WHICH SERIES OF TRANSFORMATIONS CAN BE USED TO SHOW THAT ABC~DEF?

WHICH SERIES OF TRANSFORMATIONS CAN BE USED TO SHOW THAT ABC~DEF?

Answers

Answer 1

Answer:

A) is correct

Step-by-step explanation:


Related Questions

A decreased by 20% and then increased by 20% express using algebra
asapppppp

Answers

Answer:

96%

Step-by-step explanation:

assume the whole number is x

the first thing is decreasing by 20 %

x - 20%x = 80% x

then now the 80%x is the whole number  

now It's the turn of increasing

80%x + 20% * (80% x) = 80%x + 16%x = 96% x

I hope this is hlepful to you !!!!

Feel free to ask me in the comments

Tell whether the ordered pair is a solution to the system of linear equations. 1 point
(-4,-2);
y = 2.c + 6
y = -32 – 14
Yes
No
O Maybe

Answers

Answer:

Yes

(-4,-2) is a solution of a given system of equation

Step-by-step explanation:

Explanation:-

Given that the equation

                y = 2 x + 6 ..(i)

Given point (-4,-2)

substitute   x =-4 and y = -2 in equation (i)

             -2 =2(-4) +6

            -2  = -8+6

           -2 =-2

∴ The point satisfies the given equation

     

The spinner is divided into 4 equal parts: yellow (Y), green, (G), blue (B) and red (R). Dorian says that if you spin the spinner twice, then there are exactly 12 possible outcomes. he lists the outcomes in a table. Which statement explains Dorian’s mistake?

Answers

Answer:

The spinner can land on the same color twice in a row, so there should be 16 possible outcomes

Step-by-step explanation:

4 possible outcomes with the same color

RR, OO, GG and BB.

Total Ways = 12+4=16

Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. They randomly survey 391 drivers and find that 319 claim to always buckle up. Construct a 85% confidence interval for the population proportion that claim to always buckle up.

Answers

Answer:

The 85% confidence interval for the population proportion that claim to always buckle up is (0.7877, 0.8441).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

They randomly survey 391 drivers and find that 319 claim to always buckle up.

This means that [tex]n = 391, \pi = \frac{319}{391} = 0.8159[/tex]

85% confidence level

So [tex]\alpha = 0.15[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.15}{2} = 0.925[/tex], so [tex]Z = 1.44[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8159 - 1.44\sqrt{\frac{0.8159*0.1841}{391}} = 0.7877[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8159 + 1.44\sqrt{\frac{0.8159*0.1841}{391}} = 0.8441[/tex]

The 85% confidence interval for the population proportion that claim to always buckle up is (0.7877, 0.8441).

Which graph shows u + v for the given vectors u and v?

Answers

Answer:

The answer is A

Step-by-step explanation:

When you move v's tail to u's head, you see that the vectors align up.

The graph shows (u + v) for the given vectors u and v will be Graph A.

What is vector ?

A vector is an object that has both a magnitude and a direction. Magnitude defines the size of the vector. It is represented by a line with an arrow, where the length of the line is the magnitude of the vector and the arrow shows the direction.

We have,

Four graphs and we have to tell which is the correct graph for (u + v).

So,

To add two vectors, add the corresponding components.

i.e. The sum of u and v  vector = ( u₁ + v₁, u₂ + v₂)

i.e.

Let u = (u₁, u₂)  and

v = (v₁, v₂)

Now,

(u + v) = ( u₁ + v₁, u₂ + v₂)

So,

From Graph A,

We have,

u = (1, 4) and v = (2, -2)

i.e.

u₁ = 1,

u₂ = 4,

v₁ = 2,

v₂ = -2

So,

Using the addition method of vector,

i.e.

(u + v) = ( u₁ + v₁, u₂ + v₂)

Substituting values,

(u + v) = [( 1 + 2), (4 + (-2))]

We get,

(u + v) = (3, 2)

So,

The graph A represents the correct points of (u +v).

Hence, we can say that the graph shows (u + v) for the given vectors u and v will be Graph A.

To know more about vectors click here

https://brainly.com/question/24256726

#SPJ2

PLEASE HELP I AM STUCK

Answers

Answer:

Do the pythagor theorem and add 5

It's 65

Plz helpppp!!!!! Much love

Answers

Answer:

B.

Step-by-step explanation:

16 divided by 25 as a decimal

Answers

Answer:

The answer of the question is 0.64

Answer:

0.64 is a decimal and 64/100 or 64% is the percentage for 16/25.

Step-by-step explanation:

It will take you to how you do it scan on phone

1. Socks are on sale at 10% discount. What is the sale price of a pair of socks originally
marked #125.00?​

Answers

Answer:

10/100 = x/125

1250 = 100x

1250/100 = 100x/100

12.5 = x

125 - 12.5 = 112.5

the sale price is $112.5


[tex]obtain the fourier expansion for sin ax in the interval - | \leqslant \times \leqslant | [/tex]

Answers

I really do not get it . It’s this a question ? If so can you be a little more specific .

48/96 in its simplest form

Answers

Answer:

1/2

Step-by-step explanation:

just divide it I guess

1/2

48/2

=24/2

=12/2

=6/2

=3

Hope this helps :D

According to an AP-Ipsos poll (June 15, 2005), 42% of 1001 randomly selected adult Americans made plans in May 2005 based on a weather report that turned out to be wrong.

a. Construct and interpret a 99% confidence interval for the proportion of Americans who made plans in May 2005 based on an incorrect weather report.
b. Do you think it is reasonable to generalize this estimate to other months of the year

Answers

Answer:

a) The 99% confidence interval for the proportion of Americans who made plans in May 2005 based on an incorrect weather report is (0.3798,0.4602). This means that we are 99% sure that the true population proportion is in this interval.

b) No, since May is a month with a wide range of possible weather.

Step-by-step explanation:

a)

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

42% of 1001 randomly selected adult Americans made plans in May 2005 based on a weather report that turned out to be wrong.

This means that [tex]p = 0.42, n = 1001[/tex]

99% confidence level

So [tex]\alpha = 0.01[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.575[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 2.575\sqrt{\frac{0.42*0.58}{1001}} = 0.3798[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 + 2.575\sqrt{\frac{0.42*0.58}{1001}} = 0.4602[/tex]

The 99% confidence interval for the proportion of Americans who made plans in May 2005 based on an incorrect weather report is (0.3798,0.4602). This means that we are 99% sure that the true population proportion is in this interval.

b. Do you think it is reasonable to generalize this estimate to other months of the year

No, since May is a month with a vast number of possible outcomes, as it is in the spring, not being in the winter(cold) or summer(hot), which means that it can be both hot or cold, wet or dry,...

The wall street journal corporate perceptions study 2011 surveyed readers and asked how each rated the quality of management and the reputation of the company for over 250 worldwide corporations. Both the quality of mangement and the reputation of the company were rated on an excellent, good, and fair catergorical scale. Assume sample data for 200 respondents below.
Reputation of Company
Quality of management Excellent Good Fair
Excellent 40 25 5
Good 35 35 10
Fair 25 10 15
A) use a .05 level of significance and test for independence of the quality of management and the reputation of the company. What is the p-value and what is your conculsion??
B) If there is a dependence or association between the two ratings, discuss and use the probabilities to justify your answer.

Answers

Answer:

Hello some parts of your question is missing below is the missing part

answer : A) p-value =  0.0019 ,

The level of significance ( 0.05 ) > p-value ( 0.0019 )

B) There is no dependence between the two ratings

Step-by-step explanation:

A) using a 0.05 level of significance and test for independence of the quality of management

Test statistic : [tex]X^{2}[/tex]  ∑ ( Oi - Ei )^2 / Ei

= [(40-35)^2 / 35 ] +  [(25-24.5)^2 / 24.5 ] +  [(5-10.5)^2 / 10.5]  +  [(35-40)^2 / 40]  +  [(35-28)^2 / 28]  +  [(10-12)^2 / 12]  +   [ (25-25)^2 / 25 ]  +  [(10-17.5)^2 / 17.5 ]  + [(15-7.5)^2 / 7.5]  =  17.03  

p-value = 0.0019

Df = 4  ,

The level of significance ( 0.05 ) > p-value ( 0.0019 )

B) There is no dependence between the two ratings

I need help on this and pls I actually do so dont put wrong answers or that you need points pls dont :)

Answers

Answer:

Equation: 120=66+2m

Step-by-step explanation:

120=66+2m

120-66=54

54/2=27

m=27

Word problem please help thank you

Answers

Answer:

The equation would be           P(t) = 280t + 3310              

The estimated number of moose in 2008 would be 8350 moose.

Step-by-step explanation:

First we will have to find out by how much will the number of moose increase each year. In order to do that we the number by which the population of moose increase, by the difference between 1991 and 1999. And so we get...

[tex]\frac{5830-3590 }{1999 - 1991} = \frac{2240}{8} = 280[/tex]

Now that we know by how much the number of moose increases each year, we can make the following equation...

Let "t" be the number of years from 1990, then...

P(t) = 280t + 3310

(if you are wondering why is it 3310, it is because you have to put in the number of moose that was there in 1990 and you can get that number by substracting 280 from the number of moose in 1991).

Based on the linear relation we figured out, the number of moose in 2008 would be predicted to be...

P(t) = 280t + 3310

P(2008 - 1990) = 280(2008 - 1990) + 3310

P (18) = 280(18) + 3310

P(18) = 8350

las alturas medidas en centimetros de 15 niños de una primaria fueron las siguientes 145,135,150,144,137,152,139,146,140,149,148,135,143,151,135¿cual es el promedio,mediana y moda?​

Answers

Answer:

145

Step-by-step explanation:

145 135 123 134 456 teukr68l67ewi6e5iu

Mr. Griggs took his two daughters to the movies to see Frozen 2. He paid 19 dollars in all for the tickets. An adult ticket costs 9 dollars. Write and solve an equation to find how much each child ticket cost.

Answers

Answer:

19 - 9 = 2x

$5 per child ticket

Step-by-step explanation:

19 - 9 = 2x

10 = 2x

10 ÷ 2

X= 5

$5 per child ticket

On one day, 4 chefs and 5 helpers earned $650.

On another day working the same number of hours
at the same rate of pay, 5 chefs and 6 helpers
earned $800.

How much does a chef earn each
day?

Answers

4c + 5h = 650 and

5c + 6h = 800 where c are chefs, h are helpers

Start by finding an expression for c

4c + 5h = 650
4c = 650 -5h
c = (650- 5h)/4

Then substitute that into the second equation and solve for a number value for h
5 (650-5h)/4 + 6h = 800
(3250-25h)/4 + 6h = 800
Multiply both sides by 4
3250-25h + 24h = 3200
-h = -50
h = 50

Take that 50 and substitute it into the expression we have for c to get a number value for c

C= 650-5(50)/4
C = 650-250/4
C = 400/4
C= 100

Check your first equations, substituting $50 for the helpers and $100 for the chefs.

4 (100) + 5(50) =
400 + 250 = 650

5(100) + 6(50) =
500 + 300 = 800

Your firm has developed a new product aimed at the European and Asian markets. For each of these two markets, you have identified two possible sales scenarios, called "good" and "bad", with the following probabilities:
Europe Good Europe Bad
Asia Good 0.55 0.15
Asia Bad 0.20 0.10
That is, there is a 55% chance the products sales will be good in Asia and Europe, a 15% chance they will be good in Asia but bad in Europe, and so forth.
You have four possible courses of action:
• Introduce the product simultaneously in Europe and Asia.
• Introduce it in Asia first. After it becomes apparent whether sales are good or bad, decide whether to introduce it in Europe, one year later.
• Introduce it in Europe first. After it becomes apparent whether sales are good or bad, decide whether to introduce it in Asia, one year later.
• Abandon the product.
The NPV's of the various scenarios are as follows, in millions of US dollas
Immediate Introduction After one year
Good Bad Good Bad
Asia 120 -205 +117 -205
Europe +105 -200 +102 -200
For example, "good" sales in Asia mean an NPV of S120 million if the product is introduced in this year, and S117 mlo i the product is introduced next year. In either year, "bad" sales mean an NPV of-$205 ml The information for Europe should be interpreted similarly
A) Calculate:
1) The probability of good sales in Asia The probability of good sales in Europe.
2) The probability of good sales in Asia, given that good sales are observed in Europe.
3) The probability of good sales in Asia, given that bad sales are observed in Europe.
4) The probability of good sales in Europe, given that good sales are observed in Asia.
5) The probability of good sales in Europe, given that bad sales are observed in Asia.
B) Use a decision tree to determine the best introduction strategy for the product from the standpoint of EMV. State the optimal policy and its EMV.

Answers

Solution :

1. [tex]$P(\text{ good sales in Asia }) = 0.55+0.15$[/tex]

                                     = 0.7

2. [tex]$P(\text{ good sales in Europe }) = 0.55+0.20$[/tex]

                                     = 0.75

3. [tex]$\text{P(good sales in Asia }| \text{ good sales in Europe}) $[/tex][tex]$=\frac{\text{P (good sales in Asia and good sales in Europe)}}{\text{P( good sales in Europe)}}$[/tex]

                                         [tex]$=\frac{0.55}{0.75}$[/tex]

                                          [tex]$=\frac{11}{15}$[/tex]

4. [tex]$\text{P(good sales in Asia }| \text{ bad sales in Europe}) $[/tex]

  [tex]$=\frac{\text{P (good sales in Asia and bad sales in Europe)}}{\text{P( bad sales in Europe)}}$[/tex]

  [tex]$=\frac{0.15}{0.25}$[/tex]

  [tex]$=0.6$[/tex]

5. [tex]$\text{P(good sales in Europe }| \text{ good sales in Asia}) $[/tex]

   [tex]$=\frac{\text{P (good sales in Asia and good sales in Europe)}}{\text{P( good sales in Asia)}}$[/tex]

   [tex]$=\frac{0.55}{0.7}$[/tex]

  [tex]$=\frac{11}{14}$[/tex]

6.  [tex]$\text{P(good sales in Europe }| \text{ bad sales in Asia}) $[/tex]

     [tex]$=\frac{0.2}{0.3}$[/tex]

     [tex]$=\frac{2}{3}$[/tex]                              

Tina found $4.75 at the bottom of her purse and added it to her wallet. She later bought milk and eggs for $6,55 and had
$5.43 left in her wallet
Tina wants to know how much money she had in her wallet before adding the amount she found in her purse (%). Choose ALL
equations in which x correctly represents the amount in her wallet before adding the amount she found,
A)
$6,55 - x + $4.75 - $5.43
B)
x + $4.75 - $6,55 - $5.43
C)
$5.43 -
$6.55 - $1.75 -
Eliminate
D)
$4.75 - $6.55 - $5.43 - X
E)
$5,43 - x + $4.75 - $6.55

Answers

Step-by-step explanation:

step 1. x + 4.75 - 6.55 = 5.43

step 2. looks like b is the only answer.

Answer:

i need help wit this

Step-by-step explanation:

b. Solve for x, given the
MZ2 = 9x + 6

Answers

Answer:

Step-by-step explanation:

hello :

9x+6 =60

9x+6-60 =60-60

9x -54 =0

9x -54+54 =+54

9x=54

x = 54/9

x= 6°

What 5 divided by 4.25.

Answers

Answer:

Step-by-step explanation:

5 divided by 4.25 =  85 reminder 0

(a) Calculate the mean, median, and mode of the data.
If your answer is not a whole number, enter it as number rounded to the nearest integer.
Mean =
60
Median =
60
Mode = 61
(b) What measure of central tendency, if any, best represents the data?
Mean
Median
Mode
All three represent the data equally well

Answers

Answer:

Step-by-step explanation:

what you see mode mean median;what i see the moleecur stricture of 4dsn_eix+dwk x sjsw39i4

I think it would be mean as it gives you the average answer, most likely being the most accurate.

please help with question ​

Answers

Answer:

70

Step-by-step explanation:

180 - (90) - (20)

90 - 20

70

70 because 90-20 so that will equal 70

Help
Please ..................

Answers

Plug in -11 for x
8(-11) + 2.
-86

Answer:

-86

Step-by-step explanation:

Substitute -11 for x in the equation:

8(-11)+2

=-88+2

=-86

The ratio of the three angles of a triangle is 2:4:6. What is the measure of the
SMALLEST angle?

Answers

The measures of the angles are 30, 60 and 90 degrees.
Explanation:
I assume the question should read "the measures of the ANGLES of the triangle are in the ratio 2:4:6.
If the angles are in the proportion 2:4:6, the measures of the angles have the same scale factor
x
. And, the sum of the measures of the angles of a triangle is
180
.

2
x
+
4
x
+
6
x
=
180

12
x
=
180

12
x
12
=
180
12

x
=
15

The measures of the angles are:
2
x
=
2
(
15
)
=
30

4
x
=
4
(
15
)
=
60

6
x
=
6
(
15
)
=
90

GrumpyCorp drug tests all of the recent college graduates it hires each year. The drug test currently used correctly determines drug users 96% of the time(a Positive test) and correctly determines non-users 90% of the time(a Negative test). A recent study concluded that 36% of college students use drugs. A potential employee has been tested and the result was Negative for drug use.
a) Construct ALL necessary probabilities using proper notation(Example: P(D) for a "drug user"). (Hint: there should be 6 total)
b) Find the Probability of a Negative test, by showing use of the above Probabilities first, and then followed by the proper calculation.
c) Use Bayes' Theorem to find the probability that a person who tests Positive actually was not a Drug User. Set up using Conditional Probability Notation and then substitute in numeric values.

Answers

Solution :

Drug : Drug user

T : Test positive

a). [tex]P(D) =0.36[/tex]

    [tex]$P\left(\frac{T}{D} \right) = 0.96$[/tex]

    [tex]$P\left(\frac{T^c}{D^c} \right) = 0.90$[/tex]

b). [tex]$P(T^c)= P\left(\frac{T^c}{D^c}\right) \times P(D^c)+ P\left(\frac{T^c}{D}\right) \times P(D)$[/tex]

               [tex]$=0.9 \times (1-0.36) + (1-0.96) \times 0.36$[/tex]

               = 0.5904

c). [tex]$P\left(\frac{D^c}{T}\right) = \frac{P\left(\frac{T}{D^c}\right). P(D^c)}{P\left(\frac{T}{D^c}\right). P(D^c) + P\left(\frac{T}{D}\right). P(D)}$[/tex]

                  [tex]$=\frac{(1-0.90) \times (1-0.36)}{(1-0.90) \times (1-0.36)+(0.96 \times 0.36)}$[/tex]

                 [tex]$=0.15625$[/tex]

Find the perimeter P of
JKLM
with vertices J(-3,-2),K(-5,-5),L(1.-5),M(3.-2) Round your answer to the nearest tenth

Answers

Yes just round it to two decimal then multiply to three then you’ll get ur answer. Simple.

Which function family should be used to solve the following question?
A team of scientists is studying the rate of growth of bacteria in a lab. It is found that the number of bacteria colis triplos overy
hour. If there are 6 bacteria at the beginning of the study, how many bacteria will be present after 7 hours?
A. Linear Function Family
OB. Quadratic Function Family
OC. Exponential Function Family
OD. Absolute Value Function Family

Answers

Answer:

I think d is the answer

1. 25% of 300
2. 20% of what number is 50?
3. What percent of 120 is 40?
4. If 20% of 60 is 12. Which represent the percentage?
5. Which represent the base?​

Answers

Answer:

rawrrrrrr

Step-by-step explanation:

rawrrrrrrrrrrrrrrrr

1. 75
2. 250
3. 33.33
4. 20% I think?
5. I’m not sure
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