according to newton's third law, of a sledgehammer hits a wall with a force of 1000 n, how much force does the wall hit the sledgehammer? a - 1000 n b 1000 n c 0 n d 500 n

Answers

Answer 1

The correct option is A: the force exerted on the wall by the sledgehammer is  - 1000 N

Newton's third law

Newton's third law of motion states that for every action or force, there is an equal but oppositely directed force.

Application of the newton's third law

Force with which the sledgehammer hits the wall = 1000 N

From the Newton's third law, an equal but oppositely directed force is exerted on the sledgehammer by the wall.

Thus, the force exerted by the sledgehammer on the wall = -1000 N

The negative sign indicates that the force acts in a direction opposite to that of the sledgehammer.

Thus, the correct option is A: the force exerted on the wall by the sledgehammer is  - 1000 N

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Related Questions

train travels 1/4of its total distance over half of its time with a constant velocity of 5m/s. calculate the average velocity​

Answers

Let D be the total distance (say in meters) traveled by the train and T the time (say in seconds) it takes to do so. (Assume the train moves in a straight line in only one direction.) Then the average velocity of the train as it covers this distance is

v (ave) = D/T

We're told the train can traverse a distance of D/4 in a matter of T/2 seconds if it moves at a speed of 5 m/s. This means

D/4 = (5 m/s) (T/2)

⇒   5 m/s = 1/2 D/T

⇒   v (ave) = D/T = 10 m/s

if vector b is added to vector a under what conditions does the resultant vector has magnitude a+b?​

Answers

Explanation:

hope it's useful for you knows

Which is the United States Space Shuttle-derived heavy expendable launch vehicle being designed by NASA?​

Answers

Answer:

Space Launch System (SLS)

Explanation:

Space Launch System (SLS) is the United States Space Shuttle-derived heavy expendable launch vehicle being designed by NASA.

-TheUnknownScientist 72

Calculate amount of current flowing in wire if number of charge is 8 and e = 1.69 x10^-19 , t= 8millsec

Answers

The amount of current flowing in the wire is 1.69 × 10⁻¹⁶ A

From the question,

We are to calculate, the amount of current flowing in the wire.

From the formula,

[tex]I =\frac{nQ}{t}[/tex]

Where I is the current

n is the number of charge

Q is the quantity of charge

t is the time

From the given information

n = 8

Q = e = 1.69 × 10⁻¹⁹ C

t = 8 msecs = 8 × 10⁻³ sec

Putting the parameters into the formula, we get

[tex]I = \frac{8 \times 1.69 \times 10^{-19} }{8\times 10^{-3} }[/tex]

[tex]I = 1.69 \times 10^{-16} \ A[/tex]

Hence, the amount of current flowing in the wire is 1.69 × 10⁻¹⁶ A

Learn more here: https://brainly.com/question/22135459

why can you predict how the moon will change appearance from day to day

Answers

As the Moon orbits our planet, its varying position means that the Sun lights up different regions, creating the illusion that the Moon is changing shape over time. This is because it rotates once on its axis in exactly the same time it takes to orbit Earth – 27 days and seven hours

How many kilojoules are in 1,967,256J? Round your answer to the nearest whole number.

Answers

Answer:

1,967 kilojoules.

Explanation:

1 kilo = a thousand.

There are 1.967 kilojoules in 1,967,256 joules.

What is law of energy conservation?Energy can neither be created nor destroyed.It is only get transfered from one form to another form.

What is the SI unit of energy?Joule is a SI unit of energy.There are 1000 joules in 1 kilojoules .

learn more about unit of energy here - https://brainly.com/question/3012083

#SPJ2

whats 10x10 PLEASE I NEED THIS

Answers

10 x 10
= 100

Hope you find this helpful! for solving such a difficult equation :3

Brainliest and a like is much appreciated!

Answer:

100

Explanation:

> what are the four states of matter? how are they defined?

Answers

Answer:

In physics, a state of matter is one of the distinct forms in which matter can exist. Four states of matter are observable in everyday life: solid, liquid, gas, and plasma.

...

To From Gas

Solid Deposition

Liquid Condensation

Plasma Ionization

A 50 kg pitcher throws a baseball with a mass of 0. 15 kg. If the ball is thrown with a positive velocity of 35 m/s and there is no net force on the system, what is the velocity of the pitcher? â’0. 1 m/s â’0. 2 m/s â’0. 7 m/s â’1. 4 m/s.

Answers

The velocity of the pitcher at the given mass is 0.1 m/s.

The given parameters:

Mass of the pitcher, m₁ = 50 kgMass of the baseball, m₂ = 0.15 kgVelocity of the ball, u₂ = 35 m/s

Let the velocity of the pitcher = u₁

Apply the principle of conservation of linear momentum to determine the velocity of the pitcher as shown below;

m₁u₁ = m₂u₂

[tex]u_1 = \frac{m_2 u_2}{m_1} \\\\u_1 = \frac{0.15 \times 35}{50} \\\\u_1 = 0.105 \ m/s\\\\u_1 \approx 0.1 \ m/s[/tex]

Thus, the velocity of the pitcher at the given mass is 0.1 m/s.

Learn more about conservation of linear momentum here: https://brainly.com/question/13589460

A concrete block (B-36 x10 °C-') of volume 100 mat 40°C is cooled to
-10°C. What is the change in volume? *
A. It will increase by 0.18 m
B. It will decrease by 0.18 m'
C.It will increase by 0.05 m
D. It will decrease by 0.05 mº

Answers

T1=40°C=313KT_2=-10°C=263K

Applying Charles law

[tex]\\ \sf\Rrightarrow \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]

[tex]\\ \sf\Rrightarrow \dfrac{100}{313}=\dfrac{V_2}{263}[/tex]

[tex]\\ \sf\Rrightarrow V_2=\dfrac{26300}{313}[/tex]

[tex]\\ \sf\Rrightarrow V_2=84.02ml[/tex]

A car accelerates at a constant rate of 3 m/s2 for 5 seconds. If it reaches a velocity of 27 m/s, what was its initial velocity?

A
15 m/s

B
42 m/s

C
12 m/s

D
2.1 m/s

Answers

The initial velocity of a car that accelerates at a constant rate of 3m/s² for 5 seconds is 12m/s.

CALCULATE INITIAL VELOCITY:

The initial velocity of the car can be calculated by using one of the equation of motion as follows:

V = u + at

Where;

V = final velocity (m/s)u = initial velocity (m/s)a = acceleration due to gravity (m/s²)t = time (s)

According to this question, a car accelerates at a constant rate of 3 m/s² for 5 seconds. If it reaches a velocity of 27 m/s, its initial velocity is calculated as follows:

u = v - at

u = 27 - 3(5)

u = 27 - 15

u = 12m/s.

Therefore, the initial velocity of a car that accelerates at a constant rate of 3m/s² for 5 seconds is 12m/s.

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how is the rate of evporation of a liquid affected by temperature, the surface area of a liquid exposed to air

Answers

As temperature increases, rate of evaporation also increases. This is due to increasing kinetic energy of the surface molecules which leads them to free and become vapour. c. As surface area increases, rate of evaporation also increases.

If a rock weighing 3.5 newtons is resting on cliff's ledge 12 meters from the canyon floor, what is its potential energy?

Group of answer choices

87 joules

4.5 joules

42 joules

142 joules

Answers

Answer:

42 Joules

Explanation:

Potential energy

= weight × height

= (3.5)(12)

= 42 joules

2. The _____ investigate crimes anywhere in the state.

Answers

Answer:

State Police

the police organized and maintained by a state as distinguished from those of a lower subdivision (such as a city or county) of the state government.

State police. Because they have state in there name. Like a county sheriff can only arrest people in there county.

What force is responsible for how magma flows and rocks stack up on top of one another?

Question 6 options:

Electroweak and Strong


Nuclear


Electromagnetic


Gravitational

Answers

Gravitational force is responsible for how magma flows and rocks stack up on top of one another.

Gravitational force is the force hat attracts all objects to the center of the earth. The force of gravity accounts for the fact that when an object is thrown up, it falls back to the earth.

The force that is responsible for how magma flows and rocks stack up on top of one another is the gravitational force.

Hence, it is the gravitational force that is responsible for how magma flows and rocks stack up on top of one another.

Learn more about gravitational force: https://brainly.com/question/24783651

A 5kg ball is on top of the school building at a height of 40m above the ground.
A. calculate the potential energy of the ball at that height.


B. How much power would it take to get the ball from the ground to that height in 1 minute.


C. If it is dropped what type of energy will the ball have as it approaches the ground.


D. What speed will the ball hit the ground

Answers

Answer:

A-Caclcuate the potential energy of the ball at that height

Explanation:

(a). Mass of the Body = 10 kg.

Height = 10 m.

Acceleration due to gravity = 9.8 m/s².

Using the Formula,Potential Energy = mgh

= 10 × 9.8 × 10 = 980 J.

(b). Now, By the law of the conservation of the Energy, Total amount of the energy of the system remains constant.

∴ Kinetic Energy before the body reaches the ground is equal to the Potential Energy at the height of 10 m.

∴ Kinetic Energy = 980 J.

(c). Kinetic Energy = 980 J.

Mass of the ball = 10 kg.

∵ K.E. = 1/2 × mv²

∴ 980 = 1/2 × 10 × v²

∴ v² = 980/5

⇒ v² = 196

∴ v = 14 m/s.

A 3.1 kg carton's GPE was increasing by 7.8 J as it was lifted above the ground. How high was it lifted?

Answers

Answer:it was lifted

Explanation:

by me lifting it because i can life it very high

when do magnets have the most potential energy

Answers

Answer:

Explanation:

Permanent magnets do have potential energy, stored in their magnetic field. That energy can be compared to the potential energy of some compressed spring. See the picture below, representing the magnetic field lines of a magnetized sphere : These lines are compressed inside the magnet.

Honestly I think it’s the pill

In a game of pool, a cue ball rolls without slipping toward the stationary eight ball with a momentum of 0.23 kg m/s. After the two balls collide, the final momentum of the cue ball is 0.01 kg m/s

Answers

Answer: 0.22

Explanation: Subtract 0.01kg from 0.23kg

Objects 1 and 2 attract each other with a gravitational force
of 18.0 units. If the mass of Object 1 is doubled mass of object 2 is tripled AND the
distance separating Objects 1 and 2 is halved, then the gravitational force will be
new gravitational force will be
units.

Answers

The new gravitational force of the two objects will be 432 N.

The given parameters:

Force between object 1 and object 2, F = 18 N

Let the mass of object 1 = m1Let the mass of object 2 = m2Let the distance between the two object = r

The gravitational force between the two objects is calculated by applying Newton's law of universal gravitation;

[tex]F = \frac{Gm_1m_2}{r^2} \\\\G = \frac{Fr^2}{m_1m_2}\\\\G = \frac{Gm_1m_2}{r^2} \\\\G = \frac{18r^2}{m_1m_2}[/tex]

when the mass of the object 1 = 2m1mass of the object 2 = 3m2distance between the two object = ¹/₂r

[tex]\frac{18r^2}{m_1 m_2 } = \frac{F_2(\frac{1}{2}r)^2 }{2m_1 \times 3m_2} \\\\\frac{18r^2}{m_1 m_2 } = \frac{F_2 \times r^2}{4 \times 2m_1 \times 3m_2} \\\\\frac{18r^2\times 4 \times 2m_1 \times 3m_2}{m_1 m_2\times r^2 } = F_2\\\\432 \ N = F_2[/tex]

Thus, the new gravitational force of the two objects will be 432 N.

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Which is the correct answer

Answers

Answer:

C

Explanation:

All of the other options are affecting the gravitational force and opposing force that pushed upwards, the diagram represents an object that is not moving up or down.

How fast would a(n) 75 kg man need to run in order to have the same kinetic energy as an 8.0 g bullet fired at 420 m/s ?

Answers

Mass of the bullet (m1) = 8g = 0.008 KgVelocity of the bullet (v1) = 420 m/sWe know, kinetic energy = [tex] \frac{1}{2}m {v}^{2} [/tex]Therefore, the kinetic energy of the bullet

[tex] = \frac{1}{2} \times 0.008 \times 420J \\ = 1.68J[/tex]

So, the kinetic energy of the bullet is 1.68 J. It is said that the man's kinetic energy should be same as that of the bullet.Mass of the man (m2) = 75 KgLet the velocity of the man be v2.Therefore,

[tex]1.68J = \frac{1}{2} \times 75 \: kg \times v2 \\ = > v2 = \frac{1.68 \times 2}{75} m {s}^{ - 1} \\ = 0.0448 \: m \: {s}^{ - 1} [/tex]

Answer:

0.0448 m/s

Hope you could get an idea from here.

Doubt clarification - use comment section.

What force is responsible for how magma flows and rocks stack up on top of one another?

Question 6 options:

Electroweak and Strong


Nuclear


Electromagnetic


Gravitational

Answers

Gravitational Force

Explanation:-

The magma flows through the gap between the rocks which are stacked up on top of one another.

The gravity attracts the magma to do that.

Also the rocks are stacked because of the gravitational force between them

Hence Option D is correct

Hope it helps

Answer:

pls mark me as brainliest

Explanation:

last one

Which is true for the motion of the car during its journey along OAB?
12)

A) The velocity of the car remains constant throughout the journey.
B) The change in speed alone causes the velocity of the car to vary.
C) The change in direction alone causes the velocity of the car to vary.
D) The velocity of the car changes due to the change in speed and dir

Answers

Answer:

D

Explanation:

A is wrong as the direction of the car changes, implying velocity is changing and not constant.

B and C are wrong as both the change in speed and direction contribute to the change in velocity

The smallest possible particle of complete matter is the atom. True or false?

true

false

Answers

Answer:

TRUE !!

Explanation:

An atom is the smallest particle of an element

____________ is a medium-sized flat-topped hill with cliff-face sides that is taller than it is wide.

Answers

Answer:

mesa

Explanation:

A mesa is a flat-topped mountain or hill. It is a wide, flat, elevated landform with steep sides. ... Spanish explorers of the American southwest, where many mesas are found, used the word because the tops of mesas look like the tops of tables.

can somebody explain it to me please?​

Answers

Range be R and height be h

[tex]\boxed{\sf R=\dfrac{u^2sin2\theta}{g}}[/tex]

[tex]\boxed{\sf h=\dfrac{u^2sin^2\theta}{2g}}[/tex]

u=initial velocity

theta is angle of projection.

g=acceleration due to gravity

ATQ

[tex]\\ \sf\longmapsto R=2h[/tex]

[tex]\\ \sf\longmapsto \dfrac{u^2sin2\theta}{g}=\dfrac{2u^2sin^2\theta}{2g}[/tex]

Cancelling required ones

[tex]\\ \sf\longmapsto sin^2\theta=sin2\theta[/tex]

sin2O=2sinOcosO

[tex]\\ \sf\longmapsto sin^2\theta=2sin\theta cos\theta [/tex]

[tex]\\ \sf\longmapsto \dfrac{sin^2\theta}{sin\theta cos\theta=2[/tex]

[tex]\\ \sf\longmapsto \dfrac{sin\theta}{cos\theta}=2[/tex]

[tex]\\ \sf\longmapsto tan\theta=2[/tex]

[tex]\\ \sf\longmapsto \theta=tan^{-1}(2)[/tex]

[tex]\\ \sf\longmapsto \theta=63.4°[/tex]

Done

Option B is correct

A billiard ball with a speed of 5 m/s strikes another stationary billiard ball in a perfectly elastic collision.

After the collision, the first ball has a speed of 4.35 m/s and is traveling at an angle of 30° below its original line of motion.

Find the speed and angle of the second ball, with respect to the initial line of motion, after the collision.

Answers

Assuming both billiard balls have the same mass, conservation of momentum says

[tex]m\vec v_1 + m\vec v_2 = m{\vec v_1}\,' + m{\vec v_2}\,'[/tex]

where m = mass of both billiard balls, and v₁ and v₂ = their initial velocities, and v₁' and v₂' = their final velocities. The masses are the same so the exact value of m is irrelevant. The first ball has initial speed 5 m/s and the second is at rest, so

[tex]\left(5 \dfrac{\rm m}{\rm s}\right) \, \vec\imath = {\vec v_1}\,' + {\vec v_2}\,'[/tex]

After the collision, the first ball has speed 4.35 m/s and is moving at angle of 30° below the original path, so

[tex]{\vec v_1}\,' = \left(4.35\dfrac{\rm m}{\rm s}\right)\left(\cos(30^\circ) \, \vec\imath + \sin(30^\circ) \, \vec\jmath\right) \approx \left(3.77 \dfrac{\rm m}{\rm s}\right) \vec\imath + \left(-2.18 \dfrac{\rm m}{\rm s}\right) \vec\jmath[/tex]

Then the second ball has final velocity vector

[tex]{\vec v_2}\,' \approx \left(1.23 \dfrac{\rm m}{\rm s}\right) \vec\imath + \left(2.18 \dfrac{\rm m}{\rm s}\right) \vec\jmath[/tex]

so it moves with speed

[tex]\left\|{\vec v_2}\,'\right\| \approx \sqrt{\left(1.23\dfrac{\rm m}{\rm s}\right)^2 + \left(2.18\dfrac{\rm m}{\rm s}\right)^2} \approx \boxed{2.50 \dfrac{\rm m}{\rm s}}[/tex]

at an angle of

[tex]\theta \approx \tan^{-1}\left(\dfrac{2.18}{1.23}\right) \approx \boxed{60.5^\circ}[/tex]

or about 60.5° above the original line of motion.

Please help is any one know Its correct answer ​

Answers

Answer:

a=Head

b=Tip

c=South pole of the magnet

d=North pole of the magnet

a q deben los cambios de la materia??

Answers

Answer:

wat

Explanation:

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