∆ABC is translated 2 units down and 1 unit to the left. Then it is rotated 90° clockwise about the origin to form ∆A′B′C′. The coordinates of vertex A′ of ∆A′B′C′ are . The coordinates of vertex B′ of ∆A′B′C′ are . The coordinates of vertex C′ of ∆A′B′C′ are .

Answer:

A'(-2, 1), B'(1, 0), C'(-1, 0)

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, dilation and translation.

If a point X(x, y) is translated a units right and b units down, the new location is X'(x + a, y + b) whereas if a point X(x, y) is translated a units left and b units up, the new location is X'(x - a, y - b).

If a point X(x, y) is rotated 90° clockwise about the origin, the new location is X'(y, -x)

From the image attached, ∆ABC is at A(0, 0), B(1,3) C(1, 1)

If ∆ABC is translated 2 units down and 1 unit to the left (x - 1, y - 2), the vertices would be A*(-1, -2), B*(0, 1), C*(0, -1)

If it is then rotated 90° clockwise about the origin, the new location is A'(-2, 1), B'(1, 0), C'(-1, 0)

Answer:

The coordinates of vertex A′ of ∆A′B′C′ are  (-2, 1) .

The coordinates of vertex B′ of ∆A′B′C′ are  (1, 0) .

The coordinates of vertex C′ of ∆A′B′C′ are  (-1, 0) .

Step-by-step explanation:

f(x)=-x^2+3 pls help

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