The ratio of the mass of oxygen inhaled for each breath at high altitude and at sea level is 0.629.
Let the mass of oxygen inhaled at sea level, = m₀
Let the mass of oxygen inhaled at 15000 ft, = m₁₅
The volume of air inhaled is same for both case, = v
Density of the air at mean seal level, ρ₀ = 2.337 × 10⁻³ sl/m³
Density of the air at 15000 ft, ρ₁₅ = 1.469 × 10⁻³ sl/m³
m₀ = ρ₀V, m₁₅ = ρ₁₅V
m₁₅/m₀ = ρ₁₅V/ρ₀V
m₁₅/m₀ = (1.469 × 10⁻³)/(2.337 × 10⁻³)
m₁₅/m₀ = 0.629
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Why is B the correct answer? Thanks :)
The final speed is v and the change in the total kinetic energy is 6mv² (Option B)
How do I determine the final velocity?The final speed after the collision can be obtained as illustrated below:
Mass of 1st object (m₁) = 2mspeed of 1st object (u₁) = 3vMass of 2nd object (m₂) = 4mspeed of 2nd object (u₂) = 0Final speed (v₀) = ?Momentum before = momentum after
m₁u₁ + m₂u₂ = v₀(m₁ + m₂)
Divide both sides by (m₁ + m₂)
v₀ = [m₁u₁ + m₂u₂] / (m₁ + m₂)
v₀ = [(2m × 3v) + (4m × 0)] / (2m + 4m)
v₀ = [6mv + 0] / 6m
v₀ = 6mv / 6m
v₀ = v
Thus, the final speed is v
How do I determine the change in the kinetic energy?First, we shall determine the total initial kinetic energy. Details below:
Mass of 1st object (m₁) = 2mspeed of 1st object (u₁) = 3vMass of 2nd object (m₂) = 4mspeed of 2nd object (u₂) = 0Total Initial Kinetic energy (KE₁) =?KE₁ = ½m₁u₁² + ½m₂u₂²
KE₁ = [½ × 2m × (3v)²] + [½ × 2m × 0²]
KE₁ = [m × 9v²] + 0
KE₁ = 9mv²
Next, we shall determine the total final kinetic energy. Details below:
Total mass (m) = 2m + 4m = 6mFinal speed (v₀) = vTotal final Kinetic energy (KE₂) =?KE₂ = ½mv²
KE₂ = ½ × 6m × v²
KE₂ = 3mv²
Finally, we shall determine the change in the kinetic energy of the car can be obtained as follow:
Total Initial Kinetic energy (KE₁) = 9mv²
Total final Kinetic energy (KE₂) = 3mv²
Change in total kinetic energy (ΔKE) =?
ΔKE =KE₁ - KE₂
ΔKE = 9mv² - 3mv²
ΔKE = 6mv²
In conclusion,
Final speed = vChange in total kinetic energy = 6mv²Thus, the correct answer is Option B
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consider the following observations. classify each observation based on whether it is a real observation (a true statement of something we can actually see from earth) or one that is not real (a statement of something that does not really occur as seen from earth). view available hint(s)for part a
Real: True statements
Mercury undergoes a complete cycle of phases.Daily moon rises in the east and sets in the west.Stars circle daily around north or south celestial poleEach year, neighbouring stars' positions gradually oscillate back and forth.A distance galaxy rises in east, sets in west each dayNot real: False statements:
We sometimes see a crescent JupiterBeyond Saturn, a planet rises in the west and sets in the eastEarth observation is the gathering of information on the physical, chemical, and biological processes occurring on planet Earth using remote sensing technology, often via satellites carrying imaging equipment. Earth observation is used to monitor and assess environmental changes, both natural and man-made, as well as their state.
Seismic and Global Positioning System (GPS) stations, as well as floatable buoys for monitoring ocean currents, temperature, and salinity, are some of the techniques used today for Earth observation. Air quality and rainfall patterns are also recorded by land-based stations. Space-based technologies provide repeatable datasets that provide a unique opportunity to gather data about the world when combined with appropriate technique development and analysis.
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Following question may be like this:
Consider the following observations. Classify each observation based on whether it is a real observation (a true statement of something we can actually see from Earth) or one that is not real (a statement of something that does not really occur as seen from Earth).
- Mercury goes through a full cycle of phases
- Moon rises in east, sets in west each day
- stars circle daily around north or south celestial pole
- positions of nearby stars shift slightly back and forth each year
- a distance galaxy rises in east, sets in west each day
- we sometimes see a crescent Jupiter
- a planet beyond Saturn rises in west, sets in east
the apparatus above is used to study conservation of mechanical energy. a spring of force constant 40 n/m is held horizontal over a horizontal air track, with one end attached to the air track. a light string is attached to the other end of the spring and connects it to a glider of mass m . the glider is pulled to stretch the spring an amount x from equilibrium and then released. before reaching the photogate, the glider attains its maximum speed and the string becomes slack. the photogate measures the time t that it takes the small block on top of the glider to pass through. information about the distance x and the speed v of the glider as it passes through the photogate are given below.
The reason for the modest preference for 1/2 kx2 is that you only need to measure one variable—the displacement x—in order to identify the stored energy. Utilizing 1/2 F/x necessitates measuring both displacement and force, which is frequently difficult to do.
Do kinetic and potential energy in a spring have the same value?When a spring is stretched x distances from its equilibrium point and its mass is moving with velocity v, the spring's kinetic energy and elastic potential energy are equal, or 1/2mv2 = 1/2kx2.The restoring force indicated by Hooke's Law is propelled by spring potential energy, a store of energy. When calculating the spring potential energy, U=1/2kx2—the equation for the potential energy function—instead of Hooke's Law—is essentially utilized.The reason for the modest preference for 1/2 kx2 is that you only need to measure one variable—the displacement x—in order to identify the stored energy. Utilizing 1/2 F/x necessitates measuring both displacement and force, which is frequently difficult to do.To learn more about displacement refer to:
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A body of mass 50 kg explodes and splits into three pieces. The first piece has a mass of 10 kg and a velocity of [-3,2] m/s, the second piece has a mass of 18 kg and a velocity of [5, -4] m/s. What is the velocity of the third piece?
.
The velocity of the third piece 2/11. (13 j - 15i)
What is velocity?Velocity is the directional velocity of a moving object as an indicator of the rate of change of position observed from a particular frame of reference and measured by a particular time standard.Velocity is a vector representation of the displacement an object or particle experiences with respect to time. The standard unit for velocity magnitude (also called velocity) is meters per second (m/s). Alternatively, centimeters per second (cm/s) can be used to express velocity magnitude.Simply put, velocity is the speed at which something moves in a particular direction. For example, the speed of a car traveling north on a highway, or the speed of a rocket after launch.To learn more about velocity from the given link:
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two objects with different masses collide with and stick to each other on a frictionless surface. compared to before the collision, the system of two objects after the collision has A. the same amount of total momentum and the same total kinetic energy.
B. the same amount of total momentum but less total kinetic energy.
C. less total momentum but the same amount of total kinetic energy.
D. less total momentum and less total kinetic energy.
E. Not enough information is given to decide.
After colliding, the two objects come to rest together, preserving momentum but not kinetic energy. Some motion energy is transformed to thermal energy, or heat.
What is collision?A collision occurs in physics when particles, groupings of particles, or solid entities move toward one other and get close enough to interact and exert mutual effect. When two bodies come into direct touch with each other, this is referred to as a collision. The two bodies exert pressures on each other in this situation in a brief period of time. As a result of the collision, the energy and momentum of the bodies involved change. However, there are three types of collisions: elastic, inelastic, and absolutely inelastic. To summarize, momentum is preserved in all three types of collisions. What happens to the kinetic energy is what characterizes the impacts.
Here,
The two objects collide and come to rest together, retaining velocity but not kinetic energy. Some motion energy is converted to thermal energy, often known as heat.
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A helicopter flies horizontally at a contant speed. This makes a 42500 N lift force at 78.3 degrees, and air resistance pushes back against it. What is the mass of the helicopter?
In order to calculate the mass of the helicopter, we must first calculate the force of the air resistance.
What is the mass of the helicopter?The mass of the helicopter can be calculated using the formula:
mass = lift force / (acceleration due to gravity x sin(angle of lift force))
mass = 42500 N / (9.81 m/s2 x sin(78.3°))
mass = 4289 kg.
The force of the air resistance is equal to the magnitude of the lift force multiplied by the sine of the angle of the lift force, which in this case is 42500N x sin(78.3°) = 39,941N. Now, since the lift force and the air resistance are equal and opposite, we can use Newton's second law of motion, F=ma, to calculate the mass of the helicopter.Thus, the mass of the helicopter is equal to the force of the air resistance divided by the acceleration of the helicopter, which is zero since it is moving at a constant speed.Therefore, the mass of the helicopter is 39,941N/0m/s2 = 39,941kg.The mass of the helicopter can be calculated using the principles of Newton's Second Law of Motion. According to this law, the force acting on an object is equal to its mass times its acceleration. Therefore, the mass of the helicopter can be calculated using the equation:m = F / a
where F is the lift force and a is the acceleration due to gravity (9.81 m/s^2).
Plugging in the given values, the mass of the helicopter can be calculated as:
m = 42500 N / (9.81 m/s^2)
m = 4317.3 kg
This theory is known as Newton's Second Law of Motion, which states that the net force on an object is equal to its mass times its acceleration. This law can be used to calculate the mass of the helicopter when the lift force and acceleration due to gravity are known.To learn more about Newton's Second Law of Motion refer to:
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Which of the following will have the highest surface tension?
A
Water
B
Ethanol
C
Methanol
D
Ethanal
Water has the highest surface tension than ethanol, methanol, or ethanal.
The cohesive nature of a liquid's molecules gives rise to a property of the liquid's surface known as surface tension, which enables the liquid to resist the action of an outside force. After mercury, water has the highest surface tension of any liquid. This is because hydrogen bonds are present in water molecules, which gives water its high surface tension. As a result of water's surface tension, water molecules that are in close proximity to one another at the liquid's surface (where they are in contact with air) stick together to form an invisible film. When water is heated to 25 degrees Celsius, its surface tension is 72 dynes/cm. To crack a film of water on the surface that is one centimeter long and requires 72 dynes of force.
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explain how a paradox work∞
Answer:
A paradox is a statement, proposition, or situation that seems illogical, absurd or self-contradictory, but which, upon further scrutiny, may be logical or true — or at least contain an element of truth. Paradoxes often express ironies and incongruities and attempt to reconcile seemingly opposing ideas.
Explanation:
hope this help :)
fill in the blank. since parallax is a difference in the apparent position of an object viewed along two different lines of sight, a very blank distance between viewpoints (called the baseline) is required to see a parallax shift in a distant object.target 1 of 2 if the baseline is too___compared to the object's distance, the difference in perspective will not be____
Since parallax is a difference inside this apparent position of an item when viewed along two separate lines of sight, a very wide gap between perspectives (referred to as the baseline) is necessary to detect a parallax shift in a far-off object.
What does parallax shift mean?An object's position changing due to your motion is known as parallax. For instance, if you gaze at a close object and tilt your head slightly to the side, the thing appears to be moving back and forth.
We employ parallax because?One of the most crucial techniques astronomers use to determine distance is parallax. It is incredibly precise but can only be used for close stars. By calculating how close an object is, the technique appears to move against the background of more distant objects.
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A proton is fired horizontally into a 1.0×10^5 N/C vertical electric field. It rises 1.0 cm vertically after having traveled 7.0 cm horizontally. What was the proton's initial speed?
The initial horizontal speed of the proton is 0.16 m/s.
What is the time of motion of the proton?
The time of motion of the proton is calculated by applying the following kinematic equation.
t = √ ( 2gh )
where;
h is the height risen by the protong is the acceleration due to gravityt = √ ( 2 x 9.8 x 0.01 )
t = 0.44 second
The initial horizontal speed of the proton is calculated as;
d = Vₓt
Vₓ = d / t
Vₓ = ( 0.07 m ) / ( 0.44 s )
Vₓ = 0.16 m/s
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which of the following is the best way driver/operators can prevent the aerial device from moving or chattering along a frozen solid surface on an angle? group of answer choices using wheel chocks deploying manual stabilizers positioning the apparatus laterally positioning the apparatus longitudinally
Using wheel clocks is the best option.
To stop an aerial device from moving or chattering on an angled frozen solid surface, wheel chocks are intended to be installed in front of and behind the wheels of the aerial device. The aerial equipment can't move or chatter since the chocks mechanically stop the wheels from rotating. Additionally, they can be utilised to keep the apparatus stable on the surface by adding an additional layer of friction between the ground and the object. Wheel chocks are an efficient way to stop aerial equipment from shifting or chattering on an angled frozen solid surface when used in conjunction with hand stabilisers.
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find an expression for the oscillation frequency of an elec tric dipole of dipole moment 17 and rotational inertia i for small amplitudes of oscillation about its equilibrium position in a uni form electric field of magnitude e.
The frequency would be 1/2pi [tex]\sqrt{\frac{pE}{I}}[/tex].
We know that,
Tau=-pEsinФ captures the sense
and the size of the effect.
This is the restoring torque to return the tilted dipoles to their aligned equilibrium position.
If the amplitude of movement is small,
we may replace sinθ with θ in radians.
Thus τ≈−pEθ.
Since this has a simple negative proportionality to the angle of rotation, the dipole oscillates in a simple harmonic motion,
like a torsion pendulum with a torsion constant
κ=pE. In this case, angular frequency ω is given by
ω² = [tex]\frac{k}{I}[/tex] = [tex]\frac{pE}{I}[/tex]
where I denotes thee rotational inertia of the particular dipole. The frequency of oscillation is
f= ω/ 2pi
= 1/2pi [tex]\sqrt{\frac{pE}{I}}[/tex]
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according to a newspaper account, a paratrooper survived a training jump from 1156 ft when his parachute failed to open but provided some resistance by flapping in the wind. allegedly he hit the ground at 99.25 mi/h after falling for 10 seconds. to test the accuracy of this account, you should first find the drag coefficient , assuming a terminal velocity of 99.25 mi/h and also that the deceleration of the paratrooper due to air resistence is proportional to his velocity, with constant of proportionality . remember that the acceleration due to gravity near the earth's surface is 32 ft/sec
a. Find rho.
b. Next, find the distance fallen in 6 seconds..
An object can encounter some resistance when moving through the fluid medium of air.
The drag force is the oppositional force applied by the air to a moving object. The size of the cross section A of the front face of the item, the density of the air, and the square of the object's velocity v all contribute to the drag force.
With motion exclusively in the vertical direction and letting
downward be positive, we have that
dv/dt = g - pv, where g = 32 ft/[tex]s^{2}[/tex], and so
dv/dt + pv = g. The integrating factor is [tex]e^{(pt)}[/tex], so
d/dt([tex]e^{(pt)}[/tex] * v) = g×[tex]e^{(pt)}[/tex] ----->
[tex]e^{(pt)}[/tex] * v = (g/p)*[tex]e^{(pt)}[/tex] + C ----->
v(t) = (g/p) + C×[tex]e^{(pt)}[/tex]
Now v(0) = (g/p) + C = 0, and so C = -g/p, giving us
v(t) = (g/p)×(1 - [tex]e^{(pt)}[/tex]).
Now we are given that lim(t->infinity)(v(t)) = 99 mi/h = 145.2 ft/s,
so since [tex]e^{(pt)}[/tex]-> 0 as t -> infinity we have g/p = 145.2 ft/s ------>
p = 32 ft/s^2 / (145.2 ft/s) = 0.2204 s^-1 .
Next, since we have defined downward as positive, the expression
we have for v(t) will equal dy/dt where y(0) = 0 and y increases as
the paratrooper falls. So
dy/dt = v(t) = (g/p)×(1 - [tex]e^{(pt)}[/tex])), so
y(t) = (g/p)×(t + (1/p)×[tex]e^{(pt)}[/tex]) + K.
Now y(0) = (g/p)×(0 + (1/p)) + K = 0 ----->
K = -(g/p^2) = 32 / 0.2204^2 = -658.76 ft, so
y(t) = (145.2)×(t + (4.5372)×e^(-0.2204×t)) - 658.76.
Next, y(6) = (145.2)×(6 + (4.5372)×e^(-0.2204×6)) - 658.76 = 444.84 feet.
The computed drag coefficient is substantially higher than anticipated.
The free fall distance is the longest distance an individual can travel in a predetermined amount of time. However, the distance covered in the time frame indicated in the news report is significantly greater than the greatest distance that could be covered. Consequently, the news story is exaggerated.
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as infants extract an increasing number of potential word forms from the speech stream they hear, they begin to associate these with concrete, perceptually available objects in their world. this is referred to as multiple choice question.
Infants extracting an increasing number of potential word forms from the speech stream they hear, begin to associate these with concrete, perceptually available objects is referred to as statistical learning.
Statistical learning refers to the process by which infants extract potential word forms from the speech stream they hear and begin to associate them with concrete, perceptually available objects. This process is thought to be a crucial component of language development, as it allows infants to begin to understand the structure and meaning of the language they are exposed to.
Through statistical learning, infants are able to identify patterns and regularities in the speech they hear, such as the relationship between a word and the object it refers to. This ability enables them to begin to build a vocabulary and develop an understanding of the grammar and syntax of their native language. Additionally, statistical learning may also play a role in the development of other cognitive abilities, such as memory and attention.
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Your question seems incomplete, but I suppose the question was:
"As infants extract an increasing number of potential word forms from the speech stream they hear, they begin to associate these with concrete, perceptually available objects in their world. this is referred to as"
A photon of wavelength 29 pm is scattered by a stationary electron. What is the maximum possible energy loss of the photon? (m el = 9.11 × 10-31 kg, h = 6.626 × 10-34 J · s, c = 3.00 × 108 m/s)
The maximum possible energy loss of the photon is 2.7 x 10-14 J, which is much less than the energy of the photon, 7.3 x 10-19 J.
To Calculate the energy of the photon.
E = hc/λ
E = (6.626 × 10-34 J · s)(3.00 × 108 m/s)/(29 x 10-12 m)
E = 7.3 x 10-19 J
To Calculate the maximum possible energy loss of the photon.
Max energy loss = 2m el (c2)
Max energy loss = 2(9.11 x 10-31 kg)((3.00 x 108 m/s)2)
Max energy loss = 2.7 x 10-14 J
Compare the energy of the photon and the maximum possible energy loss.
Hence, maximum possible energy loss of the photon is 2.7 x 10-14 J, which is much less than the energy of the photon, 7.3 x 10-19 J.
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A 4-kg bowling ball rolls at a speed of 15 m/s on the ground. Circle one: KE / GPE / both
Answer:
KE
Explanation:
It has KE only because it is in motion, but 0 GPE because it is on the ground. For it to have any GPE it would have to be at some height above the ground.
A barrel rider is moving in a circle with a speed of 7.0 m/s. The acceleration of the rider is 7.2 m/s/s. The speed of the object is somehow increased to 14.0 m/s (i.e., doubled). The new acceleration would be _____ m/s/s. (Assume that the radius of the circle is not changed.)
The new acceleration of the barrel rider if the speed is doubled is 14.4m/s².
How to calculate acceleration?Acceleration in physics refers to the amount by which a speed or velocity increases i.e. the change of velocity with respect to time.
The acceleration of a moving body is directly proportional to the speed of that body i.e. an increase in speed equates to an increase in acceleration.
According to this question, a barrel rider is moving in a circle with a speed of 7.0 m/s. The acceleration of the rider is 7.2 m/s². However, the speed of the object is somehow increased to 14.0 m/s.
This suggests that the acceleration of the rider will also be doubled and hence, be 14.4m/s².
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A certain amount of heat is added to some water so that its temperature rises. The same amount of heat is added to a piece of alu- minum with the same mass as the water. Which has the higher temperature change? A)water B) aluminum C) they gave equal temperature changes
At upper temperatures, the thermal conductivity decreases slowly with increasing temperature than depicted by this equation. Aluminum has the higher temperature change.
What is Aluminum ?Aluminum is a silvery-white metal and is the 13th element on the periodic table. A surprising fact about aluminum is that it is the most common metal on earth.Aluminum (Al), also known as aluminum, chemical element, light silvery-white metal of the 13th main group (III a, or boron group) of the periodic table. Aluminum is the most abundant metallic element in the earth's crust and the most commonly used non-ferrous metal. Aluminum is a silver-white colored lightest metal. Soft and easy to play. Aluminum is used in a variety of products including cans, foils, kitchenware, window frames, beer kegs and aircraft components.to learn more about Aluminum from the given link:
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the velocity of a 1.7 kg block sliding down a frictionless inclined plane is found to be 1.54 m/s. 1.70 s later, it has a velocity of 6.13 m/s.
The angle of plane is 15 degrees.
mg x Sin A gives the force that pushes the mass down the incline.
Additionally, this force uses the same formula m x a which is mass times acceleration,
where a is the original acceleration in the plane.
The block sliding has a mass of 1.7 kg and an initial speed of 1.54 m/s.
the velocity is 6.13 m/s after the time of 1.70 seconds, which is given.
By dividing the difference between the two initial velocities by the given time, or
(6.13 m/s - 1.54 m/s) / 1.70s = 2.70 [tex]m/s^2[/tex],
the acceleration a may be calculated.
ma is therefore which is equal to mass time acceleration g times sin A, or
sin A = acceleration (a) / gravity (g) , or
2.70 [tex]m/s^2[/tex] times 9.81 times 0.275.
A is equal to arc sin (0.275) = or sin A = 15 degrees
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common transparent tape becomes charged when pulled from a dispenser. if one piece is placed above another, the repulsive force can be great enough to support the top piece's weight. assuming equal point charges (only an approximation), calculate the magnitude of the charge if electrostatic force is great enough to support the weight of a 13.0 mg piece of tape held 1.30 cm above another. (the magnitude of this charge is consistent with what is typical of static electricity.)
If one piece is placed above another, the repulsive force can be great enough to support the top piece's weight.
calculate the magnitude of the charge if electrostatic force?
The magnitude of charges on the electron and proton are `1.6xx10^(-19)` C.M Mass of the electrons is `m_(e)=9.1xx10^(-31)` kg and mass of proton is `m_(p)=1.6xx10^(-27)` kg .n the equation Felect = k • Q1 • Q2 / d2 , the symbol Felect represents the electrostatic force of attraction or repulsion between objects 1 and 2.The force is perpendicular to both the velocity v of the charge q and the magnetic field B. 2. The magnitude of the force is F = qvB sinθ where θ is the angle < 180 degrees between the velocity and the magnetic field.This force emerges from the interaction between two charged objects (or point charges) and its magnitude is calculated by F=kQ1Q2r2 F = k Q 1 Q 2 r.
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Which subatomic particles contribute to the mass of an atom
Answer:
Only protons and neutrons contribute to the mass of an atom.
Explanation:
The speed of light is about 300,000 km/sec. The average distance between the Earth and the Sun (1
AU) is about 150 million km. Approximately how long will it take light to travel to 1 AU?
It will take approximately 8.3 minutes for light to travel from the Earth to 1 AU
The speed of light is a constant value of about 300,000 km/sec. To find out how long it will take light to travel to 1 AU (which is about 150 million km), we can use the formula:
Time = distance/speed
So we can substitute the values into the formula:
time = 150 million km / 300,000 km/sec
By solving the equation we get:
time = 500 seconds or approximately 8.3 minutes
Therefore, it will take approximately 8.3 minutes for light to travel from the Earth to 1 AU, which is the average distance between the Earth and the Sun.
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A boy throws a ball straight up into the air. It reaches the highest point of its flight after 4 seconds. How fast was the ball going when it left the boy's hand?
The ball's exit velocity from the boy's hand was 39.4 m/s.
The time it took the ball to reach its highest point is 4 seconds, which is the explanation.
Use the first equation of motion, v = u + gt, to determine the ball's initial velocity when it left the boy's hand.
Initial velocity (v) is used here. terminal velocity is u. t is the amount of time, and g is the gravitational acceleration, with a value of 9.8 m/s2.
At its highest point, the ball's final velocity, v, equals zero.
When the supplied values are substituted in the equation above, we get 0=u-9.8m/s2.
Therefore, the ball's exit velocity from the boy's hand was 39.4 m/s.
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A crane uses 19000 watts of power to lift a 6200 kg chunk of metal in a certain amount of time, how much
power will he use to do the same amount of work in three times the time?
er
Power (in watt) will he use to do the same amount of work in three times the time:
m=100 kgg=10 m/sh=10 m
W=mgh=100×10×10=10000 J
P= t/W
10000/20
=500 W
What is watt?Watt is a unit of power or radiant flux in the International System of Units, equivalent to 1 joule/second or 1 kg⋅m²⋅s⁻³. It is used to quantify the energy transfer rate. The watt (abbreviated W) is the standard International System of Units (SI) unit of power (energy per unit of time) equal to one joule per second. Watts are used to indicate the rate at which electrical energy is dissipated, or electromagnetic energy is radiated, absorbed, or dissipated.Watt is defined as 1 watt = 1 joule per second (1W = 1 J/s), meaning 1 kW = 1000 J/s. A watt is the amount of energy (in joules) that an electrical device (such as a light) consumes per second while in operation. So a 60W light bulb consumes 60 Joules of energy per second.To learn more about watt from the given link:
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Forces at Work
The spring-loaded cart is a simple system, which can make it easier to
analyze and apply the scientific ideas observed to a larger, more
complex system. A skateboarder is another simple system. A
skateboarder would not get anywhere without forces. Since the
skateboard does not have a motor, the skateboarder must be the one
that supplies the power to make it go. But how does this push cause
the motion? Why does the skateboarder have to continually push the
skateboard to keep it in motion?
Similar cause-and-effect relationships involved in the spring-loaded
cart can be applied to your model of the fire extinguisher go-kart.
What cause-and-effect relationships identified in
the spring-loaded cart can be applied to the
rocket sled?
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The skateboard was initially at rest, and by the time of Newton's first law, it would still be in that state. This law asserts that unless acted upon by an external or net force, a body will remain at rest or continue in a condition of uniform motion with constant velocity (in a situation where not only one force is in action).
According to this law, in order to move the skateboard, it needs an external source of force, which the skateboarder indirectly provides.
The skateboarder reverses forward on the pavement (that is he applies a force on the road in a direction opposite the direction of intended motion).
According to Newton's third law, the skateboarder's action results in an equal and oppositely directed reaction from the road on the skateboarder.
According to Newton's third law, action and response are equal but directed in opposite directions. As a result, the road pulls the skateboarder forward in response to this rearward force, which moves both the skateboarder and the skateboard in the same direction.
The acceleration of the cart is inversely related to its mass. As a result, the acceleration of the cart will decrease as its mass increases.
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(a) what is the velocity vpi of the plank relative to the surface of the ice? (use the following as necessary: vgp, mg, and mp. indicate the direction with the sign of your answer. let the positive direction be in the direction that the girl walks.)
The final velocity of plank with respect to the ice will be (-Mg×Vgp)/(Mg+Mp) and it will be in direction opposite to the girl.
Mass of the girl, = Mg
Mass of the plank, = Mp
Velocity of the girl with respect to plank, = Vgp
Velocity of the plank with respect to ice, = Vpi
Velocity of girl with respect to ice, = Vgi
Initially both girl and the plank were at rest with respect to ice, so initial momentum of both was zero. So final momentum of both with respect to ice will be zero.
Mg×Vgi + Mp×Vpi = 0
Mg×Vgi = -Mp×Vpi .....equation (1)
We know that velocity of girl with respect to the ice will be the sum of velocity of the girl with respect to the plank and the velocity of the plank with respect to the ice.
Vgi = Vpi + Vgp.... put this value in equation (1)
Mg×(Vpi + Vgp) = -Mp×Vpi
Mg×Vpi + Mg×Vgp) = -Mp×Vpi
Vpi(Mg + Mp) = -Mg×Vgp
Vpi = -Mg×Vgp/(Mg + Mp)
A negative sign indicates that the velocity of the plank will be in the opposite direction to the girl.
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--The give question is incomplete, the complete question is:
"A girl of mass Mg is standing on a plank of mass Mp. Both are originally at rest on a frozen lake that constitutes a frictionless, flat surface. The girl begins to walk along the plank at a constant velocity Vgp to the right relative to the plank. (The subscript gp denotes the girl relative to the plank.)
What is the velocity Vpi of the plank relative to the surface of the ice? (Use the following as necessary: Vgp, Mg, and Mp. Indicate the direction with the sign of your answer. Let the positive direction be in the direction that the girl walks.)"--
How far (in m) does a car going 21 m/s travel in 7.1 s?
the distance between two successive maxima of a certain transverse wave is 1.2m height crests or maxima pass a given point along the direction of travek every 12a calcultae the wave speed
The wave speed is 01 m/s, which can be calculated by using the formula:
wave speed distance between two successive maxima/time interval between two successive maxima
In this case, the distance between two successive maxima is given as 1.2m and the time
interval between two successive maxima is given as 12s.
So, the wave speed can be calculated as:
wave speed = 1.2m/12s = 0.1 m/s
It is worth mentioning that the wave speed is a scalar quantity, which means it has only magnitude and no direction. The given information is about the transverse wave which is a type of wave in which the oscillation is perpendicular to the direction of energy transfer
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An electron is moving to the right with an initial speed of vo = 3.5 x 10E7 m/s when it enters a
region of space that is L = 3.3 cm wide with a uniform electric field pointing down of magnitude
E = 8.2E4 N/C.
An electron is moving to the right with an initial speed of vo = 3.5 x 10E7 m/s when it enters a
region of space that is L = 3.3 cm wide with a uniform electric field pointing down of magnitude
E = 8.2E4 N/C. The electron will experience electric field
What informs the electron with electric field?The electron will experience a force due to the electric field, which is given by the equation F = qE, where q is the charge of the electron (a negative value) and E is the electric field.
The force will cause the electron to accelerate in the direction of the field, which is opposite to its initial direction of motion. The acceleration of the electron can be calculated using the equation a = F/m, where m is the mass of the electron.
The distance the electron will travel before it exits the region of space can be calculated using the equation x = v_0t + 0.5a*t^2, where v_0 is the initial velocity and t is the time it takes for the electron to travel through the region.
Therefore, the correct answer is as given above
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The complete question goes thus:
An electron is moving to the right with an initial speed of vo = 3.5 x 10E7 m/s when it enters a
region of space that is L = 3.3 cm wide with a uniform electric field pointing down of magnitude
E = 8.2E4 N/C. What will happen to the electron?
A bar having a length of 5 in. and cross-sectional area of0.7 m' is subjected to an axial force of 8000N. If the bar stretches 0.002m., determine the modulus of elasticity of the material. The material has linear- elastic behavior.
Answer:
Explanation:
he modulus of elasticity (E) can be calculated using the formula:Stress = Force / AreaStrain = Change in length / Initial lengthModulus of Elasticity (E) = Stress / StrainWe have the Force = 8000 N, Area = 0.7 m^2, Change in length = 0.002 m and initial length = 5 in = 0.127 mStress = Force / Area = 8000 N / 0.7 m^2 = 11428.57 N/m^2Strain = Change in length / Initial length = 0.002 m / 0.127 m = 0.0157Modulus of elasticity (E) = Stress / Strain = 11428.57 N/m^2 / 0.0157 = 727,279.9 N/m^2So the modulus of elasticity for the material of the bar is 727,279.9 N/m^2This is the ratio of the applied stress to the corresponding strain within the elastic limit, which is a measure of a material's resistance to deformation.