to its mass times gravity, which is equal to m * g. The normal force, on the other hand, is the force that the ground exerts on the car, and it is equal in magnitude to the weight of the car but in the opposite direction.

When the normal force is zero, the car loses contact with the road, which is why we're looking for the maximum speed that will still produce a normal force greater than zero.

Thus, the maximum speed can be found using the equation: v² / R = g; where v is the maximum speed of the car,

R is the radius of the circular arc, and

g is the acceleration due to gravity.

Substituting the given values gives: v² / 45.0 = 9.81

Solving for v, we get: v = √(45.0 * 9.81) = 21.8 m/s

Therefore, the maximum speed the car can have without losing contact with the road is 21.8 m/s.

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According to current understanding, how did the first generation of stars differ from stars born today?

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According to current understanding, the first generation of stars differed from stars born today in their composition.

The first generation of stars, also known as Population III stars, were made up of mostly hydrogen and helium, with very little to no heavier elements.

This is because they formed from the gas and dust left over from the Big Bang, which was primarily hydrogen and helium.

In contrast, stars born today, also known as Population I stars, have a higher percentage of heavier elements, such as carbon, oxygen, and iron.

This is because they formed from gas and dust that has been enriched with heavier elements from previous generations of stars.

As stars age and die, they expel these heavier elements into the surrounding gas and dust, which then goes on to form new stars.

Therefore, the main difference between the first generation of stars and stars born today is their composition, with the first generation having a higher percentage of hydrogen and helium, and stars born today having a higher percentage of heavier elements.

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How much energy is needed to boil 1.5kg of water? Specific Latent Heat of Fusion = 2,260,000J/kg​

Answers

Taking into account the definition of latent heat, the energy needed to boil 1.5 kg of water is 3,390,000 J.

Definition of latent heat

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

The heat Q  necessary to provide for a mass m of a certain substance to change phase is equal to

Q = m×L

where L is called the latent heat of the substance and depends on the type of phase change.

Energy needed in this case

In this case, you know:

Q= ?m= 1.5 kgL= Specific Latent Heat of Fusion = 2,260,000 J/kg​

Replacing in the definition of latent heat:

Q = 1.5 kg× 2,260,000J/kg​

Solving:

Q= 3,390,000 J

Finally, the energy needed is 3,390,000 J.

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which constellation appears to have the shape of a big ladle or a question mark?​

Answers

Answer:

Ursa Major

Explanation:

The constellation that appears to have the shape of a big ladle or a question mark is Ursa Major (also known as the Great Bear).

The difference between meteoroids and meteor

Answers

Their difference is location. Meteoroids are up in the sky. Meteors fall to Earth and flash light breaking down in the atmosphere

Answer:

Meteoroids are objects in space that range in size from dust grains to small asteroids. Think of them as “space rocks." When meteoroids enter Earth's atmosphere (or that of another planet, like Mars) at high speed and burn up, the fireballs or “shooting stars” are called meteors.

Explanation:

thx to the internet

Need help this is a grade

Answers

Answer: C

Explanation: When you have a tomato for example, it absorbs every color but red and therefore, appears red.

5. A block with mass m = 250 g is compressing a spring with a spring constant k = 60 N/m a distance of d = 16.0 cm from its equilibrium position. If the mass let go, how high above its initial position does the mass rise?​

Answers

Answer:

The potential energy stored in the spring when it is compressed by a distance of 16.0 cm can be calculated using the formula:

U = (1/2) k x^2

where U is the potential energy, k is the spring constant, and x is the displacement from equilibrium position.

Plugging in the given values, we get:

U = (1/2) * 60 N/m * (0.16 m)^2

U = 0.768 J

When the mass is released, the potential energy stored in the spring is converted to kinetic energy of the mass as it moves upward. At the highest point, all of the kinetic energy is converted back to potential energy. The total mechanical energy of the system (spring + block) is conserved, so we can equate the potential energy at the highest point to the initial potential energy stored in the spring:

mgh = U

where m is the mass of the block, g is the acceleration due to gravity (9.81 m/s^2), h is the maximum height reached by the block.

Plugging in the values, we get:

(0.250 kg) * (9.81 m/s^2) * h = 0.768 J

Solving for h, we get:

h = 0.768 J / (0.250 kg * 9.81 m/s^2) ≈ 0.312 m

Therefore, the block rises to a maximum height of approximately 0.312 m above its initial position.

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How far will the driver be behind the vehicle in front at 30mph ? Give your answer to 2 significant figures.

Answers

The driver should be at least 39 meters behind the vehicle in front at 30mph. Rounded to 2 significant figures, this is 39 meters

How did we arrive at this value?

The recommended safe following distance while driving is at least 3 seconds behind the vehicle in front of you. At 30mph (or approximately 13 meters per second), a 2-second following distance would be:

3 seconds x 13 meters/second = 39 meters

Therefore, the driver should be at least 39 meters behind the vehicle in front at 30mph. Rounded to 2 significant figures, it could then be concluded that the driver should be at least 39 meters.

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Determine the forces in all the members of the complex truss. State if the members are in tension or compression. Hint: substitute member ad with one placed between e and c

Answers

We can ascertain the forces in each component of the complex truss and whether they are in tension or compression by using the method of joints or method of sections.

To determine the forces in all the members of the complex truss, we can first substitute member AD with one placed between E and C. This will result in a simpler truss with fewer members and easier to analyze.

Once we have the simplified truss, we can apply the method of joints or method of sections to find the forces in each member. The method of joints involves analyzing the forces acting at each joint in the truss, while the method of sections involves cutting through the truss to create a section and analyzing the forces acting on that section.

After we have found the forces in the members, we can determine whether they are in tension or compression. A member is in tension if it is being stretched, while it is in compression if it is being compressed or shortened. This depends on whether the forces acting on the member are pulling it apart or pushing it together.

In general, a truss is designed so that all members are either in tension or compression, and none of them are in bending or shear. This is because trusses are designed to resist only axial loads, and not bending or shear loads.

Therefore, by using the method of joints or method of sections, we can determine the forces in all the members of the complex truss and whether they are in tension or compression.

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A boat accelerates from 8.5 m/s west to 1.8 m/s west at a rate of 2.9 m/s^2 east. How far does it travel

Answers

The distance traveled while accelerating can be found by multiplying the average velocity by the time taken to accelerate

Complete question:

A boat accelerates from 8.5 m/s west to 1.8 m/s west at a rate of 2.9 m/s^2 east. How far does it travel while accelerating?

Computation of Distance

The average velocity is the difference between the initial and final velocities, divided by two. The time taken to accelerate is the difference between the initial and final velocities, divided by the rate of acceleration.

Given Data

Average velocity = (8.5 m/s - 1.8 m/s) / 2 = 3.35 m/sTime taken to accelerate = (8.5 m/s - 1.8 m/s) / 2.9 m/s^2 = 2.03 s

we know that the expression for computing distance is given as

Distance traveled while accelerating = Average velocity * Time taken to accelerate

Substituting our data in the expression we have

Distance traveled while accelerating = 3.35 m/s * 2.03 s = 6.80 m

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when the mass of water that an iceberg displaces is equal to the mass of the iceberg, it floats. this is an example of: group of answer choices isostacy. gravity. tomography. upwelling.

Answers

The correct answer is isostasy. When the mass of water that an iceberg displaces is equal to the mass of the iceberg, it floats -  This is known as isostasy.

Isostasy is the process whereby the mass of an object affects the gravitational forces and causes it to float. In this case, when the mass of an iceberg is equal to the mass of the water it displaces, the forces acting on the iceberg are balanced, and it will float.


Isostasy occurs when a body's mass is distributed in such a way that the gravitational forces acting upon it are equal in all directions.

In the case of an iceberg, when the mass of the iceberg is equal to the mass of the water it displaces, the downward force of the iceberg's weight and the upward force of the water's buoyancy balance each other out, and the iceberg floats.

This is thus an example of isostasy, a process by which the mass of an object affects the gravitational forces, causing it to float.

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(PLS HELP ME NOW!!!!!)

Answers

Answer:

D

Explanation:

A baseball is batted. It's a long fly ball. 5. 0 seconds later the ball reaches the outfield 100 meters away and returns to the height from which it left the bat. A. What maximum height did the baseball reach?

Answers

The maximum height reached by the baseball is 24.5 meters.

We can use the kinematic equation for the vertical motion:

h = vi*t + (1/2)at^2

where h is the maximum height reached by the baseball,

vi is the initial vertical velocity,

a is the acceleration due to gravity (-9.8 m/s^2),

and t is the time taken for the ball to reach its maximum height.

At the maximum height, the vertical velocity of the ball is zero. Therefore, we can write:

h = (1/2)at^2

We know that the total time for the baseball to travel to the outfield and return is 5 seconds, so the time taken to reach the maximum height is half of that or 2.5 seconds.

After substituting the values we know, we get:

h = (1/2)(-9.8 m/s^2)(2.5 s)^2

h = 24.5 meters

Therefore, the maximum height the baseball reached is approximately 24.5 meters.

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a block of mass m is attached to the end of a horizontal massless spring (spring constant k), resting on a frictionless table. the mass is then given an initial displacement x0 from equilibrium, and an initial speed v0. ignoring friction, use energy methods to finda. its maximum speed, andb. its maximum stretch from equilibrium, in terms of the given quantities.

Answers

The maximum speed of the mass is given by vmax = sqrt((k/m)xmax²) and the maximum stretch from equilibrium is given by xmax = ((2/m)(1/2)mv0²/k).

The mass is given an initial displacement x0 from equilibrium and an initial speed v0. The maximum speed and maximum stretch from equilibrium can be found using energy methods.Ignoring friction, the total energy of the system is given as E = (1/2)kx0² + (1/2)mv0², where (1/2)kx0² represents the potential energy of the spring, and (1/2)mv0² represents the kinetic energy of the mass.

At maximum speed, all potential energy is converted to kinetic energy. Therefore, we can say that (1/2)kxmax² = (1/2)mvmax², where xmax is the maximum stretch of the spring from equilibrium and vmax is the maximum speed of the mass. Therefore, we can say that (1/2) mvmax² = (1/2) kx0², where x0 is the initial displacement of the mass from equilibrium.  

Therefore, the maximum speed of the mass is given by vmax = ((k/m)xmax²) and the maximum stretch from equilibrium is given by xmax = ((2/m)(1/2)mv0²/k). These equations can be used to find the maximum speed and initial displacement and velocity.

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if two objects that have charges of +8 C and -4 C touch each other and are then separated what will be the charge on each object

Answers

Answer:

30q1

Explanation:

Uniformly charged spheres are “touching”. 4. What must be the distance between point charge q1 = 26.0µC and point charge q2 = −47.0µC

A thief is running away from a scene and reaches a speed of 10 m/s in 5 seconds what is the thief acceleration

A. 2 m/s^2
B. 8 m/s^2
C. 18 m/s^2
D. 1 m/s^2

Answers

Answer: [tex]2 m/s^{2}[/tex] (Assuming the thief starts from 0 m/s)

Explanation:

First you take the final velocity (10) and subtract the initial velocity (0)

[tex]10-0=10[/tex]

Then you divide the difference by the time to get the acceleration

[tex]10/5=2[/tex]

This all uses the equation

[tex]V_{f}-V_{i}=ta[/tex]

A uniform electric field with a magnitude of 5.0 x 10^2 N/C is directed parallel to the positive x-axis toward the origin. What is the change in electrical energy of a proton (q= 1.60 x 10 ^-19 C ) as it moves from x = 5 m to x = 2 m?

Answers

The change in the electrical energy of a proton would be 2.40 x 10^-16 J.

Change in electrical energy

The change in electrical potential energy of a charged particle in a uniform electric field is given by the equation:

ΔPE = qEd

where q is the charge of the particle, E is the magnitude of the electric field, and d is the distance moved by the particle in the direction of the electric field.

In this case, the proton has a charge of q = 1.60 x 10^-19 C and moves a distance of d = 5 m - 2 m = 3 m in the direction of the electric field. The magnitude of the electric field is E = 5.0 x 10^2 N/C.

Substituting these values into the equation, we get:

ΔPE = (1.60 x 10^-19 C)(5.0 x 10^2 N/C)(3 m)

ΔPE = 2.40 x 10^-16 J

Therefore, the change in electrical energy of the proton as it moves from x = 5 m to x = 2 m is 2.40 x 10^-16 J.

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define moment with complete in depth explanation​

Answers

Answer: In its most basic form, a moment is the product of the distance to a point, raised to a power, and a physical quantity (such as force or electrical charge) at that point: is the physical quantity such as a force applied at a point, or a point charge, or a point mass, etc.

The Principle of Moment says that when a system is in equilibrium the sum of its clockwise moments will be equal to the sum of its anticlockwise moments. Some examples where moments i.e. turning effects are applicable will involve levers, like seesaws, opening and closing doors, nutcrackers, can openers, and crowbars.

Explanation:

In a resistive circuit if the current is increased to two times, the percentage change in the amount of heat dissipated in the circuit would be​

Answers

Answer:

P = I V = I*2 R       power used in resistive circuit

Doubling the current will cause a 4X increase in power consumed

name and explain the 3 categories of the municipality​

Answers

Answer:

please make me brainalist and keep smiling dude

Explanation:

The Act provides for the constitution of 3 types of municipalities, depending upon the size and area in every state.

Nagar Panchayat (for an area in transition from rural to the urban area);Nagar Panchayat (for an area in transition from rural to the urban area);Municipal Council for the smaller urban area; and.Nagar Panchayat (for an area in transition from rural to the urban area);Municipal Council for the smaller urban area; and.Municipal Corporation for a larger urban area.

Answer:

Explanation:

Nagar Panchayat (for an area in transition from rural to the urban area);

Nagar Panchayat (for an area in transition from rural to the urban area);Municipal Council for the smaller urban area; and.

Nagar Panchayat (for an area in transition from rural to the urban area);Municipal Council for the smaller urban area; and.Municipal Corporation for a larger urban area.

A kickball is struck with a 15.2 m/s velocity at a 63 degree angle. It lands on a rooftop 2.4 s later. How high is the roof?

Answers

Answer:

the height of the rooftop is approximately 16.4 meters or about 54 feet high.

Explanation:

To solve this problem, we need to use the kinematic equations of motion. We will assume that air resistance is negligible and that the acceleration due to gravity is -9.8 m/s^2.

First, we will use the initial velocity and angle of the kickball to find its horizontal and vertical components of velocity.

The horizontal component of velocity (Vx) can be found using the equation:

Vx = V * cos(theta)

where V is the initial velocity and theta is the angle of the kickball.

Vx = 15.2 m/s * cos(63 degrees)

Vx = 6.62 m/s

The vertical component of velocity (Vy) can be found using the equation:

Vy = V * sin(theta)

Vy = 15.2 m/s * sin(63 degrees)

Vy = 13.7 m/s

Next, we can use the vertical component of velocity to find the maximum height (h) reached by the kickball. We can use the following kinematic equation:

h = Vy^2 / (2 * g)

where g is the acceleration due to gravity.

h = (13.7 m/s)^2 / (2 * 9.8 m/s^2)

h = 9.47 meters

So, the maximum height reached by the kickball is 9.47 meters.

Finally, we can use the time it takes for the kickball to land on the rooftop to find the height (d) of the rooftop. We can use another kinematic equation:

d = Vy * t + 0.5 * g * t^2

where t is the time it takes for the kickball to land on the rooftop.

d = 13.7 m/s * 2.4 s + 0.5 * (-9.8 m/s^2) * (2.4 s)^2

d = 16.4 meters

Therefore, the height of the rooftop is approximately 16.4 meters or about 54 feet high.

Solve fast please there is no time

Answers

25 km

please make me brainalist and keep smiling dude because I do don't have time I should help

how does the president fufill the role of a economic leader

Answers

The president plays the part of an economic leader by planning the government budget.

What does an economic leader do?

examining data on monetary movements and trends. examining federal policies and initiatives to make sure they continue to support strong economic principles. advocating for economic measures that will help American workers.

What function is the president performing?

The President of the United States, who also serves as head of state and commander-in-chief of the armed forces, is given control over the Executive Branch. The president's responsibility as chief legislator is to have an impact on the creation of laws. Through his State of the Union Address, the president contributes to setting the country's policy agenda.

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since Which animal is a vertebrate?(1 point)

shrimp

octopus

crab

fish

Answers

The animal that is a vertebrate is a fish.

What are vertebrate animals?

Vertebrates are animals that possess a backbone, also known as a vertebral column or spinal column. The backbone is composed of individual vertebrae, which protect the spinal cord and provide support for the body.

Vertebrates are a diverse group of animals and include fish, amphibians, reptiles, birds, and mammals. They are characterized by having a complex nervous system, a closed circulatory system, and a well-developed brain.

Vertebrates are also capable of a wide range of behaviors and have adapted to live in various habitats, from the depths of the ocean to the highest mountains.

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Find the work done by a force F = 4i − 3j + 2k that moves an object from the point (3, 2, -1) to the point (2, -1, 4) along a straight line. The distance is measured in meters and the force in newtons.

Answers

Answer:

15 N

Explanation:

work done by the force in vector form is given by the equation,

[tex]W = \vec{F}.\delta \vec{r}[/tex]

where . represents the dot product.

in the given question,

[tex]F = 4i - 3j + 2k[/tex]

and

[tex]\delta \vec{r} = (2 - 3)i + (-1 - 2)j + (4 - (-1))k[/tex]

[tex]\delta \vec{r} = -i - 3j + 5k[/tex]

on doing the dot product we get

[tex]W = -4 + 9 + 10\\W = 15[/tex]

Hopefully this answer helped you.

Determine the total resistance for the current

Answers

The total flow of electricity from the source is equivalent to the sum of the currents through each path. To calculate the total impedance in a parallel circuit, use the method below : 1/Rt Equals 1/R1 + 1/R2 + 1/R3 +...

How do you find total resistance of a current?

IT = VT/RT or I total = V total / R total or the total current = the total voltage / the total resistance.

Current still flows along the other routes even if one of the parallel ones is blocked.

R_total = R1 + R2 +... + Rn The sum of all individual resistances makes up the system's overall resistance. Take the example issue below as an

example. A resistor with a 100 ohm electrical resistance value is linked to a resistor with a 200 ohm electrical resistance value.

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Please help me thank you

Answers

The equivalent resistance is 6R/11, the current flowing through the circuit is 55/6R, and the voltage across resistor R2 is 55/3 V when the three parallel resistors R1, R2, and R3 are joined in parallel across a 5V battery.

What is the unit of resistance?

The unit of resistance is ohm (Ω), named after the German physicist Georg Simon Ohm. One ohm is defined as the amount of resistance that will allow one ampere of current to flow with one volt of applied potential difference.

To find the equivalent resistance (R_eq) of the three parallel resistors R1, R2, and R3, we can use the formula:

1/R_eq = 1/R1 + 1/R2 + 1/R3

Substituting R1 = R, R2 = 2R, and R3 = 3R, we get:

1/R_eq = 1/R + 1/2R + 1/3R

1/R_eq = (6/6R + 3/6R + 2/6R) / (1/6R)

1/R_eq = 11/6R

R_eq = 6R/11

To find the current (I) flowing through the circuit, we can use Ohm's Law, which states that:

I = V/R_eq

Substituting V = 5V and R_eq = 6R/11, we get:

I = 5 / (6R/11)

I = 55/6R

To find the voltage (V_R2) across resistor R2, we can use the formula:

V_R2 = I * R2

Substituting I = 55/6R and R2 = 2R, we get:

V_R2 = (55/6R) * (2R)

V_R2 = 55/3 V

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Auto companies frequently test the safety of automobiles by putting them through crash tests to

observe the integrity of the passenger compartment. If a 2000. -kg car is sent toward a cement wall

with a speed of 14 m/s and the impact brings it to a stop in 4. 00 X 10^-2 s, with what average

force is it brought to rest?

Answers

The average force acting on the car as it comes to a stop is [tex]7.00 \times 10^5 N.[/tex]

We can use the equation for average force, which is:

average force = change in momentum / time

To use this equation, we first need to find the change in momentum of the car. We can use the equation:

change in momentum = final momentum - initial momentum

The initial momentum of the car is:

p1 = m1 × v1

where m1 is the mass of the car (2000 kg) and v1 is the initial velocity (14 m/s).

p1 = (2000 kg)(14 m/s) = 28,000 kg × m/s

The final momentum of the car is zero, since it comes to a stop.

p2 = 0

So the change in momentum is:

Δp = p2 - p1 = -28,000 kg × m/s

Now we can substitute these values into the equation for average force:

average force = Δp / t

where t is the time it takes for the car to come to a stop[tex](4.00 \times 10^{-2} s).[/tex]

average force =[tex](-28,000 kg\times m/s) / (4.00 \times 10^{-2} s)[/tex]

average force =[tex]- 7.00 \times 10^5 N[/tex]

The negative sign indicates that the force is acting in the opposite direction to the motion of the car. We could also take the magnitude of the force, which would be:

|average force| = [tex]7.00 \times 10^5 N[/tex]

Therefore, the average force acting on the car as it comes to a stop is [tex]7.00 \times 10^5 N.[/tex]

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