Answer:
no
Explanation:
A man has a mass of 66 kg on Earth. What is his weight in Newtons?
Answer:
answer is 66 kilograms-force = 647.2389 newtons
Explanation:
Answer:
[tex]\boxed {\boxed {\sf 646.8 \ Newtons }}[/tex]
Explanation:
Weight in Newtons can be found by multiplying the mass times the acceleration of gravity.
[tex]W=m*g[/tex]
The mass of the man is 66 kilograms on Earth.
Earth has an acceleration of gravity that is 9.8 meters per square second.
[tex]m= 66 \ kg \\g=9.8 \ m/s^2[/tex]
Substitute the values into the formula.
[tex]W=66 \ kg *9.8 \ m/s^2[/tex]
Multiply.
[tex]W=646.8 \ kg*m/s^2[/tex]
1 kg * m/s² is equal to 1 Newton, therefore our answer of 646.8 kg *m/s² is also equal to 646.8 Newtons, or N.
[tex]W=646.8 \ N[/tex]
The man's weight in Newtons in 646.8 Newtons.
Adhira loves to ride her bike around the neighborhood. She starts riding 1.2 miles at 30° S of E. Then, she rides another 2.0 miles at 20° W of S. Next, she rides 1.6 miles at 30° S of W. And finally, she rides 2.6 miles at 15° W of N. What is her final displacement from her starting point?
Answer:
D = 1.8677 miles , θ = 24.28º at South of West
Explanation:
This is an exercise in adding vectors, the easiest way to solve them is to decompose the vectors and add each component algebraically. Let's use trigonometry
first displacement. d = 1.2 miles to 30º south of East
cos ( 360-30) = cos (-30) = x₁ / d
sin (-30) = y₁ / d
x₁ = d cos (-30)
y₁ = d sin (-30)
x₁ = 1.2 cos (-30) = 1,039 miles
y₁ = 1.2 sin (-30) = -0.6 miles
second shift. d = 2.0 miles to 20º West of South
cos (270-20) = x₂ / d
cos (250) = y₂ / d
x₂ = 2.0 cos 250 = -0.684 miles
y₂ = 2.0 sin250 = -1.879 miles
Third displacement. d = 1.6 miles to 30º South of West
cos (180 + 30) = x₃ / d
sin (210) = y₃ / d
x₃ = 1.6 cos 210 = -1.3856 miles
y₃ = 1.6 sin 210 = -0.8 miles
Fourth displacement. d = 2.6 miles to 15º West of North
cos (90 + 15) = x₄ / d
sin (105) = y₄ / d
x₄ = 2.6 cos 105 = -0.6729 miles
y₄ = 2.6 sin 105 = 2,511 miles
having all the components we add
x-axis (West-East direction)
X = x₁ + x₂ + x₃ + x₄
X = 1.039 -0.684 - 1.3846 - 0.6729
X = -1.7025 miles
Y = y₁ + y₂ + y₃ + y₄
Y = -0.6 -1.879 -0.8 +2.511
Y = -0.768
The modulus of this displacement is we use the Pythagorean theorem
D = √ (X² + Y²)
D = √ (1.7025² + 0.768²)
D = 1.8677 miles
let's use trigonometry to find the direction
tan θ = Y / X
θ = tan⁻¹ Y / x
θ = tan⁻¹ (0.768 / 1.7025)
θ = 24.28º
as the two components are negative this angle is in the third quadrant
therefore in cardinal direction form is
θ = 24.28º at South of West
hey pls help with this HDJSJDH im rlly bad at this kinda stuff :,) i'll mark the correct answer brainliest
Answer:
A. Cue, White Ball, Blue Ball
Explanation:
Visualize in which order things are being hit
what is the coefficent for hydrochloric acid
Answer:
HCI
Explanation:
I dont know what you mean by coefficient but that's the thing you would see in the periodic table
plzzzz help me and I will mark u the brainiest
A ball is thrown horizontally with an initial
velocity of 20 m/s from the top of a tower
60 m high. What is the initial vertical
velocity of the ball?
a. O m/s
b. 20 m/s
c. 3.5 m/s
d. 9.81 m/s
The initial vertical velocity of a ball thrown horizontally with an initial velocity of 20 m/s from the top of a 60 m high tower is 0 m/s (option a).
The ball is thrown horizontally, so its velocity will have only components in the x-direction (horizontal). The components of the initial velocity in the y-direction (vertical) will be zero.
For a ball's velocity to have components in the vertical and horizontal direction, the ball must be thrown at a certain angle to the ground, describing a parabolic movement.
In a parabolic movement, the vertical and horizontal components of the velocity would be:
[tex] v_{x} = v_{i}cos(\theta) [/tex]
[tex] v_{y} = v_{i}sin(\theta) [/tex]
Where:
[tex] v_{i} [/tex]: is the initial velocity
θ: is the angle
Therefore, the initial vertical velocity of the ball is zero (option a).
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Scince Why do cells need to adjust when conditions change? ____________________________________________________________________________________________
Answer:
A cell is the basic block of life and is always changing to fit its environment.
Explanation:
A cell is the basic founding block of a living organisms. In other words, a cell is the basic membrane unit which contains fundamental molecules of life. It is the cell that all living things are composed of.
The cell always changes with the surroundings and environment and it adapts to it. The cells requires a constant adjustments as the conditions inside and the outside the cells changes to keep a stable internal environment. Because the environment internally and externally is always changing, the cell continuously make adjustments to stay at or the near the set point.
The mass of the sun is 1.9891030 kg and the mass of the Earth is 5.9721024kg. If the Earth’s acceleration toward the sun is 0.0059 m/s/s, what is the sun’s acceleration toward the Earth?
Answer:
this is the answer according to my calculations
Explanation:
0.001.9
2) A car is towed by a horizontal rope at a constant speed.
draw the free body diagram
Answer:
\
\
\
Explanation:
Create an acronym using the word IGNEOUS.
I Guess Nobody Enjoys Odd Unicorn Shirts
HELP PLEASE
A load is a device that changes electrical energy into other forms of energy. Which load converts electrical energy into thermal energy by passing an electric current through a high-resistance material?
A.
Hand-powered generator
B.
Toaster
C.
Fan
D.
Electrical drill
Answer:
A toaster because you plug it up for electric energy and heat to toast it
A projectile launched at an angle of 45 degrees above the horizontal travels through the air. Compared to the projectile's theoretical path with no air friction, the actual trajectory of the projectile with air friction is
A.) lower and shorter
B.) higher and shorter
C.) lower and longer
D.) higher and longer
Answer: A
Explanation:
A windshield hits a bug with force of 10 N.
What force does the bug hit the windshield?
Explain using Newton's third law.
A 3.0\, \text {kg}3.0kg3, point, 0, start text, k, g, end text box is at rest on a table. The static friction coefficient \mu_sμ s mu, start subscript, s, end subscript between the box and table is 0.400.400, point, 40, and the kinetic friction coefficient \mu_kμ k mu, start subscript, k, end subscript is 0.100.100, point, 10. Then, a 10\,\text N10N10, start text, N, end text horizontal force is applied to the box. What is the best estimate of the magnitude of the box’s acceleration?
Answer:
its 0 m/s^2 on khan
Explanation:
usually how i think of it if its below 15 N then its 0
Answer:
5.3m/s^2
Explanation:
:)
How did the scalawags change government in the South?
They administered loyalty oaths to former Confederates.
They brought Republican ideas to southern politics.
They created the public school system.
They used legislation to stop African Americans from voting.
Answer: They brought Republican ideas to southern politics.
Explanation:
Scalawags were white Southerners in the United States who supported the Republicans.ans supported the Reconstruction plan of the federal government after the civil war took place.
They wanted to make changes, and hence favored low taxes, and relief for debtors. The scalawags change government in the South by bringing Republican ideas to southern politics.
The correct option is B.
Which Box in the diagram above, should this picture go into?
Box A
ООО
O Box B
O Box C
Plzz answerr idk
the faster particles move the less kinetic energy they have true or false
Answer:
False
Explanation:
You get more kinetic energy the more the particles and less kinetic energy with less particles
7. A complex arrangement of pulleys forms what is called the block in a block
and tackle. The rope used to lift the pulleys and the load is the tackle. A block
and tackle is used to lift a truck engine, which weighs nearly 7,406 N. The
force required to lift this weight using the block and tackle is 308.6 N. What is
the mechanical advantage of the block and tackle?
Answer:
24
Explanation:
Given parameters:
Load = 7406N
Effort = 308.6N
Unknown:
The mechanical advantage of the block and tackle system = ?
Solution:
Mechanical advantage is the ability of a simple machine to amplify or increase the force needed to do work.
Mathematically;
M.A = Output force / Input force
Output force = Load
Input force = Effort
M.A = 7406N / 308.6N = 24
The mechanical advantage is 24
Explica la relación entre momento de torsión y aceleración angular mencionando tres ejemplos Una varilla uniforme delgada mide 1.5 m de longitud y tiene una masa de 6kg si la varilla se hace girar en un centro y se queda en rotación con una velocidad angular de 16 rad/seg calcular la cantidad de movimiento
Answer:
1) τ = I α whereby the torque is provided by the angular acceleration
2) L = 216 Kg m² / s
Explanation:
1) Let's start with Newton's second law
F = m a
multiply by the arm or perpendicular distance
F r = m a r
if the distance is not perpendicular a way of realizing the relations using the vector product
τ = F r = F x r
the bold are vectors. The angular and linear acceleration are related
a = α r=
τ = m (α r) r
τ = (m r²) α
the inertia of the rotational motion is
I = m r²
we substitute
τ = I α
whereby the torque is provided by the angular acceleration.
As an example we have:
* a spinning disk
* a ball rotating in the air
* a pulley
2) The rotational momentum is
L = I w
the moment of inertia of a rod that through its center
I = m L²
we substitute
L = m L² w
let's calculate
L = 6 1.5 2 16
L = 216 Kg m² / s
La cantidad de movimiento angular de la varilla uniforme es 18 kilogramos-metro cuadrado por segundo.
1) La relación entre el momento de torsión ([tex]M[/tex]), una variable cinética y relacionada con la aplicación de una fuerza externa cuya línea de proyección no cruza el centro de masa del objeto, y la aceleración angular ([tex]\alpha[/tex]), una variable cinemática, es la resistencia del cuerpo a rotar, la cual es función de su masa y su geometría, representada por la variable de momento de inercia.
A continuación, presentamos tres ejemplos del concepto:
Giro de una tuerca como consecuencia del giro de una llave inglesa por la acción de una mano y un brazo.Transmisión del movimiento a través de la transmisión de una bicicleta.Cierre de una compuerta mediante una transmisión rígida por engranes y un volante.2) Asumamos que la varilla uniforme es de masa constante, con una rotación a velocidad angular constante y con un centro de rotación localizado en el centro geométrico de la varilla. La cantidad de movimiento es expresada mediante la siguiente ecuación:
[tex]L = I\cdot \omega[/tex] (1)
Donde:
[tex]L[/tex] - Cantidad de movimiento angular, en kilogramos-metro cuadrado por segundo.[tex]I[/tex] - Momento de inercia, en kilogramos-metro cuadrado.[tex]\omega[/tex] - Rapidez angular, en radianes por segundo.El momento de inercia de una varilla uniforme con centro de rotación en el centro queda expresado por la siguiente fórmula:
[tex]I = \frac{1}{12}\cdot m\cdot L^{2}[/tex] (2)
Donde:
[tex]m[/tex] - Masa de la varilla, en kilogramos.[tex]L[/tex] - Longitud de la varilla, en metros.Al aplicar (2) en (1), tenemos la expresión resultante:
[tex]L = \frac{1}{12} \cdot m\cdot L^{2}\cdot \omega[/tex] (3)
Si sabemos que [tex]m = 6\,kg[/tex], [tex]L = 1.5\,m[/tex] y [tex]\omega = 16\,\frac{rad}{s}[/tex], entonces la cantidad de movimiento angular es:
[tex]L = \frac{1}{12}\cdot (6\,kg)\cdot (1.5\,m)^{2}\cdot \left(16\,\frac{rad}{s} \right)[/tex]
[tex]L = 18\,\frac{kg\cdot m^{2}}{s}[/tex]
La cantidad de movimiento angular de la varilla uniforme es 18 kilogramos-metro cuadrado por segundo.
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Circle the letter of each factor that determines whether a molecule
is polar or nonpolar.
a. the number of atoms in the molecule
b. the type of atoms in the molecule
c. the number of bonds in the molecule
d. the shape of the molecule
Why is physics worth knowing about
Answer:
Physics can help you in your everyday life.
Explanation:
It can also help you in life treating situations.
Unit 2 kinetic energy mastery test
Answer: kinetic energy is Energy of motion.
Explanation:
The diagram below shows the velocities of two runners.
11 m/s west
Runner 1
5 m/s east
Runner 2
From the frame of reference of runner 1, what is the velocity of runner 2?
O A. 5 m/s east
O B. 6 m/s east
C. 16 m/s west
O D. 16 m/s east
Answer : 16 m/s east
Explanation: Trust the process!!
From the frame of reference of runner 1, the velocity of runner 2 will be D) 16 m/s east
What is relative velocity ?
The relative velocity is defined as the velocity of an object with respect to another observer
When two bodies are moving in opposite directions , relative velocity get added and if bodies are moving in same direction , relative velocity will get subtracted .
From the frame of reference of runner 1, the velocity of runner 2 will be
v (relative) = v1 + v1
v1 = velocity of runner 1 = 11m/s west
v2 = velocity of runner 2 = 5m/s
v = 11 + 5 = 16 m/s
correct answer will be O D. 16 m/s east as runner 2 is running in east direction
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A. A land speed car can decelerate at 9.8m/s. How long does it take the car to come to a complete stop from a run of 885 km/hr (245.8 m/s)
TYPE ANSWER HERE
B. How far does the land speed car travel while stopping?
TYPE ANSWER HERE
C. What is the average acceleration of an object that reaches a speed of 600 m/s in a distance of 0.6 m?
TYPE ANSWER HERE
Answer:
A. 25.08 s
B. 3082.53 m
C. 3×10⁵ m/s²
Explanation:
A. Determination of the time.
This can be obtained as illustrated below:
Acceleration (a) = –9.8 m/s²
Initial velocity (u) = 245.8 m/s
Final velocity (v) = 0 m/s
Time (t) =.?
v = u + at
0 = 245.8 + (–9.8 × t)
0 = 245.8 – 9.8t
Collect like terms
0 – 245.8 = – 9.8t
– 245.8 = – 9.8t
Divide both side by –9.8
t = –245.8 / –9.8
t = 25.08 s
Therefore, it will take 25.08 s for the car to come to a complete stop.
B. Determination of the distance travelled by the car.
Acceleration (a) = –9.8 m/s²
Initial velocity (u) = 245.8 m/s
Final velocity (v) = 0 m/s
Distance (s) =?
v² = u² + 2as
0² = 245.8² + (2 × –9.8 × s)
0 = 60417.64 – 19.6s
Collect like terms
0 – 60417.64 = – 19.6s
– 60417.64 = – 19.6s
Divide both side by –19.6
s = –60417.64 / –19.6
s = 3082.53 m
Thus, the car travelled a distance of 3082.53 m before stopping completely.
C. Determination of the acceleration of the object.
Initial velocity (u) = 0 m/s
Final velocity (v) = 600 m/s
Distance (s) = 0.6 m
Acceleration (a) =?
v² = u² + 2as
600² = 0² + (2 × a × 0.6)
360000 = 0 + 1.2a
360000 = 1.2a
Divide both side by 1.2
a = 360000 / 1.2
a = 300000 = 3×10⁵ m/s²
What is the weight, on Earth, of a book with a mans of 1.5 kg?
15N
66N
11 3N
14,7N
A man is trying to push a 250 N dresser across his carpeted bedroom. He applies a force of 20 N and the carpet provides a frictional force of 8N. Which vectors represented in the diagram below will you need to consider and what will be the resulting net force?
Answer:
The correct option is;
B. Subtract vectors A from C; [tex]F_{Net}[/tex] = 12 N
Explanation:
The given parameters are;
The weight of the dresser = 250 N
The force applied by the man = 20 N = C
The frictional force provided by the carpet = 8 N = The component of the weight resisting motion = A
Therefore, the net force tending to put the dresser in motion, [tex]F_{Net}[/tex], is given as follows;
[tex]F_{Net}[/tex] = The force applied by the man, C - The frictional force provided by the carpet which is the component of the weight resisting motion, A
[tex]F_{Net}[/tex] = C - A = 20 N - 8 N = 12 N
[tex]F_{Net}[/tex] = 12 N
The resulting net force, [tex]F_{Net}[/tex] = 12 N.
The resultant force can be obtained by subtracting vector C from Vector A and the value of net force is 12 N. Hence, option (C) is correct.
Given data:
The weight of man is, W = 250 N.
The magnitude of applied force is, F = 20 N.
The magnitude of frictional force is, f = 8 N.
As per the given problem and the diagram let the applied force be denoted by vector A, Then,
Magnitude of Vector A = 20 N
And the frictional force be denoted by vector C. Then,
Magnitude of Vector C = 8 N
We know that the role of frictional force is to oppose the motion or to oppose the effect of applied force. Then the resultant force is given as,
[tex]F_{net} = F-f\\\\F_{net} = 20 - 8\\\\F_{net} = 12 \;\rm N[/tex]
Thus, we can conclude that the resultant force can be obtained by subtracting vector C from Vector A and the value of net force is 12 N. Hence, option (C) is correct.
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n
Which of the following has a crystalline appearance?
baking soda
salt
baking powder
corn starch
Answer:
B: Salt
Explanation:
I answered this correct beforehand.
Write an equation of the line in slope-intercept form.
Please explain.
Answer:
y = [tex]-\frac{1}{4}[/tex]x + 3
Explanation:
The equation of a straight line is given as:
y = mx + c
y and x are the coordinates
m is the slope
c is the y -intercept
The y-intercept = 3;
Slope = [tex]\frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex]
x₁ = 0
x₂ = 4
y₁ = 3
y₂ = 2
Slope = [tex]\frac{2-3}{4 -0 }[/tex] = [tex]-\frac{1}{4}[/tex]
y = mx + c
y = [tex]-\frac{1}{4}[/tex]x + 3
What happens to the gravitational force between two objects as the bodies become closer to each other? A. The gravitational force begins to repel the objects. B. The gravitational force increases. C. The gravitational force decreases. D. The gravitational force stays the same.
Answer:
Explanation:
The gravitational force between two objects becomes weaker if the two objects are moved apart and stronger if they are brought closer together; that is, the force depends on the distance between the objects.
The gravitational force between two objects as the bodies become closer to each other increases.
Gravitational force is force of attraction between two masses. Gravitational force(F) between two bodies is directly proportion to the product of masses(m₁,m₂) of two bodies and inversely proportional to square of distance(r) between them. mathematically it is written as,
F ∝ m₁.m₂
F ∝ 1/r²
F = G m₁,m₂÷r²
where G is gravitational constant, whose value is 6.6743 × 10⁻¹¹ m³ kg-1s⁻².
Force is expressed in Newton N in SI unit. its dimensions are [M¹L¹T⁻²].
As distance decreases the Force increases
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what is the spring constant for a spring if pulling it back .0391m causes a force in the opposite direction of .922N?
-0.361N
.361N
-2.36N
2.36N
Answer: correct me if i'm wrong but is it 0.361N