Answer:
False
Explanation:
inductive arguments have some evidence but do not have full assurance of truth of the conclusion
A current is flowing in a wire in direction 3i + 4j where the direction of the magnetic field is 5j + 12k. The force on the wire is:_____
a. 0.71(i + j).
b. 0.78i - 0.58j + 0.24k.
c. 0.78i + 0.58j - 0.24k.
d. 0.78i + 0.58j + 0.24k.
Answer:
F = 0.768 i ^ - 0.576 j ^ + 0.24 k ^
the correct answer is "b"
Explanation:
The magnetic force is
F = i l x B
The bold are vectors, in this case they give us the direction of the current and the magnetic field, for which we can solve as a determinant
[tex]F = i \left[\begin{array}{ccc}x&y&z\\3&4&0\\0&5&12\end{array}\right][/tex]
resolver
F = i ^ (4 12 - 0) + j ^ (0- 3 12) + k ^ (3 5 - 0)
F = i (48 i ^ - 36 j ^ + 15 k⁾
in this case i is the value of the current flowing through the cable
i = 16 mA = 0.016 A
F = 0.768 i ^ - 0.576 j ^ + 0.24 k ^
When reviewing the different answers, the correct answer is "b"
Calculate the average induced voltage between the tips of the wings of a Boeing 747 flying at 970 km/hr above East Lansing. The downward component of the earth's magnetic field at this place is
This question is incomplete, the complete question is;
Calculate the average induced voltage between the tips of the wings of a Boeing 747 flying at 970 km/hr above East Lansing. The downward component of the earth's magnetic field at this place is 0.7 × 10⁻⁴ T. (DATA: Assume that the wingspan is 60 meters.)
Answer:
the average induced voltage between the tips of the wings of a Boeing 747 flying is 1.132 Volts
Explanation:
Given that;
Speed S = 970 KM/hr
downward component of the earth's magnetic field B = 0.7 × 10⁻⁴
wingspan 1 = 60min
Velocity V = (970 × 10³) / 3600 = 269.44 m/s
So Average Induced Voltage E = VBI
we substitute
E = 269.44 × (0.7 × 10⁻⁴) × 60
E = 1.132 Volts
Therefore the average induced voltage between the tips of the wings of a Boeing 747 flying is 1.132 Volts
Objects are lighter on the moon than they are on earth. if an object A weighs 25lbs on the Moon and another object B weighs 25 Newtons on earth, which has more mass?
a. Object a
b. Object b
c. Same mass
d. Other
Answer:
a. Object A
Explanation:
The mass of an object implies the quantity of matter in it, while the weight is the amount of gravitational force applied on an object.
The object A has a mass of 25 lbs, but object B on the earth has a weight, W, of 25 N.
So that,
For object A on the moon, mass = 25 lbs
For object B on the earth, W = 25 N,
W = m x g
25 = m x 10 (g = 10 m/[tex]s^{2}[/tex])
m = [tex]\frac{25}{10}[/tex]
= 2.5 lbs
Mass of object B is 2.5 lbs.
Therefore, the mass of the object A is more than that of B.
A jogger runs 6km north, 5km east, then another 4km north. Her average speed is 8 km/h. How long will it take her to complete her run?
Answer:
t = 1.875 hours
Explanation:
Speed
The speed is the rate at which an object moves. If the speed is constant, then the formula to calculate it is:
[tex]\displaystyle v=\frac{d}{t}[/tex]
Where d is the distance traveled in time t.
The jogger runs 6 Km plus 5 Km plus 4 Km north for a total of 15 Km.
It's given her average speed is 8 Km/h. We can calculate the time take to complete the run by solving the above formula for t:
[tex]\displaystyle t=\frac{d}{v}[/tex]
[tex]\displaystyle t=\frac{15\ Km}{8\ Km/h}[/tex]
t = 1.875 hours
Assume you are in the car and the car is moving at a certain speed to
school. Are you at rest or in motion with respect to the school? With
respect to the car?
In football we see unbalanced forces. When 1 player exerts an unbalanced force on another player and causes a player to
Answer:
Fall
Explanation:
A force of 1.50 N acts on a 0.20 kg trolley so as to accelerate it along an air track.
The track and force are horizontal and in line. How fast is the trolley going after acceleration from rest through 30 cm, if friction is negligible?
Answer: The trolley is moving at 2.12m/s
Explanation:
Given from the question that the track and force are horizontal and inline, we have that
F= ma
where F= force= 1.50 N
m= mass = 0.2kg
therefore Acceleration , a = F/ m= 1.50/0.2 =7.5 m/s^2
To find how fast the trolley is going ie the Velocity, v
Having that
initial velocity at rest , u = 0,
acceleration a = 7.5 and
and distance, s = 30 cm = 30/100 = 0.30 m
we use motion equation that
v² = u² + 2 a s
v² = 0² + 2 x 7.5 x 0.30
v² = 4.5
v = [tex]\sqrt{4.5}[/tex]
v = 2.12 m/s
Catching a wave, a 77 kg surfer starts with a speed of 1.3 m/s, drops through a height of 1.65 m, and ends with a speed of 8.2 m/s. How much non-conservative work was done on the surfer?
Answer:
Explanation:
The total work done by the wave is expressed as;
Workdone = Potential energy + Kinetic energy
Workdone = mgh + 1/2mv²
m is the mass = 77kg
g is the acceleration due to gravity = 9.8m/s²
v is the velocity = 8.2m/s
h is the height = 1.65m
Substitute into the formula;
Workdone = 77(9.8)(1.65) + 1/2(77)8.2²
Workdone = 1245.09 + 2588.74
Workdone = 3833.83Joules
Hence the amount of non conservative work done on the sofa is 3833.83Joules
Given:
Velocity, v = 8.2 m/sHeight, h = 1.65 mMass, m = 77 kgWe know,
→ [tex]Work \ done = Potential \ energy +Kinetic \ energy[/tex]
or,
[tex]= mgh +\frac{1}{2} mv^2[/tex]
By putting the values,
[tex]= 77\times 9.8\times 1.65+\frac{1}{2}\times 77\times (8.2)^2[/tex]
[tex]= 1245.09+2588.74[/tex]
[tex]= 3833.83 \ Joules[/tex]
Thus the above approach is right.
Learn more about work done here:
https://brainly.com/question/24230840
significance of practicals in the discipline of geography
C4. A 50.0 kg boy runs at 10.0 m/s, jumps on a cart and rolls off at 2.50 m/s. What is the mass of the cart
Answer:
The mass of the cart is 150 kg.
Explanation:
Given that,
Mass of a boy, m₁ = 50 kg
Initial speed of boy, u₁ = 10 m/s
Initial speed of car, u₂ = 0 (at rest)
The speed of the cart with the boy on it is 2.50 m/s, V = 2.5 m/s
Let m₂ is the mass of the cart. Using the conservation of momentum as follows :
[tex]m_1u_1+m_2u_2=(m_1+m_2)V\\\\50(10)+m_2(0)=(50+m_2)(2.5)\\\\500=125+2.5m_2\\\\375=2.5m_2\\\\m_2=150\ kg[/tex]
So, the mass of the cart is 150 kg.
In ultimate the disc may be passed in any direction.
True
False
I think is True: Because...
when you throw a disc you can throw it in any direction, many people call it "Flying Saucer" I'll give you an example ... When you throw something, for example a paper, you want to throw it at your classmate. You already know what address you want to send it to, then I say it is: True ...
Sorry if it's wrong :(
The second-order dark fringe in a single-slit diffraction pattern is 1.40 mm from the center of the central maximum. Assuming the screen is 89.0 cm from a slit of width 0.710 mm and assuming monochromatic incident light, calculate the wavelength of the incident light.
We know, for single slit :
[tex]y =\dfrac{ n\lambda L}{a}\\\\\lambda = \dfrac{ya}{nL}[/tex] ...1)
[tex]y = 1.4\ mm = 1.4 \times 10^{-3}\ m[/tex]
n = 2
L = 89 cm = 0.89 m
[tex]a=7.1\times 10^{-4}\ m[/tex]
Putting all these in equation 1), we get :
[tex]\lambda = \dfrac{ya}{nL}\\\\\lambda = \dfrac{1.4\times 10^{-3}\times 7.1\times 10^{-4}}{2\times 0.89 }\\\\\lambda = 5.584 \times 10^{-7}\ m[/tex]
Therefore, wavelength of the incident light is [tex]5.584 \times 10^{-7}\ m[/tex] or 558.4 nm.
Hence, this is the required solution.
A typical blood pressure is 120 mm Hg. How high would you need to hang an IV bag so that the fluid enters the blood stream at this pressure? Assume the IV fluid has a density of 1000 kg/m^3.
Answer:
1.63 m
Explanation:
The following data were obtained from the question given above:
Pressure (P) = 120 mmHg
Density (d) = 1000 Kg/m³
Height (h) =?
Next, we shall convert 120 mmHg to N/m². This can be obtained as follow:
760 mmHg = 101325 N/m²
Therefore,
120 mmHg = 120 mmHg × 101325 N/m² / 760 mmHg
120 mmHg = 15998.68 N/m²
Thus, 120 mmHg is equivalent to 15998.68 N/m².
Finally, we shall determine the height to which the IV bag should be placed so that the fluid can enter the blood stream. This is illustrated below:
Pressure (P) = 15998.68 N/m².
Density (d) = 1000 Kg/m³
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) =?
P = dgh
15998.68 = 1000 × 9.8 × h
15998.68 = 9800 × h
Divide both side by 9800
h = 15998.68 / 9800
h = 1.63 m
Therefore, the the IV bag should be placed at a height of 1.63 m
2. Heather and Matthew walk with an average velocity of +0.87 m/s eastward.
If it takes them 27 minutes to walk to the store, what is their
displacement? (include direction)
(5 points)
If you are riding your bike west to your friend’s house, and you ride the 1.25 miles in 5 minutes, what is your velocity, in miles per hour?
Answer:
velocity = 15 miles / hourExplanation:
distance = 1.25 mile
time traveled = 5 min.
find velocity in miles / hour
solution:
use the formula: velocity = distance / time
velocity = 1.25 mile x 60 min
5 min 1 hour
velocity = 15 miles / hour
PLEASE PROVIDE AN EXPLANATION
THANK YOU!
Answer:
(a) 0.993 s
(b) 14.0 N/m
(c) -3.02 m/s
(d) -6.01 m/s²
Explanation:
(a) The block's position can be modeled as a cosine wave:
x(t) = A cos(ωt)
where A is the amplitude (in this case, 50 cm) and ω is the angular frequency.
At t = 0.200 s, x(t) = 15.0 cm.
15.0 cm = 50.0 cm cos((0.200 s) ω)
0.3 = cos((0.2 s) ω)
1.266 rad = (0.2 s) ω
ω = 6.33 rad/s
The period is:
T = (2π rad) (1 s / 6.33 rad)
T = 0.993
(b) For a spring-mass system, ω = √(k/m). The mass of the block is 0.350 kg, so:
ω = √(k/m)
6.33 rad/s = √(k / 0.350 kg)
6.33 rad/s = √(k / 0.350 kg)
40.1 rad/s² = k / 0.350 kg
k = 14.0 N/m
(c) Energy is conserved:
EE₀ = EE + KE
½ kx₀² = ½ kx² + ½ mv²
kx₀² = kx² + mv²
(14.0 N/m) (0.50 m)² = (14.0 N/m) (0.15 m)² + (0.35 kg) v²
v = -3.02 m/s
Alternatively, we can take the derivative of our position equation:
v(t) = -Aω sin(ωt)
v = -(0.50 m) (6.33 rad/s) sin((6.33 rad/s) (0.2 s))
v = -3.02 m/s
(d) Sum of forces on the block:
∑F = ma
-kx = ma
a = -kx / m
a = -(14.0 N/m) (0.15 m) / (0.350 kg)
a = -6.01 m/s²
Alternatively, we can take the derivative of our velocity equation:
a(t) = -Aω² cos(ωt)
a = -(0.50 m) (6.33 rad/s)² cos((6.33 rad/s) (0.2 s))
a = -6.01 m/s²
You are a world-famous physicist-lawyer defending a client who has been charged with murder. It is alleged
that your client, Mr. Lawton, shot the victim, Mr. Cray. The detective who investigated the scene of the
crime, Mr. Dibny, found a second bullet, from a shot that missed Mr. Cray, that had embedded itself into a
chair. You arise to cross-examine the detective.
You: In what type of chair did you find the bullet?
Dinby: A wooden chair.
You: How massive was this chair?
Dinby: It had a mass of 20 kg.
You: How did the chair respond to being struck with a bullet?
Dinby: It slid across the floor.
You: How far?
Dinby: Three centimeters. The slide marks on the dusty floor are quite distinct.
You: What kind of floor was it?
Dinby: A wood floor.
You: What was the mass of the bullet you retrieved from the chair?
Dinby: Its mass was 10 g.
You: Have you tested the gun you found in Mr. Lawton's possession?
Dinby: I have.
You: What is the muzzle velocity of bullets fired from that gun?
Dinby: The muzzle velocity is 450 m/s.
With only slight hesitation, you turn confidently to the jury and proclaim, "My client's gun did not fire those
shots!"
(a) How are you going to convince the jury and judge?
(b) Choose one part of your solution and perform a sense-making analysis. Clearly state which sensemaking analysis you’ve chosen and why.
Answer:
It was not fired from the client's gun because the chair slid only 3 centimeters . If it had been fired from the client's gun the chair would slid 25.82 centimeters.
Explanation:
According to the law of conservation of momentum the momentum of the system before collision must be equal to the momentum of the system after the collision.
M1u1= m2u2
Let M1 = mass of the chair = 20kg
m2= mass of the bullet= 10g= 0.001kg
u1= velocity of the chair before collision = zero m/s
u2 = velocity of the bullet before collision = zero m/s
v1= velocity of the chair after collision = ? m/s
v2 = velocity of the bullet after collision = 450 m/s
After collision their velocities change from u1 to v1 and u2 to v2 so
M1v1= m2v2
v1= m2v2/M1
v1= 0.01 *450/ 20= 0.225 m/s
Now according to the law of conservation of energy the energy of the system before collision must be equal to the energy of the system after the collision.
The energy of the chair after the bullet is hit is
KE of the chair + KE of the bullet= 1/2 (M)(v1)²+ 1/2 m(v2)²=
1/2 ( 20) (0.225 )² + 1/2 (0.01) (450)²
= 0.50625 + 1012.5= 1013.00625 Joules
Frictional force = Coefficient of kinetic force of wood on wood ( M+m) g
= 0.2* ( 20.01) 9.8= 39.2196 N
Work done by friction = frictional force * distance
If law of conservation of energy is applied the KE must be equal to the work done
KE = W
W= f*d
KE= F*d
d = KE/f= 1013.00625/ 39.2196= 25.82 cm
The chair did not move 25.82 cm .
It only moved 3 centimeter.
Hence the bullet fired was not from the client's gun.
A 5 kg ball and a 2 kg ball are placed at opposite ends of a massless beam so that the system is in equilibrium. What is the ratio of the length of the beam to the distance from the heavier ball to the pivot
Answer:
L/x = 3.5 (The ratio of length of beam to the distance from heavier ball to pivot).
Explanation:
In order for the system to be in equilibrium, the moment created by both masses about the pivot point must be equal:
m₁x = m₂y
where,
m₁ = 5 kg
m₂ = 2 kg
x = distance of 5 kg ball from pivot
y = distance of 2 kg ball from pivot
Therefore,
(5 kg)x = (2 kg)y
y = (5kg/2kg)x
y = 2.5 x
but,
x + y = L
where,
L = length of beam
using the value of y from the previous equation:
x + 2.5 x = L
3.5 x = L
L/x = 3.5 (The ratio of length of beam to the distance from heavier ball to pivot).
1.) There was an earthquake in Salt Lake City, Utah, on March 18, 2020, in the morning at 9 hours, 9 minutes, and 45 seconds Mountain Standard Time (9:9:45 MST). If the velocity of the p-wave is 7.3 km/sec and the velocity of the s-wave is 5.1 km/sec and the s-p time lag is 16 seconds, what is the distance in kilometers from Salt Lake City to the focus of the earthquake? Explain how you calculated the answer.
Answer:
7 because salt lake and Southis weat
How many neutrons does protium have
Answer:
I believe none
Explanation:
Fast and safe heart rate for workouts is called muscular strength? True or false
Answer:
False
Explanation:
Answer:
false :3
hope this helps
1.The
across each resistor is
the same in a series circuit.
) voltage
current
Answer:
The answer is Current.
Explanation:
In a series circuit, every component will have the same current.
In parallel circuit, all voltage of component remains the same.
Answer:
In a series circuit, each resistor has the same charge flowing through it.
Explanation:
If you have resistors arranged in a chain, the current only has one path to take which results in an equal charge in each resistor.
What is the highest order dark fringe, , that is found in the diffraction pattern for light that has a wavelength of 575 nm and is incident on a single slit that is 1410 nm wide?
Answer:
The highest order dark fringe is 2
Explanation:
From the question we are told that
The wavelength is [tex]\lambda = 575 \ nm = 575 *10^{-9} \ m[/tex]
The width is of the slit is [tex]d = 1410 nm = 1410 *10^{-9} \ m[/tex]
Generally the highest order dark fringe is mathematically represented as
[tex]m = \frac{w}{\lambda }[/tex]
=> [tex]m = \frac{ 1410 *10^{-9}}{ 575 *10^{-9} }[/tex]
=> [tex]m =2[/tex]
An inventor claims to have invented a heat engine that receives 750kJ of heat from a source at 400K and produces 250kJ of net work while rejecting the waste heat to a sink at 300K. Is this a reasonable claim
Answer:
the claim is not valid or reasonable.
Explanation:
In order to test the claim we will find the maximum and actual efficiencies. maximum efficiency of a heat engine can be found as:
η(max) = 1 - T₁/T₂
where,
η(max) = maximum efficiency = ?
T₁ = Sink Temperature = 300 K
T₂ = Source Temperature = 400 K
Therefore,
η(max) = 1 - 300 K/400 K
η(max) = 0.25 = 25%
Now, we calculate the actual frequency of the engine:
η = W/Q
where,
W = Net Work = 250 KJ
Q = Heat Received = 750 KJ
Therefore,
η = 250 KJ/750 KJ
η = 0.333 = 33.3 %
η > η(max)
The actual efficiency of a heat engine can never be greater than its Carnot efficiency or the maximum efficiency.
Therefore, the claim is not valid or reasonable.
Describe which relationships in Ohm’s law are DIRECT and which are INVERSE. Use examples to support your answer. You can use calculations, drawings, or graphs to make your point more clear
Answer:
I like to memorize excerpt from articles to solve and answer questions like these. I hope this can help, it's from study.com: "The relationship between voltage, current, and resistance is described by Ohm's law. This equation, i = v/r, tells us that the current, i, flowing through a circuit is directly proportional to the voltage, v, and inversely proportional to the resistance, r."
* WILL GIVE BRAINLIEST TO CORRECT ANSWER *
Name a product that people commonly purchase by mass and not by weight.
I would say food but like they take weight too
A golf ball (m=26.7g) is struck a blow that makes an angle of 33.6 degrees with the horizontal. The drive lands 190m away on a flat fairway. The acceleration of gravity is 9.8 m/s^2 . If the golf club and ball are in contact for 7.13 ms, what is the average force of impact?
Answer:
Th average force impact is [tex]F = 168.298 \ N[/tex]
Explanation:
From the question we are told that
The mass of the golf ball is [tex]m_g = 26.7 \ g = 0.0267 \ kg[/tex]
The angle made is [tex]\theta = 33.6 ^o[/tex]
The range of the golf ball is [tex]R = 190 \ m[/tex]
The duration of contact is [tex]\Delta t = 7.13 \ ms = 7.13 *10^{-3} \ s[/tex]
Generally the range of the golf ball is mathematically represented as
[tex]R = \frac{v^2 sin2(\theta)}{g}[/tex]
Here v is the velocity with which the golf club propelled it with, making v the subject
[tex]v = \sqrt{\frac{R * g}{sin 2 (\theta)} }[/tex]
=> [tex]v = \sqrt{\frac{190 * 9.8}{sin 2 (33.6)} }[/tex]
=> [tex]v = 44.94 \ m/s[/tex]
Generally the change in momentum of the golf ball is mathematically represented as
[tex]\Delta p = m * (v - u )[/tex]
here u is the initial velocity of the ball before being stroked and the value is 0 m/s
[tex]\Delta p = 0.0267 * ( 44.94 - 0 )[/tex]
=> [tex]\Delta p = 1.19996 \ kg \cdot m/s[/tex]
Generally the average force of impact is mathematically represented as
[tex]F = \frac{\Delta p }{\Delta t}[/tex]
=> [tex]F = \frac{1.19996 }{7.13 *10^{-3}}[/tex]
=> [tex]F = 168.298 \ N[/tex]
An 800 kg car is parked next to a 1000 kg car. Their centers of mass are 3.5 m apart. Find the gravitational force between them.
Answer:
4.356e-6 Newtons
Explanation:
Using the equation for the force of gravity F=[tex]\frac{Gm_1m_2}{r^2}[/tex]. The two masses are m1=800kg and m2=1000 kg. The value of G, the gravitational constant =6.67e-11. The problem states the distance between the center of masses of the two cars is 3.5 meters(r). Plugging in what we have from the problem, you will get 4.346e-6 newtons. This makes sense as gravity in itself is a weak force requiring extremely massive objects to result in a noticeable force.
from a flying aeroplane abody should be dropped in advance to hit the target why
From a flying plane a body should dropped in advance to hit the target,Why? ... The body should be dropped in advance as when the body is dropped it has the velocity of the plane. So, in air the body moves forward which we have to take into consideration in order to hit the target.
How many stars are in the universe (approximately)? O 40 sixtillion 0 365 billion O 86.4 million O one
Answer:
a i belive
Explanation:
the univerce is VERY large so a, if im wrong i apologise :(