The constant rate of change of the account is $40 or Increasing by $40 per month.
Step-by-step explanation:
Consider the provided information.
Joanne is depositing money into a bank account. After 3 months there is $120 in the account. After 6 months there is $240 in the account.
Rate of change is known as how one quantity change in relation to other.
The rate of change can be calculated as:
y2-y1/x2-x1
Now use the above formula to calculated the rate of change.
240 - 120/6-3
120/3
40
Hence, the constant rate of change of the account is $40 or Increasing by $40 per month.
A total of 710 tickets were sold for the school play . They were either adult tickets or student tickets. There were 60 more student tickets sold than adult tickets. How many adult tickets were sold ?
Answer: 325
Explanation:
Let the number of adult tickets be x
( since there are an unknown amount of tickets for adults, we already know how many student tickets there are)
Let the number of student tickets be x+60
710=x+x+60
710=2x+60
-60 -60
650=2x
650/2
= 325
Adult tickets=325
Student tickets=385
What is the equation of the line that passes through the point (5,2) and has a slope
of -3/5
Answer:y = -0.6x + 5
Step-by-step explanation:
Answer:
yessir the one on top is right btw
Step-by-step explanation:
hope this helped
The sum of two numbers is 38. The smaller number is 22 less than the larger number. What are the numbers?
Answer:
30 and 8
Step-by-step explanation:
30 - 8 = 22
Find the area of the shape shown below
Answer:
18 MARK AS BRAINLIEST OR ELSE!!!!
Step-by-step explanation:
area = 1/2h(sum of bases)
area = 1/2x3(3+9)
area = 1/2 of 36
area = 18
What value of θ makes the statement true?
cos(θ)=sin(θ/3−10)
The required value of θ for the trigonometric function cos(θ)=sin(θ/3-10) is 60°.
What are trigonometric functions?The basic Trigonometric functions are sine, cosine, tangent, secant, cosecant and cotangent.
The given equation is,
cos(θ)=sin(θ/3-10) (1)
To find the value of θ,
Change the whole equation into one trigonometric function,
Since, cos(θ)=sin(90-θ)
Substitute this value in equation (1)
sin(90-θ)=sin(θ/3-10)
⇒90-θ=θ/3-10
⇒4θ/3=80
⇒θ=60
The value of θ is 60°.
To know more about Trigonometric Function on:
https://brainly.com/question/15768633
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If you bake 3/4 of a cake in 5/6 of an hour, how long does it take to bake 18 cakes
Answer: 15
Step-by-step explanation: 5/6 times 18 = 15 hours
Which ordered pair is a solution to the equation below? 3x + 2y = 10
Question 1 options:
(4, 0)
(6, -4)
(-1, 4)
Answer:
(6,-4)
Step-by-step explanation:
I have tried replacing each option with x, y in the equation.
Let's replace (6, -4) with x and y
3x+2y=10
3(6)+2(-4)=10
3(6)= 18 2(-4)= -8
18+(-8)=10
in other words:
18-8=10
The statement is true, so the correct answer is:
(6, -4)
How do you do these two questions?
Answer:
(x − π)⁷ / 5040
(x − 1)³ / 16
Step-by-step explanation:
Taylor series expansion of a function is:
f(x) = ∑ₙ₌₀°° f⁽ⁿ⁾(x₀) / n! (x − x₀)ⁿ
where f⁽ⁿ⁾(x₀) is the nth derivative evaluated at x₀.
For the first problem, f(x) = sin x and x₀ = π. We want the seventh degree term, so n = 7.
The seventh degree term is therefore: f⁽⁷⁾(π) / 7! (x − π)⁷
Find the seventh derivative of sin x:
f(x) = sin x
f⁽¹⁾(x) = cos x
f⁽²⁾(x) = -sin x
f⁽³⁾(x) = -cos x
f⁽⁴⁾(x) = sin x
f⁽⁵⁾(x) = cos x
f⁽⁶⁾(x) = -sin x
f⁽⁷⁾(x) = -cos x
Evaluated at π, f⁽⁷⁾(x) = 1. So the seventh degree term is (x − π)⁷ / 5040.
For the second problem, f(x) = √x and x₀ = 1. We want the third degree term, so n = 3.
The third degree term is therefore: f⁽³⁾(1) / 3! (x − 1)³
Find the third derivative of √x:
f(x) = √x
f⁽¹⁾(x) = ½ x^-½
f⁽²⁾(x) = -¼ x^-³/₂
f⁽³⁾(x) = ⅜ x^-⁵/₂
Evaluated at 1, f⁽³⁾(x) = ⅜. So the third degree term is (x − 1)³ / 16.
C
Kris is cutting ribbon that each measure 2 ft
long. If Kris is cutting from a piece that measures
8zft
, how many pieces can Kris cut?
Answer:
4
Step-by-step explanation:
because 2+2+2+2=8 pretty self explanatory
Answer:
13
Step-by-step explanation:
plsss help 6th grade math
Answer: D
Step-by-step explanation:
If you put -5 and +5 on a number line and count their distance from zero they are both the same distance.